kara needs to get a 75% on her drivers education test in order to get her license. If there are 35 questions, how many does she need to get right?

Therefore , the solution of the given problem of pentagonal comes out to be Nadia has created a pentagonal prism as a result.

Pentagons is that are two-dimensional polygons having five sides and fifth angles. When we mix the Greek terms "penta" and "gon," which mean "five" and "angles," respectively, we have the word "pentagon."

Here, we know that a pentagonal prism has five rectangular sides in addition to two pentagonal bases at the top and bottom.

Pentagonal prisms are pentagon-shaped if we look at them from the bottom.

When viewed from the side, a pentagonal prism would have a rectangular shape.

If we were to look at the pentagonal prism from the front, it would appear rectangular.

Therefore , the solution of the given problem of pentagonal comes out to be Nadia has created a pentagonal prism as a result.

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On solving the provided question, we can say that In triangle DBC and BDA, So, By SSS, △DBC ≅ △BDA

A triangle is a polygon since it has three sides and three vertices. It is one of the basic geometric shapes. The name given to a triangle containing the vertices A, B, and C is Triangle ABC. A unique plane and triangle in Euclidean geometry are discovered when the three points are not collinear. Three sides and three corners define a triangle as a polygon. The triangle's corners are defined as the locations where the three sides converge. 180 degrees is the result of multiplying three triangle angles.

In triangle DBC and BDA

BD = BD ( common base)

AB = CD

AD = BC

So, By SSS,

△DBC ≅ △BDA

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A rule that makes a particular cell is highlighted in yellow only if the value it contains is less than $5000 is an example of conditional formatting.

This is a special feature that can be found in programs such as excel and allows users to automatically apply specific changes or formatting to cells that meet specific criteria.

There are four main types:

In the case of the formatting described, this can be classified as conditional formatting because all cells that meet the criteria (less than $5000) will be automatically highlighted in yellow. Moreover, the type of formatting is a change in the color of the cell.

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The unit cost for the diamond walnuts , $2.99 for 8 ounces is 37.4 cents/ounce .

In the question ,

it is given that ,

the cost for 8 ounces of diamond walnuts is = $2.99 ,

we have to find the unit rate in cents per ounce .

we know that $1 = 100 cents .

So , $2.99 is = 299 cents .

the cost for 8 ounces of diamond walnuts is = 299 cents

and the cost for 1 ounce of diamond walnuts will be = 299/8

on dividing ,

we get ,

= 37.375

≈ 37.4 cents per ounce

Therefore , the unit cost is 37.4 cents per ounce  .

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Answer:

C 5 miles

D 63 Minutes

Step-by-step explanation:

Make a proportion and solve for the number that you do not know

\(\frac{miles}{minutes}\) = \(\frac{miles}{minutes}\)

\(\frac{27}{3}\) = \(\frac{45}{x}\)  See how 27 divide by 9 is 3?  Divide 45 by 9 to get 5

\(\frac{27}{3}\) = \(\frac{x}{7}\)  This time, see how 3 x 9 is 27, so 7 x 9 is 63

Based on the raw score of 82, and the 70th percentile passing, we can infer that as regards 82 being a passing score, No, it might have a percentile rank less than 70.

The passing score is one that is in the 70th percentile or higher. This means that the raw score that a student gets needs to be considered higher than 70% of the rest of the scores.

There is a chance that the exam was so easy that most people got good scores. If that were the case, then a score of 82 can be below the 70th percentile which means that the candidate would not pass.

Options for this question are:

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If on january 1, year 1, billy co signed a three-year lease for office space The amortization expense on this leasehold improvement that Billy should  record for Year 2 is: $1,000.

Since we were told that the new overhead lighting fixtures is the amount of $2,000 now let determine the  Amortization expense using this formula

Amortization expense = New overhead lighting fixtures / 2 years

Let plug in the formula

Amortization expense =  $2,000 /2

Amortization expense = $1,000

Therefore the  Amortization expense  is the amount of $1,000.

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The complete question:

On January 1 , Year 1, Billy Co. signed a three year lease for office space. The lease required monthly rent of 8,000 for the first year. 8,100 for the second year and 8,200 for the 3rd year. Billy has the option to renew the lease for a fourth year at 8,300 per month. On January 1, Year 2, Billy permanently installed new overhead lighting fixtures at a cost of $2,000. How much amortization expense on this leasehold improvement should Billy record for Year 2?

Answer:

x<25/18 tis is d real anwer

Answer:

the answer is d because its makes the 5/6 turn into 10/6 or 1 4/6 or 1 2/3

the point at which the line intersects the given plane. x = 2 - 2t, y = 3t, z = 1 + t: x + 2y - z = 4 (x, y, z) = (0, 3, 2)

They are referred to be intersecting lines when two or more lines in a plane cross each other. The crossing lines have a common point, known as the point of intersection, which exists on all intersecting lines. They are referred to be intersecting lines when two lines have precisely one point in common. A common point connects the crossing lines. The point of intersection is also known as the common point that all intersecting lines share. There will be a point of intersection between the two coplanar, non-parallel straight lines.

We are given the equation of plane:

x + 2y - z = 7 .............. (1)

And parametric equation of line is as follows:

x = 2 - 2t, y = 3t, z = 1 + t ............... (2)

To find point of intersection of given line and plane, substitute value of x, y, z from equation (2) in equation (1),

we get,

or, (2 - 2t) + 2(3t) - (1+t) = 7

or, 2 - 2t + 6t - 1 - t = 4

or, 3t = 3

or, t = 1

Put this value of t in equation (2):

x = 2 - 2(1) = 0

y = (3×1) = 3

z = (1 + 1) = 2

Therefore point of intersection of given line and plane is: (0, 3, 2).

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Answer:

The answer should be 6.208<62.081

Step-by-step explanation:

Because the open side faces the larger value

True, for any propositional formula f, every stable model of 'f' is a model of "f'.


A stable model is a type of logical model used in logic programming and non-monotonic reasoning. It is a set of logical sentences that are consistent with the propositional formula f and that satisfy certain stability conditions.

In other words, a stable model is a model of the propositional formula "f" that is also consistent with the additional constraints imposed by the stability conditions. Because of this, every stable model of f is also a model of 'f'.

Therefore, the statement "for any propositional formula f', every stable model of f is a model of f" is true.

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The solutions to the expressions using laws of exponents are;

17) y^(19/28)

18) 1/a^(5/9)

The product rule of exponents states that "To multiply two expressions with the same base, add the exponents while keeping the base the same". Thus;

y² × y³ = y²⁺³

= y⁵

17) y^(3/7) × y^(1/4)

Applying product rule of exponents gives;

y^(³/₇ + ¹/₄)

= y^(19/28)

18) The negative exponent rule states that: To convert any negative exponent into positive exponent, the reciprocal should be taken." Thus;

x⁻³ = 1/x³

Thus;

a^(-5/9) = 1/a^(5/9)

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Answer:

Letter A represent  \(y\le x+5\)

I attached a pic of the graph made in a graph calculator.

Answer:

Therefore, the book value of the equipment at the end of year four (including year four) is $2,880.

Step-by-step explanation:

To calculate the book value of the equipment at the end of year four using the MACRS method with GDS recovery period of five years, we can use the following steps in Excel:

1. Open a new Excel spreadsheet and create the following headers in row 1: Year, Cost, Depreciation Rate, Annual Depreciation, Cumulative Depreciation, and Book Value.

2. Fill in the Year column with the years 1 through 6 (since the truck has a life of six years).

3. Enter the cost of the truck, $12,000, in cell B2.

4. Use the following formula in cell C2 to calculate the depreciation rate for each year:

=MACRS.VDB(B2, 5, 5, 1, C1)

This formula uses the MACRS.VDB function to calculate the depreciation rate for each year based on the cost of the truck (B2), the GDS recovery period of five years, the useful life of six years, the salvage value of $2,000, and the year (C1).

5. Copy the formula in cell C2 and paste it into cells C3 through C7 to calculate the depreciation rate for each year.

6. Use the following formula in cell D2 to calculate the annual depreciation for each year:

=B2*C2

This formula multiplies the cost of the truck (B2) by the depreciation rate for each year (C2) to get the annual depreciation.

7. Copy the formula in cell D2 and paste it into cells D3 through D7 to calculate the annual depreciation for each year.

8. Use the following formula in cell E2 to calculate the cumulative depreciation for each year:

=SUM(D$2:D2)

This formula adds up the annual depreciation for each year from D2 to the current row to get the cumulative depreciation.

9. Copy the formula in cell E2 and paste it into cells E3 through E7 to calculate the cumulative depreciation for each year.

10. Use the following formula in cell F2 to calculate the book value of the equipment for each year:

=B2-E2

This formula subtracts the cumulative depreciation for each year (E2) from the cost of the truck (B2) to get the book value.

11. Copy the formula in cell F2 and paste it into cells F3 through F7 to calculate the book value for each year.

12. The book value of the equipment at the end of year four (including year four) is the value in cell F5, which should be $2,880.

Answer:

B

Step-by-step explanation:

x in terms of m, M, g, and h is x = y^2 / (mgh). M is an additional variable introduced, which was not mentioned in the initial problem statement.

To solve the given equations for x in terms of m, g, and h, we will solve each equation step-by-step:

Equation 1: 6x = 9y + 5y^2 = mgh

Step 1: Rearrange the equation to isolate x:

6x = mgh - 9y - 5y^2

Step 2: Divide both sides by 6:

x = (mgh - 9y - 5y^2) / 6

Therefore, x in terms of m, g, and h is:

x = (mgh - 9y - 5y^2) / 6

Equation 2: mx = (m + M)y^2 / (m + M)gh

Step 1: Simplify the equation by canceling out (m + M) on both sides:

mx = y^2 / gh

Step 2: Divide both sides by m:

x = y^2 / (mgh)

Therefore, x in terms of m, M, g, and h is:

x = y^2 / (mgh)

Please note that in Equation 2, M is an additional variable introduced, which was not mentioned in the initial problem statement. If you have any specific values for M or any further information, please provide it, and I can adjust the solution accordingly.

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Design Alternative 1: Capital Investment: $500,000 Annual Operating Expenses: $75,000 Design Alternative 2: Capital Investment: $700,000 Annual Operating Expenses: $50,000 Design Alternative 3: Capital Investment: $600,000 Annual Operating Expenses: $60,000 Design Alternative 4: Capital Investment: $800,000 Annual Operating Expenses: $40,000

The PW (Present Worth) method is a financial evaluation technique used to compare and select the best design alternative for a project based on the present value of the cash flows associated with each alternative. In this case, we will use the PW method to determine which design alternative should be selected for the Consolidated Oil Company's new refinery.

To use the PW method, we need to calculate the present worth of the capital investment and the annual operating expenses for each design alternative. The present worth is the value of future cash flows discounted to their equivalent present value.
Here are the capital investment and annual operating expenses for each design alternative:
Design Alternative 1:
Capital Investment: $500,000
Annual Operating Expenses: $75,000
Design Alternative 2:
Capital Investment: $700,000
Annual Operating Expenses: $50,000
Design Alternative 3:
Capital Investment: $600,000
Annual Operating Expenses: $60,000
Design Alternative 4:
Capital Investment: $800,000
Annual Operating Expenses: $40,000
To calculate the present worth of each design alternative, we need to discount the cash flows using the desired Minimum Acceptable Rate of Return (MARR), which is 10% per year.
First, let's calculate the present worth of the capital investment for each design alternative. We will use the formula:
PW = (Annual Cash Flow / (1 + MARR)^n) * (1 - (1 / (1 + MARR)^t))
Where: PW = Present Worth
Annual 33333333333333333333333

.. = Capital Investment
MARR = Minimum Acceptable Rate of Return
n = Useful life of the design alternative
t = Number of years before the cash flow occurs

Using this formula, we can calculate the present worth of the capital investment for each design alternative as follows:
Design Alternative 1:
PW = (500,000 / (1 + 0.10)^8) * (1 - (1 / (1 + 0.10)^8))
PW = $500,000 * 0.4665
PW = $233,250
Design Alternative 2:
PW = (700,000 / (1 + 0.10)^8) * (1 - (1 / (1 + 0.10)^8))
PW = $700,000 * 0.3866
PW = $270,620
Design Alternative 3:
PW = (600,000 / (1 + 0.10)^8) * (1 - (1 / (1 + 0.10)^8))
PW = $600,000 * 0.4189
PW = $251,340
Design Alternative 4:
PW = (800,000 / (1 + 0.10)^8) * (1 - (1 / (1 + 0.10)^8))
PW = $800,000 * 0.3601
PW = $288,080
Now, let's calculate the present worth of the annual operating expenses for each design alternative. We will use the same formula as before:
Design Alternative 1:
PW = (75,000 / (1 + 0.10)^8) * (1 - (1 / (1 + 0.10)^8))
PW = $75,000 * 0.4665
PW = $34,987.50
Design Alternative 2:
PW = (50,000 / (1 + 0.10)^8) * (1 - (1 / (1 + 0.10)^8))
PW = $50,000 * 0.4665
PW = $23,325
Design Alternative 3:
PW = (60,000 / (1 + 0.10)^8) * (1 - (1 / (1 + 0.10)^8))
PW = $60,000 * 0.4665
PW = $27,990
Design Alternative 4:
PW = (40,000 / (1 + 0.10)^8) * (1 - (1 / (1 + 0.10)^8))
PW = $40,000 * 0.4665
PW = $18,660
Design Alternative 1:
PW = $233,250 + $34,987.50
PW = $268,237.50
Design Alternative 2:
PW = $270,620 + $23,325
PW = $293,945
Design Alternative 3:
PW = $251,340 + $27,990
PW = $279,330
Design Alternative 4:
PW = $288,080 + $18,660
PW = $306,740
To confirm our selection, we can also use the FW (Future Worth) and AW (Annual Worth) methods.
The FW method compares the future worth of the cash flows for each design alternative. However, since the question states that there is no market value, we can skip this step.
The AW method compares the annual worth of the cash flows for each design alternative. The annual worth is the equivalent uniform annual cost or benefit over the project's useful life. We can calculate the annual worth using the formula:
AW = (PW * MARR) / (1 - (1 / (1 + MARR)^n))
Where:
AW = Annual Worth
PW = Present Worth
MARR = Minimum Acceptable Rate of Return
n = Useful life of the design alternative
Using this formula, we can calculate the annual worth for each design alternative:
Design Alternative 1:
AW = ($233,250 * 0.10) / (1 - (1 / (1 + 0.10)^8))
AW = $23,325 / 5.3359
AW = $4,367.24
Design Alternative 2:
AW = ($270,620 * 0.10) / (1 - (1 / (1 + 0.10)^8))
AW = $27,062 / 5.3359
AW = $5,073.14
Design Alternative 3:
AW = ($251,340 * 0.10) / (1 - (1 / (1 + 0.10)^8))
AW = $25,134 / 5.3359
AW = $4,711.54
Design Alternative 4:
AW = ($288,080 * 0.10) / (1 - (1 / (1 + 0.10)^8))
AW = $28,808 / 5.3359
AW = $5,393.89
Based on the AW method, the design alternative with the highest annual worth is Design Alternative 4, with an annual worth of $5,393.89. This confirms our selection based on the PW method.

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Correct option is C and the angle D and F are complementary angles.

∠D+∠E+∠F=180⁰

 ....Angle sum property

∵∠E=90⁰

⇒∠D+∠F=180⁰

−90 ⁰

⇒∠D+∠F=90⁰

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The area of the regular polygons with 12 sides(dodecagon) and 5 sides (pentagon) are 389.06 in² and 19.87 in² respectively.

Area of regular polygon = 1/2 × apothem × perimeter

perimeter = (s)side length of octagon × (n)number of side.

apothem = s/[2tan(180/n)].

11 = s/[2tan(180/12)]

s = 11 × 2tan15

s = 5.8949

perimeter = 5.8949 × 12 = 70.7388

Area of dodecagon = 1/2 × 11 × 70.7388

Area of dodecagon = 389.0634 in²

Area of pentagon = 1/2 × 5.23 × 7.6

Area of pentagon = 19.874 in²

Therefore, the area of the regular polygons with 12 sides(dodecagon) and 5 sides (pentagon) are 389.06 in² and 19.87 in² respectively.

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Answer:

Second choice
∠BCA ≅ ∠DCA

Step-by-step explanation:

This logically follows from the fact that both ∠BCA and ∠DCA are right angles from the previous step. And the reason given is "All right angles are ≅)

So they are congruent

The value of the distance is 165 m and the value of the distance is 55x

The formula is given as:

d =rt

a. You traveled 3 hours at 55 mph

This means that

r = 55 and t = 3

So, we have:

d = rt

This gives

d = 55 * 3

Evaluate

d = 165

Hence, the value of the distance is 165 m

This means that

r = 55 and t = x

So, we have:

d = rt

This gives

d = 55 * x

Evaluate

d = 55x

Hence, the value of the distance is 55x

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Andrew intends to make a second batch of Sauce 1 and Sauce II with 3,180 green peppers and 5,560 hot chili peppers.

You've tried poblanos and like the heat they provide to homemade salsa, but you're ready to branch out. The good news is that there are more than 4,000 different varieties of chili peppers in the world, and more are constantly being created.

Andrew prepares hot salts. his first batch will have 4 chili peppers and 6 green peppers, while his second batch will contain 3 green peppers and 10 chili peppers. We therefore need to know how many of each he requires.

To give you an idea of how many peppers to use per bottle of hot sauce, we suggest using at least two really hot peppers per bottle for a sauce with a lot of heat. In addition, habaneros can be made with 4-6 peppers.

Therefore, 975 green peppers and 1,250 hot peppers are purchased by Andrew. He uses all of those peppers to make both types of sauce.

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(x, y) → (x+2, y+3) means a translation 2 units to the right and 3 units up.

Transformations are changes done in the shapes on a coordinate plane by rotation, reflection or translation.

here, we have,

Given the rule of transformation:

(x, y) → (x+2, y+3)

If we move horizontally 2 units to the right, 2 is added to the x-coordinate of any given point, and then 3 units up.

In other words,

(x, y) → (x+2, y+3) means Translation 2 units right and 3 units up.

For example,

Let say if we have the point A(4, 5)

Using the translation rule:

(x, y) → (x+2, y+3)

A(4, 5) → A'(4 + 2, 5 + 3) → A'(6, 8)

Therefore, the new position of A(4, 5) after translating 3 units right and 2 units up would be: A'(6,8).

Hence, (x, y) → (x+2, y+3) means a translation 2 units to the right and 3 units up.

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Answer:

hey dude try doing them first then ask people thry are easy also open your book and see the steps there

No, because

2(y + 1,5)  = 2 · y + 2 · 1,5 = 2y + 3

2y + 3 ≠ 2y + 1,5

Answer:

No

Step-by-step explanation:

2 ( y + 1.5 ) = 2y + 3. Not 2y + 1.5

Answer:

There is no answer as there is no question.

Step-by-step explanation:

Answer:

I added the answer to your newest problem :D

Step-by-step explanation:

Hope it helped!

Step-by-step explanation:

y = -3x² + mx + 10

dy/dx = -6x + m.

When dy/dx = 0, -6x + m = 0. => x = m/6.

We have y = -3(m/6)² + m(m/6) + 10 = 37.

=> -m²/12 + m²/6 = 27

=> -m² + 2m² = 324

=> m² = 324

=> m = 18 or m = -18.

There are 7 degrees of freedom.

In performing the pooled-variance t test, the degrees of freedom can be calculated using the formula:
df = (n1 - 1) + (n2 - 1)

Substituting the given values:
df = (4 - 1) + (5 - 1)
df = 3 + 4
df = 7

Therefore, there are 7 degrees of  freedom.

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There are 7 degrees of freedom for the pooled-variance t-test.

To perform a pooled-variance t-test, we need to calculate the degrees of freedom. The formula for degrees of freedom in a pooled-variance t-test is:

\(\[\text{{df}} = n_1 + n_2 - 2\]\)

where \(\(n_1\)\) and \(\(n_2\)\) are the sample sizes of the two independent samples.

In this case, \(\(n_1 = 4\)\) and \(\(n_2 = 5\)\). Substituting these values into the formula, we get:

\(\[\text{{df}} = 4 + 5 - 2 = 7\]\)

In a pooled-variance t-test, we combine the sample variances from two independent samples to estimate the population variance. The degrees of freedom for this test are calculated using the formula \(df = n1 + n2 - 2\), where \(n_1\)and \(n_2\) are the sample sizes of the two independent samples.

To understand why the formula is \(df = n1 + n2 - 2\), we need to consider the concept of degrees of freedom. Degrees of freedom represent the number of independent pieces of information available to estimate a parameter. In the case of a pooled-variance t-test, we subtract 2 from the total sample sizes because we use two sample means to estimate the population means, thereby reducing the degrees of freedom by 2.

In this specific case, the sample sizes are \(n1 = 4\) and \(n2 = 5\). Plugging these values into the formula gives us \(df = 4 + 5 - 2 = 7\). Hence, there are 7 degrees of freedom for the pooled-variance t-test.

Therefore, there are 7 degrees of freedom for the pooled-variance t-test.

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The distance between the car and Johnstown is decreasing at a rate of 33 miles per hour.

After travelling 63 miles, the distance between the car and Johnstown is changing at a rate of 33 miles per hour, and the distance between the car and Johnstown is 100 miles

To calculate the distance between the car and Johnstown after travelling 63 miles, we need to first find the starting distance.

The car starts off 163 miles directly north from the city of Johnstown, so the starting distance is 163 miles.

We then need to subtract the distance travelled from this starting distance. Since the car is travelling at a rate of 33 miles per hour, it has travelled 63 miles in the given time.

Therefore, the distance between the car and Johnstown is 100 miles

(163 - 63 = 100).

Finally, we need to calculate the rate of change of this distance. Since the car is travelling at a rate of 33 miles per hour, the rate of change of the distance between the car and Johnstown is also 33 miles per hour.

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When you want to replicate a study as closely as possible, the Methodology section of a research article would provide you with the most details about how the data was collected.

the instruments used to collect the data, the sampling method, and the procedures employed during data collection. In most research articles, the methodology section can be found after the introduction section.

It includes information on the data collection techniques used, including the type of research design, the sampling technique, data collection instruments, and the procedures used to collect the data.

.In summary, if you want to replicate a study as closely as possible, you should carefully examine the methodology section of the research article. This section contains a detailed account of how the data was collected, analyzed, and interpreted in the study.

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