Kashira has 3/9 of a pizza and Laila gave her 1/3 of a pizza. How much pizza does Kashira have now? Please provide your answer in simplest form. (NVM FIGURED IT OUT)

Answer: Pressure and Volume have an inverse and Temperature and Moles have an inverse relationship

Step-by-step explanation:

There is an inverse relationship between the following variables that define the properties of a gas:

1. Pressure (P) and Volume (V): According to Boyle's Law, when the temperature (T) is held constant, the product of pressure and volume remains constant for a given amount of gas. Mathematically, PV = constant. As one variable increases, the other decreases, indicating an inverse relationship.

2. Temperature (T) and Volume (V) in certain cases: In the case of Charles's Law, when the pressure is constant, the volume is directly proportional to temperature. However, if we consider a constant product of temperature and volume (TV = constant), and the pressure increases, then we observe an inverse relationship between temperature and volume.

Remember, these inverse relationships occur while keeping other variables constant. This is a multiple response question as both relationships mentioned above display an inverse relationship between different variables that define the properties of a gas.

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Answer:

Sure! Here's a system of equations we can set up to represent this situation:

Let x be the price of a bag of popcorn and y be the price of a drink.

Then we can set up the following system of equations:

x + 3y = 16.50 (equation for Jack's purchases)

2x + 5y = 29.75 (equation for Jill's purchases)

To solve this system of equations, we can use the substitution method.

First, we can solve for x in equation 1:

x = 16.50 - 3y

Then, we can substitute this expression for x into equation 2:

2(16.50 - 3y) + 5y = 29.75

Simplifying this equation, we get:

33 - 6y + 5y = 29.75

Combining like terms, we get:

33 - y = 29.75

Subtracting 29.75 from both sides, we get:

33 - 29.75 - y = -y

Simplifying, we get:

3.25 - y = 0

Subtracting 3.25 from both sides, we get:

-y = -3.25

Dividing both sides by -1, we get:

y = 3.25

So, the price of a drink is $3.25.

Now we can substitute this value for y back into equation 1 to solve for x:

x + 3(3.25) = 16.50

Simplifying, we get:

x + 9.75 = 16.50

Subtracting 9.75 from both sides, we get:

x = 6.75

So, the price of a bag of popcorn is $6.75.

To the nearest cent, the price of a bag of popcorn is $6.75 and the price of a drink is $3.25.

Step-by-step explanation:

The equation \(9x^2 − 3x + 9y^2 + z^2 = 9\) can be written in cylindrical coordinates as \(z^2\) = 9 - 3r(3r - cos(theta)).

to express the equation in cylindrical coordinates, we need to substitute the Cartesian variables (x, y, z) with their corresponding cylindrical variables (r, theta, z).

In cylindrical coordinates, the relationship between Cartesian and cylindrical variables is given by:

x = rcos(theta)

y = rsin(theta)

z = z

Substituting these expressions into the equation, we have:

\(9(rcos(theta))^2 -3(rcos(theta)) + 9(rsin(theta))^2 + z^2\) = 9

Simplifying the equation, we get:

\(9r^2cos^2(theta) - 3rcos(theta) + 9r^2sin^2(theta) + z^2\)= 9

Using the trigonometric identity \(cos^2(theta) + sin^2(theta)\) = 1, we can further simplify the equation to:

\(9r^2 + z^2 - 3rcos(theta)\) = 9

Finally, rearranging the terms, we obtain:

\(z^2 = 9 - 3r(3r - cos(theta))\)

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Answer:

450 minutes

Step-by-step explanation:

1 call: 10 minutes

1 week: 10×3=30 minutes

15-week semester: 30×15=450 minutes

Answer:

6000 students

Step-by-step explanation:

Since the added value of the total number of students would be 5691, so if you wound up, it would be around 6,000

Answer:3,000 students

Step-by-step explanation:

The probability that the mean of a month's reviews will take Yoonie from 3.5 to 4.25 hours is 0.7492.

The random variable X is defined as the time it takes her to complete one review.

The random variable X follows a Normal distribution with parameters μ = 4 hours and σ = 1.2 hours.

A random sample of n = 16 reviews are selected as a set.

Compute the probability that the mean of a month’s reviews will take Yoonie from 3.5 to 4.25 hours as follows:

P(3.5 < X < 4.25) = P(3.5-4/1.2√16 < x- μ /σ/√n < 4.25-4/1.2/√16)

=P(-1.67 < Z < 0.83)

= P(Z < 0.83) - (P(Z < -1.67)

= 0.7967 - 0.0475

= 0.7492

Thus, the probability that the mean of a month’s reviews will take Yoonie from 3.5 to 4.25 hours is 0.7492.

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The correct  option (D).

There are infinitely many intersection points.

a two-variable equation that, when plotted on a graph, results in a straight line.

The term "point of intersection" refers to the intersection of two lines.

Russ is attempting to solve an equation whose two sides are both linear expressions.

He graphs the system and finds that they are on the same line after setting the expressions to y.

Since both lines are the same, there are an endless number of junction places.

Russ should therefore consider the outcome to be option (D) There are a limitless number of intersections.

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I understand that the question you are looking for is:

Russ is solving an equation where both sides are linear expressions. He sets the expressions equal to y and graphs the system finding that they are the same line. How should Russ interpret this outcome? There are no intersection points. There is exactly one intersection point. There are exactly two intersection points. There are infinitely many intersection points.Russ is solving an equation where both sides are linear expressions. He sets the expressions equal to y and graphs the system finding that they are the same line. How should Russ interpret this outcome?

A. There are no intersection points.

B. There is exactly one intersection point.

C. There are exactly two intersection points.

D. There are infinitely many intersection points

For the given Rayleigh distribution with \(f(x)= 2axe^{-ax^{2} }\) , the expected value is E[X] = sqrt(pi/(4a)), and the variance is Var[X] = (2 - π/(2a²)).

the Rayleigh distribution is characterized by a probability density function (PDF) of the form \(f(x)= 2axe^{-ax^{2} }\), where a > 0. This distribution is used to model the magnitude of a two-dimensional vector whose components are independently and identically distributed Gaussian random variables.

For the Rayleigh distribution with the PDF \(f(x)= 2axe^{-ax^{2} }\) , the expected value (mean) is E[X] = sqrt(pi/(4a)), and the variance is :

Var[X] = (2 - pi/2a²).

Now, let's explain the answer in detail. To find the expected value, we integrate the product of the random variable X and its PDF over the range of possible values:

\(E[x] = \int\limits {(0 to a)x* 2axe^{-ax^{2} }} \, dx\)

By substituting u = -ax², du = -2ax dx, the integral becomes:

E[X] = ∫(0 to ∞) -ueⁿ du

Using integration by parts, we have:

E[X] = [-ueⁿ] - ∫(-eⁿ du)

= \([-xe^{-ax^{2}](0 to a) - \int\limits {0 to a}e^{-ax^{2} }\, dx }\)

The first term evaluates to 0 at both limits. The second term can be rewritten as:

E[X] = ∫(0 to ∞) e⁻ᵃˣ² dx

= √(π/4a) (by evaluating the Gaussian integral)

Thus, the expected value of X is E[X] = sqrt(pi/(4a)).

Next, to find the variance, we use the formula Var[X] = E[X²] - (E[X])². First, we calculate E[X²]:

E[X²] = ∫(0 to ∞) x² * 2axe⁻ᵃˣ²) dx

= ∫(0 to ∞) -x * d(e^(-ax²))

= [-x * e^(-ax²)](0 to ∞) + ∫(0 to ∞) e⁽⁻ᵃˣ²⁾ dx

The first term evaluates to 0 at both limits. The second term is the same as the integral calculated for E[X]. Hence:

= √(π/4a)

Substituting the values into the variance formula:

Var[X] = E[X^2] - (E[X])^2

= (√(π/4a)) - (sqrt(pi/(4a)))²

= (2 - π/(2a²))

Thus, the variance of X is Var[X] = (2 - π/(2a^2)).

Therefore, for the given Rayleigh distribution with f(x) = 2axe⁽⁻ᵃˣ²⁾,

the expected value is E[X] = sqrt(pi/(4a)), and the variance is Var[X] = (2 - π/(2a²)).

Complete Question:

A random variable X has a Rayleigh distribution if its probability density is given by f(x) = 2oxe or for x > 0, where a > 0. Show that for this distribution 1. Al l vandle has a Rayleigh distribution if its probability density i f(x) = 2axe-ar' for I > 0, where a > 0. Show that for this distribution a) The expected value is b) The variance is o? = (1-5)

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 1) -  Hence, OPTION (A ):  BC  = √58

2) -  The measure of the Angle to the Nearest Tenth is:  73.6 degrees

1) - ΔABC  is a Right Triangle.  If  AB  =  3  and  AC  =  7,  Find BC. Leave in Simplest Radical Form.

AB^2  +  AC^2   =  BC^2

       AC  = 7, AB  =  3  Into  AB^2  +  AC^2  = BC^2

        3^2  +  7^2  =  BC^2

Hence,  Option (A):   BC  =  √58

2) - The tangent of an angle is 3.4. What is the measure of the angle to the nearest tenth?

Let Angle  Be:  ∝

tan ∝  =  3.4

      ∝  =  tan^-1 (3.4)

      ∝   =  73.6104597 degrees

      ∝   =   73.6 degrees

Therefore, the measure of the Angle is:  73.6 degrees

I hope this helps you!

The shortest waiting time that would still place a patient in the longest 5% of waiting times is approximately 415.4 days.

To find the shortest waiting time that would place a patient in the longest % of waiting times, we need to determine the z-score corresponding to that percentile and then convert it back to the waiting time using the mean and standard deviation.

The longest % of waiting times can be interpreted as the upper tail of the distribution. If we assume the longest % is x%, then the corresponding z-score can be found using the formula:

z = invNorm(1 - x/100)

Let's say the longest % is 5%. Plugging in the values, we get:

z = invNorm(1 - 5/100) = invNorm(0.95)

Using a standard normal distribution table or calculator, we find that invNorm(0.95) ≈ 1.645.

Now we can convert the z-score back to the waiting time using the formula:

x = mean + z * standard deviation

Let's assume the mean waiting time is 365 days and the standard deviation is 30 days. Plugging in the values, we get:

x = 365 + 1.645 * 30 ≈ 415.35

Rounding to the nearest tenth, the shortest waiting time that would still place a patient in the longest 5% of waiting times is approximately 415.4 days.

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Answer:

A: population

Step-by-step explanation:

Um its just the definition of the word i think.

Population: a collection of persons, things, or objects under study.

Answer:

:/

Step-by-step explanation:

necesito acabar la creación de cuenta

The multiplicative rate of change of the exponential function represented in the table is 5.

To determine the multiplicative rate of change of the exponential function, we can examine the relationship between the entries in the y-column and the corresponding entries in the x-column.

Looking at the values in the y-column, we can observe that each subsequent value is obtained by multiplying the previous value by a constant factor. For example, 4.5 divided by 4 is 1.125, which is approximately 5/4. Similarly, 6.75 divided by 4.5 is approximately 5/3, and so on.

This pattern indicates that the multiplicative rate of change between consecutive entries in the y-column is 5/4. In other words, each value in the y-column is obtained by multiplying the previous value by 5/4. This consistent ratio of 5/4 represents the multiplicative rate of change of the exponential function.

Therefore, the correct answer is option 1: 5.

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Answer:

4 cups

Step-by-step explanation:

2 divided by 1/2 is 4 so there are 4 half cups of sugar.

Since the sugar is multiplied by 4 you have to multiply the flour by 4.

1*4=4

Answer:

3

Step-by-step explanation:

isbscw8sceia a qowbw s

The coordinates of point b' are (-4, 1) and the coordinates of point c' are (-6, 0).

To obtain the coordinates of points b' and c' after the same translation as point a', we need to apply the same translation vector to points b and c.

The translation vector can be found by calculating the differences between the x-coordinates and the y-coordinates of points a' and a.

Translation Vector = (x-coordinate of a' - x-coordinate of a, y-coordinate of a' - y-coordinate of a)

                   = (-2 - 3, -3 - (-4))

                   = (-5, 1)

Now, we can obtain the coordinates of points b' and c' by adding the translation vector to the respective coordinates of points b and c.

For point b':

Coordinates of b' = (x-coordinate of b + x-coordinate of translation vector, y-coordinate of b + y-coordinate of translation vector)

                 = (1 + (-5), 0 + 1)

                 = (-4, 1)

Therefore, the coordinates of point b' are (-4, 1).

For point c':

Coordinates of c' = (x-coordinate of c + x-coordinate of translation vector, y-coordinate of c + y-coordinate of translation vector)

                 = (-1 + (-5), -1 + 1)

                 = (-6, 0)

Therefore, the coordinates of point c' are (-6, 0).

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The other two factors of given polynomial are (x+2) and (2x-1).

A polynomial is an expression in mathematics that solely uses the operations of addition, subtraction, multiplication, and powers of positive-integer variables. It consists of indeterminates and coefficients. The polynomial x2 4x + 7 is an illustration of one with a single indeterminate x.

Sums of terms with the pattern kxn—where k is any positive integer and n is an arbitrary number—are known as polynomials. A polynomial is something like 3x+2x-5. Polynomials: An introduction Using the sum of powers in one or more variables multiplied by coefficients, a polynomial is a type of mathematical expression.

Given that x+3 is a factor of polynomial 2x³ + 9x² + 7x - 6. So that

2x³ + 9x² + 7x - 6

⇒ 2x³ + 6x² + + 3x² + 7x - 6

⇒ 2x²(x+3) + 3x² + 7x - 6

⇒ 2x²(x+3) + 3x² + 9x - 2x - 6

⇒ 2x²(x+3) + 3x(x+3) - 2(x+3)

⇒ (x+3)(2x² + 3x - 2)

⇒ (x+3)(2x² + 4x - x - 2)

⇒ (x+3)[2x(x+2) -1(x+2)]

⇒ (x+3)(x+2)(2x-1)

Hence, Factors of given expression are (x+3)(x+2)(2x-1)

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Answer:

Step-by-step explanation:

108cm3. Explanation: We are given the volume function: V=s3. The rate of change is found using the first derivative of this function.

Many children develop the ability to do simple arithmetic problems during their early childhood years, typically between the ages of 4 and 6. Correct option is a).

During this time, children start to understand basic mathematical concepts such as counting, addition, and subtraction. They may also begin to recognize and name numbers and use basic math vocabulary. However, it's important to note that every child develops at their own pace and some may show these skills earlier or later than others. It's also important for parents and caregivers to provide opportunities for children to practice and reinforce these skills through activities such as counting objects, playing number games, and solving simple math problems.

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Answer:

To evaluate f(x)=1/2x-3 for each value of x, we substitute each value into the function and simplify:

(a) f(-8) = (1/2)(-8) - 3 = -4 - 3 = -7

(b) f(0) = (1/2)(0) - 3 = 0 - 3 = -3

(c) f(3) = (1/2)(3) - 3 = 1.5 - 3 = -1.5

(d) f(10) = (1/2)(10) - 3 = 5 - 3 = 2

Therefore, the values of the function for each value of x are:

(a) f(-8) = -7

(b) f(0) = -3

(c) f(3) = -1.5

(d) f(10) = 2

Answer:

ok question?

Step-by-step explanation:

Completely factored expressions are:

1. x² - 7x - 18 can be factored as:

(x - 9)(x + 2)

Expand the expression using FOIL:

(x - 9)(x + 2) = x² + 2x - 9x - 18 = x² - 7x - 18

2. p² - 5p - 14 can be factored as:

(p - 7)(p + 2)

Expand the expression using FOIL:

(p - 7)(p + 2) = p² + 2p - 7p - 14 = p² - 5p - 14

3. m² - 9m + 8 can be factored as:

(m - 1)(m - 8)

Expand the expression using FOIL:

(m - 1)(m - 8) = m² - 8m - m + 8 = m² - 9m + 8

Therefore, the completely factored expressions are:

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The inequality that shows how much can be added to the regular size for a drink that costs under $4.00 is given as follows:

2.25 + 0.25n < 4.

The drink costs $2.25, plus each of the n additionals cost $0.25, hence the total cost is given as follows:

T(n) = 2.25 + 0.25n.

For a cost under $4, the cost must be less than $4, hence the inequality is given as follows:

2.25 + 0.25n < 4.

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Answer: x=16 this is the answer without the 2 in the beginning of the equation with the 2 there's no solution

Step-by-step explanation:

The number of toffee cookies Sarah baked is:

4x = 4(17) = 68

If 2/7 of the cookies are chocolate cookies then the number of chocolate cookies Sarah baked is:

2/7 x 420 = 120

If 35% of the cookies are raisin cookies then the number of raisin cookies Sarah baked is:

35/100 x 420 = 147

Let the number of toffee cookies be 4x and the number of plain cookies be 5x x is a constant.

The total number of cookies is the sum of the number of chocolate raisin toffee and plain cookies:

Total number of cookies = Number of chocolate cookies + Number of raisin cookies + Number of toffee cookies + Number of plain cookies

Substituting the values we know:

420 = 120 + 147 + 4x + 5x

Simplifying and solving for x:

420 = 267 + 9x

9x = 153

x = 17

The number of toffee cookies Sarah baked is:

4x = 4(17) = 68

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(a) For the function sequence (fn), given by fn(x) = 2^(2sin(nx)): To find the pointwise limit of (fn), we need to evaluate the limit of fn(x) as n approaches infinity for each value of x.

lim(n→∞) fn(x) = lim(n→∞) 2^(2sin(nx))

The limit will depend on the value of x. For some values of x, the limit may exist, while for others it may not exist.

(b) For the function sequence (9n), given by 9n(x) = x + (1/2)^(n√x² + 1):

To find the pointwise limit of (9n), we need to evaluate the limit of 9n(x) as n approaches infinity for each value of x.

lim(n→∞) 9n(x) = lim(n→∞) x + (1/2)^(n√x² + 1)

Similar to the previous sequence, the limit will depend on the value of x. The limit may exist for some values of x and may not exist for others.

(c) For the function sequence (hn), given by hn(x) = x^(4(1+2/n))/√(x² + 1):

To find the pointwise limit of (hn), we need to evaluate the limit of hn(x) as n approaches infinity for each value of x.

lim(n→∞) hn(x) = lim(n→∞) x^(4(1+2/n))/√(x² + 1)

Again, the limit will depend on the value of x. It may exist for some values of x and may not exist for others.

Question 2:

The sequence (Xn) is given by Xn = [10√7]/(10^n), where [r] represents the integral part of the real number r.

The first five terms of the sequence (Xn) are as follows:

X1 = [10√7]/10

X2 = [10√7]/100

X3 = [10√7]/1000

X4 = [10√7]/10000

X5 = [10√7]/100000

To explain why the set Q of rational numbers is not complete using this sequence, we can observe that the terms of the sequence (Xn) approach zero as n approaches infinity. However, the number √7 is irrational, and its square root cannot be expressed as a ratio of two integers. Therefore, no matter how large n becomes, the terms of the sequence will never equal √7 exactly. This shows that there are gaps or missing elements in the sequence, which indicates that the set Q of rational numbers is not complete.

Question 3:

To show that if ƒ: (M, d) → (Y, d) is a continuous and bijective function, then ƒ is a homeomorphism, we need to prove two things:

ƒ is a continuous function.

The inverse function ƒ^(-1) is also continuous.

Since ƒ is given as a continuous function, it satisfies the first condition.

To prove that the inverse function ƒ^(-1) is continuous, we can use the fact that a function is continuous if and only if the pre-image of an open set under the function is open.

Let U be an open set in Y. Since ƒ is bijective, its inverse ƒ^(-1) exists. Now, we need to show that the pre-image of U under ƒ^(-1) is open in M.

Since ƒ is continuous, the pre-image of U under ƒ, denoted by ƒ^(-1)(U), is open in M. Since ƒ is bijective, ƒ^(-1)(U) = (ƒ^(-1))^(-1)(U).

Therefore, the pre-image of U under ƒ^(-1) is open in M, which implies that ƒ^(-1) is continuous.

Hence, we have shown that if ƒ: (M, d) → (Y, d) is a continuous and bijective function, then ƒ is a homeomorphism.

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(a) For the function sequence (fn), given by fn(x) = 2^(2sin(nx)): To find the pointwise limit of (fn), we need to evaluate the limit of fn(x) as n approaches infinity for each value of x.

lim(n→∞) fn(x) = lim(n→∞) 2^(2sin(nx))

The limit will depend on the value of x. For some values of x, the limit may exist, while for others it may not exist.

(b) For the function sequence (9n), given by 9n(x) = x + (1/2)^(n√x² + 1):

To find the pointwise limit of (9n), we need to evaluate the limit of 9n(x) as n approaches infinity for each value of x.

lim(n→∞) 9n(x) = lim(n→∞) x + (1/2)^(n√x² + 1)

Similar to the previous sequence, the limit will depend on the value of x. The limit may exist for some values of x and may not exist for others.

(c) For the function sequence (hn), given by hn(x) = x^(4(1+2/n))/√(x² + 1):

To find the pointwise limit of (hn), we need to evaluate the limit of hn(x) as n approaches infinity for each value of x.

lim(n→∞) hn(x) = lim(n→∞) x^(4(1+2/n))/√(x² + 1)

Again, the limit will depend on the value of x. It may exist for some values of x and may not exist for others.

Question 2:

The sequence (Xn) is given by Xn = [10√7]/(10^n), where [r] represents the integral part of the real number r.

The first five terms of the sequence (Xn) are as follows:

X1 = [10√7]/10

X2 = [10√7]/100

X3 = [10√7]/1000

X4 = [10√7]/10000

X5 = [10√7]/100000

To explain why the set Q of rational numbers is not complete using this sequence, we can observe that the terms of the sequence (Xn) approach zero as n approaches infinity. However, the number √7 is irrational, and its square root cannot be expressed as a ratio of two integers. Therefore, no matter how large n becomes, the terms of the sequence will never equal √7 exactly. This shows that there are gaps or missing elements in the sequence, which indicates that the set Q of rational numbers is not complete.

Question 3:

To show that if ƒ: (M, d) → (Y, d) is a continuous and bijective function, then ƒ is a homeomorphism, we need to prove two things:

ƒ is a continuous function.

The inverse function ƒ^(-1) is also continuous.

Since ƒ is given as a continuous function, it satisfies the first condition.

To prove that the inverse function ƒ^(-1) is continuous, we can use the fact that a function is continuous if and only if the pre-image of an open set under the function is open.

Let U be an open set in Y. Since ƒ is bijective, its inverse ƒ^(-1) exists. Now, we need to show that the pre-image of U under ƒ^(-1) is open in M.

Since ƒ is continuous, the pre-image of U under ƒ, denoted by ƒ^(-1)(U), is open in M. Since ƒ is bijective, ƒ^(-1)(U) = (ƒ^(-1))^(-1)(U).

Therefore, the pre-image of U under ƒ^(-1) is open in M, which implies that ƒ^(-1) is continuous.

Hence, we have shown that if ƒ: (M, d) → (Y, d) is a continuous and bijective function, then ƒ is a homeomorphism.

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