Katie blows up a balloon and ties it so there is a fixed amount of air in the balloon. She wraps a piece of string around the widest part of the balloon, and measures it to find the size of the balloon. She has access to:
-A freezer
-A warm cupboard
-A cold refrigerator
-A normal temperature classroom

Write a plan to collect results to answer the question:

How does the temperature affect the size of a blown up balloon?
​

The total charge that flows while the battery is being charged is approximately 193,939.39 Coulombs.

To calculate the total charge that flows while the battery is being charged, we can use the relationship between electrical energy, potential difference, and charge.

The electrical energy (E) stored in the battery is given as 64 mega Jules (64 MJ). The potential difference (V) provided by the battery is 330 volts. We know that the energy (E) is equal to the product of the potential difference (V) and the charge (Q):

E = V * Q

Since the charging process is 100% efficient, all the electrical energy supplied is stored in the battery. Therefore, we can rearrange the equation to solve for the charge (Q):

Q = E / V

Substituting the given values, we have:

Q = 64 MJ / 330 V

To perform the calculation, we need to convert mega Jules (MJ) to joules (J) since the SI unit of energy is joules. One mega Joule is equal to 1 million joules:

Q = (64 * 10^6 J) / 330 V

Calculating the division:

Q ≈ 193,939.39 Coulombs

Therefore, the total charge that flows while the battery is being charged is approximately 193,939.39 Coulombs.

This value represents the quantity of electric charge transferred during the charging process, and it indicates the amount of electricity that enters the battery.

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Answer:

0.347

Explanation:

Al is the limiting reagent.

Explanation:

The stoichiometry of the reaction is such that 4 moles of Al are required for every 3 moles of diatomic oxygen. This means that if the ratio of Al to diatomic oxygen is greater than 4/3, then the oxygen is the limiting reagent. If the ratio of Al to diatomic oxygen is less than 4/3, then Al is the limiting reagent.

The problem state that the ratio of Al to diatomic oxygen is

0.32

0.26

=

16

13

=

48

39

<

52

39

=

4

3

The ration of Al to diatomic oxygen is less than 4/3, so Al is the limiting reagent.

We can also see this if we ask the question "How much Aluminum" is required to completely react 0.26 moles of diatomic oxygen??

0.26

moles

O

2

×

4

moles

A

l

3

moles

O

2

≈

0.347

moles

A

l

So it would take 0.347 moles of Al to completely react with all of the oxygen, however there is only 0.32 moles of Aluminum present, so there is not enough Al to react with all of the oxygen, and so we say that the Al is the limiting reagent.

The mass of Aluminum are needed to produce 21.6 grams of Aluminum oxide (Al₂O₃) is

Mass of any element is equal to the product of its number of moles and molar mass.

For the compound, Aluminum oxide (Al₂O₃)

The atomic masses of Aluminum is 23 and oxygen is 16.

Molecular or molar mass = ( 2 × 23 ) + ( 3 × 16 ) units

M = 46 + 48 = 94 units

The mass of Aluminum in 1 mole of aluminum oxide ,46 grams in 94 grams

Mass of Aluminum in the given 21.6 g of Aluminum oxide will be;

94 grams of Aluminum oxide contains 46 grams of Aluminum.

21.6 grams of Aluminum oxide will contain ( 46 / 94 ) × 21.6 = 10.57g of Aluminum.

Therefore, 10.57g of Aluminum are needed to produce 21.6 grams of Aluminum oxide (Al₂O₃)

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Answer:

A.

Explanation:

Answer:

Actually both of ya are incorrect, it would be D. 36.5 mL, on study island it says that.

Explanation:

The total number of sigma bonds and lone pairs is four, the hybridization of Al is sp3.

In the first molecule, the central Al atom with a negative charge is bonded to four Cl atoms, each of which has three lone pairs of electrons. To determine the hybridization of the central atom, we count the number of sigma bonds and lone pairs around it. Here, Al is bonded to four Cl atoms and has no lone pairs. Since the total number of sigma bonds and lone pairs is four, the hybridization of Al is sp3.

In the second molecule, the central C atom is double bonded to two S atoms, and each S atom has two lone pairs. Again, we count the number of sigma bonds and lone pairs. Here, the central C atom is bonded to two S atoms (two sigma bonds) and has no lone pairs. Therefore, the hybridization of C is sp.

In the third molecule, the central P atom with a lone pair is bonded to three F atoms, and each F atom has three lone pairs. The central P atom is bonded to three F atoms (three sigma bonds) and has one lone pair. Thus, the hybridization of P is sp3.

The hybridization of the central atoms in the given molecules are as follows:

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Answer: C

Explanation:

We can research about the growth rate of plant that the water has been given, since we already did 10 mL. It would be best if we research more to see if 20 mL is enough water for the plant or will it make the plant go turgid and flaccid!

the no. of Al atoms required to be laid side by side to make up a distance of 4.23 mm is = 4.23/(2 * 143 * 10^(-9) )

= 14790210 atoms of Al.

What is the radius of an atom?

The atomic radius of an atom is the distance between the centre of the nucleus and the outermost electron in each of its energy shells. Since the border is not a clearly defined physical entity, there are many non-equivalent definitions of atomic radius. The four most popular ways to define atomic radius are van der Waals radius, ionic radius, metallic radius, and covalent radius. Due to the challenges of isolating individual atoms to measure their radii, atomic radii are frequently measured in a chemically bonded state; yet, theoretical calculations are simpler when individual atoms are taken into account.

1 pm = 10^(-9) mm

radius of Al atom = 143 pm = 143 * 10^(-9) mm

Diameter of Al atom = 2 * 143 * 10^(-9) mm

Thus, the no. of Al atoms required to be laid side by side to make up a distance of 4.23 mm is = 4.23/(2 * 143 * 10^(-9) )

= 14790210 atoms of Al.

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Answer:

The correct answer is - Pine tree.

Explanation:

Coniferous trees or cone-bearing trees normally called conifers adapted their leaves and have needles like leaves that retain more water. Needles do not appear to be leaves but are modified leaves.

Conifer trees adapt this leaf modification to prevent water loss due to transpiration in the case of dry air or atmosphere. Important members of the conifer trees are pine trees, cedars, spruces, and Pines.

Answer: D. Synthesis

Explanation:

Sodium Oxide + Water = Sodium Hydroxide

Answer:

2

Explanation:

Answer:  There are 6.9 mol of \(F_{2}\) are required to react completely with 2.30 mol of S.

Explanation:

The given reaction equation is as follows.

\(S(s) + 3F_{2}(g) \rightarrow SF_{6}(g)\)

Here, 1 mole of S is reaction with 3 moles of \(F_{2}\) which means 1 mole of S requires 3 moles of \(F_{2}\).

Therefore, moles of \(F_{2}\) required to react completely with 2.30 moles S are calculated as follows.

\(1 mol S = 3 mol F_{2}\\2.30 mol S = 3 mol F_{2} \times 2.30 \\= 6.9 mol F_{2}\)

Thus, we can conclude that there are 6.9 mol of \(F_{2}\) are required to react completely with 2.30 mol of S.

Answer:

The electronic configuration of ions formed are:

Li+ (2) => 1s2

Cl- (18) => 1s2 2s2 2p6 3s2 3p6

Explanation:

Lithium metal, Li will lose 1 electron to lithium ion Li+. Chlorine atom, Cl will receive the 1 electron to form the chloride ion Cl- as shown by the following equation below:

Li —> Li+ + e

Cl+ e —> Cl-

Combine both equation

Li + Cl + e —> Li+ + Cl- + e

Cancel out 'e'

Li + Cl —> Li+ Cl-

Thus, we can write the electronic configuration for the reaction as follow:

Before reaction:

Li (3) => 1s2 2s1

Cl (17) => 1s2 2s2 2p6 3s2 3p5

After reaction

Li+ (2) => 1s2

Cl- (18) => 1s2 2s2 2p6 3s2 3p6

Therefore, the electronic configuration of the ions formed are:

Li+ (2) => 1s2

Cl- (18) => 1s2 2s2 2p6 3s2 3p6

Gold is found in various ionic compounds, but one of the most well-known and commercially significant compounds is gold chloride, also known as auric chloride or gold(III) chloride.

The chemical formula for gold chloride is AuCl₃. Gold chloride is an ionic compound composed of gold cations (Au³⁺) and chloride anions (Cl-). It is a yellow-orange solid that is highly soluble in water. Gold chloride can be formed by reacting the gold metal with chlorine gas or by dissolving the gold metal in aqua regia, which is a mixture of concentrated nitric acid and hydrochloric acid.

Gold chloride has several uses and applications. It is commonly used in the field of nanotechnology for the synthesis of gold nanoparticles. These nanoparticles have unique optical, electronic, and catalytic properties, making them valuable in various fields such as medicine, electronics, and materials science.

In addition to gold chloride, gold can also form other ionic compounds with different anions, such as gold bromide (AuBr), gold iodide (AuI), gold sulfide (Au2S), and gold cyanide (AuCN). These compounds have their own unique properties and applications.

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Answer:

Decrease the distance between them or increase the mass.

Explanation:

F= GM1M2/ R²

Answer:

decrease the distance between the objects

Explanation:

i did the test and got da epic 100 score

Because the transition state is unstable, reactant molecules don't stay there long, but quickly proceed to the next step of the chemical reaction.

According to the context, the term may or may not include ions that meet this requirement. A molecule is a collection of two or more atoms held together by the attractive forces known as chemical bonds. When speaking of polyatomic ions, the distinction between them and ions is frequently ignored in the fields of quantum physics, organic chemistry, and biochemistry.

As our understanding of molecular structure has grown, so has the definition of a molecule. Molecules are the smallest particles of pure chemical substances that nevertheless retain their composition and chemical properties, according to earlier definitions that were less accurate.

The incorruptible quintessence aether, a fifth element, was thought to be the essential component of the heavenly bodies.

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The type of bond present in the picture below for both A and B are “polar covalent bond and "dipole-dipole attraction” respectively.

The ability to form molecules and crystals is made possible by a chemical bond, which is a strong attraction between atoms or ions. The bond may be created by the sharing of electrons in covalent bonds or by the electrostatic interaction between ions that have opposing charges.

Other forms of forces present in molecules of compounds are intermolecular forces such as dipole-dipole attraction" and hydrogen bonds.

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Answer: Technician B

Explanation:

Technician B is correct. The freezing point of a substance is the temperature at which the substance changes state from a liquid to a solid.

Technician A is incorrect. On the other hand, the melting point of a substance is the temperature at which the substance changes state from a solid to a liquid.

The correct answer is option D.

Among the trace minerals, iron is the mineral that is found in highest concentrations in the body.

In human body, there are 21 trace minerals that are expected to be present including copper, zinc, iron cobalt, manganese, and fluoride.

The function of each trace mineral varies and they play huge role in the growth and development process.

For proper functioning of human body, only small quantities of these minerals are required. Among 21 minerals, iron is found in huge quantities.

Certain foods are rich sources of these minerals. However, deficiency or excess of these minerals can lead to serious health issues.

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Answer:

0.125 moles

Explanation:

2.8 litres is equivalent to 2.8dm³

At STP,

1 mole = 22.4 dm³

x mole = 2.8 dm³

Cross multiply

22.4x = 2.8

Divide both sides by 22.4

x = 2.8/22.4

x = 0.125

The molar concentration of a 12% sodium chloride solution is approximately 2.05 M.

To determine the molar concentration of a 12% sodium chloride solution, we need to convert the given percentage concentration into molarity.

First, we need to understand that the percentage concentration refers to the mass of the solute (sodium chloride) relative to the total mass of the solution.

In this case, a 12% sodium chloride solution means that there are 12 grams of sodium chloride in 100 grams of the solution.

To convert this into molar concentration, we need to consider the molar mass of sodium chloride, which is 58.5 g/mol.

We can start by calculating the number of moles of sodium chloride in 12 grams:

Moles of sodium chloride = mass of sodium chloride / molar mass of sodium chloride

Moles of sodium chloride = 12 g / 58.5 g/mol = 0.205 moles

Next, we calculate the volume of the solution in liters using the density of the solution. Since the density is not provided, we assume a density of 1 g/mL for simplicity:

Volume of solution = mass of solution / density

Volume of solution = 100 g / 1 g/mL = 100 mL = 0.1 L

Finally, we calculate the molar concentration (Molarity) by dividing the number of moles by the volume in liters:

Molar concentration = moles of solute / volume of solution

Molar concentration = 0.205 moles / 0.1 L = 2.05 M

Therefore, the molar concentration of a 12% sodium chloride solution is approximately 2.05 M.


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Answer:it’s E cause it yeshp

No, input energy is not equal to useful output energy, if it is an electric toothbrush.

Electrical Energy is the useful type of energy produced in an electric toothbrush.

If input energy is equal to useful output energy. This means that the total amount of energy that is in an isolated system (such as an engine or a generator) remains constant (conserved) over time.

However, the total amount of useful energy output of an isolated system is never equal to the total energy input.

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To determine the theoretical yield of each product, we need to first write the balanced chemical equation for the decomposition of \(NaHCO3\):

\(2NaHCO3\) → \(Na2CO3\) + H2O + CO2

According to the equation, 2 moles of NaHCO3 produce 1 mole of \(Na2CO3\), 1 mole of H2O, and 1 mole of CO2.

Given that the mass of the \(NaHCO3\) sample is 3.24 grams, we can convert this to moles using the molar mass of \(NaHCO3\):

Molar mass of \(NaHCO3\) = 22.99 + 1.01 + 12.01 + (3 * 16.00) = 84.01 g/mol

Moles of \(NaHCO3\) = 3.24 g / 84.01 g/mol = 0.0386 mol

Using stoichiometry, we can calculate the theoretical yield of each product:

Na2CO3: 0.0386 mol \(NaHCO3\) * (1 mol \(Na2CO3\) / 2 mol NaHCO3) = 0.0193 mol Na2CO3

H2O: 0.0386 mol NaHCO3 * (1 mol H2O / 2 mol NaHCO3) = 0.0193 mol H2O

CO2: 0.0386 mol NaHCO3 * (1 mol CO2 / 2 mol NaHCO3) = 0.0193 mol CO2

In the actual decomposition, if the measured mass of one of the products was 2.01 grams, it is likely to be CO2, as its molar mass is lower compared to \(Na2CO3\) and H2O.

To calculate the percent yield, we divide the actual yield (2.01 g) by the theoretical yield of CO2 (0.0193 mol) and multiply by 100:

Percent yield = (2.01 g / (0.0193 mol * 44.01 g/mol)) * 100 = X%

X represents the calculated percent yield.

In summary, the theoretical yields of each product are 0.0193 mol \(Na2CO3\), 0.0193 mol H2O, and 0.0193 mol CO2. The product with a measured mass of 2.01 grams is likely to be CO2. The percent yield can be calculated by dividing the actual yield by the theoretical yield and multiplying by 100.

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Answer:

magnesium + water == magnesium oxide + hydrogen

According to the given picture:

A represents the atomic number.

B represents the chemical symbol.

C represents the atomic mass.

D represents the name of the element.

Answer

a) Ba

b) Si

c) Zn

Explanation

The presence of unpaired electrons in an atom orbitals indicates paramagnetic properties. When no unpaired electron is observed in an atom orbitals, such an atom possesses diamagnetic properties.

Therefore, atoms in their ground states that are expected to be diamagnetic in the options are:

a) Ba

b) Si

c) Zn

Answer:

The molecular geometry would be linear

Explanation:

Carbon Dioxide has 2 electron domains which would result in a linear geometry, they're not bent because they the lone pairs of electrons are pretty far from each other

This should be a diagram of their structure (Sorry for the terrible drawing skills was in a hurry)

Considering the definition of empirical and molecular formula, the empirical formula is C₃H₅O₂ and the molecular formula is C₆H₁₀O₄.

The empirical formula or minimal formula is one that indicates the type of atoms that make up a compound, the minimum ratio of the integer number of atoms and not necessarily the exact number of atoms in it.

The molecular formula is the actual formula of the molecule and indicates the types of atoms and the number of each type involved in the formation of the molecule.

This formula can be obtained from the empirical or minimal formula, as long as the molecular mass of the compound is known. That is, divide the estimated molecular mass divided by the molecular mass of the empirical form. With the multiple obtained, we proceed to multiply the subscripts of the empirical formula, thus obtaining the molecular formula of the compound.

In this case, you know:

Assuming a 100 grams sample, the percentages match the grams in the sample. So you have:

Then it is possible to calculate the number of moles of each atom in the molecule, taking into account the corresponding molar mass:

The empirical formula must be expressed using whole number relationships, for this the numbers of moles are divided by the smallest result of those obtained. In this case:

The empirical formula must be expressed using whole number relationships, so:

Therefore the C: H: O mole ratio is 3: 5: 2

Finally, the empirical formula is C₃H₅O₂.

The molar mass of adipic acid is 146.1 g/mol and the molar mass of empirical formula is 69 g/mole.

Dividing the estimated molecular mass divided by the molecular mass of the empirical form, you get:

146.1 g/mol÷ 69 g/mol ≅ 2

This means that in the molecular formula there are 2 unit formulas, so it is necessary to multiply the number of all atoms by 2:

Molecular formula= 2×C₃H₅O₂

Molecular formula= C₆H₁₀O₄

The molecular formula is C₆H₁₀O₄.

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Answer:

See explanation

Explanation:

Biology- digestion of food materials

Chemistry- dissolving salt in water

Astronomy - observing day and night

Physics - watching a television

Geography - observing weather changes during the day