Kerosene, a common space-heater fuel, is a mixture of hydrocarbons whose "average" formula is C₁₂H₂₆.
(a) Write a balanced equation, using the simplest whole-number coefficients, for the complete combustion of kerosene to gases.

The IUPAC nomenclature system is a set of logical rules devised and used by organic chemists to circumvent problems caused by arbitrary nomenclature.

The 1-ethyl-3-propylcyclopentane molecule contains a total of 30 bond(s) There are 10 non-H bond(s), 3 rotatable bond(s) and 1 five-membered ring(s).

The 1,2-dimethylcyclopentene molecule contains two methyl groups and one double bond in the ring.

The 1,3,5-Triethylbenzene molecule contains three ethyl groups and a benzene ring.

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Answer:

The plum-pudding model did not identify a central nucleus as the source of a positive charge.

Explanation:

Sir Joseph John Thomson, most popularly known as J J Thomson. He was a famous scientist who was awarded the Noble prize for Physics for his discovery of the subatomic particle, electron.

He placed his famous model of an atom which is known as plum pudding model. He proposed that the atoms are described as the negative particles that is floating within a soup of the diffuse positive charge.

But the main defect of his proposal was that it did not recognized the presence of a central nucleus as a positive charged source.

Answer:

The plum-pudding model did not identify a central nucleus as the source of a positive charge.

Explanation:

\(\boxed{\begin{array}{c|c|c|c}\boxed{\bf Element}&\boxed{\bf No\:of\:moles}&\boxed{\bf Sample\:ratio}&\boxed{\bf Simplest\:ratio}\\ \sf C&\sf \dfrac{39.7}{12}=3.3&\sf \dfrac{3.3}{1.65}=2 &\sf 2\\ \sf H&\sf \dfrac{1.65}{1}=1.65&\sf \dfrac{1.65}{1.65}=1 &\sf 1\\ \sf O&\sf \dfrac{58.6}{35.5}=1.65 &\sf\dfrac{1.65}{1.65}=1&\sf 1\end{array}}\)

Empirical formula mass=

\(\\ \sf\longmapsto 3(12)+1+35.5=36+1+35.5=37+35.5=72.5g\)

\(\\ \sf\longmapsto n=\dfrac{Molecular\: formula\:mass}{Empirical\: formula\:mass}=\dfrac{181.5}{72.5}=2.503\approx 3\)

molecular formula

\(\\ \sf\longmapsto 3(C3HCl)=C_9H_3Cl_3\)

Answer:

volume problem

Explanation:

cubic usually means volume

Based on the data given and the equation of reaction:

1. Actual yield of CH₃COOH = 15.96 g

Theoretical yield of CH₃COOH = 29.2 g

The percentage yield = 54.6%

2. The actual yield of CH₃CH₂OH = 21 g

Theoretical yield of CH₃CH₂OH = 29.2

The percentage yield = 72.0%

3. The actual yield of CH₃COOCH₃CH₂ = 24.08 g

Theoretical yield of CH₃COOCH₃CH₂ = 58.39 g

The percentage yield = 41.2%

The percent yield of a reaction is the ratio of the actual yield and the theoretical yield of the reaction expressed as a percentage.

Mathematically;

The actual yield of a reaction is the actual amount of product obtained from a given reaction.

The theoretical yield of a reaction is the amount of product expected from a reaction as given by the equation of the reaction. The theoretical yield of a reaction is always greater than the actual yield of the reaction.

The equation of the given reaction is as follows;

CH₃COOH + CH₃CH₂OH ---> CH₃COOCH₃CH₂ + H₂O

Actual yield of CH₃COOH will be 20 * 789/1000 = 15.96 g

Theoretical yield of CH₃COOH = 29.2 g

The percentage yield will be 15.96/29.2 * 100% =54.6%

The actual yield of CH₃CH₂OH will be 20 * 1.05 = 21 g

Theoretical yield of CH₃CH₂OH = 29.2

The percentage yield will be 21/29.2 * 100% = 72.0%

The actual yield of CH₃COOCH₃CH₂ will be 26.7 * 902/100 = 24.08 g

Theoretical yield of CH₃COOCH₃CH₂ = 58.39 g

The percentage yield will be 24.08/58.39 * 100% = 41.2%

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When sulphide ore is roasted the sulphide ores generally gets converted to their respective oxides and the impurities are also oxidised and removed.

Generally roasting is defined as the process in which the mainly sulphide ores are heated below their melting point in presence of air. The sulphide ores are converted to their respective oxides and the impurities are also oxidized and removed.

During the process of roasting, the ore or the ore concentrate is treated with very hot air. Roasting is the process that is generally applied to sulfide minerals. During the process of roasting, the sulfide ore is usually converted to an oxide, and sulfur is released as sulfur dioxide, a gas.

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The outside temperature in Celsius is approximately -6.34°C.

To solve this problem, we can use the ideal gas law, which relates the pressure (P), volume (V), number of moles (n), and temperature (T) of a gas:

PV = nRT

where R is the gas constant.

Assuming the volume of the tire is constant, we can write:

P1/T1 = P2/T2

where P1 and T1 are the initial pressure and temperature, and P2 and T2 are the final pressure and temperature.

We know that the initial pressure is 32 psi at 32°C, and the final pressure is 28 psi. We want to solve for the final temperature, T2.

First, we need to convert the temperatures to Kelvin (K) by adding 273.15:

T1 = 32°C + 273.15 = 305.15 K

P1 = 32 psi

P2 = 28 psi

Now we can solve for T2:

P1/T1 = P2/T2

T2 = P2 * T1 / P1

T2 = 28 psi * 305.15 K / 32 psi

T2 = 266.81 K

Finally, we convert the temperature back to Celsius:

T2 = 266.81 K - 273.15 = -6.34°C

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Answer:

Water in different phases moves through the atmosphere (transportation). Liquid water flows across land (runoff), into the ground (infiltration and percolation), and through the ground (groundwater). Groundwater moves into plants (plant uptake) and evaporates from plants into the atmosphere (transpiration).

50.1 liters of hydrogen to combine with 18 grams of oxygen to form water at standard conditions. The balanced chemical equation for the reaction between hydrogen and oxygen is:
2H2 + O2 → 2H2O

To calculate the amount of hydrogen needed to combine with 18 grams of oxygen to form water, we need to use the balanced chemical equation for the reaction between hydrogen and oxygen:
2H2 + O2 → 2H2O
From this equation, we can see that two molecules of hydrogen react with one molecule of oxygen to form two molecules of water.
To calculate the amount of hydrogen needed, we first need to convert the 18 grams of oxygen to moles. The molar mass of oxygen is 16 g/mol, so:
18 g O2 × (1 mol O2/16 g O2) = 1.125 mol O2
From the balanced equation, we know that 1 mole of oxygen reacts with 2 moles of hydrogen. Therefore, we need:
1.125 mol O2 × (2 mol H2/1 mol O2) = 2.25 mol H2
To convert from moles to liters, we need to use the ideal gas law:
PV = nRT
where P is the pressure (which we can assume is standard pressure, 1 atm), V is the volume, n is the number of moles, R is the gas constant (0.0821 L·atm/mol·K), and T is the temperature (which we can assume is standard temperature, 273 K).
Solving for V:
V = nRT/P
V = (2.25 mol) × (0.0821 L·atm/mol·K) × (273 K) / (1 atm)
V = 50.1 L
Therefore, we need 50.1 liters of hydrogen to combine with 18 grams of oxygen to form water at standard conditions.

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The east to west daily motions of stars, planets, the Moon, and the Sun are caused by the rotation of the Earth on its axis. The Earth and all the planets revolve around the Sun on circular orbits. This produces the change in constellations observed from one time of year to the next.

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Answer: A chemical symbol is a one- or two-letter designation of an element. Compounds are combinations of two or more elements. A chemical formula is an expression that shows the elements in a compound and the relative proportions of those elements. Many elements have symbols that derive from the Latin name for the element

(a) The limiting reagent is H₃PO₄ and it also acts as the catalyst. (b) The theoretical yield of 2-methylcyclohexene is 8.34 g and the percent yield is 77.9%.

To determine the limiting reagent and catalyst in this reaction, we need to write the balanced chemical equation for the dehydration of 2-methylcyclohexanol with H₃PO₄:

2-methylcyclohexanol → 2-methylcyclohexene + H₂O

The  H₃PO₄ is not consumed in the reaction and therefore acts as a catalyst.

To determine the limiting reagent, we need to calculate the amount of product that would be produced by each reactant, assuming they were the limiting reagent:

For 2-methylcyclohexanol:

Molar mass of 2-methylcyclohexanol = 114.2 g/mol

Number of moles of 2-methylcyclohexanol = 10.0 g / 114.2 g/mol = 0.0875 mol

Number of moles of 2-methylcyclohexene produced = 0.0875 mol

For  H₃PO₄:

Assuming 85%  H₃PO₄ means it is 85% w/w (mass percent):

Mass of  H₃PO₄ = 85% x 10.0 g = 8.5 g

Molar mass of H₃PO₄ = 98.0 g/mol

Number of moles of  H₃PO₄ = 8.5 g / 98.0 g/mol = 0.0867 mol

Number of moles of 2-methylcyclohexene produced = 0.0867 mol

Since the number of moles of 2-methylcyclohexene produced is smaller for the H₃PO₄, it is the limiting reagent. The H₃PO₄ is also the catalyst in this reaction.

To calculate the theoretical yield of 2-methylcyclohexene, we can use the number of moles of the limiting reagent:

Number of moles of 2-methylcyclohexene = 0.0867 mol

Molar mass of 2-methylcyclohexene = 96.2 g/mol

Theoretical yield of 2-methylcyclohexene = 0.0867 mol x 96.2 g/mol = 8.34 g

To calculate the percent yield, we can use the actual yield (6.50 g) and the theoretical yield (8.34 g):

Percent yield = (actual yield / theoretical yield) x 100%

Percent yield = (6.50 g / 8.34 g) x 100% = 77.9%

Therefore, the limiting reagent is H₃PO₄ and it also acts as the catalyst. The theoretical yield of 2-methylcyclohexene is 8.34 g and the percent yield is 77.9%.

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The element that is most likely to pair with beryllium in a 1:1 relationship based on valence electron trends would be Se ( 6 valence electrons ). That is option A.

Valence electron is defined as the electron of an atom that is located at the outermost shell which takes part in formation of chemical bonding during a chemical reaction.

The number of Valence electron of the element beryllium = 2

The number of Valence electron of the selenium = 6

Therefore, both beryllium and selenium can form a chemical bond in a 1:1 relationship based on valence electron trends as both will complete their outer most shell into 8 electrons.

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Answer:

2 .Sulphurous acid

Explanation:

Sulphur dioxide can dissolve in water to form Sulfurous acid(H2SO3). sulphurous acid is weackly dibasic acid. sulphur dioxide is a major component of acid rain since it mixes with vapour in the atmosphere reacting to produce H2So4 .

Answer:

Sulphuric acid

Explanation:

Sulphuric acid is a major component of acid rain since it mixes with water vapour in the atmosphere, reacting to produce Sulphuric acid.

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The Tyndall effect can be used to detect whether an unknown sample is a suspension, colloid, or homogeneous solution.

Light can always travel through a solution, and there is never any general light scattering. Between solutions and suspensions, a colloid exists. By diffusing the incoming light, it produces the Tyndall effect. A suspension is hazy and contains visible suspended particles. The suspensions obstruct the passage of light.

A combination that is heterogeneous and has some of its particles settle out as it stands is called a suspension. Therefore, if a beam of light is passed through your sample and it scatters, it is either a suspension or a colloid. It is a solution if it doesn't scatter.

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The pH of 0.779 M ethylammonium chloride (C2H5NH3Cl) is 10.08. What is ethylammonium chloride? Ethylammonium chloride is a chloride salt that is formed from the reaction between ethylamine and hydrochloric acid.

Ethylamine (C2H5NH2) is the primary component in the synthesis of ethylammonium chloride. When ethylamine is added to hydrochloric acid, a white solid is formed that has the chemical composition C2H5NH3Cl.How to find pH of ethylammonium chloride?The Kb value for ethylamine is given as 4.3 x 10^-4.

The reaction for ethylamine is:C2H5NH2(aq) + H2O(l) ⇌ C2H5NH3+(aq) + OH-(aq)We can assume that ethylammonium chloride is completely ionized. So, we can write:C2H5NH3Cl → C2H5NH3+ + Cl-The hydrolysis of the ethylammonium ion is given by the following equation: C2H5NH3+ (aq) + H2O(l) ⇌ C2H5NH2(aq) + H3O+(aq)Therefore, Kb = [C2H5NH2][H3O+]/[C2H5NH3+]Let's assume x is the H3O+ ion concentration. Then [C2H5NH2] = [H3O+] and [C2H5NH3+] = 0.779 - x.Substituting these values in the above equation, we get the equation: 4.3 x 10^-4 = x^2 / (0.779 - x)By solving the above equation, we can get x, which is the H3O+ ion concentration. Once we get x, we can calculate the pH of the solution, which is given by the equation:pH = - log [H3O+]Finally, by substituting the value of [H3O+] we get the pH of the solution. PH of the solution is 10.08.

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Determine how many mL of solution A (acetic acid-indicator solution) must be added to solution B (sodium acetate-indicator solution) to obtain a buffer solution that is equimolar in acetate and acetic acid. Solution A: 10.0 mL 3.0e-4M bromescol green

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There are actually two types of taxes that working individuals pay on their earnings. The first one is individual income tax, which is a tax levied on the income of individuals or households.

The second one is social insurance taxes, which are taxes collected to fund social security and Medicare programs. Therefore, the correct answer to this question would be (3) individual income tax and social insurance taxes. Sales tax and income tax are not necessarily paid by working individuals on their earnings, so option (5) is not correct.

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2.1 moles of \(H_2O\) will have a mass of 37.8 grams.

The number of moles a substance contains and the mass of the substance are related by the following equation:

Mole = mass/molar mass

In other words, the mole of a substance is the ratio of the mass of the substance and its molar mass.

Rearranging the equation:

Mass = mole x molar mass.

In this case, we want to find the mass of 2.1 moles of water. The molar mass of water can be calculated as follows:

\(H_2O\) = (1 x 2) + 16

       = 18 g/mol

Mass of 2.1 moles of water = 2.1 x 18

                                            = 37.8 grams

In other words, 2.1 moles of water will have a mass of 37.8 grams.

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Two px atomic orbitals were used to form a sigma bonding MO (figureII, lower energy) and a sigma antibonding MO (figure I, higher energy). The bonding MO does not have a node separating the two halves of the orbital.

An atomic orbital is a function in atomic theory and quantum mechanics that describes the location and wave-like behavior of an electron in an atom. This formula can be used to calculate the likelihood of locating any atom's electron in any given location surrounding the nucleus. The phrase atomic orbital can also refer to the actual region or place where the electron is projected to be present given the orbital's mathematical form.

Each orbital in an atom is defined by a set of values of the three quantum numbers n, l, and ml, which correspond to the energy, angular momentum, and an angular momentum vector component of the electron, respectively (magnetic quantum number).

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Answer:

I think its D sorry if im wrong

Answer:i think its D

Explanation:

Answer:

solubility

Explanation:

Salt and water can be mixed until the particles of salt have become very small and are no longer visible.

Solubility is the property that is being demonstrated by this observation.

Thus, Option 4 is correct.

The solubility of a solute is the amount of that solute that can, at a given temperature, dissolve in a known volume of a solvent.

A mixture is said to be homogenous if its composition is constant throughout.

Since the dissolved salt is distributed uniformly throughout the entire salt water sample, the salt water described above is homogenous.

Ionic compounds known as salts include both positively and negatively charged ions. These ions are pulled apart by the water molecule's opposite charge, which attracts them.

Thus, it can be concluded that salt and water when mixed forms a homogenous mixture and thus soluble in nature.

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Answer:

Energy is absorbed in the reaction.

Answer:

Presence of an Electrolyte

Metal Surface

Oxygen or Other Oxidizing Agent

Difference in Potential

Electrochemical Pathway

Explanation:

Answer:

It is caused by currents of electricity that flow in the molten core.

The amount of ideal hydrogen gas is 0.07 moles.

We need to know about the ideal gas theory to solve this problem. The ideal gas is assumed that there is no interaction between particles in a gas. It can be determined by the equation

P . V = n . R . T

where P is pressure, V is volume, n is the number of moles gas, R is the ideal gas constant (62.36 L.torr/mol.K) and T is temperature.

From the question above, we know that

P = 755 torr

Pa = 25 torr

V = 1.87 L

T = 298 K

Find the hydrogen gas pressure

P = Pa + Ph

755 = 25 + Ph

Ph = 730 torr

Find the amount of hydrogen gas

Ph . V = n . R . T

730 . 1.87 = n . 62.36 . 298

n = 0.07 moles

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Answer:

It must be large

Random

Explanation:

For a sample to represent a population accurately, it must be large and contain random sample spaces.

A population is a group of organism of the same species living in a particular place where they can reproduce.

Answer:

141 ml

Explanation: