Kp equals 25 at 500c. The pressure of butane is 20. atm and isobutane is 0.0 atm Calculate the pressure of both gases at equilibrium.

Following the quantic theory, the energy of a photon equals the radiation frequency multiplied by the universal constant. ν = 2.923x10¹⁵ Hz. E = 3.09x10¹⁵Hz.

It is the branch of physics that studies objects and forces at a very low scale, at atoms, subatoms, and particles levels.

Quantum mechanics states that the elemental particles that constitute matter -electrons, neutrons, protons- have the properties of a wave and a particle.

It emerges from the quantic theory exposed by Max Planck (1922), in which he affirmed that light propagates in energy packages or photons.

He discovered the Universal Planck constant, h, used to calculate the energy of a photon.

He stated that the energy of a photon (E) equals the radiation frequency (ν) multiplied by the universal constant (h).

E = νh

In the exposed example, we need to calculate the energy required to change from the 3rd shell to the first shell.

To do it, we should know that the energy in a level (Eₙ) equals the energy associated to an electron in the most inferior energy level (E₁) divided by the square of the shell number (n²).

Eₙ = E₁ / n²

E₁ is a constant. We can express it in Joules or electroVolts

So, let us calculate the energy at level 1 and 3

Eₙ = E₁ / n²

        E₁ =  -13.6 eV / 1² =  -13.6 eV

        E₃ =  -13.6 eV / 3² =  -13.6 eV / 9 = - 1.51 eV

The change of energy can be calculated in two ways,

Option 1

ΔE = E₁ - E₃ = 2.18x10⁻¹⁸ - 2.42x10⁻¹⁹ = 1.93x10⁻¹⁸J

ΔE = E₁ - E₃ = 13.6 - 1.51 = 12.09 eV

Option 2

ΔE = -2.18x10⁻¹⁸ J (1/nf² - 1/ni²)

ΔE =-13.6 eV (1/nf² - 1/ni²)

Where nf is the final level and ni is the initial level. When the electron passes from its initial level to its final level it is called electronic transition.

ΔE = -2.18x10⁻¹⁸ J (1/nf² - 1/ni²)

ΔE = -2.18x10⁻¹⁸ J (1/1² - 1/3²)

ΔE = -2.18x10⁻¹⁸ J (1 - 0.111)

ΔE = -2.18x10⁻¹⁸ J (0.888)

ΔE = - 1.937x10⁻¹⁸ J

or

ΔE = -13.6 eV  (1/nf² - 1/ni²)

ΔE = -13.6 eV  (1/1² - 1/3²)

ΔE = -13.6 eV  (1 - 0.111)

ΔE = -13.6 eV  (0.888)

ΔE = -12.08 eV

This is the energy required for the electron to go from n= 3 to n = 1. The negative sign (-) means energy (as light or photons) released or emitted.

If we want to express the result in Hz, we just need to make a conversion.

1Hz ⇔ 6.626x10⁻³⁴J ⇔ 4.136x10¹⁵ eV.

The energy required for the electron to go from n= 3 to n = 1 is 3.09x10¹⁵ Hz.

Now, we need to calculate the frequency, ν. This is, how many times the wave oscillates back and foward per second.

To do it, we will use the universal Planck constant, h, and the absolute value of the energy, E.

ν = E/h = 1.937x10⁻¹⁸ J / 6.626x10⁻³⁴ Js = 2.923x10¹⁵ 1/s =  2.923x10¹⁵ Hz.

Answer:

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Explanation:

Answer

Open in answr app

Correct option is

A

Precipitation reaction

B

Double displacement reaction

Balanced equation for the reaction is:

KCl(s)+AgNO3(aq)→AgCl(s)+KNO3(aq)

It is a double displacement reaction as both reactants exchange ions to form new products. Also, it is a precipitation reaction as white precipitates of silver chloride(AgCl) are formed.

Answer:

Removing energy (cooling) atoms and molecules decreases their motion, resulting in a decrease in temperature

The temperature of the gas in Kelvin, after its volume is reduced to 2,450 mL, is approximately 143.27 K.

To determine the temperature of the gas in Kelvin after its volume is reduced, we can use the combined gas law, which relates the initial and final conditions of pressure, volume, and temperature for a given amount of gas.

The combined gas law equation is:

(P₁ * V₁) / T₁ = (P₂ * V₂) / T₂

Where P₁ and P₂ are the initial and final pressures, V₁ and V₂ are the initial and final volumes, T₁ is the initial temperature in Kelvin, and T₂ is the final temperature in Kelvin.

Given that the initial volume V₁ is 3,480 mL, the initial temperature T₁ is -70.0 °C (which needs to be converted to Kelvin), and the final volume V₂ is 2,450 mL, we can substitute these values into the equation.

To convert -70.0 °C to Kelvin, we add 273.15 to it, resulting in T₁ = 203.15 K.

Now we can solve for T₂:

(T₂ * V₁) / T₁ = V₂

T₂ = (V₂ * T₁) / V₁ = (2,450 mL * 203.15 K) / 3,480 mL

Simplifying the equation, we find:

T₂ ≈ 143.27 K

Therefore, the temperature of the gas in Kelvin, after its volume is reduced to 2,450 mL, is approximately 143.27 K.

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Using the prefix method for covalent compounds, the names of the given compounds are shown below:

LIF: Lithium fluoride

Cl2O7: Dichlorine heptoxide

N2O3: Dinitrogen trioxide

SF6: Sulfur hexafluoride

Na3PO4: Sodium phosphate

A covalent bond is  described as a chemical bond that involves the sharing of electrons to form electron pairs between atoms.

The properties of covalent compounds includes:

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https://www.khanacademy.org/science/chemistry/chemical-reactions-stoichiome/balancing-chemical-equations/v/balancing-chemical-equations-introduction

this will help trust me

have a good day

The mass of the silver chloride that is formed in the reaction is 4.29 g.

A chemical reaction is a process that leads to the transformation of one set of chemical substances to another.

We know that the balanced reaction equation have been shown in the question as shown.

Number of moles of the silver nitrate = 60/1000 * 0.5

= 0.03 moles

If the reaction is 1:1, then 0.03 moles of silve chloride is formed.

Mass of the silver chloride formed = 0.03 moles * 143 g/mol

= 4.29 g

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Answer:

5.29kg

Explanation:

5.29kg

The mass of 4.87×10²⁵ atoms of Zn is 5.29 Kg

From Avogadro's hypothesis,

Recall,

1 mole of Zn = 65.38 g

Converting 65.38 g to Kilogram (Kg), we have:

1000 g = 1 Kg

Therefore,

65.38 g = 65.38 / 1000

Thus, we can say that,

Finally, we shall determine the mass of Zn that contains 4.87×10²⁵ atoms. This can be obtained as follow:

6.02×10²³ atoms = 0.06538 Kg of Zn

4.87×10²⁵ atoms = \(\frac{4.87*10^{25} * 0.06538}{6.02*10^{23} } \\\\\)

Therefore, the mass of 4.87×10²⁵ atoms of Zn is 5.29 Kg

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Explanation:

H

|

H-C=C-C-OH

| | |

H H H

in this organic compound the functional groups are OH and alkene

prop-2-enol

since it has a double bond, alkene is the functional group. and also it has OH group so hydroxyl group also the other functional group

Answer:

1.03 x 10²³ atoms NaCl

Explanation:

To find the amount of table salt (NaCl) in atoms, you need to (1) convert grams to moles (using the molar mass) and then (2) convert moles to atoms (using Avogadro's Number). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units.

(Step 1)

Molar Mass (NaCl): 22.99 g/mol + 35.45 g/mol

Molar Mass (NaCl): 58.44 g/mol

10 grams NaCl                1 mole
------------------------  x  -----------------------  =  0.17 moles NaCl
                                   58.44 grams

(Step 2)

Avogadro's Number:

6.022 x 10²³ atoms = 1 mole

0.17 moles NaCl           6.022 x 10²³ atoms
--------------------------  x  --------------------------------  =  1.03 x 10²³ atoms NaCl
                                                 1 mole

We can be able to determine the amount of toxic lead in the water by thee use of  atomic absorption spectrophotometry.

A toxic metal is known as any metal that is able to affect the health of people. We know that toxic metals are mostly the metals that are in the group of the heavy metals.

Now we know lead as a metal that is able to cause brain damage especially in children. This is why it is very important that there should be a thorough examination in order to know the amount of lead that is present in water.

There are several methods that could be applied in the determination of lead and one of the most common methods is by the use of atomic absorption spectrophotometry which is able to detect even the minutest amount of the led in solution.

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Answer:

D. Nitrogen, because the ratio of moles is greater than 3:1 for H2:N2

Explanation:

Hello,

In this case, given the reaction:

\(3H_2 + N_2 \rightarrow 2NH_3\)

In order to identify the limiting reactant we must compute the moles of ammonia yielded by both reactants at first:

\(n_{NH_3}^{by\ H_2}=24.0gH_2*\frac{1molH_2}{2molH_2}*\frac{2molNH_3}{3molH_2}=8molNH_3\\ \\n_{NH_3}^{by\ N_2}=8.0gN_2*\frac{1molN_2}{28molN_2}*\frac{2molNH_3}{1molN_2}=0.57molNH_3\)

Thus, since nitrogen yields the smallest amount of ammonia as it is more heavy than hydrogen and it is in a 3:1 mole ratio for H2:N2, it is the limiting reactant, therefore the answer is D. Nitrogen, because the ratio of moles is greater than 3:1 for H2:N2.

Regards.

The boiling point of water is 100.0 °C, the boiling point of the solution will be : 101.49 °C.The correct answer is option (a) 100.00049 °C.

Ideal Solution : An ideal solution is a homogeneous mixture of two or more components that obeys Raoult's law, which states that each component's vapor pressure is proportional to its mole fraction.The boiling point of a solution depends on the solvent's properties and the solute's concentration. It's dependent on the mole fraction of the solvent and solute, as well as the total concentration of the solution. The change in boiling point of a solution is given byΔTb = Kb × m × i, whereKb = ebullioscopic constant, m molarity of the solution, and i = van't Hoff factor.Assuming that the solution's behavior is ideal, we may use the molality of the solution to compute the boiling point elevation of the solution.The molality of the solution is given by the following formula:m = (n₂ / m₂) ÷ (n₁ / m₁), where n is the number of moles, m is the mass, and the subscripts 1 and 2 refer to water and non-volatile solute sucrose, respectively.The molar mass of sucrose (C₁₂H₂₂O₁₁) is342.3 g/mol; therefore, the number of moles of sucrose is115.0 g ÷ 342.3 g/mol = 0.335 mol.m₁ = mass of water = 350.0 g, and m₂ = mass of sucrose = 115.0 g, as given in the problem.Therefore, the molality of the solution is given by:m = (0.335 mol / 0.115 kg) ÷ (1 mol / 1 kg) = 2.91 mol/kg.Substituting these values in the formula for ΔTb, we get:ΔTb = Kb × m = 0.512 °C m⁻¹ × 2.91 mol/kg = 1.49 °C.100.0 °C + 1.49 °C = 101.49 °C.

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Answer:

\(NaBF_4\)

Explanation:

In this reaction, we must exchange the amino group (\(NH_2\)) for a fluorine atom (\(F\)). Also, the first step in this reaction is the addition of nitrous acid.

We must remember that the amino group in the presence of nitrous acid produces a diazonium salt. The \(N_2\) group is a very good leaving group and many benzene derivatives can be produced from this intermediate (see figure 1).

If what we want is to bond a fluorine atom we must use \(NaBF_4\) to be able to produce m-ethylfluorobenzene (see figure 2).

I hope it helps!

Answer:

minimum energy required to to remove the most loosely bound election of an isolated gaseous atom.

Explanation:

With a 20 atomic number and 20 electrons, calcium is an atom. The atom of bromine has an atomic number of 35 and 35 electrons. 13 electrons make up the atom of aluminium, which has an atomic number of 13.

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The waves that  has the greatest wavelength is Wavelength shown with 1 wavelength stretched over a long distance.

A wave could be a disturbance or variety that voyages through a medium or space, carrying vitality without transporting matter. Waves can take different shapes and happen totally different sorts of waves, counting mechanical waves and electromagnetic waves.

Mechanical waves require a medium to propagate, meaning they require a substance like water, discuss, or a strong fabric to transmit the wave. Illustrations of mechanical waves incorporate water waves, sound waves, and seismic waves. In these waves, particles of the medium sway or vibrate in a design, exchanging energy from one molecule to another.

Electromagnetic waves, on the other hand, don't require a medium and can travel through vacuum, such as in space. Electromagnetic waves comprise of electric and attractive areas swaying opposite to each other and to the heading of wave engendering. Illustrations of electromagnetic waves incorporate obvious light, radio waves, microwaves, infrared waves, bright waves, X-rays, and gamma beams.

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Answer:

Explanation:

Answer:

A hypothesis is a suggested solution for an unexplained occurrence that does not fit into current accepted scientific theory.

To make 75.0 mL of 3.50 M HCI, 21.9 mL of 12.0 M HCl must be added. The letter A, 21.9 mL, is the right response among the options.

The space consumed within an object's borders in three dimensions is referred to as its volume. It is sometimes referred to as the object's capacity.

The potential of an object is gauged by its dimensions. For instance, a cup's capacity is stated to really be 100 ml if it can accommodate 100 ml of distilled water in its brim. The quantity of volume occupied by a three-dimensional object can also be used to describe volume.

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Inter-conversion of glucose and fructose occurs with an equilibrium constant of 1.0. Glucose isomerase catalyzes this reaction. The final concentration of fructose at equilibrium from 40mM glucose is a. 40 mM.

Using this formula to find the  final concentration of fructose

Final concentration of fructose  =Equilibrium from glucose/ Equilibrium constant

Where:

Equilibrium constant = 1.0

Equilibrium from glucose = 40 mM

Let plug in the formula

Final concentration of fructose  = 40mM / 1.0

Final concentration of fructose  =  40mM

Therefore we can conclude that the correct option is A.

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The complete question is:

Inter-conversion of glucose and fructose occurs with an equilibrium constant of 1.0. Glucose isomerase catalyzes this reaction. The final concentration of fructose at equilibrium from 40mM glucose is

a. 40 mM

b. 20 mM

c. 10 mM

d. 0 mM​

The gas that has a volume of 752 mL at 1.98 atm and 62°C is most likely NO₂ (option D).

The volume of a sample of gas can be calculated using the following formula:

PV = nRT

Where;

According to this question, the volume of a sample of gas (2.49 g) was 752 mL at 1.98 atm and 62°C. The number of moles is as follows:

1.98 × 0.752 = n × 0.0821 × 335

1.489 = 27.5n

n = 0.054mol

molar mass of the gas = 2.49g ÷ 0.054mol = 45.99g/mol

The gaseous substance with the molar mass of 45.99g/mol is NO₂.

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1) The pH is 2.5

2) The pH is 11.5

3) The initial concentration is\(2.1 * 10^-14\)M

pH is a measure of the acidity or basicity of a solution. It is defined as the negative logarithm of the concentration of hydrogen ions in the solution.

1) The pH of the solution can be gotten from;

K = \(x^2\)/0.65 - x

\(1.754 * 10^-5\)(0.65 - x) =  \(x^2\)

\(1.14 * 10^-5 - 1.754 * 10^-5x = x^2\\x^2 + 1.754 * 10^-5x - 1.14 * 10^-5 = 0\)

x = 0.003 M

pH = -log(0.003)

= 2.5

2) Kb = \(x^2\)/0.35 - x

\(1.8 * 10^-5 (0.35 - x) = x^2\\6.3 * 10^-6 - 1.8 * 10^-5x = x^2\\x^2 + 1.8 * 10^-5x - 6.3 * 10^-6 = 0\)

x = 0.003 M

pOH = -log (0.003)

= 2.5

pH = 14 - 2.5 = 11.5

3) Hydrogen ion concentration = Antilog (-11.5)

= 3.2 * 10^-12 M

\(4.9 * 10^-10 = ( 3.2 * 10^-12)^2/x \\4.9 * 10^-10x = ( 3.2 * 10^-12)^2\\x = ( 3.2 * 10^-12)^2/4.9 * 10^-10\\x = 2.1 * 10^-14 M\)

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Answer:

Explanation:

Concentration of Hg⁺² = 7.36 x 10⁻⁴ M

Concentration of Al⁺³ = 1.05 M

2Al + 3Hg⁺² = 2Al⁺³ + 3Hg .

E = E₀ + RT / nF ln [ Al⁺³]² / [ Hg⁺² ]³

E₀ = reduction potential of  Hg⁺² minus reduction potential of  Al⁺³

= 0.92 V - ( - 1.66 V )

= 2.58 V

E = 2.58  + .059 /n  log  [ Al⁺³]² / [ Hg⁺² ]³

n = 6 , [Al⁺³] = 1.05 M ; [Hg⁺²] = 7.36 x 10⁻⁴ M

E = 2.58  + .059 /6  log  [ 1.05]² / [ 7.36 x 10⁻⁴ ]³

= 2.58  + .059 /6  log  27.65 x 10⁸ .

= 2.58  + .059 /6  [8+ log  27.65 ].

= 2.58  + .059 /6  [8+ log  27.65 ].

= 2.58  + .09

= 2.67 V .

Answer:

4.25g

Explanation:

Molar concentration or molarity can be calculated thus;

Molarity (M) = number of moles (n) ÷ volume (V)

According to the provided information in this question, Volume = 5.0L, M = 0.050 M

number of moles = molarity × volume

n = 0.050 × 5

n = 0.25moles

Number of moles in a substance = mass (M) ÷ molar mass (MM)

Molar mass of ammonia (NH3) = 14 + 1(3)

= 17g/mol

Mass = moles × molar mass

Mass (g) = 0.25 × 17

Mass = 4.25g

The condensed structural formulas as a bond-line formula are given in the attachment:

1. (CH3)2CHCH2CH3

2. CH2=C(CH2CH3)2

3. CH3CHCICH2CH(CH3)2

A bond-line formula, also known as a line-angle formula or skeletal formula, is a shorthand representation of a molecule in which the carbon and hydrogen atoms are implied and only the bonds between the atoms are shown.

In this representation, each vertex or endpoint of a line represents a carbon atom, and each line segment represents a bond between two adjacent atoms. The hydrogen atoms are not shown explicitly, but are assumed to be attached to the carbon atoms to satisfy the valence requirements.

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The half-life of the phosphorus-32, given the data is 14.3 days

Half-life is the time taken for half a material to decay.

We'll begin by obtaing the number of half-lives that has elapsed. This can be obtained as follow:

2ⁿ = N₀ / N

2ⁿ = 1.2 / 0.3

2ⁿ = 4

Express 4 in index form

2ⁿ = 2²

n = 2

Thus, 2 half-lives has elapsed.

The half-life of the phosphorus-32 can be obtained as follow:

t½ = t / n

t½ = 28.6 / 2

t½ = 14.3 days

Thus, the half-life of the phosphorus-32 14.3 days

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The kinetic equation for the given reaction is first-order with respect to the reactant, and the rate constant is zero.

To determine the kinetic equation and rate constant for the given data, we need to analyze the relationship between the concentration of the reactant and time.

The general form of a first-order reaction is given by the equation:

Rate = k[A]^n

Where:

Rate is the rate of the reaction

k is the rate constant

[A] is the concentration of the reactant

n is the order of the reaction with respect to the reactant

By analyzing the given data, we can calculate the reaction rate and determine the order of the reaction and the rate constant.

Let's first calculate the reaction rate using the initial and final concentrations and the corresponding time intervals:

Rate = (Change in concentration) / (Change in time)

For the first time interval (0 to 10 min):

Rate = (13.2 kg·m^(-3) - 16.0 kg·m^(-3)) / (10 min - 0 min) = -2.8 kg·m^(-3)·min^(-1)

Similarly, we can calculate the rates for the other time intervals:

10 to 20 min: Rate = (11.1 kg·m^(-3) - 13.2 kg·m^(-3)) / (20 min - 10 min) = -2.1 kg·m^(-3)·min^(-1)

20 to 35 min: Rate = (8.8 kg·m^(-3) - 11.1 kg·m^(-3)) / (35 min - 20 min) = -2.3 kg·m^(-3)·min^(-1)

35 to 50 min: Rate = (7.1 kg·m^(-3) - 8.8 kg·m^(-3)) / (50 min - 35 min) = -1.7 kg·m^(-3)·min^(-1)

By observing the rates for different time intervals, we can see that the rate of change in concentration does not remain constant. This suggests that the reaction is not first-order with respect to the reactant.

To determine the order of the reaction, we can examine how the rate changes with the concentration. Let's calculate the rate ratios for the different time intervals:

Rate ratio (10/0) = (-2.8 kg·m^(-3)·min^(-1)) / (-2.8 kg·m^(-3)·min^(-1)) = 1

Rate ratio (20/10) = (-2.1 kg·m^(-3)·min^(-1)) / (-2.8 kg·m^(-3)·min^(-1)) ≈ 0.75

Rate ratio (35/20) = (-2.3 kg·m^(-3)·min^(-1)) / (-2.1 kg·m^(-3)·min^(-1)) ≈ 1.10

Rate ratio (50/35) = (-1.7 kg·m^(-3)·min^(-1)) / (-2.3 kg·m^(-3)·min^(-1)) ≈ 0.74

By observing the rate ratios, we can see that they are not constant, indicating that the reaction is not a simple integer order (e.g., first-order or second-order). However, we can approximate the order of the reaction by calculating the average rate ratio:

Average rate ratio = (1 + 0.75 + 1.10 + 0.74) / 4 ≈ 0.897

The order of the reaction can be approximated as the exponent that gives this average rate ratio. In this case, the order is approximately 0.897, which we can round to 1. Therefore, the kinetic equation for the reaction is:

Rate = k[A]^1.5

Now, to determine the rate constant (k), we can choose any set of data points and solve for k. Let's use the first data point at time = 0 min:

16.0 kg·m^(-3) = k * (0 min)^1.5

Since (0 min)^1.5 is zero, the right side of the equation is zero. Therefore, k must be zero as well.

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