lan often takes his dog to the park. He estimates that 30% of the other dogs he sees are retrievers, 20% are terriers and 20% are german shepherds. He designs a simulation. According to the simulation what is the probility that at least one of the next five dogs he see's is a terrier

The right answer is -8/3

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Answer:

\(slope = \frac{8}{ - 3} \)

Step-by-step explanation:

\((4 \: \: \: ,\: \: 18) = > (x1 \: \: ,\: \: y1) \\ (7 \: , \: \: \: \: \: 10) = > (x2 \: \: \: ,\: \: y2)\)

\(slope \\ = \frac{y1 - y2}{x1 - x2} \\ = \frac{18 - 10}{4 - 7} \\ = \frac{8}{ - 3} \)

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The total cost function is the sum of the two given functions, and this is equal to:

c(t) = 190 + 70*t

We know that:

If she hires both of them for the same time t, then the total cost function will be given by the sum of the two above functions, we will get:

c(t) = p(t) + e(t)

c(t) = (115 + 25*t) + (55*t + 75)

c(t) = (115 + 75) + (55*t + 25*t)

c(t) = 190 + 70*t

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Answer: the tenths place

Step-by-step explanation:

If Naya is filling up the gas tank in her motorcycle she puts 4.145 gallons of gas in the tank if the gas cost $2.57 per gallon then she spend $10.65

The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.

Given,

The cost of one gallon of gas =$2.57

The quantity of gas she puts in the tank = 4.145 gallons

Apply unitary method

Then, the cost of 4.145 gallons of gas = Cost of one gallon of the gas × Quantity of gas

The cost of 4.145 gallons of gas= 2.57×4.145= $10.65

Hence, If Naya is filling up the gas tank in her motorcycle she puts 4.145 gallons of gas in the tank if the gas cost $2.57 per gallon then she spend  $10.65

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The stationing of the end of the excavation is Station 2+080.

The volume of fill by end area method is 1440 cubic meters.

The volume of excavation by end area is 1080 cubic meters.

We have,

The stationing of the end of excavation can be determined by adding the given sections to the starting station.

Assuming the starting station is Station 2+020, the end of excavation would be at Station 2+080 (given as Station 2+020 + 60 meters).

To find the volume of fill by end area method, we need to calculate the area of the end section and multiply it by the distance between the start and end stations.

Given that the base for fill is 12 meters and the sideslope for fill is 2:1, the area of the end section can be calculated as follows:

Area of end section = (Base for fill) * (Sideslope for fill)

Area of end section = 12 * (2/1) = 24 square meters

Now, multiply the area of the end section by the distance between the start and end stations (60 meters) to find the volume of fill:

Volume of fill = Area of end section * Distance

Volume of fill = 24 * 60 = 1440 cubic meters

Therefore, the volume of fill by end area method is 1440 cubic meters.

Similarly, to compute the volume of excavation by end area, we calculate the area of the end section (base for cut * sideslope for cut) and multiply it by the distance between the start and end stations. Given that the base for cut is 12 meters and the sideslope for cut is 1.5:1, the area of the end section can be calculated as follows:

Area of end section = (Base for cut) * (Sideslope for cut)

Area of end section = 12 * (1.5/1) = 18 square meters

Multiply the area of the end section by the distance between the start and end stations (60 meters) to find the volume of excavation:

Volume of excavation = Area of end section * Distance

Volume of excavation = 18 * 60 = 1080 cubic meters

Therefore, the volume of excavation by end area is 1080 cubic meters.

Thus,

The stationing of the end of the excavation is Station 2+080.

The volume of fill by end area method is 1440 cubic meters.

The volume of excavation by end area is 1080 cubic meters.

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Answer:

To find this out, you simply multiply 6x5 which is 30

Answer:

\(\huge \boxed{8\sqrt{3}}\)

Step-by-step explanation:

\(2\sqrt{48}\)

Simplify \(\sqrt{48}\).

\(2\sqrt{16} \sqrt{3}\)

\(\sqrt{16}=4\)

\(2 \times 4\sqrt{3}\)

Apply rule : \(a \times b\sqrt{c} =ab\sqrt{c}\)

\(8\sqrt{3}\)

Answer:

2x - 5 if x ≤ 2

f(-1) = -7

Step-by-step explanation:

x ≤ 2 = (-1) ≤ 2

x > 2 = (-1) > 2

2x - 5

2(-1) - 5

-2 - 5

-7

The area of the top surface of the wedge is 9 × pi square inches.

To find the area of the top surface of the wedge, we first need to find the area of the whole circle with radius 6 inches. The formula for the area of a circle is A = pi × \(r^2\), where A is the area and r is the radius.

So, A = pi × \((6)^2\) = 36 × pi square inches.

Since the central angle of the wedge is pi/2 radians, we can find the fraction of the circle that is represented by the wedge by dividing pi/2 by 2 × pi (the total number of radians in a circle).

So, the fraction of the circle represented by the wedge is pi/2 / 2 × pi = 1/4.

To find the area of the top surface of the wedge, we simply multiply the area of the whole circle by this fraction:

Area of top surface = (1/4) × 36 × pi = 9 × pi square inches.

Therefore, the area of the top surface of the wedge is 9 × pi square inches.

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Answer:

Step-by-step explanation:

in this expression we have

two variables: 6x and 10p

one constant 5

3 terms

Answer:

Committee of Public Information

Step-by-step explanation:

The optimal allocation is x = -1/2, y = 3/2, with a shadow price of 1.50.

To maximize profit, the firm needs to determine the optimal allocation of inputs x and y within the budget constraint of $100.

Let's assume the firm uses 'a' units of input x and 'b' units of input y. Since each unit of x costs $2 and each unit of y costs $3, the total cost constraint can be expressed as:

2a + 3b ≤ 100

To maximize profit, we need to differentiate the profit function P(x, y) with respect to both inputs and set the derivatives equal to zero:

∂P/∂x = 2y - 3 = 0 ---> y = 3/2

∂P/∂y = 2x + 1 = 0 ---> x = -1/2

However, x and y cannot have negative values, so these values are not feasible. To find the feasible values, we can substitute the values of x and y into the cost constraint:

2(-1/2) + 3(3/2) = 0 + 9/2 = 9/2 ≤ 100

This constraint is satisfied, so the feasible allocation is x = -1/2 and y = 3/2.

To find the shadow price, we need to determine the rate at which the maximum profit would change with respect to a one-unit increase in the budget constraint. We can do this by finding the derivative of the profit function with respect to the cost constraint:

∂P/∂(2a + 3b) = λ

Where λ represents the shadow price or the marginal value of an additional dollar in the budget. In this case, λ is the shadow price.

Taking the derivative of the profit function with respect to the cost constraint:

∂P/∂(2a + 3b) = ∂(2xy - 3x + y)/∂(2a + 3b) = 0

2y - 3 = 0 ---> y = 3/2

Thus, the shadow price (λ) is 3/2 or 1.50 when rounded to two decimal places.

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Answer:

Step-by-step explanation:

We know that cosx = sin(\(\pi\) - x)

We can apply it here:

sin(55°) = cosx

cos(\(\pi\) - 55°) = cosx

Now we apply the arccos to both sides:

x = \(\pi\) - 55° + 2k\(\pi\) or x = -\(\pi\) - 55° + 2k\(\pi\)

The common difference of the arithmetic sequence is d = 3.

What is an Arithmetic sequence?

An arithmetic progression, also referred to as an arithmetic sequence, is a set of numbers where each term following the first is derived by adding a fixed constant number to the term before it.

To solve this problem, we can use the formula for the nth term of an arithmetic sequence. The formula is as follows:

an = a1 + (n - 1)d

Where an is the sequence's nth term, a1 is the first term, d is a common difference, and n is the number of terms we want to discover:

We know that a1 = 10 and a4 = 19. By entering these numbers into the formula, we obtain:

          a4 = a1 + (4 - 1)d

          19 = 10 + 3d

In order to find d, we can divide by 3 after subtracting 10 from both sides:

          9 = 3d

          d = 3

Therefore, the common difference of the arithmetic sequence is d = 3.

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The roots of the quadratic equation 0 = 2x² + 12x-14 is (C) x=-7 and x=1.

Any equation in algebra that can be written in the standard form where x stands for an unknown value and a, b, and c stand for known values is said to be a quadratic equation.

In general, it is assumed that a > 0; equations with a = 0 are regarded as degenerate since they become linear or even simpler.

So, the roots of 0 = 2x² + 12x-14 are:

2x² + 12x-14  = 0

2x² + 14x - 2x -14

2x(x + 7) - 2(x + 7)

(2x - 2) (x + 7)

Now, use the zero product property as follows:

2x - 2 = 0

2x = 2

x = 2/2

x = 1

And

x + 7 = 0

x = -7

Therefore, the roots of the quadratic equation 0 = 2x² + 12x-14 is (C) x = -7 and x = 1.

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Correct question:

What are the roots of the quadratic equation 0 = 2x² + 12x-14?

a. 1,6, -7

b. 2,12,-14

c. -7,1

d. -1,7

The price that Maura sell each scarf would be =$33. Maura sells each scarf for $33. That is option A.

To calculate the amount of money that Maura spends on each scarf the following is carried out.

The amount of money that she spends on the scarf material = $5.50

The percentage selling price of each scarf = 600% of $5.50

That is ;

= 600/100 × 5.50/1

= 3300/100

= $33.

Therefore, each price that is sold by Maura would probably cost a total of $33.

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The resulting value after the subtraction of 15/57 - 6/45 is 37/285

Subtraction:

Subtraction is an arithmetic operation that represents the operation of removing the particular objects from a collection.

It is signified by the minus sign, −.

Given,

Here we need to find the value of the subtraction of 15/57 - 6/45.

The fractions have unlike denominators.

First, find the Least Common Denominator and rewrite the fractions with the common denominator.

LCD(57, 45) = 855

Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD.

This is basically multiplying each fraction by 1.

\(\frac{15}{57}\times\frac{15}{15}-\frac{6}{45}\times\frac{19}{19}\)

Complete the multiplication and the equation becomes

=> 225/855 - 114/855

Complete the multiplication and the equation becomes

=> 111/855

This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 111 and 855 using

GCF(111,855) = 3

\(= > \frac{111 \div 3}{855 \div 3} = \frac{37}{285}\)

Therefore, resulting value is 37/285.

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ANSWER

The other two zeros are

• 3 + 2i

• 3 - 2i

EXPLANATION

If the zeros of a polynomial are x1, x2, x3... the polinomial function can be written in a factored form,

Hence, if we know that one of the zeros of f(x) is -4, that means that (x + 4) is a factor. Thus, we can divide the polynomial by that factor,

So f(x) is,

To find the other two zeros now we just have to find the zeros of the second factor (x² - 6x + 13), which is much easier because we can simply use the quadratic formula,

In this case a = 1, b = -6 and c = 13,

Note that the number under the radical is negative. Therefore the other two zeros are not real - in other words, in the real numbers set this function has only one zero: -4.

In the complex number set we know that i² = -1, so we can replace the minus sign under the radical by i²,

And solve the square root,

We can distribute the denominator into the sum/subtraction,

And we get that the other two zeros are,

This agrees with the complex conjugate root theorem, which states that

Answer:

3/4%= 75

3/25%= 12

I think you might have meant what is 3/4 as a percent and what is 3/25 as a percent.  If that is what you meant then here are the answers to that:

3/4 = .75 = 75%

3/25 = .12 = 12%

Answer:

20 students

Step-by-step explanation:

Given that

There are 200 students surveyed

And, the percentage of each games is as follows;

For tennis it is 10%

For basketball it is 30%

For football it is 35%

for baseball it is 25%

We need to find the number of students choose tennis

So, it should be

= 10% of 200

= 20 students

Answer:

(-1, -4.5)

(-1.5, -2.5)

Step-by-step explanation:

To find the midpoint add the coordinates and divide by 2

19.( -8,-2) (6,-7)

((-8+6)/2, (-2+-7)/2) = (-2/2, -9/2) = (-1, -4.5)

20. ( 6,5) (-8,-10)

(( 6+-8)/2 , (5-10)/2) = (-3/2,-5/2) = (-1.5, -2.5)

Answer:

19. (-1, -4.5)

20. (-1, -2.5)

Step-by-step explanation:

19.

Use the midpoint formula.

\(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\)

Substitute the values.

\(\frac{-8+6}{2},\frac{-2-7}{2}\)

Add/Subtract the numerators.

\(\frac{-2}{2},\frac{-9}{2}\)

Divide.

-1, -4.5

20.

Use the midpoint formula.

\(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\)

Substitute the values.

\(\frac{6-8}{2},\frac{5-10}{2}\)

Add/Subtract the numerators.

\(\frac{-2}{2},\frac{-5}{2}\)

Divide.

-1, -2.5

The equation of g(x) is 24 (3)ˣ when the graph is stretched vertically by a factor of 3 to form the graph g(x).

What is function?

For the parent function f(x) and a constant k >0,

then, the function given by  

g(x) = kf(x) can be sketched by vertically stretching f(x) by a factor of k if k>1 (or)

if 0 < k < 1 , then it is vertically shrinking f(x) by a factor of k

As per the given statement that the graph of f(x) is stretched vertically by a factor of 3 i.e

k = 3 >1

so, by definition

g(x) = 3 f(x) = 3 . 8(3)ˣ

= 8(3)ˣ⁺¹

= 24 (3)ˣ

Hence, the equation of g(x) is 24 (3)ˣ when the graph is stretched vertically by a factor of 3 to form the graph g(x).

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Answer:

The slope would be -2/2 or when simplified, -1.

Answer:

-1

Step-by-step explanation:

Answer:

(2/3)^6 or 64/729

Step-by-step explanation:

Simplifying exponents.

We can simplify this expression by factoring the numerator and denominator into their prime factors.

6^6 can be written as (2 x 3)^6, which is equal to 2^6 x 3^6.

9^6 can be written as (3^2)^6, which is equal to 3^(2x6) or 3^12.

So, 6^6 / 9^6 can be written as:

(2^6 x 3^6) / 3^12

We can simplify this by canceling out common factors in the numerator and denominator:

Now, we can calculate this easily:

2^6 = 64 and 3^6 = 729

So, 6^6 / 9^6 = 64 / 729

ChatGPT

Answer:

3:25 pm

Step-by-step explanation:

The distance between New Orleans and Houston is : 353 miles

Departure time of the bus : 12:20 pm

Speed of the bus: 60 mph

After 45 minutes, the bus will be at a distance of : 45/60 * 60 = 45 miles

Distance remaining to cover = 353-45 = 308 miles

Speed of the motorcycle = 72 mph

Relative speed = 60 + 72 = 132 mph

Time the two will meet = 308 / 132 =  7/3 hrs

7/3 hrs = 2 hrs  20 minutes

Time the two will meet is ;

12:20 pm + 45 minutes + 2 hrs 20 minutes

= 3:25 pm

Both the bus and the motorcycle are driving opposite to each other.

From the given data, the time at which both the bus and the motorcycle will pass each other is 3:25 PM

The time at which both the motorcycle and the  bus will pass each other.

Let after t hour from the time when motorcycle starts, they both meet.

Then we have:

353 miles = 45 minute traveled by bus + distance traveled by bus in t hour + distance traveled by motorcycle in t time.

Since 45 minutes is three fourth of an hour, thus:

Distance traveled by bus in 45 minutes is calculated as:

\(D_{Bus}(45 \:\rm min) = 60 \times \dfrac{3}{4} \: \rm miles = 45 \: \rm miles\)

Distance traveled by bus in t hours is:

\(D_{Bus}(t \: \rm hours) = 60 \times t \: \rm miles = 60t \: \rm miles\)

Distance traveled by motorcycle in t hour is:

\(D_{motorcycle}(t \: \rm hours) = 72 \times t \: \rm miles = 72t \: \rm miles.\)

Thus, we have:

\(353 = 60t + 72t + 45\\\\308= 132t\\\\t = \dfrac{308}{132}\\\\t= \dfrac{7}{3}\: \rm hours\\\\t=2 \: \rm hours + 20 \: \rm minutes\)

Thus, time at which they meet was 12:20 PM + 45 minutes + 2 hours + 20 minutes = 3:25 PM

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The answer chancedavis673 is

5.66 meters or 566 centimeters

because

Every 100 centimeters is a meter so 1534 centimeters is 15.34 meters. Then subtract the values to get 5.66.

The polar equation r = 1 + 2cos(θ) represents a cardioid, a heart-shaped curve.

To sketch the graph of the equation r = 1 + 2cos(θ) in Cartesian coordinates, we can substitute r with x and θ with y. This gives us the equation x = 1 + 2cos(y). By choosing values for y and calculating the corresponding x values, we can plot points to form the graph.

The resulting graph will show a cardioid shape, resembling a heart with a cusp at the origin. The cosine term causes the curve to oscillate symmetrically between a minimum of 1 and a maximum of 3 in the x-direction.

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Answer:

its c or d

Step-by-step explanation:

The empirical rule tells us that for a normal distribution with mean μ and standard deviation σ, approximately 99.7% of the observations fall between 98 and 122.

Since the distribution is bell-shaped, we can use the empirical rule (also known as the 68-95-99.7 rule) to estimate the percentage of observations that fall within certain ranges.

According to the empirical rule, for a normal distribution with mean μ and standard deviation σ:

About 68% of the observations fall within one standard deviation of the mean, i.e., between μ - σ and μ + σ.

About 95% of the observations fall within two standard deviations of the mean, i.e., between μ - 2σ and μ + 2σ.

About 99.7% of the observations fall within three standard deviations of the mean, i.e., between μ - 3σ and μ + 3σ.

In this case, the mean is 110 and the standard deviation is 4. Therefore:

About 68% of the observations fall between 110 - 4 = 106 and 110 + 4 = 114.

About 95% of the observations fall between 110 - 2(4) = 102 and 110 + 2(4) = 118.

About 99.7% of the observations fall between 110 - 3(4) = 98 and 110 + 3(4) = 122.

So approximately 99.7% of the observations fall between 98 and 122.

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Answer:

15.4 minutes :)

Step-by-step explanation:

We need to turn the percentage into a decimal first :)

27/100 = 0.27

Now we multiply it by 57 to see how much time has gone by!! :)

0.27 x 57 = 15.39

Now to finish, we round!

9> 5

So 3 becomes 4

She has been on the treadmill for 15.4 minutes!

Now you know how to solve this type of problem!!

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