Last week's and this week's low temperatures are shown in the table below.
Low Temperatures for 5 Days This Week and Last Week
Low Temperatures
This Week (°F)
4
10
6
9
6
Low Temperatures
Last Week (°F)
13
9
5
8 5
Which measures of center or variability are greater than 5 degrees? Select three choices.
the mean of this week's temperatures
the mean of last week's temperatures
the range of this week's temperatures
the mean absolute deviation of this week's temperatures
the mean absolute deviation of last week's temperatures
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Answer:

\(43.78^\circ\)

Step-by-step explanation:

Let θ  be the angle that the base of the leaning tower makes with the tower i.e. the angle of elevation

Since this is a right triangle we have the relationship

\(\tan\theta = \dfrac{height}{base} = \dfrac{46}{48} \approx 0.95833\\\\\)

\(\theta = tan^{-1} (0.95833) = 43.78^\circ\)

Answer
\(= 43.78^\circ\)

The angle of elevation is given by the trigonometric relation and θ = 73.40°

What are trigonometric relations?

Trigonometry is the study of the relationships between the angles and the lengths of the sides of triangles

The six trigonometric functions are sin , cos , tan , cosec , sec and cot

Let the angle be θ , such that

sin θ = opposite / hypotenuse

cos θ = adjacent / hypotenuse

tan θ = opposite / adjacent

tan θ = sin θ / cos θ

cosec θ = 1/sin θ

sec θ = 1/cos θ

cot θ = 1/tan θ

Given data ,

Let the angle of elevation be represented as E = θ

Now , the measure of the altitude = 46 m

The measure of the hypotenuse = 48 m

And , the angle of elevation is given by the trigonometric relation ,

sin θ = opposite / hypotenuse

On simplifying , we get

sin θ = 46 / 48

sin θ = 0.958333

Taking inverse on both sides , we get

θ = sin ⁻¹ ( 0.958333 )

θ = 73.40°

Hence , the angle of elevation is 73.40°

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Answer:

a) There is a 59.87% probability that none of the LED light bulbs are defective.

b) There is a 31.51% probability that exactly one of the light bulbs is defective.

c) There is a 98.84% probability that two or fewer of the LED light bulbs are defective.

d) There is a 100% probability that three or more of the LED light bulbs are not defective.Step-by-step

explanation:

For each light bulb, there are only two possible outcomes. Either it fails, or it does not. This means that we use the binomial probability distribution to solve this problem.

The exact values of the remaining trigonometric functions of θ are:

sin(θ) = √(1/64)

cos(θ) = -8

tan(θ) = -8√(1/64)

csc(θ) = 1

cot(θ) = -√(1/64) / 8

Given that sec(θ) = -8 and sin(θ) > 0, we can find the exact values of the remaining trigonometric functions using the Pythagorean identity:

sec^2(θ) = 1/sin^2(θ)

Substituting the value of sec(θ), we have:

(-8)^2 = 1/sin^2(θ)

64 = 1/sin^2(θ)

sin^2(θ) = 1/64

sin(θ) = ±√(1/64)

Since sin(θ) > 0, we take the positive square root:

sin(θ) = √(1/64)

Next, we use the reciprocal identity for cosecant:

csc(θ) = 1/sin(θ)

Substituting the value of sin(θ), we have:

csc(θ) = 1/√(1/64) = 8√(1/64) = 8/√(64) = 8/8 = 1

Next, we use the reciprocal identity for cotangent:

cot(θ) = 1/tan(θ)

We can find the value of tan(θ) using the definition:

tan(θ) = sin(θ) / cos(θ)

Substituting the values of sin(θ) and cos(θ), we have:

tan(θ) = √(1/64) / (-8) = -√(1/64) / 8

Finally, we use the reciprocal identity for a tangent:

tan(θ) = 1/cot(θ)

Substituting the value of cot(θ), we have:

tan(θ) = -8√(1/64)

Therefore, the exact values of the remaining trigonometric functions of θ are:

sin(θ) = √(1/64)

cos(θ) = -8

tan(θ) = -8√(1/64)

csc(θ) = 1

cot(θ) = -√(1/64) / 8

The complete question is:-

Find the exact value of each of the remaining trigonometric functions of

θ. Rationalize denominators when applicable.

secθ=−8, given that sinθ>0

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The expression for n(A) using the complements principle of counting is n(A) = n(S) - n(A').

The complements principle of counting states that the number of outcomes in the complement of event A is equal to the total number of outcomes in the sample space S minus the number of outcomes in event A.

Using this principle, we can express the number of outcomes in event A, n(A), as:

n(A) = n(S) - n(A')

Where:

- n(A) represents the number of outcomes in event A.

- n(S) represents the total number of outcomes in the sample space S.

- n(A') represents the number of outcomes in the complement of event A.

Therefore, the expression for n(A) using the complements principle of counting is n(A) = n(S) - n(A').

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The probability that the animal's weight will be less than 151 pounds is 0.50.

The correct option is B.

Since the given probability distribution ranges from 148 to 152, and we need to find the probability that the animal's weight will be less than 151 pounds, we can add the probabilities corresponding to the weights less than 151.

From the distribution, we see that the probability of the animal's weight being less than 151 pounds is 0.2 + 0.3 = 0.5.

Therefore, the answer is O 0.50.

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There is a 95% chance that the true mean number of hours of sleep per day for all students in the school falls within this range

To calculate the 95% confidence interval for the mean number of hours of sleep per day of a random sample of 50 students from a large high school, you would need to follow these steps:

Calculate the mean of the sample by adding up all the hours of sleep reported and dividing by the sample size (n).

Calculate the standard deviation (σ) of the sample by taking the square root of the sum of squares of the differences between the sample values and the mean divided by n1.

Calculate the standard error (SE) by dividing the standard deviation by the square root of n.

Calculate the margin of error (ME) by multiplying the standard error by the critical value of 1. 96.

Calculate the confidence interval by adding and subtracting the margin of error from the mean. This will give you the lower and upper bounds of the confidence interval.

Therefore, the 95% confidence interval for the mean number of hours of sleep per day of a random sample of 50 students from a large high school is (6. 73, 7. 67). This means that there is a 95% chance that the true mean number of hours of sleep per day for all students in the school falls within this range

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 The football player is 8 yards behind

If you wanted to do a number line you could start from 0 - 20 and count down 12 yards. the remaining pegs you have left are what it is. so 8 yards.

Answer:

y=-5x+5

Step-by-step explanation:

Answer:

she spends 9 hours

Step-by-step explanation:

Answer:

Sketch the graph of the function below, including correct signs, x-intercepts and y-

intercepts.

f(x) = (x + 2)²(x – 5)2

y

200

180

160

140

120

100

80

60

40

20

-10 9 8 7 6 5 4 3 2

1

2

3

5

6

7

Answer:

Step-by-step explanation:

6

Answer:

60-9+15=66 is the answer.

Answer:

F(x) = 44

Step-by-step explanation:

f(x) = 6x - 4

x = 8

f(x) = 6(8) - 4

f(x) =  48 - 4

Answer:

Step-by-step explanation:

f(8) = 6(8) - 4= 48 - 4 = 44

Answer:

ITS 15 THANK ME LATER!!!!

Step-by-step explanation:

Answer:

M = 1/5

Step-by-step explanation:

Answer:

83050

Step-by-step explanation:

that's the answer to the question

Answer:

(10x−7)^2

Step-by-step explanation:

(10x+7)(10x-7)

i stead of making it a "100" since they are both the same  but positive and negative () and bring it to the power of 2

Answer:

the answer is third option B

Answer:

Store a $90.30

Store B is $87.75

store B is the cheapest

Step-by-step explanation:

Just subtract 129.0 by 35% and 135.0 by 35%

Store a $90.30

Store B is $87.75

store B is the cheapest

Step-by-step explanation:

Just subtract 129.0 by 35% and 135.0 by 35%

The equation associated with the quotient of twenty and a number, decreased by 4, is equal to zero is 20/x - 4 = 0 and that number will be 5.

Determine the known quantities and designate the unknown quantity as a variable while trying to set up or construct a linear equation to fit a real-world application.

In other words, an equation is a set of variables that are constrained through a situation or case.

Let's say that number is x,

Quotients of 20 and x will be given as 20/x

20/x - 4 = 0

20/x = 4

x = 20/4 = 5

Hence"The equation associated with the quotient of twenty and a number, decreased by 4, is equal to zero is 20/x - 4 = 0 and that number will be 5".

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Answer:

1 = 130° , 2 =50° , 3 = 85°, 4=45°

Step-by-step explanation:

1 =45 + 85 = 130 { sum of opposite interior angle equals exterior angle}

2 = 180 - 1 { angles on a straight line equals 180}

= 180 -130 = 50°

4 = 180 - 135 = 45° { angles on a straight line equals 180}

3 = 135 -2 { sum of opposite interior angles equals exterior angle; 3 + 2 = 135}

3 = 135-50 = 85°

Note : sum of opposite interior angles equals external exterior angle, let's prove it:

If we look at the triangle at the bottom left, we have :

85, 45 and r { let's denote r as the missing angle}

So 85 + 45 + r = 180° { sum of angles of a triangle}

By simple arithmetic

r = 180 - ( 85+45) = 180 - 130 = 50°

but r + 4 = 180° { sum of angles in a straight line equals 180°}

4 = 180 - 50 = 130°

So you see 4 is the exterior angle of the triangle opposite to 85° and 45° interior angles}

Answer:

About 60 pecent

Step-by-step explanation:

Answer: 832 possible outcomes

To find the total number of outcomes when a coin is tossed four times and a card is selected from a standard deck of cards, we need to multiply the number of outcomes for each event.

The number of outcomes for a coin toss is 2 (heads or tails), and we toss the coin 4 times. Therefore, the number of outcomes for the coin tosses is:

2 x 2 x 2 x 2 = 16

The number of outcomes when selecting a card from a standard deck of cards is 52. Therefore, the total number of outcomes when a coin is tossed four times and a card is selected from a standard deck of cards is:

16 x 52 = 832

So there are 832 possible outcomes when a coin is tossed four times and a card is selected from a standard deck of cards.

Answer:

\(csc(3\pi ), sec(\frac{-\pi}{2})\)

The Undefined term is csc(3pi) and  sec(-pi/2) .

The area of mathematics that deals with particular angles' functions and how to use those functions in calculations. There are six popular trigonometric functions for an angle. Sine (sin), cosine (cos), tangent (tan), cotangent (cot), secant (sec), and cosecant are their respective names and acronyms (csc).

Given:

As, Cosecant is the reciprocal of sine, so the cosecant of any angle x for which sin x = 0 must be undefined, since it would have a denominator equal to 0. The value of sin (pi) is 0, so the cosecant of pi must be undefined.

Thus, csc(3pi) is undefined

and, the value of The value of cos (pi/2) is 0, so the secant of (pi)/2 must be undefined.

Thus, sec(-pi/2) is also undefined.

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The volume of the bag of nuts is the amount of nuts it can contain

The volume of the bag of nuts is 84.78 cubic inches

From the figure, we have the following parameters:

The volume of a cone is calculated using:

V = 1/3 πr^2h

Substitute the known values

V = 1/3  * 3.14 * 3^2 * 9

Evaluate the product

V = 84.78

Hence, the volume of the bag of nuts is 84.78 cubic inches

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36 of the insects are purple

4 x 45 . = 35

5 . 1

5 goes into 45 9 times so 4 x 9 =36

Step 1: Isolate the Sin Operator

\(8 sin(\frac{\pi }{6} x)=2\\sin(\frac{\pi }{6} x)=0.25\\\\\)

Step 2: Use Inverse Sin(arcsin) to isolate the term with the x variable

Note that since trig functions have 2 general solutions, this will give us one of our general solutions.

\(x=\frac{6 arcsin(0.25)}{\pi } =0.48\)

x₁= 0.48

Solving for x₂

Use the period identity for Sin Functions

\(sin(x)=sin(\pi -x)\)

X in this case is arcsin(0.25)

\(\frac{\pi }{6} x=\pi -arcsin(0.25) = 5.52\)

So our two general solutions are 0.48 and 5.52

Step 3: Period

Trig Functions have periodic behavior and this function period is

\(\frac{2\pi }{1} (\frac{6}{\pi } )= 12\)

So our general solutions are

0.48±12k, where k is an integer

5.52±12k, where k is an integer

Let k=1, and we get our next set of solutions:

12.48 and 17.52

So our answer is 0.48,5.52,12.48,17.52

Step-by-step explanation:

f(x) = a(x-x1) (x-x2)

from the vertex, we get a:

0 = a(4-2)²- 8

4a = 8

a = 2

so, the equation:

f(x) = 2(x-0) (x-4)

f(x) = 2x(x-4)

f(x) = 2x² -8x

The total number of kits, cats, sacks and wives is x⁴+x³+x²+x

Exponential expressions are just a way to write powers in short form. The exponent indicates the number of times the base is used as a factor. For example 3×3×3×3 can be written as 3⁴.

A man has x wives, each wife has x sack, therefore the number of sack = x×x = x²

each sack has x cats, therefore the number of cats = x²×x = x³

each cats has x kits, therefore the number of kits = x³× x= x⁴

therefore the total number of kits , cats, sacks and wives = kits + cats+ sacks + wives= x⁴+x³+x²+x.

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Answer:

Yes, it is a solution because inserting 8 into the equation gives you 13.

Step-by-step explanation:

1/2(8) + 9 = 13

4 + 9 = 13

13 = 13

Answer:  Number 1: = and Number 2: is C

Step-by-step explanation:

Answer:

6. >

7. 5/6, 2/3, 8/15

Step-by-step explanation:

For 6, you need to make the denominators equal, so you need to multiply 6/3*5 making it 30/15. Now which is greater 30/15 or 10/15 and you can see it's 30/15 so it would be >. For 7 you need to do the same thing but make all three denominators the same. 2/3 becomes 20/30 by multiplying by 10. 5/6 becomes 25/30 by multiplying by 5. Lastly, 8/15 becomes 16/30 by multiplying by 2. Now all their denominators are the same, so now all you have to do is order them. 25/30, 20/30, and 16/30. This is equal to 5/6, 2/3, 8/15.

The value of integral is 3.

Let's evaluate the integral over the positive half of the interval:

∫[0 to π] (cos(x) / √(4 + 3sin(x))) dx

Let u = 4 + 3sin(x), then du = 3cos(x) dx.

Substituting these expressions into the integral, we have:

∫[0 to π] (cos(x) / sqrt(4 + 3sin(x))) dx = ∫[0 to π] (1 / (3√u)) du

Using the power rule of integration, the integral becomes:

∫[0 to π] (1 / (3√u)) du = (2/3) . 2√u ∣[0 to π]

Evaluating the definite integral at the limits of integration:

(2/3)2√u ∣[0 to π] = (2/3) 2(√(4 + 3sin(π)) - √(4 + 3sin(0)))

(2/3) x 2(√(4) - √(4)) = (2/3) x 2(2 - 2) = (2/3) x 2(0) = 0

So, the value of integral is

= 3-0

= 3

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Answer:

\(3-\displaystyle \int^{\pi}_{-\pi} \dfrac{\cos x}{\sqrt{4+3 \sin x}}\; \text{d}x\approx 0.806\; \sf (3\;d.p.)\)

Step-by-step explanation:

First, compute the indefinite integral:

\(\displaystyle \int \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x\)

To evaluate the indefinite integral, use the method of substitution.

\(\textsf{Let} \;\;u = 4 + 3 \sin x\)

Find du/dx and rewrite it so that dx is on its own:

\(\dfrac{\text{d}u}{\text{d}x}=3 \cos x \implies \text{d}x=\dfrac{1}{3 \cos x}\; \text{d}u\)

Rewrite the original integral in terms of u and du, and evaluate:

\(\begin{aligned}\displaystyle \int \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x&=\int \dfrac{\cos x}{\sqrt{u}}\cdot \dfrac{1}{3 \cos x}\; \text{d}u\\\\&=\int \dfrac{1}{3\sqrt{u}}\; \text{d}u\\\\&=\int\dfrac{1}{3}u^{-\frac{1}{2}}\; \text{d}u\\\\&=\dfrac{1}{-\frac{1}{2}+1} \cdot \dfrac{1}{3}u^{-\frac{1}{2}+1}+C\\\\&=\dfrac{2}{3}\sqrt{u}+C\end{aligned}\)

Substitute back u = 4 + 3 sin x:

                            \(= \dfrac{2}{3}\sqrt{4+3\sin x}+C\)

Therefore:

\(\displaystyle \int \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x= \dfrac{2}{3}\sqrt{4+3\sin x}+C\)

To evaluate the definite integral, we must first determine any intervals within the given interval -π ≤ x ≤ π where the curve lies below the x-axis. This is because when we integrate a function that lies below the x-axis, it will give a negative area value.

Find the x-intercepts by setting the function to zero and solving for x in the given interval -π ≤ x ≤ π.

\(\begin{aligned}\dfrac{\cos x}{\sqrt{4+3\sin x}}&=0\\\\\cos x&=0\\\\x&=\arccos0\\\\\implies x&=-\dfrac{\pi }{2}, \dfrac{\pi }{2}\end{aligned}\)

Therefore, the curve of the function is:

So to calculate the total area, we need to calculate the positive and negative areas separately and then add them together, remembering that if you integrate a function to find an area that lies below the x-axis, it will give a negative value.

Integrate the function between -π and -π/2.

As the area is below the x-axis, we need to negate the integral so that the resulting area is positive:

\(\begin{aligned}A_1=-\displaystyle \int^{-\frac{\pi}{2}}_{-\pi} \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x&=- \left[\dfrac{2}{3}\sqrt{4+3\sin x}\right]^{-\frac{\pi}{2}}_{-\pi}\\\\&=-\dfrac{2}{3}\sqrt{4+3 \sin \left(-\frac{\pi}{2}\right)}+\dfrac{2}{3}\sqrt{4+3 \sin \left(-\pi\right)}\\\\&=-\dfrac{2}{3}\sqrt{4+3 (-1)}+\dfrac{2}{3}\sqrt{4+3 (0)}\\\\&=-\dfrac{2}{3}+\dfrac{4}{3}\\\\&=\dfrac{2}{3}\end{aligned}\)

Integrate the function between -π/2 and π/2:

\(\begin{aligned}A_2=\displaystyle \int^{\frac{\pi}{2}}_{-\frac{\pi}{2}} \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x&= \left[\dfrac{2}{3}\sqrt{4+3\sin x}\right]^{\frac{\pi}{2}}_{-\frac{\pi}{2}}\\\\&=\dfrac{2}{3}\sqrt{4+3 \sin \left(\frac{\pi}{2}\right)}-\dfrac{2}{3}\sqrt{4+3 \sin \left(-\frac{\pi}{2}\right)}\\\\&=\dfrac{2}{3}\sqrt{4+3 (1)}-\dfrac{2}{3}\sqrt{4+3 (-1)}\\\\&=\dfrac{2\sqrt{7}}{3}-\dfrac{2}{3}\\\\&=\dfrac{2\sqrt{7}-2}{3}\end{aligned}\)

Integrate the function between π/2 and π.

As the area is below the x-axis, we need to negate the integral so that the resulting area is positive:

\(\begin{aligned}A_3=-\displaystyle \int^{\pi}_{\frac{\pi}{2}} \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x&= -\left[\dfrac{2}{3}\sqrt{4+3\sin x}\right]^{\pi}_{\frac{\pi}{2}}\\\\&=-\dfrac{2}{3}\sqrt{4+3 \sin \left(\pi\right)}+\dfrac{2}{3}\sqrt{4+3 \sin \left(\frac{\pi}{2}\right)}\\\\&=-\dfrac{2}{3}\sqrt{4+3 (0)}+\dfrac{2}{3}\sqrt{4+3 (1)}\\\\&=-\dfrac{4}{3}+\dfrac{2\sqrt{7}}{3}\\\\&=\dfrac{2\sqrt{7}-4}{3}\end{aligned}\)

To evaluate the definite integral, sum A₁, A₂ and A₃:

\(\begin{aligned}\displaystyle \int^{\pi}_{-\pi} \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x&=\dfrac{2}{3}+\dfrac{2\sqrt{7}-2}{3}+\dfrac{2\sqrt{7}-4}{3}\\\\&=\dfrac{2+2\sqrt{7}-2+2\sqrt{7}-4}{3}\\\\&=\dfrac{4\sqrt{7}-4}{3}\\\\ &\approx2.194\; \sf (3\;d.p.)\end{aligned}\)

Now we have evaluated the definite integral, we can subtract it from 3 to evaluate the given expression:

\(\begin{aligned}3-\displaystyle \int^{\pi}_{-\pi} \dfrac{\cos x}{\sqrt{4+3 \sin x}}\; \text{d}x&=3-\dfrac{4\sqrt{7}-4}{3}\\\\&=\dfrac{9}{3}-\dfrac{4\sqrt{7}-4}{3}\\\\&=\dfrac{9-(4\sqrt{7}-4)}{3}\\\\&=\dfrac{13-4\sqrt{7}}{3}\\\\&\approx 0.806\; \sf (3\;d.p.)\end{aligned}\)

Therefore, the given expression cannot be zero.