Let the alphabet be A = {a, 1)
1. {ε} U {b} = 2) {a, b} U {ab} 3) {a, b, ab}{b} 4) {a, b, ab}{ & } 5) L= {b, ab}, L²= 6) {a}* = 7) {a, ab}* = 8) {a}* U {b} = 9) {a}* {b} = 10) {b}{a}* = 11) Ø* = 12) {ε}* =

Sandy substrate is susceptible to displacement during an earthquake.

Near the epicenter of an earthquake, there is more shaking to be seen.

To learn more about earthquake refer:

brainly.com/question/20409140

#SPJ4

Answer:

a) 0.42

b) Independent

c) 30%

d) 0.88

Explanation:

Person chooses Chicken's item : 70% = 0.7

Person chooses fish's item : 30% = 0.3

Visits in which he orders Afghani Chicken = 60% = 0.6

a) Probability that he goes to KARIM and orders Afghani Chicken:

P = 0.7 * 0.6 = 0.42

b) Two events are said to be independent when occurrence of one event does not affect the probability of the other event's occurrence. Here the person orders Afghani Chicken regardless of where he visits so the events are independent.

c)  P = 0.30 because he orders Afghani Chicken regardless of where he visits.

d)  Let A be the probability that he goes to KARIM:

P(A) = 0.7 * ( 1 - 0.6 ) = 0.28

Let A be the probability that he orders Afghani Chicken:

P(B) =  0.3 * 0.6 = 0.18

Let C be the probability that he goes to KARIM and orders Afghani chicken:

= 0.7 * 0.6 = 0.42

So probability that he goes to KARIM or orders Afghani Chicken or both:

P(A) + P(B) + P(C) = 0.28 + 0.18 + 0.42 = 0.88

Answer:

Weight Percentage of Ash = 3.4

Explanation:

Given - Coal containing 21% ash is completely combusted, and the ash is 100% removed in a water contact scrubber. If 10,000 kg of coal is burned per hour with a scrubber flow rate of 1.0 m3/min.

To find - the weight percentage of the ash in the water/ash stream leaving the scrubber is most nearly ?

Solution -

Given that,

Coal Burned Rate = 10,000 kg/hr

                              = \(\frac{10,000}{60 min} * 1 hr *\frac{kg}{hr}\)

                              = 166.6666 kg/min

⇒Coal Burned Rate = 166.6666 kg/min

Now,

Given that,

Ash content in coal = 21 %

⇒Ash in (coal that burned) = 166.6666 × \(\frac{21}{100}\) kg/min

                                             = 34.9999 ≈ 35 kg/min

⇒Ash in (coal that burned) = 35 kg/min

Now,

We know,

Density of water = 1000 kg/m³

Now,

Water flow Rate = \(1\frac{m^{3} }{min} * density\)

                           = 1000 kg/min

⇒Water flow Rate = 1000 kg/min

Now,

Total Mass flow Rate of (Water + Ash stream) = ( 1000 + 35) kg/min

                                                                           = 1035 kg/min

⇒Total Mass flow Rate of (Water + Ash stream) = 1035 kg/min

So,

Weight Percentage of Ash = (Weight of Ash ÷ Total weight of Stream) × 100

                                            = (35 ÷ 1035) × 100

                                            = 3.38 ≈ 3.4

∴ we get

Weight Percentage of Ash = 3.4

Answer:

Static Model

Explanation:

Answer:

Under cold air standard conditions, the thermal efficiency of this cycle is 56.9 percent.

Explanation:

From Thermodynamics we remember that thermal efficiency of the ideal Otto cycle (\(\eta_{th}\)), dimensionless, is defined by the following formula:

\(\eta_{th} = 1-\frac{1}{r^{\gamma-1}}\) (Eq. 1)

Where:

\(r\) - Compression ratio, dimensionless.

\(\gamma\) - Specific heat ratio, dimensionless.

Please notice that specific heat ratio under cold air standard conditions is \(\gamma = 1.4\).

If we know that \(r = 8.2\) and \(\gamma = 1.4\), then thermal efficiency of the ideal Otto cycle is:

\(\eta_{th} = 1-\frac{1}{8.2^{1.4-1}}\)

\(\eta_{th} = 0.569\)

Under cold air standard conditions, the thermal efficiency of this cycle is 56.9 percent.

Answer:

Dam they be thinking we racist

Explanation:

Answer:

XDDDD

Explanation:

XD I LOVE THIS MEME IM SAVING THIS TO MY GALLERY XD

Given that,

Mass of the object 1, m = 107.01 grams

To find,

Force on the object.

Solution,

The force acting on the object is gravitational force. The force is given by the formula as follow :

F = mg

g is acceleration due to gravity

F = 0.10701 kg × 9.8 m/s²

F = 1.048 N

So, the force acting on object 1 is 1.048 N.

Answer: Option A is correct -- 2.6 at% Pb and 97.4 at% Sn.

Explanation:

Option A is the only correct option -- 2.6 at% Pb and 97.4 at% Sn. While option B, which is 7.6 at% Pb and 92.4 at% Sn. and option C, which is 97.4 at% Pb and 2.6 at% Sn. and option D, which is 92.4 at% Pb and 7.6 at% Sn. are wrong.

Answer:

Computer programming is where you learn and see how computers work. People do this for a living as a job, if you get really good at it you will soon be able to program/ create a computer.

Explanation:

Hope dis helps! :)

Answer:

Is there supposed to be a picture...try asking question again

Answer:

4

Explanation:

To demonstrate that a problem is NP-complete, we appear that it is within the NP course and can be decreased to a known NP-complete problem. From this deduction, all the problems are NP-complete.

To demonstrate that a problem is NP-complete, we ought to appear that it is both within the NP complexity course which is as difficult as an existing NP-complete problem. Let's analyze each issue and appear how they can be seen as generalizations of known NP-complete problems:

(a) SUBGRAPH ISOMORPHISM: This problem generalizes the SUBSET-SUM problem, where rather than subsets and wholes, we have charts and subgraphs. SUBSET-SUM could be a well-known NP-complete issue, so SUBGRAPH ISOMORPHISM acquires its NP-completeness.

(b) LONGEST Way: This problem generalizes the HAMILTONIAN Way problem, where we are inquired to find a straightforward way of length rise to the number of vertices within the chart. HAMILTONIAN Way may be a known NP-complete issue, so LONGEST Way is additionally NP-complete.

(c) MAX SAT: This problem is as of now a known NP-complete problem, so no advance verification is required.

(d) Thick SUBGRAPH: This problem generalizes the CLIQUE problem, where we are inquired to discover a total subgraph of a certain size. CLIQUE could be a well-known NP-complete problem, so Thick SUBGRAPH acquires its NP-completeness.

(e) Inadequate SUBGRAPH: This problem can be seen as the complement of the Thick SUBGRAPH issue. Since Thick SUBGRAPH is NP-complete, its complement, Scanty SUBGRAPH, is additionally NP-complete.

(f) SET COVER: SET COVER may be a known NP-complete problem, so no encouraged confirmation is required.

(g) Solid Organize: This issue can be seen as a generalization of the HAMILTONIAN CYCLE  problem. In case all did values are limited to 1 or 2, rij values are all 2, and b is equal to n, the issue gets to be identical to finding a Hamiltonian cycle. Since HAMILTONIAN CYCLE is NP-complete, the Solid Arrange issue acquires its NP-completeness.

By finding the relationship between these problems and known NP-complete problems, we will conclude that they are all NP-complete.

Learn more about NP-completeness here:

https://brainly.com/question/15097934

#SPJ4

Answer: D

Explanation: When you change your transmission fluid you change your filter. When you do that you clean where the filter was. Then you can put the new filter on and the new fluid.

Transmission cleaners are used in conjunction with a transmission fluid exchange. The correct option is D.

An exclusive additional cleaning package is included with the transmission cleaner. It pushes the deposits into the oil tray ground after removing them from the transmission.

The deposits are removed from the transmission with the regular transmission oil during an oil change. A smooth-shifting performance and a longer transmission lift time are guaranteed by the use of the transmission cleaner.

You replace your filter when you change your transmission fluid. You clean the area where the filter was when you do that. Then you can put the new filter and the new fluid on.

Therefore, in addition to changing the transmission fluid, transmission cleaners are employed. The right answer is D.

To know more about transmission cleaners follow

https://brainly.com/question/14093047

#SPJ2

Technician A is wrong.

Technician B is right.

See the link below for more about automobile engineering:

https://brainly.com/question/4822721

B) transistor. Typically a constant voltage CP rectifier will NOT have transistor.

A constant voltage CP (controlled potential) rectifier is a type of rectifier used in electrochemical processes. It typically consists of a transformer, a rectifying element (such as diodes), voltage taps, and other components. However, it does not typically include a transistor, as transistors are not commonly used in CP rectifiers. Transistors are electronic devices used for amplification and switching of electrical signals, and they are not necessary for the operation of a typical constant voltage CP rectifier, which primarily functions to provide a stable DC output voltage for electrochemical processes.

learn more about voltage here:

https://brainly.com/question/31656386

#SPJ11

Answer:

which class is this. I don't know sry

Answer:

\(I=3A\)

Explanation:

From the question we are told that:

Number of lamps \(N=4\)

Potential difference \(V=60v\)

Total Resistance of the lamp is \(R= 20ohms\)

Generally the equation for Current I is mathematically given by

 \(I=\frac{V}{R}\)

 \(I=\frac{60}{20}\)

 \(I=3A\)

The fundamental components of any digital system are logic gates. It is an electronic circuit with one or more inputs and just one output.

In any digital system, logic gates serve as the fundamental building elements. One or more inputs may be present, but there is only one output in this electronic circuit. An established logic governs the relationship between the input and the output. This is the basis behind the names AND, OR, NOT, etc. given to logic gates.

Using cables that stand for 1s and 0s, we transmit data through computers. In order for computers to someday perform more difficult tasks like computing the 50th digit of, they need to be able to manipulate those 1s and 0s. Input wire 1s and 0s are converted via logic gates in computers.

A K-map is a particular type of truth table that facilitates the mapping of parameter values and leads to a shortened Boolean expression. Functions with two to four variables are ideal candidates for K-maps.

To learn more about K-map refer to:

https://brainly.com/question/15077666

#SPJ1

The number of cycles that can be applied before fatigue failure is expected is `1.69×10^5`.

The formula to calculate fatigue failure for a tube subjected to bending and internal pressure cyclic loading is given as;

$\Delta n = \frac{1}{2} \left(\frac{d_i}{R} + 1\right)(\frac{p_{\max}}{k})^m \left[1 + \left(\frac{\Delta M}{\Delta M_{th}}\right)^n\right]$

Here, `∆n` is the number of cycles that can be applied before fatigue failure is expected. `di` is the internal diameter of the tube which is 100 - 2×4 = 92 mm. `R` is the radius of curvature which is equal to 2 times the diameter, or `R = 2×50 = 100 mm`. `pmax` is the maximum internal pressure which is 18 MPa.

`k` and `m` are material constants for Al 2024-T4 and are equal to 378 MPa and -0.097 respectively. `ΔM` is the alternating bending moment which is 2 kN-m. `ΔMth` is the threshold value of bending moment, which is equal to 0.58 times the yield strength of Al 2024-T4, or `ΔMth = 0.58×386 MPa×π×(92/2)^3/32 = 2374 N-m`.

`n` is another material constant for Al 2024-T4 and is equal to -0.159.

Substituting the given values, we get;

$ \Delta n = \frac{1}{2}\left(\frac{d_i}{R}+1\right)\left(\frac{p_{max}}{k}\right)^m \left[1+\left(\frac{\Delta M}{\Delta M_{th}}\right)^n\right] $

`∆n = 1.69×10^5`

Therefore, the number of cycles that can be applied before fatigue failure is expected is `1.69×10^5`.

Know more about fatigue failure here:

https://brainly.com/question/31666734

#SPJ11

(a) Z* at 95% for two sided is 1.96,  CI₁ = 4.945  ,  CL₂ = 6.054

(b) Z* at 90% for two sided is 1.65,  CI₁ = 5.033 ,  CL₂ = 5.966

(c) 90% lower confidence bound for one sided is 5.138

(d) Now, if we compare width of two intervals in (a) and (b), we see that at higher confidence level width is greater and interval is more expanded than at the lower confidence level. So as level of significance is lower for two sided confidence interval will be more expanded.

A confidence interval in statistics is the likelihood that a population parameter will fall between a set of values a predetermined percentage of the time. When analyzing data, analysts frequently use confidence intervals that include 95% or 99% of the expected observations. Inferring that there is a 95% probability that the true value falls within that range is possible if a point estimate from a statistical model of 10.00 with a 95% confidence interval of 9.50 - 10.50 is produced.

Confidence intervals are a tool used by statisticians and other analysts to understand the statistical significance of their estimates, inferences, or predictions. One cannot satisfactorily assert that a result from data obtained through testing or experimentation is to be attributed to a specific cause rather than chance if a confidence interval contains the value of zero (or some other null hypothesis).

Learn more about confidence interval

https://brainly.com/question/20309162

#SPJ4

Answer:

a) the maximum tensile stress due to the weight of the wire is 1361.23 psi

b) the maximum load P that could be supported at the lower end of the wire is 624.83 lb

Explanation:

Given the data in the question;

Length of wire L = 400 ft = ( 400 × 12 )in = 4800 in

Diameter d = 3/16 in

Unit weight w = 490 pcf

First we determine the area of the wire;

A = π/4 × d²

we substitute

A = π/4 × (3/16)²

A = 0.0276 in²

Next we get the Volume

V = Area × Length of wire

we substitute

V = 0.0276 × 4800

V = 132.48 in³

Weight of the steel wire will be;

W = Unit weight × Volume

we substitute

W = 490 × ( 132.48 / 12³ )

W = 490 × 0.076666

W = 37.57 lb

a) the maximum tensile stress due to the weight of the wire;

σ\(_w\) = W / A

we substitute

σ\(_w\) = 37.57 / 0.0276

= 1361.23 psi

Therefore, the maximum tensile stress due to the weight of the wire is 1361.23 psi

b) the maximum load P that could be supported at the lower end of the wire. Allowable tensile stress is 24,000 psi

Maximum load P that the wire can safely support its lower end will be;

P = ( σ\(_{all\) - σ\(_w\) )A

we substitute

P = ( 24000 - 1361.23  )0.0276

P = 22638.77 × 0.0276

P = 624.83 lb

Therefore, the maximum load P that could be supported at the lower end of the wire is 624.83 lb

Flowchart of the process: Feed (C2H6 + Cl2) -> Reactor -> Separation -> Recycle (C2H6 + Cl2) and discard (HCl + C2H4Cl2) -> Product (C2H5Cl).

The volume V flowing past a point in time t is defined as the flow rate Q, or Q=Vt, where V is volume and t is time.

To calculate the molar flow rate of unconsumed C2H6 leaving the reactor, we need to first calculate the molar flow rate of C2H6 consumed in the reactor.

Molar flow rate of C2H6 in feed = 4 moles of C2H6 / mole of Cl2 * 150 mol/h = 600 mol/h

Molar flow rate of C2H6 consumed = 15% of 600 mol/h = 90 mol/h

Molar flow rate of unconsumed C2H6 leaving the reactor = Molar flow rate of C2H6 in feed - Molar flow rate of C2H6 consumed = 600 mol/h - 90 mol/h = 510 mol/h

Therefore, the molar flow rate of unconsumed C2H6 leaving the reactor is 510 mol/h.

c) To calculate the production rate of C2H5Cl leaving the reactor, we can use the stoichiometry of the reaction and the given conversion and selectivity data.

For every 100 moles of C2H6 consumed in the reactor, 80 moles of C2H5Cl is produced. Therefore, the molar flow rate of C2H5Cl leaving the reactor can be calculated as:

Molar flow rate of C2H5Cl leaving the reactor = Molar flow rate of C2H6 consumed * (80/100) = 90 mol/h * (80/100) = 72 mol/h

Therefore, the production rate of C2H5Cl leaving the reactor is 72 mol/h.

d) To calculate the molar flow rate of C2H6 and Cl2 in the fresh feed, we can use the given information that the feed contains 4 moles of C2H6 per mole of Cl2.

Let the molar flow rate of Cl2 in the feed be x. Then, the molar flow rate of C2H6 in the feed can be calculated as:

Molar flow rate of C2H6 in feed = 4 moles of C2H6 / mole of Cl2 * x

We know that the total molar flow rate in the feed is 150 mol/h. Therefore, we can write:

x + 4x = 150

Solving for x, we get:

x = 25 mol/h

Therefore, the molar flow rate of C2H6 in the fresh feed is:

Molar flow rate of C2H6 in feed = 4 moles of C2H6 / mole of Cl2 * x = 4 mol/h * 25 = 100 mol/h

And the molar flow rate of Cl2 in the fresh feed is:

Molar flow rate of Cl2 in feed = x = 25 mol/h

Thus, the molar flow rate of C2H6 and Cl2 in the fresh feed are 100 mol/h and 25 mol/h, respectively.

For more details regarding flow rate, visit:

https://brainly.com/question/27880305

#SPJ1

From the given figures of ideal op amps, the voltage gain and input resistance of each circuits is 10kΩ

The voltage gain of the inverting amplifier is given by

G = V₀ / V₁

= R₂/ R₁

= 100k / 10K

=-10 V/V

Therefore, the voltage gain of the inverting amplifier is-10 V/V

The input resistance is Rₙ = R₁

Rₙ = 10kΩ

Therefore, the input resistance is 10kΩ

Voltage gain and input resistance are important parameters in the design and analysis of electronic circuits, particularly amplifiers. Voltage gain is a measure of how much an amplifier can increase the voltage of an input signal. It is defined as the ratio of the output voltage to the input voltage, usually expressed in decibels (dB). A high voltage gain indicates that the amplifier can amplify weak signals to a much larger level. Input resistance, on the other hand, is the resistance presented by an amplifier to the input signal. It is important to match the input resistance of an amplifier with the output resistance of the signal source to ensure maximum power transfer. In general, a high input resistance is desirable as it minimizes loading effects on the signal source. Both voltage gain and input resistance are critical in the design of amplifier circuits. While a high voltage gain amplifies the signal, it can also introduce noise and distortion. Therefore, it is important to balance the voltage gain and input resistance to achieve the desired performance characteristics of the amplifier.

To learn more about parameters click here

brainly.com/question/30263052

#SPJ4

To provide constant temperature control, a thermostat is installed in the cooling system.

What is a thermostat? A thermostat is an instrument that automatically controls the temperature of a system. The thermostat helps regulate the temperature in a room or system by turning on or off a heating or cooling system in response to the temperature within a specified limit. The thermostat's main function is to provide a constant temperature control.

What is the cooling system? A cooling system is a device or set of devices that are used to cool the working components of an engine or machine. It operates by dissipating the heat generated by the working components and maintaining the system at a stable operating temperature range. Water, oil, and air are the three main mediums that are used in cooling systems. The function of a thermostat in a cooling system is to regulate the temperature of the fluid or air flowing through the engine or other equipment. A thermostat monitors the temperature and switches the cooling system on or off based on preset parameters. Thus, a thermostat provides constant temperature control to the cooling system.

Learn more about thermostats: https://brainly.com/question/28304914

#SPJ11

The SQL query is SELECT city, state, country, postal_code, SUB STR(last_name, 1, 3) AS new_last_name FROM employee_data;

Assuming the table name is "employee_data", and the column containing the last names is "last_name";

The SQL query with the added statement to retrieve the first 3 characters of each last name and store the result in a new column as "new_last_name" would be:

SELECT city, state, country, postal_code, SUB STR(last_name, 1, 3) AS new_last_name

FROM employee_data;

This query selects the columns "city", "state", "country", and "postal_code" from the "employee_data" table, and also creates a new column called "new_last_name" using the SUB STR function to retrieve the first 3 characters of each last name.

The AS keyword is used to give the new column a name that can be used in the query output.

Read more about SQL at

https://brainly.com/question/30078874

#SPJ1

Answer:

The angle between the vector and positive x-axis is approximately 59.036º.

Explanation:

By Linear Algebra and to be precise, by definition of Dot Product we can determine the angle between two vector from following expression:

\(\theta = \cos^{-1}\frac{\vec u \,\bullet \,\vec v}{\|\vec u\|\cdot \|\vec v\|}\) (1)

Where:

\(\vec u\), \(\vec v\) - Vectors, no unit.

\(\|\vec u\|\), \(\|\vec v\|\) - Norms of vectors, no unit.

\(\theta\) - Angle, measured in sexagesimal degrees.

Please notice that norms are calculated by Pythagorean Theorem. If we know that \(\vec u = (3,5)\) and \(\vec v = (1, 0)\), then the angle between the vector and positive x-axis is:

\(\|\vec u\| = \sqrt{3^{2}+5^{2}}\)

\(\|\vec u\| = \sqrt{34}\)

\(\|\vec v\| = 1\)

\(\theta = \cos^{-1}\frac{(3)\cdot (1)+(5)\cdot (0)}{\sqrt{34}\cdot 1 }\)

\(\theta = \cos^{-1}\frac{3}{\sqrt{34}}\)

\(\theta \approx 59.036^{\circ}\)

The angle between the vector and positive x-axis is approximately 59.036º.