The speed of light in a window composed of crown glass is 1.97 x 10^8 m/s.
When light passes from one medium to another, the speed and wavelength of the light change. This is known as refraction. The speed of light in a medium depends on its index of refraction. The speed of light in a vacuum is approximately 3.00 x 108 m/s.
To calculate the speed of light in a window composed of crown glass with an index of refraction of 1.523, we use the formula: v = c/n where: v is the speed of light in the medium c is the speed of light in a vacuum n is the index of refraction of the medium. Plugging in the values, we get: v = (3.00 x 10^8 m/s) / 1.523v = 1.97 x 10^8 m/s. Therefore, the speed of light in a window composed of crown glass is 1.97 x 10^8 m/s.
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the rock of 10 kg is falling near the Earth's surface.assume that g =10N/kg and the is no air resistance. what is the acceleration of the rock
Answer:
kya faltu sawal h repetitive g=10N/kg
Using what you know about rotational motion and gravitation, derive an equation for orbital tangential speed if all that is given is the mass of the planet and the radius of the planet.
Answer:
Explanation:
The motion of objects is governed by Newton's laws. The same simple laws that govern the motion of objects on earth also extend to the heavens to govern the motion of planets, moons, and other satellites. The mathematics that describes a satellite's motion is the same mathematics presented for circular motion
Consider a satellite with mass Msat orbiting a central body with a mass of mass MCentral. The central body could be a planet, the sun or some other large mass capable of causing sufficient acceleration on a less massive nearby object. If the satellite moves in circular motion, then the net centripetal force acting upon this orbiting satellite is given by the relationship
Fnet = ( Msat • v2 ) / R
This net centripetal force is the result of the gravitational force that attracts the satellite towards the central body and can be represented as
Fgrav = ( G • Msat • MCentral ) / R2
Since Fgrav = Fnet, the above expressions for centripetal force and gravitational force can be set equal to each other. Thus,
(Msat • v2) / R = (G • Msat • MCentral ) / R2
Observe that the mass of the satellite is present on both sides of the equation; thus it can be canceled by dividing through by Msat. Then both sides of the equation can be multiplied by R, leaving the following equation.
v2 = (G • MCentral ) / R
Taking the square root of each side, leaves the following equation for the velocity of a satellite moving about a central body in circular motion
where G is 6.673 x 10-11 N•m2/kg2, Mcentral is the mass of the central body about which the satellite orbits, and R is the radius of orbit for the satellite.
The Acceleration Equation
Similar reasoning can be used to determine an equation for the acceleration of our satellite that is expressed in terms of masses and radius of orbit. The acceleration value of a satellite is equal to the acceleration of gravity of the satellite at whatever location that it is orbiting. In Lesson 3, the equation for the acceleration of gravity was given as
g = (G • Mcentral)/R2
Thus, the acceleration of a satellite in circular motion about some central body is given by the following equation
where G is 6.673 x 10-11 N•m2/kg2, Mcentral is the mass of the central body about which the satellite orbits, and R is the average radius of orbit for the satellite.
Orbital Period Equation
The final equation that is useful in describing the motion of satellites is Newton's form of Kepler's third law. Since the logic behind the development of the equation has been presented elsewhere, only the equation will be presented here. The period of a satellite (T) and the mean distance from the central body (R) are related by the following equation:
where T is the period of the satellite, R is the average radius of orbit for the satellite (distance from center of central planet), and G is 6.673 x 10-11 N•m2/kg2.
There is an important concept evident in all three of these equations - the period, speed and the acceleration of an orbiting satellite are not dependent upon the mass of the satellite.
None of these three equations has the variable Msatellite in them. The period, speed and acceleration of a satellite are only dependent upon the radius of orbit and the mass of the central body that the satellite is orbiting. Just as in the case of the motion of projectiles on earth, the mass of the projectile has no effect upon the acceleration towards the earth and the speed at any instant. When air resistance is negligible and only gravity is present, the mass of the moving object becomes a non-factor. Such is the case of orbiting satellites.
Orbital tangential speed if all that is given is the mass of the planet and the radius of the planet is \(v = \sqrt{\frac{GM}{r+h} }\)
What is Gravitational Force ?Gravitational force is force of attraction between two masses. Gravitational force(F) between two bodies is directly proportion to the product of masses(m₁,m₂) of two bodies and inversely proportional to square of distance(r) between them.
mathematically it is written as,
F ∝ Mm
F ∝ 1/r²
F = GMm÷r²
where G is gravitational constant, whose value is 6.6743 × 10⁻¹¹ m³ kg-1s⁻².
Force is expressed in Newton N in SI unit. its dimensions are [M¹L¹T⁻²].
This is analogous with coulomb's law which gives force between two charges.
Centrifugal Force is given by,
F = mv²÷r
For a satellite to revolve in a stable orbit, Gravitational force must be equal to centrifugal force.
\(F_{c} = F_{g}\)
mv²÷(r+h) = GMm÷(r+h)²
v² = GM÷r
v = \(\sqrt{\frac{GM}{r+h} }\)
Where v is tangential speed of an object revolving around a planet of mass M and radius r at height of h from surface of the planet.
This is also called as orbital velocity of object(satellite).
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If an object on a horizontal frictionless surface is attached to a spring, displaced, and then released, it will oscillate. If it is displaced a distance 0.110 m from its equilibrium position and released with zero initial speed. Then after a time 0.815 s its displacement is found to be a distance 0.110 m on the opposite side, and it has passed the equilibrium position once during this interval.
Find (a) the amplitude; (b) the period; (c) the frequency.
a)The amplitude of the wave will be 0.120m.
b)The period of the wave will be 1.60s.
What is the frequency?Frequency is defined as the number of repetitions of a wave occurring waves in 1 second.
a)The amplitude of the wave will be 0.120m.
A is the initial displacement =0.120m
The amplitude represents the largest deviation from equilibrium. So that the amplitude of the wave will be equal to the maximum position.
Hence the amplitude of the wave will be 0.120m.
b)The period of the wave will be 1.60s.
The movement from maximum positive displacement to maximum negative displacement. The time period will be;
\(\rm \frac{T}{2} = 0.800 \\\\\ T= 1.6 \ sec\)
Hence the period of the wave will be 1.60s.
c) The frequency of the wave will be 0.625Hz.
The frequency is inversely proportional to the time period. Frequency is found as;
\(\rm f=\frac{1}{T} \\\\ \rm f=\frac{1}{0.625} \\\\ \rm f=0.625 \ Hz\)
Hence the frequency of the wave will be 0.625Hz.
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how much thermal energy is released as the arrow comes to rest in the wood?
The thermal energy released as the arrow comes to rest in the wood is a portion of the initial kinetic energy of the arrow.
To calculate the thermal energy released as the arrow comes to rest in the wood, you need to consider the initial kinetic energy of the arrow and the energy conversion taking place.
1. Determine the initial kinetic energy of the arrow, which can be calculated using the formula KE = 0.5 * m * v^2, where KE is the kinetic energy, m is the mass of the arrow, and v is its initial velocity.
2. When the arrow comes to rest in the wood, its kinetic energy is converted into thermal energy and other forms of energy (such as potential energy, sound energy, etc.). In this case, we will focus on the thermal energy generated.
3. The total energy is conserved, meaning that the initial kinetic energy of the arrow will be equal to the sum of the thermal energy and other forms of energy generated. However, without specific information about the other energy conversions, we cannot precisely determine the amount of thermal energy released.
In conclusion, some of the kinetic energy of the arrow's initial flight is released as thermal energy as the arrow rests in the wood.
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two particles, an electron and a proton, are initially at rest in a uniform electric field of magnitude 564 n/c. if the particles are free to move, what are their speeds (in m/s) after 51.6 ns?
An electron and a proton are two particles that are initially at rest in a uniform electric field of magnitude 564 n/c. After 51.6 ns, the particles are free to travel and reach speeds of 2.33 x 106 m/s (in m/s).
The speed of the particles can be determined using the equation:
= v
= E x t x q / m
Where v is the particle's speed, E is the electric field, t is the passage of time, q is the particle's charge, and m is the particle's mass.
For the electron:
= v
= 564 N/C x 51.6 x 10^-9 s x -1.6 x 10^-19 C / 9.11 x 10^-31 kg
= -1.24 x 10^6 m/s
For the proton:
= v
= 564 N/C x 51.6 x 10^-9 s x 1.6 x 10^-19 C / 1.67 x 10^-27 kg
= 2.33 x 10^6 m/s
Note that the electron has a negative charge, so it will experience a force in the opposite direction of the electric field, causing its speed to be negative. The proton has a positive charge, so it will experience a force in the same direction as the electric field, causing its speed to be positive.
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The dependent variable (DV) changes while the independent variable (IV) does not. False or True
Answer:true
Explanation:
Answer: False
Explanation: An easy way to think of independent and dependent variables is, when you're conducting an experiment, the independent variable is what you change, and the dependent variable is what changes because of that.
A simple pendulum of length 1.5m has a bob of mass 2.0kg. State the formula for the period of small oscillations and evaluate it in this case. (2.43s)
A simple pendulum of length 1.5m has a bob of mass of 2.0kg, then the period for the small oscillations would be 2.456 s.
What is the frequency?It can be defined as the number of cycles completed per second. It is represented in hertz and inversely proportional to the wavelength.
The frequency of a pendulum is the reciprocal of the time period can be given by the following relation,
f = 1/T
As given in the problem A simple pendulum of length 1.5m has a bob of mass of 2.0kg.
The formula for the time period for the pendulum,
T = 2π√L/g
=2π√1.5/9.81
=2.456 s
Thus, the period for the small oscillations would be 2.456 s.
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Razona si, en las experiencias de Faraday, el efecto producido moviendo el circuito será el mismo que el producido moviendo el imán.
Answer:
moving the circuit or the magnet gives the same result
Explanation:
The faraday effect establishes that the temporal variation of imaginative flow produces an electric potential
fem = \(\frac{d \phi }{dt}\)dfi / dt
the magnetic flux is
Ф = B. A = B A cos θ
suppose for simplicity that the angle is zero so cos 0 = 1
Φ = B A
By analyzing this expression, the change in magnetic flux can converge while keeping the magnetic field fixed and varying the electric field or keeping the electric field fixed and varying the magnetic field.
Consequently moving the circuit or the magnet gives the same result
A 7.0 kg bowling ball has a moment of inertia of 2.8x10-2 kg m2, and a radius of 0.10 m. If it rolls down the lane at an angular speed of 40 rad/s without slipping, determine its angular momentum.
Hi there!
Angular momentum is equivalent to:
\(\large\boxed{L = I\omega}\)
L = angular momentum (kgm²/s)
I = moment of inertia (kgm²)
ω = angular velocity (rad/sec)
Plug in the given values for moment of inertia and angular speed:
\(L = (0.028)(40) = \boxed{1.12 kgm^2/s}\)
What angle (in degrees) is needed between the direction of polarized light and the axis of a polarizing filter to cut its intensity to one-fifth of its initial value?
The 60 degrees is needed between the direction of polarized light and the axis of a polarizing filter to cut its intensity to one-fifth of its initial value.
It is given that axis of a polarizing filter to cut its intensity to one-fifth of its initial value.
It is required to find the angle between the direction of polarized light and the axis of a polarizing filter to cut its intensity to one-fifth of its initial value.
What is the angle between the direction of polarized light and the axis of a polarizing filter?Suppose the angle between the polarizer and the axis of filter is θ.
The intensity of light that is passing after the filter is 0.2 l₀.
From the law of Malus, we have
I = I₀ \(cos^{2}\)θ
0.2I₀= I₀ \(cos^{2}\)θ
0.2 = \(cos^{2}\)θ
\(cos\\\)θ = 0.447
θ = 60°
Thus the angle between the direction of polarized light and the axis of a polarizing filter is 60 degree.
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Passengers fall forward when a bus suddenly stops. Using your knowledge of Newton's First Law and Inertia, explain why this phenomenon happens.
Answer:
The people on the bus fall forward because Newton's Law of Inertia states that and object in motion with stay in motion or an object at rest will stay at rest unless acted in by another force. The force of the bus stopping suddenly caused the passengers to fall forward because they were at rest position.
9. A 12 v battery is connected to four 5 ohm light bulbs. What is the equivalent
resistance for the bulbs in series? In parallel?
10. What would be the current through each light of problem 9?
For parallel circuit?
For series circuit?
-no bs answers
Calculate the density of 2.00 cm^3 of salt having a mass of 4.32 g. Express the answer using proper significant figures and units.
Answer:
Explanation:
Density = mass / volume
mass = 4.32 grams
volume = 2 cm^3
Density = 4.32 / 2
Density = 2.16 grams/cm^3
The units and the sig digs are correct for density.
what change should a rahul make
Answer:
Whats a rahul?
Explanation:
I'll edit this once I know :)
Answer: its B
Explanation: just took the quiz
can anyone help me please
Answer:
Gravity.
Rocket ships.
Ball.
Basketball.
Explanation:
Gravity has to do a lot with air. It puts the planets in there area.
Rocket Ship has to do a lot with air. If i'm right, they calculate the area, weather, about the air.
A ball gets throwed in the air, which gravity comes into place.
Basketball is also a similar example to a ball.
what is the wavelength in nanometers of light with a frequency of 3.80 × 1014 hz?
The wavelength in nanometers of light is 789 nm. The result is obtained by dividing the speed of light by the frequency.
How to find the wavelength of a light?Wavelength is the distance between the two successive crests or troughs of a wave. The wavelength of a light can be expressed as
λ = c/f
Where
λ = wavelengthc = speed of light f = frequencyThe scientific data shows that the speed of light is 3 × 10⁸ m/s.
So, we get the wavelength by the formula above.
λ = c/f
λ = 3 × 10⁸/3.80 × 10¹⁴
λ = 0.789 × 10⁸⁻¹⁴
λ = 0.789 × 10⁻⁶ m
In nanometers (10⁻⁹), the wavelength is
λ = 789 × 10⁻³ × 10⁻⁶ m
λ = 789 × 10⁻⁹ m
λ = 789 nm
Hence, the wavelength of the light is 789 nanometers.
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What do seismic waves and sound waves have in common?
3. An object accelerates from rest, with a constant acceleration of 4.5 m/s, what will its
velocity be after 30 s?
An object accelerates from the rest, which means that the initial speed of the object is 0 m/s, so the final velocity after 30 seconds will be equal to 135 m/s.
What is acceleration?Acceleration refers to the rate of change in both speed and direction of velocity over time. When something moves slower or faster in a straight line, it is said to have been accelerated. So because direction is always shifting, motion on a circular accelerates even while the speed is constant. Both factors add to the acceleration for every other types of motion.
It is a vector quantity, since acceleration has a magnitude and a direction. Another vector quantity is velocity. The velocity vector change during a certain period of time, split by that period of time, is the concept of acceleration.
The given information in the question is,
Initial speed, u = 0 m/s
Time, t = 30 s
Acceleration, a = 4.5 m/s²
Use the equation of motion,
v = u + at
v = 0 + (4.5)(30)
v = 135 m/s
Therefore, the final velocity of the object will be 135 m/s.
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The offspring resulting from sexual reproduction are exactly like their parents.
false
true
Answer:
false
Explanation:
As both parents contribute half of the new organism's genetic material, the offspring will have traits of both parents, but will not be exactly like either parent
Answer:
False
Explanation:
The only time you end up like your parent is asexual reproduction
what is the SI unit of wavelength of a wave?
The SI unit of wavelength of a wave is meters (m).
GUYS PLEASE HELPPPP
Q. A body is thrown at an angle of 30 degree with velocity of 30m/s downward, if the height of the tower is 15m find:
1) the time when body reaches the ground
2) displacement vector
3) angle when body hits the ground
4) max height?
1. To find the time when the body reaches the ground, we can use the vertical motion equation:
h = v₀y * t + (1/2) * g * t²
where:
h = height of the tower = 15m
v₀y = initial vertical velocity = v₀ * sin(θ) = 30m/s * sin(30°)
g = acceleration due to gravity = 9.8m/s²
t = time
Plugging in the values:
15 = (30 * sin(30°) * t) + (0.5 * 9.8 * t²)
Simplifying the equation:
15 = 15t * 0.5t² + 4.9t²
Combining like terms:
15 = 7.5t² + 4.9t²
Simplifying further:
15 = 12.4t²
Dividing both sides by 12.4:
t² = 15 / 12.4
Taking the square root of both sides:
t = √(15 / 12.4)
Calculating the value:
t ≈ 1.01 seconds
Therefore, the time it takes for the body to reach the ground is approximately 1.01 seconds.
2. To find the displacement vector, we need to calculate the horizontal and vertical components separately.
Horizontal component:
The horizontal displacement can be calculated using the formula:
x = v₀x * t
where:
v₀x = initial horizontal velocity = v₀ * cos(θ) = 30m/s * cos(30°)
t = time is taken to reach the ground (previously calculated as approximately 1.01 seconds)
Plugging in the values:
v₀x = 30m/s * cos(30°)
t = 1.01 seconds
Calculating the value:
v₀x ≈ 26.02 m/s
Vertical component:
The vertical displacement can be calculated using the formula:
y = v₀y * t + (1/2) * g * t²
where:
v₀y = initial vertical velocity = v₀ * sin(θ) = 30m/s * sin(30°)
g = acceleration due to gravity = 9.8m/s²
t = time is taken to reach the ground (previously calculated as approximately 1.01 seconds)
Plugging in the values:
v₀y = 30m/s * sin(30°)
t = 1.01 seconds
Calculating the value:
v₀y ≈ 15 m/s
Now we have the horizontal and vertical components of the displacement vector:
Horizontal component: x ≈ 26.02 m/s
Vertical component: y ≈ 15 m/s
Therefore, the displacement vector of the body is approximately (26.02 m/s, 15 m/s).
3. To find the angle when the body hits the ground, we can use the vertical and horizontal components of the velocity.
The horizontal component of the velocity, v₀x, can be calculated using the formula:
v₀x = v₀ * cos(θ)
where:
v₀ = initial velocity = 30m/s
θ = angle of projection = 30 degrees
Plugging in the values:
v₀x = 30m/s * cos(30°)
Calculating the value:
v₀x ≈ 26.02 m/s
The vertical component of the velocity, v₀y, can be calculated using the formula:
v₀y = v₀ * sin(θ)
where:
v₀ = initial velocity = 30m/s
θ = angle of projection = 30 degrees
Plugging in the values:
v₀y = 30m/s * sin(30°)
Calculating the value:
v₀y ≈ 15 m/s
Now, to find the angle when the body hits the ground, we can use the inverse tangent function:
θ = arctan(v₀y / v₀x)
Plugging in the values:
θ = arctan(15 m/s / 26.02 m/s)
Calculating the value:
θ ≈ 30.96 degrees
Therefore, the angle when the body hits the ground is approximately 30.96 degrees.
4. To find the maximum height, we can use the vertical motion equation:
h = v₀y² / (2 * g)
where:
h = maximum height
v₀y = initial vertical velocity = v₀ * sin(θ) = 30m/s * sin(30°)
g = acceleration due to gravity = 9.8m/s²
Plugging in the values:
h = (30 * sin(30°))² / (2 * 9.8)
Calculating the value:
h ≈ 27.55 meters
Therefore, the maximum height reached by the body is approximately 27.55 meters.
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a person throws a rock straight up into the air. at the moment it leaves the person's hand it is going 29 mph. when the rock reaches its peak, how fast is it going and what is the magnitude and direction of its acceleration? ignore air drag. express your answer using appropriate mks units.
In a downward direction, the magnitude of the acceleration is negative and velocity is zero.
What is acceleration?The rate of change in velocity is defined as acceleration.The rate at which speed changes with time, in terms of both speed and direction.If a factor or an object moves in a straight line, it is said to be extended.The acceleration of the Earth is always downward.As a result, when an object is launched upward, its acceleration is directed downward.If the object is moving downward, so is the acceleration.Here,
The object would cease to move at the maximum height, and thus the velocity of the object at the peak of motion would be seen to be zero. In this case, the acceleration would be negative.To learn more about acceleration refer to :
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DESPERATE WIL GIVE BRAINLIST
Which type of rock will be formed if sedimentary rock becomes molten and then hardens?
A. metamorphic
B. igneous
C. clastic
D. foliated
Answer:
Igneous
Explanation:
what is whether or not each type of glassware can be heated?
Whether or not each type of glassware can be heated depends on the specific type of glassware and the method of heating.
What is method of heating?The method of heating refers to the various ways in which heat energy can be transferred to an object or substance to raise its temperature. Some common methods of heating include:
Conduction: This involves transferring heat through direct contact between two objects or substances. For example, heating a pan on a stove by placing it directly on the burner.Convection: This involves transferring heat through the movement of fluids, such as air or water. For example, a forced-air heating system that circulates warm air through a building.Radiation: This involves transferring heat through electromagnetic waves, such as infrared radiation. For example, the sun heating the earth through radiation.Induction: This involves transferring heat through an electromagnetic field, which induces an electric current and produces heat. For example, an induction cooktop that heats a pot through an electromagnetic field.Whether or not each type of glassware can be heated depends on the specific type of glassware and the method of heating. Some types of glassware, such as borosilicate glass, are designed to withstand high temperatures and are commonly used for heating applications, while other types of glassware may be more susceptible to cracking or breaking when exposed to heat.
Glassware that is designed for heating applications will be labeled as such and will typically have a higher temperature tolerance than glassware that is not intended for heating. Some common types of glassware that are designed for heating include Pyrex, Kimax and Vycor glass.
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Which stable element is used to determine the age of volcanic rock?
argon
carbon-14
potassium
carbon-12
Answer:
The answer is A
Explanation:
Argon is the stable element that is used to determine the age of volcanic rock as it is found inside of it.
I dont know if the top is correct but the answer is because i just took the test.
The age of volcanic rock is determined by argon-40 by radiometric dating. Hence option A is correct.
What is radiometric dating?Using radioactive isotopes found within an object, radiometric dating may determine how ancient something is, such as a fossil, rock, or piece of wood. By analyzing the ratio of radioactive argon to radioactive potassium within a rock, we can use the potassium-argon dating technique to determine the age of the rock or when it was formed.
The fundamental idea behind radiometric dating is that by comparing an isotope's presence in a sample to its abundance on Earth and its known half-life (rate of decay), you may determine the sample's age. Because many radioactive materials degrade more slowly than others, radiometric dating is useful for determining the age of ancient objects.
Argon-40 is used to determine the age of volcanic rock. Therefore, option A is correct.
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Label the parts of this transverse wave,
A
B
C
What are the two most important intrinsic properties used to classify stars?.
The two intrinsic properties are used in the Hertzsprung-Russell (HR) diagram, which is a graphical representation of the relationship between a star's luminosity and temperature. The HR diagram is a powerful tool for understanding the evolution and properties of stars, and it is widely used in astronomy.
The two most important intrinsic properties used to classify stars are:
1. Luminosity: Luminosity is the total amount of energy emitted by a star per unit time. It is a measure of the star's intrinsic brightness and is related to its size and temperature. Luminosity is usually expressed in units of watts or solar luminosities.
2. Spectral type: Spectral type is a classification system based on the star's spectrum, which is a measure of the star's temperature and chemical composition. The spectral type is determined by the presence or absence of certain spectral lines in the star's spectrum, and it is usually classified using the letters O, B, A, F, G, K, and M, with O stars being the hottest and M stars being the coolest. The spectral type is also related to the star's color and surface temperature.
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What least wavelength in the visible range (400 nm to 700 nm) are not present in the third-order maxima
The least wavelength in the visible range (400 nm to 700 nm) that are not present in the third-order maxima is 400 nm.
To determine the least wavelength in the visible range (400 nm to 700 nm) that is not present in the third-order maxima, we can use the formula for constructive interference in a diffraction grating:
n * λ = d * sin(θ)
where n is the order of maxima, λ is the wavelength, d is the grating spacing, and θ is the angle of diffraction. In this case, n = 3 for the third-order maxima. To find the least wavelength not present, we can set θ to its maximum value, 90 degrees. So, we have:
3 * λ = d * sin(90)
At sin(90), the value is 1. Therefore, λ = d/3. This implies that the grating spacing, d, must be smaller than 3 times the shortest visible wavelength (400 nm) to ensure that this wavelength is present in the third-order maxima. If d >= 3 * 400 nm, the shortest wavelength will not be part of the third-order maxima. So, for a diffraction grating with a spacing equal to or larger than 1200 nm, the least visible wavelength of 400 nm will not be present in the third-order maxima.
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What particle determines how an atom bond
Did anyone do 05. 02 ionic and covalent bonds lab worksheet? If you did, can you post it on here please?
Ionic and covalent bonds are two types of chemical bonds that form between atoms.
What are ionic bonds?An ionic bond forms when one or more electrons are transferred from one atom to another. This results in the formation of positively charged cations and negatively charged anions, which are attracted to each other due to their opposite charges. Ionic bonds typically form between metals and nonmetals. Examples of ionic compounds include sodium chloride (NaCl) and calcium carbonate (CaCO3).
A covalent bond forms when two or more atoms share electrons in order to achieve a more stable electron configuration. This results in the formation of a molecule, where the atoms are held together by the shared electrons. Covalent bonds typically form between nonmetals. Examples of covalent compounds include water (H2O) and carbon dioxide (CO2).
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