We must first establish the slope of line FG and then locate the negative reciprocal of that slope in order to find the equation of a line that is perpendicular to line FG and passes through the point (2, 0).
The following formula can be used to determine line FG's slope:
slope is equal to y2 - y1 / x2 - x1.
The slope of line FG at points (4, 9) and (1, 3) is:
slope = (3 - 9) / (1 - 4) = -6 / -3 = 2
We choose the negative reciprocal of the slope, which is -1/2, since we want a line that is perpendicular to FG.
The slope (-1/2) and the line's intersection location (2, 0) are now known. The point-slope form of a linear equation can be used to create
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x u y = {z l z ∈ x or z ∈ y} is a
X u y = {z l z ∈ x or z ∈ y} is a valid set builder notation. Yes, this is a valid set builder notation. This specifies the elements of the set.
A set builder notation is a way of expressing a set using a description of its elements. In this particular set builder notation, the set consists of all elements that are either in set x or set y.
The notation is written as {z l z ∈ x or z ∈ y}, where the curly braces denote the set and the statement "z ∈ x or z ∈ y" specifies the elements of the set. This is a valid set builder notation because it correctly expresses the elements of the set.
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can i have some help pls
The ratio of boys to girls in a class is 3:5. There are 40 students in the class. How many more girls than boys are there?
Answer:
3x+5x=40
=8x=40
=x=5
then no.of boys= 3×5 = 15
and no. of girls= 5×5=25
girls more than boys= 25-15=10
mark me brainliest
pls it takes too much time to solve this
Answer:
There will be 10 more girls than boys in the class.
Step-by-step explanation:
5x+3x=40
8x = 40
8x/8 = 40/8
x = 5
5*2 = 10
Show that the function defined by df(x,y)=(y2−xy)dx−x2 dy is inexact. Test th integrating factor 1/xy2 to see whether it produces an exact differential. Calculate Hˉ∘(2000 K)−Hˉ∘(0 K) for H(g).
The function df(x, y) = (y^2 - xy)dx - x^2 dy is an inexact differential.
To determine if a function is exact or inexact, we need to check if its partial derivatives with respect to x and y satisfy the condition ∂M/∂y = ∂N/∂x, where df(x, y) = M(x, y)dx + N(x, y)dy.
In this case, we have M(x, y) = y^2 - xy and N(x, y) = -x^2. Calculating the partial derivatives, we find:
∂M/∂y = 2y - x
∂N/∂x = -2x
Since ∂M/∂y is not equal to ∂N/∂x (2y - x ≠ -2x), the function df(x, y) = (y^2 - xy)dx - x^2 dy is inexact.
Next, we can test the integrating factor 1/(xy^2) to see if it produces an exact differential. The integrating factor is denoted by μ(x, y) and is given by μ(x, y) = e^(∫(∂M/∂y - ∂N/∂x)/N dx). If the resulting expression becomes an exact differential, the integrating factor is successful.
In this case, the integrating factor μ(x, y) = e^(∫(2y - x)/(-x^2) dx) = e^(-2y/x). However, integrating factor μ(x, y) does not produce an exact differential, and hence, it is not a suitable integrating factor for this function.
Lastly, the expression H(g) represents the enthalpy change of a substance g. The notation Hˉ∘(2000 K) - Hˉ∘(0 K) indicates the difference in enthalpy between the substance at 2000 Kelvin and 0 Kelvin. To calculate this difference, additional information or a specific equation relating enthalpy change to temperature is needed. Without further details, it is not possible to provide a numerical calculation for Hˉ∘(2000 K) - Hˉ∘(0 K) for H(g).
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821 X ______ = 8,210
What is the acceleration of the sled and the normal force acting on it, to the nearest tenth? a = 1.3 m/s2; fn = 63.1 n a = 1.6 m/s2; fn = 65.6 n a = 1.9 m/s2; fn = 93.7 n a = 2.2 m/s2; fn = 78.4 n
The acceleration of the sled and the normal force acting on it is
a = 1.3 m/s²; FN = 63.1 N.
What is fictional force?The force produced when two surfaces collide and slide against one another is known as frictional force. The following variables impact the frictional force: Surface roughness and the amount of force pressing them together have the biggest an impact on these forces..
Given that,
8 kg is indicated as the sled[mass. ]'s
The fictional force is given as 2.4 N
A force of 20 N was exerted on the sled at angle of 50⁰.
The force is split into vertical and horizontal components,
\(F_{h} =F_{p}cos\) And \(F_{v}=F_{p} sin\)
Here \(F_{h}\) is the horizontal component and \(F_{v}\) is the vertical component.
\(F_{h} =20\) × \(cos50\) = 12.85575219 N
Similarly, \(F_{v} =\) 20 × \(sin50=15.32088886 N\)
Since there is no motion in the vertical direction, the sum of the vertical components is 0.
Hence, \(F_{N}\)+\(F_{P}sin =mg\) where g is the acceleration due to gravity.
\(F_{N}=mg-F_{p}sin50\)⁰
\(F_{N}=8\) × \(9.8-15.32088886\) [In this case, g is 9.8 m/s²]
= 63.1 N
The acceleration of the sled and the normal force acting on it is
a = 1.3 m/s²; FN = 63.1 N.
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a sample of 40 provided a sample mean of 25.9 . the population standard deviation is 6 . what is the p-value (to 4 decimals)? use the value of the test statistic rounded to 2 decimal places in your calculations.
The p-value is the probability of obtaining a test statistic at least as extreme as the one observed, assuming the null hypothesis is true.
In this case, the test statistic is the sample mean of 25.9 compared to the population mean, given the population standard deviation of 6. We use the z-score to calculate the p-value.
The z-score is calculated by subtracting the population mean from the sample mean, and then dividing by the population standard deviation divided by the square root of the sample size (40). In this case, the z-score is 0.3.
The corresponding p-value is 0.7519, to 4 decimal places. This means that there is a 75.19% probability of obtaining a test statistic at least as extreme as the one observed, given the null hypothesis is true.
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Evaluate the triple integral ∭E x^8 e^y dV where E is bounded by the parabolic cylinder z=16−y2z=16−y2 and the planes z=0,x=4, and x=−4
The value of the triple integral is (\(16^{11}\) / 11) [(\(e^{16}\) - 1) (\(cos^8\) φ) (2π)] where E is bounded by the parabolic cylinder z=16−y2z=16−y2 and the planes z=0,x=4, and x=−4.
To evaluate the triple integral ∭E \(x^8 e^y\) dV, where E is bounded by the parabolic cylinder z=16−y² and the planes z = 0,x = 4, and x = −4, we can use the cylindrical coordinate system. Here are the steps to solve the integral:
Write down the limits of integration for each variable:
For ρ, the radial distance from the z-axis, the limits are 0 to 4.
For φ, the angle in the xy-plane, the limits are 0 to 2π.
For z, the height, the limits are 0 to 16 - y² for the parabolic cylinder, and 0 to the plane z = 0.
Write the integral using cylindrical coordinates:
∭E \(x^8 e^y\) dV = ∫\(0^4\) ∫0²π ∫\(0^{(16-y^2)\) (\(\rho^9\) \(cos^8\) φ) (\(e^y\)) ρ dρ dφ dz
Evaluate the integral:
∫0²π ∫\(0^4\)(16-y²) (\(\rho^9\) \(cos^8\) φ) (\(e^y\)) ρ dρ dφ dz
= ∫\(0^4\) ∫0²π (\(cos^8\) φ) dφ ∫\(0^{(16-y^2)}\)(\(\rho^{10\) \(e^y\)) dρ dz
= ∫\(0^4\) ∫0²π (\(cos^8\) φ) [\((16-y^2)^{11}\) / 11 \(e^y\)] dy dφ
= ∫\(0^4\) ∫0²π (\(cos^8\) φ) [(\(16^{11}\) / 11) \(e^y\) - (11/11) y² (\(16^{10}\)) \(e^y\) + (55/11) \(y^4\) (\(16^9\)) \(e^y\) - ...] dφ
= ∫\(0^4\) (\(16^{11}\) / 11) \(e^y\) [(\(cos^8\) φ) (2π)] dy
= (\(16^{11}\) / 11) [(\(e^{16}\) - 1) (\(cos^8\) φ) (2π)]
Therefore, the value of the triple integral is (\(16^{11}\) / 11) [(\(e^{16}\) - 1) (\(cos^8\) φ) (2π)].
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2.4-9.1 + 12.5x=-39,44
Help me
Answer:
3.69
Step-by-step explanation:
2.4-9.1 = -6.7
-6.7+12.5x = 39.44
12.5x = 39.44 + 6.7
12.5x = 46.14
x = 46.14 / 12.5 = 3.69
Use each of the three corresponding base and height pairs to find the area of the triangle. Why is the area the same for each calculation?
Answer:
The three correct corresponding pairs that gives the same area are;
\(\begin{gathered} A=\frac{1}{2}\times10\times3.5=17.5cm^2 \\ A=\frac{1}{2}\times5\times7=17.5cm^2 \\ A=\frac{1}{2}\times14\times2.5=17.5cm^2 \end{gathered}\)The areas are the same in each case because the product of each pair is the same.
Explanation:
Given the base and height pairs in the question.
Let us use the corresponding pairs that gives the same area.
Firstly, for the first pair;
\(\begin{gathered} A=\frac{1}{2}\times10\times3.5=17.5cm^2 \\ A=\frac{1}{2}\times10\times7=35cm^2 \\ A=\frac{1}{2}\times10\times2.5=12.5cm^2 \end{gathered}\)Secondly, the second pair is;
\(\begin{gathered} A=\frac{1}{2}\times5\times7=17.5cm^2 \\ A=\frac{1}{2}\times5\times3.5=8.75cm^2 \\ A=\frac{1}{2}\times5\times2.5=6.25cm^2 \end{gathered}\)Thirdly, the third pair;
\(\begin{gathered} A=\frac{1}{2}\times14\times3.5=24.5cm^2 \\ A=\frac{1}{2}\times14\times7=49cm^2 \\ A=\frac{1}{2}\times14\times2.5=17.5cm^2 \end{gathered}\)Therefore, the three correct corresponding pairs that gives the same area are;
\(\begin{gathered} A=\frac{1}{2}\times10\times3.5=17.5cm^2 \\ A=\frac{1}{2}\times5\times7=17.5cm^2 \\ A=\frac{1}{2}\times14\times2.5=17.5cm^2 \end{gathered}\)The areas are the same in each case because the product of each pair is the same.
PART 2 : Show your work for the equation gives the exact answer do not approximate :)
The value of x is equal to 0.660441.
what is the logarithmic function?In mathematics, the logarithmic function is an inverse function to exponentiation. The logarithmic function is defined as For x > 0, a > 0, and a ≠1, y= logₐ x if and only if x = a^y Then the function is given by f(x) = logₐ x The base of the logarithm is a. This can be read it as log base a of x.
Given here: The exponential function 2(3e)ˣ=8
Simplifying further we get, (3e)ˣ=4
Taking log both sides we get x (ln3+1)=ln4
x×2.0986=1.386
x=0.660441
Hence, The value of x is equal to 0.660441.
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What is the ending balance of an account with $42,000 and earns simple interest at a
rate of 3% for 5 years?
Answer: $6,300.00
Step-by-step explanation:
Find the minimum sample size needed when estimating population proportion with 98% confidence level, margin of error to be within 5% a (a) p .768. nd (b) p is unknown.
The minimum sample size needed is approximately 480. The minimum sample size needed, when p is unknown, is approximately 752.
When the population proportion p is known to be 0.768, the minimum sample size needed to estimate the population proportion with a 98% confidence level and a margin of error within 5% is approximately 480.
When the population proportion p is unknown, we typically use a conservative estimate of p = 0.5, which provides the largest required sample size. In this case, the minimum sample size needed to estimate the population proportion with a 98% confidence level and a margin of error within 5% is approximately 752.
When p is known, we can use the formula for sample size calculation for estimating a population proportion: n = (Z² * p * (1 - p)) / (E²)
Where: Z is the Z-score corresponding to the desired confidence level (98% confidence level corresponds to Z ≈ 2.33 for a two-tailed test)
p is the estimated population proportion (0.768 in this case)
E is the desired margin of error (5% corresponds to 0.05)
Plugging in the values, we get: n = (2.33² * 0.768 * (1 - 0.768)) / (0.05²) ≈ 480. Therefore, the minimum sample size needed is approximately 480.
When p is unknown, we use a conservative estimate of p = 0.5, which provides the largest required sample size. Using the same formula as above, we calculate: n = (2.33² * 0.5 * (1 - 0.5)) / (0.05²) ≈ 752. Therefore, the minimum sample size needed, when p is unknown, is approximately 752.
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A regular hexagon has a perimeter of 57 inches.
What is the area of the hexagon?
Enter your answer, rounded to the nearest tenth, in the box.
Rounding to the nearest tenth, the area of the hexagon is 244.3 square inches.
Area of Hexagon:The area of a regular hexagon is calculated using the formula (3√3 / 2) × s^2, where s is the length of a hexagonal side. Given that we are talking about a regular hexagon, it is important to remember that all of the sides are the same length. The formula Area of the Hexagon = (3√3 / 2) × s^2, where's' is the length of the hexagonal side, can be used to determine the area of a regular hexagon when one of its sides is known.
All of the sides of the hexagon are the same length because it is a regular shape.
Therefore, each side has a length of 57 inches / 6 = 9.5 inches.
To find the area of the hexagon, we can use the formula:
Area = (3√3 / 2) × s^2
where s is length of a side.
Substituting s = 9.5 inches, we get:
Area = (3√3 / 2) × (9.5 inches)^2
Area ≈ 244.3 square inches
Rounding to the nearest tenth, the area of the hexagon is 244.3 square inches.
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Let f be the function given by f(x) = x + \(\frac{\sqrt{x+1} }{x-1}\)
Find and simplify f(3).
Responses
A f(3) = 5
B f(3) = 3 + 2\(\sqrt{2}\)
C f(3) = 3 + \(\sqrt{2}\)
D f(3) = 4
By evaluating f(x) in x = 3, we will get that:
f(3) = 4
Thus the correct option is D:
How to evaluate the function in x = 3?Here we have the following function:
\(f(x) = x + \frac{\sqrt{x + 1} }{x - 1}\)
We want to get f(3), and to get that, we just need to replace all the "x" in the equation by the number 3, we will get:
f(3) = 3 + (3 + 1)/(3 - 1)
f(3) = 3 + √4/2 = 4
With this, we can conclude that the correct option is D:
f(3) = 4.
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Determine the number of significant digits in the measurement.
50,008 ft
The number of significant digits in the measurement 50,008 ft is five. The significant digits convey information about the precision of the measurement, and it is important to consider them when performing calculations or reporting measured values in scientific or technical contexts.
In order to determine the number of significant digits, we follow these rules:
1. Non-zero digits are always significant. In this case, there are four non-zero digits: 5, 0, 0, and 8. They are all significant.
2. Zeros between non-zero digits are also significant. In this case, there is one zero between the non-zero digits (the zero between 5 and 8). This zero is significant.
3. Leading zeros (zeros to the left of the first non-zero digit) are not significant. In this case, the zero before 5 is a leading zero and is not significant.
Therefore, we have a total of five significant digits in the measurement 50,008 ft.
The number of significant digits indicates the level of precision or certainty in a measurement. In this case, the presence of five significant digits suggests that the measurement was made with a relatively high degree of precision, allowing for accurate representation of the quantity being measured. The significant digits convey information about the precision of the measurement, and it is important to consider them when performing calculations or reporting measured values in scientific or technical contexts.
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Image transcription textProblem 3 Consider a Turing machine that has It tapes. Prove using induction that this is equivalent to a
single tape Turing machine. (You may use either the proof or, even better, the result from class
that 2-tape turing machine is equivalent to a one—tape turing machine in your proof.) ... Show more
Using induction, it can be proven that a Turing machine with 'k' tapes is equivalent to a single tape Turing machine.
Let's consider the base case when k = 2, i.e., a two-tape Turing machine. We know from class that a two-tape Turing machine is equivalent to a one-tape Turing machine. Therefore, the statement holds true for k = 2.
Now, let's assume that a Turing machine with 'k' tapes is equivalent to a single tape Turing machine. We need to prove that it also holds for k + 1 tapes.
Suppose we have a Turing machine with k + 1 tapes. We can simulate this machine using a single tape Turing machine as follows:
1. We can combine the first two tapes into a single tape, simulating the behavior of a two-tape Turing machine.
2. We can then combine the resulting tape with the third tape, simulating the behavior of a three-tape Turing machine.
3. We can continue this process until we have combined all k + 1 tapes into a single tape.
By induction, we have shown that a Turing machine with k + 1 tapes can be simulated by a single tape Turing machine, assuming that a Turing machine with k tapes can be simulated by a single tape Turing machine.
Using induction, we have proven that a Turing machine with any number of tapes 'k' is equivalent to a single tape Turing machine. This result holds true for any positive integer value of 'k'. Therefore, a Turing machine with 'k' tapes can always be converted into a single tape Turing machine without loss of computational power.
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In Foundations of Art, students are cutting circular paper plates into sectors. If the diameter of the plate is 22 cm, determine the central anglenecessary to create a sector with an area of 220 cm². Round to nearest thousandth if necessary.
STEP 1
Interpret question to make sense geometrically.
We have circular shapes, thus, we are dealing with circles and these circles have their area, however, we seek the angle with which when used to cut the circle will give us an area of 220 sq cm.
Note that this is a fraction of the total area of the circle.
This will be illustrated diagrammatically below
Area of a sector is given as:
\(\begin{gathered} \frac{\theta}{360}\times\pi(\frac{d^2}{4}) \\ \text{The question requires us to get the angle }\theta\text{ after equationg the expression to 220 sq cm} \end{gathered}\)STEP 2
Find unknown
\(\begin{gathered} \text{Making }\theta\text{ the subject of the formulae gives} \\ \theta=\frac{220\times360\times4}{\pi\times22^2}=208.348^o \end{gathered}\)The ci
. if the entries of both a and a−1 are integers, is it possible that det a = 3? hint: what is det(a) det(a−1 )?
No, it is not possible for both a and a⁻ ¹ to have integer entries and for det(a) to be equal to 3.
How det(a) is possible?If the entries of both a and a⁻ ¹ are integers, it is not possible for det(a) to be equal to 3.
To see why, note that the determinant of a matrix and its inverse are related by the formula det(a⁻ ¹ ) = 1/det(a). Therefore, we have det(a) det(a⁻ ¹ ) = det(aa⁻ ¹ ) = det(I) = 1, where I is the identity matrix.
If det(a) = 3, then we would need det(a⁻ ¹ ) = 1/3 in order for det(a)
det(a⁻ ¹ ) = 1. However, since a⁻ ¹ also has integer entries, this is not possible, because 1/3 is not an integer.
Thus, it is not possible for both a and a⁻ ¹ to have integer entries and for det(a) to be equal to 3.
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How many different ways can you write a ratio?
Answer:
3 different ways
Step-by-step explanation:
Answer:
3 different ways
Step-by-step explanation:
hope this helps
example of the diffrent way to write a ratio :
5 to 10
5 : 10
\(\frac{5}{10}\)
you travel 600 miles in 11 hours. How many miles per hour did you travel?
find area of circle
Answer:
should be 314.16 possible that is incorrect because I calculated it by pie and not by 3.
Answer:
A = 314 cm^2
Step-by-step explanation:
A = pi x r^2
A = 3.14 x (10 x 10)
A = 3.14 x 100
A = 314 cm^2
Determine the number of terms, n, given the geometric series 1 3 9 27 ... and sn=3280.
The number of terms, 'n' is 8
How to determine the number of termsLet's determine the common ratio;
common ratio, r = 3/1 = 3
The formula for sum of geometric series with 'r' greater than 1 is given as; Sn = a( r^n - 1) / (r - 1)
n is unknown
Sn = 3280
Substitute the value
3280 = 1 ( 3^n - 1) / 3- 1
3280 = 3^n -1 /2
Cross multiply
3280 × 2 = 3^n - 1
6560 + 1 = 3^n
6561 = 3^n
This could be represented as;
3^8 = 3^n
like coefficient cancels out
n = 8
Thus, the number of terms, 'n' is 8
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What is the tenth term?
1) 1, 2, 8, 14, 20
2) 15, 23, 31,
Find the missing term:
3) 4, __, 22,
4) 25, __, 53,
The solution to each of the arithmetic sequence are:
1) a₁₀ = 56
2) a₁₀ = 87
3) missing term is 13
4) missing term is 14
What is the nth term of the arithmetic sequence?The formula for the nth term of an arithmetic sequence is:
aₙ = a + (n - 1)d
where:
a is first term
n is nth term
d is common difference
1) a = 2
d = 6
a₁₀ = 2 + (10 - 1)6
a₁₀ = 2 + 54
a₁₀ = 56
2) a = 15
d = 8
a₁₀ = 15 + (10 - 1)8
a₁₀ = 87
3) The missing term will be gotten by finding the common difference.
d = (22 - 4)/2
d = 18/2
d = 9
missing term = 4 + 9 = 13
4) The missing term will be gotten by finding the common difference.
d = (53 - 25)/2
d = 28/2
d = 14
missing term = 4 + 9 = 14
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Pls help I need this in 2 min!
Answer:
16
Step-by-step explanation:
on the number line it would be 9 and 7 on the same side because -7in () would be +7 and than you add it it would be 16
find a cartesian equation for the curve and identify it. r = 3 cos()
a. hyperbola b. parabola c. circle d. ellipse
e. limaçon
The limaçon has a characteristic loop is evident in the Cartesian equation. e.
The given equation is in polar form and it represents a limaçon.
We can convert this equation into Cartesian form using the following equations:
x = r cosΘ()
y = r sin(Θ)
Substituting r = 3 cos(Θ) get:
x = 3 cos(Θ) cos(Θ)
= 3 cos²(Θ)
y = 3 cos(Θ) sin(Θ)
= 3 sin(Θ) cos(Θ)
= (3/2) sin(2Θ)
The Cartesian equation of the curve is:
x²/9 + y²/27 = cos²(Θ) + (1/4)sin²(2Θ)
This equation represents a limaçon is a type of curve formed by a point moving around a fixed point while a second point moves around the first.
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3. Data from a quadratic relationship is provided on the table below. Use the systems approach to model this relationship as a quadratic function.
This confirms that the given data points fit the quadratic equation y = 4x2 - 4x + 3.
What is data?Data is information that is organized, structured, and stored in a specific way. It is used to create meaningful information from raw facts and figures. Data can be quantitative (numerical) or qualitative (descriptive). It can be collected from various sources such as surveys, experiments, and observations. Data can be used to make decisions, track progress, and uncover trends. It is a critical component of any business, organization, or research project.
The systems approach to model a quadratic relationship begins by examining the given data points to determine if they fit a quadratic equation. If they do, then the equation can be written in standard form: y = ax2 + bx + c.
In this case, the given data points fit a quadratic equation, so the equation can be written in standard form as: y = 4x2 - 4x + 3. The coefficient 'a' is 4, the coefficient 'b' is -4, and the constant 'c' is 3.
To verify this equation, we can substitute the given data points into the equation and check whether the results match the given values.
For example, when x = -1, y = 4(-1)2 - 4(-1) + 3 = 4 + 4 + 3 = 11. The given value for this point is 11, so the equation is correct.
We can check all the other data points in the same way to verify that the equation is accurate. This confirms that the given data points fit the quadratic equation y = 4x2 - 4x + 3.
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Write a rule for the function X -1 0 1 2 3 Y 1/8 1/4 1/2 1 2
An exponential function can be represented as:
\(f(x)=a\cdot b^x\)To find the constans "a" and "b" we can choose 2 given points and substitute it in the general function.
First, lets choose the point (0,1/4):
\(\begin{gathered} f(x)=a\cdot b^x \\ \frac{1}{4}=a\cdot b^0 \\ \frac{1}{4}=a\cdot1 \\ a=\frac{1}{4} \end{gathered}\)Now, we can write the general function again:
\(f(x)=\frac{1}{4}b^x\)To find "b", we can choose another point. Lets choose (3,2)
\(\begin{gathered} f(x)=\frac{1}{4}b^x \\ 2=\frac{1}{4}b^3 \\ 2\cdot4=b^3 \\ 8=b^3 \\ \text{If we factor 8, we will find that 8=2}^3 \\ \text{So,} \\ 2^3=b^3 \\ \text{If we have the same expoent, we have to have the same base. } \\ b=2 \end{gathered}\)Now, we write the rule of the fuction:
\(\begin{gathered} f(x)=a\cdot b^x \\ f(x)=\frac{1}{4}\cdot2^x \\ or \\ f(x)=2^{-2}\cdot2^x \\ Since\text{ we have the same base, we can sum the expoents:} \\ f(x)=2^{x-2} \end{gathered}\)The exponential function can be expressed as:
\(\begin{gathered} f(x)=\frac{1}{4}\cdot2^x \\ or \\ f(x)=2^{x-2} \end{gathered}\)Playing basketball carries a met value of 8 and you weigh 130lbs or roughly 59kg, approximately how many calories per minute would you burn?.
The average person burns 575-775 calories per hour in a game of basketball. If they are shooting baskets, they will burn 325-450 calories per hour.
What is Calories?
Calories are a measure of energy. Two main definitions of "calorie" are frequently used due to historical factors. The amount of heat required to increase the temperature of one kilogramme of water by one degree Celsius was the original definition of the large calorie, food calorie, as well as kilogramme calorie (or one kelvin). The amount of heat required to produce the same increase in one gramme of water was known as the small calorie or gramme calorie. As a result, 1000 small calories are equal to 1 large calorie.
How many calories do basketball players burn?
Calories expended per minute equal (MET x body weight in kg x 3.5) / 200
"MET" is a unit of measurement for the energy expended during a given period of physical exercise. The chart above shows the MET for each activity.The energy required to perform a task with a MET of 1 is roughly equivalent to what it would take to sit stationary at room temperature without actively digesting food.When compared to a task with a MET of 1, one with a MET of 2 requires twice as much energy. Ten times as much energy is expended on a work with a MET of 10 as on one with a MET of 1.Hence, the average person burns 575-775 calories per hour in a game of basketball. If they are shooting baskets, they will burn 325-450 calories per hour.
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if a between-subjects design uses random assignment, the design will be called a(n) a.nonequivalent groups design b.repeated-measures design c.independent groups design d.matched groups design
If a between-subjects design uses random assignment, the design will be called an independent groups design.
This means that participants are randomly assigned to either the experimental or control group, ensuring that the groups are equivalent at the start of the study. This type of design allows for a comparison of the effects of the independent variable on the dependent variable between the groups. I
t is important to note that an independent groups design is different from a matched groups design, in which participants are paired based on certain characteristics before being assigned to different groups. The use of random assignment in an independent groups design helps to control for extraneous variables and increase the internal validity of the study.
If a between-subjects design uses random assignment, the design will be called a(n) c. independent groups design. This design involves assigning participants to different experimental groups or conditions using random allocation. This ensures that each participant has an equal chance of being assigned to any group, reducing potential confounds and increasing the validity of the results. The independent groups design allows for comparison between the groups and the examination of the effects of the independent variable on the dependent variable.
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Let X ∈ Mn×n(R), E be the standard basis for Rn, and B = {v1, . . . , vn} be another basis for
Rn. If Y is the change of coordinate matrix from B-coordinates to E-coordinates, then prove
that [[X v1]B · · · X vn]B] = Y −1XY.
The matrix obtained by expressing the columns of X in the B-coordinates and then converting them to the E-coordinates using the change of coordinate matrix Y is equal to the product of \(Y^{-1}\), X, and Y.
Now let's explain the proof in detail. We start with the matrix X = [v1 · · · vn]E, where [v1 · · · vn] represents the matrix formed by the columns v1, v2, ..., vn. To express X in the B-coordinates, we multiply it by the change of coordinate matrix Y, resulting in X = Y[[X v1]B · · · X vn]B].
Now, to convert the B-coordinates back to the E-coordinates, we multiply X by the inverse of the change of coordinate matrix Y, yielding Y^(-1)X = [[X v1]B · · · X vn]B].
Hence, we have shown that [[X v1]B · · · X vn]B] = Y^(-1)XY, proving the desired result.
This result is significant in linear algebra as it demonstrates how to transform a matrix between different coordinate systems using change of coordinate matrices. It highlights the importance of basis transformations and provides a useful formula for performing such transformations efficiently.
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