Liquid water at 0ºC has to give up energy in order to become ice at 0ºC.
True or False

Answers

Answer 1

The correct answer to the given question is True.

Water at 0°C is still in the liquid phase and possesses some amount of thermal energy. In order for it to solidify into ice at the same temperature, it must release that energy in the form of heat. This is because the molecules in the liquid state are more disordered and possess more kinetic energy than in the solid state. When energy is removed, the molecules become more ordered and settle into a crystalline structure, resulting in the solidification of water into ice. This process is known as freezing, and it occurs when the temperature of liquid water is reduced below its freezing point (0°C at sea level).

The release of energy during the phase change from liquid to solid is called the heat of fusion, which is the amount of energy required to change the state of a substance from solid to liquid, or vice versa, at a constant temperature. In the case of water, the heat of fusion is 334 joules per gram.

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Related Questions

A Carnot heat engine operates between a heat source at TH and a sink at 350 K. If the thermal efficiency is 77%, and the output of the heat engine is 15 kW, what are TH and QH ? Show all of your work, and list any assumptions.

Answers

The temperature of the heat source (TH) in the Carnot heat engine is approximately 524.68 K, and the heat input (QH) is approximately 12.32 kW.

The thermal efficiency (η) of a Carnot heat engine is given by the formula:

η = 1 - (TC / TH)

Where TC is the temperature of the sink and TH is the temperature of the heat source. Rearranging the formula, we have:

TH = TC / (1 - η)

Substituting the given values, we can calculate TH:

TH = 350 K / (1 - 0.77)

TH ≈ 524.68 K

To calculate QH, we use the formula for thermal efficiency:

η = 1 - (TC / TH)

Rearranging the formula, we have:

QH = η * Q_out

Substituting the given values, we can calculate QH:

QH = 0.77 * 15 kW

QH ≈ 12.32 kW

Therefore, the temperature of the heat source (TH) in the Carnot heat engine is approximately 524.68 K, and the heat input (QH) is approximately 12.32 kW.

Assumptions made:

1. The Carnot heat engine operates based on the ideal Carnot cycle.

2. The heat transfer between the source and the engine is reversible, and there are no losses or inefficiencies.

3. The temperatures given are in absolute temperature (Kelvin) scale.

4. The Carnot engine is assumed to be working under steady-state conditions.

5. There are no other heat interactions or energy transfers not mentioned in the problem statement.

6. The working fluid or substance used in the Carnot engine is not specified but is assumed to be ideal for the Carnot cycle.

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4. The average lifetime of the tau lepton is 2.906 x 10^-12 seconds and the average lifetime of
the neutral pion is 8.4 x 10^-17 seconds. Which subatomic particle has a longer lifespan and
by approximately how many times longer. Show your work and answer in a complete
sentence.
Answer:

Answers

To determine which subatomic particle has a longer lifespan, we compare the average lifetimes of the tau lepton and the neutral pion. The average lifetime of the tau lepton is 2.906 x 10^-12 seconds, and the average lifetime of the neutral pion is 8.4 x 10^-17 seconds.

Comparing these values, we can see that the average lifetime of the tau lepton (2.906 x 10^-12 seconds) is significantly longer than the average lifetime of the neutral pion (8.4 x 10^-17 seconds).

To calculate how many times longer the lifespan of the tau lepton is compared to the neutral pion, we divide the average lifetime of the tau lepton by the average lifetime of the neutral pion:

(2.906 x 10^-12 seconds) / (8.4 x 10^-17 seconds) = 3.453 x 10^4

Therefore, the tau lepton has a lifespan that is approximately 3.453 x 10^4 (34,530) times longer than the neutral pion.

1. A car starts from the rest on a circular track with a radius of 300 m. It accelerates with a constant tangential acceleration of a = 0.75 m/s?. Determine the distance traveled and the time elapsed"

Answers

Starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², the car will travel a distance of approximately 0.2119 meters or 21.19 centimeters in 0.75 seconds.

To determine the distance traveled and the time elapsed by the car starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², we can use the equations of circular motion.

The tangential acceleration is the rate of change of tangential velocity. Since the car starts from rest, its initial tangential velocity is zero (v₀ = 0).

Using the equation:

v = v₀ + at

where v is the final tangential velocity, v₀ is the initial tangential velocity, a is the tangential acceleration, and t is the time, we can solve for v:

v = 0 + (0.75 m/s²) * t

v = 0.75t m/s

The tangential velocity is related to the angular velocity (ω) and the radius (r) of the circular track:

v = ωr

Substituting the values:

0.75t = ω * 300

Since the car starts from rest, the initial angular velocity (ω₀) is zero. So, we have:

ω = ω₀ + αt

ω = 0 + (0.75 m/s²) * t

ω = 0.75t rad/s

We can now substitute the value of ω into the equation:

0.75t = (0.75t) * 300

Simplifying the equation gives:

0.75t = 225t

t = 0.75 seconds

The time elapsed is 0.75 seconds.

To calculate the distance traveled (s), we can use the equation:

s = v₀t + (1/2)at²

Since the initial velocity (v₀) is zero, the equation becomes:

s = (1/2)at²

s = (1/2)(0.75 m/s²)(0.75 s)²

s = (1/2)(0.75 m/s²)(0.5625 s²)

s = 0.2119 meters or approximately 21.19 centimeters

Therefore, the car travels a distance of approximately 0.2119 meters or 21.19 centimeters.

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A man walks for 2 hours at a speed of 3m/s. How far does he travel?

Answers

First you get the data:

Velocity (v) = 3m/sDistance (d) = ??Time (t) = 2hr

Time conversion: hours to seconds:

1 hour = 3600 seconds

\(\bf{2\not{h}*\left(\dfrac{3600 \ seg}{1\not{h}}\right)=7200 \ seg }\)

We calculate the distance, using the formula:

                           \(\bf{d=t*v }\)

                           \(\bf{d=3600\not{seg}*3\frac{m}{\not{m}} }\)

                           \(\bf{d=21600 \ m}\)

Answer: I travel to 21600 meters.

Which is one use for radioactive isotopes? sanitation architecture meteorology archaeology

Answers

Answer:

Archaeology

Explanation:

Radioisotopes are radioactive atoms of an element in which their atoms contain excess energy making them unstable. When broken down they become more stable releasing radiations.

Carbon 14 is a radioactive isotope that is used in archaeology to study and estimate the lifespan and age of organic materials such as wood, leather. Carbon 14 can be used to estimate the ages of materials up to 50000 to 60000 years.

Answer:

archaeology

Explanation:

Help me finish this pls!! 100 points

Help me finish this pls!! 100 points

Answers

The light intensity or luminous intensity is defined as the quantity of visible light that is emitted in unit time per solid angle. The unit of luminous intensity is the lumen.

From the given information,

Incandescent bulb (lumens) = 800lm

Wattage (W) = 0.074W

Lumens per watt = 800/0.07 = 1066lm/W.
Thus, the incandescent bulb has an efficiency of 1066 lm/W.

Halogen bulb (in lumens) = 6000 lm

Wattage(W) = 300W

Lumens per watt = 6000/300 = 20lm/W. Thus, the efficiency of the halogen bulb is 20lm/W.

Fluorescent bulb (in lumens) = 2000 lm

Wattage(W) = 30W

Lumens per Watt = 2000/30 = 66.66 lm/W. Thus, the efficiency of the fluorescent bulb is 66.66lm/W.

Hence, the more efficient bulb is incandescent from the given wattage and lumens.

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A pharmaceutical company proposes a new drug treatment for alleviating symptoms of PMS (premenstrual syndrome). In the first stages of a clinical trial, it was successful for 7 out of 12 women. a. Con
a. Construct a​ 95% confidence interval for the population proportion.
b. Is it plausible that it is successful for only half the​population? Explain.

Answers

a. The 95% confidence interval for the population proportion is approximately 0.249 to 0.917.

b. It is also plausible that the success rate is higher than half the population.

a. To construct a 95% confidence interval for the population proportion, we can use the formula:

CI = p' ± Z * √((p'(1-p'))/n),

Where p' is the sample proportion (success rate), Z is the Z-score corresponding to the desired confidence level (95% in this case), and n is the sample size.

Given that the drug treatment was successful for 7 out of 12 women, the sample proportion is p' = 7/12 = 0.583.

To determine the Z-score for a 95% confidence level, we need to look up the critical value from the standard normal distribution. For a two-tailed test, the Z-score for a 95% confidence level is approximately 1.96.

Substituting the values into the formula, we have:

CI = 0.583 ± 1.96 * √((0.583(1-0.583))/12).

Calculating the expression within the square root:

√((0.583(1-0.583))/12) ≈ 0.170.

Substituting this value into the formula:

CI = 0.583 ± 1.96 * 0.170.

Calculating the lower and upper bounds of the confidence interval:

Lower bound = 0.583 - (1.96 * 0.170) ≈ 0.249,

Upper bound = 0.583 + (1.96 * 0.170) ≈ 0.917.

Therefore, the 95% confidence interval for the population proportion is approximately 0.249 to 0.917.

b. To determine if it is plausible that the drug treatment is successful for only half the population (p = 0.5), we can check if the value 0.5 falls within the 95% confidence interval. In this case, since the lower bound of the confidence interval (0.249) is less than 0.5, it is plausible that the success rate is lower than half the population. However, since the upper bound of the confidence interval (0.917) is greater than 0.5, it is also plausible that the success rate is higher than half the population. The 95% confidence interval indicates that the true population proportion could lie anywhere between 0.249 and 0.917, so we cannot definitively conclude that the success rate is exactly half the population.

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If 3 forces are acting on an object but the object is in equilibrium. Two of the forces are acting towards the left with 30N each, what must the magnitude and direction be of the third force?

Answers

Answer:

60N to the right

Explanation:

They are in equilibrium so they must cancel out in magnitude and direction

To solve this we must be knowing each and every concept related to  fundamental force and its calculations. Therefore, 60N must be magnitude and towards right is the direction of the third force.

What is fundamental force?

Nature is governed by four fundamental or universal forces. All stuff in the universe would disintegrate in the absence of these forces. Any pull or push that causes an item to change its physical condition is referred to as force (in terms of motion or deformity).

since total force acting on left side is of 60N. System is in equilibrium for that 60N of force should be there on the right side of the object. In equilibrium magnitude and direction of force gets cancels.

Therefore, 60N must be magnitude and towards right is the direction of the third force.

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Help ASAP I’ll give u branliest!! This isn’t really hard

Help ASAP Ill give u branliest!! This isnt really hard

Answers

Answer:

I'm pretty sure it's mist, drizzle, droplet, and then rain.

mist, drizzle, droplet, rain

Which city has the lowest temperature and slowest speed of sound?
a. Baguio
b. Manila
c. Lipa
d. Cagayan
e. Cebu
f. Tagaytay​​

Answers

ITS A a AAA A A  a A A  A A A A A

What is the difference between a photon and a wave?

Answers

A photon can travel many light years through empty space and after that trip it can still be detected by a human eye. An electromagnetic wave requires a powerful transmitter and huge receiving antenna antennas to bridge the distance. between two planets. The path of a photon is not affected by electric charges.

Stefan’s Law of radiation states that the radiation energy of a body is proportional to the fourth
power of the absolute temperature T (in the Kelvin scale) of a body. The rate of change of this
energy in a surrounding medium of absolute temperature M is thus
dT/dt = σ*(M^4−T^4)
where σ is a positive constant when T > M. Find the general (implicit) solution of Stefan’s
equation assuming M to be a constant.

Answers

The general (implicit) solution to Stefan's equation is given by:

ln((M^2 + T^2)/(M^2 - T^2)) = 2σt + 2C, where C is the constant of integration.

To solve Stefan's equation, we can separate the variables and integrate both sides. Let's proceed with the steps:

First, rewrite the equation as follows:

(1/(M^4 - T^4)) * dT/dt = σ

Now, we integrate both sides with respect to t:

∫(1/(M^4 - T^4)) * dT = ∫σ * dt

The left side of the equation requires integration by partial fractions. The integral can be expressed as:

1/(M^4 - T^4) = A/(M^2 + T^2) + B/(M^2 - T^2)

To determine the constants A and B, we can use the method of partial fractions. Multiply through by (M^4 - T^4) and then equate the numerators:

1 = A(M^2 - T^2) + B(M^2 + T^2)

Expanding and rearranging, we have:

1 = (A + B)M^2 + (A - B)T^2

Equating the coefficients of the powers of T, we get:

A + B = 0 (coefficient of T^2)

A - B = 1 (constant term)

Solving these equations simultaneously, we find A = 1/2 and B = -1/2.

Substituting the partial fraction decomposition back into the integral, we have:

∫(1/(M^4 - T^4)) * dT = ∫(1/2)*((1/(M^2 + T^2)) - (1/(M^2 - T^2))) * dT

Integrating both sides, we obtain:

(1/2) * (ln(M^2 + T^2) - ln(M^2 - T^2)) = σt + C

where C is the constant of integration.

Finally, solving for T, we can write the general (implicit) solution to Stefan's equation as:

ln((M^2 + T^2)/(M^2 - T^2)) = 2σt + 2C

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Two charges of 5 x 10-6 C are a certain distance apart. These two positive charges experience 3.6 N of repelling electrical force between them. How far apart are these charges?

Answers

Answer:

r = 0.2499 m

Explanation:

Use Coulomb's Law: \(F_{e} = kq_{1}q_{2} / r^{2}\) where Fe is the electric force, q1 and q2 are the 2 charges respectively, k is a constant (8.99*10^9 N • m^2 / C^2) and r is the distance.

\(3.6 N = (8.99*10^{9})(5*10^{-6})(5*10^{-6}) / r^{2}\)

r = 0.2499 m

The distance that should be apart from these charges should be considered when the r = 0.2499 m.

Calculation of the distance apart:

Since

Two charges of 5 x 10-6 C are a certain distance apart. These two positive charges experience 3.6 N of repelling electrical force between them

So

here we use Columb law

Electric force = k * two charges * two charges)r^2

3.6 N = (8.99*10^9) * ( 5 * 10^-6) * (5*10^-6)r^2

r = 0.2499 m.

Hence, The distance that should be apart from these charges should be considered when the r = 0.2499 m.

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How many digits are in front of the decimal in scientific notation?



0


2


1


3

Answers

Answer:

1

Explanation:

How many digits are in front of the decimal in scientific notation?

hat is the speed of a water wave of frequency 2 hz and wavelength 1.0 m ?

Answers

The speed of a water wave can be determined by multiplying the frequency by the wavelength.

Therefore, the speed of a water wave with a frequency of 2 Hz and a wavelength of 1.0 m is 2 m/s. This is because frequency is the number of complete waves that pass a given point in one second, and wavelength is the distance between two consecutive crests or troughs of a wave.

By multiplying these two values, we can calculate the speed of the wave. In this case, the wave travels at a speed of 2 meters per second. It is important to note that the speed of a wave depends on the properties of the medium through which it travels. Water waves, for example, travel at different speeds depending on factors such as the depth of the water, the temperature, and the salinity of the water.

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what is the distance between fringes (in cm) produced by a diffraction grating having 141 lines per centimeter for 653-nm light, if the screen is 1.50 m away? your answer should be a number with two decimal places, do not include unit.

Answers

The distance between fringes is 0.696 cm

The distance between fringes produced by a diffraction grating can be calculated using the equation:

dsin(\(\theta\)) = \(m\lambda L\)

where d is the spacing between the lines of the diffraction grating, theta is the angle between the incident light and the normal to the grating, m is the order of the fringe, and lambda is the wavelength of the light.

In this case, we know that the diffraction grating has 141 lines per centimeter, or a spacing of d = 1/141 cm per line. The wavelength of the light is \(\lambda\) = 653 nm = 6.53e-5 cm.

Plugging in these values and solving for y, we get:

y = (\(m\lambda L\))/d = (m6.53e-5150)/1.41 = 0.00696m = 0.696 cm

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could anyone solve this...its kinda urgent.​

could anyone solve this...its kinda urgent.

Answers

Answer:

1) A = lost volts, B = lower, C = a small pressure, D, = Newtons kg, E = Modulation.

2) A = True(?), B = true, C = True, D = True, E = not sure sorry.

Explanation:

A delivery truck with 2.0m -high aluminum sides is driving west at 50km/hr in a region where the earth's magnetic field is B= (5.0 x 10^-5 T, north)
a. What is the potential difference between the top and the bottom of the truck's side panels? E= ____ V

Answers

The possible potential difference between the truck's top and bottom side panels is 1.39 x 10^-4 V.

The potential difference between two points in an electric circuit is given by the product of the magnetic field, the cross-sectional area of the conductor, and the component of velocity perpendicular to the magnetic field.

The potential difference between the top and bottom of the truck's side panels can be calculated using the following formula:

V = Blv

Where:

V = potential difference (V)

B = magnetic field (T)

l = length of conductor (m)

v = velocity of conductor perpendicular to the magnetic field (m/s)

Given that the magnetic field is B = (5.0 x 10^-5 T, north) and the truck is moving west at 50 km/hr = 13.89 m/s, the potential difference between the top and bottom of the truck's side panels can be calculated as:

V = Blv = (5.0 x 10^-5 T) * (2.0 m) * (13.89 m/s) = 1.39 x 10^-4 V

It is important to note that the magnetic field is pointing north and the truck is moving west, so the velocity of the truck is perpendicular to the magnetic field, which means that the potential difference is not zero. Also, it is important to note that the velocity of the truck is given in km/hr and needs to be converted to m/s before using it in the equation.

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Pls help I'm desperate

If you place a hot piece of metal in a container of water, thermal energy flows from the metal to the water. What happens after the metal and the water reach the same temperature?

The flow of thermal energy stops, and the temperature remains constant.

The flow of thermal energy continues and causes both substances to become warmer.

The flow of thermal energy reverses and causes both substances to become warmer.

The flow of thermal energy reverses, and the water becomes colder.​

Answers

Answer:

I think your answer would be D

Explanation:

An athlete running the velocity 3m/s due east is confronted with two trade winds. One wind travelling at 10m/s in a direction north 65degrees east and another wind travelling at 8m/s in a direction south 70degrees east. Find the resultant velocity and direction of the athlete

Answers

Answer:

v = 10.09 m / s,   8.78 North of East

Explanation:

The easiest way to solve this exercise is to decompose the velocities into a coordinate system, where the x-axis coincides with the West-East direction and the y-axis coincides with the South-North direction.

athlete's velocity v₁ₓ = 3 m / s

wind speed 2 v₂ = 10 m / s with direction 65 north of east

          sin 65 = v_{2y} / v₂

          cos 65 = v₂ₓ / v₂

          v_{2y} = v₂ sin 65

          v₂ₓ = v₂ cos 65

          v_{2y} = 10 sin 65 = 9.06 m / s

          v₂ₓ = 10 cos 65 = 4.23 m / s

wind speed 3 v₃ = 8 m / s with direction 70 south of east

This angle measured from the positive side of the x-axis is

          θ = 360 - 70

          θ = 290

          sin 290 = v_{3y} / v₃

          cos 290 = v₃ₓ / v₃

          v_{3y} = v₃ sin 290

          v₃ₓ = v₃ cos 290

           v_{3y} = 8 sin 290 = -7.52 m / s

          v₃ₓ = 8 cos 290 = 2.74 m / s

now we can find each component of the velocity

         

X axis

        vₓ = v₁ + v₂ₓ + v₃ₓ

        vₓ = 3 + 4.23 + 2.74

        vₓ = 9.97 m / s

Y axis  

        v_y = v_{2y} + v_{3y}

        v_y = 9.06 - 7.52

         v_y = 1.54 m / s

to find the modulus let's use the Pythagorean theorem

         v = \(\sqrt{v_x^2 + v_y^2 }\)

         v = \(\sqrt{9.97^2 + 1.54^2}\)

         v = 10.09 m / s

let's use trigonometry for the direction

         tan θ = v_y / vₓ

        θ = tan⁻¹ v_y / vₓ

        θ = tan-1 1.54 / 9/97

         θ = 8.78

           

the address is 8.78 North of East

A new car leaves a parking lot with its odometer indicating 23 miles. Two hours later it returns with an odometer reading Which statement is true of the car's trip? of 123 mile Its average speed was 50 m.p.h, its displacement was 100 miles, and its average velocity was zero. Its average speed was zero, its displacement was zero, and its average velocity was 50 m.p.h. Its average speed was zero, its displacement was 100 mies, and its average velocty was 50 m.p.h. Its average speed was 50 m.p.h, its displacement was zero, and its average velocity was zero. O cating that a red sports car passed mile marker 3 on a highway with a speed limit of 60 m.p.h. Exactly five minut later the car passes the cop, who is sitting at mile marker number 9. Even though the speed limit, was the car speeding at any point between markers 3 and 9 cop's radar indicates that the car is going the O Yes, the car's average speed was 72 m.p.h. O Yes, the car was going at least 90 m.p.h. No. There is no way to prove the driver broke the speed limit.

Answers

The correct answer is: Its average speed was 50 m.p.h, its displacement was 100 miles, and its average velocity was zero.

We can calculate the car's average speed by using the formula:

average speed = total distance traveled / total time taken

The total distance traveled is the difference between the final and initial odometer readings:

total distance traveled = 123 miles - 23 miles = 100 miles

The total time taken is 2 hours.

average speed = 100 miles / 2 hours = 50 m.p.h.

Since the car returned to its starting point, its displacement is zero. Displacement is a vector quantity that refers to the change in position of an object from its initial position to its final position. In this case, the car ended up at the same position as it started, so its displacement is zero.

Average velocity is defined as displacement divided by the total time taken. Since the displacement is zero, the average velocity is also zero, regardless of the car's speed during the trip.

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electromagnetic radiation with a wavelength of 745 nm appears as red light to the human eye. the energy of one photon of this light is 2.67 × 10-19 j. thus, a laser that emits 1.3 ×10-2 j of energy in a pulse of light at this wavelength produces photons in each pulse. electromagnetic radiation with a wavelength of 745 nm appears as red light to the human eye. the energy of one photon of this light is 2.67 × 10-19 j. thus, a laser that emits 1.3 ×10-2 j of energy in a pulse of light at this wavelength produces photons in each pulse. 3.6 × 1019 6.5 × 1013 4.9 ×1016 4.7 × 10-24 2.1 × 10-17

Answers

Photons are massless.

What is electromagnetic radiation?

Electromagnetic radiation consists of electromagnetic field-propagating waves that carry electromagnetic radiant energy. Radio waves, microwaves, infrared, visible light, ultraviolet, X-rays, and gamma rays are included. All of these electromagnetic waves comprise the electromagnetic spectrum.

Given that:

E= Energy

h= Plank's constant = 6.6*10^-34 Js

c= speed of light = 3*10^8 m/s

E=hv = hc/λ

λ=745 nm = 745*10^-9 m

E=6.6*10^-34 * 3*10^8/745*10^-9

E= 2.657* 10^19 = 2.66* 10^19 J

hence, the energy of one photon of this light is 2.66* 10^19 J

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Correct question:

Electromagnetic radiation with a wavelength of 745 nm appears as a red light to the human eye. The energy of one photon of this light is...............  A) 2.67 x 10-28 B) 2.67 x 10-19 C) 1.48 x 10-22 D)1.48 × 10-31 E) 3.75 × 1018

What is the mass amount of a Proton and a Neutron?

Answers

The masses amount of a proton and neutron are 1.0087 and 1.0073 amu respectively.

What is a Proton?

This is defined as  sub atomic particle which is positively charged and is present in the nucleus while the neutron is also a particle present in the nucleus but has a neutral charge.

Electrons on the other hand are found outside the nucleus and are negatively charged. It is the sub atomic particle which is actively involved in a chemical reaction.

The masses of neutron and proton are 1.0087 and 1.0073 amu respectively and was discovered by scientists thereby making it the most appropriate choice.

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a coal wagon of mass 80 tonnes is rolling at 5 m/s west and hooks onto the back of a locomotive of mass 150 tonnes toling 2 m/s west. what is the combined new velocity

Answers

The combined new velocity of the coal wagon and the locomotive is 3.04 m/s.

What is velocity?

Velocity is the rate of change of displacement.

To calculate the combined velocity of the coal wagon and the locomtive, we use the formula below.

Formula:

V = mu+m'u'/(m+m').................. Equation 1

Where:

V = Combined velocitym = Mass of the coal wagonm' = Mass of the locomotiveu = Intial velocity of the coal wagonu' = Initial velocity of the locomotive

From the question,

Given:

m = 80 tonnesm' = 150 tonnesu = 5 m/su' = 2 m/s

Substitute these values into equation 1

V = [(80×5)+(150×2)](80+150)V = (700)/(230)V = 3.04 m/s

Hence, the combined new velocity is 3.04 m/s.

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atmospheric pressure is measured in all of the following units except ……… ? A. torr B. pascal C. bar D. newton?

Answers

Answer:

C. Bar

Explanation:

Consider three widely separated galaxies in an expanding universe. Imagine that you are located in galaxy 1 and observe that both galaxies 2 and 3 are moving away from you. If you asked an observer in galaxy 3 to describe how galaxy 2 appears to move, what would he or she say?

Answers

Answer:

The observer will say that galaxy 2 is moving away from galaxy 3 where he stands.

Explanation:

Since the galaxies are expanding, each one would move away from the others. Observers on all three galaxies have their frame of reference fixed on their own galaxies. Judging from their own galaxies, each observer will perceive the other galaxies moving away from his/or galaxy.

The observer at galaxy 3 will talk about galaxy 2 by doing is; he will say that galaxy 2 is moving far from him.

We are told that the universe is expanding and as such, the galaxies would be expanding and moving away from each other.

Since the galaxies are expanding, it means that they will be moving away from each other.

From time dilation principle, an observer at galaxy 3 will say that galaxy 2 is moving far from him.

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Find the center of mass of the following particles (drawn large so they can be seen)

Find the center of mass of the following particles (drawn large so they can be seen)

Answers

It is possible to suspend an object at rest from its center of gravity, and gravity won't induce it to begin rotating no matter how it is positioned.  

Thus, The center of gravity of an object will be located somewhere along a vertical line that passes through the point of suspension if you suspend it from any point and allow it to come to rest.

The gravitational acceleration is (almost) constant near the surface of the earth, where the center of mass also lies.

A place that represents the average or typical location of an object's mass, as if all of the mass were contained there, is known as the center of mass (CM). The geometric center of a uniform sphere serves as its center of mass. The barycenter is another name for the CM.

Thus, It is possible to suspend an object at rest from its center of gravity, and gravity won't induce it to begin rotating no matter how it is positioned.  

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Which statement describes what happens to rocky shorelines that absorb
energy from ocean waves?
A. The shorelines are strengthened.
B. Solid rock breaks apart.
C. The rocks form a barrier, and the shorelines are not affected.
D. Small rocks and sand block the waves' energy.

Answers

Answer:

B. Solid rock breaks apart.

Explanation:

Answer:

B

Explanation:

I did it on a test lol

Two point charges, initially 2.0 cm apart, experience a 1.0-n force. if they are moved to a new separation of 8.0 cm, what is the electric force between them?

Answers

The electric force between two point charges is 1/6 N.

Given data:

Initial distance between the charges (r1) = 2.0 cm

The new distance between the charges (r2) = 8.0 cm

Initial electric force between the charges - F1 = 1.0 N

Solution:

Lets' say the two charges are q and q2. The formula to calculate electric force between the two charges is given below

F = K |q1| |q2| / r^2

K is a constant.

New electric force can be expressed as

F2/F1 = K |q1| |q2| / r2^2 ÷  K |q1| |q2| / r1^2

F2/F1 = r2^2 / r1^2

After substituting the values we will get

F2 = 1.0 N ( 2.0 / 8.0)^2

F2 = 4/64 N

F2 = 1/16N

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help me please oml 2 one

help me please oml 2 one
help me please oml 2 one
help me please oml 2 one

Answers

Color: Both the bromine gas and steak have a brownish color.

What is bromine gas?

Bromine gas is a reddish-brown, nonflammable, and highly toxic gas with a very strong, unpleasant odor. It is composed of two heavy, diatomic, halogen molecules, Br2, and is the only nonmetal element that exists as a liquid at room temperature. Bromine gas is denser than air and is soluble in water and organic solvents.

Texture: The bromine gas is a gas and therefore has no texture, while the steak is solid and has a firm texture.
Temperature: The bromine gas is a gas and therefore has a lower temperature than the steak, which is at room temperature.
Bromine Gas and Juice:
Color: The bromine gas is brownish and the juice is a yellowish or orange color.
Texture: The bromine gas is a gas and therefore has no texture, while the juice is a liquid and has a smooth texture.
Temperature: The bromine gas is a gas and therefore has a lower temperature than the juice, which is at room temperature.

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