There are four possible ways to connect a bank of three transformers for three-phase service. These connections are known as delta-delta, wye-wye, delta-wye, and wye-delta connections.
Each connection type has its own advantages and applications depending on the specific requirements of the electrical system.
1. Delta-Delta Connection: In this configuration, the primary windings of the transformers are connected in delta (Δ), and the secondary windings are also connected in delta (Δ). It is commonly used in industrial applications where load unbalance and harmonics are not a concern.
2. Wye-Wye Connection: In this configuration, the primary windings of the transformers are connected in wye (Y), and the secondary windings are also connected in wye (Y). It is widely used in commercial and residential applications due to its ability to provide a neutral connection.
3. Delta-Wye Connection: In this configuration, the primary windings of the transformers are connected in delta (Δ), and the secondary windings are connected in wye (Y). It allows the system to provide a neutral connection and is often used in power distribution systems to supply loads with a neutral.
4. Wye-Delta Connection: In this configuration, the primary windings of the transformers are connected in wye (Y), and the secondary windings are connected in delta (Δ). It is commonly used in situations where the primary system has a neutral and the secondary system needs to be isolated.
The choice of connection depends on factors such as the type of load, voltage requirements, grounding considerations, and system configuration. Each connection has its own benefits and trade-offs in terms of voltage regulation, fault tolerance, and flexibility in meeting various electrical system requirements.
Learn more about harmonics here:
https://brainly.com/question/32422616
#SPJ11
An article that discusses pharaohs and gives examples and explains how they look. Which text structure is that?
The correct answer to this open question is the following.
The text structure of an article that discusses pharaohs and gives examples and explains how they look is a description.
The text structure called description allows the reader to fully know the characteristics of the people it is referring to, including some important details. That is why the author of a description text adds words like "such as" and "for example."
When describing something, the write is giving structure to the text and sequence. What comes first., what is followed, and so on.
That is why The text structure of an article that discusses pharaohs and gives examples and explains how they look is a description. It includes cause and effect sentences, and some comparisons in order to contrast an idea.
The pinion gear A on the motor shaft is given a constant angular acceleration a3 rad/s2. If the gears A and B have the dimensions shown, determine the angular velocity and angular displacement of the output shaft . when 2 s starting from rest. The shaft is fixed to B ancd turns with it. -125 mm 35 mm
The angular displacement of the output shaft after 2 seconds is 2a3 rad, and its angular velocity is 2a3 rad/s.
To solve this problem, we need to use the kinematic equations of rotational motion. The given constant angular acceleration of pinion gear A is a3 rad/s^2. We also know that the system starts from rest, which means the initial angular velocity is zero.
Using the equation:
θ = ω0t + 1/2 a3t^2
where θ is the angular displacement, ω0 is the initial angular velocity, t is the time, and a3 is the constant angular acceleration of pinion gear A.
We can find the angular displacement of pinion gear A after 2 seconds:
θ = 0 + 1/2 (a3)(2)^2
θ = 2a3 rad
Since pinion gear A and gear B have meshed together, they have the same angular displacement. Therefore, the angular displacement of gear B and the output shaft is also 2a3 rad.
Using the equation:
ω = ω0 + a3t
where ω is the final angular velocity.
We can find the final angular velocity of pinion gear A after 2 seconds:
ω = 0 + (a3)(2)
ω = 2a3 rad/s
Since gear A and gear B have the same pitch diameter, they also have the same angular velocity. Therefore, the angular velocity of gear B and the output shaft is also 2a3 rad/s.
Know more about angular displacement here:
https://brainly.com/question/26483834
#SPJ11
a homeowner consumes 700 kwh of energy in march. determine the average cost per kwh for the month using the following residential rate schedule: base monthly charge of $10.00. first 100 kwh per month at 16 cents/kwh. next 200 kwh per month at 10 cents/kwh. over 300 kwh per month at 6 cents/kwh.
Answer:
10 cents/kwh
Explanation:
Base monthly charge = $10.00
First 100 kwh at $0.16/kwh = $16.00
Next 200 kwh at $0.10/kwh = $20.00
Remaining 400 kwh at $0.06/kwh = $24.00
Total charge = $10 + $16 + $20 + $24 /(100+200+400)
Average cost = $70/700 or 10 cents/kwh
difference between velocity profile and velocity distribution
Answer:
Profile is a graphical representation of velocity distribution
How does the use of databases improve or enhance an organization's data collection process?
Do you think an organization could function without the use of databases?
Provide details and examples to support your answer
By offering a centralized repository for collecting and managing data, databases can considerably improve an organization's data collection process.
It will be very difficult for organizations to function without the use of data base.
What is the use of Database?Databases are used to store, organize, and access data of any type. They collect information about people, places, or things. That information is gathered in one place so that it may be studied and analyzed. Databases are simply organized collections of data.
Databases allow us to work efficiently with massive amounts of data. They make data updating straightforward and reliable, and they help with accuracy.
Learn more about database here: https://brainly.com/question/26096799
#SPJ1
A rigid tank contains 10kg of R134a initially at 20 degrees and 180 kPa. The R134a is now cooled while being stirred until its pressure drops to 100kPa. Determine the entropy change of the R134a during this process.
The entropy change of the R134a during this process is 0.035 KJ
What is entropy change?Entropy change refers to the measure of the degree of disorder or randomness in a thermodynamic system. It is a concept in thermodynamics that describes the amount of energy that is unavailable for doing work in a given process.
The entropy change of a system can be calculated by subtracting the initial entropy of the system from its final entropy.
T = PV/(mR)
T1 = 180 / 10 * 0.08314
T2 = P2V/(mR)
Now T1 = T2
such that
0.08314 ln (100kpa / 180)
= 0.035 KJ
The entropy change of the R134a during this process is 0.035 KJ
Read more on entropy change herehttps://brainly.com/question/6364271
#SPJ1
a low carbon steel is heated to a temperature below the lower transformation temperature before cooling in an effort to soften it slightly. which is the heat treating process being performed?
The heat treating process being performed when a low carbon steel is heated to a temperature below the lower transformation temperature before cooling in an effort to soften it slightly is known as annealing.
Annealing is a heat treatment process that involves heating a metal to a specific temperature and holding it there for a certain amount of time before allowing it to cool down slowly. The purpose of annealing is to make a metal softer, more ductile, and more machinable. It also improves its toughness and makes it easier to form.Annealing can be done in several different ways, including full annealing, stress relief annealing, and spheroidizing annealing.
Full annealing involves heating the metal to a temperature above its upper critical temperature, holding it there for a period of time, and then allowing it to cool down slowly. Stress relief annealing involves heating the metal to a lower temperature and holding it there for a shorter period of time, while spheroidizing annealing is used to improve the machinability of high-carbon steels.
Learn more about Annealing: https://brainly.com/question/31386274
#SPJ11
For a steel alloy it has been determined that a carburizing heat treatment of 11.3 h duration will raise the carbon concentration to 0.44 wt% at a point 1.8 mm from the surface. Estimate the time necessary to achieve the same concentration at a 4.9 mm position for an identical steel and at the same carburizing temperature.
This question is incomplete, the complete question is;
For a steel alloy it has been determined that a carburizing heat treatment of 11.3 h duration at Temperature T1 will raise the carbon concentration to 0.44 wt% at a point 1.8 mm from the surface. A separate experiment is performed at T2 that doubles the diffusion coefficient for carbon in steel.
Estimate the time necessary to achieve the same concentration at a 4.9 mm position for an identical steel and at the same carburizing temperature T2.
Answer:
the required time to achieve the same concentration at a 4.9 is 83.733 hrs
Explanation:
Given the data in the question;
treatment time t₁ = 11.3 hours
Carbon concentration = 0.444 wt%
thickness at surface x₁ = 1.8 mm = 0.0018 m
thickness at identical steel x₂ = 4.9 mm = 0.0049 m
Now, Using Fick's second law inform of diffusion
\(x^2\) / Dt = constant
where D is constant
then
\(x^2\) / t = constant
\(x^2_1\) / t₁ = \(x^2_2\) / t₂
\(x^2_1\) t₂ = t₁\(x^2_2\)
t₂ = t₁\(x^2_2\) / \(x^2_1\)
t₂ = (\(x^2_2\) / \(x^2_1\))t₁
t₂ = \((\) \(x_2\) / \(x_1\) \()^2\) × t₁
so we substitute
t₂ = \((\) 0.0049 / 0.0018 \()^2\) × 11.3 hrs
t₂ = 7.41 × 11.3 hrs
t₂ = 83.733 hrs
Therefore, the required time to achieve the same concentration at a 4.9 is 83.733 hrs
What Machine Process is #1
Answer:
The first Machine Process is Turning.
Explanation:plz mark brainliest if i am right
Answer:
I believe its turning.
A galvanic cell is made up of a zinc electrode in a 1M solution of ZnSO4 and another of nickel in a 1M NiSO4 solution. The two electrodes are separated by a porous wall so that mixing of the solutions is avoided. An external wire with a switch connects the two electrodes. When the switch has just closed. A) In which of the electrodes does oxidation occur?b) WHICH OF THE ELECTRODES IS THE ANODE OF THE CELL?c) Which electrode corrodes?d) What is the emf of the galvanic cell when the switch has just closed?
A) Oxidation occurs at the zinc electrode. B) The zinc electrode is the anode of the cell. C) The zinc electrode corrodes, as it is losing electrons to form ions, which dissolve into the solution.
An electrode is a conductor that is used to establish electrical contact with a non-metallic part of a circuit, such as an electrolyte, a gas, or a vacuum. An electrode is a solid metal or semiconductor material that is used to conduct electrons to or from a chemical reaction system.
D) The emf of the galvanic cell can be calculated using the equation: emf = E(cathode) - E(anode)
Learn more about electrode here:
https://brainly.com/question/13098144
#SPJ4
the platform in a two-point scaffold should be no more than _____ inches wide.
The platform in a two-point scaffold should be no more than 14 inches wide.
This is in accordance with OSHA regulations, which require the platform width to be at least 14 inches but no more than 20 inches. The reason for this is to ensure that workers have enough space to work comfortably while also reducing the risk of tripping or falling. Additionally, the platform should be level and secured properly to prevent any movement or instability. It's important to note that the weight capacity of the platform should also be taken into consideration to avoid overloading it. In summary, the platform width of a two-point scaffold should be within the range of 14-20 inches and must be properly secured and leveled for safe use.
To know more about inches visit:
https://brainly.com/question/9264277
#SPJ11
PLEASE HELP WITH THIS ASAP! Thanks
Answer:
Architect
Explanation: You need to be unique and creative to be an architect.
How do birds achieve take-off, gliding, dive, etc.? How do they modify their body shape?
Nec ________ covers selection of time-delay fuses for motor- overload protection.
Nec Article 430 covers selection of time-delay fuses for motor- overload protection.
What article in the NEC covers motor overloads?Article 430 that is found in National Electrical Code (NEC) is known to be state as “Motors, Motor Circuits and Controllers.” .
Note that the article tells that it covers areas such as motors, motor branch-circuit as well as feeder conductors, motor branch-circuit and others.
Therefore, Nec Article 430 covers selection of time-delay fuses for motor- overload protection.
Learn more about motor- overload from
https://brainly.com/question/20738481
#SPJ1
FD=CD*((P*(V^2)*A)/2)
Please solve for V
Answer:
The answer is V = √2FD ÷ CD × PA
Explanation:
FD = CD × PV²A ÷ 2
V² = 2FD ÷ CD × PA
V = √2FD ÷ CD × PA
Thus, The value of V is V = √2FD ÷ CD × PA
-TheUnknownScientist 72
online registration verifies that you meet all prerequisites of a particular course before you can successfully register for the course. this information system is using _________ to ensure that business rules are followed.
The information system for online registration is using data validation to ensure that business rules are followed.
Data validation is the process of verifying that data entered into a system is accurate, complete, and meets the required format and business rules. In this case, the system is checking whether the user has met all the necessary prerequisites for a particular course before allowing them to register. This helps to ensure that students are only registered for courses that they are qualified to take, which can help to prevent problems such as dropped courses or failing grades. Overall, data validation is an important tool for ensuring that business rules are followed in information systems, and it plays a critical role in ensuring data quality and accuracy.
To know more about data validation click here:
brainly.com/question/29033397
#SPJ4
A tank contains 50 kg of water, which is stirred by a paddle wheel at 300 rpm while transmitting a torque of 0.2 kNm. After the tank achieves steady state, determine (a) the rate of heat transfer, (b) the rate of entropy transfer, and (c) the rate of entropy generation in the tank's universe. Assume the atmospheric temperature to be 25C.
Answer:
To determine the rate of heat transfer, we need to use the first law of thermodynamics, which states that the rate of change of energy in a system is equal to the rate of heat transfer into the system minus the rate of work done by the system. At steady state, the rate of change of energy is zero, so we have:
Rate of heat transfer = Rate of work done by the paddle wheel
The rate of work done by the paddle wheel can be calculated using the formula:
Rate of work = torque x angular velocity
where torque is given as 0.2 kNm and angular velocity is given as 300 rpm. We need to convert angular velocity to radians per second:
Angular velocity = 300 rpm x (2π/60) = 31.4 rad/s
Rate of work = 0.2 kNm x 31.4 rad/s = 6.28 kW
Therefore, the rate of heat transfer is 6.28 kW.
To determine the rate of entropy transfer, we need to use the formula:
Rate of entropy transfer = Rate of heat transfer / Temperature
The temperature is given as 25°C, which is equivalent to 298 K.
Rate of entropy transfer = 6.28 kW / 298 K = 0.0211 kW/K
Therefore, the rate of entropy transfer is 0.0211 kW/K.
To determine the rate of entropy generation, we need to use the formula:
Rate of entropy generation = Rate of heat transfer / Temperature - Rate of entropy transfer
Rate of entropy generation = 6.28 kW / 298 K - 0.0211 kW/K = 20.97 kW/K
Therefore, the rate of entropy generation is 20.97 kW/K.
Explanation:
Hope this helps!
What is the eye an example of?
sense organ
stimulus
a relay neuron
sens organ is the eye example
____ is based on the observation that the rate of increase in transistor density on microchips had increased steadily, roughly doubling every 18 to 24 months.
Answer:
Moore's Law
Explanation:
An observation that the number of transistors in a dense integrated circuit doubles about every two years (24 months), was made by Gordon E. Moore, the co-founder of Intel, and this observation became Moore's Law in 1965.
Therefore, Moore's Law is based on the observation that the rate of increase in transistor density on microchips had increased steadily, roughly doubling every 18 to 24 months.
Refrigerant 134a passes through a throttle valve as part of a refrigeration cycle. The fluid enters the valve as compressed liquid at a pressure of 0.8 MPa and a temperature of 25 C. It exits the valve at -20 C. Find the exit pressure and the exit specific internal energy.
The exit pressure will be 1.3273 bar = 0.1327 MPa and the exit specific internal energy 228.61 KJ/Kg .
1.) In graph,
1-2 = Compressor
3-4 = Throttle value
\(T_{1} \\\) = \(T_{4}\) = -20°C = 253 K
\(T_{3}\) = 25°C = 298 K
\(P_{3}\) = 0.8 MPa
Assuming saturated fluid is entering the value at point (3),
using table of R-134a properties
∵ \(h_{3} =h_{4}\) = 234.49 KJ/Kg (at 25°C,8 bar)
at \(T_{3}\) = 25° , \(P_{3}\) = 0.8 MPa =8 bar
At -20°C, \(hf_{4}\) = 173.6 KJ/Kg
\(hg_{4}\) = 386.6 KJ/Kg
\(h_{4} = hf_{3} + n_{4} ( hg_{4} - hf_{4} )\) = 234.49
173.6 + \(n_{4}\) [386.6 - 173.6] = 234.49
\(n_{4}\) = 0.285
\(P_{4} = P_{1} = P_{sat}\) = 1.3273 bar = 0.1327 MPa
2.)
Exit specific internal energy, using table R-134a
\(U_{4} = uf_{4} + n_{4} (ug_{4} - uf_{4} )\)
at -20°c, \(uf_{4}\\\) = 173.65, ufg = 192.85 KJ/ Kg
\(U_{4}\) = 173.65 + 0.285 (192.85)
\(U_{4}\) = 228.61 KJ/Kg
Learn more about Refrigerant here https://brainly.com/question/26395073
#SPJ10
Part A
In the circuit above, let C=100mF, L=1H, and R=5Ω. Find the root(s) of the characteristic equation of the circuit.
Part B
If C is adjusted to give a resonant frequency of 100rad/s, what is/are the root(s) of the new characteristic equation? Use the inductance and resistance from the previous part.
Part C
For what capacitance is the response critically damped? Use the inductance and resistance from the previous parts.
Part A : Since the discriminant is negative, the roots are complex
The roots of the characteristic equation are -2.5 + 1.9365i and -2.5 - 1.9365i.
Part B : Since the new discriminant is also negative, the roots are complex
The roots of the characteristic equation are -2.5 + 99.9687i and -2.5 - 99.9687i.
Part C : For the response to be critically damped, the capacitance should be adjusted to 0.0001F.
To find the characteristic equation of the circuit, we can start by writing the differential equation governing the circuit's behavior. The equation for an RLC circuit is given by:
LC d²q/dt² + RC dq/dt + q = 0, where q is the charge on the capacitor.
Part A:
Given C = 100mF, L = 1H, and R = 5Ω, we can substitute these values into the differential equation:
(1H)(100mF) d²q/dt² + (5Ω)(100mF) dq/dt + q = 0
Simplifying, we get:
0.1 d²q/dt² + 0.5 dq/dt + q = 0
Now we can find the characteristic equation by assuming a solution of the form q = e^(st):
0.1s² + 0.5s + 1 = 0
Multiply the equation by 10 to get rid of the decimal:
s² + 5s + 10 = 0
Using the quadratic formula, we can find the roots of this equation:
s = (-b ± √(b² - 4ac)) / (2a)
Plugging in a = 1, b = 5, and c = 10:
s = (-5 ± √(5² - 4(1)(10))) / (2(1))
s = (-5 ± √(-15)) / 2
Since the discriminant is negative, the roots are complex:
s = (-5 ± √15i) / 2
Therefore, the roots of the characteristic equation are -2.5 + 1.9365i and -2.5 - 1.9365i.
Part B:
To find the new characteristic equation with a resonant frequency of 100 rad/s, we need to adjust the capacitance. The resonant frequency is given by:
ω = 1 / √(LC)
Substituting the given values, we have:
100 = 1 / √(1(100mF))
Squaring both sides and rearranging, we find:
10 = 1 / C
C = 1/10 = 0.1F
Now, we can find the new characteristic equation with this adjusted capacitance value. Substituting the values R = 5Ω, L = 1H, and C = 0.0001F into the characteristic equation, we have:
s^2 + (5/1)s + 1/((0.0001)(1)) = 0
s^2 + 5s + 10000 = 0
To find the root(s), we solve this quadratic equation:
s = (-5 ± √(5^2 - 4(1)(10000))) / 2(1)
Simplifying further:
s = (-5 ± √(25 - 40000)) / 2
s = (-5 ± √(-39975)) / 2
Again, the discriminant is negative, so the roots of the new characteristic equation are complex numbers:
s = (-5 ± √39975i) / 2
Part C:
For the response to be critically damped, the roots of the characteristic equation should be real and equal. Since we have already found the roots in Part B as complex conjugates, we need to find the capacitance value for which the roots become real and equal.
The characteristic equation is:
s = -2.5 ± 1.9365i
For the roots to be real and equal, the imaginary part must be zero. Therefore, we set 1.9365i equal to zero:
1.9365i = 0
This implies that s = -2.5. We can substitute this value into the resonant frequency equation:
ω = 1 / √(LC)
100 = 1 / √(1H * C)
Squaring both sides and rearranging, we have:
C = 1 / (100² * 1H)
C = 1 / 10,000 = 0.0001F
Therefore, for the response to be critically damped, the capacitance should be adjusted to 0.0001F.
To know more about capacitance, visit the link : https://brainly.com/question/13578522
#SPJ11
Explain why a project team would choose to prepare a low-fidelity version of a Web site design using sticky notes
A project team may choose to prepare a low-fidelity version of a website design using sticky notes for several reasons:
Sticky notes allow for quick and easy changes. Since they are easy to move around and modify, the team can iterate on the design quickly, making adjustments and improvements without investing significant time or resources. This promotes an iterative design process, enabling the team to refine and enhance the design rapidly.Collaboration and Communication: Sticky notes facilitate collaboration and communication among team members. They can be easily placed on a whiteboard or a wall, allowing everyone to visualize and discuss the design together. Team members can share their ideas, suggestions, and feedback by directly manipulating the sticky notes, fostering effective communication and collaboration within the team.Low Cost and Accessibility: Sticky notes are affordable and readily available, making them a cost-effective option for creating prototypes. Compared to digital design tools or high-fidelity prototypes, sticky notes are inexpensive and accessible to all team members, regardless of their technical expertise. This inclusivity encourages participation from different stakeholders and promotes a diverse range of perspectives during the design process.Focus on Conceptual Design: Low-fidelity designs with sticky notes primarily focus on the conceptual aspects of the website, such as layout, content organization, and user flow. By avoiding intricate details or visual aesthetics, the team can concentrate on the fundamental structure and functionality of the design. This allows for early validation and testing of design concepts before investing significant time and resources in higher-fidelity prototypes.Emphasis on User Experience: Sticky notes enable the team to simulate user interactions and test the usability of the design. By physically moving and rearranging the sticky notes, the team can simulate user flows and assess the user experience. This hands-on approach allows for early identification of potential usability issues, leading to design improvements and a better user experience.
To learn more about fidelity click on the link below:
brainly.com/question/26959627
#SPJ11
Match each term to its measuring unit. amperes(A) farad(F) ohm(Ω) henry(H) volts(V) d(F) ohm(Ω) henry(H) volts(V) watts(W) resistance arrowRight voltage arrowRight current arrowRight power arrowRight
Answer:
Every measuring quantity has a unit.
Explanation:
Ampere or A is the measuring unit of current intensity.
Farad or F is the measuring unit of electrical capacitance.
Ohm or Ω is the measuring unit of electrical resistance.
Henry or H is the measuring unit of inductance
Volts or V is the measuring unit of voltage
Watts or W is the measuring unit of power.
3. Of the following answers, which is NOT a way for employees to control exposure routes?
There are a lot of ways employees uses in controlling exposure routes. But when risk assessment is not be performed is not a part of the control methods.
What are the three ways to control workplace hazards?The ways to control workplace hazards are known to be means taken to ensure safety in the workplace.
The examples are:
The use a hazard control plan to know, select and implement controls. Looking into the efficiency of existing controls, and creating plans with measures to protect workers in case of emergencies and nonroutine activities, etc.Learn more about exposure routes from
https://brainly.com/question/25799066
Truckco manufactures two types of trucks: 1 and 2. Each truck must go through the painting shop and assembly shop. If the painting shop were completely devoted to painting Type 1 trucks, then 800 per day could be painted; if the painting shop were completely devoted to painting Type 2 trucks, then 700 per day could be painted. If the assembly shop were completely devoted to assembling truck 1 engines, then 1,500 per day could be assembled; if the assembly shop were completely devoted to assembling truck 2 engines, then 1,200 per day could be assembled. Each Type 1 truck contributes $300 to profit; each Type 2 truck contributes $500. How much capacity in percent does a single truck of each type uses at each shop?
How do you declare a pointer to a pointer to an integer?
Like a normal variable, pointers must be declared before they can be used. Declaring a pointer is done by putting a * before the name. A type is also linked to a pointer.
What is the difference between a pointer and an integer?A variable whose value is the memory address of an int is referred to as a pointer to an int, whereas a variable whose value is the memory address of a pointer to an int is referred to as a pointer to an int and the value of that pointer to an int is referred to as a memory address of an int. Let's say you define the following three variables.
How is a pointer declared to a pointer?C Double Pointer (Pointer to Pointer) #include void main () stdio.h> int *p; int **pp; p = &a; // The address of a is indicated by pointer p. pp = &p; // Pointer pp is a double pointer that points to pointer p's address.
To know more about pointer visit :-
https://brainly.com/question/30460618
#SPJ4
TRUE / FALSE. find the angle in degrees between these two vectors: select the best answer. show your calculations in your engineering notebook.
True. To find the angle in degrees between two vectors, we can use the dot product formula and trigonometry.
To find the angle between two vectors, we use the dot product formula, which relates the dot product of two vectors to the cosine of the angle between them. The dot product is calculated by multiplying the corresponding components of the vectors and summing the results. Dividing the dot product by the product of the magnitudes of the vectors gives us the cosine of the angle.
Taking the inverse cosine of this value provides the angle in radians. To obtain the angle in degrees, we convert the result from radians to degrees by multiplying by 180/π. This calculation gives us the angle between the two vectors in degrees.
To learn more about vectors click here, brainly.com/question/24256726
#SPJ11
A resistor has color bands of orange, blue, yellow and gold. What are the resistance and tolerance of this resistor?
Answer:
Resistance = 360,000 Ω = 360 kΩ
Tolerance = +/- 5%
Explanation:
You can follow a four-band resistor chart to determine resistance and tolerance based off each column.
1st Band = Orange = 3
2nd Band = Blue = 6
3rd Band = Yellow = 10,000 Ω (this is the multiplier)
Resistance = 36 * 10,000 Ω = 360,000 Ω = 360 kΩ
4th Band = Gold = +/- 5% Tolerance
what is the key to preventing accidents in a welding shop
Answer: The key to prevent accidents in a welding shop are: Necessary protection must be taken while welding process otherwise it will harm the welder. Safety precautions must be taken. The safety precautions are mentioned on the manual of every equipment.
A young engineer is asked to design a thermal protection barrierfor a sensitive electronic device that might be exposed toirradiation from a high-powered infared laser. Having learned as astudent that a low thermal conductivity material provides goodinsulating characteristics, the engineer specifies use of ananostrutured aerogel, characterized by a thermal conductivity ofKa = 0.005 W/m-K, for the protective barrier. The engineer'sboss questions the wisdom of selecting the aerogel because it has alow thermal conductivity. Consider the sudden laserirradiation of (a) pure aluminum, (b) glass, and (c) aerogel. The laser provides irradiation of G = 10x10^6 W/m^2. Theabsortivities of the materials are alpha = 0.2, 0.9, and 0.8 for the aluminum, glass, andaerogel, respectively, and the initial temperature of the barrieris Ti = 300 K. Explain why the boss is concerned. Hint:All materials experience thermal expansion (or contraction), andlocal stresses that develop within a material are, to a firstapproximation, proportional to the local temperature gradient.Kglass = 1.4 W/m-KKaluminum = 237 W/m-K
Answer:
1. for aluminium
-8438.82k/m
8.4x10³k/m
2. For glass:
-6.43x10⁶
3. For aerosol
-1.6x10⁹
Explanation:
We have in conclusion that aerosol has a high temperature gradient. So it is not likely to have the strength to withstand a high thermal stress
Materials that have Lower thermal conductivity are likely to have their temperature gradient to be on a high side, and most of the time, these materials are brittle.
So we get why this boss is concerned about aerogel.
Please refer to the attachment for the calculations. Thank you!