a) The correlation coefficient (r) is approximately 0.300, indicating a weak positive linear relationship between the ages of Best Actresses and Best Actors.
b) Based on the correlation coefficient (r), there is a weak positive linear correlation between the ages of Best Actresses and Best Actors, suggesting that as the ages of Best Actresses increase, the ages of Best Actors also tend to increase, but the relationship is not very strong.
a)How can I calculate the correlation coefficient (r) using a calculator or statistical software?To find the correlation coefficient (r), we can use the given ages of Best Actresses and Best Actors. The correlation coefficient measures the strength and direction of the linear relationship between two variables. Using a calculator or statistical software, we calculate the correlation coefficient to be approximately 0.300.
b)Is there a significant linear correlation between the ages of Best Actresses and Best Actors based on the obtained correlation coefficient (r)?Based on the correlation coefficient (r) of approximately 0.300, there is a weak positive linear correlation between the ages of Best Actresses and Best Actors. This means that there is a tendency for the ages of Best Actresses and Best Actors to increase together, but the relationship is not very strong. The correlation coefficient ranges from -1 to +1, where 0 indicates no linear correlation, 1 indicates a strong positive linear correlation, and -1 indicates a strong negative linear correlation. In this case, the value of 0.300 suggests a weak positive linear relationship, indicating that as the ages of Best Actresses increase, the ages of Best Actors also tend to increase, albeit not strongly.
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M+14=2 what is m equal to
Answer: m=-12
Step-by-step explanation:
m+14=2
m+14-14=2-12
The distance between home plate and first base on a baseball diamond is 90 ft.
Home plate to second base is located at a distance of 90√2 feet.
A square is a rectangle in which each side is the same length. The distance separating the square's opposing vertices is known as the diagonal. The Pythagoras Theorem can be used to compute the diagonals:
Diagonal² = Side² + Side²
Diagonal² = 2 Side²
Diagonal = √2 Side
The answer to the question is that it is 90 feet from home plate to first base.
This is the length of the side that makes up the baseball diamond's square shape. The diagonal of the square is the distance from home plate to second base.
Diagonal = √2 Side
Diagonal = 90√2
Hence, home plate to second base is located at a distance of 90√2 feet.
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The question is incomplete. The complete question will be -
"A baseball diamond is square. The distance from home plate to first base is 90 feet. In feet, what is the distance from home plate to second base?"
Is 6/2 simplified ? ............
Answer:
No, 3
Step-by-step explanation:
6/2
How many times can 3 go into 6?
Answer is 3 times because 2 x 3 is 6.
Answer:
3/1
Step-by-step explanation:
Find the GCD (or HCF) of numerator and denominator
GCD of 6 and 2 is 2
Divide both the numerator and denominator by the GCD
6 ÷ 2 /2 ÷ 2
Reduced fraction:
3/ 1
Therefore, 6/2 simplified to lowest terms is 3/1.
Please help me with this homework
Answer:
x \(\geq\) -3 and
x < 5
Step-by-step explanation:
2x - 3 < 7 add 3 to both sides
2x < 10 divide both sides by 2
x < 5 and
5 - x \(\leq\) 8 subtract 5 from both sides
-x \(\leq\) 3 multiply the expression with -1 to make x positive
x \(\geq\) -3
plz help. will give brainliest.
On Monday, Braden rode 3 miles on a bike. On Tuesday, he rode 10 miles. On Wednesday, he rode 2 times farther than he did Tuesday.
How many miles has Braden ridden so far this week?
Answer:
33 miles
Step-by-step explanation: I think it is correct
Monday: 3 miles
Tuesday: 10 miles
Wednesday: 20 miles because 10 x 2 = 20
3 miles + 10 miles + 20 miles = 33 miles
Hope this helps!
Use the information to answer the following question.
Carolyn was asked to solve the following system of equations.
Her work is shown.
Step 1: 3x – 2y = 7
Step 2: 3x – 2(x + 2) = 7
Step 3: 3x – 2x + 4 = 7
Step 4: x + 4 = 7
Step 5: x = 3
Step 6: y = x + 2
Step 7: y = 3 + 2
Step 8: y = 5
Solution: (3, 5)
Did Carolyn make an error in her work?
Yes, Carolyn did not correctly combine like terms in Step 2.
Yes, Carolyn should have substituted the x-value into the first equation in Step 6.
No, Carolyn solved the system of equations correctly.
Yes, Carolyn did not correctly distribute the negative in Step 3.
Carolyn made an error in her work because she did not correctly distribute the negative in Step 3.
System of EquationsA system of equations is the given term math for two or more equations with the same variables. The solution of these equations represents the point of the intersection.
You can solve a system of equations by the adding or substitution methods. In the addition method, you eliminate a variable, on the other hand, in the substitution method you replace a variable for the other.
The question gives:3x-2y=7 (1)y=x+2The question shows that Carolyn applies the substitution method because she replaces the variable y (equation 2) in equation 1. See the given step 2.
3x – 2y = 7
3x – 2(x + 2) = 7
3x – 2x - 4 = 7 - here it is the mistake. (Carolyn did not correctly distribute the negative).
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Given: AD/DC=BE/EC
Prove: AB=DE
А
D
2
E
B
Complete the steps of the proof.
Answer:
question given unclear bro add a photo or something it isnt clear
Step-by-step explanation:
Listed in the accompanying data table are student evaluation ratings of courses and professors, where a rating of 5 is for "excellent. " Assume that each sample is a simple random sample obtained from a population with a normal distribution. A. Use the 93 course evaluations to construct a 98% confidence interval estimate of the standard deviation of the population from which the sample was obtained. B. Repeat part (a) using the 93 professor evaluations. C. Compare the results from part (a) and part (b)
The 98% confidence interval of 93 course evaluation the estimation of the population standard deviation is (0.454, 0.681). For 93 professor evaluations, it is (0.318, 0.457). The course evaluations have a wider interval, indicating more variability compared to professor evaluations.
The construction of 98% confidence interval from which the 93 course evaluations were obtained, by using the formula
Confidence interval = (√((n-1)*s²)/√(chi-square upper)-√((n-1)*s²)/√(chi-square lower)),
where n is the sample size, s is the sample standard deviation, and chi-square upper and chi-square lower are the values from the chi-square distribution table with degrees of freedom (df) equal to n-1 and a cumulative probability of 0.99/2 = 0.495.
Using the given data, we have n = 93 and s = 0.56. From the chi-square distribution table with df = 92 and cumulative probability of 0.495, we obtain chi-square upper and chi-square lower as 67.339 and 49.645, respectively.
putting the values in the formula, we get
Confidence interval = (√((93-1)*0.56²)/√(67.339)-√((93-1)*0.56²)/√(49.645))
Confidence interval = (0.454, 0.681)
Therefore, we are 98% confident that the standard deviation of the population from which the 93 course evaluations were obtained falls within the interval (0.454, 0.681).
To construct a 98% confidence interval estimate of the standard deviation of the population from which the 93 professor evaluations were obtained, we can use the same formula as in above part, but with n = 93 and s = 0.41 (the sample standard deviation for professor evaluations).
From the chi-square distribution table with df = 92 and cumulative probability of 0.495, we obtain chi-square upper and chi-square lower as 67.339 and 49.645, respectively.
putting the values in the formula, we get
Confidence interval = (√((93-1)*0.41²)/√(67.339)-√((93-1)*0.41²)/√(49.645))
Confidence interval = (0.318, 0.457)
Therefore, we are 98% confident that the standard deviation of the population from which the 93 professor evaluations were obtained falls within the interval (0.318, 0.457).
Comparing the results from other parts, we can see that the confidence interval for the standard deviation of the population from which the course evaluations were obtained is wider than that for the population from which the professor evaluations were obtained. This suggests that there is more variability in the course evaluations than in the professor evaluations.
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how to adding and subtracting polynomials worksheet ?
Adding and subtracting polynomials worksheets assist pupils in becoming acquainted with the idea of polynomial addition and subtraction.
Adding and subtracting polynomial worksheets provide pupils with a platform to access a variety of well-structured problems. Because these worksheets progress in complexity, they are simple to use and allow pupils to reinforce their concepts.
Children must study in accordance with their learning curve, and these worksheets are designed to allow young brains to work at their own speed. These math worksheets also address the logical and reasoning aspects of arithmetic, assisting pupils in real-life situations.
Students may have a better grasp and explore these worksheets more quickly with the aid of pictures. These worksheets' step-by-step approach helps pupils better comprehend ideas and reinforce their comprehension.
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a class of 30 students with 14 boys and 16 girls must select 4 leaders. how many ways are there to select the 4 leaders so that at least one girl is selected?
There are 26,404 different ways to select 4 leaders from a class of 30 students with at least one girl in the group.There are different methods to approach this problem, but one way is to use the complement rule.
That is, we can find the total number of ways to select 4 leaders from the class of 30 students, and then subtract the number of ways to select 4 leaders such that no girl is selected. The difference will be the number of ways to select at least one girl.
The total number of ways to select 4 leaders from 30 students is given by the combination formula: C(30, 4) = 27,405. This means there are 27,405 different groups of 4 leaders that can be chosen from the class.
To find the number of ways to select 4 leaders with no girls, we can consider only the 14 boys in the class. The number of ways to select 4 boys from 14 is given by the combination formula: C(14, 4) = 1,001. Therefore, there are 1,001 different groups of 4 boys that can be chosen as leaders.
Now, we can subtract the number of groups of 4 boys from the total number of groups of 4 leaders to find the number of groups with at least one girl. That is: 27,405 - 1,001 = 26,404.
Therefore, there are 26,404 different ways to select 4 leaders from a class of 30 students with at least one girl in the group.
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answer first and u will get a brain, a few free questions, thanks, or a rating.
Erica recently invested in gold that is growing in value 4% annually. She invested $4000 initially. Find the value of her investment after 6 years.
The value of Erica's investment after 6 years is approximately $4,939.05.
To find the value of Erica's investment after 6 years, we can use the compound interest formula. The formula for compound interest is given as:
A = P\((1 + r/n)^(nt)\)
Where:
A is the final amount or value of the investment.
P is the initial principal or investment amount.
r is the annual interest rate (as a decimal).
n is the number of times the interest is compounded per year.
t is the number of years.
In this case, Erica's initial investment is $4000, the annual interest rate is 4% (or 0.04 as a decimal), and the investment is growing annually. Therefore, we have:
P = $4000
r = 0.04
n = 1 (since the interest is compounded annually)
t = 6 years
Plugging these values into the compound interest formula, we can calculate the final value of the investment:
A = $4000(1 + \(0.04/1)^(1*6)\)
A = $4000(1 + 0.04)^6
A = $4000(1.04)^6
Evaluating this expression, we find:
A ≈ $4,939.05
Therefore, the value of Erica's investment after 6 years is approximately $4,939.05.
This calculation assumes that no additional investments or withdrawals were made during the 6-year period and that the interest rate remains constant at 4% per year.
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Help??? First right answer gets brainliest
Answer:
c
Step-by-step explanation:
SUV was detected exceeding the posted speed limit of 60 km/hr, how many kilometers would she have traveled if she was driving 80 km/hr for half an hour
SUV was detected exceeding the posted speed limit of 60 km/hr, 40 kilometers would she have traveled if she was driving 80 km/hr for half an hour.
Given that an SUV was detected exceeding the posted speed limit of 60 km/hr. We need to calculate how many kilometers would she have traveled if she was driving 80 km/hr for half an hour.
Using the formula,
s = v.t
Where s = Distance
v = Velocity
t = time
In this scenario, the velocity of the SUV is given as 80 km/hrt = 0.5 hrs
The distance she will travel at 80 km/hr in 0.5 hrs will be; s = 80 x 0.5s = 40 km
Therefore, the SUV would have traveled 40 kilometers if she was driving 80 km/hr for half an hour.
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Need help fast pleasee??
Answer:
Option 3.) f(-3) = g(-3), since that x-value of the point of intersection
Hope this helps!
Unit 6 Test Part B
MCR3U Summer
4. Sophie is riding her bike home when she runs over a nail. It gets stuck to the tire of her bike but does not pop
the tire. As she continues to cycle home, the nail hits the ground every 2 seconds and reaches a maximum
height of 48 cm
Answer:
You did not ask anything, i guess that you want to find the equation of the height of the nail as a function of time.
Data that we have:
The nail is in a circular object.
the nail hits the ground every 2 seconds, then the weel does a full cycle every 2 seconds.
The maximum height of the nail is 48cm, and as the nail is stuck on the weel, the maximum height will be when the nail is on top of the weel.
From this, we can conclude that the diameter of the weel is 48cm.
Now, with this we could write the equation of the height of the nail as a function of time.
We know that this is a periodic function, so let's write it as:
f(t) = A*cos(c*t) + B
where A, B and c are constanst.
At t = 0, when the byke hits the nail, the nail must be in the ground, so we have that:
0 = A*cos(c*0) + B
A + B = 0
A = - B
and we also know that the function is periodic with T = 2s
cos(c*t) = cos(c*(t + 2s) = cos( c*t + 2s*c)
and we know that the period of the cosine function is 2*pi
then:
c*2s = 2*pi
c = (2pi/2s) = pi/s
then our function is:
f(t) = -B*cos(t*pi/s) + B
now, the maximum heightwill be when cos(t*pi/s) = -1, and this happens at t = 1s
f(1s) = -B*cos(pi) + B = 2B
And we know that the maximum height is 48cm
2*B = 48cm
B = 24cm
Then the function of the height of the nail is:
f(t) = -24cm*cos(t*pi/s) + 24cm
the international nanny association reports that in a random sample of 528 in-home child care providers (nannies), 20 work for either a nationally known, a locally known, or an internationally known celebrity (2011 international nanny association salary and benefits survey). find a 95% confidence interval for the true proportion of all nannies who work for a celebrity.
The 95% confidence interval for the true proportion of all nannies who work for a celebrity is approximately 0.0145 to 0.0613.
The confidence interval:
In this case, we have a random sample of 528 in-home childcare providers (nannies) and we want to estimate the proportion of nannies who work for a celebrity.
To do this, we calculate the sample proportion (p-hat) by dividing the number of nannies working for a celebrity by the total sample size.
Here we have
Sample size (n) = 528
Number of nannies working for a celebrity (x) = 20
First, we calculate the sample proportion (p-hat), which is the proportion of nannies working for a celebrity in the sample:
=> p-hat = x / n = 20 / 528
Next, we calculate the standard error (SE) using the formula:
SE = √(p-hat × (1 - p-hat)) / n)
SE = √((20 / 528) × (1 - 20 / 528) / 528)
Now, we can calculate the margin of error (ME) using the critical value associated with a 95% confidence level.
Since we have a large sample size, we can use the z-value:
z-value for a 95% confidence level ≈ 1.96
ME = z-value × SE
Finally, we can calculate the confidence interval:
Confidence Interval = p-hat ± ME
Substituting the values:
Confidence Interval = [ 20 / 528) ± (1.96×√(20 / 528)×(1 - 20 / 528) / 528) ]
Simplifying:
Confidence Interval ≈ 0.0379 ± 0.0234
Therefore,
The 95% confidence interval for the true proportion of all nannies who work for a celebrity is approximately 0.0145 to 0.0613.
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Anyone know this? Algebra I think is this
Answer:
It's the 3rd picture. -3 1/4 + 4 3/4 = 1 1/2
Step-by-step explanation:
A therapist wanted to determine if yoga or meditation is better for relieving stress. The therapist recruited 100 of her high-stress patients. Fifty of them were randomly assigned to take weekly yoga classes, and the other 50 were assigned weekly meditation classes. After one month, 30 of the 50 patients in the yoga group reported less stress, and 35 of the 50 patients in the meditation group reported less stress. Assuming the conditions for inference are met, what is the 95% confidence interval for the difference in proportions of patients experiencing stress relief from the yoga and meditation groups?
Find the z-table here.
(0.40 minus 0.30) plus-or-minus 1.65 StartRoot StartFraction 0.40 (1 minus 0.40) Over 100 EndFraction + StartFraction 0.30 (1 minus 0.30) Over 100 EndFraction EndRoot
(0.60 minus 0.70) plus-or-minus 1.96 StartRoot StartFraction 0.60 (1 minus 0.60) Over 100 EndFraction + StartFraction 0.70 (1 minus 0.70) Over 100 EndFraction EndRoot
(0.60 minus 0.70) plus-or-minus 1.65 StartRoot StartFraction 0.60 (1 minus 0.60) Over 50 EndFraction + StartFraction 0.70 (1 minus 0.70) Over 50 EndFraction EndRoot
(0.60 minus 0.70) plus-or-minus 1.96 StartRoot StartFraction 0.60 (1 minus 0.60) Over 50 EndFraction + StartFraction 0.70 (1 minus 0.70) Over 50 EndFraction EndRoot
answer is D
The correct answer to this question is option D: (0.60 minus 0.70) plus-or-minus 1.96 StartRoot StartFraction 0.60 (1 minus 0.60) Over 50 EndFraction + StartFraction 0.70 (1 minus 0.70) Over 50 EndFraction EndRoot.
To find the 95% confidence interval for the difference in proportions of patients experiencing stress relief from the yoga and meditation groups, we need to use the formula:
CI = (p1 - p2) ± z*√[(p1(1-p1)/n1) + (p2(1-p2)/n2)]
Where p1 and p2 are the proportions of patients experiencing stress relief in the yoga and meditation groups, respectively, n1 and n2 are the sample sizes of the yoga and meditation groups, respectively, and z is the critical value from the z-table corresponding to the 95% confidence level.
Plugging in the given values:
p1 = 30/50 = 0.60
p2 = 35/50 = 0.70
n1 = 50
n2 = 50
z = 1.96 (from the z-table for a 95% confidence level)
CI = (0.60 - 0.70) ± 1.96*√[(0.60(1-0.60)/50) + (0.70(1-0.70)/50)]
CI = (-0.10) ± 1.96*√[(0.24/50) + (0.21/50)]
CI = (-0.10) ± 1.96*√[0.009]
CI = (-0.10) ± 1.96*(0.095)
CI = (-0.10) ± 0.186
Therefore, the 95% confidence interval for the difference in proportions of patients experiencing stress relief from the yoga and meditation groups is (-0.286, 0.086).
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4/6-3/8 zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz
Answer:
The answer is 7/24 ~hope this helps~
btw, sick pic B-)
Step-by-step explanation:
The diagonal of a rectangle is 58" the site is 40" and the base is 42" what is the ratio of the diagonal to the base of the rectangle
Answer:
29:21
Step-by-step explanation:
The ratio of the diagonal to the base of ration is written as 58:42.
The ratio has the greatest common factor as 2.
58÷2:42÷2
29:21
The simplified ratio becomes 29:21.
Susan got a prepaid debit card with 20 on it. For her first purchase with the card, she bought some bulk ribbon at a craft store. The price of the ribbon was 16 cents per yard If after that purchase there was 14.88 left on the card, how many yards of ribbon did Susan buy?.
The yards of ribbon purchased by Susan using amount on the debit card is equal to 32 yards.
Amount on prepaid debit card = $20
Price of the ribbon = 16 cents per yard
Amount left on the card after purchasing ribbon = $14.88
Amount used to purchase ribbon
= Amount on initial amount debit card - Amount left after purchasing ribbon
= $20.00 - $14.88 =$5.12
So Susan spent $5.12 on the ribbon.
Now ,use the price per yard to figure out how many yards she bought,
= Amount spent to buy ribbon / price of the ribbon per yard
= $5.12 ÷ $0.16 per yard
= 32 yards
Therefore, Susan bought 32 yards of ribbon with her prepaid debit card.
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To pass inspection, a new basketball should bounce back to between 68% and 75% of the starting height. A new ball is dropped from 6 feet and bounces back 4 feet 1 inch. does the ball pass inspection? Explain
To pass inspection, the ball must bounce back to between 68% and 75% of the starting height. written as a decimal, the ball must bounce between a low of __ feet and height of __ feet.
Answer: Yes, it does. It must bounce of a low of 4.08 feet and a high of 4.5 feet
Step-by-step explanation:
....................
Answer:
a. x (less than or equal to) 24
Step-by-step explanation:
i hope this helps :)
Identify the constant of proportionality from the graph. 9 0 15 3 A2
To find the constant of proportionality:
We can see that for every 1 unit we move to the right on the x- axis (positive), the line moves up 2 units.
Divide the change on y by that change on x:
2/1=2
The constant of proportionality is 2. (option a)
What is mass if force is 45 N and acceleration is 39 m/s/s?
Answer:
The answer is 1.15 kgStep-by-step explanation:
To find the mass of an object given it's acceleration and the force acting on it we use the formula
\(mass = \frac{force}{acceleration} \\ \)
From the question
force = 45 N
acceleration = 39 m/s²
We have
\(force = \frac{45}{39} = \frac{15}{13} \\ = 1.153846...\)
We have the final answer as
1.15 kgHope this helps you
The data on ages at which a sample of 35 fathers had their first child show a mean 25.43 and standard deviation 5.19. Define the population parameter of interest in this context.
Answer:
Step-by-step explanation:
A population parameter describes an entire population; a particular characteristic of an entire population. A value that describes the entire population. In this context, the population parameter is looking into the average ages of fathers when they had their first child, but this value is not given. The mean given here is the sample statistic.
Since, the population studied here is a very large population (all fathers), you have a statistic. But sometimes, if the population is very small and groups are small enough to measure, you have a parameter.
for the following diagram, angles 3 and 6 are:
Answer:
alternate
is this an exam or test?
State if the triangles are similar. If so, how do you know they are similar and complete the similarity statement.
ΔFED
~ ____
Answer:
FED ~ MLF
Step-by-step explanation:
∠L = ∠E
∠F = ∠F
Since both angles are congruent, that would mean all angles are congruent.
If all angles are congruent, then the triangles are always similar no matter the length of the sides.
The complete statement is \(\triangle FED\sim \triangle FLM\).
What are the similar triangles?Similar triangles are the triangles that have the same shape, but their sizes may vary.
What is AA or angle angle similarity rule?If any two angles of a triangle are equal to any two angles of another triangle, then the two triangles are similar to each other.
What are vertically opposite angles?When two lines intersect each other, then the opposite angles are formed due to intersection are called vertical angles or vertically opposite angles.
According to the given question.
We have two triangles LMF and EDF
In triangles LMF and EFD we have
∠MLF = ∠DEF (given)
Also, ∠MFL = ∠DFE (vertically opposite angles)
Since, we know that " if any two angles of a triangle are equal to any two angles of another triangle, then the two triangles are similar to each other".
Therefore, by AA similarity criteria triangle FED is similar to FLM.
Hence, the complete statement is \(\triangle FED\sim \triangle FLM\).
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If a graph includes the points (2,5) and (8,5) which of the following must be true ? 1.it is the graph of a linear function 2.it is not the graph of a function 3.it is the graph of an increasing function 4.none of the above
Answer
Option 1 is correct.
The graph could easily be the graph of a linear function.
Explanation
The points (2, 5) and (8, 5) can be seen to lie on the same line of y = 5
So, we can conclude that the graph could be a simple linear function, or a curve that passes this point twice.
So, option A is the only correct option here.
Hope this Helps!!!