Luz made a semicircular pendant with a radius of 8 centimeters to use on a keychain. She attached a wire around the edge of the pendant. What is the approximate length of the wire she attached to the pendant?
41.13 cm
50.27 cm
50.26 cm
25.13 cm

Answer:

Not "free". The new sales price is $31.08

Step-by-step explanation:

Given that the costs of the drone ($129.50) is discounted 40%, the new price after the discount

= $129.50 - 40% * $129.50

= $129.50 - $51.80

= $77.70

Given that the  next month, the sale price is discounted an additional 60%., the new price after this discount

= $77.70 - 60% * $77.70

= $77.70 - $46.62

= $31.08

From above, the drone is not "free". The new sales price is $31.08

The simplified expression of (5.1)(5.1^2)^4 is (5.1)^9

The expression is given as:

(5.1)(5.12)4

Rewrite the expression properly as follows:

(5.1)(5.1^2)^4

Rewrite the expression properly as follows:

(5.1)(5.1^2)^4 = (5.1) * (5.1^2)^4

Apply the power law of indices

(5.1)(5.1^2)^4 = (5.1) * (5.1^8)

Apply the power law of indices

(5.1)(5.1^2)^4 = (5.1)^(1 + 8)

Evaluate the sum

(5.1)(5.1^2)^4 = (5.1)^9

Hence, the simplified expression of (5.1)(5.1^2)^4 is (5.1)^9

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The total amount of cost of Franklin's family using a non-network provider will be $24,725.

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

They had 17 physician visits, 9 specialist visits, and 4 physical therapist appointments at $90 each. They also had a hospital charge of $21,675 with an admission charge of $350.

Then the total charge is given as,

T = 17 × $90 + 9 × $90 + 4 × $90 + $21,675 + $350

T = $1,530 + $810 + $360 + $21,675 + $350

T = $24,725

The total amount of cost of Franklin's family using a non-network provider will be $24,725.

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Franking Family pays a total of $24,725.

The unitary technique involves first determining the value of a single unit, followed by the value of the necessary number of units.

For example, Let's say Ram spends 36 Rs. for a dozen (12) bananas.

12 bananas will set you back 36 Rs. 1 banana costs 36 x 12 = 3 Rupees.

As a result, one banana costs three rupees. Let's say we need to calculate the price of 15 bananas.

This may be done as follows: 15 bananas cost 3 rupees each; 15 units cost 45 rupees.

Given:

Franklin Family spend on 17 physician visits, 9 specialist visits, 4 physical therapist appointments at $90 each.

They also had a hospital charge of $21,675 with an admission charge of $350.

So, total they had paid

= 17(90) + 9(90) + 4(90) + 21675 + 350

= 1530 + 810 + 360 + 21675 + 350

= $24,725

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The required answer is  there are a total of 42 water bottles in the kitchen at Camp Willow Tree.

Explanation:-

At Camp Willow Tree, the counselors are counting the number of water bottles in the kitchen. They find 3 six-packs and 2 twelve-packs.

To calculate the total number of water bottles, follow these steps:

1. Multiply the number of six-packs (3) by the number of water bottles in each six-pack (6): 3 x 6 = 18 water bottles.
2. Multiply the number of twelve-packs (2) by the number of water bottles in each twelve-pack (12): 2 x 12 = 24 water bottles.
3. Add the number of water bottles from the six-packs and twelve-packs together: 18 + 24 = 42 water bottles.
At Camp Willow Tree, the counselors have found a total of 30 water bottles in the kitchen. This is because each six-pack contains 6 water bottles, and 3 six-packs make a total of 18 water bottles. On the other hand, each twelve-pack contains 12 water bottles, and 2 twelve-packs make a total of 24 water bottles. Adding 18 and 24 together, we get 42, which is the total number of water bottles found. Therefore, the counselors have found 30 water bottles in the kitchen.

So, there are a total of 42 water bottles in the kitchen at Camp Willow Tree.

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If a line's angle with the x-axis is then, that line's slope will be tanα, and the new road's slope will be tan(0) = 0.

D Street is depicted as a vertical line with a 90° angle of inclination in the accompanying figure. In other words, D Street has an infinite slope.

The new road will therefore have 0° of inclination if it is perpendicular to D street because if they are perpendicular and D street is vertical, the new road is level and has 0° of inclination.

A horizontal line now has zero slopes.

The new road has a zero slope as a result.

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False. the student’s t statistic for testing the significance of a binary predictor can be greater than 0.

The t-statistic is used for testing the significance of a regression coefficient in a linear regression model. A binary predictor (also known as a dummy variable or indicator variable) has only two possible values (0 or 1), and its coefficient can be tested using a t-test. However, the t-statistic can never be greater than 0 because it measures the difference between the estimated coefficient and its hypothesized value (usually 0), divided by its standard error. If the estimated coefficient is greater than the hypothesized value, the t-statistic will be positive. If it is less than the hypothesized value, the t-statistic will be negative. But it can never be greater than 0.

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The number 2.921, which repeats as 2.9212121..., can be expressed as the ratio of integers 32/11.

To convert the repeating decimal 2.9212121... to a ratio of integers, we can set it up as an algebraic equation. Let x represent the repeating decimal:

x = 2.9212121...

Multiplying both sides of the equation by 100 to shift the decimal point two places to the right, we get:

100x = 292.1212121...

Next, we subtract the original equation from the shifted equation to eliminate the repeating part:

100x - x = 292.1212121... - 2.9212121...

This simplifies to:

99x = 289

Dividing both sides of the equation by 99 gives:

x = 289/99

Simplifying further, we can express 289/99 as a ratio of integers:

289/99 = 32/11

Therefore, the repeating decimal 2.9212121... is equivalent to the ratio of integers 32/11.

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9514 1404 393

Answer:

  101

Step-by-step explanation:

  1² + 10² = 1 + 100 = 101 . . . sum of 1st and 10th square numbers

Answer:101

Step-by-step explanation:yw

The area of the shelf is 12.5 square inches.

The coordinates of the vertices of the shelf are:

I(10, 15)
J(10, 10)
K(5, 10)

To find the area of the shelf, we can use the formula for the area of a triangle.

Since the shelf is in the shape of a right triangle, we can use the formula:

Area = (base × height) / 2

First, let's find the base and height of the triangle.

The base of the triangle is the horizontal distance between the points J and K.

To find this distance, we subtract the x-coordinates of J and K:

Base = Jx - Kx

Base = 10 - 5

Base = 5 inches

The height of the triangle is the vertical distance between the points J and I.

To find this distance, we subtract the y-coordinates of J and I:

Height = Iy - Jy

Height = 15 -10

Height = 5 inches

Now, we can substitute these values into the formula for the area:

Area = (base × height) / 2

= (5 × 5) / 2

= 25 / 2

= 12.5 square inches

Therefore, the area of the shelf is 12.5 square inches.

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The expected value of sales at a price of $1 is 11.015 for the given regression demand equation.

In the regression demand equation e(log(sales | price)) = 11.015 - 2.442 log(price), you want to find the expected value of sales at a price of $1. To find the expected value of sales, you need to substitute the given price of $1 into the equation and solve for the sales. Substituting the price of $1 into the equation, you get: e(log(sales | 1)) = 11.015 - 2.442 log(1). Since log(1) = 0, the equation simplifies to: e(log(sales | 1)) = 11.015 - 2.442 * 0, e(log(sales | 1)) = 11.015
Therefore, the expected value of sales at a price of $1 is 11.015.

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Presumably you mean 555 as a number in base 10.

We have

555 = 5 • (100 + 10 + 1)

… = 5 • (4 • 25 + 2 • 5 + 1)

… = 5 • (4 • 5² + 2 • 5¹ + 1 • 5⁰)

… = 4 • 5³ + 2 • 5² + 1 • 5¹

… = 4210₅

Answer:

I would recommend that if it is re-testable, keep that slide open and open another so you can copy from the other slide

try 15? kwqjwkjjsjshejqjdwjejdjhwksjdwkjsekjrskjfkskdjeekjee

The  procedure permute-without-identity does what Professor Kelp intends.

As per the given question,

Professor Kelp wants to write a procedure that produces any permutation randomly except the identity permutation in which every element ends up where it started.

He has proposed the procedure permute-without-identity. We need to check whether this procedure does what Professor Kelp intends or not.

Procedure permute-without-identity:

Generate a permutation π ∈ Sn−1 uniformly at random. (Note that the identity permutation is not in Sn−1.)

Return the permutation obtained by shuffling the elements of π using a uniformly random shuffle.

Randomly shuffle the list using the Fisher-Yates shuffle, which creates a uniformly random permutation of the list.

Professor Kelp's procedure permute-without-identity chooses a permutation at random from the set of all permutations except the identity permutation.

So, there are n! - 1 possible choices of π.

Then, the elements of π are shuffled randomly using a uniformly random shuffle.

The identity permutation is excluded from π as it is not included in Sn-1.

Since the identity permutation is not included in Sn-1, it cannot be chosen by the procedure permute-without-identity.

Hence, the procedure does what Professor Kelp intends.

This procedure achieves the desired outcome by avoiding the case where all elements end up where they started.

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The two numbers are 3 and 12 when 15 is the result of sum two numbers. One to two are compared in a 4:1 ratio.

Given that,

15 is the result of adding two numbers. One to two are compared in a 4:1 ratio.

We have to find which two numbers are they.

We know that,

Let take x and y to denote the two numbers

We get

x + y = 15   ----->equation(1)

x = 4y        ----->equation(2)

Substitute the 4y in equation(1)

(4y) + y = 15

5y = 15

Divide both sides by 5

y = 3.

Substitute y=3 in equation(2)

x=4(3)

x = 12

Therefore, The two numbers are 3 and 12 when 15 is the result of adding two numbers. One to two are compared in a 4:1 ratio.

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a) Since the triangles are congruent, and ΔABC is congruent to ΔDEF, segments AB and DE have the same value. Therefore, you can use algebra to solve for x when using the knowledge that (12 - 4x) is equal to (15 - 3x).

To solve:

12 - 4x = 15 - 3x

12 = 15 + x

-3 = x

Therefore, x is equal to -3.

b) To find the value of AB, plug in the value of x found in part a).

12 - 4x

12 - 4(-3)

12 - (-12)

12 + 12 = 24

Thus, segment AB is equal to 24.

c) As shown in part b), plug in the value of x found in part a) to find the value of segment DE.

15 - 3x

15 - 3(-3)

15 - (-9)

15 + 9 = 24

Thus, segment DE is also equal to 24.

We can confirm the knowledge of the equal side lengths because the triangle are congruent. This means that all the side lengths in the triangle are the same, which is confirmed when algebraically plugging in the value of x to solve for the values of the segments AB and DE.

I hope this helps!

Answer:

p = 7

Step-by-step explanation:

(2+10i) - (7+pi) = (-5+3i)

2-7 = -5

10i - pi = 3i

Subtract 10i from each side

-pi = 3i - 10i

-pi = -7i

Divide by -i

p = 7

That means p = 7

Yes, it is worth it and the expected profit for Andy is $7 per game

Given: Cost of the game = $2If Andy gets a number card (2-10), he wins nothing. For any face card (jack, queen, or king), he wins $3For any ace, he wins $5, and he wins an extra $20 if he draws the ace of clubs.

To calculate the expected gain, we use the formula:
E(X) = P1X1 + P2X2 + P3X3 + ………….+PnXn
Where E(X) is the expected value or expected gain, Pi is the probability of getting outcome Xi.

Let's find the expected gain for Andy. So, Andy wins nothing for number cards (2 to 10)

Thus, E(X) = P1X1 + P2X2 + P3X3 + ………….+PnXn= (36/52)*0 + (12/52)*3 + (4/52)*5 + (1/52)*(5 + 20)= (1/13)*(36*0 + 12*3 + 4*5 + 1*25)= (1/13)*(36 + 12*3 + 4*5 + 25)= (1/13)*(36 + 36 + 20 + 25)= (1/13)*117= $9

If we subtract the cost of the game, we get the expected profit, which is $7. Therefore, the expected profit for Andy is $7 per game.

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Out of 8 members of the committee, it is possible to create two subcommittees only.

We know that in order to create subcommittees. we need to divide the total number of people on the committee into equal parts so that they form subcommittees.

Here, it is given that there are 8 members on the committee.

A subcommittee needs to have 3 people in it.

On dividing 8 people into groups of three, we get

⇒ \(\frac{8}{3}\)

⇒ 2.66..

Here, it is obvious that the 0.66... can not be considered because it is not a whole number and hence, does not mean any number of people.

So, we can create only two different subcommittees from 8 members on the main committee.

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In a 4x3x2x2 factorial experiment, you have 4 independent variables and potentially 4 main effect hypotheses.

The 4 independent variables are represented by the four numbers in the experimental design

(i.e., 4 levels of variable A, 3 levels of variable B, 2 levels of variable C, and 2 levels of variable D).

The potentially 4 main effect hypotheses are one for each independent variable, which states that there is a significant effect of that independent variable on the outcome variable.

A factorial experiment includes multiple factors simultaneously, each consisting of two or more

levels. Many factors simultaneously influence what is studied in a factorial experiment, and

experimenters consider the main effects and interactions between factors.

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Angle ABC is greater than angle C, as required. Given triangle ABC with AC greater than AB, and BD drawn such that AD is congruent to AB, we need to prove that angle ABC is greater than angle C.

To begin with, we can draw a diagram to visualize the situation. In the diagram, we see that BD is an altitude of triangle ABC, as well as a median since it divides the base AC into two equal parts. We also see that triangles ABD and ABC are congruent by the side-side-side (SSS) criterion, which means that angle ABD is equal to angle ABC.

Now, we can use this information to prove our statement. Since triangle ABD and triangle ABC are congruent, their corresponding angles are also equal. Therefore, we know that angle ABD is equal to angle ABC.

Next, we observe that angle ABD is a right angle, since BD is an altitude of triangle ABC. This means that angle ABC is the sum of angles ABD and CBD.

Since AD is congruent to AB, we also know that angles ABD and ADB are congruent. Therefore, angle CBD is greater than angle ADB.

Putting all of this together, we can conclude that angle ABC is greater than angle C, as required.

In summary, we have shown that given triangle ABC with AC greater than AB and BD drawn such that AD is congruent to AB, angle ABC is greater than angle C. This is because angles ABD and CBD add up to angle ABC, and angle CBD is greater than angle ADB.

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Answer:

\(\left[\begin{array}{ccc}3&-1&\\-1&1/2\\\end{array}\right]\)

Step-by-step explanation:

The matrix system for the linear equations: x + 2y = 8, 2x + 6y = 9

\(\left[\begin{array}{ccc}1&2&\\2&6\\\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}8\\9\end{array}\right]\)

To get the coefficient of x and y, the inverse of the first matrix (let the first matrix be A) must be known.

\(A^{-1}\) = (1 / determinant of A) x Adjoint of A

the determinant of A = (1 x 6) - (2 x 2) = 6 - 4 = 2

Adjoint of A = \(\left[\begin{array}{ccc}6&-2&\\-2&1\\\end{array}\right]\)

\(A^{-1}\)= \(\frac{1}{2} \left[\begin{array}{ccc}6&-2\\-2&1\end{array}\right]\) = \(\left[\begin{array}{ccc}3&-1&\\-1&1/2\\\end{array}\right]\)

There are 5,760 ways to arrange the books on the bookshelf.

A permutation is an ordered arrangement of objects, and it can be calculated as follows:

ⁿPₓ = n! / (n - x)!

where n is the total number of objects and r is the number of objects that we are arranging.

To determine the total number of ways in which we can arrange the books on a bookshelf, we need to first calculate the total number of possible arrangements. We can do this by using the fundamental principle of counting, which tells us that the total number of possible arrangements is equal to the product of the number of ways in which each book can be arranged.

Therefore, the total number of possible arrangements can be calculated as follows:

Total number of possible arrangements = Number of ways to arrange math books × Number of ways to arrange history books × Number of ways to arrange science books

In our case, we have 4 math books, 5 history books, and 2 science books, so we can calculate the number of permutations for each type of book as follows:

Number of ways to arrange math books = ⁴P₄ = 4! / (4-4)! = 4! / 0! = 24

Number of ways to arrange history books = ⁵P₅ = 5! / (5-5)! = 5! / 0! = 120

Number of ways to arrange science books = ²P₂ = 2! / (2-2)! = 2! / 0! = 2

Now, we can substitute these values in the formula for the total number of possible arrangements:

Total number of possible arrangements = 24 × 120 × 2 = 5,760

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Answer:

a(10 - 13)

Step-by-step explanation:

The only common factor between these numbers is a, as 10 and 13 do not share factors (13 is prime). We can only factor out a.

Answer:

correct

Step-by-step explanation:

Answer:

416mm^3

Step-by-step explanation:

volume = length x width x height

= 10.4 x 5 x 8

=416

In order to select the statement that can deduce the line segments to be parallel, using the information given, when m7 = m5 - 90, we can conclude that:  line segments BD and CE are parallel.

Statement that can deduce the line segments to be parallel:

When the given information is considered, it can be observed that in the given figure, the opposite angles of the quadrilateral are supplementary.

The opposite angles of the quadrilateral are: m1 + m2 = 180°, m3 + m4 = 180°, m5 + m6 = 180°, and m7 + m8 = 180°.

Also, given that: m5 = m1 and m7 = m5 - 90

Substituting the value of m5 in the second equation, we get:

m7 = m1 - 90

This implies that angle m7 is supplementary to angle m1.

Now, since the opposite angles of a quadrilateral are supplementary, angles m1 and m7 are supplementary angles.

Thus, the line segments BD and CE are parallel since angles m1 and m7 lie on opposite sides of the transversal (line segment BC) and are supplementary angles.

Therefore, the statement that can deduce the line segments to be parallel is: When m7 = m5 - 90, line segments BD and CE are parallel.

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