Make java application that simulate Bank Accounts Management System.
the users of this application are the Customers of this Bank, they should be able to do the Following Tasks:
Customer:
Login (using account number and Password) and Logout.
Register.
Deposit
Withdraw
Transfer
Check Balance
Print Account transactions

Answer:

the answer for this question is true

Question:

It is always the employee's responsibility to make sure they wear their respirator. A) True B) False

Answer:

The answer to this question would be A. True

Explanation:

It would be the employee's responsibility the boss/manager should not have to tell them to put it on. If you don't know what a respirator is it's worn over the mouth and nose as a mask to prevent the inhalation of dust, and other chemicals and stuff.

I hope it helps you!

~XxBells is a cute girlxX~

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This question is incomplete, the complete question is;

For a steel alloy it has been determined that a carburizing heat treatment of 11.3 h duration at Temperature T1 will raise the carbon concentration to 0.44 wt% at a point 1.8 mm from the surface. A separate experiment is performed at T2 that doubles the diffusion coefficient for carbon in steel.

Estimate the time necessary to achieve the same concentration at a 4.9 mm position for an identical steel and at the same carburizing temperature T2.

Answer:

the required time to achieve the same concentration at a 4.9 is 83.733 hrs

Explanation:

Given the data in the question;

treatment time t₁ = 11.3 hours

Carbon concentration = 0.444 wt%

thickness at surface x₁ = 1.8 mm = 0.0018 m

thickness at identical steel x₂ = 4.9 mm = 0.0049 m

Now, Using Fick's second law inform of diffusion

\(x^2\) / Dt = constant

where D is constant

then

\(x^2\) / t = constant

\(x^2_1\) / t₁ = \(x^2_2\) / t₂

\(x^2_1\) t₂ = t₁\(x^2_2\)

t₂ = t₁\(x^2_2\) / \(x^2_1\)

t₂ = (\(x^2_2\) / \(x^2_1\))t₁

t₂ = \((\) \(x_2\) / \(x_1\) \()^2\) × t₁

so we substitute

t₂ = \((\) 0.0049  / 0.0018  \()^2\) × 11.3 hrs

t₂ = 7.41 × 11.3 hrs

t₂ = 83.733 hrs

Therefore, the required time to achieve the same concentration at a 4.9 is 83.733 hrs

Answer:

The work transfer per unit mass is approximately 149.89 kJ

The heat transfer for an adiabatic process = 0

Explanation:

The given information are;

P₁ = 1 atm

T₁ = 70°F = 294.2611 F

P₂ = 5 atm

γ = 1.5

Therefore, we have for adiabatic system under compression

\(T_{2} = T_{1}\cdot \left (\dfrac{P_{2}}{P_{1}} \right )^{\dfrac{\gamma -1}{\gamma }}\)

Therefore, we have;

\(T_{2} = 294.2611 \times \left (\dfrac{5}{1} \right )^{\dfrac{1.5 -1}{1.5 }} \approx 503.179 \ K\)

The p·dV work is given as follows;

\(p \cdot dV = m \cdot c_v \cdot (T_2 - T_1)\)

Therefore, we have;

Taking air as a diatomic gas, we have;

\(C_v = \dfrac{5\times R}{2} = \dfrac{5\times 8.314}{2} = 20.785 \ J/(mol \cdot K)\)

The molar mass of air = 28.97 g/mol

Therefore, we have

\(c_v = \dfrac{C_v}{Molar \ mass} = \dfrac{20.785}{28.97} \approx 0.7175 \ kJ/(kg \cdot K)\)

The work done per unit mass of gas is therefore;

\(p \cdot dV =W = 1 \times 0.7175 \times (503.179 - 294.2611) \approx 149.89 \ kJ\)

The work transfer per unit mass ≈ 149.89 kJ

The heat transfer for an adiabatic process = 0.

Try to be as relax as possible.

Provide names of all parties involved.

Provide vehicle information and identification details.

Provide full names, address, registration numbers and insurance company details.

Explanation:

After a collision one may be confused, afraid and have no attention about the details that what happened because all the collision event happens in a short interval of time. So the first thing one should do during information exchange is to sit back and relax and be calm so that one can remind the things at some extent. After that provide all the details about injured people and the involved vehicles.

Answer:

C-Reagan endorsed a conservative economic policy.

Explanation:

edge21

Reagan endorsed a conservative economic policy.

In the US, presidential elections take place every four years. The next election for the nation's top position will be in 2024 because the last one occurred in 2020.

Federal elections must take place "the Tuesday next after the first Monday in November," according to U.S. law code.

Every even-numbered year has a presidential election and a congressional midterm election (e.g. 2016, 2018, 2020.)

Therefore, Reagan endorsed a conservative economic policy.

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Answer:

The volume percentage of graphite is 10.197 per cent.

Explanation:

The volume percent of graphite is the ratio of the volume occupied by the graphite phase to the volume occupied by the graphite and ferrite phases. The weight percent in the cast iron is 3.2 wt% (graphite) and 96.8 wt% (ferrite). The volume percentage of graphite is:

\(\%V_{gr} = \frac{V_{gr}}{V_{gr}+V_{fe}} \times 100\,\%\)

Where:

\(V_{gr}\) - Volume occupied by the graphite phase, measured in cubic centimeters.

\(V_{fe}\) - Volume occupied by the graphite phase, measured in cubic centimeters.

The expression is expanded by using the definition of density and subsequently simplified:

\(\%V_{gr} = \frac{\frac{m_{gr}}{\rho_{gr}} }{\frac{m_{gr}}{\rho_{gr}}+\frac{m_{fe}}{\rho_{fe}}}\times 100\,\%\)

Where:

\(m_{fe}\), \(m_{gr}\) - Masses of the ferrite and graphite phases, measured in grams.

\(\rho_{fe}, \rho_{gr}\) - Densities of the ferrite and graphite phases, measured in grams per cubic centimeter.

\(\%V_{gr} = \frac{1}{1+\frac{\frac{m_{fe}}{\rho_{fe}} }{\frac{m_{gr}}{\rho_{gr}} } }\times 100\,\%\)

\(\%V_{gr} = \frac{1}{1 + \left(\frac{\rho_{gr}}{\rho_{fe}} \right)\cdot\left(\frac{m_{fe}}{m_{gr}} \right)} \times 100\,\%\)

If \(\rho_{gr} = 2.3\,\frac{g}{cm^{3}}\), \(\rho_{fe} = 7.9\,\frac{g}{cm^{3}}\), \(m_{gr} = 3.2\,g\) and \(m_{fe} = 96.8\,g\), the volume percentage of graphite is:

\(\%V_{gr} = \frac{1}{1+\left(\frac{2.3\,\frac{g}{cm^{3}} }{7.9\,\frac{g}{cm^{3}} } \right)\cdot \left(\frac{96.8\,g}{3.2\,g} \right)} \times 100\,\%\)

\(\%V_{gr} = 10.197\,\%V\)

The volume percentage of graphite is 10.197 per cent.

Following are the solution to the given points:

\(\to C_{Gr} = 100\\\\ \to C_{\alpha}= 0\)From \(Fe-F_{\frac{e}{3}} c\) diagram.  

\(\to W_{\alpha} =\frac{C_{Gr}-C_{o}}{C_{Gr}-C_{\alpha}}\)

           \(= \frac{100-3.6}{100-0} \\\\= \frac{100-3.6}{100} \\\\= \frac{96.4}{100} \\\\=0.964\)

Calculating the weight fraction of graphite:  

\(\to W_{Gr}=\frac{C_0 - c_d}{C_{Gr} -c_d}\)

            \(= \frac{3.6-0}{100-0} \\\\ = \frac{3.6}{100} \\\\= 0.036\)

Calculating the volume percent of graphite:

\(\to V_{Gr}=\frac{\frac{W_{Gr}}{P_{Gr}}}{\frac{w_{\alpha}}{P_{\alpha}}+ \frac{W_{Gr}}{P_{Gr}}}\)

           \(=\frac{\frac{0.036}{2.3}}{\frac{0.964}{7.9}+\frac{0.036}{2.3}}\\\\=0.11368 \times 100\%\\\\=11.368\%\)

Therefore, the final answer is "0.964, 0.036, and 11.368%"

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The circuit that may not be used to determine the value of the resistor is (Option A). See the attached image.

A resistor is a component of an electronic circuit that restricts or regulates the passage of electrical current.

Resistors can also be used to supply a fixed voltage to an active device such as a transistor.

A resistor is a two-terminal electrical component that offers resistance to current flow. Resistors are commonly employed in electrical circuits to reduce current flow, split voltages, impede transmission signals, and bias active parts.

Individual electronic components such as resistors, transistors, capacitors, inductors, and diodes are linked by electrical wires or traces through which electric current can pass to form an electronic circuit.

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Answer:

I think it is false!

Explanation:

Answer: I think it's true

Explanation:

Because if you were part of a play, you would have a part but if you work on props, you don't have a part onstage.

Defining the circumstances that require research action, as well as a comprehensive examination of the history and references.

A rigorous and methodical study and inquiry of some area expertise is referred to as research.

A "systematic inquiry" is a planned activity that includes data gathering (mathematical or subjective) and analysis in order to discuss the issue.

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Powder actuated tools should never be used on hard, brittle, or non-ductile materials.

Powder actuated tools, also known as "powder-actuated nail guns" or "direct fastening tools," are designed for driving fasteners such as nails or pins into various materials using controlled explosive charges. However, using powder actuated tools on certain materials can pose risks and potential hazards.

Materials that are hard, brittle, or non-ductile, such as concrete, ceramic tiles, glass, stone, or certain types of metal, should not be subjected to the force generated by powder actuated tools. These materials can crack, shatter, or splinter under the high impact or pressure applied by the tool, leading to structural damage, injury, or other safety concerns.

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The bandwidth that the cable can provide for data transfer is where the biggest distinction of CAT5e cable exists.

The primary distinction between Cat5e and Cat6 cabling is in the capacity, both of which enable speeds up to megabytes Per second, which is more than enough for the majority of internet connections. Faster data transfer is made possible by higher bandwidth, and Cat6 cables handle speeds up to 250 Gaz as opposed to Cat5e's 100 MHz.

The frequency of a Cat7 is also higher than that of the Cat6. How frequently a signal may go via a cable is determined by its frequency. Therefore, 10,000 Mbit/s may be transported 10,000 times per second at a bandwidth of 1,000 MHz. Therefore, data may be transmitted via a Cat7 wire more quickly than a Cat6 link.

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The Java code is given below:

VotingMachine vm = new VotingMachine();

vm.voteDemocrat();

vm.voteDemocrat();

vm.voteRepublican();

vm.voteIndependent();

vm.countDemocrat(); // returns 2

vm.countRepublican(); // returns 1

vm.countIndependent(); // returns 1

vm.whoWon(); // returns “Democrat”

The VotingMachine class remembers and counts votes in a simple election with only parties, democrats and republicans.

The state of VotingMachine-objects is the current count (integers) of votes for democrats and republicans. In the initial state, both counters should be zero.

The VotingMachine class has two method for reading the current state, getDemocratTally() and getRepublicanTally(), and three methods for altering the state, clear(), voteDemocrat() and voteRepublican(), with the following behavior:

getDemocratTally - returns the current number (an int) of democrat votes

getRepublicanTally - returns the current number (an int) of republican votes

voteDemocrat() - registers a(nother) democrat vote

voteRepublican() - registers a(nother) republican vote

clear - clears all the votes and returns to the initial state

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Answer:

This is an example of the conduction of electricity through metal. Free moving electrons on the car will conduct a electric field when a voltage is applied to the car;  in this case the transmission line, and would flow through the metal to the door handle causing electrocution.

a The natural frequency of the paralysis transient response is 1.07 rad/s.

b The maximum possible percent paralysis if a 2% mixture of isoflurane is used is 7.63%.

c  The step response of paralysis if a 1% mixture of isoflurane is used

The percent isoflurane that would have to be used for 100% paralysis is 27.3%.

A. The damping ratio is given by ζ = −b/2√(a² - c²).

In this case, a = 1.15, b = 0, and c = 0.28,

The natural frequency of the paralysis transient response is given by ωn = √(a² - c²)

= √(1.15² - 0.28²)

= 1.07 rad/s.

B. The maximum possible percent paralysis is given by the steady-state value of the step response. In this case, the steady-state value is equal to the gain of the system, which is 7.63 × 10⁻².

Therefore, the maximum possible percent paralysis if a 2% mixture of isoflurane is used is 0.0763 = 7.63%.

C. The step response of paralysis if a 1% mixture of isoflurane is used is shown below.

Time (s) | Percent paralysis

------- | --------

0.0 | 0.00

0.1 | 0.03

0.2 | 0.06

0.3 | 0.09

0.4 | 0.12

0.5 | 0.15

0.6 | 0.18

0.7 | 0.21

0.8 | 0.24

0.9 | 0.27

1.0 | 0.30

As you can see, the percent paralysis increases rapidly at first, and then approaches a steady-state value of

= 7.63 × 10⁻²

= 7.63%.

D. For 100% paralysis, the percent paralysis must equal the gain of the system, which is 7.63 × 10⁻². Therefore, the percent isoflurane that would have to be used for 100% paralysis is

= 0.63 × 10⁻² / 0.28

= 27.3%.

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The state of stress at point B is -221.66psi and the case of compression and positive in case of tension is 39.375psi

In continuum mechanics, it should be noted that stress is a physical quantity that describes forces present during deformation.

In this case, ann object being pulled apart, such as a stretched elastic band, is subject to tensile stress and may undergo elongation.

The value will be:

= (420 × 1.5 × 3) / 3 × 4/12 × 3

= 39.375

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step: 1 of 16

The static thrust is defined as such a force which is developed and applied by the jet engine on the surrounding air or earth when the airplane is at rest condition.

Power is defined as the rate of doing work with respect to time. Power is a scalar quantity and having no direction. The unit of power is J/s  or watt in an hour(w) .

The expression to calculate the resultant power Ps  is,

PRETV  …… (1)

Here, Ps  is the required power, T R  is the required thrust and is the velocity of the airplane at a certain altitude.

The expression for the actual power for two engines is,

P, = 2(TV)  …… (2)

Here, т.  is the actual thrust and  is the velocity of the airplane for a given altitude.

step: 2 of 16

Write the expression for the thrust of an airplane.

TRE W CIC)  …… (3)

Here, T R  is the required thrust, W  is the weight of the airplane, с. is the lift polar coefficient of the airplane and Ср  is the drag polar coefficient of the plane.

Write the expression for the lift polar coefficient of the airplane.

W C 1 2P. Vis  …… (4)

Here, P  is the air density,  is the velocity of the airplane for a given altitude and S  is the wing area.

Write the expression for drag polar coefficient.

C, = CD,0 + C πε(AR)  …… (5)

Here, Сро  is the zero-lift drag coefficient,  is the Oswald’s efficiency factor and AR  is the aspect ratio.

It is clear from the power required curve that maximum velocity at the altitude at 5 km is

Hence, the required maximum velocity at the altitude of 5 km  is295 m/s.

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The insurance company offers four different deductible levels for its homeowners policyholders and the insured.

The level means an amount of money that the policyholder must pay out of pocket before their insurance coverage kicks in. The 4 different deductible levels offered by the insurance company are none, low, medium, and high.

The policyholder can choose the deductible level based on their budget and the level of risk are willing to assume. A higher deductible level typically results in a lower premium payment and lower deductible level typically results in a higher premium payment.

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Answer:

please mark me as BRAINLIEST

Explanation:

There are so many software packages available to develop HTML. The software packages can be grouped into two main categories: text-based (or code-based) editors.

...

WYSIWYG editors

Macromedia Dreamweaver.

Microsoft FrontPage.

Adobe GoLive.

To anticipate health hazards in each of the eight areas of the AAP plant, the following information could be used:

1. Shipping/Receiving:

2. Hydraulic Presses:

3. Metal Working Lines:

4. Robotic Welding Stations:

5. Hand-Welding Stations in Rework Areas:

6. Small Paint Booths:

7. QA/QC Laboratory:

8. Final Inspection Area:

To anticipate health hazards in each area of Acme Automotive Parts (AAP) manufacturing facility, the following information would be relevant.

1. Shipping/Receiving: Material Safety Data Sheets (MSDS) for chemicals received, potential for heavy lifting injuries, and risks associated with forklift operations.

2. Hydraulic Presses and Metal Working Lines: MSDS for lubricants and coolants, risks of crush injuries, and exposure to metal fumes.

3. Robotic and Hand-Welding Stations: MSDS for welding materials, welding fume exposure, and risk of burns.

4. Paint Booths: MSDS for paints and coatings, potential for volatile organic compounds (VOCs) exposure, and respiratory hazards.

5. QA/QC Laboratory: MSDS for chemicals used in testing, potential for chemical exposure, and ergonomic risks.

6. Final Inspection Area: Ergonomic risks associated with repetitive tasks, MSDS for any chemicals used, and general safety precautions.

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The thing that  occurs during the intake stroke on a four-stroke internal combustion diesel engine is  a. Air is drawn through the intake valve in to the cylinder

In a diesel engine's four-stroke intake process, the cylinder's downward movement of the piston generates a vacuum. This intake valve allows the flow of clean air to be taken in by the vacuum. While a gasoline engine combines air and fuel in the intake stroke, a diesel engine solely takes in air in this process.

During the compression stroke that follows, the air undergoes compression while fuel is injected into the superheated compressed air during the combustion stroke.

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The performance tables of an aircraft for takeoff and climb are based on A— pressure/density altitude.

The performance tables of an aircraft for takeoff and climb are typically based on pressure/density altitude. Pressure altitude refers to the altitude above the standard pressure level, while density altitude takes into account variations in atmospheric pressure and temperature, which affect air density. By using pressure/density altitude, the aircraft's performance calculations can be adjusted to account for changes in atmospheric conditions.

Pressure/density altitude is crucial in aircraft performance because it affects various factors that impact the aircraft's takeoff and climb capabilities. As altitude increases, the air density decreases, resulting in reduced engine performance and less lift generation. This reduction in performance affects parameters such as takeoff distance, climb rate, and fuel consumption. Therefore, by considering pressure/density altitude, pilots and aircraft performance engineers can accurately assess the aircraft's capabilities under different atmospheric conditions and make informed decisions regarding takeoff and climb performance.

Hence, pressure/density altitude is the key parameter used in aircraft performance tables for takeoff and climb. It accounts for changes in atmospheric conditions and allows pilots and performance engineers to determine the aircraft's performance capabilities accurately. By using pressure/density altitude, the aircraft's performance calculations can be adjusted to ensure safe and efficient operations during takeoff and climb phases.

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The work done on air during the compression process is 3.327 KJ in 8l piston-cylinder device contains air at 300 kpa and 300 k.

One of the main ways a thermodynamic system interacts with its environment and exchanges energy is through work in thermodynamics. A process that allows the system to spontaneously exert macroscopic forces on its surroundings, or the opposite, facilitates an exchange of energy.

Work is considered to have been completed on a system when a force is applied and the system experiences a displacement. A system is considered to have completed work when it exerts force on an object and results in displacement.

The formula for work is W=Fd

Given that

P1 = 300k pa , V1 = 8L

v2 = 2L

Temperature remains constant it means that this is isothermal process

For isothermal process P1V1 = P2V2

We know that work for isothermal process  

W = P1V1 ln P1/P2

Now by putting the values

W = 300 * 8 * 10^-3 ln 2/8

W = -3.327 KJ

Negative sign indicates is process is compression

W=3.327 KJ

Work done on air during this compression process is 3.327 KJ

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The exclusion of some traditional partners from the "democratic camp" by the United States will undoubtedly deepen the gap between the two sides.

About summit :

This move by the US is seen as a sign of its dissatisfaction with the policies and behavior of these countries. In addition, the invitation of some countries or regions suspected of "democratic retrogression" may lead to further erosion of the credibility of the summit in the eyes of the invited countries, as well as the international community. At the same time, it is worth noting that the United States must consider the consequences of such actions and the possible damage to its international image. If the US is seen as selectively choosing partners, it may undermine its overall influence in the world.

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The initial enthalpy and the entropy of the saturated water can be found out from the table of A-12E

i.e.   \($h_1= 101 \ \text{Btu/lbm}$\)

       \($s_1 = 0.22717 \text{ Btu/lbmR}$\)

Since the process mentioned above is an adiabatic compression process, the entropy will remain constant throughout the process. Therefore, we take the value of entropy and the final pressure using the table with few interpolations and also approximations to find the final enthalpy. It is given by :

       \($h_2= 116.09 \text{ Btu/lbm}$\)

So the work input from the energy balance equation :

       \($\dot{W} + \dot{m}h_1 = \dot{m}h_2$\)

          \($w=h_2 - h_1$\)

              = 116.09 - 101

              = 15.09

Therefore, \($w= 15.09 \text{ Btu/lbm}$\)

Answer:

I think trains are pretty awesome. There's a train in japan that levitates slightly and runs on magnetism. Pretty amazing. It's super fast too

With a mass flow rate of 22.2 kg/s and steady state running at -10 c, 1.4 bar, refrigerant 134a enters a water-jacketed compressor and departs at 50 c, 12 bar. 792.9 watt of compressor power is needed.

At -4 degrees Celsius, refrigerant 134a enters a compressor that is running in steady state and leaves at a pressure of 14 bar. The efficiency of the isentropic compressor is 85%. You can disregard the compressor's ability to transfer heat to its surroundings. Effects on potential energy and kinetic energy are also insignificant.

At a rate of 100 kPa, saturated vapour of refrigerant-134a enters an adiabatic compressor.

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Take into account a transfer function Where A=9.4, H (w) = fl. Determine the magnitude of H (no) at f=0.5Hz. Question 8: 10 points. Take into account a transfer...

What is the example of transfer?

to transport something or someone from one location, vehicle, individual, or group to another: He has been transferred to a mental hospital. She took her revolver out of the holster on her shoulder and put it in her handbag. From one bus to the next, we were transferred.

Moving anything from one form or location to another is referred to as a transfer, which is why money that was transferred from one account to another is regarded as a transfer.

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Answer:

True

Explanation:

Below is a cut and paste.  Also read where recycling shops will pay up to $200 to harvest the precious metals used in catalyst process.  Thieves will actually steal them from parked cars!!

Catalytic converters also use an oxidative catalyst composed of platinum or palladium. It helps reduce hydrocarbons (HC) and carbon monoxide (CO). To start with, carbon monoxide and oxygen combine to form carbon dioxide (CO2). Then, unburnt hydrocarbons and oxygen combine to form carbon dioxide and water.

Oxidation reactions for carbon monoxide and unburned hydrocarbons

Answer:

True

Explanation:

IM doing it right now