Marine chemist exam in the mass percent composition of manganese sulfide compound from ocean floor he determined that 60.2% of this compound is sulfur determine the mole ratio between manganese and sulfur

Answer:

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Explanation:

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Answer:

Salt solution may be calculated by measuring the specific gravity of a sample of water using a hydrometer.

Hope this answer correct (^^)....

Explanation:

In natural radioactive decay, three common emissions occur. When these emissions were originally observed, scientists were unable to identify them as some already known particles and so named them:

alpha particles ( α )

beta particles (β)

gamma rays (γ)

These particles were named using the first three letters of the Greek alphabet. Some later time, alpha particles were identified as helium-4 nuclei, beta particles were identified as electrons, and gamma rays as a form of electromagnetic radiation like x-rays, except much higher in energy and even more dangerous to living systems.

To answer this question, we have to use the heat of vaporization of water, that tells us the amount of energy required to evaporate or condense 1 g of water.

According to it, you need to remove 2.257kJ to condensate 1 g of water:

It means that -208.09kJ are required to condensate 92.2grams of water.

The answer is negative because to condensate a substance you have to remove heat, so when we express it we have to write as a negative amount.

Ammonium sulfide nh4s is the name-formula pair that is incorrectly matched.

The formula is a fact or a rule that is expressed using mathematical symbols. Normally, three or more values are connected by an equal sign. When you know the value of one quantity, you may apply the formula to determine how much the other quantity is worth.

Following that, demand fell as households decided not to make purchases and instead made do about what they already had. When a result, formula producers would have to produce less as the market changed. Delays: Supply chain bottlenecks brought on by the epidemic continue to affect the production of baby formula. With the maker Abbott, delays brought on by the weather have also happened.

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Answer:

... x M x V. • Example: Prepare 800 mL of 2 M sodium chloride. ... solutions are indicated by w/v% and are defined as the grams of solute per ...

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Answer:

The answer is Conduction

Explanation:

Conduction is the process of heat being transferred between objects through direct contact, and it's the most common type of heat transfer.

Answer:

The answer is Conduction

Explanation:

Conduction is the process of heat being transferred between objects through direct contact, and it's the most common type of heat transfer.

I hope this helps!

The mass of the solid aluminum that forms are 192.73 grams

To determine the mass of solid aluminum that forms, we need to use stoichiometry and the balanced chemical equation for the reaction between magnesium and aluminum nitrate.

The balanced chemical equation is:

3 Mg + 2 Al(\(NO_{3}\))3 → 3 Mg(\(NO_{3}\))2 + 2 Al

The equation shows that 3 moles of magnesium react with 2 moles of aluminum to produce 2 moles of aluminum nitrate.

To calculate the mass of solid aluminum, we need to know the amount of magnesium used. Given that the volume of the magnesium is 150.0 mL and its density is 1.738 g/cm³, we can calculate the mass of magnesium using the formula:

Mass = Volume × Density

Mass of magnesium = 150.0 mL × 1.738 g/cm³ = 260.7 g

Now, using the molar mass of magnesium (24.31 g/mol) and the molar ratio from the balanced equation, we can determine the moles of magnesium used:

Moles of magnesium = Mass of magnesium / Molar mass of magnesium

= 260.7 g / 24.31 g/mol

= 10.72 mol

According to the stoichiometry of the balanced equation, the ratio of moles of magnesium to moles of aluminum is 3:2. Therefore, the moles of aluminum formed will be:

Moles of aluminum = (2/3) × Moles of magnesium

= (2/3) × 10.72 mol

= 7.15 mol

Finally, we can calculate the mass of solid aluminum using its molar mass (26.98 g/mol):

Mass of aluminum = Moles of aluminum × Molar mass of aluminum

= 7.15 mol × 26.98 g/mol

= 192.73 g

Therefore, the mass of the solid aluminum that forms is approximately 192.73 grams.

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Answer: pressure exerted by vapor

Explanation:

Answer:

1. pH = 2.98

2. pH = 4.02

3. pH = 8.12

Explanation:

1. Initial molarity of benzoic acid (Molar mass: 122.12g/mol; Ka = 6.14x10⁻⁵) is:

0.235 ₓ (1mol / 122.12g) = 1.92x10⁻³ moles / 0.100L = 0.01924M

The equilibrium of benzoic acid with water is:

C6H5CO2H(aq) + H2O(l) → C6H5O-(aq) + H3O+(aq)

And Ka is defined as the ratio between equilibrium concentrations of products over reactants, thus:

Ka = 6.14x10⁻⁵ = [C6H5O⁻] [H3O⁺] / [C6H5CO2H]

The benzoic acid will react with water until reach equilibrium. And equilibrium concentrations will be:

[C6H5CO2H] = 0.01924 - X

[C6H5O⁻] = X

[H3O⁺] = X

Replacing in Ka:

6.14x10⁻⁵ = [X] [X] / [0.01924 - X]

1.1815x10⁻⁶ - 6.14x10⁻⁵X = X²

1.1815x10⁻⁶ - 6.14x10⁻⁵X - X² = 0

Solving for X:

X = -0.0010→ False solution. There is no negative concentrations

X = 0.0010567M → Right solution.

pH = - log [H3O⁺] and as [H3O⁺] = X:

pH = - log [0.0010567M]

2.

pH of a buffer is determined using H-H equation (For benzoic acid:

pH = pka + log [C6H5O⁻] / [C6H5OH]

pKa = -log Ka = 4.21 and [] could be understood as moles of each chemical

The benzoic acid reacts with NaOH as follows:

C6H5OH + NaOH → C6H5O⁻ + Na⁺ + H₂O

That means NaOH added = Moles C6H5O⁻ And C6H5OH = Initial moles (1.92x10⁻³ moles - Moles NaOH added)

7.00mL of NaOH 0.108M are:

7x10⁻³L ₓ (0.108 mol / L) = 7.56x10⁻⁴ moles NaOH = Moles C₆H₅O⁻

And moles C6H5OH = 1.92x10⁻³ moles - 7.56x10⁻⁴ moles = 1.164x10⁻³ moles C₆H₅OH

Replacing in H-H equation:

pH = 4.21 + log [7.56x10⁻⁴ moles] / [ 1.164x10⁻³ moles]

3. At equivalence point, all C6H5OH reacts producing C6H5O⁻. The moles are 1.164x10⁻³ moles

Volume of NaOH to reach equivalence point:

1.164x10⁻³ moles ₓ (1L / 0.108mol) = 0.011L. As initial volume was 0.100L, In equivalence point volume is 0.111L and concentration of C₆H₅O⁻ is:

1.164x10⁻³ moles / 0.111L = 0.01049M

Equilibrium of  C₆H₅O⁻ with water is:

C₆H₅O⁻(aq) + H₂O(l) ⇄  C₆H₅OH(aq) + OH⁻(aq)

Kb = [C₆H₅OH] [OH⁻]/ [C₆H₅O⁻]

Kb = kw / Ka = 1x10⁻¹⁴ / 6.14x10⁻⁵ = 1.63x10⁻¹⁰

Equilibrium concentrations of the species are:

C₆H₅O⁻ = 0.01049M - X

C₆H₅OH = X

OH⁻ = X

Replacing in Kb expression:

1.63x10⁻¹⁰ = X² / 0.01049- X

1.71x10⁻¹² - 1.63x10⁻¹⁰X - X² = 0

Solving for X:

X = -1.3x10⁻⁶ → False solution

X = 1.3076x10⁻⁶ → Right solution

[OH⁻] =  1.3076x10⁻⁶

as pOH = -log [OH⁻]

pOH = 5.88

And pH = 14 - pOH

Answer:

Beliefs or practices that are regarded as "scientific" and "factual" but have not been proven nor are they backed by science.

Explanation:

Example: Astrology

As provided in the question, the pH of a solution is equal to the negative logarithm of the H₃O⁺ concentration in the solution (the square brackets denote the molar concentration).

We are given a solution with an H₃O⁺ concentration of 5.6 × 10⁻⁹ M. So, the pH of this solution would be:

pH = -log[H₃O⁺] = -log(5.6 × 10⁻⁹ M) = 8.25.

A pH that is equal to 7 is neutral; less than 7, acidic; and greater than 7, basic. As 8.25 is greater than 7, this solution is basic.

Answer:

c

Explanation:

Answer:

c

Explanation:

Answer: B

Explanation: im pretty sure my teacher mentioned something about N--h bonds are non polar

Answer:

C

Explanation:

Answer:

0.1M

Explanation:

Molarity = \(\frac{mole}{volume}\)

Let d be the diluted solution, let i be the initial solution

\(C_{d} V_{d} = C_{i}V_{i}\)

\(C_{d} = \frac{C_{i}V_{i}}{V_{d}}\)

= 0.15 x (100x10^-3) / (50x10^-3)+(100x10^-3)

= 0.1 M

Answer:

for me, it is hard to understand the topics in the module and it can affect your grades that's why I am angry like a volcano When the pressure is too much an explosive eruption can happen, which can be dangerous and destructive

The vapor pressure of the SiCl₄ in the mmHg at the 33.0 °C is the 312 mmHg.

The Clausius - Clapeyron equation is as :

ln ( P₂ / P₁ ) = ΔHvap / R ( 1 / T₁ - 1 / T₂ )

P₂ = P₁eˣ

Where,

The temperature, T₁  = 5.4 °C = 278.55 K

The temperature, T₂  = 33.0 °C= 306 K

The pressure, P₁ = 100 mmHg

ΔHvap is the heat of the vaporization = 30.2 kJ /mol = 30200 J/mol

The gas constant, R = 8.314 J / mol K

x = ΔHvap / R ( 1 / T₁ - 1 / T₂ )

x = 30200 / 8.314 ( 1/ 278.55 - 1/ 306 )

x = 1.05

P₂ = 100 \(e^{1.05}\)

P₂ = 312 mmHg

The vapor pressure of the  SiCl₄ is 312 mmHg.

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Answer: A

Explanation:

Answer:

1. 126.44 or 126.4

2. 12.766 or 12.8

3.190.77 or 190.8

4.12.833 or 12.8

Explanation:

Answer:

option a. Temperature is equal to 273 k. Is the correct one

A boils when its vapour pressure is equal to, or greater than, the external pressure pushing on it. Therefore, option (b) is correct.

A boiling point of a liquid can be defined as the temperature at which the vapour pressure becomes equal to the atmospheric pressure of the liquid. The liquid is converted into a vapour at this temperature.

With the addition of heat that the liquid changes into vapour without any increase in temperature. The vapour pressure increases until it is equal to the pressure of the gas surrounding it as a liquid is heated. Bubbles of vaporized liquid are formed within the liquid and rise to the surface.

At the boiling temperature, the vapour inside the bubble will exert enough pressure to prevent the bubble from collapsing. The molecules of a liquid will able to overcome the forces of attraction between molecules to create vapour.

Therefore, at boiling point, the vapour pressure is equal to, or greater than, the external pressure pushing on it.

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Answer:

The final temperature of the copper would be 311.3°C.

I hope this helps you

To convert acetone (propanone) to propanal, you can use a two-step process involving reduction and oxidation reactions. Here's a general outline of the process:

1. Reduction of Acetone to Isopropanol:

First, you need to reduce acetone to isopropanol (2-propanol) using a reducing agent. Common reducing agents for this step include sodium borohydride (NaBH₄) or lithium aluminum hydride (LiAlH₄).

Reaction conditions:

- Acetone + NaBH₄ (or LiAlH₄) → Isopropanol

- Solvent: usually an alcohol (e.g., methanol or ethanol) or an ether (e.g., THF)

- Temperature: room temperature or slightly above

2. Oxidation of Isopropanol to Propanal:

Next, oxidize isopropanol to propanal using an appropriate oxidizing agent. A common oxidizing agent for this step is pyridinium chlorochromate (PCC), which selectively oxidizes primary alcohols to aldehydes without over-oxidizing to carboxylic acids.

Reaction conditions:

- Isopropanol + PCC → Propanal

- Solvent: an aprotic polar solvent (e.g., dichloromethane)

- Temperature: room temperature

- Avoid strong oxidizing agents like potassium permanganate (KMnO₄) or chromium trioxide (CrO₃) because they can over-oxidize the isopropanol to propionic acid.

Answer:

metallic bond —> sharing of many electrons

covalent bond —> sharing of electrons

ionic bond —> transferring of electrons

Explanation:

im not 100% sure this is right but i hope it still helps!

The equilibrium concentration of Br2 in the container will be 0.0376 M at 400 K.

Equilibrium concentration is described as a state when the rate of forward reaction in a chemical reaction becomes equal to the rate of backward reaction.

The reaction is given as :

Br2 + Cl2 ⇌ 2BrCl

The equilibrium constant expression for the above reaction is:

Kc = [BrCl]^2 / [Br2][Cl2]

Given initial moles of Br2 and Cl2, we can calculate their initial concentrations as follows:

[Br2] = 0.25 mol / 3.0 L = 0.0833 M

[Cl2] = 0.55 mol / 3.0 L = 0.1833 M

Assuming that x moles of Br2 react to form 2x moles of BrCl.

Therefore, the equilibrium concentrations of Br2, Cl2, and BrCl will be:

[Br2] = 0.0833 - x

[Cl2] = 0.1833 - x

[BrCl] = 2x

Kc = [(2x)^2] / [(0.0833 - x)(0.1833 - x)]

x = 0.0457 mol

In conclusion, the equilibrium concentration of Br2 is:

[Br2] = 0.0833 - 0.0457 = 0.0376 M

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Answer:

intermolecular interactions

Explanation:

hope this helps

The intermolecular attraction keeps molecules together in a liquid and stops them from becoming a gas.

The electromagnetic forces of attraction and repulsion that act between atoms and other types of nearby particles, such as atoms or ions, are examples of intermolecular forces.

Liquids have qualities that are halfway between gases and solids, yet they are closer to solids. Intermolecular forces, in opposed to intramolecular forces like covalent ties that bind atoms together in molecules as well as polyatomic ions, keep molecules with each other in a liquid or solid.

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Answer:

3 years

Explanation:

(50*0.3)x>=100