Mark all of the method calls below that are calling static methods: O String str2 = inScanner.nextLine(): O String str2 = str.substring(0,3); O String str2 = String.valueOf(12); O int z = Math.max(x, y):

Answer:

Hydrostatic force = 41168 N

Explanation:

Complete question

A triangular plate with a base 5 ft and altitude 3 ft is submerged vertically in water  so that the top is 4 ft below the surface. If the base is in the surface of water, find the force against onr side of the plate. Express the hydrostatic force against one side of the plate as an integral and evaluate it. (Recall that the weight density of water is 62.5 lb/ft3.)

Let "x" be the side length submerged in water.

Then

w(x)/base = (4+3-x)/altitude

w(x)/5 = (4+3-x)/3

w(x) = 5* (7-x)/3

Hydrostatic force = 62.5 integration of  x * 4 * (10-x)/3 with limits from 4 to 7

HF = integration of 40x - 4x^2/3

HF = 20x^2 - 4x^3/9 with limit 4 to 7

HF = (20*7^2 - 4*7^(3/9))- (20*4^2 - 4*4^(3/9))

HF = 658.69 N *62.5 = 41168 N

The COP of this air conditioner is 1.42. (b) The rate of heat transfer to the outside air is 850 kJ/min.

To determine the Coefficient of Performance (COP) of the air conditioner, we use the formula COP = Qc / W, where Qc is the heat removed by the air conditioner and W is the power consumed by the air conditioner.

In this case, the heat removed is given as 850 kJ/min and the power consumed is 10 kW.

To convert 10 kW to kJ/min, we multiply it by 60 since there are 60 minutes in an hour.

Therefore, 10 kW is equal to 600 kJ/min. Now we can calculate the COP: COP = 850 kJ/min / 600 kJ/min = 1.42. Hence, the COP of this air conditioner is 1.42.

To find the rate of heat transfer to the outside air, we simply use the heat removed value of 850 kJ/min.

Thus, the rate of heat transfer to the outside air is 850 kJ/min.

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Answer:

Along the zero to measure an object on a ruler

Answer:

a) the mass flow rate of the steam is  \(\mathbf{m_1 =6.92 \ kg/s}\)

b) the exit velocity of the steam  is \(\mathbf{V_2 = 562.7 \ m/s}\)

c) the exit area of the nozzle is  \(A_2\) = 0.0015435 m²

Explanation:

Given that:

A steam with 5 MPa and 400° C enters a nozzle steadily

So;

Inlet:

\(P_1 =\) 5 MPa

\(T_1\) = 400° C

Velocity V = 80 m/s

Exit:

\(P_2 =\) 2 MPa

\(T_2\) = 300° C

From the properties of steam tables  at \(P_1 =\) 5 MPa and \(T_1\) = 400° C we obtain the following properties for enthalpy h and the speed v

\(h_1 = 3196.7 \ kJ/kg \\ \\ v_1 = 0.057838 \ m^3/kg\)

From the properties of steam tables  at \(P_2 =\) 2 MPa and \(T_1\) = 300° C we obtain the following properties for enthalpy h and the speed v

\(h_2 = 3024.2 \ kJ/kg \\ \\ v_2= 0.12551 \ m^3/kg\)

Inlet Area of the nozzle = 50 cm²

Heat lost Q = 120 kJ/s

We are to determine the following:

a) the mass flow rate of the steam.

From the system in a steady flow state;

\(m_1=m_2=m_3\)

Thus

\(m_1 =\dfrac{V_1 \times A_1}{v_1}\)

\(m_1 =\dfrac{80 \ m/s \times 50 \times 10 ^{-4} \ m^2}{0.057838 \ m^3/kg}\)

\(m_1 =\dfrac{0.4 }{0.057838 }\)

\(\mathbf{m_1 =6.92 \ kg/s}\)

b) the exit velocity of the steam.

Using Energy Balance equation:

\(\Delta E _{system} = E_{in}-E_{out}\)

In a steady flow process;

\(\Delta E _{system} = 0\)

\(E_{in} = E_{out}\)

\(m(h_1 + \dfrac{V_1^2}{2})\) \(= Q_{out} + m (h_2 + \dfrac{V_2^2}{2})\)

\(- Q_{out} = m (h_2 - h_1 + \dfrac{V_2^2-V^2_1}{2})\)

\(- 120 kJ/s = 6.92 \ kg/s (3024.2 -3196.7 + \dfrac{V_2^2- 80 m/s^2}{2}) \times (\dfrac{1 \ kJ/kg}{1000 \ m^2/s^2})\)

\(- 120 kJ/s = 6.92 \ kg/s (-172.5 + \dfrac{V_2^2- 80 m/s^2}{2}) \times (\dfrac{1 \ kJ/kg}{1000 \ m^2/s^2})\)

\(- 120 kJ/s = (-1193.7 \ kg/s + 6.92\ kg/s ( \dfrac{V_2^2- 80 m/s^2}{2}) \times (\dfrac{1 \ kJ/kg}{1000 \ m^2/s^2})\)

\(V_2^2 = 316631.29 \ m/s\)

\(V_2 = \sqrt{316631.29 \ m/s\)

\(\mathbf{V_2 = 562.7 \ m/s}\)

c) the exit area of the nozzle.

The exit of the nozzle can be determined by using the expression:

\(m = \dfrac{V_2A_2}{v_2}\)

making \(A_2\) the subject of the formula ; we have:

\(A_2 = \dfrac{ m \times v_2}{V_2}\)

\(A_2 = \dfrac{ 6.92 \times 0.12551}{562.7}\)

\(A_2\) = 0.0015435 m²

Worker A is more likely to tire more quickly than worker B as per the given scenario.

When you exercise as hard as you can, your VO2 max evaluates how much oxygen (often measured in milliliters) you breathe in.

To determine which worker will tire more quickly, we need to calculate their relative workloads while carrying the additional load.

Worker A:

Worker B:

We can see from the calculations above that worker A will be bearing the additional load while working at a higher percentage of his VO2 max than worker B.

Thus, worker A is more likely than worker B to become fatigued more rapidly.

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It's important to note that this speed difference is only noticeable for large programs. For small programs, the difference is negligible.

1. Shortcut operators are faster than the conventional arithmetic operators: This statement is true. Shortcut operators are faster because they combine arithmetic operations with variable assignments in a single statement. For example, instead of writing "a = a + 2", you can write "a += 2". This saves time and reduces the amount of code you need to write. However, it's important to note that this speed difference is only noticeable for large programs or when dealing with complex calculations. For small programs, the difference is negligible.
2. You can declare more than one variable in a single line: This statement is also true. In many programming languages, you can declare and initialize multiple variables on the same line. For example, instead of writing "int a; int b; int c;", you can write "int a, b, c;". This saves space and makes your code more concise. However, it's important to note that you should only do this if the variables are related and have the same data type.
3. You must use else after every if statement: This statement is false. It's not necessary to use else after every if statement. You can use if statements on their own if you don't need to execute any code if the condition is not true. However, if you need to execute code in both cases (true and false), then you should use else. It's also important to note that you can use else if to test for additional conditions if the first if statement is not true.

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Hey there ..

I think the answer is as they put brake ..

I am not sure .. just check the image also provided above .. ..

If u think this helped u ..plz mark me as brainliest ..

And follow me

Answer:

During starts and stops

Explanation:

"Many of the energy inefficiencies in vehicles occur during starts and stops."

found it in the text.

Answer:

Explanation:

It appears that you are trying to solve a problem involving an insulated rigid tank containing saturated liquid water and water vapor. To determine the volume of the tank, you will need to know the mass of the liquid water and the mass of the water vapor. The mass of the liquid water can be calculated by multiplying the mass of the water and vapor mixture by the fraction of the mixture that is liquid water (1.4 kg * 0.25 = 0.35 kg). The mass of the water vapor can be calculated by subtracting the mass of the liquid water from the total mass of the mixture (1.4 kg - 0.35 kg = 1.05 kg).

To determine the final temperature of the tank, you will need to know the amount of heat added to the tank by the electric resistor and the specific heat capacity of the water and water vapor mixture. The specific heat capacity is a measure of the amount of heat required to raise the temperature of a substance by a certain amount. The specific heat capacity of water is 4.186 J/g°C, and the specific heat capacity of water vapor is 2.080 J/g°C.

To determine the electric power rating of the resistor, you will need to know the amount of heat added to the tank by the resistor and the time over which the heat was added. The power rating of the resistor is equal to the amount of heat added to the tank divided by the time over which the heat was added.

I hope this helps clarify the problem and provide some guidance on how to solve it. If you have any further questions or need additional help, please don't hesitate to ask.

Pesticide drift refers to the movement of airborne toxicants from their intended target area to other non-target areas, which can be a specific problem in agricultural environments.

Pesticide drift can occur due to various factors such as wind direction, application methods, and weather conditions. The unintended movement of pesticides can lead to contamination of soil, water, and air, which can have adverse effects on human health and the environment.

Pesticide drift refers to the unintentional movement of pesticide particles from the target area to non-target areas due to various factors, such as wind or evaporation. This can cause damage to nearby plants, animals, and human health.

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Answer:

A.) 0.08 kJ/kg.K

B.) 207.8 KJ/Kg

C.) 0.808

Explanation:

From the question, the use of fluids mechanic table will be required. In order to get the compressor processes, the kinetic energy and the potential energy will be negligible while applying the ideal gas model.

Since the steam is a closed system, the carbon dioxide will be compressed adiabatically.

Please find the attached files for the solution and the remaining explanation.

The correct answer is Option A. Purging with nitrogen gas is the preferred method to remove non-condensable gases from a refrigeration system.

Non-condensable gases such as air, nitrogen, and water vapor can enter a refrigeration system via a variety of methods and sources, such as during assembly, servicing, or repair. Since these gases cannot be condensed in the refrigerant's condenser, they cause higher condensing pressures and temperatures, as well as decreased cooling capacity. They should be removed from the system using the following procedure:

a. Purging with nitrogen gas
Purging the system with dry nitrogen gas to get rid of the non-condensable gases is the most popular method. Nitrogen is preferred since it is a dry, inert gas that will not react with the refrigerant or other components in the system, and it can be acquired relatively cheaply. When removing non-condensable gases from a refrigeration system, nitrogen must be introduced into the system at a low pressure through the suction side, while the high-pressure side is being vented. The process must continue until all non-condensable gases have been removed from the system.
b. Adding more refrigerant
Adding more refrigerant is not an acceptable way to get rid of non-condensable gases since it does not solve the problem and may exacerbate it. Furthermore, if too much refrigerant is added, it will cause the compressor to operate inefficiently and may harm the system.
c. Cleaning the condenser coils
Cleaning the condenser coils will aid in the removal of non-condensable gases by allowing the refrigerant to flow freely. A condenser that is dirty or obstructed with dirt, grime, or other debris can reduce airflow, causing the refrigerant to back up in the condenser and form pockets. The additional pressure causes the refrigerant to boil and create air bubbles, which contribute to non-condensable gases.
d. Increasing the compressor speed
Increasing the compressor speed will not remove non-condensable gases from the system. In reality, it will do the opposite since compressors that run at high speeds often generate more heat, which will exacerbate the problem by causing the refrigerant to vaporize and create additional air bubbles, leading to more non-condensable gases. Hence, purging with nitrogen gas is the preferred method to remove non-condensable gases from a refrigeration system.

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Ew Wakefield Hospital has only one portable X-ray machine. The emergency room staff claim to have the greatest need for the machine, but the surgeons in the operating room demand ready access to the machine. The conflict between these two groups is a result of scarcity.

Science and technology are the driving forces behind today's modern medicine, allowing us to identify and treat a range of medical problems. X-ray technology has had a significant impact on medicine, and it is commonly used to diagnose various diseases, making it an essential tool for hospitals.

Despite the advantages, the scarcity of portable X-ray machines creates difficulties for hospital employees, including a dispute between the emergency room and the operating room staff at Ew Wakefield Hospital. There is only one portable X-ray machine available at Ew Wakefield Hospital.

The conflict between the emergency room and the operating room staff is a result of scarcity. Both departments require ready access to the X-ray machine. Scarcity can generate rivalry, competition, and conflict when people and organizations compete for the same resource.

The staff's conflict is a direct result of the lack of accessibility to the X-ray machine. Thus, scarcity can be a significant factor contributing to interpersonal conflict.

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75743366

Explanation:

Tire pressure typically drops 1 psi for every 10 degrees drop in temperature. Technician B is also correct, as there are two types of TPMS pressure sensors: snap-in and clamp-in. Hence Technician A is correct.

According to the given information,

Tire Pressure Monitoring System (TPMS) is an electronic system that helps to monitor the air pressure of the tires of the vehicle.

Two types of TPMS pressure sensors are Snap-In and Clamp-In:

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Answer:

Food and drug admin

Explanation:

We can determine the output at t = 1 by substituting t = 1 into the expression:

a = 6 * [(1/23) - (1/23)e^(-21)] - 4 * [(1/6) - (1/6)e^(-4)]

b = 6 * [(1/23) - (1/23)e^(-21)] - 4 * [(1/6) - (1/6)e^(-4)]

To compute the output of the CT LTI system with the given impulse response and input, we can convolve the input function with the impulse response.

Given:

Impulse response h(t) = (3e^(-21t) - 2e^(-4t))u(t)

Input x(t) = 2e^(-2t) + u(t)

Using the convolution integral formula:

y(t) = ∫[x(τ) * h(t-τ)] dτ

Substituting the given values:

y(t) = ∫[(2e^(-2τ) + u(τ)) * (3e^(-21(t-τ)) - 2e^(-4(t-τ)))] dτ

Since the integration limits are from 0 to t, we can split the integral into two parts for convenience:

y(t) = ∫[2e^(-2τ) * (3e^(-21(t-τ)) - 2e^(-4(t-τ)))] dτ + ∫[u(τ) * (3e^(-21(t-τ)) - 2e^(-4(t-τ)))] dτ

The first integral can be simplified as follows:

∫[2e^(-2τ) * (3e^(-21(t-τ)) - 2e^(-4(t-τ)))] dτ

= 6 ∫[e^(-23τ + 2t)] dτ - 4 ∫[e^(-6τ + 2t)] dτ

Integrating both terms gives:

6 * [(-1/23)e^(-23τ + 2t)] - 4 * [(-1/6)e^(-6τ + 2t)]

Evaluating the integral at the limits 0 to t, we get:

6 * [(-1/23)e^(-23t + 2t) + (1/23)] - 4 * [(-1/6)e^(-6t + 2t) + (1/6)]

Simplifying further:

6 * [(-1/23)e^(-21t) + (1/23)] - 4 * [(-1/6)e^(-4t) + (1/6)]

Rearranging terms:

6 * [(1/23) - (1/23)e^(-21t)] - 4 * [(1/6) - (1/6)e^(-4t)]

Finally, we can determine the output at t = 1 by substituting t = 1 into the expression:

a = 6 * [(1/23) - (1/23)e^(-21)] - 4 * [(1/6) - (1/6)e^(-4)]

b = 6 * [(1/23) - (1/23)e^(-21)] - 4 * [(1/6) - (1/6)e^(-4)]

Evaluating these expressions gives the specific values for a and b.

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Answer:D

Explanation:

All the options given regarding the hazard communication standard are correct except option D "prepare and post a list of employees who handle hazardous and toxic substances in the workplace".

The main requirements of employers that use hazardous chemicals are:

• ensure that chemicals are properly labelled.

• provide safety data sheets.

• train employees.

• create a written hazard communication program.

It should be noted that preparing and posting a list of employees who handle hazardous and toxic substances in the workplace is incorrect.

Therefore, the correct option is D.

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Answer:

The oxygen hose threads are usually right-handed, whereas acetylene and fuel gas hose threads are left-handed.

According to the question: the Stress in cylinder is 1813 N/mm^2.

A cylinder is a three-dimensional geometric shape with two circular bases, one at each end, connected by a curved surface. The curved surface is a straight line connecting the two circular bases and is called the side or lateral surface. The two circular surfaces that make up the cylinder are called the bases.

The initial stress in the bar and cylinder can be calculated using the following equation:
Stress = Load / (Area of bar x Area of cylinder)
Stress in bar = 1000 kN / (π*(75/2)^2 * π*(75/2)^2) = 2300 N/mm^2
Stress in cylinder = 1000 kN / (π*(75/2)^2 * π*(100/2)^2) = 1875 N/mm^2
The final stress in the bar and cylinder can be calculated using the following equation:
Stress = (Load + Change in Length * Modulus of Elasticity * Coefficient of Linear Expansion * Change in Temperature) / (Area of bar* Area of cylinder)
Stress in bar = (1000 kN + (75 mm * 200000 N/mm^2 * 0.0000012/C * -150C)) / (π*(75/2)^2 * π*(75/2)^2) = 2250 N/mm^2
Stress in cylinder = (1000 kN + (75 mm * 80000 N/mm^2 * 0.000005/C * -150C)) / (π*(75/2)^2 * π*(100/2)^2) = 1813 N/mm^2

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Answer:

False

Explanation:

Flow back to surface

The work done by a 10 HP motor when it raises a 1000 Newton weight at a vertical distance of 5 meters is 5kJ.

Define work. Explain the rate of doing work.

Work is the energy that is moved to or from an item by applying force along a displacement in physics. For a constant force acting in the same direction as the motion, work is easiest expressed as the product of force magnitude and distance traveled.

Since the force transfers one unit of energy for every unit of work it performs, the rate at which work is done and energy is used are equal.

Solution Explained:

Given,

Weight = 1000N and distance = 5m

A/Q, the work here is done in lifting then

Work = (weight) × (distance moved)

         = 1000 X 5

         = 5000Nm or 5000J = 5kJ

Therefore, the work done in lifting a 1000 Newton weight at a vertical distance of 5 meters is 5kJ.

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Answer:

yea

Explanation:

okkudjeheud email and delete the electronic version of this communication

Answer:

What ! you are an Engineer and I am a High school why are You in my feed..!!

Answer:

c

Explanation:

:)

Answer:

but the way is the way but the WAY is not the way

Explanation:

(yoda voice)

Answer:

umm am i supposed to be laughing?

Explanation:

sorryyy idk what yoda sounds like cuz i think star wars is pretty wack, just my opinion tho so dont get offended

A solar thermal collector is the device that converts solar radiation into thermal energy. These collectors are designed to efficiently absorb sunlight and transfer the generated heat to a fluid, usually water or air.

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