Matter is made up of small

Cellulose and Starch substances are composed of the same monomer units, just arranged differently.

Option D is correct.

A monomer is a little particle that responds with a comparative atom to frame a bigger atom. It is the littlest unit in a polymer, which is much of the time a macromolecule with high sub-atomic weight. DNA, RNA, proteins, and carbohydrates are all biological macromolecules made up of monomers.

Some cracks can be successfully repaired with monomer systems. A liquid composed of monomers that will polymerize into a solid is known as a monomer system. The flammability, toxicity, and volatility of suitable monomers vary. They are insoluble in water.

Incomplete question:

Which substances are composed of the same monomer units, just arranged differently?

a. saccharides; glycogen

b. glycogen; chitin

c. cellulose; chitin

d. cellulose; starch

e. starch; sugar

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Answer:

2.13 atm

Explanation:

Answer:

Explanation:

The same. The force down (the weight of the barbells) is counter balanced by the weight up ( a person holding the barbells). A little later on, you are going to draw force diagrams showing that these two forces are drawn acting in opposite directions.

You can satisfy yourself by drawing a box and putting 1 arrow pointing up on the bottom and labeling it 756 up and another arrow on the top of the box pointing down and labeling it 756. They balance.

The correct answer is C. 241 g. The balanced equation is Fe3O4 + 8H2 → 3Fe + 4H2O. Therefore, 750 g of Fe would produce 750/3 = 250 g of H2O, which is 241 g when rounded to the nearest whole number.

can you give me the b mark?

Answer:

C, number of protons and neutrons

poste en français s’il vous plaît

Answer:

Be careful, your chemistry teacher knows that you posted this question and he bookmarked this page!

Explanation:

From an online cheimstry teacher.

The general structure of a carboxylic acid is shown by option D.

In organic chemistry, a carboxylic acid is an organic acid that consists of a carboxyl group connected to an R-group. the overall components of carboxylic acid are R−COOH or R−CO₂H, with R referring to the alkyl, alkenyl, aryl, or other institution. Carboxylic acids arise broadly.

A carboxylic acid is a natural compound that incorporates a carboxyl group (C(=O)OH). the general formulation of a carboxylic acid is R–COOH, with R referring to the relaxation of the molecule. A carboxylic acid may be the concept of a mixture between functional corporations: an alcohol institution, related to hydrogen certain to oxygen, which attaches to a carbonyl institution, involving a carbon double sure to oxygen.

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Answer:

pH = 4

Explanation:

Given that,

The concentration of [H⁺] is \(10^{-4}\ M\)

We need to find the pH of the solution. We know that,

\(pH=-log[H^+]\)

Also,

HNO3 → H+ + NO-3

Put all the values,

\(pH=-log[1\times 10^{-4}]\\\\pH=4\)

So, the pH of the solution is equal to 4.

Answer:

The answer is 4778.4 cm (cubed)

Explanation:

V = (πr(squared)) x (h/3)

V = (π x 13(squared)) x (27/3)

V = 530.9291585 x 9

V = 4778.4

16.95g is the mass of ethanol (C2H60) that are required to produce 1,000 kJ during boiling? The heat of vaporization of ethanol is 38.6 kJ / mole.

The most fundamental characteristic of matter is mass, which is one of the basic quantities in physics. Mass is a term used to describe how much matter is there in a body. The kilogramme (kg) is the international standard of mass. A nuclear reaction, for instance, results in the total weight of the substance being reduced as a tiny quantity of matter is transformed into a very large amount of energy.

moles of ethanol = 38.6/  1,000=0.368moles

molecular weight of ethanol =46.07g/mol

mass = 0.368×46.07

         = 16.95g

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Explanation:

weight= mass* 9.8N

100 kg mass weighs about 980 Newtons on Earth.

The percent by mass of acetic acid in the vinegar is 2.33%.

Below are the steps to solve the given problem using the data table given below:

Step 1: Calculate the mass of the vinegar. Given,Mass of flask and vinegar solution- 25.17gMass of flask- 15.12gMass of vinegar solution = Mass of flask and vinegar solution - Mass of flask= 25.17 g - 15.12 g= 10.05 g

Step 2: Calculate the moles of NaOH used in the titration.Molarity of NaOH solution is 0.1 M.Moles of NaOH = Molarity × Volume of NaOH usedMoles of NaOH = 0.1 M × 39.00 mL (since the initial volume of NaOH is 0.00 mL)Moles of NaOH = 0.0039 moles

Step 3: Determine the moles of acetic acid used in the reaction.The balanced chemical equation for the reaction between NaOH and acetic acid (the main component of vinegar) is given below:CH3COOH + NaOH → CH3COONa + H2OMoles of NaOH = Moles of CH3COOH (since they react in a 1:1 ratio)Moles of CH3COOH = 0.0039 moles

Step 4: Calculate the mass of acetic acid used in the reaction.Molar mass of acetic acid is 60.05 g/mol.Mass of CH3COOH = Moles of CH3COOH × Molar mass of CH3COOH= 0.0039 moles × 60.05 g/mol= 0.234 gStep 5: Calculate the percent by mass of acetic acid in the vinegar.Percent by mass of acetic acid = (Mass of CH3COOH / Mass of vinegar solution) × 100%= (0.234 g / 10.05 g) × 100%= 2.33%.

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Answer:

Im pretty sure you use mass

Explanation:

Answer:

Los químicos eligen definir la AMU como 1/16 de la masa promedio de un átomo de oxígeno que se encuentra en la naturaleza; es decir, el promedio de las masas de los isótopos conocidos, ponderado por su abundancia natural. Los físicos, por otro lado, lo definieron como 1/16 de la masa de un átomo del isótopo oxígeno-16 (16O).

Answer:

Mass and speed

Explanation:

Mass and speed determine the amount of kinetic energy an object has. Mass is an intrinsic property of a body.

Mass refers to an intrinsic property of a body. It was traditionally believed to be related to the quantity of matter in a physical body, until the discovery of the atom and particle physics. It was found that different atoms and different elementary particles, theoretically with the same amount of matter, have nonetheless different masses.

Mass in modern physics has multiple definitions which are conceptually distinct, but physically equivalent. Mass can be experimentally defined as a measure of the body's inertia, meaning the resistance to acceleration when a net force is applied. The object's mass also determines the strength of its gravitational attraction to other bodies. The SI base unit of mass is the kilogram.

In physics, mass is not the same as weight, even though mass is often determined by measuring the object's weight using a spring scale.

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If a cell culture has 3 x 105 cells per ml , and the culture flasks hold 75 ml of culture each and you have 12 flasks, The bond between K⁺ and Cl⁻ ions is an ionic bond.

The main contact that takes place in ionic compounds is called ionic bonding, and it involves the electrostatic attraction between two atoms or ions with dramatically differing electronegativities. Along with covalent and metallic bonds, it is one of the most prevalent types of bonds. Ions are atoms, or collections of atoms, that have an electrical charge. Ions with a negative charge are produced by gaining electrons in atoms (called anions). Ions with a positive charge are created when atoms lose their electrons (called cations).

Electrovalence, as opposed to covalence, is the name for this transfer of electrons. The cation is a metal atom in the most straightforward scenario, while the anion is a nonmetal atom, however these ions can have more complex chemical compositions.

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The solubility of Ag₂O in a solution buffered at pH 10.50 is approximately 1.46 x 10⁻⁴ M.

The solubility of silver oxide (Ag₂O) in a solution buffered at pH 10.50 depends on the specific buffer used, as well as the temperature and pressure of the system. However, we can make some general predictions based on the solubility product constant (Ksp) of silver oxide and the pH of the buffer.

At pH 10.50, the solution is basic. The basicity will cause the silver oxide to hydrolyze, which means it will react with water to form a silver hydroxide compound. The balanced chemical equation for this reaction is; Ag₂O + H₂O → 2AgOH

The solubility of Ag₂O will then depend on the solubility of AgOH, which has its own Ksp value. The Ksp of AgOH is 1.5 x 10⁻⁸ at 25°C.

If we assume that the hydrolysis reaction has reached equilibrium, we can use the Ksp of AgOH to calculate the solubility of Ag₂O. At equilibrium, the product of the concentrations of the silver and hydroxide ions is equal to Ksp.

[Ag⁺][OH⁻]² = Ksp

Since the hydrolysis reaction produces two moles of AgOH for every mole of Ag₂O, we can write the expression for Ksp in terms of the solubility of Ag₂O, x;

(2x)[OH⁻]² = Ksp

We also know that at pH 10.50, the concentration of hydroxide ions ([OH⁻]) is 3.16 x 10⁻⁴ M. Substituting these values into the expression for Ksp, we can solve for x;

(2x)(3.16 x 10⁻⁴)² = 1.5 x 10⁻⁸

x = 1.46 x 10⁻⁴

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Three common naturally radioactive elements are uranium, thorium, and radium.

These elements undergo radioactive decay, emitting radiation in the form of alpha, beta, or gamma particles. Radioactive decay is the process by which an unstable atomic nucleus loses energy by radiation. A material containing unstable nuclei is considered radioactive. Three of the most common types of decay are alpha decay, beta decay, and gamma decay, all of which involve emitting one or more particles.

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Three common naturally radioactive elements are uranium, potassium, and carbon-14.

Radioactivity is a phenomenon in which certain unstable atoms undergo spontaneous nuclear decay and emit radiation in the form of particles or waves. Many elements found in nature are naturally radioactive, meaning they contain unstable isotopes that undergo radioactive decay.

Three common naturally occurring radioactive elements are:

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Full Question: "Some elements are naturally radioactive. Can you list 3 common ones?"

The molecule H₁₂O₆ does not exist in nature. The formula H₁₂O₆ suggests the presence of 12 hydrogen atoms and 6 oxygen atoms.

However, such a configuration is highly unstable and does not conform to the principles of chemical bonding and stability. In a typical molecule of water (H₂O), two hydrogen atoms are bonded to one oxygen atom. The Lewis structure for water would represent this bonding arrangement. Each hydrogen atom contributes one valence electron, and oxygen contributes six valence electrons.

The Lewis structure for water would show two lines (representing covalent bonds) connecting the oxygen atom to each hydrogen atom. Additionally, the oxygen atom would have two lone pairs of electrons (represented by dots) surrounding it. It is important to note that the Lewis structure represents the valence electron arrangement in a molecule and provides insight into its bonding and geometry.

However, the Lewis structure alone may not capture the full 3D shape and molecular properties. In the case of H₁₂O₆, the presence of 12 hydrogen atoms and 6 oxygen atoms is highly unlikely due to the unfavorable electron configuration and excessive charge repulsion.

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The pH of a 0.1 M solution of ethylamine is approximately 3.30.

To determine the pH of a 0.1 M solution of ethylamine, we need to consider the acid-base equilibrium of ethylamine (\(C_2H_5NH_2\)) and its conjugate acid, ethyl ammonium ion ( \(C_2H_5NH_3^+\) ).

The dissociation reaction is as follows:

\(C_2H_5NH_2} + {H_2O} \rightleftharpoons{C_2H_5NH_3}^+ + {OH}^-\)

The pKa value of ethyl ammonium ion is given as 10.70. This means that at equilibrium, the concentration of \(C_2H_5NH_3^+\) will be equal to the concentration of \(OH^-\).

Since we have a 0.1 M solution of ethylamine, the initial concentration of \(C_2H_5NH_2\)is also 0.1 M.

Let's denote the concentration of \(C_2H_5NH_3^+\) as [ \(C_2H_5NH_3^+\)] and the concentration of \(OH^-\) as [\(OH^-\)]. At equilibrium, these concentrations will be equal.

Since ethylamine is a weak base, we can assume that the concentration of \(OH^-\) formed from the dissociation of water will be negligible compared to the concentration of \(OH^-\) formed from the ionization of ethylamine.

Therefore, we can approximate the concentration of \(OH^-\) as [\(OH^-\)] = [ \(C_2H_5NH_3^+\)].

Now, using the equation for the pKa, we can calculate the concentration of [ \(C_2H_5NH_3^+\) ]:

pKa = -log10([ \(C_2H_5NH_3^+\)]/[(\(C_2H_5NH_2\))])

Rearranging the equation, we get:

[ \(C_2H_5NH_3^+\)] = [(\(C_2H_5NH_2\))] * \(10^{-pKa}\)

Substituting the values:

[ \(C_2H_5NH_3^+\)] = \(0.1 M * 10^{-10.70}\)

Calculating this, we find:

[ \(C_2H_5NH_3^+\)] \(\approx 1.97 * 10^-{11} M\)

Since the concentration of [\(OH^-\)] is approximately equal to the concentration of [ \(C_2H_5NH_3^+\)], we can use the equation for pOH to find the pOH:

pOH = -log10([\(OH^-\)]) = -log10([ \(C_2H_5NH_3^+\)) \(\approx -log10(1.97 * 10^{-11})\)

Calculating this, we get:

pOH \(\approx\) 10.70

Finally, we can find the pH using the equation:

pH = 14 - pOH = 14 - 10.70 \(\approx\) 3.30

Therefore, the pH of a 0.1 M solution of ethylamine is approximately 3.30.

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To determine the pKb1 of CO32-, we can use the relationship between pKa and pKb for conjugate acid-base pairs:

pKa + pKb = pKw

where pKw is the ionization constant of water, which is approximately 14. Therefore, we can rearrange the equation to solve for pKb:

The pKb value represents the negative logarithm of the equilibrium constant (Kb) for the reaction of a base with water. In this case, we are interested in the equilibrium reaction between CO32- and water, which can be represented as CO32- + H2O ⇌ HCO3- + OH-.

By utilizing the relationship pKa + pKb = pKw, we can rearrange the equation to solve for pKb. Given that pKa1 of H2CO3 is 6.35, we subtract this value from pKw (approximately 14) to obtain pKb1

pKb = pKw - pKa

pKb1 = 14 - 6.35 = 7.65

Since none of the given answer choices matches the calculated value, it seems there might be an error or omission in the available options. Please double-check the answer choices provided or refer to additional information to obtain the correct pKb1 value for CO32-.

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A Bronsted-Lowry base is defined as a substance that C. acts as a proton acceptor.

This concept focuses on the transfer of protons (H+) in a chemical reaction. When a Brønsted-Lowry base is placed in water (H2O), it accepts a proton from a water molecule, forming a hydroxide ion (OH-) and increasing the concentration of hydroxide ions in the solution. This process distinguishes the Brønsted-Lowry base from a Brønsted-Lowry acid, which acts as a proton donor.

In a typical acid-base reaction, a Brønsted-Lowry base interacts with a Brønsted-Lowry acid, resulting in the transfer of a proton from the acid to the base. This process generates a conjugate acid and a conjugate base. The conjugate acid is the product formed when the base gains a proton, while the conjugate base results from the acid losing a proton. This proton transfer helps maintain the balance of H+ and OH- ions in the solution.

In summary, the key characteristic of a Brønsted-Lowry base is its ability to act as a proton acceptor, which increase in the concentration of hydroxide ions (OH-) when placed in water. This definition provides a framework for understanding the behavior of bases in acid-base reactions and their role in maintaining the equilibrium of H+ and OH- ions in a solution. Therefore the correct option C

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Answer:

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

\(n = \frac{N}{L} \\\)

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

\(n = \frac{3.01 \times {10}^{23} }{6.02 \times {10}^{23} } = \frac{3.01}{6.02} = 0.5 \\ \)

We have the final answer as

Hope this helps you

The mass of 1 mole of raindrops is approximately 0.050 g, and there are approximately 1.42 ×\(10^{25}\) moles of raindrops in the Pacific Ocean.

1. Mass of 1 mole of raindrops:

Given that the mass of the raindrop is 50 mg (milligrams), we need to convert it to grams before calculating the mass of 1 mole.

1 mg = 1 × \(10^{-3}\) g

50 mg = 50 × \(10^{-3}\)g = 0.050 g

The molar mass of a substance is numerically equal to its atomic or molecular weight. Therefore, the mass of 1 mole of raindrops is 0.050 g.

2. Number of moles of raindrops in the Pacific Ocean:

Given that the mass of the Pacific Ocean is 7.08 × \(10^{20}\) kg, we need to convert it to grams before calculating the number of moles.

1 kg = \(10^3\) g

7.08 × \(10^{20}\) kg = 7.08 ×\(10^{23}\) g

Now, we can calculate the number of moles of raindrops:

Number of moles = Mass / Molar mass

Number of moles = (7.08 ×\(10^{23}\) g) / (0.050 g)

Number of moles ≈ 1.42 × \(10^{25}\) moles (rounded to 2 significant digits)

Therefore, the mass of 1 mole of raindrops is approximately 0.050 g, and there are approximately 1.42 × \(10^{25}\) moles of raindrops in the Pacific Ocean.

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A film inside a box can be exposed by beta particles but not alpha particles due to their different penetration capabilities

Alpha particles are much larger and heavier than beta particles, which means that they cannot penetrate through materials as easily as beta particles.

When a film is kept in a box, the box acts as a shield that blocks alpha particles from reaching the film, as the particles cannot pass through the material of the box. However, beta particles are smaller and have less mass, which makes them more capable of passing through materials. Therefore, if there is a source of beta particles outside the box, they can penetrate through the material of the box and reach the film, potentially exposing it.

In summary, the ability of particles to penetrate through materials is dependent on their size and mass, with alpha particles being too large to penetrate through the box and beta particles being small enough to pass through it.

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The galvanic cell design involves the reduction of hydrogen ions to hydrogen gas at the cathode and the oxidation of hydrogen gas to hydrogen ions at the anode, resulting in a transfer of electrons and the overall reaction of 2H₂O + H₂ → 2H⁺ + 2OH⁻ + H₂.

The two half-reactions provided are:

1. 2H₂O → 2H⁺ + 2e⁻ (reduction half-reaction)

2. H₂ → 2H⁺ + 2e⁻ (oxidation half-reaction)

To design a galvanic cell, we need to combine these half-reactions in such a way that the reduction and oxidation reactions occur separately. This can be achieved by connecting the two half-cells with a salt bridge or a porous membrane.

In this case, the reduction half-reaction involves the reduction of water (H₂O) to hydrogen gas (H₂) by gaining two electrons (2e⁻). The oxidation half-reaction involves the oxidation of hydrogen gas (H₂) to hydronium ions (H⁺) by losing two electrons (2e⁻).

To construct the galvanic cell, we would typically represent the anode (oxidation) and cathode (reduction) compartments. The anode is where oxidation occurs, and the cathode is where reduction occurs. The half-cell notation for each half-reaction would look like this:

Anode (oxidation half-reaction): H₂ → 2H⁺ + 2e⁻

Cathode (reduction half-reaction): 2H₂O + 2e⁻ → 2H₂ + 2OH⁻

Overall, the balanced reaction of the galvanic cell would be:

2H₂O + H₂ → 2H⁺ + 2OH⁻ + H₂

This reaction represents the transfer of electrons from the anode to the cathode, with hydrogen ions (H⁺) being reduced to form hydrogen gas (H₂) at the cathode, and hydrogen gas (H₂) being oxidized to form hydrogen ions (H⁺) at the anode.

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Answer:

3 × 10¯¹⁰

Explanation:

9×10² ÷ 3×10¹²

The above expression can be evaluated as follow:

9×10² ÷ 3×10¹²

Recall:

3² = 9

3¹ = 3

Therefore,

9×10² ÷ 3×10¹² = 3²×10² ÷ 3¹×10¹²

Recall:

y^m ÷ y^n = y^(m – n)

Therefore,

3²×10² ÷ 3×10¹² = 3²¯¹ × 10²¯¹²

= 3¹ × 10¯¹⁰

Recall:

y¹ = y

Therefore,

3¹ × 10¯¹⁰ = 3 × 10¯¹⁰

Therefore,

9×10² ÷ 3×10¹² = 3 × 10¯¹⁰