Matthew has a points card for a movie theater. He receives 50 rewards points just for signing up. He earns 8.5 points for each visit to the movie theater. He needs at least 185 points for a free movie ticket

Which inequality can be used to determine v, the minimum number of visits Matthew needs to earn his first free movie ticket?

If you go twice as fast, your stopping distance will increase by four times (option C).

This relationship is based on the laws of physics and the principles of motion.

When an object is in motion, its stopping distance is influenced by its initial speed, reaction time, and braking capabilities. The stopping distance consists of two components: the thinking distance (the distance traveled during the reaction time) and the braking distance (the distance needed to bring the object to a complete stop).

According to the laws of physics, the braking distance is directly proportional to the square of the initial speed. This means that if you double your speed, the braking distance will increase by a factor of four. In other words, going twice as fast will require four times the distance to come to a stop.

It is important to note that this relationship assumes other factors, such as road conditions and braking efficiency, remain constant. However, in real-world scenarios, these factors may vary and can affect the stopping distance to some extent.

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Answer: Well you have to see on the number that is close to the decimal point

Step-by-step explanation:

0.2438

0.4485

0.8641

3.2527

17.9926

Answer:

ED = 57 , AB = 19

Step-by-step explanation:

the midsegment FC is half the sum of the parallel bases , that is

\(\frac{AB+ED}{2}\) = FC

\(\frac{4x+3+18x-15}{2}\) = 38 ( multiply both sides by 2 )

22x - 12 = 76 ( add 12 to both sides )

22x = 88 ( divide both side by 22 )

x = 4

then

ED = 18x - 15 = 18(4) - 15 = 72 - 15 = 57

AB = 4x + 3 = 4(4) + 3 = 16 + 3 = 19

The test statistic is at α = 0.10 we have sufficient evidence that means weight is given by μ = 132 lb.

What is p-value?

The p-value, used in null-hypothesis significance testing, represents the likelihood that the test findings will be at least as extreme as the result actually observed, presuming that the null hypothesis is true.

As given,

State the hypothesis,

Ha: μ = 132

Ha: μ ≠ 132 (two failed test)

Test satisfies:

As σ is unknown we will use t-test satisfies

t = (x - μ)/(s/√n)

Substitute values,

t = (137 - 132)/(14.2/√20)

t = 1.57

t satisfies is 1.57.

Critical values,

P(t < tc) = P(t < tc) = 0.05

using t table at df = 19

tc = ±1.729

So value is tc = (-1.729, 1.729)

P-value:

P(t > ItstatI) = p-value

P(t > I1.57I) = p-value

Using t-table

p-value = 0.1329

given

α = 0.10

So, p-value < α

Do not reject Null hypothesis.

Conclusion:

At α = 0.10 we have sufficient evidence that means weight is given by μ = 132 lb.

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Answer:

\(\frac{1}{3} (n+4)\)

That is what the expression would be

Answer:

Step-by-step explanation:

English translation:

If the quality control manager wants to estimate the average life of lamps with 20 hours, with a confidence level of 95% and an error of 10% is assumed. What is the sample size?

There are different kinds of math problem. There will be 11 rats in sewer #1.

The term  word problems is known to be problems that are associated with a story, math, etc. They are known to often vary in terms of technicality.

Lets take

sewer #1 = a

sewer #2 = b

sewer #3 = c

Note that   A=B-9

So then you would have:

A=B-9

B=C- 5

A+B+C=56

Then you have to do a substitution so as to find C:

(B- 9) + (C-5) + C = 56

{ (C- 5)-9} + (C-5) + C = 56

3C - 19 = 56

3C = 75

B = C- 5

B = 25 - 5

Therefore, B = 20

A = B - 9

= 25 - 9

=11

Therefore, there are are 11 rats in sewer #1

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The visitor data is best modeled by a quadratic function, and the state park management should plan for more than 400 visitors next year.

To do this, we simply plot the points on a graph.

See attachment for the graph that represents the table.

From the attached graph, we can see that the points on the graph follows an approximately quadratic path

Hence, the visitor data is best modeled by a quadratic function

Also, the state park management should plan for more than 400 visitors next year.

This is so because the range of a quadratic function is the set of all real numbers.

This means that the table can accept a value of 400 (or greater) as one of its data points

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Answer:

Step-by-step explanation:

Charlemagne son died in Aisa he was shot

Answer:

3/25

Step-by-step explanation:

0.12 multiplied by 100 equals 12

which means 12/100 is 0.12

now simplify

6/50

3/25

Solving for q will give us the optimal quantity that maximizes the profit,  a function that gives the total profit earned can be written as:

Profit(q) = (Revenue per item - Cost per item) * q

Assuming that the revenue and cost are functions of the quantity sold (q), the total profit can be calculated as follows:

Profit(q) = Revenue(q) - Cost(q)

To find the quantity which maximizes the profit, we can take the derivative of the profit function with respect to q and set it equal to zero, and then solve for q:

Profit'(q) = Revenue'(q) - Cost'(q) = 0

Solving for q will give us the quantity that maximizes the profit. However, without knowing the specific forms of the revenue and cost functions, we cannot write a specific profit function or find the quantity that maximizes the profit.

In general, the profit function can be written as:

Profit(q) = (Revenue per item - Cost per item) * q

where the revenue per item and cost per item are functions of q. To find the quantity that maximizes the profit, we need to differentiate the profit function with respect to q and set it equal to zero:

Profit'(q) = Revenue'(q) - Cost'(q) = 0

Solving for q will give us the optimal quantity that maximizes the profit.

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Answer:

1 the case is xy 12 2. is h= 4x=8

Step-by-step explanation:

i dont know im just 11 in middle school!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Your answer: d. The interaction (called the A + B interaction). The interaction evaluates mean differences between treatment conditions that are not predicted from the overall main effects from factor A or factor B.

The option that is not one of the hypothesis tests used in two-factor ANOVA is d. The interaction (called the A + B interaction). The correct term for the interaction in two-factor ANOVA is A × B interaction, which evaluates mean differences between treatment conditions that are not predicted from the overall main effects from factor A or factor B. The other two hypothesis tests in two-factor ANOVA are the main effect of factor A (evaluating mean differences between rows) and the main effect of factor B (evaluating mean differences between columns). In two-factor ANOVA, the matrix is used to organize the data and conduct the statistical analysis.
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Answer:

1,

Step-by-step explanation:

now z also a dk4k ak4 smka 4ml 4 LL

Answer:

Original Patio:

-perimeter - 36 feet

-area - 80 square feet

New Patio:

-perimeter - 40 feet

-area - 96 square feet

The standard deviation of the sampling distribution of sample means, based on samples of the amounts of weight lost by 72 people on this diet, is approximately 0.695 pounds.

To calculate the standard deviation of the sampling distribution of sample means, we need to use the formula for the standard deviation of a sample mean. This formula states that the standard deviation of the sampling distribution (σ) is equal to the standard deviation of the population (σ) divided by the square root of the sample size (n).

Given that the population standard deviation (σ) is 5.9 pounds and the sample size (n) is 72, we can plug these values into the formula:

Standard Deviation of the Sampling Distribution (σ) = σ / √n

σ = 5.9 pounds

n = 72

Substituting these values, we get:

Standard Deviation of the Sampling Distribution (σ) = 5.9 / √72

To find the standard deviation of the sampling distribution, we need to evaluate the square root of 72. Using a calculator or mathematical software, we find that √72 is approximately 8.49.

Now, let's calculate the standard deviation of the sampling distribution:

Standard Deviation of the Sampling Distribution (σ) = 5.9 / 8.49 ≈ 0.695 pounds (rounded to two decimal places)

Therefore, the standard deviation of the sampling distribution of sample means, based on samples of the amounts of weight lost by 72 people on this diet, is approximately 0.695 pounds.

This value represents the average amount of variation or dispersion in the means of different samples taken from the population. It indicates how much the sample means are likely to deviate from the population mean.

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Answer:

3 5/18 cups of oatmeal are left in the container.

Step-by-step explanation:

4/9 times 5 = 20/9

5 1/2 = 11/2

11/2 - 20/9 = 99/18 - 40/18

= 59/18

= 3 5/18

The distance in the east direction Mr. Jackamonis after Ms Follis walks 5 feet directly north and the distance between them is 13 feet, obtained using Pythagorean Theorem is 12 feet

Pythagorean Theorem states that the square of the length of the hypotenuse side of a right triangle is equivalent to the sum of the squares of the lengths of the other two sides of the right triangle.

Let a represent the length of the hypotenuse side, and let b and c represent the lengths of the other two sides, then according to the Pythagorean Theorem, we get;

a² = b² + c²

The direction Ms. Follis walks = 5 feet directly north

The direction Mr. Jackamonis walks = Directly east

The distance between Ms. Follis and Mr. Jackamonis = 13 feet apart

The distance Mr. Jackamonis walks, d, can  be found using Pythagorean Theorem as follows;

13² = 5² + d²

Therefore;

d² = 13² - 5² = 144

d = √(144) = 12

d = ± 12

Distances are measured using natural numbers, therefore;

d = 12 feet

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Answer:

Given that certificate of deposits earns 0.75% interest every three months, the value of $25,000 after 8 years will be:

A=P(1+r/100)^nt

where:

A=amount

P=principle

r=rate

t=time

n=number of terms

thus:

from the infomation

$25000, r=0.75%, t=8 years, n=12/3=4

thus

A=25000(1+0.0075/100)^(4*8)

A=25000(1.0075)^32

A=$3175.28

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

Answer:

width is 9 length is 12 :)

Step-by-step explanation:

I'm doing this stuff rn

Answer: $7.65 for a dozen/12

Step-by-step explanation: 2.55 x 3

Solution :

Initial population, P = 752,000 .

Rate of decrease, r = 1.4 % .

Now, population decrease in 1st year :

\(P_1 = P( 1 - 0.014 )\)

Also, population decrease in 2nd year :

\(P_2 = P_1( 1 -0.014 )\\\\P_2 = P( 1 - 0.014)^2\)

Similarly for each next x year, population will be :

\(P_x = P( 1-0.014)^x\)

Therefore, population after x years is given by :

\(P_x = 752000 ( 1-0.014)^x\)

To find the perimeter of triangle ARC, we need to determine the lengths of its sides based on the given information.

From the given information, we know that BD = √3. However, we need additional information or measurements to calculate the lengths of the sides of triangle ARC. Without more information, we cannot determine the specific lengths of AR and RC, which are crucial for finding the perimeter.

Therefore, without additional details about the relationship between triangle ABC and triangle ARC or the measurements of other sides or angles, we cannot accurately determine the perimeter of triangle ARC.

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We find that the percentile is approximately 79.97%. This means that the bag of nuts weighing 15.1 ounces falls in the top 20.03% of all bags of nuts in terms of weight.

To find the percentile for the bag of nuts that weighed 15.1 ounces, we can use the z-score formula and the standard normal distribution. The z-score measures the number of standard deviations an observation is from the mean.

First, we calculate the z-score using the formula:

z = (x - μ) / σ

where x is the observed value, μ is the mean, and σ is the standard deviation. In this case, x = 15.1, μ = 14.6, and σ = 0.6.

z = (15.1 - 14.6) / 0.6 = 0.83

Next, we find the percentile corresponding to the z-score using a standard normal distribution table or a calculator. The percentile value represents the percentage of values below the given observation.

Looking up the z-score of 0.83 in the standard normal distribution table, we find that the percentile is approximately 79.97%. This means that the bag of nuts weighing 15.1 ounces falls in the top 20.03% of all bags of nuts in terms of weight.

In other words, the bag of nuts that weighed 15.1 ounces is heavier than approximately 79.97% of the bags in the sample. It is considered relatively high in weight compared to the other bags, as it is in the upper 20.03 percentile. This information can be useful for quality control purposes, as it indicates that the bag of nuts has a higher weight than most of the bags produced, possibly exceeding the specified target weight of 14.5 ounces.

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The length, breadth and height will be 78 cm, 78cm, 78cm each.

let consider the length = l

breadth = b

height = h

we are provided that

l + b + h = 234cm .......(1)

Also we have to maximize the volume , provided length is equal to breadth

∴ eqn (1) becomes

2b + h = 234

h = 234 - 2b

also ,

volume(v) = lbh

v = b²(234 - 2b)

v = b²234 - 2b³

now to maximize the volume we take the first derivative of the volume wrt 'b' and place it equal to zero. ( lagrange method )

i.e. d( v)/db = 0

∴  468b - 6b² = 0

 6b² - 468b = 0

6b( b - 78 ) = 0

∴  b = 78 cm

now as length = breadth

l = b = 78 cm

also putting this value in eqn (1)

h = 234 - 2b

h =  78 cm

So , the dimensions will be equal and will be 78cm , 78cm, 78cm each .

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For the inductive step, assuming the statement holds for a graph with n components, where n < k, we consider a graph with (n + 1) components. By removing one vertex from one of the components, we create a new graph with k - 1 vertices and n components. By the induction hypothesis, this new graph has at least (k - 1) - n edges. Adding back the removed vertex and connecting it to the n components creates at least one new edge in each component. Therefore, the total number of edges in the original graph is at least k - 1.

Thus, by induction, it is proven that if a simple graph has n components, it has at least k - n edges.

To prove the statement by induction, we need to establish a base case and an inductive step.

**Base case:**

When the graph has only one component (n = 1), it means that all k vertices are connected, forming a single connected component. In this case, the number of edges in the graph is maximized, and it can be calculated using the formula for a complete graph with k vertices.

The number of edges in a complete graph with k vertices is given by the formula: E = k(k-1)/2.

Since there is only one component, and it is a complete graph, the number of edges in the graph is E = k(k-1)/2.

Now, let's substitute n = 1 in the statement we need to prove:

"If a simple graph has n components (n = 1), then it has at least k - n edges."

Plugging in the values:

"If a simple graph has 1 component, then it has at least k - 1 edges."

From the base case, we can see that the graph indeed has k - 1 edges when it has only one component.

**Inductive step:**

Assume the statement holds for a graph with n components, where n < k. We will prove that it holds for a graph with (n + 1) components.

Let G be a simple graph with k vertices and (n + 1) components. We can remove one vertex from one of the components to create a new graph G'. The new graph G' will have k - 1 vertices and n components.

By the induction hypothesis, G' has at least (k - 1) - n edges.

Now, let's consider the original graph G. When we add back the vertex we removed, it can be connected to any of the n components in G'. This addition of the vertex creates at least one new edge in each of the n components.

Therefore, the total number of edges in G is at least the number of edges in G' plus the number of new edges added by the vertex. Mathematically, it can be expressed as:

Edges(G) ≥ Edges(G') + n

Since Edges(G') + n = ((k - 1) - n) + n = k - 1, we have:

Edges(G) ≥ k - 1

Hence, we have proved that if a simple graph has n components, it has at least k - n edges.

By the principle of mathematical induction, the statement is true for all values of n such that 1 ≤ n < k.

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