max has 16 1/2 ounces bag of walnuts. she only use 1/4 for making cookies.how many ounces will she use for cookies

Answer:

The interval of the domain over which the function m is negative

will be: (6, ∞)

Step-by-step explanation:

We have to determine the interval of the domain over which the function m is negative.

The x-intercept of the graph is:

at y = 0, x = 6

(0, 6) is the x-intercept.

From the graph, it is clear that at the x-intercept x=6, the graph tends to continue downward towards infinity i.e. (6, ∞) where the graph would be negative as it is heading downwards.

Thus, the interval of the domain over which the function m is negative will be: (6, ∞)

Answer: (6,00)

Step-by-step explanation:

All of the following are security risks associated with the ARES​ system, except​  is (C)  doctors and trainers may be restricted to viewing only partial data.

The security risks associated with the ARES system include the lack of uniform data security procedures, potential misuse of patient data, restricted access for doctors and trainers, and the possibility of patient health data being viewed by competing trainers and other clubs.

However, among these options, the exception is option C, which states that doctors and trainers may be restricted to viewing only partial data.

Option C suggests that doctors and trainers may have limited access to data, viewing only partial information.

This limitation, although it may affect the convenience and efficiency of the system, does not directly pose a security risk. In fact, restricting access to certain data can be seen as a security measure to protect patient privacy and sensitive information. On the other hand, options A, B, D, and E all describe legitimate security risks associated with the ARES system.

These risks involve the lack of standardized data security procedures, the potential misuse of patient data, and unauthorized access to patient health data by competing trainers or other clubs, which can compromise patient confidentiality and raise ethical concerns.

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Answer:

49

Step-by-step explanation:

plug in the value of m.

\(8^{2}\)-15 = 64 - 15 = 49

The expression x^2 + 8x + 3 to complete the square is 16.

The value we need to add in the blank space in the expression x^2 + 8x + 3 to complete the square is 16.

Here's how we can get that value:

Step 1: Divide the coefficient of the x term by 2 and square the result. That is, (8/2)^2 = 16.

Step 2: Add the value obtained in Step 1 to the expression in the blank space. Thus, x^2 + 8x + 3 + 16 = x^2 + 8x + 19.

Now, we have the perfect square trinomial x^2 + 8x + 16, which is the square of (x + 4).

Therefore, we can write x^2 + 8x + 19 as (x + 4)^2 - 3.

Thus, the value we can add in the blank space in the expression x^2 + 8x + 3 to complete the square is 16.

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The probability that at least one washing machine breaks down in the first year of operation is approximately 0.9814 or 98.14%.

To find the probability that at least one washing machine breaks down in the first year of operation, we can use the complement rule and subtract the probability of none of the machines breaking down from 1.

Given that 15% of washing machines break down, and 32 machines are purchased by the laundromat, we can calculate the probability using the binomial distribution.

The probability that a single washing machine breaks down in the first year is 15% or 0.15. Since each machine operates independently, we can treat the breakdown of each machine as a Bernoulli trial.

Let's define success as a machine breaking down and failure as a machine not breaking down. The probability of success is 0.15, and the probability of failure is 1 - 0.15 = 0.85.

To find the probability that none of the machines break down, we use the binomial distribution formula:

P(X = k) = C(n, k) * \(p^k\) * \((1 - p)^{n - k}\)

In this case, we want to calculate the probability that k = 0, i.e., none of the machines break down. The formula becomes:

P(X = 0) = C(32, 0) * \(0.15^0\)* \(0.85^{32}\)

Now, to find the probability that at least one machine breaks down, we subtract the probability of none breaking down from 1:

P(at least one breakdown) = 1 - P(X = 0)

By plugging in the values and performing the calculations, we can find the probability that at least one washing machine breaks down in the first year of operation for the laundromat.

P(X = 0) = C(32, 0) * \(0.15^0\)* \(0.85^{32}\)

= 1 * 1 * \(0.85^{32}\)

≈ 0.0186

P(at least one breakdown) = 1 - P(X = 0)

= 1 - 0.0186

≈ 0.9814

Therefore, the probability that at least one washing machine breaks down in the first year of operation is approximately 0.9814 or 98.14%.

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ccabo de 25 años será la edad del padre tres veces mayor que la edad del hijo.El número es 36.Hay 8 hombres, 16 mujeres y 72 niños.Hay 27 cerdos y 8 pavos

Sea x el número de años transcurridos. La edad del padre será 35 + x y la edad del hijo será 5 + x. La ecuación que representa la situación es: 35 + x = 3(5 + x). Resolviendo la ecuación, tenemos:

35 + x = 15 + 3x

2x = 20

x = 10

Por lo tanto, después de 10 años, la edad del padre será tres veces mayor que la edad del hijo.

Sea x el número desconocido. La ecuación que representa la situación es: 2x - (1/2)x = 54. Resolviendo la ecuación, tenemos:

(4/2)x - (1/2)x = 54

(3/2)x = 54

x = 36

Por lo tanto, el número desconocido es 36.

Sea x el número de hombres. Según la información dada, el número de mujeres es el doble, es decir, 2x, y el número de niños es el triple, es decir, 3(x + 2x) = 9x. La ecuación que representa la situación es: x + 2x + 9x = 96. Resolviendo la ecuación, tenemos:

12x = 96

x = 8

Por lo tanto, hay 8 hombres, 16 mujeres y 72 niños en la reunión.

Sea x el número de cerdos y y el número de pavos. Según la información dada, tenemos las siguientes ecuaciones: x + y = 35 (por el total de cabezas) y 4x + 2y = 116 (por el total de patas). Resolviendo este sistema de ecuaciones, obtenemos:

x + y = 35

4x + 2y = 116

Multiplicamos la primera ecuación por 2:

2x + 2y = 70

Restamos la segunda ecuación de la primera:

2x + 2y - (4x + 2y) = 70 - 116

-2x = -46

x = 23

Sustituyendo el valor de x en la primera ecuación, tenemos:

23 + y = 35

y = 12

Por lo tanto, hay 23 cerdos y 12 pavos en la granja.

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Answer:

20800 dollars

Step-by-step explanation:

15600*(1/0.75)

=20800

the original price was 20800 dollars.

weirdly expensive computer though

TO complete the partial One Way ANOVA table without blocks, we will need to know the original values of the dealership and error degrees of freedom (df) and sum of squares (SS). Since you have not provided the values, the table if you have the necessary information:

1. DEALERSHIP: Keep the original dealership df and SS values, as they won't change in this case.

2. ERROR: Add the original dealership df and SS values to the error df and SS values, since you are removing the blocks from the analysis.

3. TOTAL: The total df and SS values remain the same as in the original RBD ANOVA table.

If you can provide the original values for dealership and error df and SS, I would be happy to help you complete the table.

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Answer:

i think someone can figure this out, but if they cant just say somthing like a or f

Step-by-step explanation:

Answer:

the answer is A.

Step-by-step explanation:

to get the you would use the distributive property to multiple the 4 by the two term in the parentheses.

Answer:

It would be A

Step-by-step explanation:

The Key Skill is: Distribution Property

1) We have the expression 4(6-2x)

2) We have to use distribution property to expand this.

The way distribution property works is that we need to multiply the 6 by the 4 on the outside, and also the -2x by the 4 on the outside.

4 x 6 = 24

4 x -2x = -8x

Therefore, the final expression is 24-8x.  

The only answer that matches this is A.

Hope you understood & have a nice DAY!! :D

The transformation of System A into System B is:

Equation [A2]+ Equation [A 1] → Equation [B 1]"

The correct answer choice is option D

How can we transform System A into System B?

To transform System A into System B as 1 × Equation [A2] + Equation [A1]→ Equation [B1] and 1 × Equation [A2] → Equation [B2].

System A:

-3x + 4y = -23 [A1]

7x - 2y = -5 [A2]

Multiply equation [A2] by 2

14x - 4y = -10

Add the equation to equation [A1]

14x - 4y = -10

-3x + 4y = -23 [A1]

11x = -33 [B1]

Multiply equation [A2] by 1

7x - 2y = -5 ....[B2]

So therefore, it can be deduced from the step-by-step explanation above that System A is ultimately transformed into System B as 1 × Equation [A2] + Equation [A1]→ Equation [B1] and 1 × Equation [A2] → Equation [B2].

The complete image is attached.

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Attached above is the graph of the line passing through the points (2, -6) and (-1,9).

How to plot the graph:

Firstly, we need to locate the first point (2,-6)

That means a point 2 on the x axis and -6 on the y-axis.

Then, next locate the second point (-1,9)

That means a point -1 on the x axis and 9 on the y-axis.

Then lastly, join the two points.

Answer:

Equation= 10+6x=4x-4

Answer= x is -7

Step-by-step explanation:

equations 1, 2, 4, and 5 are consistent and possibly true, while equation 3 is not consistent.

Let's analyze each equation to determine if they are consistent and possibly true:

1. A - B - C = 0

This equation states that the difference between A, B, and C is zero. It is consistent and possibly true if A = B + C.

2. C = -7.15m

This equation states that the value of C is equal to -7.15m. It is consistent and possibly true if C is indeed equal to -7.15m.

3. |A| - |B| = -2.9m

This equation states that the absolute value of A minus the absolute value of B is equal to -2.9m. It is not consistent because the absolute value of a number is always non-negative, so the left-hand side of the equation can never be negative.

4. (42.1m) * \(\hat{x}\) = (3.2m) * \(\hat{y}\)

This equation states that the product of 42.1m and \(\hat{x}\) (unit vector in the x-direction) is equal to the product of 3.2m and \(\hat{y}\) (unit vector in the y-direction). It is consistent and possibly true if the magnitudes of \(\hat{x}\) and \(\hat{y}\) are appropriately related to satisfy this equation.

5. Ay < 0

This equation states that the y-component of vector A is less than zero. It is consistent and possibly true if the y-component of vector A is indeed negative.

In summary, equations 1, 2, 4, and 5 are consistent and possibly true, while equation 3 is not consistent.

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Among the given equations, the consistent and possibly true equations are:

A - B - C = 0 (Equation 1)

C = -7.15m (Equation 2)

Ay < 0 (Equation 5)

Let's analyze each equation to determine which ones are consistent and possibly true:

1. A - B - C = 0:

This equation represents the sum of three variables, A, B, and C, equal to zero. Without any further information about the variables, we cannot determine its consistency or truth.

2. C = -7.15m:

This equation sets the variable C equal to -7.15m. It is consistent and true if the value of C is indeed -7.15m.

3. |A| - |B| = -2.9m:

This equation states the absolute value of A minus the absolute value of B equals -2.9m. However, the absolute value of a quantity is always positive, so it cannot be negative. Therefore, this equation is inconsistent and unlikely to be true.

4. (42.1m)x^ = (3.2m)y^:

This equation equates a scalar quantity, 42.1m, multiplied by the unit vector x^, with a scalar quantity, 3.2m, multiplied by the unit vector y^. Since x^ and y^ are perpendicular unit vectors, it is not possible for them to be equal. Therefore, this equation is inconsistent and unlikely to be true.

5. Ay < 0:

This equation states that the y-component of vector A is less than zero. It is consistent and possibly true if the y-component of A is indeed negative.

Based on the analysis above, the equations that are consistent and possibly true are equation 2 (C = -7.15m) and equation 5 (Ay < 0).

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Therefore, a particular solution to the equation y″ + 6y′ + 8y = 54 is yp = 27/4.

To find a particular solution to the equation y″ + 6y′ + 8y = 54, we can use the method of undetermined coefficients.

First, identify the general form of the particular solution based on the non-homogeneous term: Since the right side of the equation is a constant (54), we can guess that the particular solution will be in the form of yp = A, where A is a constant.

Next, substitute the guess into the equation: The first and second derivatives of yp = A are both 0 (y′ = 0, y″ = 0). So, substituting into the equation, we get 0 + 6(0) + 8A = 54.

Now, solve for the constant A: 8A = 54, so A = 54/8 = 27/4.

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Answer: 17600

Step-by-step explanation: 16000*10% is the same as 16000*0.1, then you get 1600. 16000+ 1600 is 17600

The Economic Order Quantity (EOQ) formula is used to compute the optimal quantity of an inventory to order at any given time. It is calculated by minimizing the cost of ordering and carrying inventory, and it is an important element of supply chain management.

According to the problem given, the following information is given:Demand = 100 bags / weekOrder cost = $55 / orderAnnual holding cost = 25% of costDesired cycle-service level = 92%Lead time = 4 week(s) (20 working days)Standard deviation of weekly demand = 13 bagsCurrent on-hand inventory is 350 bags, with no open orders or backorders.a. To calculate the Economic Order Quantity (EOQ), we need to use the formula:EOQ = √[(2DS)/H],whereD = Demand per periodS = Cost per orderH = Holding cost per unit per period. Substitute the given values,D = 100 bags/weekS = $55/orderH = 25% of cost = 0.25Total cost of inventory = S*D + Q/2*H*DIgnoring Q, the above expression is the annual ordering cost. Since we know the annual cost, we can divide the cost by the number of orders per year to obtain the average cost per order.Substituting the given values in the above formula,

EOQ = √[(2DS)/H] = √[(2*100*55)/0.25] = 420 bags

Sam's optimal order quantity is 420 bags. Hence, the answer to this part is 420.b. To calculate the reorder point (R), we use the formula:R = dL + SS,whereL = Lead timed = Demand per dayS = Standard deviation of demandSubstituting the given values,d = 100 bags/weekL = 4 weeksS = 13 bags/week

R = dL + SS = (100*4) + (1.75*13) = 425 bags

Therefore, the reorder point is 425 bags.c. If the inventory withdrawal of 10 bags has been made, we can calculate the new on-hand inventory using the formula:On-hand inventory = Previous on-hand inventory + Received inventory – Issued inventoryIf there are no open orders,Received inventory = 0Hence,On-hand inventory = 350 + 0 – 10 = 340Since the current on-hand inventory is more than the reorder point, it is not time to reorder. Therefore, the answer to this part is "It is not time to reorder."d. Annual holding cost of the current policy is the product of the holding cost per unit per period and the number of units being held.Annual holding cost =

(350/2) * 0.25 * 55 = $481.25

The annual holding cost is $481.25.Annual ordering cost = Total ordering cost / Number of orders per yearIf we assume 52 weeks in a year,Number of orders per year = 52/4 = 13Total ordering cost = 13 * $55 = $715Annual ordering cost = $715/13 = $55Therefore, the annual ordering cost is $55.

The Economic Order Quantity (EOQ) formula is used to compute the optimal quantity of an inventory to order at any given time. Sam's optimal order quantity is 420 bags. The reorder point is 425 bags. If there is an inventory withdrawal of 10 bags, then it is not time to reorder. The annual holding cost is $481.25. The annual ordering cost is $55. The average time between orders is 4.46 weeks.

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Answer:

38 degrees celsius

Step-by-step explanation:

1.8C+32 = 100.4

INverse property. Subtrat 32 from both sides

1.8c=68.4

divide 1.8 from both sides to isolate x

c=38

The temperature is 38 degrees celsius

The equation "Sixty-four reduced to a number is forty-eight" can be expressed algebraically or as algebra expression as: 64 - x = 48

In this equation, the variable "x" represents the unknown number that we are trying to find. By subtracting "x" from 64, we are reducing the value to 48.

Therefore, it can be translated into an algebraic equation:

64 - x = 48

Solving the equation allows us to determine the value of the variable "x," which represents the number we are looking for. The use of variables in algebraic expressions allows us to generalize problems and find solutions for different scenarios.

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The function that gives the number of tickets bought by dragons fans after w consecutive wins is: t(w)= 200*(1.11)^w

Tickets bought by Dragon fans in one game = 200

For every consecutive win, the tickets increase by a factor of 1.11

Therefore, for the first win, the number of tickets were 200

For the second consecutive win, the number of tickets increased to 200*1.11= 200*(1.11)^1, since after each consecutive win the number of tickets increases by a factor of 1.11

For the third consecutive win, the number of tickets bought by fans increased to 200*1.11*1.11= 200*(1.11)^2

Hence, for w consecutive wins, the function will turn out to be;

t(w)= 200*(1.11)^w

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A:

4 seconds per centimer:

30cms               15 cms

----------------       -------------

2 minutes           1 minute

1 minute= 60 seconds

15 cms                       1cm

-----------------     =     ----------------

60 seconds              4seconds

B: 15 cms per minute

30cms/2minutes

(divide by 2 to get speed for one minute)

15cm/1 minute

Answer:

23cm

Step-by-step explanation:

in this case, you don't have to actually care both the 4 because it is not a side. whoever did that is trying to trick you. now you are left with 7cm,6cm, and 10cm.

10+6+7=23

Answer:

Explanation:

I don't really understand what just happened to my calculator but i searched on goo gle but it's the correct answer..

(;ŏ﹏ŏ)(ㆁωㆁ)

Answer:

85x(500-0.10x)

Step-by-step explanation:

The distribution of the data is typically considered to be skewed to the right if the median is higher than the mean.

So the distribution of the data is typically considered to be skewed to the right if the median is higher than the mean (positively skewed). In other words, the distribution's tail is longer to the right than to the left. Take the following values, for instance, 1, 2, 3, 5, 100, as part of a dataset. This dataset has a mean of 22.2 and a median of 3, with the mean being (1 + 2 + 3 + 5 + 100) / 5 = 22.2. The distribution is positively skewed with a lengthy tail of high values in this instance because the median is significantly lower than the mean. If a few extreme values in the dataset are significantly higher than the remainder of the range, the distribution may be positively skewed.

Therefore, In other words, the distribution's tail is longer to the right than to the left. Take the following values, for instance, 1, 2, 3, 5, 100, as part of a dataset. This dataset has a mean of 22.2 and a median of 3, with the mean being (1 + 2 + 3 + 5 + 100) / 5 = 22.2.

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Answer:

Number of students in 6th grade = 29

Number of boys = 15

Number of girls = 29-15 = 14

Ratio of boys to girls = 15 : 14

Step-by-step explanation:

smchmack me with dat brainliest

Answer:

15:14

Step-by-step explanation:

15 boys

total 29

29-15=14 because the rest of the class would have to be girls

The additive inverse of –2+ 8i will be 2 – 8i. The additive inverse of a digit is the digit that delivers zero when added to it.

The additive inverse of a number is the number that produces zero when added to it. A negative number's additive inverse is positive. The additive inverse of itself is zero.

From the definition;

\(\rm x= 2+ 8i \\\\ \rm x= 2+ 8i + 2-8i \\\\ \rm x= 0\)

Option C gives zero on addition. That's why it is correct.

Hence the additive inverse of –2+ 8i will be 2 – 8i.

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Answer:

The answer is C:

2-8i

Step-by-step explanation:

Edge 2022 :-)

Answer:

The answer would be D

Step-by-step explanation:

To find how many Katie has, you would have to double it ( times by 2 ). Then subtract 3, since Alejandro has three less than twice as many as Katie.

Answer:

the answer is d just did the test got it right

Step-by-step explanation:

Since v is a vector of magnitude 4 and makes angle 30° with the positive x axis, vector v in component form is v = 2√3i + 2j

To find vector v in component form, we need to know what a vector is

A vector is a physical quantity that has both magnitude and direction.

A vector can be resolved into perpendicular components along the x, y and z axis.

Since vector v has a magnitude of 4 making an angle of 30 with the positive x - axis, its x-component is V = (vcos30°)i

= (4cos30°)i

= (4 × √3/2)i

= 2√3i.

The y-component of v is V' = (vsin30°)j

= (4 × sin30°)j

= (4 × 1/2)j

= 2j

So, vector v in component form is v = V + V'

= 2√3i + 2j

So, since v is a vector of magnitude 4 and makes angle 30° with the positive x axis, vector v in component form is v = 2√3i + 2j

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Answer:

2 hours

Step-by-step explanation:

Answer:

About 2.5 hours

Step-by-step explanation:

divide 130 by 52 = 2.5