Mechanic... Mechanical Engineer... What's the difference?
Instructions: Answer the question below with at least TWO complete sentences.

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Answer 1

Answer:

Mechanic: a person who repairs and maintains machinery

Mechanical engineers: design power-producing machines

Explanation:

Related Questions

A venturi meter was fitted in a pipe of 0.1 m diameter where the pressure head was 10 m, and the max flow rate was 10 m³/min. Find the diameter of the throat so that the pressure is always positive.
1. 9.01 m
2. 10 m
3. 0.01 m
4. 0.091 m

Answers

The correct option is 4. 0.091 m. Here's how to find the diameter of the throat so that the pressure is always positive:

A Venturi meter is fitted into a pipeline with a diameter of 0.1 m where the pressure head is 10 m, and the maximum flow rate is 10 m³/min.
We must determine the diameter of the throat so that the pressure is always positive.Diameter of the pipe, D1 = 0.1 mPressure head, H = 10 mMaximum flow rate, Q = 10 m³/min
Let the diameter of the throat be d.Using the formula of continuity,Q = A1V1 = A2V2Q = A1 × (Q/A1) = A2 × (Q/A2)A1/A2 = (V2/V1) = (d/0.1)²H = (P1 - P2)/ρgh = [(P1 - P2)/(ρg)] × 1where ρ is the density of the fluid in kg/m³, and g is the gravitational acceleration= [(P1 - P2)/(ρg)] × A1/A2 = [(P1 - P2)/(ρg)] × (0.1/d)²Since P1 - P2 is always positive, we must choose the value of d that is less than 0.1 m.
Now, we will use the given data to compute the value of d= [(Q/πd²/4) × 4/π] × [(0.1/d)²/2g]d⁴ = (8Q²g)/(π²H²) and d = (8 × 10² × 9.81)/(π² × 10²) = 0.091 m, correct up to two decimal places.
The diameter of the throat so that the pressure is always positive is 0.091 m.

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ex: an electrical firm manufactures light bulbs that have a life span that is approximately normally distributed. the population standard deviation is not known. a sample of 30 bulbs is found to have an average life span of 800 hours and a sample standard deviation of 45 hours.

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The value of pv is 0.101

How to calculate if a random sample of 30 bulbs has an average life of 788 hours ?

Data given and notation

X = 788 represent the average life for the sample

θ = 40 represent the population standard deviation

n = 30 sample size

µ = 800 represent the value that we want to test

α = represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

pv represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to apply a two tailed test.

What are H0 and Ha for this study?

Null hypothesis: µ = 800

Alternative hypothesis :µ ≠ 800

Compute the test statistic

The statistic for this case is given by:

z = X -µo/θ √n

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

z = 788 - 800/40√30 = - 1.64

Give the appropriate conclusion for the test

Since is a one side left tailed test the p value would be:

pv = 2 × P ( z< - 1.64 ) = 0.101

Therefore the value of pv is 0.101

The complete question is : An electrical firm manufactures light bulbs that have a lifetime that is approximately normally distributed with a mean of 800 hours and a standard deviation of 40 hours. Test the hypothesis that μ = 800 hours against the alternative, μ = 800 hours, if a random sample of 30 bulbs has an average life of 788 hours. Use a P-value in your answer.

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What is the basic requirement of measurements?

Answers

The basic requirement of measurements is to have a standard or reference point against which to compare the quantity being measured. This standard or reference point should be well-defined and stable, and the measurement process should be repeatable and consistent. Additionally, it is important to ensure that the measurement equipment is calibrated and in good working condition.

Answer:

The most basic requirement for measurements is the presence of a standard or reference point against which the quantity being measured can be compared. The measurement process should be repeatable and consistent, and the standard or reference point should be well-defined and stable. Furthermore, ensure that the measurement equipment is calibrated and in good working order.

Explanation:

Fog is usually prevalent in industrial areas because of
1. atmospheric stabilization around cities.
2. an abundance of condensation nuclei from combustion products.
3. increased temperatures due to industrial heating.

Answers

An abundance of condensation nuclei from combustion products is the main reason why fog is usually prevalent in industrial areas.

Combustion products such as smoke and particulate matter provide a large number of tiny particles that serve as nuclei for the formation of fog droplets.

The presence of these particles, combined with cool and humid weather conditions, can lead to the formation of thick fog in industrial areas.

Additionally, the urban heat island effect caused by industrial heating can trap moisture close to the ground and contribute to the formation of fog. However, atmospheric stabilization around cities is not a primary cause of fog in industrial areas.

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what is the lighting load on a 120v circuit for six 100w incandescent lights and four fluorescent fixtures with a ballast rating of 1.5a, all operating continuously for 8 hours per day?

Answers

Note that the lighting load on a 120v circuit for six 100w incandescent lights and four fluorescent fixtures with a ballast rating of 1.5a, all operating continuously for 8 hours per day is: 10,560 Watts.

What is Lighting Load?

A building's lighting loads are sometimes referred to in terms of "Lighting Power Density," which is measured in watts per square foot or square meter.

It is to be noted that a single calculation is used to compute lighting load:

W=VA.

Where

W = Watts

V = Volts; and

A = Amps

To determine the total wattage for the fluorescent fixtures we say:

4 fixtures x 1.5 amps x 120 volts = 720 watts

Next, we add the wattages for the incandescent lights and fluorescent fixtures to get the total wattage for the circuit. That is:

(6 x 100watts) + 720 watts
= 600 watts + 720 watts

= 1,320 watts

Thus the Load is 1,320 watts.

If all lighting will operate continuously for 8 hours/day, then:

Daily energy consumption will be:

1320 x 8

= 10,560 Watts.

Thus, the Lighting Load on a 120v circuit for 6 100w incandescent lights and four fluorescent fixtures with a ballast rating of 1.5a Operating at 8 hours per day is 10,560 Watts.

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Point charges of 2μC, 6μC, and 10μC are located at A(4,0,6), B(8,-1,2) and C(3,7,-1), respectively. Find total electric flux density for each point: a. P1(4, -3, 1)

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To find the total electric flux density at point P1(4, -3, 1), calculate the electric field contribution from each point charge (2μC, 6μC, and 10μC) and sum them up.

To find the total electric flux density at point P1(4, -3, 1), we need to calculate the electric field contribution from each point charge (2μC, 6μC, and 10μC). The electric field at a point due to a point charge is given by Coulomb's law. By considering the distance between each point charge and point P1, we can calculate the electric field vectors. Then, by summing up the electric field vectors from each charge, we obtain the total electric field at point P1. The magnitude and direction of this total electric field represent the electric flux density at that point.

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............................

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Answer:

Sorry whats the question

Explanation:

are trains cool because if they are then my dad didn't beat me

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Answer:

I think trains are pretty awesome. There's a train in japan that levitates slightly and runs on magnetism. Pretty amazing. It's super fast too

What are sketches or technical drawings called

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Answer:

Technical drawing, also known as drafting or draughting, is the act and discipline of making detailed drawings. These drawings visually communicate how something works or how it is to be made.

Draughting is another term for sketches and technical drawings.

to produce cooling the refrigerant must

Answers

Answer:

The compressor

Explanation:

to compress the low-pressure dry gas refrigerant from the evaporator and raise its pressure and temperature to that of the condenser, to produce flow around the system.

what type of bit should be used to drill holes in plexiglass

Answers

Conical drill bits should be used to drill holes in plexiglass.

To drill holes in plexiglass, it is recommended to use a **drill bit specifically designed for acrylic or plastics**, such as a **multipurpose or brad-point drill bit**.

Plexiglass, also known as acrylic, is a brittle material that requires careful drilling to avoid cracking or chipping. Standard drill bits, such as those used for metal or wood, are not ideal for drilling plexiglass as they can cause excessive heat buildup and exert too much force, leading to damage.

Multipurpose drill bits or brad-point drill bits have specially designed tips that help reduce the risk of cracking. They often feature a sharper point for easier starting and smooth cutting edges to prevent chipping. These types of drill bits are specifically engineered for drilling into plastics like plexiglass.

When drilling, it is essential to apply light and consistent pressure, use a low drill speed, and ensure the plexiglass is properly supported to minimize vibrations and prevent cracking. Additionally, it is advisable to place a scrap piece of wood or plastic underneath the plexiglass to prevent damage to the surface beneath.

By using a drill bit designed for acrylic or plastics and employing proper drilling techniques, you can effectively and safely drill holes in plexiglass without compromising its integrity.

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1. Discuss how products incorporate aesthetic design and why this appeals to target markets 2. Discuss how the universal design process has impacted engineering design and the impact these expectations will have on the future of product design.

Answers

Explanation:

Remember, to say a product is incorporated with aesthetic design implies that its overall appearance is designed to look beautiful to the eyes of the user/buyer. For example, a clothing company whose target market is mainly focused on women's clothing would need to take into consideration that certain colors like pink, blue, etc are attractive to women more than men. So they'll have to ensure the colors of their clothing are suitable to the needs of their target market.

The Universal Design process involves building products that can be used by a wide range of users at ease. For example, you may ask yourself: Is my product/service easily accesible to those with disabilities?

Other processes include;

Defining who the users (or universe) are of the products. Involve consumers in the design.Follow the existing standards of product designEvaluate and review your universal design methods

Determine the resistance of 3km of copper having a diameter of 0,65mm if the resistivity of copper is 1,7x10^8

Answers

Answer:

Resistance of copper = 1.54 * 10^18 Ohms

Explanation:

Given the following data;

Length of copper, L = 3 kilometers to meters = 3 * 1000 = 3000 m

Resistivity, P = 1.7 * 10^8 Ωm

Diameter = 0.65 millimeters to meters = 0.65/1000 = 0.00065 m

$ Radius, r = \frac {diameter}{2} $

$ Radius = \frac {0.00065}{2} $

Radius = 0.000325 m

To find the resistance;

Mathematically, resistance is given by the formula;

$ Resistance = P \frac {L}{A} $

Where;

P is the resistivity of the material. L is the length of the material.A is the cross-sectional area of the material.

First of all, we would find the cross-sectional area of copper.

Area of circle = πr²

Substituting into the equation, we have;

Area = 3.142 * (0.000325)²

Area = 3.142 * 1.05625 × 10^-7

Area = 3.32 × 10^-7 m²

Now, to find the resistance of copper;

$ Resistance = 1.7 * 10^{8} \frac {3000}{3.32 * 10^{-7}} $

$ Resistance = 1.7 * 10^{8} * 903614.46 $

Resistance = 1.54 * 10^18 Ohms

. Find the derivative of y = x² – 5x using the definition of the derivative.

Answers

Answer:

$\displaystyle y' = 2x - 5$

General Formulas and Concepts:

Algebra I

Terms/Coefficients

Expanding/Factoring

Functions

Function Notation

Calculus

Limits

Limit Rule [Variable Direct Substitution]: $\displaystyle \lim_{x \to c} x = c$

Differentiation

DerivativesDerivative NotationDefinition of a Derivative: $\displaystyle f'(x) = \lim_{h \to 0} \frac{f(x + h) - f(x)}{h}$

Explanation:

Step 1: Define

Identify

$\displaystyle y = x^2 - 5x$

Step 2: Differentiate

Substitute in function [Definition of a Derivative]: $\displaystyle y' = \lim_{h \to 0} \frac{[(x + h)^2 - 5(x + h)] - (x^2 - 5x)}{h}$Expand: $\displaystyle y' = \lim_{h \to 0} \frac{x^2 + 2hx + h^2 - 5x - 5h - x^2 + 5x}{h}$Combine like terms: $\displaystyle y' = \lim_{h \to 0} \frac{2hx + h^2 - 5h}{h}$Factor: $\displaystyle y' = \lim_{h \to 0} \frac{h(2x + h - 5)}{h}$Simplify: $\displaystyle y' = \lim_{h \to 0} (2x + h - 5)$Evaluate limit [Limit Rule - Variable Direct Substitution]: $\displaystyle y' = 2x + 0 - 5$Simplify: $\displaystyle y' = 2x - 5$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

saan nag tungo si Aguinaldo at ilang pinuno ng kilusan pagkatapos mapairal ang kasunduan na pansamantalang nag dulot ng kapayapaan

Answers

Answer:

sa china po

Explanation:

sana makatulong ako

4. a. A family purchased a 3 acre piece of land in Limuru for Kshs.30,000,000.00 fifteen years ago. They planted trees at a cost of Kshs.250,000.00 per acre. Each year they have been spending on average Kshs.25,000.00 per acre per month to take care of the trees and also to secure the property. They are now considering selling it. What is the minimum amount they should accept so as not to incur a loss bearing in mind that comparable properties have been yielding a rate of 6.5% interest per annum? (8 marks)

b. “Compulsory acquisition is the power of government to acquire private rights in land for public good without the willing consent of the owner but; in exchange for compensation”. Discuss this statement with special reference to the main considerations that ought to be made in conducting a valuation for compulsory acquisition. (12 marks)

Answers

The family should accept a minimum of Kshs.42,250,000.00 to avoid incurring a loss.

Why should they accept this amount and why?

To obtain the total cost, the expenses for the land, trees and upkeep are summed up and subsequently reduced by 6. 5% using a discount rate.

Hence, it can be seen that a forced acquisition appraisal primarily focuses on three key factors: the land's market value, the expenses involved in replacing the property, and the potential harm caused to the owner's belongings.

Answers

Answer:

non-functional requirement,

Yes they can.

The application loading time is determined by testing system under various scenarios

Explanation:

non-functional requirement are requirements needed to justify application behavior.

functional requirements are requirements needed to justify what the application will do.

The loading time can be stated with some accuracy level after testing the system.

Answers

Answers

Voltage V = 480V

three loads of 1) 10Kw, 8 kVAR

2) 5 kVA, 0.9 power factor lagging

3) 12kW, 0.95 pf leading

Now for load1

Active power P = V^2 / R

Resistance R1 = V^2 / P

= (480 * 480) / 10*1000 = 23.04 OHMS

Reactive power Q = 8kVAR

let x be reactance

Q = V^2 / x

8 * 1000 = (480 * 480) / x

x1 = j28.8 ohms (inductive)

Load 2

Active power = kVA * nf = 5 * 9 = 4.5 Kw

Reactive power = sqrt(S^2 - P^2)

= Sqrt (5^2 - 4.5^2)

= 2.179 kVAR

now Resistance R2 = V^2 / P2 = (480 * 480) / 4.5*10^3

= 51.2 ohms

Reactance X2 = V^2 / Q2 = (480 * 480) / 2.178*10^3

X2 = 105.75 ohms

x2 = -j105.75 ohms (capacitive)

Load 3

Active power = 12kW AND PF = 0.95

kVA rating = 12/0.95 = 12.63 kVA

reactive power Q3 = sqrt (12.63^2 - 12^2 )

= 3.94 kVAR

Resistance R3 = V^2/P3 = (480*480) / 12*10^3

= 19.2 ohms

Reactance x3 = V2 / Q3 = (480 * 480) / 3.94*10^3

x3 = 58.47 ohms

x3 = -j58.47 ohms (capacitive)

NOW

series combination of R and X

1/ZT = [1/(R1 + jx1)] + [1/(R2-jx2)] + [1/(R3-jx3)]

we substitute

1/ZT = [1/(23.04 + j28.8)] + [1/(51.2 - j105.74)] + [1/(19.2-58.48)]

1/ZT = 0.02571 + j1.92688*10^-3

ZT = 38.67 -j2.897 (total impedance)

so ZT = [ 38.786 ∠-4.28° ] ohms

parallel combination of R AND X

1/ZT = 1/R1 + 1/jx1 + 1/R2 + 1/(-jx2) + 1/R3 + 1/(-jX3)

1/ZT = 1/23.04 + 1/j28.8 + 1/51.2 + 1/(-j105.74) + 1/19.2 + 1/(-58.48)

1/ZT = 0.1150 - j0.008164

ZT = 8.65 +j0.6141

so ZT = [ 8.673 ∠4.06° ] ohms

Will this circuit work to make the light bulb light up?

Answers

Answer:
No it will not work.

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Mechanic... Mechanical Engineer... What's the difference? Instructions: Answer the question below with at least TWO complete sentences.

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Mechanic... Mechanical Engineer... What's the difference?
Instructions: Answer the question below with at least TWO complete sentences.