Mike watched TV for 1,800 seconds on Friday, 1.5hours on Saturday, and 45minutes on Sunday. Howmany total minutes of TVdid Mike watch?
Answers
Watched TV 1,800s friday
1.5h saturday
45 minutes sunday
How many minutes?
First we need to convert seconds and hours to minutes:
\(\begin{gathered} 1\text{ hour - 60 minutes} \\ 1.5h\text{ - x } \\ x=\text{ }\frac{\lparen60min\rparen\lparen1.5h\rparen}{1h} \\ x=\text{ 90 min} \\ \\ 60\text{ seconds - 1 minute} \\ 1,800\text{ seconds - x} \\ x=\frac{\lparen1,800s\rparen\lparen1min\rparen}{60\text{ s}} \\ x=\text{ 30 min} \end{gathered}\)So now we have to add all the minutes watched:
\(\begin{gathered} Total\text{ watched= 90 min + 30 min + 45 min} \\ Total\text{ watched= 165 minutes } \end{gathered}\)Mike watched a total of 165 minutes on TV.
Related Questions
Chris wants to order DVD's over the internet. Each DVD costs $16 and shipping the
entire order costs $10. If he can spend no more than $100, how many DVD's could he
buy? Round down to the nearest whole DVD.
What am I supposed to be comparing
Answers
HELP ME Answer it from the forst one to the last one with the rght answer please.This is Urgent so do it Faster if u now the answers
Answers
Step-by-step explanation:
2) 63
3) 7000
4) 10
These are some answers
a line has slope -3 and the y intercept is 7. what is the slope intercept form of the line?
Answers
Answer:
y = -3x + 7
Step-by-step explanation:
\(y = mx + b\)
m = slope
b = y intercept
eq:
\(y = - 3x + 7\)
Given f(x) = x² - 5x - 6 and g(x) =
x² - 6x, what are the domain restrictions
for (-)(x)?
A) x # +6
B) x = 0
C) x = 0,6
D) x = -2,6
Answers
The domain restrictions for (f/g)(x) are (c) x = 0, 6
How to determine the domain restrictions for (f/g)(x)?From the question, we have the following parameters that can be used in our computation:
f(x) = x² - 5x - 6
g(x) = x² - 6x
The composite function (f/g)(x) is calculated as
(f/g)(x) = f(x)/g(x)
substitute the known values in the above equation, so, we have the following representation
(f/g)(x) = (x² - 5x - 6 )/(x² - 6x)
For the domain restriction, we have
x² - 6x = 0
When solved, we have
x = 6 or x = 0
Hence, the domain restrictions for (f/g)(x) are (c) x = 0, 6
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Question
Given f(x) = x² - 5x - 6 and g(x) = x² - 6x, what are the domain restrictions
for (f/g)(x)?
A) x = +6
B) x = 0
C) x = 0,6
D) x = -2,6
choose a value for x and then solve to find the corresponding y value that makes that equation true . a) 6x = 7y b) 5x + 3y = 9 c) y + 5 - 1/3 x = 7
Answers
For every equation, we have to choose a value for x, and solve for y.
For part a) we have that the equation is:
\(6x=7y\)If we choose the following value for x:
\(x=1\)And substitute it in the equation, we find the value of y:
\(\begin{gathered} 6(1)=7y \\ 6=7y \\ \text{Dividing both sides by 7:} \\ \frac{6}{7}=y \end{gathered}\)Answer for part a) when x=1, the value of y is y=6/7
For part b) we have the equation:
\(5x+3y=9\)If we choose the following value for x:
\(x=3\)and substitute it in the equation to find y:
\(5(3)+3y=9\)To solve for y, first, we solve the multiplication between 5 and 3:
\(15+3y=9\)Now we subtract 15 to both sides:
\(\begin{gathered} 3y=9-15 \\ 3y=-6 \end{gathered}\)Finally, divide both sides by 3:
\(\begin{gathered} \frac{3y}{3}=\frac{-6}{3} \\ y=-2 \end{gathered}\)Answer for part b) when x=3, the value of y is y=-2
For part c) we have the equation:
\(y+5-\frac{1}{3}x=7\)In this case, we can choose a value for x in such a way that we eliminate the fraction. For this, we can again choose the value:
\(x=3\)And we substitute it:
\(y+5-\frac{1}{3}(3)=7\)1/3 by 3 is equal to 1:
\(y+5-1=7\)Next, combine the like terms on the left side 5-1 which is 4:
\(y+4=7\)And finally, subtract 4 to both sides:
\(\begin{gathered} y=7-4 \\ y=3 \end{gathered}\)Answer for part c) when x=3, the value of y is y=3
Let (1=1,2,3, 4, 5, 6, 7, 8, 9, 10
Answers
The list of elements in the sets are as follows:
A. A ∩ B = {2, 9}
B. B ∩ C = {2, 3}
C. A ∪ B ∪ C = {1, 2, 3, 5, 7, 8, 9, 10}
D. B ∪ C = {2, 3, 5, 7, 9, 10}
How to find the elements in a set?Set are defined as the collection of objects whose elements are fixed and can not be changed.
Therefore,
universal set = U = {1,2,3, 4, 5, 6, 7, 8, 9, 10}
A = {1, 2, 7, 8, 9}
B = {2, 3, 5, 9}
C = {2, 3, 7, 10}
Therefore,
A.
A ∩ B = {2, 9}
B.
B ∩ C = {2, 3}
C.
A ∪ B ∪ C = {1, 2, 3, 5, 7, 8, 9, 10}
D.
B ∪ C = {2, 3, 5, 7, 9, 10}
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Which values complete the translated function?
Answers
Step-by-step explanation:
g(x) = f(x) that moved 4 units down and 1.5 units to the left.
the turning point in the middle of the function tells us this clearly.
to make that translation happen, it means
g(x) = f(x + 1.5) - 4 = (x - -1.5)³ + -4
the "-4" simply subtracts 4 units from every function result f(x) calculated. that moves everything down by 4 units.
and the "-1.5" (actually "x + 1.5") makes every function result of f(x) happen 1.5 units "earlier" for g(x). so, a shift to the left.
6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.
Answers
1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)
2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)
3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)
4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)
5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)
6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)
7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)
8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)
9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)
10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)
11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)
12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)
13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)
14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)
Here are the journal entries for the given transactions:
1. Bricks and timber purchased for construction:
Debit: Bricks (Asset) - Rs 60,000
Debit: Timber (Asset) - Rs 35,000
Credit: Bank (Liability) - Rs 95,000
2. Transfer to fixed deposit account:
Debit: Fixed Deposit (Asset) - Rs 13,000
Credit: Current Account (Asset) - Rs 13,000
3. Appointment of Mr. S.N. Rao as Accountant:
Debit: Salary Expense (Expense) - Rs 300
Debit: Security Deposit (Asset) - Rs 1,000
Credit: Accountant (Liability) - Rs 300
4. Goods sold to Shruti:
Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000
Credit: Sales (Income) - Rs 80,000
5. Goods purchased from Richa:
Debit: Purchases (Expense) - Rs 60,000
Credit: Accounts Payable - Richa (Liability) - Rs 60,000
6. Goods sold to Shilpa:
Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000
Credit: Sales (Income) - Rs 50,000
7. Goods sold to Garima:
Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000
Credit: Sales (Income) - Rs 1,00,000
8.Purchase of land:
Debit: Land (Asset) - Rs 2,00,000
Debit: Brokerage Expense (Expense) - Rs 2,000
Debit: Registration Charges (Expense) - Rs 15,000
Credit: Bank (Liability) - Rs 2,17,000
9. Goods and cash taken away by proprietor:
Debit: Proprietor's Drawings (Equity) - Rs 65,000
Credit: Goods (Asset) - Rs 25,000
Credit: Cash (Asset) - Rs 40,000
10. Goods sold to Charu:
Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000
Credit: Sales (Income) - Rs 1,20,000
Credit: Cost of Goods Sold (Expense) - Rs 80,000
Credit: Profit on Sales (Income) - Rs 40,000
11. Rent paid for the building:
Debit: Rent Expense (Expense) - Rs 60,000
Credit: Bank (Liability) - Rs 60,000
12. Goods sold to Sunil:
Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000
Credit: Sales (Income) - Rs 24,000
Credit: Cost of Goods Sold (Expense) - Rs 20,000
Credit: Profit on Sales (Income) - Rs 4,000
13. Goods purchased from Nanda and supplied to Helen:
Debit: Purchases (Expense) - Rs 1,000
Debit: Accounts Payable - Nanda (Liability) - Rs 1,000
Credit: Accounts Receivable - Helen (Asset) - Rs 1,300
Credit: Sales (Income) - Rs 1,300
14. Goods received from Rohit and Sons and supplied to Madan:
Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)
Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700
Debit: Accounts Receivable - Madan (Asset) - Rs 3,000
Credit: Sales (Income) - Rs 3,000
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Help me!!
What is x?
-0.5x=-22
Answers
Answer:
44
Step-by-step explanation:
Answer:
x=44
Step-by-step explanation:
22÷0.5=?
22x2=44
20 points for solving!
Answers
Answer:
m = 5 and n = 6
Step-by-step explanation:
In a parallelogram, opposite sides of the figure are congruent (equal to each other).
This means that 3m - 7 = m + 3 and 2n + 12 = 4n
We can now solve for the variables
3m - 7 = m + 3
==> add 7 to both sides
3m = m + 10
==> subtract 2 from both sides
2m = 10
==> divide both sides by 2
m = 5
2n + 12 = 4n
==> subtract 2n from both sides
12 = 2n
==> divide both sides by 2
6 = n
Answer:
n=6,m=2
Step-by-step explanation:
4n=2n+12
2n =12
n=6
m+3=3m-1
4=2m
m=2
What is the measure in radians for the central angle of a circle whose radius is 8 cm and intercepted arc length is 5.6 cm? Enter your answer as a decimal in the box. radians
Answers
The measure in radians for the central angle is approximately 0.7 radians.
To find the measure in radians for the central angle of a circle, we can use the formula:
θ = s / r
where θ is the central angle in radians, s is the intercepted arc length, and r is the radius of the circle.
In this case, the radius is given as 8 cm and the intercepted arc length is 5.6 cm.
Plugging these values into the formula, we have:
θ = 5.6 cm / 8 cm
Simplifying the expression:
θ = 0.7
We may use the following formula to get the centre angle of a circle's measurement in radians:
= s / r
s is the length of the intercepted arc, r is the circle's radius and is the centre angle in radians.
The intercepted arc length in this instance is 5.6 cm, while the radius is specified as 8 cm.
When these values are plugged into the formula, we get:
θ = 5.6 cm / 8 cm
Condensing the phrase:
θ = 0.7
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if a polygon is a triangle, then it has exactly three sides. is the converse of the conditional true?
Answers
Answer:
If a polygon is a triangle then it has exactly three sides
A polygon has 3 sides if and only if it is a triangle. Put it all together: Conditional: If a polygon is a triangle, then it has three sides. Converse: If a polygon has three sides, then it is a triangle.
Answer:
yes
Step-by-step explanation:
because the polygon it has tree sides it's called triangle hope it's helpa rectangular feild 70m long and 50m wide has a path of uniform width around it if the area of the path is 104m² find the width of the path
Answers
The 70 meters by 50 meters rectangular field having a path with an area of 104 m² around it indicates that the width of the path, found using the quadratic formula is about 0.43 meters.
What is the quadratic formula?The quadratic formula is a formula that is used to find the values of x that are the solutions to the the the quadratic equation of the form, a·x² + b·x + c = 0.
The length of the rectangular field = 70 meters
The width of the rectangular field = 50 meters
The width of the path around the field = Uniform width
Area of the path around the field = 104 m²
Let x represent the width of the path, we get;
(70 + 2·x) × (50 + 2·x) - 70 × 50 = 104
4·x² + 240·x = 104
4·x² + 240·x - 104 = 0
The quadratic formula which can be used to find the value of x in the equation a·x² + b·x + c = 0, is presented as follows;
\(x = \dfrac{-b\pm \sqrt{b^2-4\cdot a \cdot c} }{2\cdot a}\)
Comparing the equation 4·x² + 240·x - 104 = 0 to the quadratic equation for the quadratic formula; a·x² + b·x + c = 0, we get;
a = 4, b = 240, c = -104
Therefore;
\(x = \dfrac{-240\pm \sqrt{240^2-4\times 4 \times (-104)} }{2\times 4}\)
x ≈ 0.430 or x ≈ -60.4
The possible value of the width of the path is x ≈ 0.43 metersLearn more about the quadratic formula here:
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Dividing fractions word problems, please help I need it........
Answers
Answer:
25
Step-by-step explanation:
l x w = h
25 x 7.2 = 180
Use the parallelogram to find m
m
Answers
Using the parallelogram law to find m, the value of m is 50°.
What is the parallelogram law?The parallelogram law states that the sum of the squares for a parallelogram's four sides is equal to the sum of the squares for its two diagonals.
The parallelogram must have equal opposed sides in Euclidean geometry.
If ABCD is a parallelogram, then AB = DC and AD = BC, the parallelogram law is stated as:
2(AB)² + 2 (BC)² = (AC)² + (BD)²
If the parallelogram is a rectangle, the parallelogram law is stated as:
2(AB)² + 2 (BC)² = 2(AC)²
The value of the unknown angles in the parallelogram are as follows:
CED = 180 - (60 + 33 + 37)
CED = 50°
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Nathan is stocking bathrooms at the hotel where he works. he has 18 rolls of toilet paper and 9 bars of soap. if he wants all bathrooms to be stocked identically, with the same combination of supplies in each one and nothing left over, what is the greatest combination of bathrooms Nathan can stock
Answers
How many miles does he run in one year
Answers
Answer Key:
1. Since the question says Mr. Smith runs 2.7 miles every day of the week, you will need to multiply it with 365, the days of the year. The total answer you would get D. 985.5 miles.
| I just want to help you with #2 anyway
Jenny had 188 but she is spending 14 per week
Answers
Answer:
14×7=98
188-98=90 so she had 90 left
Can someone help me on this
Answers
Answer:
39V3 Sq.units of that will help you
At an arcade, a book of 20 tickets costs $5, a book of 30 tickets costs $7, and a book of 50 tickets costs $10. Would a graph of the relationship between price and number of tickets in a book be a straight line? Explain.
Answers
Answer:
yes
Step-by-step explanation:
100 Points! Geometry question. Photo attached. Please show as much work as possible. Thank you!
Answers
The value of side TS is,
⇒ TS = 28
First, we are going to divide the figure and named new points X and Y as:
Now, we know that TS is the sum of TX and XS.
TS = TX + XS
Additionally, TX has the same length of HJ, so:
TX = HJ = 14
Now, we want to know the length of YK, and we can calculate it using the following equation:
LK = LY + YK
LY = HJ,
so, LY = 14
And, 42 = 14 + YK
42 - 14 = YK
28 = YK
Finally, since T and S are midpoints, the length of XS is the half of the length of YK. It means that XS is:
XS = YK/2
XS = 28/2
XS = 14
Therefore, TS is equal to:
TS = TX + XS
TS = 14 + 14
TS = 28
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PLEASE ANSWERING THIS QUESTION!!
However, you should assume the question always wants a reduced fraction as the answer. So, in the 2/4 example, you should enter 1/2. Some questions will consider 2/4 the same as 1/2, but you should get in the habit of always reducing your fractions to lowest terms.
Enter 9/45 in reduced form: (Blank)
Please show your work!
Explain your answer!
Do not spam answers.
Nonsense answers will be reported and delete.
Thanks!
Answers
Answer:
1/5
Step-by-step explanation:
because 9 divided by 9 is 1, and that means you must divide the denominator to, so 45 divided by 5, thus, you have 1/5
how do we reduce?
We commonly/usually reduce them with their suitable factors or in which table they go (multiplication factors)
So as 2/4 is reduced into 1/2 , here 2 and 4 are multiples of 2 and can be reduced into their simple forms as 1 and2
Because 2 x 1 = 2 and 2 x 2 = 4
So now considering the question. , 9/45
This can be reduced in two ways
With factors of three first!
=> 9/45
This goes in three table as 3 x 3 = 9 and 3 x 15 = 45
So we get it as 3/15
And we can again simplify this with 3
3 x 1 = 3 and 3 x 5 = 15
Which comes out to be 1/5
Now second method ;
Directly with 9 table
We know , 9 x 1 = 9 and 9 x 5 = 45
Can be reduced as 1/5 easily.
Also refer attachment
Answer the questions
Answers
B. 9600000000
C. 244000
D. 50230000000
Junk Food Central Inc sells 50-pound boxes of donuts wholesale to warehouse clubs for $10/box. The fixed costs of this operation are $80,000, while the variable costs of donuts are $.10/pound.
1.) Calculate the profit or loss on 12,000 boxes and 25,000 boxes.
2.) If Junk Food Central has an annual interest expense of $10,000, calculate the degree of financial leverage at both 20,000 and 25,000 boxes.
3.) What is the degree of combined leverage at both sales levels?
Answers
(1) The junk Food Central Inc will incur a loss of $20,000 if they sell 12,000 boxes and a profit of $45,000 if they sell 25,000 boxes.
(2) At 20,000 boxes, the degree of financial leverage is 2, and at 25,000 boxes, it is 1.3.
(3) The degree of combined leverage at 20,000 boxes is 20 and the degree of combined leverage at 25,000 boxes is 7.2.
What is the profit/loss on the boxes?To calculate the profit or loss on 12,000 boxes, we need to first calculate the total cost of producing these boxes:
Variable cost per box = 50 lbs/box x $0.10/lb = $5/box
Total variable cost = $5/box x 12,000 boxes = $60,000
Total cost = Fixed cost + Total variable cost = $80,000 + $60,000 = $140,000
Revenue = 12,000 boxes x $10/box = $120,000
Profit/Loss = Revenue - Total cost = $120,000 - $140,000 = -$20,000
(negative sign indicates loss)
To calculate the profit or loss on 25,000 boxes, we can use the same formula:
Variable cost per box = 50 lbs/box x $0.10/lb = $5/box
Total variable cost = $5/box x 25,000 boxes = $125,000
Total cost = Fixed cost + Total variable cost = $80,000 + $125,000 = $205,000
Revenue = 25,000 boxes x $10/box = $250,000
Profit/Loss = Revenue - Total cost = $250,000 - $205,000 = $45,000
The degree of financial leverage is a measure of how sensitive a company's earnings per share (EPS) are to changes in its earnings before interest and taxes (EBIT).
It is calculated as follows:
Degree of financial leverage = EBIT / (EBIT - Interest expense)
At 20,000 boxes, the EBIT is:
Revenue = 20,000 boxes x $10/box = $200,000
Variable cost = $5/box x 20,000 boxes = $100,000
Fixed cost = $80,000
EBIT = Revenue - Variable cost - Fixed cost = $200,000 - $100,000 - $80,000 = $20,000
Degree of financial leverage = $20,000 / ($20,000 - $10,000) = 2
At 25,000 boxes, the EBIT is:
Revenue = 25,000 boxes x $10/box = $250,000
Variable cost = $5/box x 25,000 boxes = $125,000
Fixed cost = $80,000
EBIT = Revenue - Variable cost - Fixed cost = $250,000 - $125,000 - $80,000 = $45,000
Degree of financial leverage = $45,000 / ($45,000 - $10,000) = 1.3
The degree of combined leverage (DCL) is a measure of the sensitivity of a company's EPS to changes in its sales. It is calculated as follows:
DCL = Degree of operating leverage x Degree of financial leverage
The degree of operating leverage (DOL) is a measure of how sensitive a company's EBIT is to changes in its sales. It is calculated as follows:
DOL = Revenue / (Revenue - Variable cost - Fixed cost)
At 20,000 boxes:
DOL = $200,000 / ($200,000 - $100,000 - $80,000) = 10
DCL = 10 x 2 = 20
To calculate the DOL and DCL at 25,000 boxes, we can use the same formula:
DOL = Revenue / (Revenue - Variable cost - Fixed cost)
At 25,000 boxes:
DOL = $250,000 / ($250,000 - $125,000 - $80,000) = 5.55
DCL = 5.55 x 1.3 = 7.2
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Suppose 8 books stacked on top of one another. Each book is 1 5/9 inches thick. How high is the stack of books?
Answers
Answer:
Step-by-step explanation:
12.4
you have to multiply 1 5/9 times 8
Find the points on the curve y = 2x3 + 3x2 − 12x + 3 where the tangent line is horizontal.
Answers
the tangent is only horizontal at the critical points of the equation, so
\(y=2x^3+3x^2-12x+3\implies \cfrac{dy}{dx}=6x^2+6x-12\implies \cfrac{dy}{dx}=6(x^2+x-2) \\\\\\ \stackrel{\textit{setting the derivative to 0}}{0=6(x^2+x-2)}\implies 0=x^2+x-2 \\\\\\ 0=(x+2)(x-1)\implies \boxed{x= \begin{cases} -2\\ 1 \end{cases}} \\\\[-0.35em] ~\dotfill\\\\ y=2(-2)^3+3(-2)^2-12(-2)+3\implies y=-16+12+24+3\implies \boxed{y=23} \\\\\\ y=2(1)^3+3(1)^2-12(1)+3\implies y=2+3-12+3\implies \boxed{y=-4} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \text{\LARGE (-2~~,~~23)\qquad (1~~,~~-4)}~\hfill\)
A retail store had total sales of $436, $650, $530, $500, $650, $489, and $423 last week. Which measure of data would make the store’s sales last week appear the most profitable? Find
Mean
Median
Explanation
Answers
The most common measures are mean, median, and mode. MIS. Measure ... For an even amount of data values - Calculate the mean of the two middle numbers. ... store had total sales of $436, $650, $530, $500,$650, $489, and $423 last week. ... would make the store's sales last week appear the most profitable? Explain.
The mean and the median of the data will be $525.43 and $500, respectively.
What is Mean?The mean is the straightforward meaning of the normal of a lot of numbers. In measurements, one of the markers of focal propensity is the mean. The normal is alluded to as the number-crunching mean. It's the proportion of the number of genuine perceptions to the absolute number of perceptions.
A retail store had total sales of $436, $650, $530, $500, $650, $489, and $423 last week.
Then the mean of the data will be
Mean = (436 + 650 + 530 + 500 + 650 + 489 + 423) / 7
Mean = $525.43
Arrange the data in ascending order, then we have
$423, $436, $489, $500, $530, $650, $650
Then the median of the data will be
Median = $500
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What the meaning of statement this?
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The proof demonstrates that given a well-ordered set W, an isomorphic ordinal can be found using the function F. The uniqueness of this ordinal is established using the Replacement Axioms. The set F(W) is shown to exist for each x in W, and if the least F(W) exists, it serves as an isomorphism of VV onto -y.
Lemma 2.7: This is a previously stated lemma that is referenced in the proof. Unfortunately, without the specific details of Lemma 2.7, it's difficult to provide further explanation for its role in the proof.
Well-ordered set W: A well-ordered set is a set where every non-empty subset has a least element. In this proof, W is assumed to be a well-ordered set.
Isomorphic ordinal: An ordinal is a mathematical concept that extends the notion of natural numbers to represent order and magnitude. An isomorphic ordinal refers to an ordinal that has a one-to-one correspondence or mapping with another ordinal, preserving their order and magnitude properties.
Function F: The function F is defined to assign an ordinal o to each element x in W. This means that for every x in W, there is a corresponding ordinal o.
Existence and uniqueness: The proof asserts that if there exists an ordinal o that is isomorphic to a specific initial segment of the ordinal VV (the set of all ordinals), then this ordinal o is unique. In other words, there is only one ordinal that can be mapped to the initial segment of VV given by x.
Replacement Axioms: The Replacement Axioms are principles in set theory that allow the construction of new sets based on existing ones. In this case, the Replacement Axioms are used to assert that the set F(W) exists, which is the collection of all ordinals that can be assigned to elements of W.
For each x in W: The proof states that for every x in W, there exists an ordinal o that can be assigned to it. If there is no such ordinal, the proof suggests considering the least x for which such an ordinal does not exist.
The least F(W): The proof introduces the concept of the least element in the set F(W), denoted as the least F(W). If this least element exists, it serves as an isomorphism (a one-to-one mapping) of the set of all ordinals VV onto the ordinal -y.
Overall, the proof outlines the existence and uniqueness of an isomorphic ordinal that can be obtained from a well-ordered set W using the function F, and it relies on the Replacement Axioms and the concept of least element to establish this result.
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Which of the following are two-step equations? Choose more than
one answers
Answers
Answer:
i think a b d f
Step-by-step explanation:
A table blueprint uses the scale 3 inches :2 feet.If the model is 15 inches long how long is the table!!!!!HURRY
Answers
Answer:
I am pretty positive it is thirty if you need work shown just let me know if it is wrong for some reason then I apologize.
Step-by-step explanation:
If the model is 15 inches. Then the length of the table will be 10 feet.
What is dilation?Dilation is the process of increasing the size of an item without affecting its form. Depending on the scale factor, the object's size can be raised or lowered.
A table blueprint uses the scale 3 inches :2 feet.
The scale factor will be 2 feet: 3 inches.
If the model is 15 inches.
Then the length of the table will be
⇒ (2 feet/ 3 inches) x 15 inches
⇒ 2 x 5
⇒ 10 feet
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