Mind-Set Matters In 2007 a Harvard psychologist set out to test her theory that ‘‘Mind-Set Matters. "1 She recruited female maids2 working in different hotels to participate in her study, and informed maids (randomly chosen) that the work they do satisfies the Surgeon General’s recommendations for an active lifestyle (which is true), giving the maids examples on how their work qualifies as good exercise. The other maids were told nothing. After four weeks, the exercise habits of the two groups had not changed, but the informed group had lost an average of lbs () and the uninformed group had lost an average of lbs (). The data are stored in MindsetMatters. Based on this study, does ‘‘Mind-Set Matter"? In other words, for maids, does simply thinking they are exercising more actually cause them to lose more weight?

Answer:

No

Step-by-step explanation:

To divide fractions you need to do the reciprocal of the 2nd fraction and them multiply.

Eg. \(\frac{1}{3}\) ÷ \(\frac{2}{4}\)

This is the same thing as \(\frac{1}{3}\) ×\(\frac{4}{2}\)

Which equals \(\frac{4}{6}\) and if simplified, it will be \(\frac{2}{3}\)

So you don't need a common denominator to divide, you have to use the method showed above.

The most appropriate method for creating an estimate of the percent of district residents who support the building of a new middle school would be  v. A one-sample z-interval for a population proportion.

In this case, the superintendent wants to estimate the proportion (percentage) of district residents who support the building of a new middle school. To achieve this, a random sample of district residents can be selected, and the proportion of residents in the sample who support the new middle school can be calculated.

Since the sample size is relatively large (as it is a large school district), the sampling distribution can be assumed to follow a normal distribution. Therefore, a one-sample z-interval for a population proportion is suitable for estimating the proportion of district residents who support the new middle school.

Using this method, a confidence interval can be constructed around the sample proportion, providing an estimate of the true proportion of district residents who support the new middle school, along with a measure of uncertainty.

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Answer:

Choice D.

Step-by-step explanation:

D=[18. 16]

[-14 -6]

-0.5D = [-0.5(18) -0.5(16)]

[-0.5(-14) -0.5(-6)]

-0.5D = [ -9 -8]

[ 7 3]

Answer:

Step-by-step explanation:

well if you 6+2 is 8 that is the one's place then 50+10 is 60 that is the tens place then 300+100 is 400 that is the hundreds place and add 400+60+8 is 468

You Welcome

Answer:

The probability is 0.5 tiles will be green

Step-by-step explanation:

Hope this helps

Answer:

10 chairs are 102 inches

Step-by-step explanation:

Beacause 5 chairs are 51 so the double of chairs will be 102 inches

The 18th term of the arithmetic sequence -13, -9, -5, -1, 3,... is 55. Thus, the right answer is option A. which is A(18) = 55

Arithmetic Progression is a sequence of numbers in which the difference between two numbers in the series is a fixed definite value.

The specific number in the arithmetic progression is calculated by

\(a_n=a_1+(n-1)d\)

where \(a_n\) is the term in arithmetic progression at the nth term

\(a_1\) is the initial term in the arithmetic progression

d is the difference between two consecutive terms

In the given question, \(a_1\) = -13

d = -9 - (-13) = 4

Therefore, to calculate the 18th term,

\(a_{13}=a_1+(18-1)d\)

= -13 + (17) 4

= -13 + 68

= 55

Hence, the 18th term of the above AP is 55

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Failure to include some units, or entire portions, of the defined survey population in the actual operational sample frame represents: a noncoverage error.

One of the components of coverage error that results from a flawed sample frame that excludes a certain percentage of the population is noncoverage.

Sampling errors need to be controlled and reduced to a level at which their presence does not defeat or obliterate the usefulness of the final sample results.

The difference between the observed values of a variable and the long-run average of the observed values in repetitions of the measurement is the sampling error.

Noncoverage, another word for these frames, inadequate coverage is also known as undercoverage.

Sampling errors can be decreased by increasing the sample size.

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The temperature at a given chirp rate can be determined from a linear regression model as follows;

a. The linear regression model is; T = 4.1484·C - 166.1

b. At 72 °F the chirp rate is approximately 57 chirps per minute

At 90 °F the chirp rate is approximately 62 chirps per minute

A linear regression model, models a relationship between variables using a linear approach

a. The data given the values of the temperatures at a  given chirp rate per minute is used to create the attached scatter plot.

From the scatter plot, a trend line is drawn using the Add Chart Element, within the Chart Tools, Design Menu.

From the Format Trendline window, The Display Equation on chart check box is selected, to show the trend line equation.

The trendline equation that is the linear regression model for chirp rate as a function of time is; y = 4.1484·x - 166.1

Where, y = T, and x = C, we have; T = 4.1484·C - 166.1

b. If the temperature, T, is 72 °F, we have;

T = 72 °F

72 = 4.1484·C - 166.1

\(C = \dfrac{72+166.1}{4.1484} \approx 57\)

If the temperature is 90 °F, the chirp rate is calculated as follows;

T = 90 = 4.1484·C - 166.1

\(C = \dfrac{90+166.1}{4.1484} \approx 62\)

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Answer:

11-4x

Step-by-step explanation:

The approximate percentage of light remaining after passing through 6 feet of water, to the nearest tenth of a percent is 4.7%

The percentage of light remaining is calculated from the percentage of light remaining after a depth of one foot each.

Percentage of light remaining after 1 feet = 100 - 40% = 60%.

Percentage of light remaining after 6 feet = 60% × 60% × 60% × 60% × 60% × 60% = 4.7%

Therefore, the approximate percentage of light remaining after passing through 6 feet of water, to the nearest tenth of a percent is 4.7%.

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Answer:

The ordered pair that is the solution to the system lies in Quadrant IV

The x-coordinate of the solution is 9

The y-coordinate of the solution is -8

Step-by-step explanation:

The inverse Laplace transform of ℒ^-1 8s - 16 (s^2 + s)(s^2 + 1) is:

\(-4(e^-t - 1) - 4e^(-t) sin(t) - 4cos(t)\)

To find the inverse Laplace transform of ℒ−1 8s − 16 (s2 s)(s2 1), we can first simplify the expression:

\(8s - 16 (s^2 + 1)(s^2 + s)= 8s - 16 (s^4 + s^3 + s^2 + s)= -16s^4 - 16s^3 + 8s^2 - 16s\)

We can then use partial fraction decomposition to write this expression as a sum of simpler fractions:

\(-16s^4 - 16s^3 + 8s^2 - 16s = (-4s^2 + 4s - 4)/(s + 1) + (-4s^2 - 8s)/(s^2 + 1) + (-4s)/(s^2 + 1)\)

To find the inverse Laplace transform of each term, we can use theorem

\(L^-1 (-4s^2 + 4s - 4)/(s + 1) = -4L^-1 (s + 1) + 4ℒ^-1 1 = -4(e^-t - 1)\\L^-1 (-4s^2 - 8s)/(s^2 + 1) = -4L^-1 (s + 2i)/(s^2 + 1) = -4e^(-t) sin(t)\\ℒ^-1 (-4s)/(s^2 + 1) = -4ℒ^-1 (s/(s^2 + 1)) = -4cos(t)\)
Therefore, the inverse Laplace transform of ℒ^-1 8s - 16 (s^2 + s)(s^2 + 1) is:

\(-4(e^-t - 1) - 4e^(-t) sin(t) - 4cos(t)\)

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\( c.\:{x}^{ - 4} \)

\(\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}\)

\( \frac{7 {x}^{4} }{7 {x}^{8} } \\ = \frac{ {x}^{4} }{ {x}^{8} } \\ = {x}^{4 - 8} \\ = {x}^{ - 4} \)

Note:-

\( {x}^{m} \times {x}^{n} = {x}^{m + n} \\ {x}^{m} \div {x}^{n} = {x}^{m - n} \)

\(\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{.}}}}}\)

The function g(x,y,z) will change by approximately -2.2440 as the point P(x,y) moves 0.3 units towards P₁(-1,0,2).

To determine the change in the function g(x,y,z), we first calculate the gradient of g(x,y,z) with respect to x, y, and z. Taking the partial derivatives, we have ∂g/∂x = 2 + cos(z), ∂g/∂y = -sin(z), and ∂g/∂z = -xsin(z) - ycos(z).

Next, we find the direction vector from P₀(1,-2,0) to P₁(-1,0,2) by subtracting the coordinates of P₀ from  P₁, resulting in (-2, 2, 2). We normalize this vector to obtain the unit direction vector.

Using the directional derivative formula, we compute dg = (∂g/∂x, ∂g/∂y, ∂g/∂z) · (direction vector) = (2 + cos(z))(-2) + (-sin(z))(2) + (-xsin(z) - ycos(z))(2).

By plugging in the values from P₀ and  P₁ into the above equation and evaluating the expression, we find dg ≈ -2.2440. This indicates that g(x,y,z) will change by approximately -2.2440 as the point P(x,y) moves 0.3 units towards  P₁(-1,0,2).

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The total surface area of the tires making contact with the ground at any one time for the truck with 18 wheels, tire radius of 21 in, tire width of 12 in, and 20% contact area is approximately 5700.24 square inches.

The surface area of one tire making contact with the ground can be calculated as follows:

The diameter of the tire is 2 * radius = 2 * 21 in = 42 in

The length of the portion of the tire making contact with the ground is 20% of the circumference of the tire = 0.2 * π * 42 in ≈ 26.39 in

The width of the tire making contact with the ground is given as 12 in

Therefore, the surface area of one tire making contact with the ground is approximately 26.39 in * 12 in = 316.68 square inches

Since the truck has 18 wheels, the total surface area of all the tires making contact with the ground at any one time is 18 * 316.68 square inches = 5700.24 square inches.

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Answer:

The easiest ways to do this is to add, subtract, multiply, or devide 5 from a number, do that operation to x, and set that number as the equivelent.

For example

3 * 5=15

so

3x=15

Rounding to the nearest whole number, the distance from Mike's eyesight to the top of the statue is approximately 27 ft.

To find the distance from Mike's line of sight to the top of the statue, we can use trigonometry and the concept of similar triangles. Let's assume the distance from Mike's eyesight to the top of the statue is represented by 'd'. We have two right triangles:

Triangle 1: Mike's triangle

Angle of elevation: 11°

Opposite side: Mike's height = 5 ft

Adjacent side: Distance from Mike's eyesight to the statue = d ft

Triangle 2: Statue triangle

Angle of elevation: 90°

Opposite side: Statue height = 420 ft

Adjacent side: Distance from Mike's eyesight to the statue = d ft

We can use the tangent function to set up the equation:

tan(11°) = (Mike's height) / (Distance from Mike's eyesight to the statue)

tan(11°) = 5 / d

To find d, we can rearrange the equation:

d = 5 / tan(11°)

Using a calculator, the value of d is approximately 27.48 ft.

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Answer:

6y + 5x = -54  

Step-by-step explanation:

y = m x + b -> slope-intercept form

ax + by = c -> standard form

\(y = - \frac{5}{6} x - 9\)

6y = -5x - 54

6y + 5x = -54  

Answer:

107

Step-by-step explanation:

Here is some info that might help


-2 factors is a hint



+0 +2 +4 is a fractor of 4/1


if not 41

Answer:

3

Step-by-step explanation:

The minimum product of sums is a term used in digital logic and Boolean algebra to describe a method of simplifying logic circuits.

It is a way of minimizing the number of logic gates required to implement a certain function.

The minimum product of sums (also known as the minimum sum of products) involves representing a given Boolean function as the sum of its minterms (the minimum number of product terms required to represent the function).

The goal is to find a representation with the minimum number of product terms, which will result in the minimum number of logic gates and the most efficient implementation of the circuit.

This method involves using Boolean algebra to simplify the function, applying rules such as the distributive law, the idempotent law, and De Morgan's laws to minimize the number of terms.

The final result is a simplified Boolean expression that can be used to design a circuit with the minimum number of gates.

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Answer:

5cm

Step-by-step explanation:

It is the pythagorean Theorem and there is this special rule my teacher always told me to follow that means it is always 3, 4, and 5. Trust me, I had this problem before. It is 5cm just use the pythagorean theorem.

The distributive property is used when you have a value multiplied by 2 values separated by an operation.

For example, if you have x (y + z), then you would use the distributive property to get x (y + z) = xy + xz.

Answer:

40 oranges are there in 100 fruites.

The expected value for Game 1 is $14.50, you would be willing to pay up to $14.50 to participate in the game. For Game 2, with an expected value of $50, you would be willing to pay up to $50 to participate in the game.

To determine how much you would pay or have to be paid to take part in either Game 1 or Game 2, we need to calculate the expected value of each game. The expected value is the average outcome of the game if it were played many times, and it's calculated using the probabilities and potential winnings or losses.

For Game 1, the expected value (EV1) can be calculated as follows:

EV1 = (Win amount x Probability of winning) + (Loss amount x Probability of losing)
EV1 = ($30 x 0.5) + (-$1 x 0.5)
EV1 = $15 + (-$0.50)
EV1 = $14.50

For Game 2, the expected value (EV2) can be calculated similarly:

EV2 = (Win amount x Probability of winning) + (Loss amount x Probability of losing)
EV2 = ($2000 x 0.5) + (-$1900 x 0.5)
EV2 = $1000 + (-$950)
EV2 = $50

Now that we have the expected values, we can determine how much to pay or be paid to take part in each game. Since the expected value for Game 1 is $14.50, you would be willing to pay up to $14.50 to participate in the game. For Game 2, with an expected value of $50, you would be willing to pay up to $50 to participate in the game.

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Answer: yes it is a solution

Step-by-step explanation: 2x+3>5 -> x>1

Answer:

1,

Step-by-step explanation:

now z also a dk4k ak4 smka 4ml 4 LL