moment of inertia times angular velocity; measured in units of mass times units of velocity or expressed as kilogram-meters squared per second in si; a vector quantity.

Answers

Answer 1

The quantity that is expressed as the product of moment of inertia and angular velocity is known as angular momentum.

Angular momentum is a vector quantity and is measured in units of mass times units of velocity, which is equivalent to kilogram-meters squared per second in SI units. It represents the rotational analog of linear momentum and is important in understanding the conservation of angular momentum in rotating systems.
The concept of angular momentum, which involves moment of inertia and angular velocity. Angular momentum (L) is the product of an object's moment of inertia (I) and its angular velocity (ω). It can be represented mathematically as:
L = I * ω
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Answer 2

The moment of inertia times angular velocity is a measure of rotational motion and is expressed as the ˘ of the moment of inertia and the angular velocity. The units of velocity are typically meters per second (m/s) or radians per second (rad/s), depending on the context.

The units of moment of inertia are kilograms times meters squared (kg x m²). When these units are multiplied together, the resulting unit is kilogram-meters squared per second (kg x m²/s), which is the SI unit for angular momentum. Since angular momentum is a vector quantity, it has both magnitude and direction.

I is the moment of inertia, a measure of an object's resistance to rotational motion, and is typically determined by the object's mass distribution and geometry.

ω is the angular velocity, a measure of how fast an object rotates about a specific axis, and is typically expressed in radians per second (rad/s).

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Related Questions

Use the Pythagorean Theorem to find the velocity of an airplane traveling north at 100 kilometers per hour. It is also flying through a wind that is blowing west at 30 kilometers per hour.

Answers

Answer:

I'm not sure

Explanation:

HAVE FAITH IN UR SELF AND YOU WILL GETT ITTTT HOPEFULLAYY

what causes short sightedness ?how is it corrected

Answers

Answer:

Short sight occurs when the eyeball is too long or the lens is too thick, or both. As a result, light rays from distant objects are focused in front of the retina (because the light rays are highly converged). The image formed on the retina is therefore out of focus.

Short sight can be corrected by wearing glasses with concave lenses. Light rays from distant objects are diverged by concave lenses before entering the eyes, so that light can be focused on the retina to form a sharp image.

the question says "___________________ was the inventer of the radio?
please answer it

Answers

I believe it’s Guglielmo Marconi

An electric lamp is marked 240v, 60w
It is left to operate for 1h. How much
heat is generated by the lamp

Answers

Answer:

H = 0.06 kWh

Explanation:

Given that,

Power of an electric lamp, P = 60 W

Voltage, V = 240 V

It is operated for 1 hour

We need to find the heat generated by the lamp. Heat generated is given by :

\(H=P\times t\\\\H=60\ W\times 1\ h\\\\H=60\ Wh\\\\H=0.06\ kWh\)

So, 0.06 kWh of the heat is generated by the lamp.

62. Two forces are acting on the ring in Figure 22. What is the net force acting on the ring?

Answers

We have that force forces on a plane we Resolve to the x plane and the y plane then we derive the corresponding result using the equation

\(R=\sqrt{(\sum fx)^2+(\sum fy)^2}\)

From the question we are told

Two forces are acting on the ring in Figure 22. What is the net force acting on the ring.

Force

Generally the equation for the Net Force  is mathematically given as

\(R=\sqrt{(\sum fx)^2+(\sum fy)^2}\)

Therefore

For two forces

We Resolve to the x plane and the y plane then we derive the corresponding result using the equation

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how much solar radiation does the earth intercept from the sun?

Answers

The amount of solar radiation that the Earth intercepts from the Sun varies depending on several factors, including the distance between the Earth and the Sun, the Earth's orbital eccentricity, and atmospheric conditions.

On average, the Earth intercepts about 1,366 watts per square meter (W/m²) of solar radiation outside of the Earth's atmosphere. This value is known as the solar constant. However, due to various factors, including the Earth's atmosphere, not all of this solar radiation reaches the surface. The atmosphere absorbs, scatters, and reflects a portion of the incoming solar radiation. The actual amount of solar radiation that reaches the Earth's surface depends on factors such as the angle of incidence, cloud cover, aerosols, and the specific location and time of year.

On average, about 70% of the solar radiation that reaches the top of the Earth's atmosphere makes it through the atmosphere and reaches the surface. Therefore, the average amount of solar radiation that reaches the Earth's surface is approximately 957 W/m². It's important to note that these values are averages and can vary depending on various factors and geographical locations.

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To maintain a constant speed, the force provided by a car's engine must equal the drag force plus the force of friction of the road (the rolling resistance). Assume all values are accurate to three significant digits. (Assume the density of air is 1.21 kg/m3.) (a) What is the magnitude of drag force (in N) at 58 km/h and 110 km/h for a Toyota Camry

Answers

The magnitude of the drag force on a Toyota Camry is approximately 473.68 N at 58 km/h and 1550.85 N at 110 km/h.

To calculate the magnitude of the drag force on a Toyota Camry at different speeds, we can use the formula:

Drag Force = (1/2) × Cd × A × ρ × v²

where Cd is the drag coefficient, A is the cross-sectional area of the car, ρ is the density of air, and v is the velocity of the car.

Given:

Cd = 0.28 (drag coefficient for a Toyota Camry)

A = 2.2 m² (estimated cross-sectional area of a Toyota Camry)

ρ = 1.21 kg/m³ (density of air)

Speed at 58 km/h = 58 km/h × (1000 m/km) / (3600 s/h) ≈ 16.11 m/s

Speed at 110 km/h = 110 km/h × (1000 m/km) / (3600 s/h) ≈ 30.56 m/s

Now we can calculate the drag force at each speed:

Drag Force at 58 km/h:

Drag Force = (1/2) × 0.28 × 2.2 m² × 1.21 kg/m³ × (16.11 m/s)²

Drag Force ≈ 473.68 N

Drag Force at 110 km/h:

Drag Force = (1/2) × 0.28 × 2.2 m² × 1.21 kg/m³ × (30.56 m/s)²

Drag Force ≈ 1550.85 N

Therefore, the magnitude of the drag force on a Toyota Camry is approximately 473.68 N at 58 km/h and 1550.85 N at 110 km/h.

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HELP PLS. WILL GIVE OUT BRAINLIEST!!!

What word is used to refer to a group of organ systems working together?

organism
cell
tissue
organ

Answers

Answer:

organism

Explanation:

In the systems

First is

1.cell

group of cells is

2. Tissue

group of tissues

3. Organ

group of organs

4. Organ system

group of organ systems

5.Organism

Organism

EXPLANATION: I did this

For vibrational motion, what term denotes the maximum displacement from the equilibrium position?.

Answers

For vibrational motion, the amplitude denotes the maximum displacement from the equilibrium position.

What is vibrational motion?

The motion in which there are some vibrations about the fixed position called mean position is termed vibrational motion. For example, the motion of a wave on the string has perpendicular vibration.

What is amplitude?

The amplitude is defined as the maximum displacement of the vibration from its mean position. For vibrational motion, the mean position is the equilibrium position. So amplitude is the term that denotes the maximum displacement from the equilibrium position. For example, the displacement of the string wave from its equilibrium position is the amplitude of the string wave.

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Compound microscopes focus light through ______ to produce a magnified image.

Answers

Igiydbvvyicdiybbbvugbdjgcdyfvvuybs hdiyggfvyfvsgucstyfstufvvugvdugdd

Diffraction of white light with a single slit produces bright lines of different colors.What is the color of the central image?

Answers

Answer:

white

Explanation:

This experiment causes lines of different colors because the constructive interference depends on the wavelength, so for different wavelength, the position of the maximum will be different.

Now, in diffraction fo a single slit we always have a central maximum (for all the colors)

This means that after the diffraction, we will have that all the colors have a maximum in the center, which will produce white light again, then the color of the central image is white

What will happen to people involved in handling Gamma rays if they are not providedwith lead coated apron and equipment without safety measures❤

Answers

Answer:

When gamma rays pass through the human body, they ionize the tissue.  gamma ray ionization can affect healthy cells. When high levels of gamma rays bombard a body, a resulting dangerous ionization of tissue can cause skin cancer.

Explanation:

A beam of electrons is accelerated from rest along the x-axis through a potential difference of 20.0 V. It is then directed at a single slit of width 1.00 x 10-4 m, and the width of the central maximum on a distant screen is measured to be Ay = 5.00x10-4 m. (a) Find the distance from the slit to the screen. [2] (b) What is the uncertainty Apy in the y-momentum of each electron striking this central maximum?

Answers

The distance from the slit to the screen is not provided in the given information, so it cannot be determined. The uncertainty in the y-momentum the central maximum is at least 2.65 × 10^-26 kg m/s.

B. Explanation:

(a) To find the distance from the slit to the screen, we can use the formula for the diffraction pattern from a single slit:

y = (λL) / (w)

where y is the width of the central maximum, λ is the de Broglie wavelength of the electrons, L is the distance from the slit to the screen, and w is the width of the slit.

We can rearrange the formula to solve for L:

L = (y * w) / λ

The de Broglie wavelength of an electron is given by the equation:

λ = h / p

where h is the Planck's constant (6.626 × 10^-34 J s) and p is the momentum of the electron.

The momentum of an electron can be calculated using the equation:

p = √(2mE)

where m is the mass of the electron (9.10938356 × 10^-31 kg) and E is the energy gained by the electron.

The energy gained by the electron can be calculated using the equation:

E = qV

where q is the charge of the electron (1.602 × 10^-19 C) and V is the potential difference through which the electrons are accelerated.

Substituting the given values:

E = \((1.602 ×*10^{-19} C) * (20.0 V) = 3.204 * 10^{-18} J\)

Now we can calculate the momentum:

p = \(\sqrt{2} * (9.10938356 * 10^{-31 }kg) * (3.204 × 10^{-18 }J)) ≈ 4.777 * 10^{-23} kg m/s\)

Substituting the values of y, w, and λ into the formula for L:

L = \(((5.00 ×*10^{-4 }m) * (1.00 * 10^{-4 }m)) / (4.777 ×*10^{-23 }kg m/s) = 1.047 * 10^{16} m\)

Therefore, the distance from the slit to the screen is approximately 1.047 × 10^16 meters.

(b) The uncertainty in the y-momentum of each electron striking the central maximum, Apy, can be calculated using the uncertainty principle:

Apy * Ay ≥ h / (2Δx)

where Δx is the uncertainty in the position of the electron in the y-direction.

Since we are given the width of the central maximum Ay, we can take Δx to be half the width:

Δx = Ay / 2 = (5.00 × 10^-4 m) / 2 = 2.50 × 10^-4 m

Substituting the values into the uncertainty principle equation:

\(Apy \geq (5.00 * 10^{-4} m) ≥ (6.626 * 10^{-34 }J s) / (2 * (2.50 * 10^{-4} m))\)

\(Apy \geq (6.626 * 10^{-34 }J s) / (2 * (2.50 * 10^{-4} m * 5.00 * 10^{-4} m))\)

\(Apy \geq (6.626 * 10^{-34 }J s) / (2.50 * 10^{-8} m^2)\)

\(Apy \geq 2.65 * 10^{-26} kg m/s\)

Therefore, the uncertainty in the y-momentum of each electron striking the central maximum is at least 2.65 × 10^-26 kg m/s.

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The Voyager 1 space probe was launched by NASA in 1977. It's now the most distant spacecraft from Earth, as it hurtles into space at over 60,000 km/h. It has run out of fuel, so it can't change its own motion.

One of your friends says, "If Voyager 1 doesn't collide with anything and is too far from anything to be affected by gravity, it will gradually slow down and stop."

I have to either agree or disagree with my friend, then i have to explain.

Answers

The statement, "The Voyager 1 space probe can't change its own motion" is correct and true. The Voyager 1 space probe was launched by NASA in 1977, and since then it has traveled over 14 billion miles away from Earth. It's the most distant spacecraft from Earth.

The Voyager 1 was designed to study the outer solar system and it sent valuable data back to Earth. But, now it has run out of fuel and cannot change its own motion as the thrusters that are responsible for keeping the spacecraft’s antenna pointed toward Earth have to be continuously fired to compensate for the small natural imbalances in its motion. Therefore, the statement is correct that Voyager 1 cannot change its own motion. It is still continuing its journey into space at a speed of over 60,000 km/h and is expected to keep traveling until it reaches other stars and the next galaxy beyond our Milky Way. So, I agree with the statement that the Voyager 1 space probe can't change its own motion.

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what are three assumptions of the kinetic molecular theory​

Answers

Kinetic molecular theory is based on the following postulates, or assumptions:
1. Gases are composed of a large number of particles that behave like hard, spherical objects in a state of constant, random motion.
2. These particles move in a straight line until they collide with another particle or the walls of the container.
3. These particles are much smaller than the distance between particles. Most of the volume of a gas is therefore empty space.

Zach, whose mass is 85 kg, is in an elevator descending at 8 m/s. The elevator takes 3.2 s to brake to a stop at the first floor.What is Zach's weight while the elevator is braking?

Answers

Explanation:

acceleration = 8/3.2 = 2.5m/s² ( acceleration due to gravity = g ).

mass = 85 kg.

weight = mg = 85×2.5 = 212.5N .

hope this helps you.

Which process is involved in the formation of a galaxy

Answers

Answer:

SUN

Explanation:

EARTH

the process that is involved in the formation of the galaxy is the sun

How many seconds will it takes to stop?

How many seconds will it takes to stop

Answers

In order to find the time it takes, first let's convert the distance from miles per hour to feet per second: calculate the acceleration using Torricelli's equation

\(40\text{ mph}=40\cdot1.467\text{ ft/s}=58.7\text{ ft/s}\)

Then, let's :

\(\begin{gathered} V^2=V_0^2+2\cdot a\cdot d\\ \\ 0^2=58.7^2+2\cdot a\cdot50\\ \\ 100a=-3445.7\\ \\ a=-34.46\text{ ft/s^^b2} \end{gathered}\)

Now, we calculate the time with the formula below:

\(\begin{gathered} \Delta S=V_0t+\frac{at^2}{2}\\ \\ 50=58.7t-17.23t^2\\ \\ -17.23t^2+58.7t-50=0\\ \\ t=\frac{-58.7\sqrt{58.7^2-4\cdot(-17.23)\cdot(-50)}}{2\cdot(-17.23)}\\ \\ t_1=t_2=1.7 \end{gathered}\)

Therefore the time required is 1.7 seconds.

A 13kg box slides 4.0m down a frictionless ramp, then collides with a spring whose spring constant is 170 N/m. At what compression of the spring does the box have its maximum speed?

Answers

From the question, the compression that is able to produce the maximum speed is 1.73 m.

What compression has the maximum speed?

We can see that there is potential energy stored in the spring. This energy can be converted into kinetic energy when a spring is released. In this case, the spring can now be able to do a meaningful work as we can see.

The image that shows the set up of the question can be seen clearly in the image that is attached to this answer as we can see. We can now write the following;

W = dmgsin∅

Where W is the work done by the spring, we have;

1/2 kx² = dmgsin∅

k = force constant

x = compression

d = distance covered

∅ = angle covered

Thus we can substitute the values as;

(0.5 * 170 * x²) = 4 * 13 * 9.8 * sin 30

x² = 4 * 13 * 9.8 * sin 30/0.5 * 170

x² = 254.8/85

x = 1.73 m

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A 13kg box slides 4.0m down a frictionless ramp, then collides with a spring whose spring constant is

A bungee jumper,of mass 49 kg,is attached to one end of a light elastic cord of natural length 22 metres and modulus of elasticity 1078 newtons.The other end of the cord is attached to a horizontal platform,which is at a height of 60 metres above the ground. The bungee jumper steps off the platform at the point where the cord is attached and falls vertically.The bungee jumper can be modelled as a particle.Assume that Hooke's Law applies whilst the cord is taut, and that air resistance is negligible throughout the motion. When the bungee jumper has fallen x metres,his speed is vm s-1 (a) By considering energy,show that when x is greater than 22 5v2=318x-5x2-2420 (6) (b) Explain why x must be greater than 22 for the equation in part (a) to be valid. (1) (c) Find the maximum value of x. (4) (d) (i) Show that the speed of the bungee jumper is a maximum when x =31.8. (3) (ii) Hence find the maximum speed of the bungee jumper.

Answers

(a) The equation derived from energy considerations is

5v² = 318x - 5x² - 2420.

(b) To ensure the validity of the equation, x must be greater than 22 meters.

(c) The maximum value of x, when the cord is fully stretched, is approximately 4.45 meters.

(d) (i) At x = 31.8 meters, the speed of the bungee jumper is maximized according to the derived equation.

(d) (ii) The maximum speed of the bungee jumper is approximately 25.2 m/s, obtained from the equation and analysis of energy conservation.

How can the motion of the bungee jumper be analyzed using energy considerations?

(a) By considering energy, we can analyze the motion of the bungee jumper. Initially, the bungee jumper is at a height of 60 meters above the ground.

As the jumper falls, the elastic cord stretches and exerts an upward force on the jumper due to Hooke's Law.

The total energy of the system is conserved, and it can be divided into two components:

gravitational potential energy (GPE) and elastic potential energy (EPE).

At the top of the fall (x = 0), all the energy is in the form of GPE:

        GPE = mgh (Gravitational potential energy)

When the bungee jumper has fallen x meters, his speed is vm m/s.

At this point, his potential energy has been converted into kinetic energy (KE) and elastic potential energy:

           KE = (1/2)mv² (Kinetic energy)

          EPE = (1/2)kx² (Elastic potential energy)

Since air resistance is negligible, the total energy remains constant:

           GPE + EPE = KE

          49 * 9.8 * 60 + (1/2)(1078)x² = (1/2) * 49 * v²

Substituting the given values:

          5v² + 318x - 5x² = 2420

(b) The equation in part (a) is derived under the assumption that the cord is taut and stretched.

For the cord to be taut and stretched, the distance fallen (x) must be greater than the natural length of the cord (22 meters). If x is less than or equal to 22, the cord would not be stretched, and Hooke's Law would not be applicable. Therefore, x must be greater than 22 for the equation to be valid.

(c) To find the maximum value of x, we need to determine the point at which the bungee cord reaches its maximum stretch.

At this point, the bungee cord is fully stretched, and the upward force from the cord is equal to the weight of the jumper.The maximum stretch of the cord occurs when the upward force from the cord (kx) is equal to the weight of the jumper (mg):

              kx = mg

         1078x = 49 * 9.8

                 x = (49 * 9.8) / 1078

                 x ≈ 4.45 meters

Therefore, the maximum value of x is approximately 4.45 meters.

(d) (i) To find the speed of the bungee jumper when it is at a maximum, we can differentiate the equation derived in part (a) with respect to x and set it equal to zero to find the maximum point.

Differentiating the equation:

     d(5v² + 318x - 5x²) / dx = 0

                            318 - 10x = 0

                                    10x = 318

                                        x = 31.8 meters

(ii) Now that we have the value of x at the maximum speed, we can substitute it back into the equation to find the maximum speed (vm):

       5v² + 318(31.8) - 5(31.8)² = 2420

       5v² ≈ 3178.4

         v² ≈ 635.68

        v ≈ √(635.68)

        v ≈ 25.2 m/s

Therefore, the maximum speed of the bungee jumper is approximately 25.2 m/s.

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when the car you are riding in stops suddenly, heavy objects move toward the front of the car. explain why a helium-filled balloon will move toward the rear of the car.

Answers

Inertia is the tendency of an object to resist any change in its state of motion. When a car suddenly stops, the heavy objects in the car tend to continue moving forward due to their inertia. However, the helium-filled balloon moves towards the rear of the car because of the same principle.

The reason for this is that the helium-filled balloon is less dense than the air around it. When the car stops suddenly, the air inside the car continues to move forward due to its inertia, but the balloon, being less dense, experiences less force and moves relatively backward. This is because the balloon is not affected by the same amount of inertia as the heavy objects in the car.

The balloon moves towards the rear of the car due to its lower density compared to the air around it, which causes it to experience less force when the car stops suddenly. This is an interesting example of how the concept of inertia affects different objects in different ways.

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an aluminum rod with a initial length of 15 m and a diameter of 37 mm is subjected to an axial tensile load of 65 kn. calculate its elongation (mm). 0.2390.02390.0023923.9

Answers

The elongation of the aluminium rod subjected to an axial tensile load is 0.00239 mm. So, the 3rd option is correct.

It is given to us that -

Initial length of the aluminium rod = 15 mm

Diameter of the aluminium rod = 37 mm

Axial tensile load on the aluminium rod = 65 kN

We have to find out the elongation of the aluminium rod in mm.

The deformation (in this case, elongation) of an aluminium rod with specific length and diameter which is subjected to an axial tensile load can be represented in the form of an equation given by -

δ = \(\frac{P*L}{A*E}\) ----- (1)

where,

δ = Deformation of the rod

P = Axial tensile load

L = Length of the rod

A = Area of the rod

E = \(2*10^{5}\) \(N/mm^{2}\)

According to the given information, we have

P = 65kN = \(65*10^{3}\) N

L = 15 mm

A = \(\frac{\pi }{2} d^{2}\) where d is diameter of rod

Substituting these values in equation (1), we have

δ = \(\frac{P*L}{A*E}\)

=> δ = \(\frac{65*10^{3}*15}{\frac{\pi }{2} (37)^{2}*2*10^{5}}\)

=> δ = 0.00239 mm

Thus, the elongation of the aluminium rod subjected to an axial tensile load is 0.00239 mm. So, the 3rd option is correct.

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Which of the following does not contribute to the potential energy of an object?
Оа Gravitational constant, org, of the Earth
b Height of the object above the Earth's surface
Mass of the object
d Velocity of the object

Answers

Answer:

A. Gravitational constant

Velocity of an object does not contribute to the potential energy of an object.

What is total energy ?

Total energy of any object under consideration is the sum of potential energy (P.E) and kinetic energy (K.E) and is constant throughout the motion.

The energy possessed by a body due to its position or configuration is known as potential energy. when an object is at rest, velocity is equal to zero, thus velocity of the object doesn't contribute to potential energy, it only depends upon gravitational constant "g", height of the object above the Earth's surface and mass of the object.  

Therefore, Velocity of an object does not contribute to the potential energy of an object.

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which one of the following statements concerning the antiparticle of the proton is true? options: a) the antiproton has a positive charge and a negative mass. b) the antiproton has no charge and a positive mass. c) the antiproton has a negative charge and a negative mass. d) the antiproton has no charge and a negative mass. e) the antiproton has a negative charge and a positive mass.

Answers

The antiproton, which is the antiparticle of the proton, has a negative charge and a positive mass. option e) is The correct statement concerning the antiparticle of the proton

The correct statement concerning the antiparticle of the proton is option e) the antiproton has a negative charge and a positive mass.

1. An antiparticle is a particle that has the same mass as its corresponding particle but with opposite charge.

2. The proton has a positive charge and a positive mass.

3. According to the concept of antimatter, the antiparticle of the proton is called the antiproton.

4. Since it is an antiparticle, the antiproton must have the opposite charge of the proton, which is negative.

5. However, the mass of the antiparticle remains the same as its corresponding particle, which means the antiproton has a positive mass.

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A container of carbon dioxide has a volume of 315 cm³ at a temperature of 25°C if the pressure remains constant what is the volume of 54°C

Answers

Answer:

680.4

Explanation:

the formula is V1 over T1 is equals (=) to V2 over T2 .

and we have been given that

V1 represents 315

T1 represents 25°c

V2 is unknown and what we're finding

T2 represents 54°c

so 315×54 all over 25 ...gives you 680.4

A 33-N force is applied to a 7-kg object to move it with a constant velocity of 6.3 m/s across a level surface. The coefficient of friction between the object and the surface is approximately ____. Round your answer to the hundredths place.(Use the approximation g ≈ 10 m/s2.)

Answers

Given:

The applied force is,

\(F=33\text{ N}\)

The mass of the object is,

\(m=7\text{ kg}\)

The constant velocity of the object is,

\(v=6.3\text{ m/s}\)

To find:

The coefficient of friction between the object and the surface

Explanation:

The object is moving with a constant velocity which means the object is under equilibrium. So, the applied force is equal to the frictional force on the object.

If the coefficient of friction between the object and the surface is

\(\mu\)

we can write the frictional force as,

\(f=\mu mg\)

For equilibrium condition,

\(\begin{gathered} \mu mg=F \\ \mu=\frac{F}{mg} \\ \mu=\frac{33}{7\times10} \\ \mu=0.47 \end{gathered}\)

Hence, the coefficient of friction between the object and the surface is 0.47.

67.0mi/hr to m/s
please show work

Answers

After the arrow, I rounded to the nearest hundredth
67.0mi/hr to m/s please show work

What is 45 °F in °C?

Answers

The temperature conversion formula between Fahrenheit (°F) and Celsius (°C) is as follows: °C = (°F - 32) x 5/9. This formula can be used to convert a temperature measured in Fahrenheit to its equivalent in Celsius.

To convert 45 °F to °C, we can substitute 45 for °F in the formula and perform the calculation:

°C = (45 - 32) x 5/9

°C = 13.33

So 45 °F is equivalent to 13.33 °C.

It's important to note that the Fahrenheit and Celsius scales are different and not directly comparable. The freezing point of water is 32 °F (0 °C) and the boiling point of water is 212 °F (100 °C) on the Fahrenheit scale. While on the Celsius scale, the freezing point of water is 0 °C and the boiling point of water is 100 °C.

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the volume of a gas is proportional to the temperature of a gas is known as

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Charles's law means that the volume of a gas is directly proportional to its absolute temperature

Simple Gas Laws - Boyle's Law, Charles' Law

Boyle's Law tells us that the volume of a gas increases as the pressure decreases. Charles's law tells us that the volume of a gas increases with increasing temperature

This is stated by Karl's law, also known as the law of volumes

For a dry gas sample, its volume and Kelvin temperature are directly proportional if the pressure is kept constant

Mathematical representation -

 \(\begin{equation*} PV=nRT \end{equation*}\)           P : is a Pressure(Pa)

  \(\begin{equation*} V=\frac{nRT}{P} \end{equation*}\)              V : is volume (\(m^{3}\))

                              T : absolute temperature (K)

                              R : gas constant \(\begin{equation*} 8.314K^{-1}.mol^{-1} \end{equation*}\)

                               n : amount of substance of the gas (mole)

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According to "Take a Closer Look", what type of lens does a camera contain? science

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Answer:

convex write convex only don't write convex lens

Explanation:

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