Monochromatic light of wavelength 637 nm is incident on a narrow slit. On a screen 1.89 m away, the distance between the second diffraction minimum and the central maximum is 1.51 cm.


a. Calculate the angle of diffraction θ of the second minimum.

b. Find the width of the slit.

Answer:

A collision is an interaction between two objects that have made contact (usually) with each other. As in any interaction, a collision results in a force being applied to the two colliding objects. Newton's laws of motion govern such collisions

An interaction between two items that have made contact with one another  is referred to as a collision. A collision exerts a force on the objects interacting, just like any other interaction. Such collisions are regulated by Newton's laws of motion.

In physics, a collision, which is also known as an impact, is the abrupt, violent coming together and in near vicinity of two bodies, such as two pool cues, a golf club and a ball, a hammer as well as a nail, two railroad cars when linked, or a falling item and a floor.

The force and the amount of time the objects are in touch, in addition to the materials the two objects are made of, have an impact on the outcome of the impact. Generally,is common knowledge that a hardened steel ball bounced on a steel plate would rebound almost to the original position from where it was dropped, while a ball made of putty and lead will not.

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The work done by the field F when the object moves along the given path from the initial point to the final point is 13/4.

To calculate the work done by the field F when the object moves along the given path from the initial point to the final point, we can use the line integral of the dot product between the field and the path:

W = ∫ F · dr

where W is the work done, F is the field, dr is the differential displacement vector along the path, and the integral is taken over the path from the initial point to the final point.

Given that F(x, y, z) = 5xy, 4yz, 6xz, and r(t) = t, t², t³ for 0 ≤ t ≤ 1, we need to calculate the dot product F · dr and integrate it along the path.

First, let's express dr in terms of t:

dr = dx i + dy j + dz k

  = (dx/dt) dt i + (dy/dt) dt j + (dz/dt) dt k

  = dt i + (2t) dt j + (3t²) dt k

Now, let's calculate the dot product F · dr:

F · dr = (5xy) dx + (4yz) dy + (6xz) dz

      = (5xy) (dx/dt) dt + (4yz) (dy/dt) dt + (6xz) (dz/dt) dt

      = 5xy dt + 4yt² dt + 6xt³ dt

Substituting the values of x, y, and z from r(t):

F · dr = 5(t)(t²) dt + 4(t²)(t²) dt + 6(t)(t³) dt

      = 5t³ dt + 4t⁴ dt + 6t⁴ dt

      = (5t³ + 4t⁴ + 6t⁴) dt

      = (5t³ + 10t⁴) dt

Now, we can integrate the dot product F · dr along the path from t = 0 to t = 1:

W = ∫ (5t³ + 10t⁴) dt

 = (5/4)t⁴ + (10/5)t⁵ + C

Evaluating the integral at the limits:

W = [(5/4)(1)⁴ + (10/5)(1)⁵] - [(5/4)(0)⁴ + (10/5)(0)⁵]

 = (5/4) + (10/5)

 = 5/4 + 2

 = 13/4

Complete Question: Calculate the work done by the field F when the object moves along the given path from the initial point to the final point. F(x, y, z) = 5xy, 4yz, 6xz , r(t) = t, t2, t3 for 0 ≤ t ≤ 1

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The cost of method because the source's pace procedures the velocity of sound transferring to the proper will be 1/2fs.

When each movements withinside the same route with same velocity n' = n, i.e. there can be no Doppler impact because of the truth relative motion amongst deliver and listener is zero.

The motion of the observer will adjust the frequency of the measured sound from a table certain deliver: An observer moving in the direction of the deliver measures a higher frequency. An observer moving a ways from the deliver measures a lower frequency.

The Doppler impact is an alteration withinside the determined frequency of a legitimate due to motion of each the deliver or the observer. The actual trade in frequency is called the Doppler shift.

It will cause an increase in frequency heard thru an observer at the same time as the deliver is moving withinside the direction of the observer and a decrease in frequency heard thru an observer at the same time as the deliver is moving a ways from the observer. The doppler impact can be determined at the same time as an ambulance with a siren on procedures and passes an observer.

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Answer:

62.5 m

Explanation:

.......................................

Part A:

To calculate the average number of stars we would have to search before expecting to hear a signal, we need to determine the fraction of stars that are likely to have civilizations broadcasting radio signals.

Given that there are 5×10^6 civilizations broadcasting radio signals and 500 billion (5×10^11) stars in the Milky Way Galaxy, we can calculate the fraction as follows:

Fraction = (Number of civilizations) / (Total number of stars)

= 5×10^6 / 5×10^11

= 1/10^5

= 0.00001

This fraction represents the probability that a random star has a civilization broadcasting radio signals. To find the average number of stars we need to search, we can take the reciprocal of this fraction:

Average number of stars = 1 / Fraction

= 1 / 0.00001

= 100,000

Therefore, on average, we would have to search approximately 100,000 stars before expecting to hear a signal.

Part B:

If there are only 100 civilizations instead of 5×10^6, we can recalculate the average number of stars we would have to search.

Using the same formula as before, but with the updated number of civilizations:

Fraction = (Number of civilizations) / (Total number of stars)

= 100 / 5×10^11

= 1/5×10^9

= 0.2×10^(-9)

Taking the reciprocal of this fraction gives us:

Average number of stars = 1 / Fraction

= 1 / (0.2×10^(-9))

= 5×10^8

Therefore, if there are only 100 civilizations, on average, we would have to search approximately 500 million stars before expecting to hear a signal.

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Bohr's model helped to explain how electrons could only change orbits by exchanging or absorbing energy in fixed quanta.

For instance, if an electron jumps into an orbit that is one orbit closer to the nucleus, it will have to expel energy equal to the energy difference between the two orbits.

A small positively charged nucleus is encircled by rotating negatively charged electrons in set orbits, according to the Bohr Atomic Model.

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The distributor's job is to distribute refrigerant equally throughout the circuiting of the evaporator. As the expansion valve's larger nozzle opens, the distributor maintains a constant flow rate.

An essential piece of machinery in the HVAC sector is the Thermal Expansion Valve (TXV). The valve's function is to regulate the flow of refrigerant into the evaporator section. In this manner, it regulates the discrepancy between superheat and the refrigerant temperature that is currently present at the evaporator outlet.

The thermal expansion relief valve works similarly to an expansion tank by taking up the extra pressure that thermal expansion causes in the plumbing system.

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According to the given statement , the next charge on the object with an excess of 2.15 x 10²⁰ protons is 3.44 C (coulombs).

The next charge on an object can be determined by considering the excess protons it has. Each proton has a charge of +1.6 x 10⁻¹⁹ coulombs.

Given that the object has an excess of 2.15 x 10²⁰ protons, we can calculate the total charge by multiplying the number of protons by the charge of each proton:

Total charge = (2.15 x 10²⁰ protons) * (1.6 x 10⁻¹⁹ C/proton)

To perform this calculation, we can use scientific notation. When multiplying numbers in scientific notation, we add the exponents and multiply the coefficients:

Total charge = 2.15 * 1.6 x 10²⁰ * 10⁻¹⁹ C

Now, let's simplify the multiplication:

Total charge = 3.44 x 10 C

The next charge on the object with an excess of 2.15 x 10²⁰ protons is 3.44 C (coulombs).

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Part A: The radius of curvature of the lens surface is approximately 3.17 m. Part B: The focal length of the lens is approximately 1.59 m.

Part A:

To find the radius of curvature of the lens surface, use the formula for the radius of the nth bright ring in a planoconvex lens:

r = √(n × λ × f),

where r = radius of the nth bright ring, λ = wavelength of light, and f = focal length of the lens.

In this case, n = 42 (since the last bright ring is observed at the edge), λ = 580 nm (converted to meters, so λ = 580 × 10⁻⁹ m).

Rearranging the formula, solve for f:

f = r² / (n × λ).

Plugging in the values:

f = (0.021 m²) / (42 × 580 × 10⁻⁹ m).

Calculating this expression gives:

f = 3.17 m.

Therefore, the radius of curvature of the lens surface is approximately 3.17 m.

Part B:

The focal length of the lens can be determined using the formula:

f = R / 2,

where R = radius of curvature.

Plugging in the value for the radius of curvature obtained in Part A:

f = 3.17 m / 2.

Calculating this expression gives:

f = 1.59 m.

Therefore, the focal length of the lens is approximately 1.59 m.

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Since the speed is the same through out, acceleration for the trip will be zero.

Acceleration is the rate at which velocity is changing. It is a vector quantity.

If you ride your bike at a constant speed of 5 m/s for 300 s from your house to the mailbox, your acceleration for the trip will be equal to zero.

Because Acceleration = Change in speed ÷ time

Since the speed is constant, acceleration = 0/time = 0

Therefore, the acceleration for the trip is zero.

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Answer:

0 m/s^2

Explanation:

No change in speed or direction = constant velocity = no acceleration.

For a merry go round with a radius of R=1.8 m and moment of inertia I=184 kg-m^2 is spinning with an initial angular speed of w=1.48 rad/s   is mathematically given as

F= 618.9 N

Generally, the equation for the angular speed  is mathematically given as

w = v/R

Therefore

w= 4.7/1.8

w= 2.611 rad/s

Where total momentum

Tm= 642.96 + 272.32

Tm= 915.28

and total inertia

Ti= 184 + 246.24

Ti= 430.24

In conclusion, centripetal force

F= mrw^2

F = m*R*w2^2

F = 76*1.8*2.127^2

F= 618.9 N

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a merry go round with a radius of R=1.8 m and moment of inertia I=184 kg-m^2 is spinning with an initial angular speed of w=1.48 rad/s in the counter clockwise direction when viewed from above a person with mass m=76 kg and velocity v=4.7 m/s runs on a path tangent to the merry go round once at the merry go round the person jumps on and holds on to the rim of the merry go round angular speed of the merry go round after the person jumps on 2.127 rad/s Once the merry go round travels at this new angular speed with what force does the person need to hold on?

the amount of incoming radiation to earth compare to the amount of outgoing radiation is the amount of incoming radiation must be greater than the amount of outgoing radiation. Hence correct option is A.

Energy that emanates from a source and moves through space at the speed of light is referred to as radiation. This energy has wave-like qualities and is accompanied by an electric field and a magnetic field. The term "electromagnetic waves" can also be used to describe radiation.

The sun is sending radiation which contains all types of radiation, ultraviolet radiation, visible radiation and IR radiation. whatever we feel heat in sun light is called as IR radiation.

Outgoing radiation is nothing but reflected radiation from the surface of the earth, most of the radiation is absorbed by the earth surface and a small amount of radiation is reflected by the sea.

Hence option A is correct.

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The net force on a vehicle that is accelerating at a rate of 1.8 m/s2 is 2100 N. The approximate mass of the vehicle in kg is 1166.67kg.

The word "force" has a clear definition. At this level, calling a force a push or a pull is entirely appropriate. A force is not something an object "has in it" or that it "contains." One thing experiences a force from another. There are both living things and non-living objects in the concept of a force.

The vector sum of the forces exerted on a particle or object is known as the net force. The original forces' impact on the motion of the particle is replaced by the net force, which is a single force.

Force ( F ) is 2100N

Acceleration ( a ) is 1.8m/s²

Mass(m)= ?

According to formula;

Force = mass × acceleration

F= m × a

2100 = m × 1.8

2100 / 1.8 = m

Therefore, m = 1166.6kg.

Thus, The net force on a vehicle that is accelerating at a rate of 1.8 m/s2 is 2100 N. The approximate mass of the vehicle in kg is  1166.67kg.

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Answer:

The  reflected spot will appear to be closer than when  the aquarium was empty.

N1 sin θ1 = N2 sin θ2         N1 is in air and equals 1, N2 is greater than one

θ2 is measured from the vertical and the ray is less than θ1

The distance to spot is less so it appears closer

(Consider a spot directly below the pointer    L1 = N2 L2)

If N2 = 4/3 then L2 would be 3/4 L1

At rest, when travelling at a constant speed, and when in mechanical equilibrium, there is no acceleration and answer choice D is correct.

In mechanics, acceleration describes the rate at which a driving object's velocity changes over time. They are accelerations and vector quantities. The direction of an object's acceleration is determined by the direction of the net force acting on it. Depending on whether an object is moving faster, slower, or in a different direction, its velocity may change. Examples of acceleration include a falling apple, the moon orbiting the earth, and a car that has stopped at a stop sign. The car is positively accelerating if the speed is increasing. As the car slows down, its speed decreases. A decline in speed is referred to as negative acceleration. In both situations, the car is traveling ahead, yet one has a positive acceleration and the other a negative one.

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The initial velocity of the suitcase is 7. 63 m/s The initial velocity of the suitcase can be calculated using the following formula:

u = v0 + at

where u is the final velocity, v0 is the initial velocity, a is the acceleration due to gravity (which is 9.81 m/s^2), and t is the time.

We are given that the suitcase slides 3. 00 m down the ramp, so its displacement on the ramp is 3. 00 m. We are also given that the suitcase then slides an additional 5. 00 m along the floor before coming to a stop. Therefore, the total displacement of the suitcase is 8. 00 m.

Using the formula for displacement, we can calculate the time it takes for the suitcase to slide 8. 00 m:

t = 8. 00 m / 9.81 m/\(s^2\)

t = 0. 81 s

Now we can plug in the values we have found into the formula for the initial velocity:

u = v0 + at

u = 0 + 0. 81 s * 9.81 m/\(s^2\)

u = 7. 63 m/s

Therefore, the initial velocity of the suitcase is 7. 63 m/s.  

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Hope this helps you.

Answer:

\(4.0\; {\rm m}\).

Explanation:

The speed \(v\) of a wave is the distance the wave travels in unit time.

The frequency \(f\) of a wave is the number of cycles completed in unit time. Note that \(1\; {\rm Hz} = 1\; {\rm s^{-1}}\). Thus, for the wave in this question, frequency would be \(f = 85\; {\rm Hz} = 85\; {\rm s^{-1}}\).

The wavelength \(\lambda\) of the wave is the distance travelled in each cycle of the wave. To find wavelength, divide the speed of the wave (distance travelled in unit time) by the frequency of the wave (number of cycles included in that much distance.)

\(\begin{aligned}\lambda &= \frac{v}{f} \\ &= \frac{340\; {\rm m\cdot s^{-1}}}{85\; {\rm s^{-1}}} \\ &\approx 4.0\; {\rm m}\end{aligned}\).

Since these three vehicles would all go the same speed at the bottom if released from the same height, they would not all possess the same amount of kinetic energy because they have different amounts of potential energy.

Kinetic energy is dependent on the velocity of the object as well as its mass. Therefore, the three vehicles, though they have the same speed, would differ in their kinetic energy due to their varying mass. This concept is known as mechanical energy and is the sum of kinetic and potential energy.

Mechanical energy is also constant in an ideal situation where no external forces are acting upon the object. For instance, the three vehicles will all have the same mechanical energy at the release point but would not possess the same amount of kinetic energy due to their mass difference. Therefore, they would have different amounts of potential energy when released.

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In conclusion, the experiment aimed to determine the acceleration due to gravity by measuring the period of a simple pendulum. The experiment was performed by measuring the length of the pendulum and recording the time for 10 oscillations. The data was then used to calculate the average period and subsequently, the acceleration due to gravity using the formula: g = (4π²L)/T².

Based on the results obtained, the acceleration due to gravity was found to be (9.79 ± 0.06) m/s², which is in good agreement with the accepted value of 9.81 m/s². The small discrepancy could be due to the experimental errors such as air resistance, friction and measurement errors.

Overall, the experiment was successful in determining the acceleration due to gravity using a simple pendulum and demonstrated the relationship between the period and the length of the pendulum.

Therefore, the magnitude of vector C is 25.

Given:A = 10x - 2yB = 5x + 4yC=2A + BNow we have to calculate the magnitude of vector C.Let's calculate each part of the vector C first;2A = 2(10x-2y) = 20x - 4yB = 5x + 4yC = 2A + B= (20x-4y)+(5x+4y)=25xNow we can calculate the magnitude of vector C by using the formula;|C| = √(Cx²+Cy²+Cz²)Here, we only have two dimensions, so the formula becomes;|C| = √(Cx²+Cy²)|C| = √(25²) = 25. Therefore, the magnitude of vector C is 25.

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Answer:

Yes but no

Explanation:

Here the kid cant say that he has created s magnetic field as iron fillings do not have magnetic properties

Answer:

inference

Explanation:

inference is when u observe something and make ur own conclusion off of it so it may not be entirely accurate

For an object's sound to not be shifted in frequency, the object must be either stationary or moving directly towards or away from the observer at a constant speed.

The Doppler effect causes a change in the perceived frequency of the sound waves received by the observer, which can make the sound appear higher or lower in pitch depending on the direction of the relative motion.

To ensure that the sound from an object is not shifted in frequency, the object and the observer must have no relative motion with respect to each other. This means that the object must either be stationary with respect to the observer or moving directly towards or away from the observer at a constant speed.

If the object is moving towards the observer, the frequency of the sound waves will appear higher than the original frequency, but if the object is moving away from the observer, the frequency of the sound waves will appear lower than the original frequency

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Answer:

Here is the answer. Hope this helps you!

Explanation:

Average velocity is the sum of initial and final velocity divided by 2. I t is the same as total Displacement divided by total time. Average velocity is calculated when the body is in non-uniform motion (also when total displacement and time is not given). The formula is as follows:

u + v/2 = \(v_{av}\)

Average velocity = Average speed

during motion in a straight line. therefore, the above mentioned formula can be used for calculating average speed as well, when the direction is one and only the same, that is, during motion in a straight line. The S.I unit remains the same-

m/s.

Since velocity is vector, average VELOCITY is also vector. However, Average SPEED is scalar as speed is scalar. both can be equal only when the distance = displacement and when they are following the same direction of motion.

The angular velocity in rad/s is 753.9 rad/s.

The velocity in m/s of the hard drive at a radius of 0.0889 m is 67.02 m/s.

In Mathematics and Physics, the angular velocity of a physical object can be calculated by using this formula:

ω = θ/t

Where:

In order to convert the unit revolutions per minute (RPM) to radians per seconds (rad/s), we would multiply the value by 2π and then divide by 60 as follows;

Angular velocity in rad/s = 7200 × 2π/60

Angular velocity in rad/s = 753.9 rad/s.

At a radius of 0.0889 meters, the velocity of the hard drive in m/s can be calculated as follows;

Velocity = radius × angular velocity

Velocity = 0.0889 × 753.9

Velocity = 67.02 m/s.

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Answer:

I cant read it sorry.

Explanation:

The body is accelerating upward toward the center of the circle it traces out with magnitude

a = v ² / R

where

v = linear speed of the body

R = 3.4 m = radius of the circle it traces/length of the string

The only forces acting on it at the lowest point are the tension T of the string pulling upward on the body and weight W = mg of the body pulling it downward. By Newton's second law, we have

∑ F = T - mg = ma

Replace the acceleration with the expression from earlier and solve for v :

300 N - (17 kg) g = (17 kg) v ² / (3.4 m)

v ² = ((3.4 m) 300 N - (17 kg) g) / (17 kg)

v = √[ ((3.4 m) 300 N - (17 kg) g) / (17 kg) ]

v ≈ 5.16527 m/s ≈ 5.2 m/s