Mountain Dew is a mixture. Which of the following statements could be used to support the claim
that Mountain Dew is a mixture?
a. Mountain Dew is made of only one kind of element.
b. Mountain Dew is made of many elements that are all bonded together.
c. Mountain Dew is made of only one kind of molecule.
d. Mountain Dew is made of many substances that can be separated out.

Answer:

Explanation:

The maximum tension the cord can withstand is 69 N, so we know that the tension in the cord cannot exceed this value. The tension in the cord is related to the acceleration of the truck through Newton's second law:

ΣF = ma

where ΣF is the net force on the crate, m is the mass of the crate, and a is the acceleration of the truck.

In this case, the only force acting on the crate in the horizontal direction is the tension in the cord. Therefore, we can write:

ΣF = T = ma

where T is the tension in the cord.

We can solve this equation for the acceleration:

a = T/m

We know that the tension cannot exceed 69 N, so the maximum acceleration the truck can have before the cord breaks is:

a = 69 N / 26 kg

a ≈ 2.65 m/s^2

Therefore, the maximum acceleration the truck can have before the cord breaks is 2.65 m/s^2.

Given:

The frequency of the wave, f=723 Hz.

To find:

The period of the wave.

Explanation:

The frequency of a wave is the number of the waves that pass through a point per second.

The period of a wave is the time it takes for the wave to complete one cycle.

The period of a wave is given by the inverse of its frequency.

Thus the period of the wave is given by,

On substituting the known value in the above equation,

Final answer:

The period of the wave is 1.38×10⁻³ s.

Answer:

The velocity is  \(v =2.455 \ m/s\)

Explanation:

From the question we are told that  

   The diameter of the pipe is  \(d = 4.25 \ cm = 0.0425 \ m\)

    The magnetic field is  \(B = 0.575 \ T\)

     The hall voltage is  \(V_H = 60.0 mV = 60 *10^{-3} \ V\)

Generally the average fluid velocity is mathematically represented as

          \(v = \frac{V}{ B * d }\)

=>       \(v = \frac{60*10^{-3}}{ 0.575 * 0.0425 }\)

=>       \(v =2.455 \ m/s\)

Explanation:

You can just use Pythagorean theorem to find the resultant mag

20^2 + 100^2 = R^2

mag of R = 102 m/s

The initial velocity of the object in motion is determined as 19.8 m/s.

The initial velocity of the object in motion is calculated by applying the third equation of motion as follows;

v² = u² + 2gh

where;

when the object reaches maximum height, the final velocity, v = 0

The initial velocity of the object in motion is calculated as;

0 =  u² + 2 (-9,8ms²) x 20m​

0 =  u² - 392

u² = 392

u = √392

u = 19.8 m/s

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Answer:

the reading on the scale is 158.5 mm.

Explanation:

Given;

upper fixed point of the temperature scale, x₁ = 260 mm

lower  fixed point of the temperature scale, x₂ = 50 mm

upper temperature scale, T₁ = 212 °F

lower temperature scale, T₂ = 32 °F

thermometer reading, t = 125 °F, let the reading on the scale = x

Interpolate as follows to determine the value of "x"

\(\frac{X_1 - X}{X_1-X_2} = \frac{T_1-t}{T_1-T_2} \\\\\frac{260-X}{260-50} = \frac{212-125}{212-32} \\\\\frac{260 -X}{210} =\frac{87}{180} \\\\180(260-X) = 87(210)\\\\46800 -180 X = 18270 \\\\180X = 46800-18270\\\\180X = 28530\\\\X = \frac{28530}{180} \\\\X = 158.5 \ mm\)

Therefore, the reading on the scale is 158.5 mm.

Answer:

magnitude of the Coriolis acceleration is 44.235 ft/s² and the direction of the acceleration is along the axis of transmission

Explanation:

Given the data in the question;

Speed of carousel N = 24 rpm

From the diagram below, selected path direction defines the Axis of slip.

Hence, The Coriolis is acting along the axis of transmission

Now, we determine the angular speed ω of the carousel.

ω = 2πN / 60

we substitute in the value of N

ω = (2π × 24) / 60

ω = 2.5133 rad/s

Next, we convert the given velocity from mph to ft/s

we know that; 1 mph = 1.4667 ft/s

so

\(V_{slip\) = 6 mph = ( 6 × 1.4667 ) = 8.8002 ft/s

Now, we determine the magnitude of the Coriolis acceleration

\(a_c\) = 2( \(V_{slip\) × ω )

we substitute

\(a_c\) = 2( 8.8002 ft/s × 2.5133 rad/s )

\(a_c\) = 44.235 ft/s²

Hence, magnitude of the Coriolis acceleration is 44.235 ft/s² and the direction of the acceleration is along the axis of transmission

The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J

First, we shall list out the given parameters from the question. This is shown below:

The quantity of heat energy that must be transferred can be obtained as follow:

Q = MCΔT

= 2.25 × 394 × 220

= 195030 J

Thus, we can conclude quantity of heat energy that must be transferred is 195030 J

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The dependent variable in the experiment in which a student sleeps different intervals of time to get different grades is the grade

In this experiment,

An independent variable is the variable that can be altered by the researcher to get different results. The dependent variable is the variable that gets altered due to the change in independent variable.

Therefore, the dependent variable is the Grades

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Answer:

\(\boxed{\text{\sf \Large 42 m}}\)

Explanation:

Use height formula

\(\displaystyle \sf H=\frac{u^2 sin(\theta)^2}{2g}\)

u is initial velocity

θ = 90° (fired vertically upward)

g is acceleration of gravity

\(\displaystyle \sf H=\frac{29^2 \times sin(90 )^2}{2 \times 10}=42.05\)

Cobalt is the element's isotope that is often used to treat cancer patients.

Hence, the correct option is (1)e ek

Answer: COBALT

Explanation:

The element's isotope often used to treat cancer patients is cobalt. Cobalt-60 also known as (60Co) is a radioactive isotope of cobalt that emits gamma radiation. Its used in chemo therapy for cancer patients. Hence 1). Cobalt is the correct answer

The coin's acceleration is 0.37 m/s²

Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.

Calculation:-

V² = U -2aS

a = U/2S

  = 2/2×2.7

   =  0.37 m/s²

Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.

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The speed of the wind is 20 miles per hour.

To solve this problem, we can use the formula:

Speed = Distance/Time

Let's assume that the speed of the wind is x miles per hour.

With the wind, the plane travels at a speed of 460 miles per hour. This means that its speed relative to the ground is the sum of its airspeed and the speed of the wind:

460 = Airspeed + x

Against the wind, the plane travels at a speed of 420 miles per hour. This means that its speed relative to the ground is the difference between its airspeed and the speed of the wind:

420 = Airspeed - x

We can solve this system of equations to find the airspeed of the plane:

460 = Airspeed + x

420 = Airspeed - x

Adding the two equations gives:

880 = 2Airspeed

Dividing both sides by 2 gives:

Airspeed = 440 miles per hour

Now that we know the airspeed of the plane, we can find the speed of the wind by substituting this value into one of the equations we obtained earlier:

460 = Airspeed + x

460 = 440 + x

x = 20

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A) Therefore, the amount of work performed by heart is \($2.9289 \times 10^{-3} \mathrm{~J}\)

b) Therefore, the power require is \($0.013313 \mathrm{~W}\)

c) Therefore, the efficiency of heart is\($0.2219 \%$.\)

A) Calculate the amount of the work performed by the heart during the systole by using the following relation:

\($$\begin{aligned}W & =\frac{1}{2} m_b v^2 \\& =\frac{1}{2}\left(\rho_b A v\right) v^2 \\& =\frac{1}{2} \rho_b A v^3 \\& =\frac{1}{2} \rho_b\left(\frac{\pi}{4} d^2\right) v^3 \\& =\frac{1}{2} \times 1.057 \times 10^3 \times\left(\frac{\pi}{4} \times(0.029)^2\right) \times(0.2032)^3 \\& =2.9289 \times 10^{-2} \mathrm{~J}\end{aligned}$$\)

Therefore, the amount of work performed by heart is \($2.9289 \times 10^{-3} \mathrm{~J}$.\)

b) Calculate the power during systole by using the following relation:

\($$\begin{aligned}P & =\frac{W}{t} \\& =\frac{2.9289 \times 10^{-3}}{0.22} \\& =0.013313 \mathrm{~W}\end{aligned}$$\)

Therefore, the power require is \($0.013313 \mathrm{~W}$.\)

C) Calculate the efficiency of the heart by using the following relation:

\($$\begin{aligned}\eta & =\frac{P_{\text {out }}}{P_{\text {ov }}} \\& =\frac{0.013313}{6} \\& =0.0022188(0.2219 \%)\end{aligned}$$\)

Therefore, the efficiency of heart is\($0.2219 \%$.\)

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Answer: Railroad engineering ideas

The velocity of the car along east direction  must be 34.94 m/s.

In physics momentum of any object can be defined as product of velocity and mass. As velocity is a vector quantity, momentum is also a vector quantity. So, to define momentum both magnitude and direction are required.  SI unit of momentum is kg-m/s.

Mass of the car = 1370 kg.

Mass of the   pickup truck a = 2280 kg

Momentum of the  pickup truck along east = 2280 kg × 21 m/s

= 47880 kg-m/s.

Hence, velocity of the car along east direction = (47880/1370) m/s

= 34.94 m/s.

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With an initial horizontal velocity of 32.31 m/s and a time of 3.23 seconds to impact the earth, the projectile was launched.

When an object is hurled horizontally in projectile motion, it has zero initial vertical velocity and only a horizontal initial velocity. Through the projectile's entire motion, the original horizontal velocity is maintained.

\(y = 1/2 * a_y * t^2\)

\(t^2 = 2y / a_y\)

\(t = sqrt(2y / a_y)t = sqrt(2*75.72 m / 9.81 m/s^2)\)

t = 3.23 s (rounded to two decimal places)

\(x = vi_x * t\)

\(vi_x = x / t\)

\(vi_x = 104.42 m / 3.23 s\)

\(vi_x = 32.31 m/s\)(rounded to two decimal places)

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Displacement is a vector magnitude that depends on the position of the body which is individualistic for the trajectory.

While, Distance is a scalar magnitude that measures over the trajectory.

Answer:

A

Explanation:

Answer:

The characteristics that determine how easily two substances change temperature are:

The volume and density of the substances and the amount of time they are in contact do not directly affect how easily they change temperature.

Explanation:

Answer:

Erosion is the wearing away if land by forces such as water and wind. It has created things such as mountain peaks, valleys and coastlines.

Answer:

35 N to the left

Explanation:

Do 65 minus 30, and you get 35 N to the left

Because force is a vector quantity, you have to mention both magnitude and direction in your answer.

The magnitude of the force on the tooth is approximately 0.022 N.

To find the magnitude and direction of the force on the tooth, we can use Hooke's Law, which states that the force exerted on an object is directly proportional to the change in length of a material when it is stretched or compressed.

First, we need to calculate the strain (ε) of the stainless-steel wire.

Strain is defined as the change in length divided by the original length:

ε = ΔL / L₀

Given that the change in length (ΔL) is 0.10 mm \((0.10 \times 10^{-3} m)\) and the unstretched length (L₀) is 3.1 cm \((3.1 \times 10^{-2} m)\), we can calculate the strain:

\(\epsilon=(0.10 \times 10^{-3} m)/(3.1 \times 10^{-2} m)=0.003225\)

Next, we can use Young's modulus (E) to calculate the stress (σ) in the wire.

Stress is defined as the force per unit area:

σ = E * ε

Given that Young's modulus (E) for stainless-steel is 18 × 10¹⁰ N/m², we can calculate the stress:

σ = (18 × 10¹⁰ N/m²) * 0.003225 = 5.805 × 10⁸ N/m²

Now, we can find the force (F) on the tooth by multiplying the stress by the cross-sectional area (A) of the wire:

F = σ * A

The cross-sectional area (A) can be calculated using the formula for the area of a circle:

A = π * (d/2)²

Given that the diameter (d) of the wire is 0.22 mm\((0.22 \times 10^{-3} m)\), we can calculate the cross-sectional area:

\(A = \pi * (0.22 \times 10^-3 m / 2)^{2} = 3.802 \times 10^{-8} m^2\)

Finally, we can calculate the force:

\(F = (5.805 \times 10^{8} N/m^{2}) * (3.802 \times 10^-8 m^{2}) \approx 2.206 \times 10^{-2} N\)

Therefore, the magnitude of the force on the tooth is approximately 0.022 N.

Since the wire is stretched, the force is pulling the tooth in the direction opposite to the stretching.

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The difference between fluid pressure at location 2 and fluid pressure at location 1 is mathematically given as

dP = 114 kPa

Parameters are :

density of liquid,

speed of flow at location 1, = 9.15m/s

diameter of pipe at location 1, = 12.3cm

diameter of pipe at location 2, = 16.1 cm

height of pipe at location 1, = 9.29 m

We know that the Bernoulli's equation is mathematically given as

P + ρ*g*y + v² =pipe  constant

Where

A1*v1 = A2*v2

π*(0.105/2)²*9.91 = π*(0.167/2)²*v2

v2 = 3.9 m/s

Hence, we have that

P1 + ρ*g*y1 + v1² = P2 + ρ*g*y2 + v2²

dP = 1290*9.8*9.01 + 9.91² - 3.9²

dP = 114 kPa

In conclusion, difference between fluid pressure is dP = 114 kPa

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A person born in the United States is considered a citizen of the country, according to the 14th Amendment's "Citizenship" provision.

Citizens of both the United States and the State in which they live include everyone who was born or naturalised in the country and is subject to its laws. No State may enact or carry out any legislation that restricts the rights or privileges of US citizens; no State may rob anyone of their life, liberty, or property without first providing them with a fair trial; and no State shall deny anyone living under its jurisdiction the equal protection of the law.

Based on the first clause of Section 1,1, the Court has determined that a child born in the United States to Chinese parents who were not qualified for naturalisation themselves is nonetheless a citizen of the United States with all the rights.

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Answer:

Question 5: The period of the waves is the time it takes for one complete up-and-down cycle of the boat.

In this case, the boat bobs up and down 10 times in 8 seconds.

Therefore, the time it takes for one up-and-down cycle is:

8 seconds ÷ 10 cycles = 0.8 seconds

So the period of the waves is 0.8 seconds.

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Question 6 : The frequency of the waves is the number of complete up-and-down cycles per unit time, typically measured in Hertz (Hz).

In this case, the boat bobs up and down 10 times in 19 seconds.

Therefore, the frequency of the waves is:

Frequency = Number of cycles ÷ Time

Frequency = 10 cycles ÷ 19 seconds

Frequency ≈ 0.526 Hz

So the frequency of the waves is approximately 0.526 Hz.

So, the force of gravity that the asteroid and the planet have on each other approximately \( \boxed{\sf{2.9 \times 10^{17} \: N}} \)

Hi ! Now, I will help to discuss about the gravitational force between two objects. The force of gravity is not affected by the radius of an object, but radius between two object. Moreover, if the object is a planet, the radius of the planet is only to calculate the "gravitational acceleration" on the planet itself,does not determine the gravitational force between the two planets. For the gravitational force between two objects, it can be calculated using the following formula :

\( \boxed{\sf{\bold{F = G \times \frac{m_1 \times m_2}{r^2}}}} \)

With the following condition :

We know that :

What was asked :

Step by step :

\( \sf{F = G \times \frac{m_X \times m_Y}{r^2}} \)

\( \sf{F = 6.67 \cdot 10^{-11} \times \frac{1.55 \cdot 10^{22} \cdot 3.95 \times 10^{28}}{(3.75 \times 10^{11})^2}} \)

\( \sf{F \approx \frac{40.84 \times 10^{-11 + 22 + 28}}{14.0625 \times 10^{22}}} \)

\( \sf{F \approx 2.9 \times 10^{39 - 22}} \)

\( \sf{F \approx 2.9 \times 10^{17} \: N} \)

So, the force of gravity that the asteroid and the planet have on each other approximately

\( \boxed{\sf{2.9 \times 10^{17} \: N}} \)