Mrs. Greenaway has decided to open a new preschool in her town. To decide whether she will have enough students to be successful, she hires a researcher to conduct a survey of the town’s population. Which of the following groups would make up the best sample for this survey?

A. parents of preschool children
B. parents of elementary school children
C. registered voters in the town
D. members of the town council

Answer:

Point H, Point D, Point G, Point F

Answer:

-5x^4 + 3

Step-by-step explanation:

Answer:

\(-5x^{4}\)+3

Step-by-step explanation:

Add like terms: 3x^4 and -8x^4. Add them to get -5x^4. The 3 is left alone and added to the sum.

\(-5x^{4}\)+3

Answer: 36in squared

Step-by-step explanation:

Answer: 36

Step-by-step explanation:

To find the area of a shape, multiple the two sides, length * width in this case 6*6 is 36.

this is the full answer for you're Q

please give me good

The time taken by the object to hit the ground will be 9 seconds.

A quadratic equation is a polynomial with a degree of 2 or the maximum power of the variable is 2 in quadratic equations. It has two solutions as its maximum power is 2.

Given that an object is launched at 9.8 meters per second (m/s) from a 308.7-meter tall platform. The function that represents the object's height s at time t seconds after launch is

s(t) = −4.9t²+ 9.8t + 308.7

To find the time taken put the function equal to zero.

−4.9t²+ 9.8t + 308.7 = 0

t² - 2t - 63 = 0

t² - 9t + 7t - 63 = 0

t ( t - 9 ) +7 ( t - 9 ) = 0

( t - 9 ) ( t + 7 ) = 0

t = 9 and -7(ignore)

t = 9 seconds

Therefore, the time taken by the object to hit the ground will be 9 seconds.

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Answer:

nonrigid and segement lengths ar enot

Step-by-step explanation:

Step-by-step explanation:

volume of triangular prism= area of cross section *length

volume of triangular prism= area of cross section *lengthv=(1/2bh)l

volume of triangular prism= area of cross section *lengthv=(1/2bh)lv=?,b=5,h=40

volume of triangular prism= area of cross section *lengthv=(1/2bh)lv=?,b=5,h=40 =(1/2*5*7)40

volume of triangular prism= area of cross section *lengthv=(1/2bh)lv=?,b=5,h=40 =(1/2*5*7)40 =(35/2)40

=17.5*40

=700cm³

The volume of triangular prism is 700cm³

Answer:

Step-by-step explanation:

Good luck

a) The ground speed of the plane is approximately 200.04 mph, and the true course is approximately 128.75°.

b) The ground speed of the plane is approximately 203.21 mph, and the true course is approximately 22.55°.

a) To find the true course and ground speed of the plane, we can consider the combined effect of the airspeed and wind currents.

The airspeed of the plane is 165 mph with a heading of 140°. Breaking it down into components:

Airspeed:

Horizontal component: 165 * cos(140°) ≈ -79.91 mph

Vertical component: 165 * sin(140°) ≈ 142.41 mph

The wind currents are running at 45 mph at 165° clockwise from due north. Breaking it down into components:

Wind velocity:

Horizontal component: 45 * sin(165°) ≈ -39.05 mph

Vertical component: 45 * cos(165°) ≈ 22.54 mph

Adding the corresponding components, we get:

Total horizontal velocity: -79.91 - 39.05 ≈ -118.96 mph

Total vertical velocity: 142.41 + 22.54 ≈ 164.95 mph

The ground speed can be calculated using the Pythagorean theorem:

Ground speed = √((Total horizontal velocity)² + (Total vertical velocity)²)

= √((-118.96)² + (164.95)²)

≈ 200.04 mph

The true course can be found using the inverse tangent function:

True course = arctan(Total vertical velocity / Total horizontal velocity)

= arctan(164.95 / (-118.96))

≈ 128.75°

b) Similarly, for the second scenario, the airspeed of the plane is 240 mph with a heading of 230°. Breaking it down into components:

Airspeed:

Horizontal component: 240 * cos(230°) ≈ -206.96 mph

Vertical component: 240 * sin(230°) ≈ -112.09 mph

The wind currents are running at a constant 40 mph in the direction 300°. Breaking it down into components:

Wind velocity:

Horizontal component: 40 * cos(300°) = 40 * cos(60°) = 20 mph

Vertical component: 40 * sin(300°) = 40 * sin(60°) = 34.64 mph

Adding the corresponding components:

Total horizontal velocity: -206.96 + 20 ≈ -186.96 mph

Total vertical velocity: -112.09 + 34.64 ≈ -77.45 mph

Calculating the ground speed using the Pythagorean theorem:

Ground speed = √((Total horizontal velocity)² + (Total vertical velocity)²)

= √((-186.96)² + (-77.45)²)

≈ 203.21 mph

Determining the true course using the inverse tangent function:

True course = arctan(Total vertical velocity / Total horizontal velocity)

= arctan((-77.45) / (-186.96))

≈ 22.55°

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Step-by-step explanation:

the distance between 2 points on a coordinate system creates a right-angled triangle.

the distance is the Hypotenuse (the side opposite of the 90° angle). and the x- and y- coordinate differences are the legs.

then Pythagoras applies

c² = a² + b²

c being the Hypotenuse, a and b being the legs.

so,

distance² = (xd - xf)² + (yd - yf)²

5² = (-7 - x)² + (-2 - 2)² = 49 + 14x + x² + 16

25 = x² + 14x + 65

x² + 14x + 40 = 0

the general solution to such a quadratic equation

ax² + bx + c = 0

is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

x = (-14 ± sqrt(14² - 4×1×40))/(2×1) =

= (-14 ± sqrt(196 - 160))/2 =

= (-14 ± sqrt(36))/2 = (-14 ± 6)/2 = -7 ± 3

x1 = -7 + 3 = -4

x2 = -7 - 3 = -10

Richard's net pay for the week, considering Social Security, Medicare, and FIT deductions, can be calculated by subtracting the total deductions from his gross earnings.

First, let's determine the amount deducted for Social Security. The Social Security rate is 6.2%, and the maximum earnings subject to this deduction are $118,500. Since Richard is $1,000 below the maximum level, the amount subject to Social Security deduction is $1,000. Therefore, the Social Security deduction is 6.2% of $1,000.

Next, we calculate the Medicare deduction. The Medicare rate is 1.45%, and it is applied to the entire earnings of $1,700.

To calculate the FIT deduction, we need additional information about Richard's taxable income, tax brackets, and exemptions. Without this information, we cannot provide an accurate calculation for the FIT deduction.

Finally, we subtract the total deductions (Social Security, Medicare, and FIT) from Richard's gross earnings of $1,700 to obtain his net pay for the week.

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Step-by-step explanation:

yo that's actually really sick

The measure of angle ABC is given as follows:

m < ABC = 145º.

Two angles are defined as supplementary angles when the sum of their measures is of 180º.

In a parallelogram, we have that the opposite angles are supplementary.

The opposite angles for this problem are given as follows:

Hence the measure of angle ABC is given as follows:

m < ABC + 35º = 180º.

m < ABC = 145º.

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Answer:

7/2 or 3 1/2

hope this helps

have a good day :)

Step-by-step explanation:

Answer:

7/2

Step-by-step explanation:

3/2 + 4/2 = 7/2

Hope this helps!!

Answer:

There were 1,495 students enrolled at liberty middle this year

Step-by-step explanation:

1,300 + 15%

Answer:

2/7 or about 29%

Step-by-step explanation:

2 are blue and there are 7 cards total so 2/7 and 2 divided by 7 is .2857 or .29 (29%).

Answer:

2/7

Step-by-step explanation:

There are 7 envelopes and 2 blue envelopes so the probability that the envelope will be blue is 2/7

The mean and standard deviation of a sampling distribution of sample means with sample size 249 are 71 and approximately 1.267 respectively when the population has a mean of 71 and standard deviation of 20.

We know that, if the population has mean \(=\mu\) and standard deviation \(=\sigma\) and if the sampling distribution has sample size of n then

mean of the sampling distribution will be \((\mu_{\bar{x}})=\mu\)

and the standard deviation of sampling distribution will be \((\sigma_{\bar{x}})=\frac{\sigma}{\sqrt{n}}\)

Here in this problem,

Mean of the population \((\mu)\) = 71

Standard Deviation of the population \((\sigma)\) = 20

And the sample size of the sampling distribution (n) = 249

So, the mean of sampling distribution \((\mu_{\bar{x}})=\mu\) = 71

Standard Deviation of sampling distribution \((\sigma_{\bar{x}})=\frac{\sigma}{\sqrt{n}}=\frac{20}{\sqrt{249}} \approx 1.267\) (Correct up to three decimal places)

Hence, the mean and standard deviation of the sampling distribution of sample means with sample size 249 are 71 and 1.267 (approximately) respectively.

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The time spent on homework will be naturally more an explanatory variable and exam grade a response variable.

The Linear equation for a scatter plot y = mx+b has two variables i.e., a Dependent Variable [Y] and an Independent variable [X] .

A student who spends more time on his work and do it nicely will automatically get good exam grade . On the other side, a student who did'nt dedicate much time to the homework and carelessly does it , will obviously score a low exam grade.We can see that the exam grade is dependent on the time spent on the homework which naturally makes exam grade a response variable and time spent on home a independent thus an explanatory variable.

Hence, the time spent on homework will be naturally more an explanatory variable and exam grade a response variable.

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To determine the size of the weight matrix for the given convolutional neural network (CNN), we need to consider the number of units in the first layer and the dimensions of the input grayscale images.

In a CNN, the weight matrix is used to perform the convolution operation, which involves applying filters to the input images. Each unit in the first layer corresponds to a specific filter or kernel. The size of the weight matrix will depend on the number of units in the layer and the dimensions of the filters.Let's assume that the number of units in the first layer is N, and the input grayscale images have pixel dimensions MxM. In this case, the weight matrix will have dimensions N x (K x K), where K represents the kernel size. Each row of the weight matrix corresponds to the weights associated with a specific unit in the first layer.The number of columns in the weight matrix is determined by the kernel size, which is typically a square matrix.

The values in the weight matrix represent the learnable parameters of the CNN.  By adjusting the weights in the matrix, the CNN can learn to extract meaningful features from the input images and make accurate predictions. Overall, the size of the weight matrix for the given CNN is N x (K x K), where N is the number of units in the first layer, and K is the kernel size. The rows of the weight matrix correspond to the units in the first layer, and the columns represent the weights associated with each pixel in the kernel used for convolution.

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Answer:
45.2x0.784

Step-by-step explanation:

This problem equals 35.4368, which has four decimal points

The correct values for a, b, c, d, and e are a = 16, b = 29, c = 24, d = 22, and e = 30 for group of 75 students on asking whether they like Algebra or Geometry.

For the values of a, b, c, d, and e, we can use the information provided in the table. Let's break it down step-by-step:

We are given that a total of 75 math students were surveyed. Therefore, the total number of students should be equal to the sum of the students who like algebra, the students who like geometry, and the students who do not like either subject.

75 = 45 (Likes Algebra) + 53 (Likes Geometry) + 6 (Does Not Like Either)

Simplifying this equation, we have:

75 = 98 + 6

75 = 104

This equation is incorrect, so we can eliminate options c and d.

Now, let's look at the information given for the students who do not like geometry. We know that a + b = 6, where a represents the number of students who like algebra and do not like geometry, and b represents the number of students who do not like algebra and do not like geometry.

Using the correct values for a and b, we have:

16 + b = 6

b = 6 - 16

b = -10

Since we can't have a negative value for the number of students, option a is also incorrect.

The remaining option is option e, where a = 29, b = 16, c = 24, d = 22, and e = 30. Let's verify if these values satisfy all the given conditions.

Likes Algebra: a + c = 29 + 24 = 53 (Matches the given value)

Does Not Like Algebra: b + d = 16 + 22 = 38 (Matches the given value)

Likes Geometry: c + d = 24 + 22 = 46 (Matches the given value)

Does Not Like Geometry: b + e = 16 + 30 = 46 (Matches the given value)

All the values satisfy the given conditions, confirming that option e (a = 29, b = 16, c = 24, d = 22, and e = 30) is the correct answer.

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Answer:

equalateral

Step-by-step explanation:

each side is equal to the next

Answer:

2. Equilateral

Step-by-step explanation:

Step 1: Process Of Elimination-

1. Right: No

This triangle is not a right triangle because it does not have a right triangle indicator nor does it equal 90°.

2. Equilateral: Yes

This triangle is an equilateral triangle because all 3 sides are equal and they add up to 180° meaning each side equal 60°.

3. Acute: No

A acute triangle is a triangle that is less then 90° but this triangle equals 180°.

4. Scalene: No

A scalene triangle is a triangle that has different side angles but they all add up to 180° but here we can see that the sides are equal.

Answer: No

Step-by-step explanation:

Linear expression is y=mx + b

14 is just a number, it doesn't have a slope or y-intercept!

Answer:

\(\begin{cases}a_1=1\\a_{n+1}=2 a_n\end{cases}\)

Step-by-step explanation:

A recursive formula for a sequence allows you to find the nth term of the sequence provided you know the value of the previous term in the sequence.

The first three terms of the sequence are:

Therefore, as each term of the sequence is twice the previous term it is a geometric sequence.

When writing a recursive rule, remember to include the definition of the first term of the sequence.

Therefore, the recursive formula for the given situation is:

\(\begin{cases}a_1=1\\a_{n+1}=2 a_n\end{cases}\)

-----------------------------------------------------------------------------------------------

Additional information

The "a" signifies "term".  So a₁ is the first term, a₂ is the second term ... aₙ is the nth term.  Therefore, aₙ₊₁ is the next term.

"u" is regularly used instead of "a", but as "a" is used as the first term when writing explicit formulas, it is more preferable.

As a recursive formula for a sequence allows you to find the nth term of the sequence provided you know the value of the previous term in the sequence, to find the 6th term for example, we would need to calculate the previous terms first:

\(\implies a_1=1\)

\(\implies a_2=2 \cdot a_1=2 \cdot 1=2\)

\(\implies a_3=2 \cdot a_2=2 \cdot 2=4\)

\(\implies a_4=2 \cdot a_3=2 \cdot 4=8\)

\(\implies a_5=2 \cdot a_4=2 \cdot 8=16\)

\(\implies a_6=2 \cdot a_5=2 \cdot 16=32\)

Note:  It is more preferable to find an explicit formula for the nth term of a sequence since with an explicit formula we do not need to calculate the previous term(s).

The explicit formula for this sequence of this question is:

\(a_n=2^{n-1}\)

Therefore, to find the 6th term using the explicit formula, simply substitute n = 6 into the formula:

\(\implies a_6=2^{6-1}=2^5=32\)

As you can see, it yields the same result as the recursive formula but without the need to calculate the preceding terms.

a) By strong induction, any amount of postage worth 8 cents or more can be made from 3-cent or 5-cent stamps.

b) By strong induction, any amount of postage worth 24 cents or more can be made from 7-cent or 5-cent stamps.

c) By strong induction, any amount of postage worth 12 cents or more can be made from 3-cent or 7-cent stamps.

a. Prove that any amount of postage worth 8 cents or more can be made from 3-cent or 5-cent stamps.

Base case: For postage worth 8 cents, we can use two 4-cent stamps, which can be made using a combination of one 3-cent stamp and one 5-cent stamp.

Induction hypothesis: Assume that any amount of postage worth k cents or less, where k is greater than or equal to 8, can be made from 3-cent or 5-cent stamps.

Induction step: Consider any amount of postage worth (k+1) cents. Since k is greater than or equal to 8, we can use the induction hypothesis to make k cents using 3-cent or 5-cent stamps. Then, we can add one more stamp to make (k+1) cents. If the last stamp we added was a 3-cent stamp, we can replace it with a 5-cent stamp to get the same value. If the last stamp we added was a 5-cent stamp, we can replace it with two 3-cent stamps to get the same value. Therefore, any amount of postage worth (k+1) cents can be made from 3-cent or 5-cent stamps.

b. Prove that any amount of postage worth 24 cents or more can be made from 7-cent or 5-cent stamps.

Base case: For postage worth 24 cents, we can use three 8-cent stamps, which can be made using a combination of one 7-cent stamp and one 5-cent stamp.

Induction hypothesis: Assume that any amount of postage worth k cents or less, where k is greater than or equal to 24, can be made from 7-cent or 5-cent stamps.

Induction step: Consider any amount of postage worth (k+1) cents. Since k is greater than or equal to 24, we can use the induction hypothesis to make k cents using 7-cent or 5-cent stamps. Then, we can add one more stamp to make (k+1) cents. If the last stamp we added was a 5-cent stamp, we can replace it with two 7-cent stamps to get the same value. If the last stamp we added was a 7-cent stamp, we can replace it with three 5-cent stamps to get the same value. Therefore, any amount of postage worth (k+1) cents can be made from 7-cent or 5-cent stamps.

c. Prove that any amount of postage worth 12 cents or more can be made from 3-cent or 7-cent stamps.

Base case: For postage worth 12 cents, we can use one 3-cent stamp and three 3-cent stamps, which can be made using a combination of two 7-cent stamps.

Induction hypothesis: Assume that any amount of postage worth k cents or less, where k is greater than or equal to 12, can be made from 3-cent or 7-cent stamps.

Induction step: Consider any amount of postage worth (k+1) cents. Since k is greater than or equal to 12, we can use the induction hypothesis to make k cents using 3-cent or 7-cent stamps. Then, we can add one more stamp to make (k+1) cents. If the last stamp we added was a 3-cent stamp, we can replace it with two 7-cent stamps to get the same value. If the last stamp we added was a 7-cent stamp, we can replace it with one 3-cent stamp and two 7-cent stamps to get the same value. Therefore, any amount of postage worth (k+1) cents can be made from 3

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Answer:

yea

Step-by-step explanation:

yea

Answer:

24

Step-by-step explanation:

4-(-20)= 4+20=24

The probability that he'll use both the bus and the train is 0.2222

What is probability and example?

Probability = the number of ways of achieving success. the total number of possible outcomes. For example, the probability of flipping a coin and it being heads is ½, because there is 1 way of getting a head and the total number of possible outcomes is 2 (a head or tail). We write P(heads) = ½ .

There are just two ways in which Justin use both the bus and the train on the same day:

1. He used bus in the morning and train in the evening

2. He used train in the morning and bus in the evening

Additionally, every day he has 9 possible ways to used the transportation, 3 in the morning multiply by 3 in the evening. This is:

       3         *         3           =  9

p= 0.222

So, the probability is calculate as a division between the possible ways in which he use both transportations and the total possible ways. This is:

p=0.222

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Based on the information provided, if Henry's credit card balance was 612 dollars and his next purchase caused him to exceed the credit limit of 2000 dollars,

then the cost of his next purchase must be greater than the difference between the credit limit and the current balance. In mathematical terms:

Cost of next purchase > (2000 - 612)

Your answer: Cost of next purchase > 1388 dollars

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Answer:

w = 9

Step-by-step explanation:

- 3w + 15w + 7 = 8w + 43 , simplifying

12w + 7 = 8w + 43 ( subtract 8w from both sides )

4w + 7 = 43 ( subtract 7 from both sides )

4w = 36 ( divide both sides by 4 )

w = 9

W=9

first, you simplify the expression.

12w + 7 = 8w + 43.

After that, we group all the w terms on the left side of the equation.

Subtract 8w from both sides:

12w + 7 - 8w = 8w + 43 - 8w

Group like terms:

12w - 8w + 7 = 8w + 43 - 8w

Simplify the arithmetic:

4w + 7 = 8w + 43 - 8w

Group like terms:

4w + 7 = 8w - 8w + 43

Simplify the arithmetic:

4w + 7 =43

Then, we group all constants on the right side of the equation

Subtract 7 from both sides:

4w + 7 - 7 = 43 - 7

Simplify the arithmetic:

4w = 43 - 7

4w = 36

Now, we isolate the w. Divide both sides by4:

4w / 4 = 36 / 4

Simplify the fraction:

w = 36/4

Find the greatest common factor of the numerator and denominator:

w = 9 × 4/1 × 4

Factor out and cancel the greatest common factor:

w = 9