Mrs. J . weighs 557 N. what is her mass?

The component of the solar magnetic field that is dragged out of the solar corona and into the Solar System by the solar wind flow is known as the interplanetary magnetic field (IMF), which is now more commonly referred to as the heliospheric magnetic field (HMF).

Our planet is shielded from cosmic radiation and charged particles from our Sun by the magnetic field, which is created by the motion of molten iron in the Earth's core. Additionally, it offers the foundation for compass navigation.

It travels throughout the solar system on the solar wind. We refer to the magnetic field of the Sun as the "Interplanetary Magnetic Field," or "IMF," outside of the planets. The IMF has a spiral shape as a result of the Sun's rotation (once every 27 days), and is known as the "Parker spiral" after the scientist who first described it. The most crucial component of auroral activity is the interplanetary magnetic field's (Bz) north-south direction.

Learn more about magnetic field on:

https://brainly.com/question/14411049

#SPJ1

Answer:

The scientific meaning for temperature is at the heart of thermodynamics. It arises from the Zeroth Law of thermodynamics that states that if two systems are in thermal equilibrium and one of those systems is in thermal equilibrium with a third system, then all three systems are in thermal equilibrium with each other.

Explanation:

Answer:

The double arrow represents thermal equilibrium between systems.

Explanation:

The answer for the experiment is obtained by the principle of Newton's law of cooling. The initial temperature of the Room is taken as 32°C.

The ice cubes are mixed with room-temperature water, the ice starts to melt and the water becomes cold. This is because the ice and water have two different temperatures and when they are mixed there is an exchange of heat is taken place. When the ice cubes mixed with water the room temperature is decreases from 32°C. After stirring the mixture because of the heat released, the temperature increases.

When the ice-water mixture is stirred, the heat energy is evolved which melts the ice in the mixture, and therefore the temperature increases gradually. And stirring of water for every 5 minutes leads ice cubes to melt completely to form water and the level of water increases in the final stage. This was given by Newton's law of cooling.

To learn more about Newton's law of Cooling:

https://brainly.com/question/14643865

#SPJ1

Answer:

The correct answer is - c.  Spaceship will have a velocity to the East and will be slowing down.

Explanation:

In this case, if turned on thruster #2 then it will exert force on the west side as thruster 2 is on the east side and it can be understood by Newton's third law that says each action has the same but opposite reaction.

As the spaceship engine applies force on the east side then according to the law the exhauster gas applies on towards west direction. It will try to decrease the velocity of the spaceship however, the direction of floating still be east side initally.

Answer:

eclipsing binary star system

Explanation:

The eclipsing timing method is one of the indirect methods Astronomers use to detect extrasolar planets. Eclipsing binary star system is detected from the drop in luminosity as one star passes in front of the other. The orbit plane of the two stars lies so nearly in the line, when viewed from Earth.

Thus, A binary star system that is detected from the drop in luminosity as one star passes in front of the other is called eclipsing binary star system.

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

Learn more about earthquakes from the given link.

https://brainly.com/question/25843505

Answer:

5.0 x 10^8

Explanation:

because u moved it 8 times to it places

Answer:

A. h = 2.15 m

B. Pb' = 122 KPa

Explanation:

The computation is shown below:

a)  Let us assume the depth be h

As we know that

\(Pb - Pat = d \times g \times h \\\\ ( 119 - 101) \times 10^3 = 856 \times 9.8 \times h\)

After solving this,  

h = 2.15 m

Therefore the depth of the fluid is 2.15 m

b)

Given that  

height of the extra fluid is

\(h' = \frac{2.35 \times 10^{-3}}{ area} \\\\ h' = \frac{2.35 \times 10^{-3}} { 66.2 \times 10^{-4}}\)

h' = 0.355 m

Now let us assume the pressure at the bottom is Pb'

so, the equation would be

\(Pb' - Pat = d \times g \times (h + h')\\\\Pb' = 856 \times 9.8 \times ( 2.15 + 0.355) + 101000\)

Pb' = 122 KPa

(A)  The depth of the fluid is 2.14 m.

(B)  The new pressure at the bottom of container is 121972 Pa.

Given data:

The cross-sectional area of the container is, \(A =66.2 \;\rm cm^{2}=66.2 \times 10^{-4} \;\rm m^{2}\).

The density of fluid is, \(\rho = 856 \;\rm kg/m^{3}\).

The container pressure at bottom is, \(P=119 \;\rm kPa=119 \times 10^{3} \;\rm Pa\).

The atmospheric pressure is, \(P_{at}=101 \;\rm kPa=101 \times 10^{3}\;\rm Pa\).

(A)

The given problem is based on the net pressure on the container, which is equal to the difference between the pressure at the bottom and the atmospheric pressure. Then the expression is,

\(P_{net} = P-P_{at}\\\\\rho \times g \times h= P-P_{at}\)

Here, h is the depth of fluid.

Solving as,

\(856\times 9.8 \times h= (119-101) \times 10^{3}\\\\h=\dfrac{ (119-101) \times 10^{3}}{856\times 9.8}\\\\h= 2.14 \;\rm m\)

Thus, the depth of the fluid is 2.14 m.

(B)

For an additional volume of \(2.35 \times 10^{-3} \;\rm m^{3}\) to the liquid, the new depth is,

\(V=A \times h'\\\\h'=\dfrac{2.35 \times 10^{-3}}{66.2 \times 10^{-4}}\\\\h'=0.36 \;\rm m\)

Now, calculate the new pressure at the bottom of the container as,

\(P'-P_{at}= \rho \times g \times (h+h')\\\\\P'-(101 \times 10^{3})= 856 \times 9.8 \times (2.14+0.36)\\\\P'=121972 \;\rm Pa\)

Thus, we can conclude that the new pressure at the bottom of container is 121972 Pa.

Learn more about the atmospheric pressure here:

https://brainly.com/question/13323291

Answer:

because of gravity the ball falls

Answer:

Gravity

Explanation:

Gravity is the force the world gives which I magnetic and yeah-

Explanation:

That must be the right ans.

Answer:

PHYSICAL CHANGE

Explanation:

PLEASE DON'T JUST IGNORE IT

I HOPE I WILL GET A GOOD RESPONSE

Answer:

1) 5.52 cm , C) 5.5 cm

Explanation:

When a measurement is carried out, in addition to the value of the magnitude, the error or uncertainty of the measurement must occur, in a direct measurement with an instrument the uncertainty is equal to the appreciation of the instrument.

Uniform see the errors by the number of significant figures days, in this cases they are two decimals for which the appreciation of the instrument ± - 0.01

now we can analyze the measurements made

1) 5.52 cm. Validate. It is a valid measurement is within the uncertainty range

2) 6.63 cm. It does not validate. It is out of the error range

3) 5.5 cm Valid. It is within the given error range,

4) 5.93 cm Not Valid. It is out of the error range.

Answer:

6.63 and 5.93

Explanation:

Answer:

1:2

Explanation:

It is given that,

Initial RMS AC voltage is 100 V and final RMS AC voltage is 200 V.

We need to find the ratio of the number of turns in the primary to the secondary  for step up transformer.

For a transformer, \(\dfrac{V_1}{V_2}=\dfrac{N_1}{N_2}\)

So,

\(\dfrac{N_1}{N_2}=\dfrac{100}{200}\\\\\dfrac{N_1}{N_2}=\dfrac{1}{2}\)

So, the ratio of the number of turns in the primary to the secondary is 1:2.

Answer:

Evaporative Water Loss = 2 kg

Explanation:

According to the given condition, the water entering the body must be equal to the water leaving the body. Therefore,

Water Entering the Body = Water Leaving the Body

Feed Water + Drinking Water + Metabolic Water = Urine Water + Evaporative Water Loss

using the given values:

1 kg + 5 kg + 0.5 kg = 4.5 kg + Evaporative Water Loss

Evaporative Water Loss = 1 kg + 5 kg + 0.5 kg - 4.5 kg

Evaporative Water Loss = 2 kg

The electric field is zero at x = -16.45cm

Data;

As the 3μC is larger than -2.0μC  and the charges are opposite sign. The electric field will be zero at the negative axis.

Let the point be at x.

For an electric field to be equal to zero;

\(k(\frac{q_1}{d_1})^2 + k(\frac{q_2}{d_2})^2 = 0\\\frac{3.4}{(5-x)^2} - \frac{2}{x^2} = 0\\\)

Let's solve for x using mathematical methods.

\(\frac{3.4x^2 - 2(5-x)^2}{(5-x)^2x^2}= 0\\ 3.4x^2 - 2(5-x^2) = 0\\3.4x^2 - 50 - 2x^2 + 20x = 0\\1.4x^2 +20x - 50 = 0\)

Solving the above quadratic equation;

\(x = -16.45cm\)

The electric field is zero at x = -16.45cm

Learn more on electric field at a point here;

https://brainly.com/question/1592046

https://brainly.com/question/14372859

Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe.

Galileo Galilei played a crucial role in challenging the prevailing geocentric model of the universe proposed by Aristotle and supported by Ptolemy. He provided several lines of evidence that effectively disproved their theories and supported the heliocentric model proposed by Nicolaus Copernicus. Some of the key evidence used by Galileo includes:

1. Observations through a telescope: Galileo was one of the first astronomers to use a telescope to observe the heavens. His telescopic observations revealed several important discoveries that contradicted the Aristotelian-Ptolemaic worldview. He observed the phases of Venus, which demonstrated that Venus orbits the Sun and not Earth. He also observed the four largest moons of Jupiter, now known as the Galilean moons, which provided evidence for celestial bodies orbiting a planet other than Earth.

2. Sunspots: Galileo's observations of sunspots provided evidence that the Sun is not a perfect celestial body, as suggested by Aristotle. Sunspots indicated that the Sun has imperfections and undergoes changes, challenging the notion of celestial perfection.

3. Mountains on the Moon: Galileo observed the rugged and uneven surface of the Moon, which contradicted Aristotle's belief in celestial spheres made of perfect, unchanging material. The presence of mountains on the Moon suggested that celestial bodies are subject to the same physical laws as Earth.

4. Phases of Venus: Galileo's observations of the phases of Venus provided direct evidence for the heliocentric model. As Venus orbits the Sun, it goes through phases similar to the Moon, ranging from crescent to full. This observation strongly supported the idea that Venus revolves around the Sun.

These lines of evidence presented by Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe. His work marked a significant turning point in the history of science and laid the foundation for modern astronomy.

for more questions on heliocentric

https://brainly.com/question/21113123

#SPJ8

(a) Calculate the displacement r :

r = (8.5 i + 13 j + 8.2 k) m - (1.5 i + 1.75 j + 1.2 k) m

r = (7 i + 11.25 j + 7 k) m

The work W done by F in the direction of this displacement is

W = F • r = (2 i + 4 j + 6 k) N • (7 i + 11.25 j + 7 k) m

W = (2×7 + 4×11.25 + 6×7) Nm = 101 J

(b) The average power P of the machine is then

P = W / ∆t = (101 J) / (12 s)

P = 101/12 J/s ≈ 8.42 W

The total resistance of the circuit is  1.313 x 10⁷ ohms.

The total resistance of the series circuit is the sum of all the resistance of the circuit.

The total resistance of the circuit is calculated by summing all the individual component of the circuit.

Rt = R₁   +  R₂     +   R₃

where;

P = V²/Rt

where;

Rt  =  V²/P

Rt = (12 + 4.8)² / (21.5 x 10⁻⁶)

Rt = 1.313 x 10⁷ ohms

Learn more about total resistance here: https://brainly.com/question/1851624

#SPJ1

Without lenses, his near point is at 66.7 cm. In order to read a material at 50 cm, he needs a lens of 2.0D.

The near point is the closest distance of distinct vision. We can obtain the focal length from the power as in; f = 100/2.5 = 40cm

1/40 = -1/v + 1/25

1/v = 1/25 - 1/40

1/v = 0.04 - 0.025

v = 66.7 cm

Now if he wants to read at 50 cm

1/f = -1/50 + 1/25

1/f = 1/25 - 1/50

1/f =  0.04 - 0.02

f = 50cm

Power = 100/50 cm = 2 D

Learn more about power of a lens:https://brainly.com/question/1503351

#SPJ1

Answer:

9 x 10^1  km/hr  

Explanation:

25 m/s   x  3600 sec / hr   x  1km / 1000 m = 90 km/hr

Answer:

The frequency the motorcyclist hears is 601.60 Hz

Explanation:

The Doppler effect is a physical phenomenon where an apparent change in wave frequency is presented by a sound source with respect to its observer.

The following expression is considered the general case of the Doppler effect:

\(f'=f*\frac{v+-vR}{v-+vE}\)

Where:

f ’, f: Frequency perceived by the receiver and frequency emitted by the emitter respectively. Its unit of measurement in the International System (S.I.) is hertz (Hz), which is the inverse unit of the second (1 Hz = 1 s-1)

v: propagation speed of the wave in the medium. It is constant and depends on the characteristics of the medium. In this case, the speed of sound in air is considered to be 34o m / s

vR, vE: Receiver and emitter speed respectively. Your unit of measure in the S.I. is the m / s

±, ∓:

The + sign is used:

The sign - is used:

In this case:

Replacing:

\(f'=523 Hz*\frac{340 m/s+13.6 m/s}{340 m/s-32.6 m/s}\)

Solving:

\(f'=523 Hz*\frac{353.6 m/s}{307.4 m/s}\)

f' = 601.60 Hz

The frequency the motorcyclist hears is 601.60 Hz

Answer:

a) \(\Delta \dot K = 24.570\,kW\), b) \(\dot W_{out} = 12729.15\,kW\), c) \(A_{in} = 0.0136\,m^{2}\)

Explanation:

A turbine is a device which works usually in steady state and assumption of being adiabatic means no heat interactions between steam through turbine and surroudings and produce mechanical work from fluid energy. Changes in gravitational energy can be neglected. This system can be modelled after the First Law of Thermodynamics:

\(-\dot W_{out} + \dot m \cdot (h_{in} - h_{out}) + \frac{1}{2}\cdot \dot m \cdot (v_{in}^{2}-v_{out}^{2}) = 0\)

a) Change in kinetic energy

\(\Delta \dot K = \frac{1}{2}\cdot \dot m \cdot (v_{in}^{2} - v_{out}^{2})\)

\(\Delta \dot K = \frac{1}{2} \cdot \left(12.6\,\frac{kg}{s} \right) \cdot \left[\left(80\,\frac{m}{s} \right)^{2}-\left(50\,\frac{m}{s} \right)^{2}\right]\)

\(\Delta \dot K = 24570\,W\)

\(\Delta \dot K = 24.570\,kW\)

b) Power output

\(\dot W_{out} = \dot m \cdot (h_{in} - h_{out}) + \frac{1}{2}\cdot \dot m \cdot (v_{in}^{2}-v_{out}^{2})\)

\(\dot W_{out} = \left(12.6\,\frac{kg}{s}\right)\cdot \left(3446\,\frac{kJ}{kg} - 2437.7\,\frac{kJ}{kg} \right) + 24.570\,kW\)

\(\dot W_{out} = 12729.15\,kW\)

c) Turbine inlet area

Turbine inlet area can be found by using the following expressions:

\(\dot V_{in} = \dot m \cdot \nu_{in}\)

\(\dot V_{in} = \left(12.6\,\frac{kg}{s}\right) \cdot \left(0.086442\,\frac{m^{3}}{kg} \right)\)

\(\dot V_{in} = 1.089\,\frac{m^{3}}{s}\)

\(A_{in} = \frac{\dot V_{in}}{v_{in}}\)

\(A_{in} = \frac{1.089\,\frac{m^{3}}{s} }{80\,\frac{m}{s} }\)

\(A_{in} = 0.0136\,m^{2}\)

Answer:

hello

Explanation:

For scientists, they offer a unique opportunity to study aspects of the sun like its corona, the layer of plasma surrounding the star. ... By studying the inner regions of the corona that we can generally only see and photograph well during a total solar eclipse, scientists can learn more about how weather works in space.

have a nice day

hope it helps

byee

Answer:

For scientists,they offer a unique opportunity to study aspects of the sun like it's Corona, the layer of plasma surrounding the star......By studying the inner regions of the Corona that we can generally only see and photograph well during a total solar eclipse, scientists can learn more about how weather works in space

Answer:

The car's final speed will be 28 m/s

Explanation:

We can use the kinematics equation

\(v_f=v_0+at\)

Note

\(v_f\) is the final velocity

\(v_0\) is the initial velocity

\(a\) is the acceleration

\(t\) is the time

We are given

\(v_0=0\\a=7\\t=4\)

Lets evaluate \(v_f\).

Substituting our values into the equation gives us

\(v_f=0+7*4\)

Lets simplify

\(v_f=7*4\)

\(v_f=28\)

(a) The time taken before the student catches the bus is 11.52 seconds.

(b) The distance the student have to run before she overtakes the bus is 63.36 m.

(c) The speed of the bus is 2.0 m/s.

(d) If the student's top speed is 2.7 m/s he will still catch the bus, since the bus's speed is 2.0 m/s.

Apply the principle of relative velocity as follows;

(Vs - Vb)t = D

where;

(Vs - at)t = D

where;

(5.5 - 0.173t)t = 40.4

5.5t - 0.173t² = 40.4

0.173t² - 5.5t + 40.4 = 0

solve the quadratic equation using formula method;

a = 0.173, b = -5.5, c = 40.4

t = 11.52 seconds or 20.27 seconds

so the minimum time taken by the student to over take the bus is 11.52 seconds

d = vt

d = 5.5 m/s x 11.52 s = 63.36 m

v = at²

v = 0.173 x (11.52)

v = 2.0 m/s

If the student's top speed is 2.7 m/s he will still catch the bus, since the bus's speed is 2.0 m/s.

Learn more about speed of bus here: https://brainly.com/question/647176

#SPJ1

Answer:

Distance from sun to Neptune = 4.495E9 km

Time for light to travel = 4.495E9 / 3E5 sec = 14,980 sec

That is from sun to Neptune time fof light = 250 min

Time for light to travel from sun to earth is about 8 min

So the time from Neptune would be 242 to 258 min depending on position of Neptune - Note that Neptune is about 30X as far from the sun as earth and

250 min / 8 min is roughly 30

The uniform motion of kinematics allows us to find the time it takes for light to arrive from Neptune to Earth, which varies between:

          t₁ = 1.45 10⁴ s and t₂₂= 1.55 10⁴ s

depending on the relative distance of the two planets

given parameters

to find

They  velocit of an electromagnetic wave is constant, so we can use the uniform motion relationships

             v = d / t

             t = d / v

where v is the speed of light, d the distance and y time, in this case the speed of the wave is the speed of light (v = c)

We look in the tables for the distances and the rotation periods around the sun

                           distance ( m)         period (s)

Sun Neptunium     4.50 10¹²             5.2 10⁹

Sun - Earth             1.5    10¹¹              3.2 10⁷

With the data of the period it is observed that the rotation of Neptune is much greater than that of Eart rotation around the sun, for which we will assume that Neptunium is fixed in space and the Earth may be in its aphelion or perihelion, maximum approach o away distance from the sun, consequently we calculate the time for the two cases:

Maximum approach

positions relative distance from the dos Plantetas is

         Δd = \(x_{Neptuno - Sum} - x_{Earth - Sum}\)d  

         Δd = 4.50 10¹²  - 1.5 10¹¹

         Δd = 43.5 10¹¹ m

the time it takes for Neptune's light to reach Earth is

        Δt = \(\frac{ 43.5 \ 10^{11} }{3 \ 10^8}\)  

        Δt = 14.5 10³ s

        Δt = 1.45 10⁴ s

We reduce to hours

        Δt = 1.45 10⁴ s (1 h / 3600 s) = 4.03 h

Maximum away

         Δd = \(x_{Neptune - Sum} + x_{Neptune-Sum}\)  

         Δd = 4.50 10¹² + 1.5 10¹¹

         Δd = 46.5 10¹¹

The time is

         Δt = \(\frac{46.5 \ 10^{11}}{ 3 \ 10^8}\)  

         Δt = 15.5 10³

         Δt = 1.55 10⁴ s

We reduce to hours

         Δt = 1.55 10⁴ s (1 h / 3600 s) = 4.31 h

In conclusion, the time it takes for light to arrive from Neptune to Earth varies between:

          t₁ = 1.45 10⁴ s and t₂ = 1.55 10⁴ s

depending on the relative distance of the two plants

learn more about the speed of light here:   https://brainly.com/question/14355103

The distance between the toyota camry and the student after 5 seconds would be 37.8 meters.

Since the Toyota Camry is moving only along the x-direction and the student is moving only along the y-direction, we can treat their motions independently.

Let's first find how far the Toyota Camry will travel along the x-direction in 5 seconds, using the equation:

x = xo + v0t + (1/2)at^2

where xo = 0 m (since it starts from rest), v0 = 0 m/s (since it starts from rest), a = 3 m/s^2 (the constant acceleration), and t = 5 s.

Plugging in the values, we get:

x = (1/2)(3 m/s²)(5 s)^2 = 37.5 m

So after 5 seconds, the Toyota Camry will be 37.5 meters away from its starting position, in the positive x-direction.

Now let's find how far the student will travel along the y-direction in 5 seconds, using the equation:

y = yo + vt

where yo = 0 m (since the student starts from rest), v = 1 m/s (the constant speed), and t = 5 s.

Plugging in the values, we get:

y = (1 m/s)(5 s) = 5 m

So after 5 seconds, the student will be 5 meters away from their starting position, in the positive y-direction.

To find the distance between the Toyota Camry and the student, we can use the Pythagorean theorem, since their motions are perpendicular:

distance = sqrt(x^2 + y^2)

distance = sqrt((37.5 m)^2 + (5 m)^2)

distance = 37.8 m (rounded to one decimal place)

Therefore, the distance between the Toyota Camry and the student after 5 seconds is approximately 37.8 meters.

More on kinematic motion can be found here: https://brainly.com/question/11910853

#SPJ1

The position of q3 when q = 10nC is x3 = 2/5 cm. The two possible values of x3 are 2/5 cm and 18/5 cm.

Let F1 and F2 be the forces exerted by q1 and q2 respectively on q3.

Using Coulomb's law, we have:

F1 = k * (q1 * q3) / r^2

F2 = k * (q2 * q3) / (d-r)^2

where k is the Coulomb constant (k = 9 x 10^9 Nm^2/C^2) and r is the distance between q1 and q3 on the x-axis.

Given that F1 = F2, we can equate the two expressions and solve for r:

k * (q1 * q3) / r^2 = k * (q2 * q3) / (d-r)^2

Simplifying and solving for r, we get:

r = (d*q2) / (q1 + q2)

Substituting the given values, we get:

r = (2*4q) / (q + 4q) = 8/5 cm

Now, to find the position of q3, we can use the fact that the three charges are collinear on the x-axis:

x3 + r = 2 => x3 = 2 - r

where x3 is the distance of q3 from q1 on the x-axis.

Substituting the value of r, we get:

x3 = 2 - (8/5) = 2/5 cm

To find the two possible values of x3 when q can be either positive or negative, we need to consider the two cases where all charges are either positive or negative.

Case 1: All charges are positive.

In this case, q1, q2, and q3 are all positive charges. Using the same method as before, we get:

r = (2*4q) / (q + 4q) = 8/5 cm

x3 = 2 - r = 2 - (8/5) = 2/5 cm

Therefore, one possible value of x3 is 2/5 cm.

Case 2: All charges are negative.

In this case, q1, q2, and q3 are all negative charges. Using the same method as before, we get:

r = (2*4q) / (-q - 4q) = -8/5 cm

x3 = 2 - r = 2 - (-8/5) = 18/5 cm

Therefore, the other possible value of x3 is 18/5 cm.

To know more about electric forces, here

https://brainly.com/question/8635934

#SPJ4

"down/up the plane" suggests an inclined plane, but no angle is given so I'll call it θ for the time being.

The free body diagram for the crate in either scenario is the same, except for the direction in which static friction is exerted on the crate. With the P = 100 N force holding up the crate, static friction points up the incline and keeps the crate from sliding downward. When P = 350 N, the crate is pushed upward, so static friction points down. (see attached FBDs)

Using Newton's second law, we set up the following equations.

• p = 100 N

∑ F (parallel) = f + p cos(θ) - mg sin(θ) = 0

∑ F (perpendicular) = n - p sin(θ) - mg cos(θ) = 0

• P = 350 N

∑ F (parallel) = P cos(θ) - F - mg sin(θ) = 0

∑ F (perpendicular) = N - P sin(θ) - mg cos(θ) = 0

(where n and N are the magnitudes of the normal force in the respective scenarios; ditto for f and F which denote static friction, so that f = µn and F = µN, with µ = coefficient of static friction)

Solve for n and N :

n = p sin(θ) + mg cos(θ)

N = P sin(θ) - mg cos(θ)

Substitute these into the corresponding equations containing µ, and solve for µ :

µ = (mg sin(θ) - p cos(θ)) / (mg cos(θ) + p sin(θ))

µ = (P cos(θ) - mg sin(θ)) / (P sin(θ) + mg cos(θ))

Next, you would set these equal and solve for m :

(mg sin(θ) - p cos(θ)) / (mg cos(θ) + p sin(θ)) = (P cos(θ) - mg sin(θ)) / (P sin(θ) + mg cos(θ))

...

Once you find m, you back-substitute and solve for µ, but as you might expect the result will be pretty complicated. If you take a simple angle like θ = 30°, you would end up with

m ≈ 36.5 kg

µ ≈ 0.256

The coefficient of static friction between the plane and the crate is μ = 0.256 and the mass of the crate is m=36.4 kg.

From the given,

The force that opposes the crate by sliding is P = 100N

In X-axis, the sum of forces is zero.

ΣF = 0

Pcosθ - mgsinθ-Ff = 0

Ff = Pcosθ - mgsinθ

In Y-axis

Psinθ - mgcosθ - N = 0

N = Psinθ-mgcosθ

Frictional force, Ff = μN, μ is the coefficient of friction

Ff = μN

Pcos30- mgsin30 + μ( Psin30+mgcos30) = 0

μ = mgsin30-Pcos30/Psin30+mgcos30 ------1

The block is sliding with the horizontal force, F = 350N

X-axis

P₂cosθ - mgsinθ-Ff = 0

Y-axis

P₂sinθ - mgcosθ - N = 0

N = P₂sinθ-mgcosθ

μ = P₂cos30-mgsin30/P₂sin30-mgcos30   -----2

Equate equations 1 and 2

mgsin30-Pcos30/Psin30+mgcos30 =P₂cos30-mgsin30/P₂sin30-mgcos30

4.905m-86.6/50+8.49 = 303.1-4.905m/175+8.49

41.7m² + 123m - 1.516×10⁴ = 0

-41.7m² +2330m -1.516×10⁴(4.905-86.6)(175+8.49) =(303.1-4.905)(50+8.49)

83.4m² - 2207m -3.03×10⁴ = 0

m= 36.4 kg

Hence, the mass of the crate is 36.4 Kg.

Substitute the value of m in equation 1,

μ = 4.905(36.4) - 86.6 / 50 + 8.49

μ  = 0.256

Thus, the coefficient of static friction is 0.256.

To learn more about friction and its types:

https://brainly.com/question/30886698

#SPJ1

Answer:

Sedentary lifestyle is the lifestyle by which most physical activity is abandoned, performing activities that do not require energy consumption or large muscle movements on a large scale, such as using a computer, driving a car or playing video games.

Today, most young people have gradually turned towards sedentary lifestyles, mainly motivated by the increase in technological availability, and the extensive dependence generated on technology both to communicate with their peers (cell phones, social networks, etc. .) and for leisure time (video games, etc.).

Some ways to promote physical activity in young people and prevent sedentary lifestyle can be to create sports groups, where young people can establish social relationships without depending on networks or technological devices, or establish tasks of physical activity during study or work hours.