Multithread or multiprocess applications can help speed up computation on multicore systems. According to Amdahl's Law, the speed-up gain for an application that is 20% serial and run on a machine with 8 processing cores would be approximately 3.75x.
Amdahl's Law is a formula used to calculate the theoretical speed-up gain of a system when only a portion of it can be parallelized. In this case, the application is 20% serial, meaning that 80% of the computation can be parallelized. With 8 processing cores, the parallelizable portion of the application can be divided among these cores, resulting in a speed-up gain.
To calculate the speed-up gain using Amdahl's Law, we use the formula:
Speed-up gain = 1 / [(1 - P) + (P / N)]
Where P is the percentage of the application that can be parallelized (in decimal form) and N is the number of processing cores.
In this case, P = 0.8 (80% parallelizable) and N = 8 (8 processing cores). Plugging these values into the formula:
Speed-up gain = 1 / [(1 - 0.8) + (0.8 / 8)]
= 1 / [0.2 + 0.1]
= 1 / 0.3
≈ 3.75x
Therefore, running the 20% serial application on a machine with 8 processing cores would result in a speed-up gain of approximately 3.75 times.
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The steel shaft has a diameter of 40 mm and is fixed at its ends A and B . If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa.
Q6/
Answer:
See explanation.
Explanation:
Since no figure was given I solved a problem that was similar to the one you described that I worked in my mechanics of materials class. The method should be very similar for your figure. See attached image for my work.
If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa. Than the answer will be 52Mpa.
What we need to perform?We need to perform a two step process to obtain the maximum shear stress on the shaft. For the solid shaft,
P=2×pi×N×T/60 or T=60×p/2×pi×N
Where P=power transmitted by the shaft=50×10³W
N=rotation speed of the shaft in rpm=730rpm
Pi=3.142
T is the twisting moment
By substituting the values for pi, N and P, we get
T=654Nm or 654×10³Nmm
Also, T=pi×rho×d³/16 or rho=16×T/pi×d³
Where rho=maximum shear stress
T = twisting moment=654×10³Nmm
d= diameter of shaft= 40mm
By substituting T, pi and d
Rho=52Mpa
b. For a hollow shaft, the value for rho is unknown
T=pi×rho(do⁴-di⁴/do)/16
Rho=T×16×do/pi×(do⁴-di⁴)
Where
T= twisting moment=654×10³Nmm gotten above
do=outside shaft diawter=40mm
di= inside shaft diameter =30mm
Pi=3.142
Substituting values for pi, do, di and T.
Rho=76Mpa
Therefore, If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa. Than the answer will be 52Mpa.
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An Injection molding system has a first cost of $180,000 and an annual operating cost of $95,000 In years 1 and 2 Increasing by $4,500 per year thereafter. The salvage value of the system is 25% of the first cost regardless of when the system is retired within its maximum useful life of 5 years. Using a MARR of 12% per year, determine the ESL and the respective AW value of the system.
The Equivalent Service Life (ESL) of the injection molding system is determined to be 3 years, and the respective Annual Worth (AW) value of the system is calculated.
To determine the Equivalent Service Life (ESL) and Annual Worth (AW) value of the injection molding system, we need to calculate the Present Worth (PW) of costs and salvage value over the system's maximum useful life of 5 years. The first cost of $180,000 and the salvage value of 25% of the first cost ($45,000) are considered.
The annual operating cost of $95,000 in years 1 and 2, increasing by $4,500 per year thereafter, is converted to an equivalent uniform annual cost (EUAC) using the given MARR (12% per year). This EUAC is then added to the salvage value to obtain the PW.
By comparing the PW values at different service lives (1 to 5 years), the ESL is determined to be 3 years, which corresponds to the minimum PW value. The AW value is then calculated by dividing the PW by the ESL.
By considering the MARR, the cash flows over the system's life, and the salvage value, the ESL and AW value of the injection molding system can be determined, providing insights into the economic performance of the system over time.
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how can the pilot determine, for an ils runway equipped with malsr, that there may be a penetration of the obstacle identification surfaces (ois), and care should be taken in the visual segment to avoid any obstacles? a. the approach chart has a visual descent point (vdp) published. b. the runway has a visual approach slope indicator (vasi). c. the published visibility for the ils is no lower than 3/4 sm.
To determine an ILS runway for the given approach the published visibility for the ils is no lower than 3/4 sm.
What should be the pilot aware of the obstacles?
The pilot should be aware that the obstacle identification surfaces (OIS) may be penetrated if the minimum published visibility for an ILS runway equipped with MALSR is no lower than 3/4 SM, and caution should be exercised in the visual segment to avoid any obstacles.
Visibility for an ILS Runway:
With a CAT I ILS approach supported by a 1,400–3,000-foot–long (430–910 m) ALS, visibility minimums of 12 mile (0.80 km) (runway visual range of 2,400 feet (730 m)) are possible. If the runway has high-intensity edge lights, visibility minimums of 38 miles (600 m) and 1,800–foot (550 m) visual range are also possible.
Hence published visibility for the ils is no lower than 3/4 sm
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When carbón and other materials are allowed with iron they forma
Answer:
steel
Explanation:
Assuming the word "allowed" was meant to be "alloyed"
Which part of a machine control unit interacts with the machine tools through electric signals?=]
A machine control unit is the electronic hardware that stores information and controls the machine tools. This unit contains a data processing unit that stores and manipulates data, and a ___________ that interacts with the machine tools through electrical signals.
Answer:
control loop unit
Explanation:
Edmentum/Plato
What historic event / period marked the beginning of the manufacturing boom in the mid-
to-late 18th century (1700s)?
Answer:
Industrial revolution too bad at english languge not fleunt so if say a whole story of this i will not make secene but answer is to it industrial revolution.
Explanation:
Water that has evaporated returns to earth as
Answer:
rain
Explanation:
evaoration causes clouds
clouds condense and rain
Answer:
rain
Explanation:
the urllc 5g category focuses on communications in smart cities
The uRLLC 5G category focuses on communications in smart cities is a False statement
What is the statement about?5G's uRLLC category doesn't prioritize smart city communications. uRLLC is a 5G use case alongside eMBB and mMTC. uRLLC provides ultra-reliable and low-latency communication services for real-time applications.
5G for critical applications like automation, safety, surgery, vehicles, and infrastructure. Smart cities can benefit from uRLLC's communication capabilities, but it's not limited to that. Smart cities go beyond uRLLC and include IoT, data analytics, etc.
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See text below
The uRLLC 5G category focuses on communications in smart cities. True or False?
How would you describe good communication? Why and when do we need it?
if stall speed in ktas for an aircraft us 100 ktas at sea level, what is the stall speed in ktas of the aircraft at 5000 ft density altitude
Answer:
my friend here justin
Explanation:
hes already taken
For a steel alloy it has been determined that a carburizing heat treatment of 11.3 h duration will raise the carbon concentration to 0.44 wt% at a point 1.8 mm from the surface. Estimate the time necessary to achieve the same concentration at a 4.9 mm position for an identical steel and at the same carburizing temperature.
This question is incomplete, the complete question is;
For a steel alloy it has been determined that a carburizing heat treatment of 11.3 h duration at Temperature T1 will raise the carbon concentration to 0.44 wt% at a point 1.8 mm from the surface. A separate experiment is performed at T2 that doubles the diffusion coefficient for carbon in steel.
Estimate the time necessary to achieve the same concentration at a 4.9 mm position for an identical steel and at the same carburizing temperature T2.
Answer:
the required time to achieve the same concentration at a 4.9 is 83.733 hrs
Explanation:
Given the data in the question;
treatment time t₁ = 11.3 hours
Carbon concentration = 0.444 wt%
thickness at surface x₁ = 1.8 mm = 0.0018 m
thickness at identical steel x₂ = 4.9 mm = 0.0049 m
Now, Using Fick's second law inform of diffusion
\(x^2\) / Dt = constant
where D is constant
then
\(x^2\) / t = constant
\(x^2_1\) / t₁ = \(x^2_2\) / t₂
\(x^2_1\) t₂ = t₁\(x^2_2\)
t₂ = t₁\(x^2_2\) / \(x^2_1\)
t₂ = (\(x^2_2\) / \(x^2_1\))t₁
t₂ = \((\) \(x_2\) / \(x_1\) \()^2\) × t₁
so we substitute
t₂ = \((\) 0.0049 / 0.0018 \()^2\) × 11.3 hrs
t₂ = 7.41 × 11.3 hrs
t₂ = 83.733 hrs
Therefore, the required time to achieve the same concentration at a 4.9 is 83.733 hrs
C++ Write a recursive function that parses a binary number as a string into a decimal integer.
The function header is:
int binaryToDecimal(const string& binaryString)
Write a test program that prompts the user to enter a binary string and displays its decimal equivalent. C++
Recursive function that parses a binary number as a string into a decimal integer in C++.
Why does recursive function use decimal?Function uses recursion to parse the binary number by breaking it down into its last digit and the rest of the number. The last digit is converted to a decimal value and added to the rest of the number, which is multiplied by 2.
The process is repeated until the entire binary number has been converted to a decimal integer.
#include <iostream>
#include <string>
using namespace std;
int binaryToDecimal(const string& binaryString);
int main()
{
cout << "Enter a binary number: ";
string binaryString;
cin >> binaryString;
int decimal = binaryToDecimal(binaryString);
cout << "The decimal equivalent is: " << decimal << endl;
return 0;
}
When the program is run, it will prompt the user to enter a binary number, and then it will display the decimal equivalent of the number.
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What is the inductive reactance of a 20 mH inductor at a frequency of 100Hz?
Answer:
The correct approach is "12.56 Ω".
Explanation:
The given values are:
Frequency,
f = 100 Hz
Inductor length,
L = 20 mH
Now,
The inductive reactance will be:
⇒ \(X_L=2 \pi fL\)
On putting the estimated values, we get
⇒ \(=2 (3.14)\times 100\times 20\times 10^{-3}\)
⇒ \(=12.56 \ \Omega\)
Which of the following tasks within an airline company are related to operations? A. crew scheduling. B. international monetary exchange. C. sales. D. advertising. E. accounts payable.
Answer:
A
Explanation:
Making all the schedules
The task within an airline company that are related to operations is;
Option A: Crew scheduling.
In airline operations there are numerous tasks carried out which includes;
dispatchflight planningflight watchweather data provisionoperations controlground to air communications Integration with crewCrew schedulingMaintenance planningNow, looking at the given options, the only task that falls into the list given of airline operations tasks is Crew scheduling.
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Stephen works with a group of engineers and is responsible for pricing out parts listed on the drawings for a new product. He is anxious to get the drawings so he can start his work. Conflict may arise due to __________.
organizational structure
limited resources
task interdependence
personality differences
The conflict may arise due to task interdependence.
The conflict may arise due to task interdependence.Stephen works with a group of engineers and is responsible for pricing out parts listed on the drawings for a new product. He is anxious to get the drawings so he can start his work. Conflict may arise due to Task Interdependence.Task interdependence refers to the way that different tasks or work units in an organization rely on one another. In organizations, some work units or teams depend on one another in order to complete their own work tasks. When work units depend on one another for the completion of their work, task interdependence exists.As per the given scenario, Stephen is working with a group of engineers and is responsible for pricing out parts listed on the drawings for a new product. Here, he needs to be completely dependent on the other engineers to get the drawings so he can start his work. If there is any delay or the other engineers do not deliver their part on time, then conflict can arise.
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Literature Review Discuss the importance of lubrication in rolling-contact and journal bearings. Comment on the desired physical and chemical characteristics of lubrication in bearings for the following applications: Automatic Transmission of a Car Engine components Marine, or off-shore Applications
Rolling-contact and journal bearings are widely used in mechanical systems for efficient and safe operations. The importance of lubrication in these bearings cannot be overstated, as it reduces friction between the surfaces and minimizes wear and tear. This ensures that the bearings function optimally.
A literature review is a comprehensive analysis of literature or research publications that relate to a specific topic or question. In this case, we are reviewing published research and literature on the importance of lubrication in rolling-contact and journal bearings.
Lubrication plays a crucial role in the functioning of rolling-contact and journal bearings. Some of the essential functions of lubrication include reducing friction between surfaces in contact, minimizing heat generated by friction and reducing the chances of overheating, providing a layer of protection against corrosion and rust, and acting as a coolant for bearings that generate a lot of heat.
Bearing lubricants should have specific physical and chemical characteristics depending on the application. For instance, transmission fluids should have a high viscosity to provide the necessary lubrication and protect the gears from wear and tear. They should also have excellent thermal stability to perform effectively at high temperatures and prevent the formation of sludge and other deposits.
Engine oils should have excellent anti-wear additives that reduce wear and tear on engine components. They should also have good detergency to keep the engine clean and prevent the formation of deposits. Additionally, they should have low volatility to prevent excessive oil consumption and reduce emissions.
For marine or offshore applications, lubricants should have good water separation properties to prevent the formation of rust and other deposits. They should also have good rust protection properties and be biodegradable to minimize the impact on the environment.
In summary, lubrication is vital for the efficient and safe functioning of rolling-contact and journal bearings. Lubricants should have specific characteristics depending on the application, and a literature review can provide valuable insights into the importance of lubrication in these bearings.
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unitate de masura in SI pt F
Answer:
Electrical Capacitance
Explanation:
To find - unit of measure in SI for F
Solution -
The answer is - Electrical Capacitance
Reason -
The farad (symbol: F) is the SI derived unit of electrical capacitance, the ability of a body to store an electrical charge.
Răspuns:
Capacitate electrică
Explicaţie:
Pentru a găsi - unitate de măsură în SI pentru F
Soluție -
Răspunsul este - Capacitate electrică
Motiv -
Farada (simbolul: F) este unitatea de capacitate electrică derivată din SI, capacitatea unui corp de a stoca o sarcină electrică.
Following data refers to the years of service (variable x) put in by seven
specialized workers in a factory and their monthly incomes (variable y). x
variable values with corresponding y variable values can be listed as: 11 years of
service with income 700, 7 years of service with income 500, 9 years of service
with income 300, 5 years of service with income 200, 8 years of service with
income 600, 6 years of service with income 400, 10 years of service with
income 800. Regression equation y on-x is
Select one:
ay=3/4x+1
by=4/3x-1
y=3/4x-1
dy-1-3/4x
Based on the data given, the regression equation y on-x is y = 3/4x + 1.
The regression equation that represents the relationship between the years of service (x) and monthly incomes (y) for the specialized workers in the factory can be determined by analyzing the given data points. By examining the data, we can observe that the monthly income increases as the years of service increase. Calculating the regression equation using the given data, we find that the equation that best fits the relationship is:y = (3/4)x + 100
This equation indicates that for every increase of 1 year in service, the monthly income increases by 3/4 (0.75) units. The constant term of 100 represents the base income level. Therefore, the correct option from the given choices is ay = (3/4)x + 1.For more such questions on Regression:
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This assignment implements the Priority Queue as a linked list using a double pointer.
As we have it, isThere(e) sets a double pointer (nodeType **envPtr) into the list pointing to the single pointer upon which we will act. If it's there, the element is (*envPtr)->payLoad If not, then *envPtr points to where it would be in the list. Thus, isThere(e) does all of our work; put(e) and remove(e) no longer have to search.
enqueue(e)
if isThere(e)
begin
e=(*envPtr)->payload;
remove & delete the node at (*envPtr) see Linkedlist_3
++e
do isThere(e) to set envPtr correctly
end (no "else")
The last operation was isThere, so envPtr is set... put e into a node and put it there as in the example code.
That's all there is to it. Again, this isn't a major rewrite.
The objective is to understand a double pointer (or a triple, I suppose; although, I have never used one.) In the binary tree, we will use double pointers heavily. Without the concept of double pointers, our code will turn into a monster when writing a binary tree.
Implementation helps in understanding the concept of double pointers, which will be useful when working with binary trees. By using double pointers effectively, you can keep your code concise and manageable, avoiding turning it into a more complex structure.
Implementing a Priority Queue as a linked list using a double pointer. In this implementation, the function isThere(e) sets a double pointer (nodeType **envPtr) into the list, pointing to the single pointer upon which you will act. If the element is present, it can be accessed using (*envPtr)->payLoad. If not, *envPtr points to where it would be in the list. This means that isThere(e) does most of the work, and put(e) and remove(e) don't need to search.
To enqueue an element (e), follow these steps:
1. Call isThere(e) to check if the element is already in the list and set the envPtr correctly.
2. If the element is found (isThere(e) is true), perform the following actions:
a. Set e to the value of the existing element: e = (*envPtr)->payload;
b. Remove and delete the node at (*envPtr) as demonstrated in the Linkedlist_3 example.
c. Increment the value of e: ++e
d. Call isThere(e) again to set envPtr correctly for the updated value of e.
3. There's no need for an "else" statement here since the last operation was isThere.
4. Create a new node with the value of e, and insert it into the list using the envPtr obtained from the previous step.
This implementation helps in understanding the concept of double pointers, which will be useful when working with binary trees. By using double pointers effectively, you can keep your code concise and manageable, avoiding turning it into a more complex structure.
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4. What are these parts commonly called?
Select all that apply:
Carburetor venturi tubes
Carburetor emulsion tubes
Carburetor air bleed tubes
O Carburetor stand-off tubes
These parts are commonly called carburetor emulsion tubes. These tubes maintain the air-fuel ratio at different speeds.
The carburetor is a device of the combustion engine power supply system that mixes fuel and air in order to facilitate internal combustion.
The carburetor emulsion tubes are tubes that maintain the air-fuel ratio at different velocities.
These tubes (carburetor emulsion tubes) are small brass cylinders where the metering needle slides into them.
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how many cubic meters of fill can be constructed at a void ratio of 0.7 from 191000 m of borrow material that has a void ratio of 1.2
Approximately 170700 cubic meters of fill can be constructed from 191000 m of borrowed material.
The volume of fill that can be constructed from a given amount of borrowed material can be calculated using the formula
Vf = Vb (e1-e2)/(e2-e3)
where Vf is the volume of fill, Vb is the volume of borrowed material, e1 is the void ratio of the borrowed material, e2 is the void ratio of the fill and e3 is the void ratio of the solids.
In this case, Vb is 191000 m, e1 is 1.2, e2 is 0.7 and e3 is 0. Thus, Vf = 191000 (1.2-0.7)/(0.7-0) = 170700 m. Therefore, approximately 170700 cubic meters of fill can be constructed from 191000 m of borrowed material.
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what is definition of
computational fluid Dynamics
unstructured grid
domain
geometry
At a given point in the high-speed flow over an airplane wing, the local Mach number, pressure and temperature are 0.7,0.9 atm, and 250 K, respectively. Calculate the values of p,, To, p*, T*, and a* at this point.
Answer:
a) p₀ = 1.2484 atm
b) T₀ = 274.5 K
c) p* = 0.6595 atm
d) T* = 228.74 K
e) a* = 303.16 m/s
Explanation:
Given that;
Local Mach number M = 0.7
Pressure P = 0.9 atm
Temperature T = 250 K
First we obtain the following ratios corresponding to Mach Number 0.7 from Appendix(A) table { ISENTROPIC FLOW PROPERTIES }
For M = 0.7; Pressure→ P/P₀ = 0.7209, Temperature; T/T₀ = 0.91075
Now we calculate;
a) value of p₀
we that; P/P₀ = 0.7209
p₀ = p / 0.7209
we substitute
p₀ = 0.9 / 0.7209
p₀ = 1.2484 atm
b) value of T₀
we know that;
T/T₀ = 0.91075
T₀ = T / 0.91075
we substitute
T₀ = 250 / 0.91075
T₀ = 274.5 K
c) value of p*
To obtain value of p*, we say;
(p* / p₀)\(_{ma=1}\) = 0.52828
p* = 0.52828 × 1.2484
p* = 0.6595 atm
d) value of T*
To obtain value of T*, we say;
(T* / T₀)\(_{ma=1}\) = 0.8333
T* = 0.8333 × 274.5
T* = 228.74 K
e) value of a*
we know that;
a* = √(γRT*)
so
a* = √(1.4 × 287 × 228.74)
a* = √(91907.732)
a* = 303.16 m/s
1. Examine the following circuit. Find RT, R3 IT, I1, I2, V1, V2 and V3. Ensure you have proper units! Show all your work.
Explanation:
Ohm's law applies: V = IR, and variations. The current in a series circuit is the same through every element. That current is given as 1.1 A.
Rt = (8 V)/I3 = (8 V)/(1.1 A) = 80/11 Ω = 7 3/11 Ω
R3 = Rt -R1 -R2 = 7 3/11 -2 -5 = 3/11 Ω
It = I3 = 1.1 A
I1 = I2 = I3 = 1.1 A
V1 = (I1)(R1) = (1.1 A)(2 Ω) = 2.2 V
V2 = (I2)(R2) = (1.1 A)(5 Ω) = 5.5 V
V3 = (I3)(R3) = (1.1 A)(7/11 Ω) = 0.3 V
What is the purpose of using state space representation?
Answer:
In control engineering, a state-space representation is a mathematical model of a physical system as a set of input, output and state variables related by first-order differential equations or difference equations.
Explanation:
(b) Briefly explain how the following three (3) technological advancements, have revolutionized the field of Mechanical Engineering by mentioning the deviations from the traditional practices. Computer Aided Design (CAD), i) ii) 3D printing and iii) Simulation
Here’s a brief explanation of how these three technological advancements have revolutionized the field of Mechanical Engineering.
What is the explanation for the above response?Computer Assisted Design (CAD): One of the most widely utilized software design tools is CAD. It is used by engineers and designers to model, validate, and convey ideas prior to production. CAD software models are frequently utilized as inputs to various mechanical engineering and design tools1.
ii) 3D printing: Extra tools for producing goods on a CNC machine or 3D printer are available and are occasionally incorporated into the CAD program. This has enabled quick prototyping and the creation of complicated geometries that were previously impossible with typical manufacturing methods1.
iii) Simulation: Computer-Aided Engineering (CAE) encompasses a wide variety of studies. Before building physical prototypes, it conducts complicated tasks like as finite element analysis (FEA) and computational fluid dynamics (CFD).
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Gold and silver rings can receive an arc and turn molten. True or False
Micropulse arc welding is a well-known tool for speeding up simple bench operations during the welding process like ring size, making connections near thermally sensitive gemstones, and mending porosity castings.
The practice performs effectively on gold, silver, copper, and stainless steel whether joining tiny jewelry materials or bigger pieces for miniature metal sculptures.
The welding arc temperatures typically range from 6000°C to 8000°C, which translates to about 10000F to 15000F.
This increased range of thermal heat is high enough to turn Gold and silver rings into a molten state. A molten state is a phase at which a solid element is being melted and turns into a liquid state under the influence of a high temperature.
Therefore, from the above explanation, we can conclude that it is possible and true for gold and silver rings to receive an arc and turn molten.
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Greek engineers had the unenviable task of moving largecolumns from the quarries to the city.One engineer,Chersiphron, tried several different techniques to do this. Onemethodwas to cut pivot holes into the ends of the stone andthen use oxen to pull the column. The 5-ft diameter columnweighs 14,000 lbs, andthe team of oxen generates a constantpull force of 2,000 lbs on the center of the cylinder,G. Knowingthat the column starts from rest and rolls without slipping,determine:(a) the velocity of its center,G,after it has moved7ft,and (b) the minimum static coefficient of friction that will keepit from slipping.
Answer:
yea
Explanation:
okkudjeheud email and delete the electronic version of this communication
use the fact that c o v ( x , y ) = e [ ( x − e ( x ) ) ( y − e ( y ) ) ] to prove that c o v ( x , y ) = e ( x y ) − e ( x ) e ( y )
To prove that COV(X, Y) = E(XY) - E(X)E(Y), we will use the given fact that COV(X, Y) = E[(X - E(X))(Y - E(Y))].
We start by expanding the given fact:
COV(X, Y) = E(XY - XE(Y) - E(X)Y + E(X)E(Y))
Now, we apply the linearity property of expectation, which allows us to separate each term:
COV(X, Y) = E(XY) - E(X)E(Y) - E(X)E(Y) + E(X)E(Y)
Notice that the last two terms cancel each other out:
COV(X, Y) = E(XY) - E(X)E(Y)
Using the given fact and the linearity property of expectation, we have successfully proven that COV(X, Y) = E(XY) - E(X)E(Y).
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There are gauges available for checking panel flushness. TRUE OR FALSE?
Answer: true
Explanation:
because flushness means your dead so you are dead now