Nachos this is going from a double bond (-ene) to a triple bond (-yne). Oxidized reduced

The mass of the magnetic oxide of iron (Fe3O4) that can be produced from 48.0 g of pure iron and an excess of oxygen is 68.72 g.

The formation of the magnetic oxide of iron (Fe3O4) is described by the balanced equation:

4Fe + 3O2 → 2Fe2O3

According to the equation, four moles of iron (Fe) react with three moles of oxygen (O2) to produce two moles of Fe2O3.

To determine the amount of Fe2O3 produced from a given amount of Fe, we can follow these steps:

1. Calculate the number of moles of Fe that react:

The mass of pure iron (Fe) as 48.0 g, we can convert it to moles:

48.0 g Fe / 55.85 g/mol = 0.859 mol Fe

2. Use the balanced equation the number of moles of Fe2O3 produced:

The balanced equation, we know that 4 moles of Fe produce 2 moles of Fe2O3.

So, we can calculate:

1 mol Fe2O3 = 4/2 = 2 mol Fe

0.859 mol Fe produces 0.859/2 = 0.43 mol Fe2O3

3. Calculate the mass of Fe2O3 produced:

Using the number of moles of Fe2O3 obtained above and the molar mass of Fe2O3 (159.69 g/mol):

Mass of Fe2O3 = 0.43 mol Fe2O3 × 159.69 g/mol = 68.72 g

The mass of the magnetic oxide of iron (Fe3O4) that can be produced from 48.0 g of pure iron and an excess of oxygen is 68.72 g.

This calculation is based on the stoichiometry of the balanced equation and provides an estimation of the expected yield of Fe3O4.

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By doing scientific experiment we can prove inference about the acidity of the paper is true.

The experiment is nothing but to do the test of the hypothesis and are the main foundation of the scientific method, the steps include Make an observations, form hypothesis, conduct experiment, evaluation of result.

Then accept or reject the hypothesis from the evaluated result, if rejected make new hypothesis; Another important factor is variable which is compulsorily added to the experiment.

Three major types of variables included like dependent, independent and controlled variables.

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Answer:

The most common isotope is Bromine-79.

Explanation:

Answer:

CH3F

Explanation:

because if drawn out its is asymmetric

Answer:

1. In electron dot structure, the dot represent one electrons.

2. Ionic compounds are highly soluble in water.

3. The bond formed by the mutual sharing of two electrons is called covalent bond.

4. there are 3 bonds in nitrogen molecule.

5. the ionic bonds are non-directional.

6. NaCl is taken in molten state

7. formula of common salt is NaCl.

8. Oxygen gas is a diamotic molecule.​

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1. Na cannot replace K

2. Co will replace Cu

3. Zn cannot replace itself

4. Ni  cannot replace Ba

The reactivity series is a table showing how reactive elements. The reactiveness could be in descending or ascending order.

Reactivity series exist for both cations and anions.

In this case, we are dealing with cations. The reactivity series for cations is in the attached image.

The following can be observed from the table:

As a rule of thumb, cations at the lower part of the table cannot displace cations at the upper part during reactions.

Thus:

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To produce CO2 (g), the necessary chemicals are a carbonate (such as sodium bicarbonate or calcium carbonate) and an acid (such as vinegar or hydrochloric acid). The net ionic equation would be: H+ (aq) + CO32- (aq) → CO2 (g) + H2O (l) or 2H+ (aq) + CO32- (aq) → CO2 (g) + H2O (l)

Based on your lab procedure, the necessary chemicals to produce CO2 (g) are typically a carbonate or bicarbonate salt, such as sodium carbonate (Na2CO3) or sodium bicarbonate (NaHCO3), and an acid, such as hydrochloric acid (HCl).

The net ionic equation for the generation of CO2 (g) using sodium bicarbonate (NaHCO3) and hydrochloric acid (HCl) is as follows:

HCO3- (aq) + H+ (aq) → CO2 (g) + H2O (l)

This equation represents the reaction between bicarbonate ions and hydrogen ions to produce carbon dioxide gas and water.

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Answer:

Helium and Neon have similar chemical properties because both of them completely fill the outer shell of their atoms' electrons, so there is nothing to share with other atoms, neither with the same element nor with any other element.

Explanation:  

Helium and Neon are both  noble gases . As elements react, their atoms, by losing, acquiring, or sharing electrons, complete their outer shells. Noble gas atoms already have full outer shells, so there is no tendency for them to lose, gain, or share electrons. There are incomplete outer shells of atoms of group 1 and 7 elements (so they are reactive)

Chemical properties of HELIUM and NEON -:

Hence, helium and neon have similar chemical properties as they are the most stable due to having the maximum number of valence electrons their outer shell can hold.

Answer:

A = 66.98 square in.

Explanation:

The Area of a sector is given by the formula

\(A = \frac{\theta}{360}\times \pi r^2\)

here θ is the central angle and r is the radius

given that θ = 120° and radius =  8 inches

\(A = \frac{120}{360}\times3.14\times 8^2\)

A = 66.98 square in.

Answer:

In a open system, the thermal energy of a system may be changed by adding or removing matter with a different temperature.

Explanation:

The thermal energy of a system can be changed when a new substance of different temperature is introduced into the system

The thermal energy of a system is the amount of heat energy contained in that system.

The quantity of heat in a system is given as;

\(Q = mc \Delta \theta\)

where;

\(\Delta \theta\) is the change in the temperature of the system

When a new substance is introduced into the system, the temperature of the resulting system changes.

For example;

Thus, the thermal energy of a system can be changed when a new substance of different temperature is introduced into the system.

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Answer:

The H—C—H bond angle in methane is the tetrahedral angle, 109.5°. This angle is obtained when all four pairs of outer electrons repel each other equally. The bond angles in water is less than 109.5° because of the stronger repulsion by their lone pairs of electrons.

a. 63.13 g of silver bromide is formed. b. Potassium bromide is limiting, and silver nitrate is in excess. c. 0.56 g of potassium bromide is left over. d. The percent yield is 46.96%.

In this problem, we first need to determine which reactant is limiting and which one is in excess. To do this, we can calculate the amount of product that each reactant would produce if it were completely consumed. The reactant that produces less product is the limiting reactant, and the other reactant is in excess.

In this case, using the molar masses of the reactants and the stoichiometry of the balanced chemical equation, we find that silver nitrate would produce 108.22 g of silver bromide, while potassium bromide would produce only 63.13 g. Therefore, potassium bromide is limiting, and silver nitrate is in excess.

To determine the amount of excess reactant left over, we can use the amount of limiting reactant consumed in the reaction to calculate the amount of product formed, and then subtract this from the total amount of product formed. In this case, 29.12 g of potassium bromide is consumed, producing 63.13 g of silver bromide. Therefore, 92.67 g - 29.12 g = 63.55 g of potassium bromide is in excess, and 63.55 g - 63.13 g = 0.42 g of potassium bromide is left over.

Finally, to calculate the percent yield, we can divide the actual yield (14.77 g) by the theoretical yield (63.13 g) and multiply by 100%. This gives us a percent yield of 23.41%, but we need to divide by the stoichiometric coefficient of silver bromide (1) to get the percent yield based on silver bromide. Therefore, the percent yield based on silver bromide is 23.41%/1 = 23.41%. The percent yield based on silver nitrate or potassium bromide would be different, but they are not relevant for this problem.

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Gas volume at STP was 1.12 10 7 cm3. At STP, the volume for 1 mole per gas is calculated to be 25 litres, followed by the kind of gas and dominant force. Actual gas having a repulsive force of +ve deviation.

V=nRT/P is how this formula is written. V = n R T / P, where V is the gas's volume in L, n is indeed the number of moles, R is the real gases constant, T is indeed the gas' temperature in K, and P is the gas's pressure in atm.

S.T.P. One mole of every gas takes up 22.4 litres of space at typical conditions of temperature and pressure of 0o and 1 atm, respectively. This volume is an approximate value, since the volume of various gases varies significantly. Every gas at S.T.P. has a molar volume of 22.4L.

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At the top of Mt. Everest, the solubility of oxygen in water is approximately 8.57×10^(-5) mol/L, calculated using Henry's law with the partial pressure of oxygen and the Henry's law constant.

To calculate the solubility of oxygen (O2) in water at the top of Mt. Everest, we can use Henry's law, which states that the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas above the liquid.

Henry's law equation is given by:

S = k * P

where S is the solubility of the gas, k is the Henry's law constant, and P is the partial pressure of the gas.

Partial pressure of O2 (P) = 0.209 * 0.250 atm (mole fraction of O2 in air multiplied by atmospheric pressure)

Henry's law constant (k) = 1.30×10^(-3) mol/(L⋅atm)

Plugging in the values into the equation:

S = (1.30×10^(-3) mol/(L⋅atm)) * (0.209 * 0.250 atm) ≈ 8.57×10^(-5) mol/L

Therefore, the solubility of oxygen in water at the top of Mt. Everest is approximately 8.57×10^(-5) mol/L.

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A photosynthetic reaction is the formation of the glucose and oxygen molecule by water and carbon dioxide. 12 moles of water will be used in the reaction.

Moles are the ratio of the mass of the substance to the molar mass of the substance.

In the photosynthetic reaction, 6 moles of carbon dioxide and 6 moles of water are utilized to produce 1 mole of a glucose molecule and 6 moles of oxygen.

From this, it can be said that the number of moles consumed of carbon dioxide and water will be equal and in the ratio of 1:1.

The number of moles of carbon dioxide will be equal to that of the water molecule and will also be equal to the ratio of the mass of carbon dioxide to the molar mass of carbon dioxide.

The moles of water will be calculated as:

\(\begin{aligned}\rm moles &= \rm \dfrac{\text{mass of CO}_{2}}{\text{molar mass of CO}_{2}}\\\\&= \dfrac{528}{44.01}\\\\&= 12\;\rm moles\end{aligned}\)

Therefore, option A. 12 moles of water will be used.

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The frequency of a wave 2.8 x 10³ Hertz is then the wavelength of these gamma rays is 107 nm

Wavelength is the the distance between two successive crests or troughs of a wave

Here given data is

Frequency = 2.8 x 10³ Hertz

Velocity of gamma rays = 3×10⁸m/s

We have to calculate wavelength of these gamma rays?

So, wavelength = velocity/frequency

λ = v/f

λ = 3×10⁸m/s/2.8 x 10³ Hertz

λ = 107 nm

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Answer:

Carbon and oxygen combine to form two oxides, carbon monoxide and carbon dioxide in which the ratio of the weights of carbon and oxygen is respectively 12:16 and 12:32.

Therefore, it takes approximately 23.2 kJ of energy to boil 100 mL of water.

The correct answer is D. 100 mL × 1g divided by 1mL × 1mol divided by 18.02g × 4.186 kJ/mol = 23.2 kJ

To calculate the energy required to boil 100 mL of water, we need to use the specific heat capacity of water, which is approximately 4.186 J/g·°C. The molar mass of water is 18.02 g/mol.

First, we convert the volume of water from milliliters to grams:

100 mL × 1 g/1 mL = 100 g

Then, we calculate the number of moles of water:

100 g × 1 mol/18.02 g = 5.548 mol

Finally, we multiply the number of moles by the molar heat of vaporization of water, which is approximately 40.65 kJ/mol:

5.548 mol × 4.186 kJ/mol = 23.2 kJ

Therefore, it takes approximately 23.2 kJ of energy to boil 100 mL of water.

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According to the research, the correct option is C. A scatterplot identifies the problem and its variables showing quantitative data that relate two variables.

It is a control and support tool that shows a geometric design that presents the existing links and the level of correlation between variables and how one variable influences another.

In this sense, given that it is a tool or graphic representation it is widely used in statistics, that helps to identify the possible association between two related sets of data, it seeks to correlate said variables in order to better control the process and improve it.

Therefore, we can conclude that according to the research, the correct option is C. A scatterplot identifies the problem and its variables showing quantitative data that relate two variables.

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Answer:

GROUP 2

Explanation:

u asked this already

i just dont understand...

In 2CaCO3 there are 3 elements

I hope that helped you! If you have any further questions comment down below or message me! Good luck!

approximately 0.27 grams of BaF2 will be dissolved in 125 mL of the saturated solution of BaF2.

How to solve the problem?

The solubility product constant (Ksp) for BaF₂ is given as 1.50 x 10⁻⁶. This means that at equilibrium, the product of the concentration of Ba₂₊ and F- ions will be equal to Ksp.

The balanced equation for the dissolution of BaF₂ is BaF₂(s) ⇔ Ba₂₊(aq) + 2F-(aq).

We can use the Ksp value to determine the concentration of Ba₂₊ and F- ions in a saturated solution of BaF₂

Let x be the molar solubility of BaF₂. Then, the concentration of Ba₂₊ ions in the saturated solution will be x mol/L, and the concentration of F- ions will be 2x mol/L, according to the stoichiometry of the balanced equation.

The Ksp expression can be written as:

Ksp = [Ba₂₊][F-]²

Substituting the expressions for the concentrations of Ba₂₊ and F- ions, we get:

Ksp = x (2x)⅝ = 4x³

Solving for x, we get:

x³= Ksp / 4 = 1.50 x 10⁻⁶/ 4 = 3.75 x 10⁻⁷

x = (3.75 x 10⁻⁷)¹/³ = 0.0077 mol/L

This means that the molar solubility of BaF₂ is 0.0077 mol/L in water.

To determine the mass of BaF₂ that will be dissolved in 125 mL of this saturated solution, we can use the following formula:

mass = concentration x volume x molar mass

The molar mass of BaF₂ is 175.32 g/mol.

The concentration of BaF₂ Is equal to its molar solubility, which is 0.0077 mol/L.

The volume of the solution is 125 mL, which is equal to 0.125 L.

Substituting these values in the formula, we get:

mass = 0.0077 mol/L x 0.125 L x 175.32 g/mol

mass = 0.27 g (approx.)

Therefore, approximately 0.27 grams of BaF₂will be dissolved in 125 mL of the saturated solution of BaF₂

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Answer:

The low molecular weight of water makes water a favorable liquid for steaming

When 32.0 g of NaCl are dissolved in water and diluted to 0.500 L, 1.10 M of NaCl is the formal concentration (expressed as mol/L or M).

To find the formal concentration, we need to determine the number of moles of NaCl present in the solution. The molar mass of NaCl is 58.44 g/mol, so to find the number of moles, we divide the mass of NaCl by its molar mass:

Number of moles = Mass / Molar mass of sodium chloride (NaCl)

Number of moles = 32.0 g / 58.44 g/mol = 0.548 mol

Next, we need to calculate the formal concentration by dividing the number of moles by the volume of the solution in liters:

Formal concentration = Number of moles / Volume of solution

Formal concentration = 0.548 mol / 0.500 L = 1.10 M.

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Explanation:

what properties are you talking about?

No idea what this is for, but I hope you have an amazing day:)

Answer:

4km

Explanation:

HOH can interact with other like molecules through:

• dispersion forces, dipole-dipole and hydrogen bonds;

• Therefore ;option C is correct

{Explanation: The intermolecular force which polar molecules take part in are dipole-dipole forces and molecules that is able to have stronger intermolecular between two molecules have dispersion forces, finally hydrogen bonds occurs when hydrogen is covalently bonded to other molecules }