Need help ??????????????

Answer:

y = ± √ 7/2

Step-by-step explanation:

2*y^2-8-(6-2*y^2)=0

(2 • (y2)) - 8) - (6 - 2y2) = 0

(2y2 - 8) - (6 - 2y2) = 0

Pull out like factors :

4y2 - 14 = 2 • (2y2 - 7)

4.2 Factoring: 2y2 - 7

difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

Proof : (A+B) • (A-B) =

A2 - AB + BA - B2 =

A2 - AB + AB - B2 =

A2 - B2

2 • (2y2 - 7) = 0

5.1 Solve : 2 = 0

5.2 Solve : 2y2-7 = 0

Add 7 to both sides of the equation :

2y2 = 7

Divide both sides of the equation by 2:

y2 = 7/2 = 3.500

When two things are equal, their square roots are equal. Taking the square root of the two sides of the equation we get:

y = ± √ 7/2

Answer:

20,160.

Step-by-step explanation:

Answer:

Um im sure the answer is C btw

Step-by-step explanation:

correct me if im wrong

Answer:

6715.486347 or 6715.49

Step-by-step explanation:

6200(1+.04/12)^12x2

The minimal approximation error A-A 2achievable by a rank-1 approximation A to A is

||A - A1||₂=0 where A is 2×2 matrix.

We have given a matrix A as seen in above figure or A = [ 5 15 ; 6 18 ; -1 -3 ; -4 -12 ; 2 6]

note here that C₂= 3C₁

where Cᵢ --> iᵗʰ column

v = [ 5 ; 6 ; -1 ; -4 ; 2]

||v||² = 82 => ||v|| = √82

and A At v = 820 v

and A At = [ 82 246 ; 246 738]

AAt [1;3] = 820[1;3]

=> v1 = 1/√10(1,3)^t

Then the best rank of 1 approx

= √820 /√80√10 [ 5 ; 6 ; -1 ; -4 ; 2] [ 1 3]

= A

Since , the rank of matrix A is one so, the minimal approx. value is ||A - A1||2 = 0

Hence, the minimal Approx. ||A - A1||2 = 0 .

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Complete question:

Consider the matrix A: A = [5 15] 6 18 -1 -3 -4 -12 [26] What is the minimal approximation error A-A 2 achievable by a rank-1 approximation A to A? Hint: Can you determine this without explicitly calculating the SVD?

Answer:

Add all of them together. 1/5 + 2/4 + 4/3 + 3/2 = 53/15 miles

Step-by-step explanation:

1/5 + 2(1/4) + 4(1/3) + 3(1/2)

Answer:

Step-by-step explanation:

The experimental probability of the cube landing on three is 1/10.

a. The corresponding unit rate of Dog Cakes, Bark Bits, and Woofy Waffles for each package is $1.85 per pound, $2.25 per pound, and $1.90 per pound respectively.

b. The best buy using the unit rates found in Part A is $1.85 per pound.

Part A: We divide the cost by the size to determine the unit pricing for each package.

Dog Cakes: The unit price is $74 divided by 40 pounds or $1.85 per pound.

Bark Bits: $27 divided by 12 pounds equals $2.25 per pound.

Unit pricing for Woofy Waffles is $76 divided by 40 pounds or $1.90 per pound.

Part B: We compare unit pricing to get the best purchase. The greatest deal is the package with the lowest unit price. The greatest deal in this situation is Canine Cakes, which has the lowest unit price at $1.85 per pound.

Even though Canine Cakes and Woofy Waffles have the same size (40 pounds), Canine Cakes has a cheaper unit rate than Woofy Waffles. The product with the highest unit rate is Bark Bits, making it the most costly per pound. Canine Cakes is the greatest purchase based on unit prices.

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The question is -

Jeremiah needed dog food for his new puppy. He compared the prices and sizes of three types of dog food.

Canine Cakes Bark Bits Woofy Waffles

Size (pounds) 40 12 40

Cost $74 $27 $76

Part A: Calculate the corresponding unit rate for each package.

Part B: Determine the best buy using the unit rates found in Part A. Explain your answer.

Answer:

the equation to find the slope is (y2-y1)/(x2-x1)

the points are (-1,2) and (2,2) so plug it in and you get

(2-2)/(2-(-1))

0/ (2+1)

0/3

whenever the numerator is 0, that means the slope is 0. the line is just a horizontal line.

Answer:

-12+8

Step-by-step explanation:

Answer:

The correct answer is c

Step-by-step explanation:

Got it on edg. 2021

If the reaction was done with excess sodium bicarbonate, the amount of calcium chloride would determine the amount of precipitate produced.

The theoretical mass of precipitate produced in a reaction between calcium chloride and sodium bicarbonate can be calculated by using the balanced chemical equation for the reaction. The balanced equation for this reaction is given as follows:

CaCl₂ + NaHCO₃ → CaCO₃ + NaCl + H₂O

In this reaction, one mole of calcium chloride reacts with one mole of sodium bicarbonate to produce one mole of calcium carbonate precipitate, one mole of sodium chloride solution, and one mole of water.

The mass of the precipitate can be calculated by multiplying the molar mass of calcium carbonate by the number of moles of calcium carbonate produced.

So, to calculate the theoretical mass of precipitate produced, you need to know the amount (in moles) of calcium chloride and sodium bicarbonate used in the reaction. If the reaction was done with excess sodium bicarbonate, the amount of calcium chloride would determine the amount of precipitate produced.

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Answer:

yes because 4 times 9 is equal to 36  and 4 times 5 is equal 20

Step-by-step explanation:

Yes, both the expressions ( 36 + 20 ) and 4 ( 9 + 5 ) are equivalent to each other.

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

The given expressions are solved as:-

First expression,

36 + 20 = 56

Second expression,

4( 9 + 5 ) = 36 + 20

               = 56

From the above calculations,

( 36 + 20 ) = 4 ( 9 + 5 )

Therefore, both the expressions ( 36 + 20 ) and 4 ( 9 + 5 ) are equivalent to each other.

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The expected value of the distribution for the random variable x is 10. This means that if we were to repeat the experiment many times, the average value of x would converge to 10, with some fluctuations around this central value due to the randomness of the uniform distribution.

The expected value of a random variable is a measure of the central tendency of its distribution, representing the average value that we would expect to observe over many trials or events. In the case of a uniform distribution, where all values between the minimum and maximum are equally likely, the expected value can be calculated as the average of the two endpoints:
e(x) = (5 + 15) / 2 = 10
Therefore, the expected value of the distribution for the random variable x is 10. This means that if we were to repeat the experiment many times, the average value of x would converge to 10, with some fluctuations around this central value due to the randomness of the uniform distribution.
It is important to note that the expected value is not always equal to the most common or typical value of a distribution, but rather represents a measure of the overall tendency of the data. Other measures such as the variance or standard deviation can provide additional information about the spread or variability of the distribution, which can be useful for making statistical inferences or predictions.

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Step-by-step explanation:

Hey there!

Given;

f(X) = (3-x)/(x^2+4).

g(x) = 3x.

Now;

g(2) = 3*2

= 6

Now, Find f(g(2))

\( = f(g(2)) \)

\( = f(6)\)

\( = \frac{3 - 6}{ {6}^{2} + 4} \)

\( = \frac{ - 3}{40} \)

\( = \frac{ - 3}{40} \)

Therefore, f(g(X))= -3/40.

Hope it helps...

The probability that a student who has an A is a male is 60%.

To find the probability that a student who has an A is a male, we need to calculate the ratio of the number of male students with an A to the total number of students with an A.

Given that there are 19 students in total, and 6 of them are female, we can determine that there are 19 - 6 = 13 male students. Out of these male students, 7 do not have an A. Therefore, the number of male students with an A is 13 - 7 = 6.

Now, we know that there are 10 students in total who have an A. Therefore, the probability that a student with an A is a male can be calculated as the ratio of the number of male students with an A to the total number of students with an A:

Probability = Number of male students with an A / Total number of students with an A

Probability = 6 / 10

Probability = 0.6 or 60%

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The probability that the center is up when the person’s call comes in is 2/5

What is Probability?

Probability is an area of mathematics that deals with numerical representations of how probable an event is to occur or how likely a statement is to be true. The probability of an occurrence is a number between 0 and 1, where 0 denotes the event's impossibility and 1 represents certainty.

Solution:

Let us consider a random variable Y it presents the number of person’s call comes when center is up. Beginning at 12:00 midnight, a computer center is up for 1 hour and then down for 2 hours on a regular cycle.

We need to find  the probability that the center is up when the person’s call comes in.

Let 12:00 midnight be ‘a = 0’, then we will have ‘b = 5’, therefore f(y) = 1/5

For beginning of a = 0, the computer is up for 1 hour, so P(0<Y<1)

The computer is down for 2 hours and then up for another one hour, so P(3<Y<4)

Hence,

The probability that the center is up when the person’s call comes in is given by:

P(0<Y<1) + P(3<Y<4) = ∫f(y) dy + ∫f(y) dy

= (1/5)y + (1/5)y

= (1/5)((1-0)+(4-3))

= 2/5

Therefore, The probability that the center is up when the person’s call comes in is 2/5

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Answer:

The segment that connects the midpoints of the legs of a trapezoid is called the median of the trapezoid.

Step-by-step explanation:

The intervals B) and C) therefore include a solution for the equation h(x) = k(x). Hence, the response is: B) -3 < x < 1.5, C) -1.5 < x < 1.5.

We must identify the ranges when h(x) = k. (x).

Let's first construct the equation:

|h(x)| + 1 = x^2 + 3

Given that h(x) is an absolute value function, we must take into account two scenarios:

Example 1: Since x - 4 0, |x - 4| equals x - 4.

When we enter this into the equation, we obtain:

(x - 4) + 1 = x^2 + 3

Simplifying:

x^2 - x - 6 = 0

Factoring:

(x - 3)(x + 2) = 0

Thus, x = 3 or x = -2.

Example 2: Since x - 4 0, |x - 4| equals - (x - 4)

When we enter this into the equation, we obtain:

-(x - 4) + 1 = x^2 + 3

Simplifying:

x^2 + x - 8 = 0

Factoring:

(x + 2)(x - 4) = 0

Thus, x = -2 or x = 4.

Hence, x = -2, 3, or 4 are the answers to the equation h(x) = k(x).

The intervals B) and C) therefore include a solution for the equation h(x) = k(x).

Hence, the response is:

B) -3 < x < 1.5

C) -1.5 < x < 1.5

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Answer: 28

Step-by-step explanation:

28 is thhe missing number

The profit of Aslam is Rs. 31,474.50 and the profit of Akram is Rs. 35,025.50.

To find the profit of each person, we can use the concept of ratios.

First, let's find the total investment made by both Aslam and Akram:
Total investment = Aslam's investment + Akram's investment
Total investment = 27000 + 30000 = 57000

Next, let's calculate the ratio of Aslam's investment to the total investment:
Aslam's ratio = Aslam's investment / Total investment
Aslam's ratio = 27000 / 57000 = 0.4737

Similarly, let's calculate the ratio of Akram's investment to the total investment:
Akram's ratio = Akram's investment / Total investment
Akram's ratio = 30000 / 57000 = 0.5263

Now, we can find the profit of each person using their respective ratios:
Profit of Aslam = Aslam's ratio * Total profit
Profit of Aslam = 0.4737 * 66500 = 31474.5

Profit of Akram = Akram's ratio * Total profit
Profit of Akram = 0.5263 * 66500 = 35025.5

Therefore, the profit of Aslam is Rs. 31,474.50 and the profit of Akram is Rs. 35,025.50.

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(a) To find the amount in the account at the end of 1 year, we use the formula:

A = P(1 + r)^n

where A is the amount in the account at the end of the year, P is the principal (the initial amount deposited), r is the interest rate as a decimal, and n is the number of times the interest is compounded in a year. In this case, P = $4500, r = 0.06 (since the interest rate is 6%), and n = 1 (since the interest is compounded once a year). So, we have:

A = $4500(1 + 0.06)^1

= $4500(1.06)

= $4770

Therefore, the amount in the account at the end of 1 year is $4770.

(b) To find the amount in the account at the end of 2 years, we again use the formula:

A = P(1 + r)^n

However, in this case, n = 2 (since the interest is compounded twice in 2 years). So, we have:

A = $4500(1 + 0.06)^2

= $4500(1.1236)

= $5061.20

Therefore, the amount in the account at the end of 2 years is $5061.20.

a) The probability of having two flaws in one square meter of cloth is 0.0044. b) The probability of having one flaw in 10 square meters of cloth is 0.0360. c) The probability of having no flaws in 20 square meters of cloth is 0.1653. d) The probability of having at least two flaws in 10 square meters of cloth is 0.0337.

a) The Poisson distribution is used to model the number of flaws in bolts of cloth. The mean is given as 0.08 flaws per square meter. Using the formula for the Poisson distribution, we can calculate the probability of having two flaws in one square meter of cloth. The formula is P(X = k) = (e^(-λ) * λ^k) / k!, where λ is the mean and k is the number of flaws. Plugging in the values, we get \(P(X = 2) = (e^(-0.08) * 0.08^2) / 2! ≈ 0.0044.\)

b) To find the probability of having one flaw in 10 square meters of cloth, we need to consider the rate per square meter. Since the mean is given as 0.08 flaws per square meter, the mean for 10 square meters would be 0.08 * 10 = 0.8. Using the same Poisson formula, we calculate P(X = 1) = \((e^(-0.8) * 0.8^1) / 1! ≈ 0.0360.\)

c) For the probability of having no flaws in 20 square meters of cloth, we can again use the Poisson formula with the mean adjusted for the area. The mean for 20 square meters is 0.08 * 20 = 1.6. Plugging the values into the formula, we get \(P(X = 0) = (e^(-1.6) * 1.6^0) / 0! ≈ 0.1653.\)

d) To find the probability of having at least two flaws in 10 square meters of cloth, we can calculate the complement of the probability of having zero or one flaw. Using the same mean of 0.8, we can calculate P(X ≤ 1) and subtract it from 1 to get the desired probability. P(X ≤ 1) = P(X = 0) + P(X = 1) ≈ 0.2018. Therefore, P(X ≥ 2) ≈ 1 - 0.2018 = 0.7982.

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Answer:

a= 11/30

Step-by-step explanation:

Divide the 5 1/2 miles by the 15 minutes

5.5/15= .36

.36 = 11/30    

Answer:

The imaginary part is zero.

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

Two linear lines can never intersect twice

Answer:

12, 30, 36, 48

Step-by-step explanation:

Answer:

64

Step-by-step explanation: because he can at least steal 64 packs before   the                 cops get him

Answer:

4

or

4.92753623188  **However you cannot just buy a portion of one pack so you round back down to 4 packs.

Step-by-step explanation:

First we have $25, since he spent $8, we can now claim he has $17, Divide 17 into 3.45, He can buy 4 packs.

The fully expanded and simplified expression is:

\(4a^12 - 24a^9 + 36a^6.\)

An expression contains one or more terms with addition, subtraction, multiplication, and division.

We always combine the like terms in an expression when we simplify.

We also keep all the like terms on one side of the expression if we are dealing with two sides of an expression.

Example:

1 + 3x + 4y = 7 is an expression.com

3 + 4 is an expression.

2 x 4 + 6 x 7 – 9 is an expression.

33 + 77 – 88 is an expression.

We have,

To expand \((2a^6 - 6a^3)^2\), we can use the formula:

\((a + b)^2 = a^2 + 2ab + b^2\)

with \(a = 2a^6\) and \(b = -6a^3:\)

\((2a^6 - 6a^3)^2 = (2a^6)^2 + 2(2a^6)(-6a^3) + (-6a^3)^2\)

\(= 4a^12 - 24a^9 + 36a^6\)

Thus,

The fully expanded and simplified expression is:

\(4a^12 - 24a^9 + 36a^6.\)

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The inradius of the triangle of the given dimensions will be equal to the value 2.

To find the inradius of a triangle, we need to know the semi perimeter of the triangle, which is half of the perimeter. The perimeter of a triangle is the sum of the lengths of its sides. So, the semi perimeter of triangle ABC is (6+8+10)/2 = 12.

Now that we know the semi perimeter, we can use the formula for the inradius of a triangle:

inradius = √(s-a)(s-b)(s-c)/s

where a, b, and c are the lengths of the sides of the triangle and s is the semi perimeter.

Plugging in the values for a, b, c, and s, we get:

inradius = √(12-6)(12-8)(12-10)/12 = √(6)(4)(2)/12 = √48/12} = √4 = 2

Therefore, the inradius of triangle ABC is 2.

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