Answers
Answer:
4:1 (I think)
Step-by-step explanation:
Let's write some equations first:
For both prices increasing by 20:
\(\frac{x+20}{y+20} =\frac{5}{2}\)
then we can use cross multiplication
2x+40=5y+100
For both prices decreasing by 5:
\(\frac{x-5}{y-5} =\frac{5}{1}\)
same here:
5y-25=x-5
Using substitution for 5y, we get: 5y=x+20
2x+40=5y+100
2x+40=x+20+100
x=80
plugging this in to the second equation:
5y-25=x-5
5y-25=80-5
5y-25=75
5y=100
y=20
therefore we get x:y=80:20
4:1
Related Questions
Trina has a credit card that uses the adjusted balance method. For the first 10
days of one of her 30-day billing cycles, her balance was $780. She then
made a purchase for $170, so her balance jumped to $950, and it remained
that amount for the next 10 days. Trina then made a payment of $210, so her
balance for the last 10 days of the billing cycle was $740. If her credit card's
APR is 17%, which of these expressions could be used to calculate the
amount Trina was charged in interest for the billing cycle?
OA. (30)($780)
365
B.
O C.
D.
0.17
365
0.17
365
0.17
365
30
30
(10 $780+10 $950 +10 $210)
30
10
$780+10$950+10 $740
30
•30) ($570)
Answers
The expression that could be used to calculate the amount Trina was charged in interest for the billing cycle is (APR / 365) x 30 days x adjusted balance.
What is the adjusted balance method?The adjusted balance method is one of the methods for computing the finance charge (interest and other fees) for credit cards.
The adjusted balance is the ending balance determined after adjusting the opening balance with purchases and payments.
Credit card interest method = adjusted balance method
Beginning balance = $780
Purchase = $170
Payment = $210
Adjusted balance, AB = $740 ($780 + $170 - $210)
APR = 17% = 0.17 (17/100)
The interest charged = (APR / 365) x 30 days x adjusted balance
= $10.34 [(0.17/365) x 30 x $740]
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2x+7x=77
5x+7y=115
solve for x & y that makes both expressions true.
Answers
The solution that makes both expressions true is x = 8.55556 and y = 10.31746.
To solve for x and y, we need to use a system of equations involves finding the values of x and y that satisfy both equations simultaneously.
We can start by using the first equation to solve for x:
2x + 7x = 77
Combining like terms:
9x = 77
Dividing both sides by 9:
x = 8.55556 (rounded to six decimal places)
Now that we know the value of x we can use either equation to solve for y. Let's use the second equation:
5x + 7y = 115
Substituting x = 8.55556:
5(8.55556) + 7y = 115
Simplifying:
42.7778 + 7y = 115
Subtracting 42.7778 from both sides:
7y = 72.2222
Dividing both sides by 7:
y = 10.31746 (rounded to six decimal places)
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Sorting algorithms no unread replies.no replies. we are using and interacting with sorting algorithms in every day life. in your chapter reading this week, you reviewed many sorting algorithms. find an example of a place in real, everyday life where you interact with, implement or use one of the sorting algorithms covered in chapter 3. for example, while playing cards you may have found yourself implementing the insertion sort algorithm (without knowing it). for this peer interaction, post your example of a place in real, everyday life where you interact with, implement or use one of the sorting algorithms. be sure to provide your us with enough information so that we will thoroughly understand your example and use of a sorting algorithm. once you have made your post, please respond to at least two of your classmates interacting and communicating on the sorting algorithm use in real world context.
Answers
A sorting algorithm is defined as an algorithm that sorts the elements of a list. The most commonly used sequences are numerical sequence and lexicographical sequence, ascending or descending.
A sorting algorithm is used to reorder an array or list of elements according to an element comparison operator. Comparison operators are used to define a new order of elements in that data structure. Consider example, The above list of characters is sorted in ascending order by their value. That is, characters with lower values are placed before characters with higher values. It is important in real life because it supports the development of the scientific concept that things can be owned and organized into distinct groups (e.g. creatures, cars, weather types, etc.). We will now discuss some real-world examples of using sorting algorithms.
1) Your phone's contact list is sorted. This means that your data is organized in this way so you can easily access the contacts you want from your phone. That is, "I ordered."
2) Paper sorting : Imagine a teacher sorting students' work alphabetically by student name. This type of operation is similar to the functionality of sorting algorithms such as bucket sort. Sorting is more efficient process.
3) Traffic lights : Traffic lights are a good example of how algorithms are used in the real world around us. Next time you get stuck in a car at a red light, think about the algorithm that traffic lights run." Most traffic lights don't automatically switch between green, yellow, and red. This algorithm is a well-established turn-by-turn algorithm that directs traffic correctly. It's in order (it may not seem that way when you're sitting at a red light).
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seb buys 1 gallon of paint that covers 400 square feet
Answers
The least amount of paint that is needed to paint the walls of a room with a rectangular prism shape is 1. 8 gallons.
How to find the amount of paint ?There would be two walls with 10 x 16 dimensions so the area is :
= 2 x 10 x 16
= 320 square feet
Two walls with 20 x 10 dimensions :
= 2 x 20 x 10
= 400 square feet
The total area is :
= 400 + 320
= 720 square feet
One gallon of paint can cover 400 square feet so the number of gallons needed is:
= 720 / 400
= 1. 8 gallons
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Full question is:
One gallon of paint covers 400 square feet. What is the least amount of paint needed to paint the walls of a room in the shape of a rectangular prism with a length of 20 feet, a width of 16 feet, and a height of 10 feet? Write your answer as a decimal.
Prove that if A and B are m x n matrices, then A and B are row equivalent if and only if A and B have the same reduced row echelon form
Answers
We have proven that if A and B are m x n matrices, then A and B are row equivalent if and only if A and B have the same reduced row echelon form.
What is matrices?Matrices are a type of mathematical structure used to store and analyze data. They are represented as a series of rows and columns, with each cell in the matrix containing a number or other value. Matrices are used to solve systems of equations, perform matrix multiplication and determine the inverse of a matrix. They are also used in linear programming, cryptography, and other areas of mathematics.
Row equivalence is defined as a pair of matrices A and B being row equivalent if there is a sequence of row operations that can transform A into B, or vice versa. This means that if A and B are row equivalent, then A and B can be transformed into one another by a series of row operations.
A reduced row echelon form is defined as a matrix in which all non-zero rows are above any rows of all zeroes and the leading coefficient of each non-zero row is 1. In other words, all of the non-zero rows have a leading coefficient of 1, and any rows of all zeroes are below the non-zero rows.
Therefore, if A and B are row equivalent, then A and B can be transformed into one another by a series of row operations. This means that we can use the same series of row operations to transform A and B into the same reduced row echelon form. This proves that if A and B are row equivalent, then A and B have the same reduced row echelon form.
On the other hand, if A and B have the same reduced row echelon form, then they must have been transformed into the same form by a series of row operations. This means that the same series of row operations must have been used to transform A and B into the same reduced row echelon form, which means that A and B are row equivalent. This proves that if A and B have the same reduced row echelon form, then A and B are row equivalent.
To prove that if A and B are m x n matrices, then A and B are row equivalent if and only if A and B have the same reduced row echelon form, we can use the definition of row equivalence and the definition of a reduced row echelon form.
Therefore, we have proven that if A and B are m x n matrices, then A and B are row equivalent if and only if A and B have the same reduced row echelon form.
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Just give me the answer no expiation.
Answers
Answer:
b. 424
Step-by-step explanation:
it gives the equation N=41b+137
N=41(7)+137
N=424
How can you check if a line belongs to a plane (Cartesian equation of the line and the equation of the plane is given)?
Answers
For example, suppose you have the Cartesian equation of a line in the form:
y = mx + b
and the equation of a plane in the form:
ax + by + cz + d = 0
To check if the line belongs to the plane, you can substitute a point (x, y) on the line into the equation of the plane and solve for z. If the resulting value of z satisfies the equation of the plane, then the line belongs to the plane.
Here's an example:
Suppose the Cartesian equation of the line is y = 2x + 1, and the equation of the plane is 2x + 3y + 4z + 5 = 0.
If we substitute a point on the line, such as (1, 3), into the equation of the plane, we get:
2(1) + 3(3) + 4z + 5 = 0
Solving for z, we find that z = -1.5.
Since the resulting value of z satisfies the equation of the plane, the line belongs to the plane.
If the resulting value of z does not satisfy the equation of the plane, then the line does not belong to the plane.
Julián gasta 2/5 de sus ahorros en el viaje “fin de curso” y el 25% de ellos en unos patines.
a) Si los ahorros de Julián son 140 € ¿cuánto gasta en el viaje “fin de curso”?
b) ¿Y cuánto le cuestan los patines?
c) ¿Cuántos euros le quedan a Julián?
Answers
The Julián has 0.84 euros left after making these purchases.
Given that Julián spends 2/5 of his savings on a school trip, and 25% of his savings on skates. The question is asking us to find out how much the skates cost and how much money he has left after making these purchases. Let's solve this problem step-by-step.
Part (a) is already solved as we know that Julián spends 2/5 of his savings on a school trip and 25% of his savings on skates.
Part (b) To determine how much the skates cost, we need to first find out what percentage of his savings he spent on skates. Since he already spent 2/5 of his savings, that means he has 3/5 left.
And since he spent 25% of his total savings on skates, we can set up an equation as follows:
0.25(x) = 3/5where x is his total savings.
Cross-multiplying: 0.25(x) * 5 = 3x1.25x = 3x = 3/1.25x ≈ 2.4So, his total savings would be around 2.4 euros.
Therefore, the cost of the skates is 0.25(2.4) = 0.6 euros.Part (c) To find out how much money he has left, we subtract the cost of the school trip and the skates from his total savings:
Total savings - School trip - Skates
= Money left2.4 - (2/5)(2.4) - 0.6
= Money left2.4 - 0.96 - 0.6
= Money left0.84 euros
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Newton's Law of Gravitation states that two bodies with masses m1 and m2 attract each other with a force F, where r is the distance between the bodies and G is the gravitational constant. F = G(m_1m_2)/r^2 Use Newton's Law of Gravitation to compute the work W required to propel a 1100 kg satellite out of the earth's gravitational field. You may assume that the earth's mass is 5.98✕1024 kg and is concentrated at its center. Take the radius of the earth to be 6.37✕106 m and G = 6.67✕10-11 Nm2/kg2. (Round your answer to three significant digits.)
Answers
The two bodies are being drawn together by a force of 10812 N, according to Newton's Law of Gravitation.
Every particle in the universe is drawn to every other particle with a force that is directly proportional to the product of their masses and inversely proportional to their separation from one another, according to Newton's Law of Universal Gravitation.
Symbolically, Newton came to the following conclusion on the strength of the gravitational force:
F = G(m₁ × m₂) / r²
F is the gravitational force between two bodies, m1 and m2 are the bodies' masses, r is the distance between their centres, and G is the gravitational constant of the universe.
According to the query,
satellite's mass is m1 = 1100 kg.
mass of earth = 5.98 ×10²⁴ kg
Radius of the earth = 6.37 × 10⁶ m
G = 6.67 × 10⁻¹¹ Nm² / kg²
Force = G(m₁ × m₂) / r²
Substituting the values,
F = 6.67 × 10⁻¹¹( 1100 × 5.98 ×10²⁴) /( 6.37 × 10⁶)²
=> F = 6.67 × 1100 × 5.98 × 10¹³ / 40.58 × 10¹²
=> F = 43,875.26 × 10 / 40.58
=> F = 10812 N
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Check for extraneous solutions when plugging -7 into x-5=2(x+1).
Check for extraneous solutions when plugging 1 into x-5=-2(x+1)
Please hurry
Answers
There are no extraneous solutions when plugging -7 into x-5=2(x+1).
So extraneous solutions means the solutions that you get by solving an equation, but after you try plugging it back into your original equation, the solution does not work.
Now we have our solutions of x=7, and we just need to check whether it is extraneous or not. We can do this by taking x=1 and plugging it back into your original equation x - 5 = 2(x + 1)
x - 5 = 2(x + 1)
-7 - 5 = 2(-7 + 1)
-12 = -14 + 2
-14 + 14
0 = 0
We end up getting that 0 = 0 which is correct,
Thus, there are no extraneous solutions.when plugging -7 into x-5=2(x+1).
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Need answer with full work
Answers
Answer:
Step-by-step explanation:
x^2 - 17x - 60
(x - 20)(x + 3)
x^2 + 3x - 20x - 60
x^2 - 17x - 60
(x + 20) is not one of the factors
using F.O.I.L., it would have been
x^2 + 17x - 60
Solve 2-3 cos x=5+3 cosx for 0° ≤ 180°
Answers
The equation 2-3cos(x) = 5+3cos(x) has no solution in the range of 0° to 180°.
1. Start with the given equation: 2-3cos(x) = 5+3cos(x).
2. Subtract 3cos(x) from both sides to isolate the constant term: 2-3cos(x) - 3cos(x) = 5.
3. Combine like terms: 2-6cos(x) = 5.
4. Subtract 2 from both sides: -6cos(x) = 3.
5. Divide both sides by -6: cos(x) = -1/2.
6. To find the solutions for cos(x) = -1/2 in the range of 0° to 180°, we need to determine the angles where cos(x) equals -1/2.
7. These angles are 120° and 240°, as cos(120°) = cos(240°) = -1/2.
8. However, the given equation states that 2-3cos(x) equals 5+3cos(x), which is not satisfied by cos(x) = -1/2.
9. Therefore, the equation 2-3cos(x) = 5+3cos(x) has no solution in the range of 0° to 180°.
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You can use a calculator if you want :)
Answers
Answer:
A. -0.02
Step-by-step explanation:
-\(\frac{5}{25}\)=-\(\frac{1}{5}\)
1/5 is 20%
-1/5 is -20%
-.02% is greater because it's closer to zero
The graph of the function f(x) = (x − 3)(x + 1) is shown.
On a coordinate plane, a parabola opens up. It goes through (negative 1, 0), has a vertex at (1, negative 4), and goes through (3, 0).
Which describes all of the values for which the graph is positive and decreasing?
all real values of x where x < −1
all real values of x where x < 1
all real values of x where 1 < x < 3
all real values of x where x > 3
Answers
The expression that describes all of the values for which the graph is positive and decreasing is all real values of x where x < -1
Which describes all of the values for which the graph is positive and decreasing?The equation of the function is given as:
f(x) = (x - 3)(x + 1)
When the value of the graph is positive, we have:
f(x) > 0
So, the function becomes
(x - 3)(x + 1) > 0
Split the above inequality
x - 3 > 0 and x + 1 > 0
Solve for x in the inequalities
x > 3 and x > -1
Hence, the expression that describes all of the values for which the graph is positive and decreasing is all real values of x where x < -1
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NEED HELP ON THIS ASAP!!
Answers
Answer :
The answer is A.
Answer:
A) 140
Step-by-step explanation:
since angle RA is 40
and angle one seems the same so
<1+<2=140
40+<2=180
-40 -40
<2=140
Constant of Variation
Does the function y = 10/x² shown in the graph below have a maximum y=value or a minimum y-value?
Answers
Answer:
No
Step Explanation:
I calculated it logically
Hi can someone please help me solve the following system of inequalities and state the coordinates in the solution setz
Answers
The graph of the system of the inequalities is attached.
To graph the inequalities y < -x - 4 and y ≥ (3/5)x + 4, we can start by graphing the corresponding equations and then shade the appropriate regions based on the inequality signs.
Let's begin with the equation y = -x - 4:
Choose a range of x-values to plot.
For simplicity, let's use x-values from -10 to 10.
Substitute different x-values into the equation to find corresponding y-values.
For example:
When x = -10, y = -(-10) - 4 = 10 - 4 = 6.
When x = 0, y = -(0) - 4 = -4.
When x = 10, y = -(10) - 4 = -10 - 4 = -14.
Plot these points on the coordinate plane and draw a straight line passing through them.
This line represents the equation y = -x - 4.
Next, let's graph the equation y = (3/5)x + 4:
Again, choose a range of x-values to plot. Let's use the same range of -10 to 10.
Substitute different x-values into the equation to find corresponding y-values. For example:
When x = -10, y = (3/5)(-10) + 4 = -6 + 4 = -2.
When x = 0, y = (3/5)(0) + 4 = 0 + 4 = 4.
When x = 10, y = (3/5)(10) + 4 = 6 + 4 = 10.
Plot these points on the coordinate plane and draw a straight line passing through them.
This line represents the equation y = (3/5)x + 4.
Now, let's shade the regions based on the inequalities:
For y < -x - 4, we need to shade the region below the line y = -x - 4.
For y ≥ (3/5)x + 4, we need to shade the region above or on the line y = (3/5)x + 4.
Hence, the region where the shaded regions overlap represents the solution to both inequalities.
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The sum of three consecutive integers is 33. What are the numbers?
Answers
Answer:
10,11,12
Step-by-step explanation:
Divide 33 by 3 and get 11. So the number 11 a number 1 less than 11 and a number one more than 11 will get you the correct answer.
The difference between the circumference and the diameter of a circle is 90cm. Find the radius
Answers
Answer:
Step-by-step explanation:
Circumference is 2πr - 2r = 90cm
2r(π-1)=90
divide both sides by (π-1)
2r = 90/(π-1)
2r = 42.024...
r = 21.012399 cm
Help
Albie is comparing the ratio of students in her class that are wearing the color green to the total number of students in her class. She finds out of 30 students in her class, 7 are wearing green. What kind of ratio relationship is she using?:
A: Part-to-part relationship
B: Whole relationship
C: Part-to-whole relationship
D: Part relationship
Answers
Answer:
C
Step-by-step explanation:
Beacuse part to whole means describing a specific part of a group to the whole group, in our case students wearing green : students
(a) Tom is 7 years old. Bill is 5 years older than Tom.
Write Bill's age in terms of T.
Answers
Answer:
12 years old
Step-by-step explanation:
7 + 5 = 12
T + 5
A fish is reeled in at a rate of 1.9 feet per second from a point 10 feet above the water (see figure). At what rate is the angle between the line and the water changing when there is a total of 25 feet of line out?
Answers
9514 1404 393
Answer:
1.9 degrees per second
Step-by-step explanation:
The angle α the line makes with the water can be described by ...
Sin = Opposite/Hypotenuse
sin(α) = 10/(25 -1.9t)
Taking derivatives gives ...
α'·cos(α) = -10(-1.9)/(25 -1.9t)²
Then the rate of change of the angle at t=0 is ...
α' = 19/(25²·cos(α))
Of course, cos(α) = √(1 -sin(α)²) = √(1 -(10/25)²) = √(21/25), so we have ...
α' = 19/(125√21) . . . radians/second
α' ≈ 0.033269 radians/s ≈ 1.90 degrees/s
Find the total surface area
Answers
Answer:
585
Step-by-step explanation:
Explanation in picture below.
What is the exact value of sin pi/3?
Answers
The exact value of sin(pi/3) is √3. By definition, the sine of an angle is the ratio of the length of the opposite side to the length of the hypotenuse. Therefore, sin(pi/3) = √3/1 = √3.
The exact value of sin(pi/3) can be determined using trigonometric properties and identities.
First, we know that pi/3 is equivalent to 60 degrees. In a unit circle, the point corresponding to 60 degrees forms an equilateral triangle with the origin and the x-axis. This triangle has side lengths of 1, 1, and √3.
To find the sine of pi/3, we consider the side opposite the angle (pi/3) in the triangle. In this case, the opposite side has a length of √3. The hypotenuse of the triangle is 1, as it is the radius of the unit circle.
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A Six packs of undershirt cost $13.98. This is $3.96 less the cost of buying six individual shirts if each undershirt cost the same amount how much does each undershirt cost when purchased individually?
Answers
(1) Complete the number sequences.
(a) 0.4, 0.2, 0.6, 0.4, 1.2, 1.0, 3.0,
Answers
The next three numbers of sequence is,
⇒ 2.8, 8.4, 8.2
What is Multiplication?To multiply means to add a number to itself a particular number of times. Multiplication can be viewed as a process of repeated addition.
Given that;
The sequence is,
⇒ 0.4, 0.2, 0.6, 0.4, 1.2, 1.0, 3.0, .., .., ...,
Now,
Since, The sequence is,
⇒ 0.4, 0.2, 0.6, 0.4, 1.2, 1.0, 3.0, .., .., ...,
Clearly, The pattern of the sequence is,
⇒ 0.4 - 0.2 = 0.2
⇒ 0.2 × 3 = 0.6
⇒ 0.6 - 0.2 - 0.4
⇒ 0.4 × 3 = 1.2
⇒ 1.2 - 0.2 = 1.0
⇒ 1.0 × 3 = 3.0
⇒ 3.0 - 0.2 = 2.8
⇒ 2.8 × 3 = 8.4
⇒ 8.4 - 0.2 = 8.2
Thus, Next three terms of the sequence is,
⇒ 2.8, 8.4, 8.2
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11+m>15 what’s the answer for this problem?
Answers
Answer:
m > 4
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightEquality Properties
Step-by-step explanation:
Step 1: Define
11 + m > 15
Step 2: Solve for m
Subtract 11 on both sides: m > 4Here we see that any value m greater than 4 would work as a solution to the inequality.
Use Newton’s Method to find the solution to x^3+1=2x+3 use x_1=2 and find x_4 accurate to six decimal places. Hint use x^3-2x-2=0 as your equation.
Answers
Let \(f(x) = x^3 - 2x - 2\). Then differentiating, we get
\(f'(x) = 3x^2 - 2\)
We approximate \(f(x)\) at \(x_1=2\) with the tangent line,
\(f(x) \approx f(x_1) + f'(x_1) (x - x_1) = 10x - 18\)
The \(x\)-intercept for this approximation will be our next approximation for the root,
\(10x - 18 = 0 \implies x_2 = \dfrac95\)
Repeat this process. Approximate \(f(x)\) at \(x_2 = \frac95\).
\(f(x) \approx f(x_2) + f'(x_2) (x-x_2) = \dfrac{193}{25}x - \dfrac{1708}{125}\)
Then
\(\dfrac{193}{25}x - \dfrac{1708}{125} = 0 \implies x_3 = \dfrac{1708}{965}\)
Once more. Approximate \(f(x)\) at \(x_3\).
\(f(x) \approx f(x_3) + f'(x_3) (x - x_3) = \dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125}\)
Then
\(\dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125} = 0 \\\\ \implies x_4 = \dfrac{5,881,319,037}{3,324,107,515} \approx 1.769292663 \approx \boxed{1.769293}\)
Compare this to the actual root of \(f(x)\), which is approximately 1.769292354, matching up to the first 5 digits after the decimal place.
b) A car priced at $3600 is reduced by 25%.
What is the reduced price?
Answers
3600:25 =144
reduced price is 144$
i dont know how to do this so hElp
Answers
Answer:
3.5× c20
#######################