Neglecting friction, what factor affects the final speed of an object sliding down a ramp? - gravity - the length of the ramp - the height of the ramp - the mass of the object - the path the object takes
Answers
The factor that affects the final speed of an object sliding down a ramp is primarily gravity. The force of gravity pulls the object down the ramp and increases its speed as it moves toward the bottom.
The height of the ramp also affects the speed, as a higher ramp will provide the object with more potential energy, which will then be converted into kinetic energy as it slides down.
The length of the ramp, on the other hand, does not directly affect the speed, but it may indirectly affect it by changing the angle of the ramp and therefore altering the force of gravity acting on the object.
The mass of the object will also affect the speed, with heavier objects accelerating slower than lighter objects due to the increased force required to move them.
Finally, the path the object takes will not affect the speed if the ramp is a straight line, but if the ramp has twists and turns, the object may slow down due to the friction caused by these changes in direction.
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Neglecting friction, the final speed of an object sliding down a ramp is primarily affected by the following factors:
The height of the ramp: The height of the ramp determines the gravitational potential energy that the object has at the top of the ramp. As the object slides down the ramp, this potential energy is converted into kinetic energy, which determines the speed of the object. The greater the height of the ramp, the greater the gravitational potential energy, and hence the greater the final speed of the object.The length of the ramp: The length of the ramp determines the distance over which the potential energy is converted into kinetic energy. The longer the ramp, the more time the object has to accelerate due to gravity, and hence the greater the final speed of the object.The mass of the object: The mass of the object also affects the final speed. Heavier objects have more inertia, which means that they resist changes in motion more than lighter objects. This means that a heavier object sliding down a ramp will have a lower final speed than a lighter object, given the same height and length of the ramp.The path the object takes: The path the object takes down the ramp can also affect the final speed, but only if the ramp is curved or has a complex shape. In such cases, the path can affect the direction and magnitude of the gravitational force acting on the object, and hence affect its final speed. However, for a straight ramp, the path taken by the object does not affect the final speed, as long as it remains on the ramp.In summary, the final speed of an object sliding down a ramp is primarily affected by the height and length of the ramp, and the mass of the object.
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Related Questions
In a salt solution, salt is a solute. why
Answers
Answer: Because it can dissolve in water
Explanation: Logic
What does WNBA stand for
Answers
Answer:
Women's national basketball association
Explanation:
Answer: womens national basketball association
Explanation: my dream
Barbera argues that simple machines like levers and pulleys reduce the amount of work needed
to get things done. Clarice argues that machines don’t decrease work - they decrease force.
Who is right and why?
Answers
Answer:
Machines can reduce force but not work.
Work = force * distance
If a machine reduces the force input by a factor of two, say, then the distance traveled by the applied force must be doubled
One cannot get more work out of a machine than the work input to the machine.
A roller coaster has a loop in which the centripetal acceleration equals 9.8m/s2 . Of the tangential speed of the roller coaster cars is 15-7 m/s
Answers
Answer:
25.152mExplanation:
Compete question;
A roller coaster has a loop in which the centripetal acceleration equals 9.8m/s² . If the tangential speed of the roller coaster cars is 15.7 m/s, find its radius.
centripetal acceleration a = v²/r
v is the tangential speed
r is the radius
Given
v = 15.7m/s
a = 9.8m/s²
9.8 = 15.7²/r
9.8r = 15.7²
r = 15.7²/9.8
r = 246.49/9.8
r = 25.152m
Hence the radius of the coaster is 25.152m
A bat hasa mads of 2kg at the velocity of 45 m/s what is the kinectic energy could he give to a ball
Answers
Answer:
the kinetic energy the bat can give to a ball is 2,025 J.
Explanation:
Given;
mass of the bat, m = 2kg
velocity of the bat, v = 45 m/s
The kinetic energy the bat can give to a ball is calculated as;
\(K.E = \frac{1}{2} mv^2\\\\K.E = \frac{1}{2} \times \ 2 \ \times \ 45^2\\\\K.E = 2,025 \ J\)
Therefore, the kinetic energy the bat can give to a ball is 2,025 J.
1. A meter rule is found to balance at the 48cm mark. When a body of mass 60g is suspended at the 6cm mark the balance point is found to be at the 30cm mark. Calculate, i) the mass of the meter rule 11) the distance of the balance point from the zero end, if the body were moved to the 13cm mark.
Answers
Hi there!
We can use a summation of torques to solve.
Recall the equation for torque:
\(\large\boxed{\Sigma \tau = rF}\)
r = distance from fulcrum (balance point)
F = force (in this instance, weight, N)
We can set the fulcrum to be the balance point of 30 cm.
Thus:
Meter ruler:
Center of mass at 48 cm ⇒ 48 - 30 = 18 cm
Object:
At 6cm ⇒ 30 - 6 = 24 cm
For the ruler to be balanced:
\(\large\boxed{\Sigma \tau_{cc} = \Sigma \tau_{ccw}}\)
Thus:
\(M_Rg(18) = 60g(24)\\M_R = \frac{60(24)}{18} = \boxed{80 g}\)
The mass of the ruler is 80 grams.
If the body were moved to 13 cm:
B (balance point) - 13 = distance of object
48 - B = distance from ruler center of mass to balance point
\(80g(48 - B) = 60g(B - 13)\\\\3840 - 80B = 60B - 780\\\\4620 = 140B\\\boxed{B = 33 cm}\)
The new balance point would be 33cm from the zero end.
A pickup truck of mass 3500 kg moving at 72 kmh-1 collides head-on with a car of mass 2000 kg moving in the opposite direction. After colliding, both the pickup and the car came to rest.
(i) An 8 grade physics student commented that the law of conservation of momentum was NOT upheld in this collision, since both vehicles were moving before the collision and none of them was moving after colliding. State whether or not you agree with the student's comment and give a reason why you agree or disagree.
Answers
Answer:
Explanation:
The Law of Momentum Conservation says that the mass times the velocity of the truck + the mass times the velocity of the car BEFORE they hit has to = the mass of the tuck times the velocity of the truck + the mass of the car times the velocity of the car AFTER they hit. If we don't know the velocity of the car, we can solve for it, and then we can say that Momentum has been conserved. Before I do that, I am going to tell you that 72 kmh is 20 m/s.
\((3500*20+2000x)_b=0_a\) The 0 is because if there is no velocity after they hit, it doesn't matter what the velocities are; anything times 0 is 0.
70,000 + 2000x = 0 where x is the velocity of the car
70,000 = -2000x so
x = -35.
As long as the car was initially traveling 35 m/s in the opposite direction )hence, the - sign), momentum is conserved. So I'm not sure exactly how you can answer this otherwise.
A baseball bat strikes a baseball with a force of 35 N. The bat is in contact with the ball for 0. 12 s.
What impulse did the bat exert on the baseball to change the ball's momentum?
Answers
Answer:
4.2 N. S
Explanation:
Impulse =Force X Time
35 X 0.12
4.2 N
5). A body of mass 75kg lying on a surface of
μ = 0.4 move in the direction of a horizontal force
of 300N applied to it.
a). Calculate the
i). friction force
ii). acceleration of the body
b). Explain the result in aii).
Answers
Explanation:
a) i) Calculation of the friction force:
The friction force can be determined using the equation:
friction force = coefficient of friction * normal force
The normal force is equal to the weight of the object, which can be calculated as:
normal force = mass * gravitational acceleration
where the gravitational acceleration is approximately 9.8 m/s².
normal force = 75 kg * 9.8 m/s² = 735 N
friction force = 0.4 * 735 N = 294 N
ii) Calculation of the acceleration of the body:
Now, we can calculate the acceleration using Newton's second law:
net force = mass * acceleration
Since the applied force and the friction force act in opposite directions, the net force can be calculated as:
net force = applied force - friction force
net force = 300 N - 294 N = 6 N
mass = 75 kg
6 N = 75 kg * acceleration
acceleration = 6 N / 75 kg = 0.08 m/s²
b) Explanation:
In part (a), we calculated the friction force to be 294 N and the acceleration of the body to be 0.08 m/s². The positive acceleration indicates that the body is moving in the direction of the applied force.
The friction force opposes the motion of the body and acts in the opposite direction to the applied force. In this case, the applied force of 300 N is greater than the friction force of 294 N. As a result, the net force acting on the body is 6 N in the direction of the applied force.
The small net force of 6 N, compared to the body's mass of 75 kg, results in a relatively low acceleration of 0.08 m/s². This indicates that the body will accelerate slowly in the direction of the applied force due to the presence of friction.
Overall, the friction force and the resulting acceleration of the body are determined by the coefficient of friction (μ) and the mass of the object. In this case, the body experiences a relatively high friction force, leading to a small acceleration.
you have an open tube that is 1.7m long what is the fundemental frequency and wavelength of the tube
Answers
write an equation for the acceleration of the two connected blocks in terms of m1, m2, and the acceleration due to gravity g.
Answers
The equation for the acceleration of the two connected blocks in terms of m1, m2, and the acceleration due to gravity is a = (m1 + m2)g/m2.
The equation shows that the acceleration of the two connected blocks is directly proportional to the total mass of the two blocks and the acceleration due to gravity. In other words, the more mass in the two blocks, the higher the acceleration.
Similarly, as the acceleration due to gravity increases, the acceleration of the two connected blocks increases. To understand this further, consider the example of two blocks, one with mass m1 and the other with mass m2, being accelerated by the same force due to gravity.
The equation shows that the acceleration of the two blocks is a = (m1 + m2)g/m2, where m1 and m2 are the masses of the two blocks and g is the acceleration due to gravity. This means that if the mass of the first block is doubled, the acceleration will double. Similarly, if the acceleration due to gravity is doubled, the acceleration of the two blocks will also double.
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Calculate the energies of the first four rotational levels of1H127 I free to rotate in three dimensions,using for its moment of inertia I=μR2, with μ=mHmI/(mH+mI) and R = 160 pm
Answers
The energies of the first four rotational levels of 1H127I can be calculated using the formula:
E = B(J(J+1))
where B is the rotational constant, J is the rotational quantum number, and h and c are Planck's constant and the speed of light, respectively.
The rotational constant can be calculated using the moment of inertia formula I=μR^2 as follows:
B = h/(8π^2cI)
where h is Planck's constant, c is the speed of light, and I is the moment of inertia.
Substituting the given values we get:
μ = mHmI/(mH+mI) = (1.0078 amu * 126.9045 amu)/(1.0078 amu + 126.9045 amu) = 1.002 amu
I = μR^2 = (1.002 amu)(160 pm)^2 = 0.004921 kg m^2
B = h/(8π^2cI) = (6.626 x 10^-34 Js)/(8π^2 x 3 x 10^8 m/s x 0.004921 kg m^2) = 2.921 x 10^-23 J
Using the formula above, the energies of the first four rotational levels are:
E1 = B(1(1+1)) = 2B = 5.842 x 10^-23 J
E2 = B(2(2+1)) = 6B = 1.7526 x 10^-22 J
E3 = B(3(3+1)) = 12B = 3.5051 x 10^-22 J
E4 = B(4(4+1)) = 20B = 5.842 x 10^-22 J
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ultraviolet radiation falls in the wavelength region of to meters. what is the energy of ultraviolet radiation that has a wavelength of m? energy
Answers
the energy of ultraviolet radiation that has a wavelength is 6.95*\(10^{-19}\) kj/photon
calculation :
1.E =hc/λ
λ = hc/E
= \(\frac{6.6626*10^{-34}*3*10^{8} }{1.99*10^{-19} }\)
= \(1.0*10^{-8}m\)
2 . E =hc/λ
λ = hc/E
= \(\frac{6.6626*10^{-34}*3*10^{8} }{3.97*10^{-19} }\)
= 501 nm
3 . λ = 286 nm
E =hc/λ
= \(\frac{6.6626*10^{-34}*3*10^{8} }{286}\)
= 6.95*\(10^{-19}\) kj/photon
In physics, energy is the quantitative property transmitted to the body or physical system, perceived in the performance of work and in the form of heat and light. Energy is Conserved - The law of conservation of energy states that energy can be transformed into form, but cannot be created or destroyed. The unit of measure for energy in the International System of Units (SI) is the joule (J).
Common forms of energy include the kinetic energy of moving bodies, the potential energy stored in bodies (due to their position in the field, etc.), the elastic energy stored in fixed bodies, the chemical energy associated with chemical reactions, Radiant energy carried by electromagnetic radiation and internal energy contained in thermodynamic systems. All living things absorb and emit energy all the time.
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Why will an object in motion continue at a contant peed and in a contant direction
Answers
An object in motion continues to move at a constant speed and in a constant direction because there is no outside force acting upon it to change its speed and direction.
According to the first law of Newton, an object remains at rest or moves at a constant speed in a constant direction unless it is acted on by an unbalanced force or outside force.
Newton's first law of motion signifies that an object in motion is continued to be moving at a constant speed and in a constant direction.; only an outside force can change the speed and direction of the object. According to this law, if an object is at rest, it remains at rest, unless an outside force is applied on it.
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A certain AM radio wave has a frequency of
1.12 x 106
Hz. Given that radio waves travel at
2.99 x 108
m/s, what is the wavelength of this radio wave? (Round your answer to three significant figures.)
Answers
Answer: 267 m
Explanation:
2.99x10^8 m/s
———————-
1.12 x 10^6 Hz
3. What is a consideration when forcing interior walls?
A.
C.
D.
The wall coverings often hide interior metal framing.
The walls may be load-bearing and affect structural integrity.
Power tools must be used since all interior walls are reinforced.
Forcing the wall will require firefighters to work in a team of two.
Answers
Power tools must be used since all interior walls are reinforced is a consideration when forcing interior walls.
The correct option is C.
What does a load-bearing?The load of the floor or roof construction above them is supported by load-bearing walls, also referred to as "bearing walls." They are made to transfer weight from the roof to the foundation by passing through the flooring. A bearing wall, also known as a load-bearing barrier or a structural wall, supports the entire weight of the home. This wall assists in distributing the weight of the building from the roof to the base, and its loss could lead to the building collapsing.
How is a load-bearing determined?Tom proposes going up to the attic or basement to check which direction the joists run to see if a wall is load-bearing. The wall is still most likely not load-bearing if it runs parallel to the joists.
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The complete question is -
What is a consideration when forcing interior walls?
A-The wall coverings often hide interior metal framing.
B-The walls may be load-bearing and affect structural integrity.
C-Power tools must be used since all interior walls are reinforced.
D-Forcing the wall will require firefighters to work in a team of two.
A long plank XY lies on the ground. A load of 120 N is placed on it, at a distance of 0.50m from end X, as shown. End Y is lifted off the ground. The … upward force needed to do …
Answers
The value of W which is the weight of the plank acting at its midpoint is 100 N
Forces acting on the plank:
120 N ( load ) at 0.5 mW ( Weight of the plank ) at 2 m 65 N ( Upward force ) at 4 mSince the plank is at rest, the system is in equilibrium. Therefore, the net force if the system is zero.
( 120 * 0.5 ) + ( W * 2 ) - ( 65 * 4 ) = 0
60 + 2 W - 260 = 0
2 W = 200
W = 100 N
The net force of a system is the sum of all forces acting on the system. For an object in rest or at constant velocity, the net force is equal to zero.
Therefore, the value of W is 100 N
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define vector quantity giving examples
Answers
Answer:
Quantity with direction and magnitude
Displacement
Explanation:
What is the primary cause of earthquakes?
Answers
Answer:
Tectonic movement is the primary cause of earthquake.
The rigid beam is supported by the three suspender bars. bars ab and ef are made of aluminum and bar cd is made of steel. if each bar has a cross-sectional area of 450 mm2, determine the maximum value of p if the allowable stress is (σallow)st = 200 mpa for the steel and ( σallow)al = 150 mpa for the aluminum. est = 200 gpa and eal = 70 gpa.
Answers
Answer:
Pmax = 67.5 KN
Explanation:
We need to calculate the maximum allowable value of P for both aluminum and steel bars.
FOR STEEL BARS:
Since,
(σallow)st = (Pmax)st/A
where,
(σallow)st = maximum allowable stress of steel bar = 200 MPa = 2 x 10⁸ Pa
A = Cross-sectional area of steel bar = 450 mm² = 0.45 x 10⁻³ m²
(Pmax)st = Maximum allowable force for steel bar = ?
Therefore,
2 x 10⁸ Pa = (Pmax)st/0.45 x 10⁻³ m²
(Pmax)st = (2 x 10⁸ Pa)(0.45 x 10⁻³ m²)
(Pmax)st = 9 x 10⁴ N = 90 KN
FOR Aluminum BARS:
Since,
(σallow)al = (Pmax)al/A
where,
(σallow)al = maximum allowable stress of Al bar = 150 MPa = 1.5 x 10⁸ Pa
A = Cross-sectional area of Aluminum bar = 450 mm² = 0.45 x 10⁻³ m²
(Pmax)al = Maximum allowable force for Aluminum bar = ?
Therefore,
1.5 x 10⁸ Pa = (Pmax)al/0.45 x 10⁻³ m²
(Pmax)al = (1.5 x 10⁸ Pa)(0.45 x 10⁻³ m²)
(Pmax)al = 6.75 x 10⁴ N = 67.5 KN
Since,
(Pmax)al < (Pmax)st
Therefore,
The maximum allowable force will be:
Pmax = (Pmax)al
Pmax = 67.5 KN
PLEASE HELP!!!
Which is an element found on the periodic table?
A. Sodium
B. Carbon Dioxide
C. Dihydrogen Monoxide
D. Magnesium Sulfate
Answers
A. Sodium . . . Element #11 on the Periodic Table; when combined with other stuff as a chemical compound, it can make salt, Drano, and Alka-Seltzer
B. Carbon Dioxide . . . compound, made of elements Carbon and Oxygen ; produced when wood or gasoline burns; comes out of your lungs when you breathe out; air has a little bit of it, which is getting to be too much
C. Dihydrogen Monoxide . . . compound, made of elements Hydrogen and Oxygen, usually known by its popular name: "Water".
D. Magnesium Sulfate . . . compound, made of elements Magnesium and Sulfur; I don't know anything about this compound.
The chemical elements are shown in tabular form on the periodic table, also referred to as the periodic table of the elements.
Sodium exists an element found on the periodic table.
What is mean by periodic table?The chemical elements are shown in tabular form on the periodic table, also referred to as the periodic table of the elements. It is frequently used in physics, chemistry, and other sciences and is frequently regarded as a symbol of chemistry.
A system for arranging the chemical elements is the periodic table. The fundamental components of all matter are the chemical elements. The atomic number is a distinct characteristic of each chemical element. This figure is based on how many protons there are in each of the element's atoms.
Sodium is a chemical element with the atomic number 11 and weight 22,9898. A relative density of 0,97 at 20°C (68°F) indicates that it is a soft, reactive, and low melting point metal. The most significant alkaline metal from a business standpoint is sodium.
Therefore, the correct answer is option A. Sodium.
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Simulate a blackbody spectrum of temperature 900 Kelvin. Determine the peak wavelength in nanometers of an object of that temperature nanometers What is the emissive intensity of the object (the amount of power emitted per unit area )? ×10 W/m 2
Answers
A blackbody spectrum of temperature 900 Kelvin has been simulated. The peak wavelength in nanometers of an object of that temperature is determined to be nanometers. The intensity of the blackbody radiation at a given temperature and wavelength can be determined using Planck's law.
Planck's law, which describes the intensity of blackbody radiation, is given byI(λ) = 2hc²λ⁻⁵[exp(hc/λkT) - 1]⁻¹Where c = speed of light, h = Planck's constant, k = Boltzmann constant, T = temperatureλ = wavelength of lightI (λ) = spectral radiant intensity expressed in watts per square metre per unit wavelength.
Simulating the blackbody spectrum for a temperature of 900 K:
Using the equation for peak wavelength λ_max = 2897/T nm, where T = 900 KTherefore,λ_max = 2897/900λ_max = 3.22 µm or 3220 nm.
The emissive intensity of the object (the amount of power emitted per unit area) is given asI = σT⁴, where σ is the Stefan-Boltzmann constant.
Therefore,I = σT⁴ = 5.67 × 10⁻⁸ × (900)⁴W/m²= ×10 W/m².
Hence, the emissive intensity of the object is ×10 W/m².
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the movement of matter is
called
Answers
Answer:
From batteries to biology, how atoms move is critical for understanding how matter behaves. These new FPMD techniques streamline calculations to accelerate run time and boost efficiency, allowing researchers to simulate a million or more atoms
Explanation:
if we made a model in which the sun was a typically sized orange, then the earth would be about the size of a group of answer choices black bean grain of salt grape peanut m
Answers
The Sun is about the size of an orange, so the Earth would be about the size of a grape compared to it. This is because the Earth is much smaller than the Sun.
If the sun was a typically sized orange, the Earth would be about the size of a grape.The Sun is about the size of an orange, so the Earth would be about the size of a grape compared to it. This is because the Earth is much smaller than the Sun, with a diameter of around 7,917 miles, while the Sun has a diameter of around 864,000 miles. To put this into perspective, the Earth would be a tiny speck of dust compared to the size of the orange Sun. Thus, the Earth would be about the size of a grape if the Sun was a typically sized orange.
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Find as many sets of three perfect squares where the largest of the three perfect squares is the sum of the two smaller perfect squares. for example, one set is 9, 16, 25 because 9 + 16 = 25.
Answers
Here are a few sets of three perfect squares where the largest is the sum of the two smaller ones:
1. 3, 4, 5 (since 3^2 + 4^2 = 5^2)
2. 5, 12, 13 (since 5^2 + 12^2 = 13^2)
3. 7, 24, 25 (since 7^2 + 24^2 = 25^2)
4. 8, 15, 17 (since 8^2 + 15^2 = 17^2)
5. 9, 40, 41 (since 9^2 + 40^2 = 41^2)
6. 11, 60, 61 (since 11^2 + 60^2 = 61^2)
7. 12, 35, 37 (since 12^2 + 35^2 = 37^2)
8. 13, 84, 85 (since 13^2 + 84^2 = 85^2)
These are just a few examples, and there are infinitely many more sets of three perfect squares satisfying the given condition.
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An object originally moving at a speed of 20. meters per second accelerates uniformly for 5.0 seconds to a final speed 50. meters per second. What is the acceleration of the object, in m/s2 to the nearest tenth?
Answers
Read the following dream interpretation and answer the question that follows.
"I suspect that the patient's dream of being chased originates from his unresolved feelings of guilt during childhood."
What perspective of dream interpretation is being offered?
A. Freudian
B. activation-synthesis
C. Jungian
D. motivation
Answers
Answer:
Freudian
Explanation:
Answer:
Freudian
Explanation:
HURRY PLEASE
Two different bumper designs are shown here.
Recall that if the colliding objects have hard surfaces, the collision is elastic. Based on this description, which bumper design is more likely to result in an elastic collision? Predict how this bumper design will change the force that car 2 experiences during the collision.
Answers
The design that has the metal bar would increase the chances of an elastic collision and lead to an increase of the velocity of the car after collision.
What is elastic collision?We know that an elastic collision is one in which there is a conservation of the kinetic energy of the momentum. Recall that the colliding particles would have to constitute a closed system such that there is no loss in the momentum of the objects that are colliding.
We have two designs of the bumpers of the cars. We know that the balloon design would have more tendency to have this car stick to the other car and create an inelastic Collison.
However, with the metal bar design, there is less tendency that the cars would stick together after collision and we would have an elastic collision. The effect of this is that velocity of the car 2 may increase after the collision.
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Our Sun shines bright with a luminosity of 3.828x10^26 Watt. Her energy is responsible for many processes and the habitable temperatures on the Earth that make our life possible.
(a) Calculate the amount of energy arriving on the Earth in a single day
(b) To how many liters of heating oil ( energy density: 37.3x10^6 J/litre) is this equivalent?
(c) The Earth reflects 30% of this energy: Determine the temperature on Earth’s surface.
(d) What other factors should be considered to get an even more precise temperature estimate?
NOTE: The Earth’s radius is 6730km, the Sun’s radius is 696x10^3 km, 1AU is 1.495x10^8
Answers
Answer:
(a) 1317.44 W/m²
(b) 1.74×10¹⁵ litres of heating oil
(c) -20.63°C
(d) Energy storage in the Earth and the air
Explanation:
The parameters given are;
Luminosity of the Sun = 3.828 × 10²⁶ Watt
Distance of the Earth from the Sun, d = 152.06 × 10⁶ km
The radius of the Sun = 696 × 10³ km
The radius of the Earth, \(r_E\) = 6730 km
The surface area of the Sun = 12000 × Surface area of the Earth
The surface area of the Sun = 6.09 × 10¹² km²
Cross sectional area of the Earth = 1.27 × 10⁴ m² = 0.0127 km²
By the inverse square law, we have;
\(R = \dfrac{Luminosity \, of \, the \, Sun}{4 \pi d^2}\)
Where:
R = Solar radiation reaching the Earth
Therefore;
\(R = \dfrac{3.828 \times 10^{26}}{4 \times \pi \times (1.5206 \times 10^{11})^2} = 1317.44 \ W/m^2\)
Hence, the energy, E, reaching the Earth in a day is given as follows;
E = R × 4×π×\(r_E\)²×60×60×24 = 1317.44 × 4 × π × 6730000² × 60×60×24
E = 6.479×10²² Joules
(b) The number of litres of heating oil is therefore;
6.479×10²² J ÷ (37.3×10⁶ J/litre) = 1.74×10¹⁵ litres of heating oil
(c) 30% of the Energy is reflected, therefore;
0.7 × 6.479×10²² Joules = 4.54×10²² Joules reaches the Earths surface
From Stefan-Boltzmann law, we have;
\(T = \left (\dfrac{\left (1 - \alpha \right ) \times R }{4\times \sigma } \right )^{\dfrac{1}{4}}\)
Where:
α = 0.3
σ = Stefan-Boltzmann constant = 5.6704×10⁻⁸ W/(m²·K⁴)
Therefore;
\(T = \left (\dfrac{\left (1 - 0.3 \right ) \times 1317.44 }{4\times 5.6704 \times 10^{-8} } \right )^{\dfrac{1}{4}} = 252.52 \ K = -20.63 ^{\circ} C\)
(d) The heat storage in the Earth and the air
objects do not cease to exist when they are out of reach or view. this concept is referred to as
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Objects do not cease to exist when they are out of reach or view. this concept is referred to as: Object permanence.
Object permanence is the understanding that objects continue to exist even when they are no longer visible or in reach. It is an important developmental milestone in infants and young children, as they begin to understand that objects have a separate existence from themselves and that they can be retrieved or brought back into view.
The concept of object permanence has been studied in psychology and cognitive development, and is believed to be a fundamental building block for later cognitive processes such as memory, problem-solving, and language development.
The ability to form mental representations of objects that are not currently present is also important for social interactions, as it allows individuals to understand that others have their own thoughts, feelings, and perspectives.
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