Noble gas electron configuration for ion silver, Ag+ is Ag⁺ = [Kr] 4d¹⁰
Noble gas Electronic configuration for Ag is :
atomic number of silver, Ag is 47.
¹⁰⁸Ag₄₇ = 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d⁹ 5s²
there is exception : Half filled and full filled d orbital are more stable than the one electron is less. so one electron moves from s orbital to d orbital to make it more stable. so the correct electronic configuration is as follows :
¹⁰⁸Ag₄₇ = 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 5s¹
now for Ag⁺ , we loose one electron. so, the electronic configuration is :
Ag⁺ = 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰
noble gas configuration for Ag⁺ ion is as follows:
Ag⁺ = [Kr] 4d¹⁰
Thus, Noble gas Electronic configuration for Ag is : Ag⁺ = [Kr] 4d¹⁰ , Ag+ is Ag⁺ = [Kr] 4d¹⁰
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What is the element found in Group 17 Period 4?
Answer:
Bromine is found in Group 17, Period 4 on the periodic table.
Explain why the Earth has four different seasons
Answer:
Earths rotation
Explanation:
Answer:
because if there was not four diferent season we would not have a day or a night because we would not be moving
Explanation:
Which of the following compounds will be most soluble in nonane (C₉H₂O)?
a. 1-pentanol
b. benzene
c. ethanol
d. ethyl methyl ketone
e. acetic acid
The solubility of a compound in a particular solvent depends on several factors, including the polarity of the solvent and the solute. Nonane is a nonpolar solvent, which means that it cannot dissolve polar compounds effectively. In general, compounds with nonpolar properties are more soluble in nonane compared to polar compounds.
1-pentanol, ethanol and acetic acid are polar compounds because they contain a hydroxyl group (-OH) or carbonyl group (C=O) that makes them more soluble in polar solvents such as water. Benzene and ethyl methyl ketone are nonpolar compounds because they lack any polar functional groups and contain only carbon and hydrogen atoms.
Based on their polarities, we can predict that benzene and ethyl methyl ketone will be the most soluble in nonane because nonane is a nonpolar solvent. The polar compounds (1-pentanol, ethanol, and acetic acid) will not dissolve well in nonane due to their polarity. Acetic acid may have some solubility in nonane because it has a relatively small polar functional group and a large nonpolar hydrocarbon chain. In conclusion, the most soluble compound in nonane is likely to be benzene or ethyl methyl ketone, both of which are nonpolar. The polar compounds are not expected to be very soluble in nonane due to the nonpolar nature of the solvent.
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2. C) Br2 and Cl2 can react to form the compound BrCl. The boiling point of Br2 is 332 K, whereas the boiling point of BrCl is 278 K. Explain this difference in boiling point in terms of all the intermolecular forces present between molecules of each substance.
It can be explained by the presence of stronger intermolecular forces in BrCl, such as dipole-dipole interactions, compared to the weaker dispersion forces in \(Br_{2}\) .
The difference in boiling points between \(Br_{2}\) and BrCl can be explained by the intermolecular forces present between their molecules. \(Br_{2}\) consists of nonpolar molecules held together by weak London dispersion forces, which are the result of temporary fluctuations in electron density.
In contrast, BrCl molecules have a polar covalent bond, creating permanent dipole-dipole interactions in addition to London dispersion forces. The presence of stronger dipole-dipole interactions in BrCl leads to increased intermolecular forces, requiring more energy to overcome and hence resulting in a lower boiling point compared to \(Br_{2}\).
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three examples of resistors
Answer:
fixed resistors, variable resistors, resistance dependent on a physical quantity
You have 3.00 m3 of a fixed mass of a gas at 150 kPa. Calculate the pressure if the volume is reduced to 1.20 m3 at a constant temperature.
Answer:
Solution:
Explanation:
V1 = 3.00m3
T1 = 150kPa
V2 = 1.20m3
T2 = x
As ,
V1 = V2
T1 T2
3.00 = 1.20
150 X
3.00 x X = 150 x 1.20
3.00X = 180
X = 180
3.00
X = 60 kPa
The final pressure can be calculated using Boyle's law. The final pressure of the gas if the volume is increased from 3 m³ to 1.20 m³ with an initial pressure of 150 kPa is obtained as 375 kPa.
What is Boyle's law?Boyle's law states that at constant temperature, the volume of a gas is inversely proportional to the pressure of the gas. Hence, volume decreases with increase in pressure and vice versa.
If P₁ and V₁ be the initial pressure and volume respectively and P₂, V₂ be their final quantities, then the relation between them can be written as:
P₁ V₁ = P₂ V₂ .
It is given that the initial volume and pressure is 3 m³ and 150 kPa and the final volume is 1.20 m³ . Then, the final pressure is calculated as follows:
P₂ = P₁ V₁ / V₂
= (3 m³ × 150 kPa) / 1.20 m³
= 375 kPa
Hence, the final pressure of the gas will be 375 kPa.
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Given: 12 - x = 20 - 5x
To Prove: x = 2
Answer:
12 - x = 20 - 5x
Add 5x on both sides,
12 - x + 5x = 20 - 5x
12 + 4x = 20
Subtract 12 on both sides,
12 - 12 + 4x = 20 - 12
4x = 8
Divide 4 on both sides,
4x / 4 = 8 / 4
x = 2
Hence proved.
how many molecules are in the compound 3CO2
The number of molecule is represented by the stoichiometry. The chemical compound 3CO\(_2\) has three molecules.
What is carbon dioxide?Carbon dioxide is a colorless gas with a strong odor as well as a sour taste. It is among the most significant greenhouse gases associated with global warming.
Nonetheless, it is a tiny component of the Earth's atmosphere, created by the burning of carbon-containing materials, fermentation, and animal respiration, and used by plant inside the photosynthesis producing carbohydrates. The number of molecule is represented by the stoichiometry. The chemical compound 3CO\(_2\) has three molecules.
Therefore, the chemical compound 3CO\(_2\) has three molecules.
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helpppppppppppppp!!!!!!!!!!!!!how did chlorine atom attain saturation in potassium chloride and oxygen dichloride
In the Haber Process, ammonia is synthesized from nitrogen andhydrogen:
N2 (g) + 3H2 -----> 2NH3(g)
ΔG at 298K for this reaction is -33.3 kj/mol. the valuef ΔG at 298 K for a reaction mixture that consists of 1.9 atmN2, 1.6 atm H2 and 0.65 atm NH3 is________.
a.) -3.86 x 103
b.) -1.8
c.) -7.25 x 103
d.) -40.5
e.) -104.5
The value of ΔG at 298 K for a reaction mixture containing 1.9 atm N2, 1.6 atm H2, and 0.65 atm, the answer is (a) -3.86 × 10^3.
NH3 can be calculated using the equation:
ΔG = ΔG° + RT ln(Q)
where ΔG is the standard Gibbs free energy change, ΔG° is the standard Gibbs free energy change at standard conditions, R is the gas constant, T is the temperature in Kelvin, and Q is the reaction quotient.
In this case, we are given ΔG° as -33.3 kJ/mol. To calculate Q, we need to use the partial pressures of the gases in the reaction mixture. The reaction stoichiometry tells us that the ratio of the partial pressures of N2, H2, and NH3 is 1:3:2. Therefore, we can write:
Q = (P(NH3))^2 / (P(N2) * P(H2)^3)
Plugging in the given values of P(N2) = 1.9 atm, P(H2) = 1.6 atm, and P(NH3) = 0.65 atm, we can calculate Q. Then, using the value of R = 8.314 J/(mol·K) and the temperature T = 298 K, we can substitute these values into the equation and solve for ΔG.
The calculated value of ΔG at 298 K for the given reaction mixture is approximately -3.86 × 10^3 J/mol. This value is equivalent to -3.86 kJ/mol. Therefore, the answer is (a) -3.86 × 10^3.
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A plastic soda bottle is flexible enough that the pressure of the bottle can change even
without opening it. You have an empty soda bottle at room temperature (25.0 °C) and
standard pressure (100 kPa). What will the new temperature be if you put it in your
freezer and the bottle decreases its pressure to 702 mm Hg? Do not include units in your
answer.
To solve this problem, we can use the combined gas law, which relates the pressure, volume, and temperature of a gas:
P1V1/T1 = P2V2/T2
where P1, V1, and T1 are the initial pressure, volume, and temperature, and P2, V2, and T2 are the final pressure, volume, and temperature.
Since the bottle is sealed and the volume is constant, we can simplify the equation to:
P1/T1 = P2/T2
Rearranging and plugging in the given values, we get:
T2 = (P2 × T1) / P1
= (702 mmHg × 298 K) / 100 kPa
≈ 209.8 K
Converting to Celsius, we get:
T2 ≈ -63.3 °C
Therefore, if the bottle decreases its pressure to 702 mm Hg in the freezer, the new temperature will be approximately -63.3 °C.
products for combustion
Answer:
Carbon Dioxide
Carbon Monoxide
Sulfur Dioxide
Nitrogen Oxides
Lead
Particulate Matter
Explanation:
during translation, what molecule bears the anticodon?
Answer:
tRNA
Anticodons are found on molecules of tRNA. Note:Each three-letter sequence of mRNA nucleotides (codons) corresponds to a specific amino acid, or to a stop codon.
15. 25. 0 g of mercury is heated from 25°C to 155°C, and absorbs 455 joules of heat in the
process. Calculate the specific heat capacity of mercury.
When 15.25 g of mercury is heated from 25°C to 155°C, and it absorbs 455 joules of heat in the process. The specific heat capacity of mercury is approximately 0.266 J/g°C.
The specific heat capacity (C) of a substance is defined as the amount of heat required to raise the temperature of one gram of the substance by one degree Celsius. The formula to calculate heat (Q) is given by: Q = m * C * ΔT
Where Q is the heat absorbed, m is the mass of the substance, C is the specific heat capacity, and ΔT is the change in temperature. In this case, we have the following values: m = 15.25 g, Q = 455 J, ΔT = 155°C - 25°C = 130°C
Plugging these values into the formula, we can solve for C: 455 J = 15.25 g * C * 130°C C = 455 J / (15.25 g * 130°C) C ≈ 0.266 J/g°C Therefore, the specific heat capacity of mercury is approximately 0.266 J/g°C.
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A cross results in three phenotypes. A nual typothesis of recessive epistasis is tested. Your calculated chi-square value is 6.4. Assuming a p Value of 0.05, do you reject the null frypothesis? yes. No
The null hypothesis is rejected when the chi-square value is higher than the critical value or p-value. In this case, the chi-square value of 6.4 is higher than the critical value for a p-value of 0.05, which is 3.84. Therefore, the null hypothesis is rejected.
A cross results in three phenotypes. A null hypothesis of recessive epistasis is tested. Your calculated chi-square value is 6.4. Assuming a p-value of 0.05, do you reject the null hypothesis?The answer is yes.What is a chi-square value?A chi-square value is a measure of how different two sets of data are. It compares the observed data to the expected data and generates a statistic that shows how far apart they are. It compares the observed data to the expected data and generates a statistic that shows how far apart they are. The chi-square test is a statistical hypothesis test that is used to determine if there is a significant difference between two groups of data. The null hypothesis is rejected when the chi-square value is higher than the critical value or p-value. In this case, the chi-square value of 6.4 is higher than the critical value for a p-value of 0.05, which is 3.84. Therefore, the null hypothesis is rejected.
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draw the molecule by placing atoms on the grid and connecting them with bonds. use square brackets to denote the overall charge. include all lone pairs of electrons. clo3- clo4- no3- so3
ClO3-: The chlorine atom carries a single negative charge.
ClO4-: The chlorine atom carries a single negative charge.
NO3-:The nitrogen atom does not carry any charge, and the molecule as a whole carries a single negative charge.
Certainly! Here are the drawings of the molecules you requested:
1. ClO3-
O
|
Cl - O
|
O [-
2. ClO4-
O
|
Cl - O
|
O
|
O [-
3. NO3-
O
||
N - O
|
O [-
4. SO3
O
||
S - O
||
O
Please note that for SO3, it does not carry any charge (neutral molecule), as requested.
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Combined Gas Law
If a gas triples its volume and doubles its Kelvin temperature, what would happen to the pressure of the gas?
The pressure of the gas would now be 2/3 of its initial value.
What is the new pressure of the gas?We know that we can be able to use the ideal gas equation to be able to obtain the parameters that concern gases. In this case, we are dealing with the volume, temperature and volume all at once hence we need to use the general gas equation.
Initial pressure of the gas P1 = P
Final pressure of the gas P2 = ??
Initial volume of the gas V1 = V
Final volume of the gas V2 = 3V
Initial temperature of the gas T1 = T
Final temperature of the gas = 2T
P1V1/T1 = P2V2/T2
P1V1T2 = P2V2T1
P2 = P1V1T2/V2T1
P2 = P * V * 2T/3V * T
P2 = 2/3P
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Which of the following are functions of the stomach?
Answer:
1-Temporarily store food.
2-Contract and relax to mix and break down food.
3-Produce enzymes and other specialized cells to digest food
A 3.00 L sample of paint that has a density of 4.65 g/mL is found to contain 33.1 g lead (II) nitride. Determine (A) how many grams of lead ion are in the paint sample? (B) How many ions of lead are in the paint? (C) what is mass percentage of lead in the paint/ What is the ppm?
1) Grams of lead.
Convert grams of lead (II) nitride to moles of lead (II) nitride
\(molofPb_3N_2=33.1gPb_3N_2\cdot\frac{1molPb_3N_2}{649.61gPb_3N_2}=0.0509lofPb_3N_2\)Convert moles of lead (II) nitride into moles of Pb
\(\text{molesofPb}=0.0509molPb_3N_2\cdot\frac{3\text{molPb}}{1molPb_3N_2}=0.1527\text{molPb}\)Convert moles of Pb into grams of Pb
\(\text{gofPb}=0.1527\text{molPb}\cdot\frac{207.2\text{ g Pb}}{1\text{molPb}}=31.64\text{ g Pb}\)There is 31.64 g of ions of lead in the sample of paint.
a piece of magnesium with a mass of 5.867 g was heated in a crucible which was open to the air. after the magnesium had combusted and allowed to cool down the product was found to have a mass of 8.956 g. i. determine the empirical formula of the magnesium oxide formed. ii. the actual empirical formula of magnesium oxide is mgo. suggest three possible reasons why the value obtained in the experiment described above did not produce the correct formula.
The empirical formula for magnesium oxide is Mg₅O₄.
The empirical formula is defined as the simplest whole-number ratio of atoms in a compound.
The ratio of atoms is the same as the ratio of moles. So calculate the molar ratio of Mg to O.
Mass of magnesium oxide = mass of Mg + mass of O
8.956 g = 5.867 g + mass of Oxygen
Mass of Oxygen = (8.956– 5.867) g = 3.08 g
Moles of Mg=(5.867g Mg×1 mol Mg) / 24.3g Mg=0.24 mol Mg
Moles of Oxygen =(3.08g O×1 mol O) / 16.00g O = 0.192 mol O
Element mass moles ratio integers
Magnesium 5.867 0.24 1.25 × 4 5
Oxygen 3.08 0.192 1 × 4 4
The empirical formula of magnesium oxide is Mg₅O₄.
b)
Students sometimes get different results from these tests. These might lead to change in emperical formula:-
1.) Magnesium oxide product can escape as they lift the lid
2). Not all magnesium is likely to react (the product may look grayer than white)
3.) they are more likely to run the product with their splint so it's not all rated (more common than you might expect)
4.) misalignment when measuring size
5.) that magnesium is tightly bound so that it does not turn over.
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A 0.995 g unknown mixture containing calcium chloride reacts to give 0.505 of calcium phosphate precipitate. What is the percentage of calcium chloride in the unknown mixture?
The percentage of the calcium present is 50.8 %.
What is the percentage of calcium?We know that a reaction has to do with the combination of two or more substances so as to give a product. The substances that are combined are called the reactants while the substance that is obtained is called the product.
We are told in the question that 0.995 g unknown mixture containing calcium chloride reacts to give 0.505 of calcium phosphate precipitate. Now the amount of calcium that is present shows in the mass of the calcium phosphate precipitate obtained.
Percentage of the calcium = 0.505 g/0.995 g * 100/1
= 50.8 %
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Cassiterite is an ore of a metal tin. What is an ore?
Answer:
Cassiterite is an ore of Sn.It is also called tinstone and has molecular formula of SnO
2 . It is heavy, metallic, hard tin dioxide that is the major ore of tin. It is colourless when pure, but brown or black when iron impurities are present.
4. acetyl salicylic acid (the active ingredient in aspirin) has a formula of c9h8o4. how many moles of base will be needed to neutralize are there in 0.25g? (assume an equal mole ratio of h to oh- )
To determine the number of moles of base needed to neutralize 0.25g of acetyl salicylic acid, we first need to calculate the number of moles of acetyl salicylic acid in 0.25g.
The formula mass of acetyl salicylic acid (C9H8O4) can be calculated as: C = 9 x 12.01 = 108.09 H = 8 x 1.01 = 8.08 O = 4 x 16.00 = 64.00 Formula mass = 108.09 + 8.08 + 64.00 = 180.17 g/mol To find the number of moles in 0.25g, we can use the formula:moles = mass / molar mass moles = 0.25g / 180.17 g/mol = 0.00139 mol
Since the mole ratio of H to OH- is equal, we need an equal number of moles of base to neutralize the acid. Therefore, we need 0.00139 moles of base to neutralize 0.25g of acetyl salicylic acid.
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Can someone help with these
What does the slang term "the Boards" refer to?
Answer:
It can mean "boardwalk" or a "board of a school."
~Mia Sedillo~
The surface currents of Earth’s oceans are most likely created by which of the following?
Answer:
global wind patterns. the rotation of the Earth. the shape of the ocean basins.
Explanation:
In a one or two paragraph summary explain why Sodium light is Orange and Potassium light is lilac when placed in a flame.
Use the words: electron, quantum jump, ground state, orbitals, photons, emitting, absorbing, light spectrum, energy mass (words are not in order)
Answer:
?
Explanation:
In which of the following processes do the molecules become more orderly? Olemonade mix dissolving in water water freezing O ice melting O dry ice subliming O rubbing alcohol evaporating
The following processes in which the molecules become more orderly is:
b) water freezing.
In water freezing, the molecules transition from a liquid state to a solid state as the temperature decreases. As the temperature drops below the freezing point, the water molecules arrange themselves in a more ordered and structured manner, forming a solid crystal lattice. The molecules align themselves in a specific pattern, with fixed positions and regular spacing between them.
In contrast, the other options involve processes where the molecules become less orderly:
a) Lemonade mix dissolving in water: When the lemonade mix dissolves in water, the molecules of the mix disperse throughout the water, creating a homogeneous solution. The molecules become more randomly distributed, rather than ordered.
c) Ice melting: Ice melting occurs when the temperature increases, causing the solid ice to transition into liquid water. The molecules gain enough energy to break free from their fixed positions in the crystal lattice, resulting in a more disordered arrangement.
d) Dry ice subliming: Dry ice, which is solid carbon dioxide, sublimes when it is exposed to warmer temperatures. Instead of melting into a liquid, dry ice directly converts from a solid to a gas. The molecules rapidly escape the solid state and disperse as a gas, leading to a more chaotic arrangement.
e) Rubbing alcohol evaporating: Evaporation of rubbing alcohol involves the liquid molecules gaining enough energy to transition into a gas phase. As the molecules gain energy, they escape the liquid surface and disperse as a gas. The process of evaporation does not involve an increase in orderliness.
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The K a of propanoic acid ( C 2 H 5 COOH ) is 1. 34 × 10 − 5. Calculate the pH of the solution and the concentrations of C 2 H 5 COOH and C 2 H 5 COO − in a 0. 597 M propanoic acid solution at equilibrium
The pH of the solution is 2.55 and the concentrations of C₂H₅COOH and C₂H₅COO⁻ are 0.594 M and 0.00282 M respectively.
The following chemical equation describes how propanoic acid, a weak acid, will ionise in water.
C₂H₅COOH(aq) + H₂O(l) ↔ C₂H₅COO⁻(aq) + H₃O⁺(aq)
The concentration of the initial solution of propanoic acid is 0.597 M.
The Ka of propanoic acid is 1.34 × 10⁻⁵.
Let the concentration of each of the products is x.
Now, We have Ka = [C₂H₅COO⁻] [H₃O⁺] / [C₂H₅COOH] [H₂O]
or, 1.34 × 10⁻⁵ = x × x / 0.597
or, x² = 0.8 × 10⁻⁵
or, x = 2.82 × 10⁻³ M
or, x = 0.00282 M
So, concentration of C₂H₅COO⁻ = x = 0.00282 M
Concentration of C₂H₅COOH = 0.597 - 0.00282 = 0.594 M
Now, pH of solution = -log[H₃O⁺] = -log[x] = -log(0.00282) = 2.55
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A sound wave moves from a solid material into a liquid. What would happen to the frequency of the sound?