Norman purchased 3.5 lb. Of his favorite mixture of dried fruits to use in a trail mix. The total cost was $16.87. How much does the fruit cost per pound?

Answer: 250

Step-by-step explanation:

Use equation to solve

C= 2πr

C=2π(40)

C=80π

C=80*3.14

Answer:

Step-by-step explanation:

DO IT YOUR SELF

Answer:

the circumference is 31.4

Step-by-step explanation:

The computation of the circumference is shown below:

As we know that

Circumference is

= 2πr

= 2π (10 ÷ 2)

= 2× 3.14 × 5

= 31.4

Hence, the circumference is 31.4

According to the equation for the maximum speed, it is found that the height at the top of the swing of the rider is of 0.8 m.

As stated in the problem, it is given by:

v = 2gh.

In which:

In this problem, the parameters are g = 9.8, v = 15. Hence we can solve for h to find the height.

v = 2gh

2 x 9.8h = 15

19.6h = 15

h = 15/19.6

h = 0.8.

The height at the top of the swing of the rider is of 0.8 m.

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Given :

David rented a truck for one day there was a base fee of $17.99 .

Charge per mile driven is, c = 98 cents = $0.98 .

He pay $137.55 at the end of the day.

To Find :

How many miles did he drive the truck.

Solution :

Let, number of miles he drive is n.

So,

\(n = \dfrac{137.55 - 17.99}{0.98}\\\\n = 122\ miles\)

Therefore, number of miles he drive the truck is 122 miles.

Answer:

X = - 84

Step-by-step explanation:

The correct option is c, the fraction with repeating decimals is 3/11.

A fraction in lowest terms with a prime denominator other than 2 or always produces a repeating decimal.

Here the options are:

a) 3/25

b) 3/16

c) 3/11

d) 3/8

If you know the prime numbers, you can see that there is only one option with a prime number in the denominator.

That option is the third one, where the denominator is 11, that fraction will have repeated decimals

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An exponential regression equation for this set of data is \(y = 18400(0.872)^x\).

The value of the car, to the nearest cent, after 11 years is $4078.49.

Based on the table representing the value of a car over time that was purchased for 18400 dollars, we would calculate the value of a and b in order to write the exponential equation as follows;

\(f(x) = a(b)^x\)

18,400 = a(b)⁰

a = 18,400

Next, we would determine value of b as follows;

16,049 = 18,400(b)¹

16,049 = 18,400b

b = 16,049/18,400

b = 0.8722 ≈ 0.872

Therefore, the required exponential equation is given by;

\(y = 18400(0.872)^x\)

When x = 11 years, the value of the car, to the nearest cent can be calculated as follows;

\(y = 18400(0.872)^{11}\)

y = $4078.49

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Therefore, Linda bought 21 yards of ribbon. Hence, Linda bought 94 yards of ribbon.

The number of yards of ribbon Linda bought, we need to calculate the difference between the initial balance on the card and the remaining balance after the purchase.

The initial balance on the card was $20. To find the amount spent on ribbon, we subtract the remaining balance ($17.06) from the initial balance. $20 - $17.06 = $2.94

Now, we need to determine how many yards of ribbon Linda could purchase with $2.94, given that the price of the ribbon is 14 cents per yard.

To find the number of yards, we divide the total amount spent ($2.94) by the price per yard (14 cents): $2.94 ÷ $0.14 = 21

Therefore, Linda bought 21 yards of ribbon.

Hence, Linda bought 94 yards of ribbon.

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Answer:

you type 75 words per minute.

Step-by-step explanation:

since there are 60 minutes in an hour, simply divide 4,500 by 60 to get 75. i hope this helps you! good luck and have a great day. :)

See attachment for math work and answer.

Velocity of jet in still air is 647 miles per hour and velocity of wind is 70 miles per hour.

Given,

Jet's velocity against wind 1731 / 3 = 577  mile per hour

flying with wind it   2151 / 3 = 717 miles per hour.

Let the velocity of jet in still air be x miles per hour and velocity of wind be y miles per hour.

As such its velocity against wind is x−y and with wind is x+y and therefore

x−y=577;

x+y=717

Adding the two

2x = 1294

x = 647

y= 717 − 647

y = 70

Hence velocity of jet in still air is 647 miles per hour and velocity of wind is 70 miles per hour.

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Answer:

Step-by-step explanation:

50 people in the class

20/50, 25/50, 5/50: 40%, 50%, 10%

0.40 is blonde and 0.60 probability

Answer:

B

Step-by-step explanation:

The easiest way to find the answer is to convert all of the fractions to have the same denominator,...

A = (22/55 / 11 = 2/5 and 2/5 * 20)            = 40/100

B = (17/20 * 5)                                             = 85/100

C = (4/5 * 20)                                              = 80/100

D = (3/4 * 25)                                              = 75/100

B (Lily) is the highest followed by C (Nikki), D (Sydney), and A (Monica)

Hope it helps,... Chow,...!

Answer:

9h

Step-by-step explanation:

Given data

Sofia earns $9 per hour mowing lawns

Let the total amount earned be t

and let the time worked be h

Hence

t= 9*h

t= 9h

The expression is 9h

Answer: B

Step-by-step explanation: B is larger by about 9.42 in

Answer:

35742

Step-by-step explanation:

Answer:

(f - g)(x)

Step-by-step explanation:

6x3 + x2 + 9x - 3

The possible values of k are k = 2 and k = -2. These are the values of the constant k for which f(x) is continuous at x = 2.

A relation between a collection of inputs and outputs is known as a function. A function is, to put it simply, a relationship between inputs in which each input is connected to precisely one output.

To determine the values of the constant k for which f(x) is continuous at x = 2, we need to ensure that the left-hand limit, the right-hand limit, and the value of f(x) at x = 2 are all equal.

First, let's find the left-hand limit as x approaches 2. We evaluate the function for x < 2:

f(x) = x² + 5kx    (for x < 2)

Taking the limit as x approaches 2 from the left side (x < 2), we have:

lim(x→2-) f(x) = lim(x→2-) (x² + 5kx) = 2² + 5k(2) = 4 + 10k

Next, let's find the right-hand limit as x approaches 2. We evaluate the function for x > 2:

f(x) = k²x + 4x + 4    (for x > 2)

Taking the limit as x approaches 2 from the right side (x > 2), we have:

lim(x→2+) f(x) = lim(x→2+) (k²x + 4x + 4) = k²(2) + 4(2) + 4 = 2k² + 8 + 4 = 2k² + 12

Now, let's evaluate the value of f(x) at x = 2:

f(x) = 3k² - 4    (for x = 2)

f(2) = 3k² - 4

For f(x) to be continuous at x = 2, the left-hand limit, the right-hand limit, and the value of f(x) at x = 2 should all be equal. Therefore, we set up the following equation:

4 + 10k = 2k² + 12 = 3k² - 4

Simplifying, we have:

2k² + 8 = 3k² - 4

Rearranging the terms, we get:

k² - 12 = 0

Factoring, we have:

(k - 2)(k + 2) = 0

So, the possible values of k are k = 2 and k = -2. These are the values of the constant k for which f(x) is continuous at x = 2.

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A)

If the order of choice is taken into consideration, we consider four possibilities for the first choice and three for the second. Then the total number of ways is given by:

B)

If the order of choices is not taken into consideration, we must divide the the previous result by 2, which is the total number of ways by which we can organize two letters (ex: AB and BA):

a. The decay of 232Th to 236U through emission of a 1z = 90 2s particle is not possible.

b. The decay of 238Pu to 236U through emission of a 1z = 94 2s particle is possible.

c. The decay of 11B to 11B through emission of a 1z = 52 1s particle is not possible.

d. The decay of 33P to 32S through emission of a 1z = 152 1s particle is not possible.

e. No information is provided for decay e.

a. The decay of 232Th to 236U through emission of a 1z = 90 2s particle is not possible. This is because the atomic number of the daughter nucleus (236U) would be 92 (the same as uranium), and the mass number would be 238. Therefore, this decay violates the law of conservation of element.

b. The decay of 238Pu to 236U through emission of a 1z = 94 2s particle is possible. This is because the atomic number of the daughter nucleus (236U) would be 92 (uranium), and the mass number would be 234. Therefore, this decay is possible.

c. The decay of 11B to 11B through emission of a 1z = 52 1s particle is not possible. This is because the atomic number of the daughter nucleus (11B) would be the same as that of the parent nucleus, and the mass number would also remain the same. Therefore, this decay violates the law of conservation of mass and charge.

d. The decay of 33P to 32S through emission of a 1z = 152 1s particle is not possible. This is because the atomic number of the daughter nucleus (32S) would be less than that of the parent nucleus (33P). Therefore, this decay violates the law of conservation of charge.

e. No information is provided for decay e.

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The probability that the sample standard deviations exceeds 3.5 hours more than 0.95 is 0.23 < 0.95 ..

The numbers of hours spent on watching television by a student in a weak before is normally distributed.

We have provide the following details, standard

deviations of sample ( Number of hours in weak) (σ) = 4.5 hours

sample size (n) = 30

we shall compute the mean and variance of sample .

The E of s squared is equal to 4.5 squared. The variance of S squared is equal to twice the square of sigma divided by 1, which is 30 minus 1, which is 28.6, 28.2817. The chi-square distribution here has 29 degrees of freedom, which equals 29 squared to 4.5 squared. We want to find probabilities greater than 90 because the standard deviation of our sample is greater than 3.5 hours. The probability that S squared is greater than 3.5 is The probability that chi-square with 29 degrees of freedom is greater than

17. 54321 is very high. This is the same as zero.

This is equal to 1 minus the probability that 29 degrees of freedom chi-square is greater than 51 points 5556, which is what we want for part B. we are given one Probability will be zero.

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#Complete question

The number of hours spent watching television by students in the week before final exams has a normal distribution with a standard deviation of 4.5 hours. A random sample of 30 students was taken.a. Is the probability more than 0.95 that the sample standard deviation exceeds 3.5 hours?b. Is the probability more than 0.95 that the sample standard deviation is less than 6 hours?

\((i)\\\\2A = \begin{pmatrix}3x \times 2 & 1 \times 2 & 5 \times 2\\0\times 2 & 2x \times 2 & -3 \times 2\end{pmatrix} = \begin{pmatrix}6x & 2 & 10\\0 & 4x & -6\end{pmatrix}\\\\\\(ii)\\\\2A + B = C\\\\\implies \begin{pmatrix}6x & 2 & 10\\0 & 4x & -6\end{pmatrix} + \begin{pmatrix}y & 0 & -4\\1 & -3y & 2\end{pmatrix} = \begin{pmatrix}31& 2 & 6\\1 & 17& -4\end{pmatrix}\)

\(\implies \begin{pmatrix}6x+y & 2+0 & 10-4\\0+1 & 4x-3y & -6+2\end{pmatrix} = \begin{pmatrix}31 & 2 & 6\\1 & 17& -4 \end{pmatrix}\\\\\\\implies \begin{pmatrix}6x+y & 2 & 6\\1 & 4x-3y & -4\end{pmatrix} = \begin{pmatrix}31 & 2 & 6\\1 & 17& -4 \end{pmatrix}\\\\\text{System of equations},\\\\6x +y =31,~~ 4x -3y = 17\\\\\\(iii)\\\\6x +y-31 =0 \\\\4x-3y -17=0\\\\\text{Solving by cross multiplication method}\\\\\\\dfrac x{1(-17) - (-31)(-3)} = \dfrac y{4(-31) - 6(-17)} = \dfrac 1{6(-3) - 4(1)}\)

\(\implies \dfrac{x}{-17 -93} = \dfrac{y}{-124 +102} = \dfrac 1{-18-4}\\\\\\\implies -\dfrac{x}{110} = -\dfrac{y}{22} = -\dfrac 1{22}\\\\ \implies \dfrac{x}{110} = \dfrac{y}{22} = \dfrac 1{22}\\\ \\\text{Hence,}\\\\\\x=\dfrac{110}{22}=5,~~~~ y= \dfrac{22}{22} =1\)

Answer:

  (i)

  \(2A=\left[\begin{array}{ccc}6x&2&10\\0&4x&-6\end{array}\right]\)

  (ii) 6x+y=31; 4x-3y=17

  (iii) (x, y) = (5, 1)

Step-by-step explanation:

The matrix 2A is written by multiplying each element of A by 2.

  \(2A=\left[\begin{array}{ccc}6x&2&10\\0&4x&-6\end{array}\right]\)

__

Variables are seen in elements (1, 1) and (2, 2) of the matrices A and B, so the simultaneous equations can be chosen from those elements of the equation 2A+B=C.

__

A graphing calculator shows the solution to be (x, y) = (5, 1).

Answer:

6.25 m/s

Step-by-step explanation:

There is an equation for this

SPEED (M/S) = DISTANCE (M) / TIME (S)

so if we put 375 as the distance and put 60 for time , you see that it is coming together

375m/60s = 6.25 m/s

(m/s stands for metres per second)

Answer:

The volume of the cylinder section is about 82.8, and the volume of the cone is about 28.2.

Step-by-step explanation:

To find the cone's volume, it is v=pir^2*h/3

To find the cylinder, it is v=pir^2*h

I'm sure you can do the rest.

The decision to use a univariable or multivariable regression model depends on the research question, data availability, model complexity, and goodness of fit.

What is the linear regression equation?

The formula for simple linear regression is Y = mX + b, where Y is the response (dependent) variable, X is the predictor (independent) variable, m is the estimated slope, and b is the estimated intercept.

When deciding whether to use a univariable or multivariable linear regression model, there are several factors to consider:

Research question: Consider the research question you are trying to answer. If you are interested in understanding the relationship between a single independent variable and a dependent variable, then a univariable regression model may be sufficient. However, if you want to explore the effect of multiple independent variables on a dependent variable, then a multivariable regression model may be more appropriate.

Data availability: Look at the data you have available. If you have only one independent variable that you believe is relevant to your research question, then a univariable regression model may be appropriate. However, if you have multiple independent variables that could potentially influence the dependent variable, then a multivariable regression model may be necessary.

Model complexity: Consider the complexity of the model you want to build. If you are interested in a simple linear relationship between an independent variable and a dependent variable, then a univariable regression model may be sufficient. However, if you believe that there are interactions between multiple independent variables that could affect the dependent variable, then a multivariable regression model may be necessary.

Model fit: Evaluate the goodness of fit of both univariable and multivariable models. Compare the R-squared values of each model to determine which model provides a better fit to the data. A higher R-squared value indicates a better fit between the independent and dependent variables.

Hence, the decision to use a univariable or multivariable regression model depends on the research question, data availability, model complexity, and goodness of fit.

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Answer:

Step-by-step explanation:

Ok what’s the problem

xy + xz is an even integer & x is even and y + xz is an odd integer &  either (x-1) is even or (y-z) is even .

1. xy + xz is an even integer - SUFFICIENT

Given:

xy + z is odd ...(i)

xy + xz is even ...(ii)

subtracting (ii) from (i)

we get xz - z, which should be odd (* since odd - even = odd)

=> z(x-1) is odd

=> both z and (x-1) is odd

=> since (x-1) is odd, x must be even.

2. y + xz is an odd integer -INSUFFICIENT

Given:

xy + z is odd ...(i)

y + xz is odd ...(ii)

subtracting (ii) from (i)

we get xy + z - y - xz

= (x-1)(y-z) , which should be even

=> either (x-1) is even or (y-z) is even ....insufficient to determine

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you know at least one of them is heads is 1/3 or approximately 0.33.

There are four possible outcomes when flipping two coins: HH (both heads), HT (one head and one tail), TH (one head and one tail), and TT (both tails).

If you know that at least one of them is heads, then the only remaining possibilities are HH, HT, and TH.

Since there are three equally likely outcomes and only one of them is HH, the probability that they are both heads given that you know at least one of them is heads is 1/3 or approximately 0.33.

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