Answer:
Part A: 115
Part B: 36000
Explanation:
Part A asks for the perimeter, which is adding, so add up the 15, 40, and 60, which will equal to 115.
Part B asks for the area, which is multiplying, so you multiply the numbers,
15 x 40 x 60 = 36000
15 x 40 = 600
600 x 60 = 36000
You could try multiplying it a different way but get the same answer:
60 x 40 x 15 = 36000
60 x 40 = 2400
2400 x 15 = 36000
I'm not sure if this is correct but I hope I helped
have a great day/night :))
7x + 3 = 11 show work plz
Answer:
x = 8/7
Step-by-step explanation:
7x + 3 = 11
-3 -3
7x = 8
7 7
x = 8/7
Write the equation of the line that passes through (1, 3) and has a slope of 2 in point-slope form
Answer:
y-3= 2(x-1)
Step-by-step explanation:
1. The equation of a line in point slope form is y-y1= m(x-x1)
2. m=slope and (x1,y1) is the point the line passes through
3. The point the line passes through is (1,3)
4, The slope is 2
5. Therefore the answer is y-3=2(x-1)
Answer:
y-3=2(x-1)
Step-by-step explanation:
Point slope form is y-y1=m(x-x1)
Now we just need to plug in what you have into this equation.
y-3=2(x-1) and this is the point slope form for this line.
Write the expression
as a
single natural logarithm.
3 In 5
What number when multiplied by 113 has a product of 1
Answer:
3/4
Step-by-step explanation:
Answer:
1/13
Step-by-step explanation:
copied of that person
find f(n) when n = 3k, where f satisfies the recurrence relation f(n) = 2f(n∕3) 4 with f(1) = 1.
Main Answer: The value of f(n) = 16(f(k))^4 when n = 3k.
Supporting Question and Answer:
How can we determine the value of f(n) when n = 3k using the given recurrence relation and initial condition?
By analyzing the given recurrence relation f(n) = 2f(n/3)^4 and the initial condition f(1) = 1, we can recursively calculate the value of f(n) for n = 3k. Using the recurrence relation, we can express f(n) in terms of f(n/3) and apply it iteratively. The value of f(n) when n = 3k is given by f(n) = 16(f(k))^4, where f(1) = 1 is used as the base case.
Body of the Solution:To find the value of f(n) when n = 3k, where f satisfies the recurrence relation f(n) = (2f(n/3))^4 with f(1) = 1, we can use the recurrence relation to recursively calculate the values of f(n).
Given that f(1) = 1, we can calculate the values of f(n) for n = 3, 9, 27, and so on.
f(3) = (2f(3/3))^4
= ((2f(1)))^4
= 2^4(1)^4
= 16
f(9) = (2f(3))^4
= (2(16))^4
= 1048576
f(27) =(2f(9))^4
= (2(1048576))^4
=(2097152)^4
Therefore, f(n) when n = 3k is given by:
f(3K) =16(f(k))^4
So, f(n) =16(f(k))^4 when n = 3k, where f satisfies the given recurrence relation and f(1) = 1.
Final Answer:Therefore, f(n) =16(f(k))^4 when n = 3k.
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Find the value of sin K rounded to the nearest hundredth, if necessary.
Answer: sin K =
24
L
18
M
Submit Answer sin k=
Answer:
Step-by-step explanation:
IS =K
Given that line t and line g are parallel and that m<2=105 and m<15=95 select the angle measure for each angle named.
Answer:
<1 = <9 = <4 = <12 = 75
<2 = <3 = <10 = <11 = 105
<5 = <8 = <13 = <16 = 85
<6 = <7 = <14 = <15 = 95
A wheel is spun using a troque of 48Nm. What is the angular acceleration of the wheen if it has a moment of inertia of 62 kg. M2
The answer to the given question is the angular acceleration of the wheel is 0.7742 rad/s².
We can use the formula for rotational dynamics:
τ = Iα
where τ is the torque applied, I is the moment of inertia, and α is the angular acceleration.
Rearranging this equation, we get:
α = τ / I
Plugging in the given values, we have:
α = 48 Nm / 62 kg⋅m²
Simplifying, we get:
α = 0.7742 rad/s²
Rotational dynamics deals with the motion of objects that are rotating around an axis. The key concept in rotational dynamics is torque, which is a measure of how much a force can cause an object to rotate. The moment of inertia is another important quantity in rotational dynamics, and it describes an object's resistance to rotational motion. The moment of inertia depends on the distribution of mass around the axis of rotation. The angular acceleration of a rotating object is directly proportional to the torque applied and inversely proportional to the moment of inertia. Therefore, a greater torque or a smaller moment of inertia will result in a greater angular acceleration. These concepts are used in a variety of applications, from the motion of planets to the operation of engines and turbines.
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You may need to use the appropriate appendix table or technology to answer this question. The following results are for independent random samples taken from two populations. Sample 1 Sample 2 n1 = 20 n2 = 30 x1 = 22.8 x2 = 20.1 s1 = 2.2 s2 = 4.6 (a) What is the point estimate of the difference between the two population means? (Use x1 − x2. ) 2.7 (b) What is the degrees of freedom for the t distribution? (Round your answer down to the nearest integer.) (c) At 95% confidence, what is the margin of error? (Round your answer to one decimal place.) (d) What is the 95% confidence interval for the difference between the two population means? (Use x1 − x2. Round your answers to one decimal place.)
a). The difference between the two population means is estimated at a location to be 2.7.
b). 49 different possible outcomes make up the t distribution. The margin of error at 95% confidence is 1.7.
c). The range of the difference between the two population means' 95% confidence interval is (0.0, 5.4).
d). The (0.0, 5.4) represents the 95% confidence interval for the difference among the two population means.
What is standard deviations?The variability or spread in a set of data is commonly measured by the standard deviation. The deviation between the values in the data set and the mean, or average, value, is measured. A low standard deviation, for instance, denotes a tendency for data values to be close to the mean, whereas a high standard deviation denotes a larger range of data values.
Using the equation \(x_1-x_2\), we can determine the point estimate of the difference between the two population means. In this instance, we calculate the point estimate as 2.7 by taking the mean of Sample
\(1(x_1=22.8)\) and deducting it from the mean of Sample \(2(x_2=20.1)\).
With the use of the equation \(df=n_1+n_2-2\), it is possible to determine the degrees of freedom for the t distribution. In this instance, the degrees of freedom are 49 because \(n_1\) = 20 and \(n_2\) = 30.
We must apply the formula to determine the margin of error at 95% confidence \(ME=t*\sqrt[s]{n}\).
The sample standard deviation (s) is equal to the average of \(s_1\) and \(s_2\) (3.4), the t value with 95% confidence is 1.67, and n is equal to the
average of \(n_1\) and \(n_2\) (25). When these values are entered into the formula, we get \(ME=1.67*\sqrt[3.4]{25}=1.7\).
Finally, we apply the procedure to determine the 95% confidence interval for the difference between the two population means \(CI=x_1-x_2+/-ME\).
The confidence interval's bottom limit in this instance is \(x_1-x_2-ME2.7-1.7=0.0\) and the upper limit is \(x_1+x_2+ME=2.7+1.7=5.4\).
As a result, the (0.0, 5.4) represents the 95% confidence interval for the difference among the two population means.
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can someone please help me with this
Answer:
y-intercept =3
x-intercept =3/2
slope =-2
Step-by-step explanation:
y=-2x+3
0=-2x+3
2x=3
x=3/2
(T/F) Endogeneous variables are correlated with the error term. True False
The Endogenous variables are variables that are correlated with the error term in a regression model.The statement is true.
the error term represents the unobserved factors that affect the dependent variable, and endogenous variables are those that are influenced by these unobserved factors.
In regression analysis, the error term is assumed to be uncorrelated with the independent variables. However, if there is correlation between the error term and any of the independent variables, those variables are considered endogenous. This can lead to biased and inconsistent estimation results.
To address endogeneity, various methods can be employed, such as instrumental variable regression, two-stage least squares regression, or fixed effects regression.
These techniques aim to control for the correlation between the endogenous variables and the error term, allowing for more reliable estimates of the relationship between the independent variables and the dependent variable.
In summary, endogenous variables are indeed correlated with the error term in a regression model, making it necessary to address endogeneity to obtain accurate and reliable results.
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A curve has slope 5x 4 y at every point (x,y). If it is known that the curve passes through the point (0,−3), what is the equation of the curve?
The equation of a curve with slope 5x^4y at every point (x,y) and passing through (0,-3) is y = ±3e^(x^5). The method of separation of variables was used to solve the differential equation and find the constant of integration.
To find the equation of the curve with slope 5x^4y at every point (x,y) and passing through the point (0,-3), we can use the method of separation of variables.
First, let's separate the variables x and y by multiplying both sides by dx and dividing both sides by 5x^4y:
dy/dx = 5x^4y
(1/y) dy = 5x^4 dx
Integrating both sides, we get:
ln|y| = x^5 + C
where C is the constant of integration.
To find the value of C, we can use the fact that the curve passes through the point (0,-3). Substituting x = 0 and y = -3 into the equation, we get:
ln|-3| = 0 + C
C = ln(3)
Therefore, the equation of the curve is:
ln|y| = x^5 + ln(3)
Taking the exponential of both sides, we get:
|y| = e^(x^5+ln(3))
Since y can be positive or negative, we can write:
y = ±e^(x^5+ln(3))
Simplifying, we get:
y = ±3e^(x^5)
Therefore, the equation of the curve is y = ±3e^(x^5), and it passes through the point (0,-3).
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Which expression is equivalent to (x Superscript 27 Baseline y) Superscript one-third?
1. x Superscript 3 Baseline (Superscript 3 StartRoot y end root)
2. x Superscript 9 Baseline (Superscript 3 StartRoot y end root)
3. x Superscript 27 Baseline (Superscript 3 StartRoot y end root)
4. x Superscript 24 Baseline (Superscript 3 StartRoot y end root)
Answer:
B
Step-by-step explanation
i got a 100 on the quiz
The required equivalent expression to the given expression is x Superscript 9 Baseline (Superscript 3 StartRoot y end root). Option 2 is correct.
What is simplification?It is a technique in mathematics to operate and interpret the function to make the function or expression straightforward or more understandable is called simplifying and the process is called simplification.
Here,
the given expression,
(x Superscript 27 Baseline y) Superscript one-third = [x²⁷/y]¹/³
= [[x²⁷/³]/∛y
= x⁹/∛y = x Superscript 9 Baseline (Superscript 3 StartRoot y end root)
Thus, the required equivalent expression to the given expression is x Superscript 9 Baseline (Superscript 3 StartRoot y end root). Option 2 is correct.
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(7x + 34)
(10x - 23)
Divide 36 in the ratio 5 : 4
5/4 times 36 is found as 9.5=45.
Let's solve examples; Divide 68 in the ratio 7:2 + 68.7/2=34.7 = 238 Divide 48 in the ratio 3 : 12 + 48.3/12=4.3 = 12 Divide 23 in the ratio 5 : 8 + 23.5/8 = 115/8 (not simplistic)Consider the ordered basis B of R^2 consisting of the vectors [1 -6] and [2 -1] (in that order) . Find the vector X in R^2 whose coordinates with respect to the basis B are '[6 -1] , x = ____.
The vector X in \(R^{2}\) whose coordinates with respect to the basis B are [6, -1] is X = [4, -35]
An ordered basis B in \(R^{2}\) is a pair of linearly independent vectors that can be used to uniquely represent any vector in the 2-dimensional space.
In this case, the ordered basis B consists of the vectors [1, -6] and [2, -1].
A vector X in \(R^{2}\) can be written as a linear combination of the basis vectors. To find the vector X whose coordinates with respect to basis B are [6, -1], we can represent it as follows:
X = 6 × [1, -6] + (-1) × [2, -1]
Now, we just need to perform the linear combination:
X = 6 × [1, -6] + (-1) × [2, -1]
X = [6 × 1, 6 × (-6)] + [(-1) × 2, (-1) × (-1)]
X = [6, -36] + [-2, 1]
Next, add the corresponding components of the two resulting vectors:
X = [(6 + -2), (-36 + 1)]
X = [4, -35]
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the slope of the line whose equation is x+y=6
If you worked 6 hrs and got $90 how much dollars would you get per hour
Answer:
$15 an hour
Step-by-step explanation:
90 divided by 6 is 15.
Answer:
$15 per hour
Step-by-step explanation:
There's six hours so to get each hour, divide the $90 dollars by 6 and you will find your answer.
Please Brainliest if you found this helpful!
PLEASE HELP ME ON THIS ALGEBRA PROBLEM!!!
The number of permutations of 8 objects taken 3 at a time is.
The number of permutations of 8 objects taken 3 at a time is 336.
To calculate the number of permutations, we use the formula for permutations of n objects taken r at a time, which is given by P(n, r) = n! / (n - r)!. In this case, we have 8 objects and we want to take 3 objects at a time. Therefore, the number of permutations is P(8, 3) = 8! / (8 - 3)! = 8! / 5!.
Simplifying further, we have 8! = 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 and 5! = 5 x 4 x 3 x 2 x 1. Canceling out common factors, we get (8 x 7 x 6) / (3 x 2 x 1) = 336.
Therefore, the number of permutations of 8 objects taken 3 at a time is 336.
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Demand history for the past three years is shown below, along with the seasonal indices for each quarter.
Year Quarter Demand Seasonal Index
Year 1 Q1 319 0.762
Q2 344 0.836
Q3 523 1.309
Q4 435 1.103
Year 2 Q1 327 0.762
Q2 341 0.836
Q3 537 1.309
Q4 506 1.103
Year 3 Q1 307 0.762
Q2 349 0.836
Q3 577 1.309
Q4 438 1.103
Use exponential smoothing with alpha (α) = 0.35 and an initial forecast of 417 along with seasonality to calculate the Year 4, Q1 forecast.
The Year 4, Q1 forecast using exponential smoothing with α = 0.35 and an initial forecast of 417, along with seasonality, is 335.88.
Exponential smoothing is a forecasting technique that takes into account both the historical demand and the trend of the data. It is calculated using the formula:
Forecast = α * (Demand / Seasonal Index) + (1 - α) * Previous Forecast
Initial forecast (Previous Forecast) = 417
α (Smoothing parameter) = 0.35
Demand for Year 4, Q1 = 307
Seasonal Index for Q1 = 0.762
Using the formula, we can calculate the Year 4, Q1 forecast:
Forecast = 0.35 * (307 / 0.762) + (1 - 0.35) * 417
= 335.88
Therefore, the Year 4, Q1 forecast using exponential smoothing with α = 0.35 and an initial forecast of 417, along with seasonality, is 335.88.
The forecasted demand for Year 4, Q1 using exponential smoothing is 335.88.
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Grade 7 Math, Unit 6 Lesson 7 Practice Problems Question 3
Please help!!
This is grade 7 math btw
A. Equation to represent the hanger is 5(x)+2=17
B. We remove two from the right to balance the left side. 5x minus 2 equals 5 x's and 17-2=15. The balances hanger represents an equation that would be 5x=15. 5 x's would be 15÷5 which would give us 5 groups of 3. 15÷5=3 so, one of the x's equals 3. So, x=3
Sorry I couldn't do C. I am so sorry... :(
) let ℎ() = (3() − 23). use the table of values to find ℎ′(2). (4 points
The answer is: ℎ′(2) = 21 using inverse logic for the given question.
To find ℎ′(2), we first need to find the slope of the tangent line to the graph of ℎ() at the point where = 2. We can use a table of values to do this.
To create a table of values, we choose some values of and calculate the corresponding values of ℎ(). Let's choose a few values of close to 2:
= 1.8: ℎ(1.8) = 3(1.8) - 23 = -17.4
= 1.9: ℎ(1.9) = 3(1.9) - 23 = -16.3
= 2.0: ℎ(2.0) = 3(2.0) - 23 = -15
= 2.1: ℎ(2.1) = 3(2.1) - 23 = -13.9
= 2.2: ℎ(2.2) = 3(2.2) - 23 = -12.8
Now, we can use these points to estimate the slope of the tangent line at = 2. Specifically, we can use the difference quotient:
[ℎ(2+h) - ℎ(2)]/h
where h is a small number (in this case, h = 0.1). Plugging in the values from our table, we get:
[ℎ(2.1) - ℎ(2)]/0.1 = (-13.9 - (-15))/0.1 = 21
This means that the slope of the tangent line to the graph of ℎ() at = 2 is approximately 21. Therefore, we have:
ℎ′(2) = 21
So, the answer is: ℎ′(2) = 21 in inverse case.
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the time needed to complete a final examination in a particular college course is normally distributed with a mean of
The probability of a student completing the final examination in less than 65 minutes is 13.45%.
The time it takes to complete a final examination in a particular college course is normally distributed with a mean of 77 minutes and a standard deviation of 12 minutes. This can be expressed mathematically as X~N(77, 12).
The probability of a student completing the final examination in less than 65 minutes can be calculated by using the Z-score formula:
Z = (x - μ) / σ
Where x = 65 minutes, μ = 77 minutes, and σ = 12 minutes.
Plugging these values into the formula, we get:
Z = (65 - 77) / 12 = -1.17
Using a Z-score table, we can find the probability of a student completing the final examination in less than 65 minutes, which is equal to 0.1345, or 13.45%. Therefore, the probability of a student completing the final examination in less than 65 minutes is 13.45%.
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HELP! I NEED HELP URGENT!
1. 30/24= 5/4 is it proportional?
2. 12/16= 6/4 is it proportional?
Answer:
1st one is proportional
2nd is not proportional
Step-by-step explanation:
30/5=6 24/4=6
Yes, 1 is proportional.
12/6=2 16/4=4
No, 2 is not proportional.
---
hope it helps
- The weight of an object having mass 5kg is 450 N weight of another object having mass 50kg is 147N. Check weather the mass and we weight are proportional What is the constant of proportionality
Answer:
see below
Step-by-step explanation:
We are here given that weight of an object having mass of 5kg is 450N .
As we know that,
Weight = mass * acceleration due to gravity (g)
So that ,
450N = g * 5kg
g = 450/5 m/s²
g = 90m/s²
Again in second case,
147N = g' * 50kg
g' = 147/50 m/s²
g' = 29.4 m/s²
since here g ≠ g'
Therefore,
mass and weight are not promotional in this case. This may be due to the fact that the acceleration due to gravitational force of each celestial object is different and weights may have been measured on different planets.
And the constant of proportionality is g ( acceleration due to the gravitational force) .
And we are done!
Which is closest to the volume of a sphere with a radius equal to 8 centimeters?
Α.
267.9 cm3
B
803.8 cm3
С
1,607.7 cm3
D
2,143.6 cm3
Answer:
Step-by-step explanation:
volume of sphere = 4πr³/3
= 4π×512/3
≈ 2143.6 cm³
Simplify:
(5ab)^2 (-2a^2 bc^2)^3
Please show work. I'll give Brainliest
Answer:
-200a^8b^5c^6
Step-by-step explanation:
When you square and cube what is in the parenthesis (multiply them using pemdas), and combine like terms, you get a simplified answer of -200a^8b^5c^6.
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Please answer ASAP for notes (will mark someone brainiest if 2 people answer)
Use the image to determine the type of transformation shown
A. Vertical translation
B. Reflection across the X-axis
C.180° counterclockwise rotation
D. Horizontal Translation
Answer:
it's A.
Step-by-step explanation:
a vertical translation, in the name, means you are moving the graph up or down the y axis. a horizontal translation is moving the graph left or right on the x axis. a reflection across the x axis is all the x values *-1. 180 counterclockwise rotation is rotating the graph top to bottom.
Answer:
A. Vertical translation
Step-by-step explanation:
A vertical translation means the object moves up or down without changing anything else of itself, such as size, rotation, reflection, etc. Only movement up and down.
Reflection is where the object moves as though the axis is a mirror, where the object translates the same distance from the axis, but also flips across the axis, so if it is an x-axis, it flips upside down, and at a y-axis, flips left and right.
A rotation in any direction that is 180 degrees means that the object appears to be flipped opposite of what it started as. For example, if A is at the top point, after rotation, A would be the bottom point.
A horizontal translation is the same as with a vertical translation, except the object moves left or right.
From each of these analyses I provided on each of the answer choices, we can clearly see that the correct answer is the first option, "A. Vertical translation," as the object did exactly as I described what a vertical translation is.
If I helped (and more clearly explained, hopefully, than the other answer), please make this answer brainliest ;)
What number, divided by 3/7 , will result in a value of 2 1/3?