of the following orbital occupancy designations is incorrect? a)3d7 b)2p6 c)4f6 d)1s2 e)4f15

Answer:

The correct option is;

Sun, planets, moons, asteroids, comets

Explanation:

The Solar System consists of the system of celestial bodies bound gravitationally to the Sun, which includes the 8 regular planets, 2 dwarf planets, 796, 354 known minor planets, 4,143 comets, moons, which are natural satellites, an asteroid belt, which consists of a belt of rock and metal containing celestial bodies moving in a belt round the Sun

Junita will do more work on the square box. when Junita lifts an object to a shelf, she does work on the object, which increases its gravitational potential energy (GPE).

The amount of work done on an object is equal to the increase in its GPE.

Junita lifted a round box and a square box to a shelf. She did work on the boxes, increasing their GPE. The round box's GPE increased by 50 J, meaning Junita exerted 50 J of work.

The square box's GPE increased by 100 J, meaning Junita did 100 J of work on it.

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Choice-B is a relevant statement, although we can't see enough of the picture to actually know what's going on.

A good example of this scenario is our own moon.  Because of the Sun's  gravitational influence, the Moon's orbit around the Earth is not a circle or an ellipse.

Answer:

....

Explanation:

The time taken for the radioactive material to decay from 400 counts per sec to 50 counts per sec is 3 years.

We'll begin by calculating the number of half-lives that has elapsed. This can be obtained as follow:

Original amount (N₀) = 400 count per sec

Amount remaining (N) = 50 count per sec

Number of half-lives (n) =?

N × 2ⁿ = N₀

50 × 2ⁿ = 400

Divide both side by 50

2ⁿ = 400 / 50

2ⁿ = 8

2ⁿ = 2^3

n = 3

Thus, 3 half-lives has elapsed

Finally, we shall determine the time taken for the radioactive material to reduce to 50 counts per sec. This can be obtained as follow;

Number of half-lives (n) = 3

Half-life (t½) = 1600 years

Time (t) =?

t = n × t½

t = 3 × 50,457,600,000 seconds

t = 151,372,800,000 seconds = 3 years

Therefore, it will take 3 years for the radioactive material to decay to 50 counts per second.

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Answer:

   (3) the same before and after the collision

Explanation:

The sum of products of mass and velocity before the collision is ...

  (2 kg)(0.250 m/s) + (2 kg)(0 m/s) = 0.50 kg·m/s

The sum of products of mass and velocity after the collision is ...

  (2 kg +2 kg)(0.125 m/s) = 0.50 kg·m/s

The total momentum is unchanged.

Answer:

The forces are balanced

Explanation:

For an object to be unbalanced, each force has to be in the opposite direction of another force and have equal strength.

Taking a look at this photo:

The forces are balanced because the left and right side both have forces acting in the opposite direction and will equal strength, 25 Newtons.

The same is said about the top and bottom of the rectangle, but the equal strength is 10 Newtons.

We need to use the formula: Force = Mass × Acceleration Let's use the given values to calculate the force exerted on the deer when it is hit by the car. The car weighs 235 lb and it is traveling north at 75 mph. The deer weighs 150 lb and it is going 35 mph east. Force = 44045 lbSince the force is a vector quantity, it has both magnitude and direction.

Step 1: Convert the velocities into feet per second.1 mile = 5280 feet1 hour = 3600 seconds So, the velocity of the car is:75 mph = (75 × 5280) ÷ 3600 = 110 feet/secondThe velocity of the deer is:35 mph = (35 × 5280) ÷ 3600 = 51.3 feet/second

Step 2: Find the components of velocity of the deer. The velocity of the deer is in the east direction, so we need to find its horizontal component, vx, and its vertical component, vy. If the angle between the deer's velocity and the x-axis is θ, then: vx = v × cosθandvy = v × sinθv = 51.3 feet/secondθ = 90° - arctan(0 / 110) = 90°So,vx = 51.3 × cos90° = 0 feet/second vy = 51.3 × sin90° = 51.3 feet/second

Step 3: Find the net velocities of the car and the deer. Since the car is moving north and the deer is moving east, the net velocity of the car and deer together can be found using the Pythagorean theorem. Net velocity = √[(vx + 110)² + vy²]Net velocity = √[(0 + 110)² + (51.3)²]Net velocity = √(12100 + 2631.69)Net velocity = √14731.69Net velocity = 121.3 feet/second

Step 4: Find the net momentum of the car and the deer. Net momentum = (mass of car × velocity of car) + (mass of deer × velocity of deer)Net momentum = (235 × 110) + (150 × 121.3)Net momentum = 25850 + 18195Net momentum = 44045 lb ft/second

Step 5: Find the force exerted on the deer. Force = Net momentum ÷ time Here, time is the duration of the collision which is not given in the problem. We will assume it to be 1 second. Force = 44045 ÷ 1

Force = 44045 lb Since the force is a vector quantity, it has both magnitude and direction. The direction of force is along the line of impact which is not given in the problem.

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Therefore, the maximum speed of the emitted electrons is 1.62 x 10⁶ m/s.

The photoelectric effect is observed on two metal surfaces. If light of wavelength 300.0 nm is incident on a metal that has a work function of 2.80 eV, the maximum speed of the emitted electrons is 1.62 x 10⁶ m/s. What is the photoelectric effect? The photoelectric effect, also known as the Hertz–Lenard effect, is a phenomenon in which electrons are emitted from a metal surface when light is shone on it. The photoelectric effect was initially studied by Heinrich Hertz in 1887 and later by Philipp Lenard in 1902.Latex-free answer: To calculate the maximum speed of emitted electrons using the photoelectric effect equation, we can use the following formula: KEmax = hν - φwhere KE max is the maximum kinetic energy of the ejected electron, h is Planck's constant, ν is the frequency of the incident light, and φ is the work function of the metal. Using the equation, we can convert the given wavelength of 300.0 nm to frequency by using the formula c = λν where c is the speed of light and λ is the wavelength. c = λνν = c/λν = (3.0 x 10⁸ m/s) / (300.0 x 10⁻⁹ m)ν = 1.0 x 10¹⁵ Hz, Now we can plug in the values in the equation: KE max = (6.626 x 10⁻³⁴ J s) (1.0 x 10¹⁵ Hz) - (2.80 eV)(1.60 x 10⁻¹⁹ J/eV)KE max = 1.06 x 10⁻¹⁹ J - 4.48 x 10⁻¹⁹ JKE max = -3.42 x 10⁻¹⁹ J. Since KE max is a positive value, we can convert the value to speed using the equation KE = 1/2mv² where m is the mass of the electron and v is the velocity of the electron: v = √(2KE/m)v = √[(2)(3.42 x 10⁻¹⁹ J)/(9.11 x 10⁻³¹ kg)]v = 1.62 x 10⁶ m/s. Therefore, the maximum speed of the emitted electrons is 1.62 x 10⁶ m/s.

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Answer:

Answer:the car is speeding up

Explanation:

Answer:

They have holes that are positively charged

Explanation:

There are two types of semiconductors i.e. p-type and n-type.

p-type is a type of semiconductor that is formed when a trivalent impurity is added to an intrinsic semiconductor like silicon or germanium. Boron (B), Gallium (Ga), Indium(In), Aluminium(Al) etc are trivalent impurities. Due to this combination, a large number of holes are created in it.

Hence, p-types of semiconductors have holes that are positively charged.

Answer: Some places like Florida and California are both very hot and dry places, the sun damages your skin more in sunny places then in colder more breezy places.

Explanation:

At 9:00 p.m. on august 18, the bright star vega is straight overhead as seen from charlottesville ,Vega would appear to an observer in Cajamarca, Peru, approximately 22.5 degrees south of overhead.

To determine where the star Vega would appear to an observer in Cajamarca, Peru, we need to consider the difference in latitude between Charlottesville and Cajamarca. Since the star is straight overhead in Charlottesville, we need to find the corresponding latitude in Cajamarca where Vega would be overhead.

The circumference of the Earth is approximately 40,000 km, so traveling 5,000 km south from Charlottesville brings us one-eighth of the way around the Earth.

Knowing that, we can calculate the latitude shift by dividing the Earth's total latitude range (from the North Pole to the South Pole, 180 degrees) by 8.

Latitude shift = 180 degrees / 8 = 22.5 degrees

Therefore, Vega would appear to an observer in Cajamarca, Peru, approximately 22.5 degrees south of overhead.

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The angular frequency of the glider that takes 0.30 s to travel the distance of 12 cm from one turning point to another is 20.93 rad/s.

The angular frequency is the magnitude of the angle of the sector of the circle formed by the trajectory of the point that moves in a circle per unit time. Briefly, angular speed is the angular speed accompanied by the direction. The unit of angular speed is rad/second or rad/minute or rad/hour, depending on what is known from each problem.

The equation for determining the angular speed or angular frequency is:

ω= 2\(\pi\)/T or ω = 2\(\pi\)f

Where f = 1/T

ω = angular speed or frequency (rad/second)

\(\pi\) = 3.14

f = frequency (rev/second)

T = period (second)

We have,

T = 0.30 s

So, ω = 2\(\pi\)/T

= 2 (3.14) / 0.30

= 20.93 rad/s

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Given the statement:

The further away the galaxy is, the ____________ the shift found by the Hubble.

Let's complete the statement.

According the Hubble's brilliant observation, the shift of the galaxy is directly proportional to the distance of the galaxy from the Earth.

This means that as the distance of the galaxy increases, the shift also increase.

Therefore, the further away a galaxy is, the greater the shift found by the Hubble telescope.

ANSWER:

D. Greater

Answer:

You can increase your cardio respiratory endurance by exercising on the regular base that increase your heart beat and breathing rates. Some examples of good exercise is running, jumping rope, swimming dancing ect.

Explanation:

You are welcome.

1. Astronomical observational patterns are used to determine the history of the universe by studying the light emitted or absorbed by celestial objects. Scientists analyze the patterns in the electromagnetic spectrum, such as the distribution of wavelengths, intensity, and spectral lines, to gather information about the composition, temperature, motion, and evolution of celestial bodies.

Astronomical observational refers to the act of observing celestial objects and phenomena in the field of astronomy. It involves the use of telescopes, detectors, and other instruments to collect data and study various aspects of the universe.

2. Mount Wilson and Mount Palomar Observatories were used to observe and collect data about space due to several reasons. Firstly, the locations of these observatories provide advantages for astronomical observations.

3. The NASA Mission Statement is: "To pioneer the future in space exploration, scientific discovery, and aeronautics research." This mission statement reflects NASA's commitment to advancing human knowledge, technological innovation, and exploration beyond Earth's boundaries. NASA aims to push the boundaries of scientific understanding, develop and test new technologies, explore the cosmos, and inspire the next generation of scientists and engineers.

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Answer:

Renewable energy sources can come again, but nonrenewable is gone forever. For example, coal and gasoline are both nonrenewable.

Explanation:

The shortest distance in which the car can stop, after the brakes are applied, without the groceries sliding off the seat is 27.5 m.

We can use the equations of motion for constant acceleration to solve this problem. The acceleration of the car when the brakes are applied is given by, a = -μg, where μ is the coefficient of friction, g is the acceleration due to gravity (9.8 m/s^2), and the negative sign indicates that the acceleration is in the opposite direction to the motion of the car. We need to find the distance, d, that the car travels before coming to a stop.

v^2 = u^2 + 2as

where v is the final velocity (0 m/s), u is the initial velocity (16 m/s), a is the acceleration (-μg), and s is the distance traveled.

Solving for s,

s = (v^2 - u^2) / (2a)

Plugging in the values,

s = (0 - (16 m/s)^2) / (2(-0.65)(9.8 m/s^2)) = 27.5 m

So the car will travel 27.5 m before coming to a stop.

Now we need to check if the groceries will slide off the seat during braking. The maximum force of friction that the seat can exert on the groceries is given by,

F_friction = μ_friction * F_normal

where μ_friction is the coefficient of friction (0.45 for kinetic friction), and F_normal is the normal force exerted by the seat on the groceries. The normal force is equal to the weight of the groceries, which is,

F_normal = m * g = 7.0 kg * 9.8 m/s^2 = 68.6 N

So the maximum force of friction is,

F_friction = 0.45 * 68.6 N = 30.9 N

The force of friction during braking is given by,

F_braking = m * a = 7.0 kg * (-0.65) * 9.8 m/s^2 = -45.4 N

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The magnitude of the electric force on the charge is 5 N.

The magnitude of force on the charge is calculated as follows;

F = Eq

where;

F = 100 N/C  x 0.05 C

F = 5 N

Thus, the magnitude of the electric force on the charge is 5 N.

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Answer:

5n downward

Explanation:

took the assignment

Answer:

I think is B but I'm not sure

The statement which is true about Earth's energy budget is that most of the energy from the sun is absorbed by the atmosphere and surface. Thus, the correct option for this question is B.

Earth's energy budget may be characterized as the mutual balance between the radiant energy that significantly reaches Earth from the sun with respect to the energy that flows from Earth back out to space.

In order to maintain a constant global average temperature, all of the sun's radiation that successfully enters Earth's atmosphere must eventually be sent back to space. There are three sources of Earth's energy budget may include incoming solar energy (shortwave radiation), Outgoing longwave radiation, and Earth's internal heat sources and other small effects.

Therefore, the correct option for this question is B.

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The radial velocity method preferentially detects large planets close to the central star

The radial velocity technique is able to detect planets around low-mass stars, such as M-type (red dwarf) stars.

This is due to the fact that low mass stars are more affected by the gravitational tug of planets.

When a planet orbits around a star, the star wobbles a little.

From this, we can determine the mass of the planet and its distance from the star.

hence we can say that,

option D is correct.

The radial velocity method preferentially detects large planets close to the central star

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Option D) 1.5 m/s² is the correct answer.

The magnitude of the acceleration of the car is 1.5 m/s².

given the data in the question;

record of the observation;

Time(s)      Speed(m/s)

3.0                4.0

5.0                7.0

6.0                8.5

Since its undergoing constant acceleration, we can make use any two from the three data recorded.

So, lets consider motion between t₁ = 3.0s and t₂ = 5.0s

Initial velocity at t₁ ; u = 4.0 m/s

final velocity at t₂; v = 7.0 m/s

Now, Time Elapsed; \(t = t_2 - t_1 = 7.0s - 5.0s = 2.0s\)

To determine the magnitude of acceleration "a", we use the first equation of motion which says;

\(v = u + at\)

we make "a" the subject of the formula

\(a =\frac{v - u}{t}\)

so we substitute in our values;

\(a = \frac{(7.0m/s) - (4.0m/s)}{2.0s}\)

\(a = \frac{3.0m/s}{2.0s}\)

\(a = 1.5 m/s^2\)

Therefore, the magnitude of the acceleration of the car is 1.5 m/s².

Option D) 1.5 m/s² is the correct answer.

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Answer:

Measles and Whooping Cough

Explanation:

I really hope so

Answer:

Hey

Explanation:

Answer:

1st is magnetic waves. second one is air.

The density of lead is 11.4 g/cm3 at 25°C and the volume occupied by 25.0 g of lead is 2.19 cm3. Hence, option A is the correct option.

The formula to calculate the volume (V) of a substance is:

V = m / ρ

Here, m is the mass of the substance and ρ is its density so in this case, we have:

m = 25.0 g

ρ = 11.4 g/cm3

Putting these values into the formula:

V = 25.0 g / 11.4 g/cm3

V = 2.19 cm3

Therefore, the volume occupied by 25.0 g of lead is 2.19 cm3.

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Answer:

Answer is a wave with the longest wavelength.

Explanation:

I hope it's helpful!

Frozen preparations such as ice cream, sorbet, gelato, granite can be melted and refrozen, except gelato which cannot be melted and refrozen. This is because the ice cream, sorbet, and granite all contain a high content of fat which allows them to melt and refreeze successfully without becoming damaged.

However, the process of freezing the gelato forms tiny ice crystals, which provide its unique texture. If gelato is melted, it will lose its texture and will not re-freeze successfully.A gelato is a dense Italian ice cream that has a creamy texture and has a lower fat content than traditional ice cream. It is made by mixing milk, sugar, and flavorings, such as nuts or chocolate, and then churned to incorporate air into the mixture.

So, the ice cream, sorbet, and granite all contain a high content of fat which allows them to melt and refreeze successfully without becoming damaged.

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