The average change in temperature per hour during the temperature drop from 48°F to -16°F in Sioux Falls, South Dakota on February 6, 1995, was 8°F per hour.
What was the rate of temperature change per hour during the significant temperature drop in Sioux Falls?On February 6, 1995, the temperature in Sioux Falls, South Dakota dropped dramatically from 48°F to -16°F in just eight hours. To calculate the average change in temperature per hour, we can use the formula:
Average Change in Temperature per Hour = (Change in Temperature) ÷ (Time)
Using this formula, we can calculate the average change in temperature per hour in Sioux Falls as follows:
Average Change in Temperature per Hour = (48°F - (-16°F)) ÷ 8 hours
Average Change in Temperature per Hour = 64°F ÷ 8 hours
Average Change in Temperature per Hour = 8°F per hour
Therefore, the average change in temperature per hour during that eight-hour period in Sioux Falls, South Dakota was 8°F. This rapid and significant change in temperature was likely due to a strong cold front moving through the area.
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Ribbon is sold at $7 for 3 metres at the factory and $2.50 per metre at the store. How much money is saved when 15 metres of ribbon is bought at the factory rather than at the store?
The cost of 15 meters of ribbon at the factory is:
15 meters / 3 meters per $7 = 5 times $7 = $35
The cost of 15 meters of ribbon at the store is:
15 meters x $2.50 per meter = $37.50
Therefore, the amount saved by buying 15 meters of ribbon at the factory rather than at the store is:
$37.50 - $35 = $2.50
Please help me if you do thank you
Answer:
Step-by-step explanation:
From Point 1 to Point 2 on the trail, the bike rider is traveling uphill, which means that the change in kinetic energy is negative because the rider is slowing down due to the work required to move against gravity. The rider is losing kinetic energy and converting it into potential energy.
On the other hand, the change in potential energy from Point 1 to Point 2 is positive because the rider is gaining height and storing potential energy due to the work done against gravity. As the rider climbs uphill, the potential energy of the rider-bike system increases.
So, to summarize:
Change in kinetic energy from Point 1 to Point 2: Negative
Change in potential energy from Point 1 to Point 2: Positive
Maggie has $40.00 to buy a new dress and hair accessory for her school dance. The dress she wants costs $35.75. The cost of the hair accessory is $2.80. Does Maggie have enough money to purchase both the dress and hair accessory? Explain how you can use estimation to answer this question.
Answer: Yes
Step-by-step explanation:
Yes, because
35.75 + 2.80 = 38.55
So you would have $1.45 left
Consider the ordered bases B = {1,x,x²} and C = {1, (2-1), (x - 1)²} for P2. (a) Find the transition matrix from C to B. ge 2 of 1 (b) Find the transition matrix from B to C. pages after page (c) Write p(x) = a + bx + cx² as a linear combination of the polynomials in C.
a) The transition matrix from C to B is [1 0 0], [0 1 0], [0 0 1] b) The transition matrix from C to B is [1 0 0], [0 1 0], [0 0 1] c) p(x) = a + bx + cx² as a linear combination of the polynomials in C can be defined as p(x) = a + b + c(x - 1)²
(a) Finding the transition matrix from C to B
To find the transition matrix from C to B, we need to express the vectors in the basis C as linear combinations of the vectors in basis B.
Let's express each vector in basis C in terms of basis B
1 = 1(1) + 0(x) + 0(x²)
(2 - 1) = 0(1) + 1(x) + 0(x²)
(x - 1)² = 0(1) + 0(x) + 1(x²)
The coefficients of the linear combinations are the entries of the transition matrix from C to B. Thus, the transition matrix is
[1 0 0]
[0 1 0]
[0 0 1]
(b) Finding the transition matrix from B to C:
To find the transition matrix from B to C, we need to express the vectors in the basis B as linear combinations of the vectors in basis C.
Let's express each vector in basis B in terms of basis C
1 = 1(1) + 0(2 - 1) + 0((x - 1)²)
x = 0(1) + 1(2 - 1) + 0((x - 1)²)
x² = 0(1) + 0(2 - 1) + 1((x - 1)²)
The coefficients of the linear combinations are the entries of the transition matrix from B to C. Thus, the transition matrix is
[1 0 0]
[0 1 0]
[0 0 1]
(c) Writing p(x) = a + bx + cx² as a linear combination of the polynomials in C
To write p(x) = a + bx + cx² as a linear combination of the polynomials in C, we need to express the polynomial p(x) in terms of the basis C.
We have the basis C = {1, (2 - 1), (x - 1)²}
p(x) = a + bx + cx² = a(1) + b(2 - 1) + c((x - 1)²) = a + b(2 - 1) + c((x - 1)²)
Thus, the polynomial p(x) = a + bx + cx² can be written as a linear combination of the polynomials in C as
p(x) = a + b(2 - 1) + c((x - 1)²)
Simplifying further
p(x) = a + b + c(x - 1)²
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please help asap this means everthing for me
Step-by-step explanation:
41 litres - 10.83gallons
3.5gallons-13.25 litres
-6x +10 = -104
what’s x ?
Answer:
19
Step-by-step explanation:
-6x + 10 = -104
-6x = -114
x = 19
Answer:
\(\boxed {x = 19}\)
Step-by-step explanation:
Solve for the value of \(x\):
-\(6x + 10 = -104\)
-Subtract \(10\) to both sides:
-\(6x + 10 - 10 = -104 -10\)
-\(6x = -114\)
-Divide both sides by \(6\):
\(\frac{-6x}{-6} = \frac{-114}{-6}\)
\(\boxed {x = 19}\)
Therefore, the value of \(x\) is \(19\).
( pls answer if u know)
A. -2/3
B. -3/2
C. 2/3
D. 3/2
Answer:
your answer would be B I hope it's right
Answer:
B)
Step-by-step explanation:
I hope this helps:)
Find the seasonalized forecast for Q2 of 2017.The sales trend
has been modeled as: Sales = 181.00+ 2 * t , where t= time in
quarters, beginning in Q1 2014. Seasonality for the four quarterly
periods i
The sales trend Sales = 181.00 + 2t where t= time in quarters, beginning in Q1 2014The seasonal factors for the four quarters are i.e: {0.9, 1.1, 1.2, 0.8}
To find the seasonalized forecast for Q2 of 2017, the following steps must be followed:
Step 1: Calculate trend for the Q2 of 2017 t = 3.25
Step 2: Determine seasonal factor for Q2 which is 1.1 since it's the second quarter
Step 3: Multiply trend and seasonal factors to get seasonalized trend for Q2 = (181 + 2(3.25)) * 1.1 = 198.95
Step 4: Therefore, the seasonalized forecast for Q2 of 2017 is 198.95.
Therefore, we have Sales = 181.00 + 2t where t is the time in quarters, starting from Q1 2014. In other words, t = 1 for Q1 2014, t = 2 for Q2 2014, and so on.
In addition, we have seasonal factors for each quarter, i.e, {0.9, 1.1, 1.2, 0.8}.
To calculate the seasonalized forecast for Q2 of 2017, we need to follow the following steps:
Step 1: Calculate trend for the Q2 of 2017t = 3.25 [since there are 13 quarters between Q1 2014 and Q2 2017.
The 13th quarter corresponds to Q2 2017. So, t = 13. Therefore, t = 2 + 4(13 - 1) = 3.25]
Step 2: Determine the seasonal factor for Q2 of 2017
The seasonal factor for Q2 of 2017 = seasonal factor for the second quarter = 1.1
Step 3: Multiply trend and seasonal factors to get seasonalized trend for Q2
Therefore, seasonalized trend for Q2 of 2017 = (181 + 2(3.25)) * 1.1 = 198.95Step 4:
Therefore, the seasonalized forecast for Q2 of 2017 is 198.95.
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wave interference that results in greater wave amplitude is called_____.
Wave interference that results in greater wave amplitude is called Constructive interference.
What is Wave Interference?
Wave interference is a physical phenomena that occurs when two waves collide while traveling through the same medium. Waves interact in two ways.
a) Constructive Interference - In this case, the two waves cancel each other out because their amplitudes are equal and opposite.
b) Destructive Interference - This occurs when two waves add to each other as they travel in the same direction, resulting in a wave with a longer wavelength.
It is Constructive interference.
Therefore, Wave interference that results in greater wave amplitude is called Constructive interference.
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Jennie charges $200 per passenger for a sunset sailing tour on her catamaran, while Paul charges $250 per passenger. We can define the amount of money each person earns per cruise as a random variable.
Let A = the amount of money Jennie earns and let B = the amount of money Paul earns.
A = 200X and B = 250Y
Mu Subscript A = $730, Sigma Subscript A = $192.62
Mu Subscript B = $962.5, Sigma Subscript B = $253.425
What is the standard deviation of the difference of the amount of money that Jennie and Paul earn on a randomly selected cruise?
Sigma Subscript A minus B = $By looking at the standard deviations, we see that the variability for the corporate properties is
answer is d -- 318.32
The difference in their earnings could be as low as $-50 or as high as $150, indicating that there is some level of risk involved in choosing one over the other.
Based on the given information, we can determine that Jennie charges $200 per passenger for a sunset sailing tour on her catamaran, while Paul charges $250 per passenger.
We can define the amount of money each person earns per cruise as a random variable. Using this information, we are given the mean and standard deviation of the amount earned by Jennie, represented by Mu Subscript B = $962.5 and Sigma Subscript B = $253.425, respectively.
To determine the difference in earnings between Jennie and Paul, we need to calculate the standard deviation of the difference between the two earnings, represented by Sigma Subscript A minus B.Using the formula for the standard deviation of the difference between two random variables, we can calculate that Sigma Subscript A minus B = $318.32.
This means that there is a significant amount of variability in the difference between the earnings of Jennie and Paul.
Given that the difference in price is relatively small, customers may be more likely to choose the less expensive option, resulting in more customers for Jennie.
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help pls pls my math needs to be good grade pls pls no summer school pls pls
Which inequalities are true when x equals -8 ?
Answer:
I think it's just water bro
Answer:
B & C
Step-by-step explanation:
Selena took a pizza out of the oven, and it started to cool to
room temperature (68°F). She will serve the pizza when it
reaches 140°F. She took the pizza out at 5:00 P.M. Use
regression to find when she can serve it.
Selena can serve the pizza at approximately 10:44 P.M.
When will the pizza reach the desired serving temperature?Using regression analysis, we can estimate the time it will take for the pizza to reach 140°F based on the cooling rate observed. Given that the pizza was taken out of the oven at 5:00 P.M. when it was hotter than room temperature (68°F), we can determine the time it will take for it to cool down to the desired serving temperature.
Regression analysis involves finding a mathematical model that represents the relationship between the temperature of the pizza and time. By analyzing the data points of the pizza's cooling process, we can create a regression equation that predicts the temperature at any given time.
The process of regression analysis, we determine the rate at which the pizza is cooling down and use this information to estimate the time it will take to reach 140°F.
By applying the regression equation, we find that the pizza will reach the desired serving temperature of 140°F at approximately 10:44 P.M.
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Please answer with full solutions and only answer if you know!
Answer:
a) even
b) 4th differences: -72
c) minimum: 0, maximum: 4. This function has 0 real zeros.
d) -1377
e) -288
Step-by-step explanation:
You want to know a number of the characteristics of the function f(x) = -3x⁴ +6x² -10:
whether even or oddwhich finite differences are constantnumber of zerosAROC on [2, 7]IROC at x=3a) Even/OddA function is even if f(x) = f(-x). The graph of an even function is symmetrical about the y-axis. An even polynomial function will only have terms of even degree.
The exponents of the terms of f(x) are 4, 2, 0. These are all even, so we can conclude the function is an even function.
We can also evaluate f(-x):
f(-x) = -3(-x)⁴ +6(-x)² -10 = -3x⁴ +6x² -10 ≡ f(x) . . . . . the function is even
b) Finite differencesWe can look at values of x on either side of x=0. The attachment shows function values and finite differences for x = -3, -2, ..., +3.
The fourth finite differences are constant at -72. (We expect this value to be -3·4!, the leading coefficient times the degree of the polynomial, factorial.)
c) Number of zerosA 4th-degree polynomial will always have exactly four zeros. They may be complex, rather than real. Complex zeros will come in conjugate pairs, so the number of real zeros may be 0, 2, or 4; a minimum of 0 and a maximum of 4.
This polynomial function has no real zeros. The four complex zeros are approximately ...
±1.18864247 ±0.64255033i
d) AROC on [2, 7]The average rate of change on the interval [a, b] is given by ...
AROC = (f(b) -f(a))/(b -a)
For [a, b] = [2, 7], this is ...
AROC = (((-3(7²) +6)7² -10) -((-3(2²) +6)2² -10)/(7 -2)
= ((-147 +6)(49) -(-12 +6)(4)) / 5 = (-6909 +24)/5 = -6885/5 = -1377
The average rate of change on [2, 7] is = -1377.
e) IROC at x=3The derivative of the function is ...
f'(x) = -3(4x³) +6(2x) = 12x(-x² +1)
f'(3) = 12·3(-3² +1) = 36(-8) = -288
The instantaneous rate of change at x=3 is -288.
Kelly rolls two number cubes 50 times. After each roll, she records whether the number on
each cube is even (E) or odd (O). Her results are shown in the graph. Based on Kelly's results,
which is the most reasonable prediction for the number of times two odd numbers will occur
when two number cubes are rolled 2,000 times?
The most reasonable prediction for the number of times two odd numbers will occur when two number cubes are rolled 2,000 times is 480.
Option D is the correct answer.
What is a percentage?The percentage is calculated by dividing the required value by the total value and multiplying by 100.
Example:
Required percentage value = a
total value = b
Percentage = a/b x 100
Example:
50% = 50/100 = 1/2
25% = 25/100 = 1/4
20% = 20/100 = 1/5
10% = 10/100 = 1/10
We have,
Number of times the dice were rolled = 50
The number of times two odd numbers occur = 12
The percentage of two odd numbers occurs.
= 12/50 x 100
= 12 x 2
= 24%
Now,
Number of times the dice were rolled = 2000
The most reasonable prediction for the number of times two odd numbers will occur.
= 24% of 2000
= 24/100 x 2000
= 24 x 20
= 480
Thus,
The most reasonable prediction for the number of times two odd numbers will occur is 480.
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Random error is an error that?
Random error is an unpredictable deviation from the true value or expected outcome in a measurement or experiment.
Random error refers to the unpredictable and uncontrollable variations that occur when making measurements or conducting experiments. It is a type of error that introduces inconsistencies and fluctuations in the data, leading to discrepancies between the observed values and the actual values.
Random errors can arise from various sources, such as equipment limitations, environmental factors, or human factors like imprecise readings or variations in technique.
Unlike systematic errors, which are consistent and biased in a particular direction, random errors are characterized by their lack of pattern or regularity. They are typically caused by factors that are difficult to quantify or account for, making it challenging to eliminate them entirely.
However, by taking repeated measurements and applying statistical analysis techniques, researchers can mitigate the impact of random errors and obtain more reliable and accurate results.
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PLZ i NEED THE ANSWER !!!
Answer:
1. Given
2. Angle addition property
3. Angle addition property
4. Substitution property
5. Addition and subtraction property
Find the area of the surface generated when the given curve is revolved about the given axis. y=1/16(e^8x+e^−8x),
for
−3≤x≤3;
about the x-axis The surface area is
square units.
In this problem, the lower limit of integral is -3 and the upper limit of integration is 3.
We can use the formula for the surface area of a solid of revolution generated by a curve revolving around a given axis. The formula is S = 2π ∫ a b y dx, where a and b are the lower and upper limits of integration, and y is the height of the curve at x. In this problem, the lower limit of integration is -3 and the upper limit of integration is 3. Substituting y = 1/16(e^8x + e^-8x) into the equation gives S = 2π ∫ -3 3 (1/16(e^8x+e^-8x)) dx. Integral this expression gives S = 10512π.
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jiminy’s cricket farm issued a 30-year, 4.5 percent semiannual bond three years ago. the bond currently sells for 104 percent of its face value. the company’s tax rate is 22 percent.
a) Cost of debt, I = 4.25%(annual)
b) After tax cost of debt = 3.315%
c) After tax cost of debt of 3.135% is more relevant.
Given:
FV = 100
Semiannual bond issued 3 years ago
Maturity = 27
Price, PV = 104
coupon rate = 4.5%
Tax rate = 22%
a) Semiannual bond issued 3 years ago
Maturity, n = 27 years × 2 = 54
Coupon C = 4.5%/2×100 = 2.25
Now,
Pretax cost of debt,
Cost of debt, I = [C+(FV-PV)/n] / (FV+PV)/2
= [2.25 +(100 - 104)/54] / [ 100+1040/2
= 2.12%
= 2.12×2
Cost of debt, I = 4.25%(annual)
b) After tax cost of debt = cost of debt × (1-T)
= 4.25% × (1-22%)
After tax cost of debt = 3.315%
c) After tax cost of debt is more relevant.
Hence we get the required answer.
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A map Uses a scale of — centimeter = 75 kilometers.
50 kilometers
Answer:
Step-by-step explanation:
75
Given that \(sin(x)+cos(x)=\frac{2}{5}\), compute the following.
\(sin^4(x)+cos^4(x)\)
6. In a vegetable store, a customer paid $8.80
for 3 pounds of tomatoes and 5 pounds of
potatoes. A second customer paid $15.15
for 7 pounds of tomatoes and 6 pounds of
potatoes. What is the positive difference in the
price per pound of tomatoes and potatoes?
MTG unlimited has three employees in his account department..in the second week of October 2021the employees worked for the hours indicated below.Jane =58hours, Esther=45, Jessie=38.tje normal working.hours is 40hours.employees are paid q basic hourly rate of sh.200employee is alos entitled to overtime of 150% ofj basic hourly rate for the hours worked above the normal working hours.Required ,the wages paid to Jane, Esther and Jessie on the second week of October 2021.
The total wages paid to the three employees in the second week of October 2021 were sh. 24,200 for Jane, sh. 16,500 for Esther, and sh. 13,700 for Jessie.
In the second week of October 2021, Jane, Esther, and Jessie, who work in the account department of MTG Unlimited, worked for 58 hours, 45 hours, and 38 hours, respectively. The normal working hours are 40 hours per week, and the employees are paid a basic hourly rate of sh.200. They are also entitled to overtime pay of 150% of the basic hourly rate for the hours worked above the normal working hours. The normal working hours per week are 40 hours. Therefore, Jane worked for 18 hours over the normal working hours (58 - 40 = 18), Esther worked for 5 hours over the normal working hours (45 - 40 = 5), and Jessie worked for 2 hours over the normal working hours (38 - 40 = -2, which is not over the normal working hours, so we assume it to be 0). The basic hourly rate is sh.200. Therefore, the overtime pay rate is sh.300 (i.e., 150% of sh.200). To calculate the wages paid to each employee, we first calculate their basic pay, which is the product of their normal working hours and the basic hourly rate. For Jane, the basic pay is sh.8,000 (40 x sh.200), for Esther, it is sh.8,000, and for Jessie, it is sh.8,000. Next, we calculate their overtime pay, which is the product of the number of hours worked above the normal working hours and the overtime pay rate. For Jane, the overtime pay is sh.5,400 (18 x sh.300), for Esther, it is sh.750 (5 x sh.150), and for Jessie, it is sh.0. Finally, we add the basic pay and the overtime pay to get the total wages paid to each employee. For Jane, the total wages paid is sh.24,200 (sh.8,000 + sh.5,400 + sh.10,800), for Esther, it is sh.16,500 (sh.8,000 + sh.750 + sh.7,750), and for Jessie, it is sh.13,700 (sh.8,000 + sh.0 + sh.5,700).
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Zoey puts $1,560 into a saving account. The account pays 2.5% simple interest. How much interest will she earn in 3 years.
Answer:
$1,715 to fing out use a cosbnj vndbjerm c
Answer: $1,668
Step-by-step explanation: 2.5% of 1560 is 36. 36*3 is 108. 1560+108 is 1668.
What is the solution set for the inequality.
x ≤ 6
A
{6, 7, 8, 10}
B
{1, 3, 4, 5}
C
{-1, 0 , 2, 4, 6}
D
{0, 3, 5, 6, 8}
Answer:
b
Step-by-step explanation:
Find the last digit of 10
94
. Last digit = Solve the following congruences ensuring your answers are whole numbers less than the modulus m (so in 0,…,m−1 ). If there is more than one solution, enter the answer as a list separated by commas. For example: 0,1,3 a. x−3≡18(mod11) Answer: x= b. x
2
≡3(mod6) Answer: x=
In conclusion, the last digit of 10^94 is 1. For the congruences, x ≡ 10 (mod 11) and x can be either 3 or 5 (mod 6).
To find the last digit of 10^94, we can use modular arithmetic. The modulus m is 10 because we are looking for the last digit. We can rewrite 10^94 as (10^4)^23 since the last digit of 10^4 is always 0.
Now, (10^4)^23 ≡ 0^23 (mod 10). Any number raised to the power of 0 is 1.
Therefore, the last digit of 10^94 is 1.
As for the congruences:
a. x - 3 ≡ 18 (mod 11)
To solve this, we add 3 to both sides:
x ≡ 21 (mod 11)
x ≡ 10 (mod 11)
b. x^2 ≡ 3 (mod 6)
To solve this, we can try all numbers from 0 to 5 and see which ones satisfy the congruence:
0^2 ≡ 0 (mod 6)
1^2 ≡ 1 (mod 6)
2^2 ≡ 4 (mod 6)
3^2 ≡ 3 (mod 6)
4^2 ≡ 4 (mod 6)
5^2 ≡ 1 (mod 6)
From this, we can conclude that the possible values for x in this congruence are 3 and 5.
In conclusion, the last digit of 10^94 is 1. For the congruences, x ≡ 10 (mod 11) and x can be either 3 or 5 (mod 6).
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Suppose a normal distribution has a mean of 266 and a standard deviation of
12. What is P(x>278)?
Answer:
I think the answer is P(x>178)
Step-by-step explanation:
Answer: 0.16
Step-by-step explanation: Quizzed
which source of error is computed in the denominator of the test statistic for the between-subjects design, but not the within-subjects design?
The source of error is computed in the denominator of the test statistic for the between-subjects design, but not the within-subjects design is Option (c) between-groups.
The test statistic is a numerical value that measures the difference between groups, and it is typically derived from the data collected in the experiment. In a between-subjects design, the test statistic is computed by comparing the means of two or more groups of participants on a given variable. This means that the test statistic reflects the difference between groups, rather than within groups.
In contrast, in a within-subjects design, the test statistic is computed by comparing the scores of the same group of participants on a given variable, before and after some intervention or treatment. This means that the test statistic reflects the difference within groups, rather than between groups.
The Given question States, which source of error is computed in the denominator of the test statistic for the between-subjects design but not the within-subjects design? In a between-subjects design, the test statistic is typically computed using an analysis of variance (ANOVA), which involves partitioning the total variability in the data into two components: the variability between groups and the variability within groups. The denominator of the test statistic in a between-subjects ANOVA reflects the variability within groups, which is a measure of the random error in the data. This error arises from individual differences between participants that are not related to the experimental manipulation. By contrast, the variability between groups reflects the systematic effects of the experimental manipulation, and is used to estimate the effect size or the degree of association between the independent and dependent variables.
In a within-subjects design, the variability between groups is not relevant, because there is only one group of participants that is measured twice (or more) on the same variable. Instead, the denominator of the test statistic in a within-subjects design reflects the variability within subjects, which is a measure of the random error in the data. This error arises from factors such as measurement error, natural variability in the participants' responses, and other sources of noise that are not related to the experimental manipulation.
The source of error computed in the denominator of the test statistic depends on the type of experimental design used. In a between-subjects design, the denominator reflects the variability within groups, while in a within-subjects design, it reflects the variability within subjects. The choice of design depends on the research question, the nature of the variables being measured, and other practical considerations.
Therefore, the source of error is computed in the denominator of the test statistic for the between-subjects design, but not the within-subjects design is Option (c) between-groups.
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Complete Question
Which source of error is computed in the denominator of the test statistic for the between-subjects design, but not the within-subjects design?
a. Between-persons
b. Within-groups
c. Between-groups
d. Within-persons
A car traveled 1010 miles at an average speed of 3030 miles per hour
and then traveled the next 1010 miles at an average speed of 5050 miles
per hour. What was the average speed, in miles per hour, of the car for the
2020 miles?
The average speed, in miles per hour, of the car for the 20 miles is 37.5 mph
Average speedAverage speed v = d/t where
d = total distance and t = total timeMaking t subject of the formula, we have
t = d/v
Time to cover first 10 milesNow when the car travels 10 miles at an average speed of 30 miles per hour,
d = 10 mi and v = 30 mph.So, t = d/v
= 10/30
= 1/3 h
Time to cover next 10 miles
Also, when the car travels the next 10 miles at an average speed of 50 miles per hour,
d' = 10 mi and v' = 50 mph.So, t' = d'/v'
= 10/50
= 1/5 h
Time to cover 20 miles
The total time for the 20 miles is T = t + t'
= 1/3 h + 1/5 h
= (5 + 3)/15 h
= 8/15 h
Average speed for 20 miles
So, the average speed for the 20 miles is v = D/T where
D = 20 miles and T = 8/15 h.So, v = D/T
v = 20 mi ÷ 8/15 h
v = 20 × 15 mi/8 h
v = 2.5 × 15 mi/h
v = 37.5 mph
So, the average speed, in miles per hour, of the car for the 20 miles is 37.5 mph
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How many triangles can a heptagon be divided into? 3 5 4 6
Answer:
5 triangles.
Step-by-step explanation:
Answer:
5 or 4
Step-by-step explanation:
Use linear approximation to estimate cos(0.75) at x_0 = π/4 to 5 decimal places.
To find the approximation of the value of `cos(0.75)` at `x₀ = π/4`,
using linear approximation, we will use the formula;
`L(x) ≈ f(x₀) + f'(x₀)(x - x₀)`Given,`x₀ = π/4` and `f(x) = cos x`, and
therefore, `f'(x) = -sin x`.
So, `f'(x₀) = -sin (π/4) = -1/√2`.
Now, applying the formula,
`L(x) = f(π/4) + f'(π/4)(0.75 - π/4)`
`=> L(x) = cos(π/4) + [-1/√2] (0.75 - π/4)`
`=> L(x) = [√2 / 2] - [-1/√2] [1/4]`
`=> L(x) = [√2 / 2] + [1/4√2]`
`=> L(x) = [2 + √2] / 4√2`
Thus, the linear approximation of `cos 0.75` at `x₀ = π/4` is `[2 + √2] / 4√2`
which, to 5 decimal places, is approximately `0.73135`.
Hence, the required estimate is `0.73135`.
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