On January 2, 2021, Twilight Hospital purchased a $100,000 special radiology scanner from Bella Inc. The scanner had a useful life of 4 years and was estimated to have no disposal value at the end of its useful life. The straight-line method of depreciation is used on this scanner. Annual operating costs with this scanner are $105,000. Use incremental analysis for retaining or replacing equipment decision. Approximately one year later, the hospital is approached by Dyno Technology salesperson, Jacob Cullen, who indicated that purchasing the scanner in 2021 from Bella Inc. Was a mistake. He points out that Dyno has a scanner that will save Twilight Hospital $25,000 a year in operating expenses over its 3-year useful life. Jacob notes that the new scanner will cost $110,000 and has the same capabilities as the scanner purchased last year. The hospital agrees that both scanners are of equal quality. The new scanner will have no disposal value. Jacob agrees to buy the old scanner from Twilight Hospital for $50,000. Instructions a. If Twilight Hospital sells its old scanner on January 2, 2022, compute the gain or loss on the sale. B. Using incremental analysis, determine if Twilight Hospital should purchase the new scanner on January 2, 2022. C. Explain why Twilight Hospital might be reluctant to purchase the new scanner, regardless of the results indicated by the incremental analysis in (b)

Answer:

0.875

Step-by-step explanation:

7/8 = 0.875

Answer:

0.875

Step-by-step explanation:

Try to make the denominator to power of 10

8 *125 = 1000

So, multiply both numerator and denominator by 125

\(\frac{7}{8}=\frac{7*125}{8*125}=\frac{875}{1000}=0.875\)

Answer:

x = 81/4

Step-by-step explanation:

multiply both sides by 4

4x + 15 = 96

subtract 15 from both sides

4x = 81

divide both sides by 4

x= 81/4

i hope that's right

Answer:

81/4

Step-by-step explanation:

Answer:

Your answer is A

Step-by-step explanation:

The reason is because 1/10 is 3 muffins so if it was 7/10 it would be 21 8/10 is 24 and 9/10 is 27 and 10/10 is 30 muffins

Answer: The answer is 30

Step-by-step explanation:

You do 21 x 10 and the answer is on top of 7: 120/7

Then do 120 divided by seven and there is your answer.

Tyler purchased 12 Iiters for $7.58

His PER liter cost is:

7.58/12 = 0.6316

The max he wants to pay is 0.62, which is definitely less than what he paid for.

He paid around 0.63 but his max is 0.62

So,

He did not stay under.

Answer:

64

Step-by-step explanation:

Given :

h α 1 / sqrtk

h = k/sqrt(d)

Obtain the value of k, when. d = 4 and h = 20

20 = k / sqrt(4)

20 = k / 2

20 * 2 = k

k = 40

Therefore, the value of d when h = 5

h = k/sqrt(d)

5 = 40 / sqrt(d)

Square both sides

25 = 1600/d

25d = 1600

d = 1600 / 25

d = 64

d = 64

The function that represent the balance A in the account after t years is f(t) = 13000( 1.013 )^( 2t ).

This question is incomplete, the complete question is:

Rawan deposits $13,000 into an account that pays 2.6% annual interest compounded every 6 months.

Write a function to represent the balance A in the account after t years.

The formula accrued amount in a compounded interest is expressed as;

A = P( 1 + r/n )^( n × t )

Where A is accrued amount, P is principal, r is interest rate and t is time.

Given that;

First, convert R as a percent to r as a decimal

r = R/100

r = 2.6/100

r = 0.026

Given that time = t.

A = P( 1 + r/n )^( n × t )

f(t) = 13000( 1 + 0.026/2 )^( 2 × t )

f(t) = 13000( 1 + 0.026/2 )^( 2t )

f(t) = 13000( 1 + 0.013 )^( 2t )

f(t) = 13000( 1.013 )^( 2t )

Therefore, the accrued amount after t years is f(t) = 13000( 1.013 )^( 2t ).

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In this manner, ready to conclude that an < am for all positive integers n and a few positive numbers k.

To appear that an < am, we got to compare the values of the arrangements an and am for all positive integers n and a few positive numbers k.

Given:

an = 2n + 1

am = n + k*o(n)

where o(n) signifies the arrange of n, speaking to the number of digits in n.

Let's compare an and am by substituting the expressions for an and am:

an = 2n + 1

am = n + k*o(n)

We want to appear that an < am, so we got to demonstrate that 2n + 1 < n + k*o(n) holds for all positive integers n and a few positive numbers k.

Let's simplify the inequality:

2n + 1 < n + k*o(n)

Modifying the terms:

n < k*o(n) - 1

Presently, we ought to consider the behavior of the arrange work o(n). The arrange work o(n) counts the number of digits in n. For any positive numbers n, o(n) will be greater than or break even with to 1.

Since o(n) ≥ 1, able to conclude that k*o(n) ≥ k.

Substituting this imbalance back into the first disparity, we have:

n < k*o(n) - 1 ≤ k - 1

Since n could be a positive numbers, and k may be a positive numbers, we have n < k - 1, which holds for all positive integers n and a few positive numbers k.

In this manner, ready to conclude that an < am for all positive integers n and a few positive numbers k.

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The solution is an < m.

Here is a more detailed explanation of the solution:

The first step is to show that ko(n) is always greater than or equal to 0. This is true because k is a positive integer, and the order of operations dictates that multiplication is performed before addition.

Therefore, ko(n) = k * o(n) = k * (n + 1), which is always greater than or equal to 0.

The second step is to show that m = n + ko(n) is always greater than or equal to n.

This is true because ko(n) is always greater than or equal to 0, so m = n + ko(n) = n + (k * (n + 1)) = n + k * n + k = (1 + k) * n + k.

Since k is a positive integer, (1 + k) is always greater than 1, so (1 + k) * n + k is always greater than n.

The third step is to show that an = 2n + 1 is always less than m.

This is true because m = (1 + k) * n + k is always greater than n, and an = 2n + 1 is always less than n.

Therefore, an < m.

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========================================================

Explanation:

For any parallelogram, the diagonals cut each other in half. Formally this is known as bisection.

What this means is that the pieces AE and CE are the same length.

AE = CE

6x-8 = 2x+24

6x-2x = 24+8

4x = 32

x = 32/4

x = 8

Then we can calculate the length of each piece mention

Both pieces are 40 units long to confirm we have the correct x value.

Therefore,

AC = AE + CE = 40+40 = 80

The portion of the parabola from t=-1 to t=1 can be parametrized as x=2t²-4 and y=t.

A parabola is a symmetrical and U-shaped curve that is defined by a mathematical equation.

In this case, we will use the variable t to represent the y-coordinate and find the corresponding x-coordinate. The equation becomes y=t, and substituting this into the original equation, we get

=> x=2t²-4.

To find the portion of the parabola where -1≤t≤1, we can plot the points (x, y) for various values of t in this range.

when t=-1,

=> x=2(-1)²-4 = 0.

And when

t=1, x=2(1)²-4 = -2.

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Answer:

<

Step-by-step explanation:

4th grade math?

4/8 = 1/2 as they are both equivalents to 0.5

3/8 is less than 4/8, there for less than 1/2 (which is the same as 4/8)

The kind of triangle in the image above is a scalene triangle.

A scalene triangle is a type of triangle that has three sides with different lengths. It is one of the three main types of triangles, the other two being isosceles and equilateral triangles. They also have three different angles.

Scalene triangles do not have any congruent sides or angles, making them the most diverse and versatile type of triangle. They can be used to construct many different shapes and figures, and have many unique properties and characteristics that make them useful in a variety of fields, including mathematics, physics, and engineering.

In the image given, the three sides of the triangle appears to be of different sizes.

Therefore, we can conclude that the triangle is a scalene triangle.

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The z-scores will remain the same regardless of whether you use inches or centimetres for the height measurements.

The z-scores will not change if you convert the height measurements from inches to centimetres or vice versa. The z-score is a standard score representing the number of standard deviations, a value above or below the mean of a normal distribution.

The z-score is calculated using the formula z = (x - mean)/standard deviation, where x is the value being compared to the mean and standard deviation of the distribution.

Converting the height from inches to centimetres or vice versa will only change the units of measurement, but the relative position of a value within the distribution will remain unchanged.

Therefore, the z-scores will remain the same regardless of whether you use inches or centimetres for the height measurements.

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Answer:

\(x=2587th °\sqrt{f(12.600)} =1.00098\)

Step-by-step explanation:

\(569993885.5908653x^{2} 587 \: \\ \div 45086001.0000256 \\ = 569993885.6 \: {x}^{2} 587\div 45086001.0 \\ 12.64236953727610 = {x}^{2} 587\)

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "12.6" was replaced by "(126/10)".

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

(126/10)-(x^2587)=0

Step by step solution :

STEP

1

:

63

Simplify ——

5

Equation at the end of step

1

:

63

—— - x2587 = 0

5

STEP

2

:

Rewriting the whole as an Equivalent Fraction

2.1 Subtracting a whole from a fraction

Rewrite the whole as a fraction using 5 as the denominator :

x2587 x2587 • 5

x2587 = ————— = —————————

1 5

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2 Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

63 - (x2587 • 5) 63 - 5x2587

———————————————— = ———————————

5 5

Equation at the end of step

2

:

63 - 5x2587

——————————— = 0

5

STEP

3

:

When a fraction equals zero :

3.1 When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

63-5x2587

————————— • 5 = 0 • 5

5

Now, on the left hand side, the 5 cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

63-5x2587 = 0

Solving a Single Variable Equation:

3.2 Solve : -5x2587+63 = 0

Subtract 63 from both sides of the equation :

-5x2587 = -63

Multiply both sides of the equation by (-1) : 5x2587 = 63

Divide both sides of the equation by 5:

x2587 = 63/5 = 12.600

x = 2587th root of (63/5)

The equation has one real solution

This solution is x = 2587th root of (12.600) = 1.00098

One solution was found :

x = 2587th root of (12.600) = 1.00098

Answer:

B

Step-by-step explanation:

I got it right on the assignment

Hope this helps :)

Answer:

B. A web diagram shows what connects these different types of doctors.

Step-by-step explanation:

Answer:

95 degrees

Step-by-step explanation:

vertical opposite angles

There are FOUR  4's in a deck of 52  

   4/52 = 1/13 chance

Second card less than 5 ?

    4 aces    4  two's  4 threes and 4  fours

      16/ out of 52 = 16/52 chance = 4/13 chance

1/13 * 4/13 = 4/169  chance of picking as questioned

Discrete random variables can only take on certain values (like whole numbers). They cannot take on any value within a given range, but only certain fixed values, separated by some space.

The random variable described is continuous. The exam score is continuous and can take any value within a given range. Hence it cannot take up any exact value, instead it takes up a value between two values and the probability of that value is zero.Here is a brief explanation:Discrete Random Variables: Discrete random variables can only take on certain values (like whole numbers). They cannot take on any value within a given range, but only certain fixed values, separated by some space.Continuous Random Variables: Continuous random variables can take on any value (within a given range) and the probability of that value is zero. Their probability distributions are represented by continuous graphs like normal distribution, exponential distribution, etc. They are represented using intervals of numbers rather than specific numbers.For instance, the number of rainy days in a month can be measured using a discrete random variable since the number of days can only be a whole number (such as 0, 1, 2, 3, ...). So, if we use a continuous random variable to measure the height of students in a class, it can be any number between a given range, like 155 cm or 155.1 cm, or 155.2 cm, etc. And, it’s very rare to have the same height of two students, hence it’s a continuous random variable.

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Using a standard normal distribution table, we find the area under the curve between -5 and 5 for our normal distribution with a mean of 0 and a standard deviation of 2.5 to be approximately 0.9545.

The area under the curve of a normal distribution represents the probability of obtaining a random sample from the distribution within a certain range of values.

In this case, we are interested in finding the area under the curve between -5 and 5 for a normal distribution with a mean of 0 and a standard deviation of 2.5.

To solve this problem, we can use the standard normal distribution table to calculate the area under the curve. The standard normal distribution is a normal distribution with a mean of 0 and a standard deviation of 1.

To transform our normal distribution with a mean of 0 and a standard deviation of 2.5 into a standard normal distribution, we can use the formula:

z = (x - μ) / σ

where z is the standard score, x is the value of the variable, μ is the mean of the distribution, and σ is the standard deviation of the distribution.

In our case, we can transform the values of -5 and 5 as follows:

z1 = (-5 - 0) / 2.5 = -2

z2 = (5 - 0) / 2.5 = 2

We can then use a standard normal distribution table to find the area under the curve between -2 and 2, which corresponds to the area under the curve between -5 and 5 for our original normal distribution.

Using a standard normal distribution table, we can find that the area under the curve between -2 and 2 is approximately 0.9545.

Therefore, the area under the curve between -5 and 5 for our normal distribution with a mean of 0 and a standard deviation of 2.5 is approximately 0.9545.

This means that there is a 95.45% probability of obtaining a random sample from the distribution within the range of -5 and 5.

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The time complexity of finding a source in a directed graph or determining such a source does not exist if the graph is represented by its adjacency matrix is V².

If a directed graph is represented by an adjacency matrix, the following approach may be used to either discover a source inside the network or establish that there isn't one:

This approach has an O(V²) time complexity, where V is the number of graph vertices. This is due to the fact that it takes O(V²) time to traverse the whole adjacency matrix in order to determine each vertex's in-degree. The next step requires traversing the inDegree array in O(V) time in order to discover a vertex with in-degree 0. In the worst scenario, it takes O(V²) time to determine if there is a path connecting this vertex to every other vertex.

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Answer:

If you comment fractions I will do them!

Step-by-step explanation:

Across:

A = 46

E = can't see the fraction

H = 2111

I = 64

J = 29

L = can't see the fraction

P = 55005

R = can't see the fraction

S = 21

T = 49

U = 308

V =129

X = can't see the fraction

Y = 4008

Z = 15

BB = 375

EE = 65

FF = 16

GG = 64

Down:

B = 600

C = can't see the fraction

D = 316

G = can't see the fraction

H = can't see the fraction

K = 9520

L = 15010

N = 299

O = 59

Q = 518

T = 4116

U = 333

V = 1006

W = 189

AA = 55

CC = 71

DD = 56

Answer- 9 shelves

In order to find out how many shelves are need we must divided 175 into 20. 175 divided by 20 is 8.75. But, because you cannot have have .75 of a shelf, you have to round this to a whole. This means that 9 shelves will be the least needed number of shelves need to store 175 books. To check this answer 20 books X 8 shelves is 160 books, which means eight shelves can only store 160 books, we will need and additional shelf to store the last 15 books.

HOPE THIS HELPS & GOOD LUCK!

The length of the base of the parallelogram is 16 inches.

What is parallelogram?

A parallelogram is a four-sided plane figure with opposite sides parallel and congruent (having the same length). This means that the opposite sides of a parallelogram are parallel to each other and have the same length. Additionally, the opposite angles of a parallelogram are equal in measure, which means they have the same degree of rotation.

Let's use the information given in the problem to set up an equation and solve for the length of the base.

From the problem, we know that the height of the parallelogram is 5 inches.

h = 5

We also know that the base of the parallelogram is six more than twice the height. Let's use b to represent the length of the base:

b = 2h + 6

Now we can substitute the value we know for the height and solve for the base:

b = 2(5) + 6

b = 10 + 6

b = 16

Therefore, the length of the base of the parallelogram is 16 inches.

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The correct answer is D) -1.

To find the values of x where the tangent line to the graph of the function \(y = x^2 + 2x - 3\)is horizontal, we need to find the points where the derivative of the function is equal to zero.

First, let's find the derivative of the function:

\(y = x^2 + 2x - 3\)i

y' = 2x + 2

Setting y' equal to zero and solving for x:

2x + 2 = 0

2x = -2

x = -1

Therefore, the only value of x where the tangent line to the graph of the function is horizontal is x = -1.

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Answer:

Circumference is pi times diameter so that would equal 15 pi. The formula to find the area of a circle is A=pi * r^2 So you divide 15 by 2 to find the radius. r=7.5 Then you square it and multiply it by pi and get 56.25pi which is about equal to 176.715

The ratio of bream to tench to carp is given by the expression; 12 : 7 : 21

A ratio is a relationship between two or more items, that quantitatively expresses the number of times a unit item can be found within the quantity of each item in the set of items.

The given parameters are;

Number of fish in the pond = 40

The number of fish in the pond that are bream = 12

The number of fish that are tench = 1/4 of the fish that are not bream

The number of the fish that are carp = The rest of the fish that are not bream or carp

Required;

The ratio of bream to tench to carp of the fish in the pond.

Solution;

The number of fish that are either tench or carp = 40 - 12 = 28

The number of the fish that are tench = (1/4) × 28 = 7

Therefore;

The number of fish that are carp = 28 - 7 = 21

Which gives;

Number of bream in the pond = 12

Number of tench in the pond = 7

Number of carp in the pond = 21

The ratio of the number of bream to tench to carp in the pond is given by the expression;

\(\displaystyle{ \frac{12}{40}:\frac{7}{40}:\frac{21}{40}}\)

Given that the expression for the ratio cannot be simplified further, we have;

The ratio of bream to tench to pond is 12 : 7 : 21

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The approximate value of P(-0.78 ≤ z ≤ 1.16) for a standard normal distribution is approximately 0.6610 or 66.1%.

To find the approximate value of P(-0.78 ≤ z ≤ 1.16) for a standard normal distribution, we need to use the given portion of the standard normal table.

From the table, we can see that P(z ≤ -0.78) is approximately 0.216, and P(z ≤ 1.16) is approximately 0.8770.

To find the desired probability P(-0.78 ≤ z ≤ 1.16), we subtract the smaller probability from the larger one:

P(-0.78 ≤ z ≤ 1.16) = P(z ≤ 1.16) - P(z ≤ -0.78)

≈ 0.8770 - 0.216

≈ 0.6610

Therefore, the approximate value of P(-0.78 ≤ z ≤ 1.16) for a standard normal distribution is approximately 0.6610 or 66.1%.

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