or the following reaction, the change in free energy, delta G degree, is 4.73 kJ/mol at 25 degree C. Determine the equilibrium constant. N_O_4 (g) 2NO_2(g) a) -1.91 b) 6.74 c) 1.91 d) 0.148

280.53 L is the final volume in liters.

Applying the ideal gas equation for O₂

    PV = nRT  

where P is pressure, V is volume, n is the number of moles of gas, R is gas constant and T is temperature

As n and T are not changing

So,  

    P₁V₁ = P₂V₂  ⇒equation 1

now from the question we have,

Given data;

    P₁ = 20.8 atm, P₂= 2.70 atm

    V₁ = 26.3 L

now we have to find the volume of a gas when pressure is changed.

V₂ = ?  

Put values in equation 1

    20.8 × 26.3 = 2.70 × ?

     V₂ = 20.8 × 26.3 / 2.70

     V₂ = 280.53 L  

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Answer: electrons have a wave like character and can be solved with wave equations

Explanation: it’s the answer

Schrödinger's solution to the wave equation agreed with the Rydberg constant, proving electrons have a wave-like character and can be solved with wave equations. The correct option is C.

Schrödinger's solution tells the position of an electron is space and time. It also tells the energy and position of electrons. It describes the wave nature of the electron.

Rydberg constant is the unit of energy. Its symbol is Ry. It is equivalent to the photon's energy, whose wave number is the Rydberg constant. It is a physical constant.

Either the exponential or the trig functions must be chosen; not both. Particles are traveling left and right in the sin and cos solutions, which represent states of definite energy.

Thus, the correct option is C. Electrons have a wave-like character and can be solved with wave equations regarding Schrödinger's solution.

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The air pressure of 112 psi in the inner tube of a racing bike tire is approximately 7.62 atm by using the conversion formula: 1 atm = 14.696 psi

To convert the pressure from psi (pounds per square inch) to atm (atmospheres), we can use the following conversion formula:
1 atm = 14.696 psi
To convert 112 psi to atm, we need to divide the given pressure (112 psi) by the conversion factor (14.696 psi/atm):
112 psi / 14.696 psi/atm = 7.62 atm (approximately)
So, the air pressure in the inner tube of a tire on a typical racing bike when held at a pressure of about 112 psi is approximately 7.62 atm. Therefore, the correct option is B) 7.62 atm.

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Answer:

B

Explanation:

Hypoesthesia reduces physical sensation, especially that of skin.

To solve this we must be knowing each and every concept related to hypesthesia. Therefore, the correct option is option B among all the given options.

Hypoesthesia is caused mostly by nerve injury and blood vessel blockages, which cause ischemia damage to tissues fed by the stopped blood vessels. This damage can be detected using several imaging investigations.

The most common causes of hypoesthesia are nerve blood and injury channel blockages, which induce ischemic damage to tissues nourished by the blocked blood arteries. Several imaging examinations can be used to discover this injury. Hypoesthesia diminishes physical experience, particularly cutaneous sensation.

Therefore, the correct option is option B.

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Answer:

The increase in mass is not due to the heating but due to the reaction of the metal with oxygen in air to form an oxide

Explanation:

When a metal is heated in the presence of air, oxygen present in air reacts with the metal to form the oxide of the metal. The mass of this oxide is greater than the original metal by the amount of oxygen added to the metal during the reaction.

The above reaction is known as an oxidation reaction. Generally,

metal M + O2 ---> MO2

Answer:

It was the fifth radioactive element discovered, and is typically a colorless gas that puts off an insane glow when frozen.

DNA contains deoxyribonucleotide triphosphates joined together by phosphodiester-covelent bonds.

The full form of DNA is deoxyribonucleic acid and this is the only one responsible for the heredity transfer from the parent to the offspring as it contains the genetic codes and some characteristics of the parent.

The DNA is bonded by nitrogen base pairs and the phosphodiester-covalent bonds are the backbone of the NDA.

Therefore, DNA contains deoxyribonucleotide triphosphates joined together by phosphodiester-covalent bonds.

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Answer:

If a compound is made from a metal and a non-metal, its bonding will be ionic. If a compound is made from two non-metals, its bonding will be covalent.

Explanation:

Cu(OH)2 → CuO + H₂O

FW CuO 79.545 g

g CuO = 0.75 mol x 79.545 g/mol = 59.659 g

"The percent by mass of Cl in manganese(IV) perchlorate is approximately 31.33%." Percent by mass, also known as mass percent or weight percent, is a way to express the concentration or composition of a component in a mixture or compound. It represents the ratio of the mass of the component to the total mass of the mixture or compound, expressed as a percentage.

The formula for percent by mass is:

Percent by mass = (Mass of component / Total mass of mixture or compound) × 100

In this formula, the mass of the component refers to the amount of the specific substance, and the total mass of the mixture or compound includes the masses of all the components combined.

To find the percent by mass of Cl in manganese(IV) perchlorate (Mn(ClO₄)₄), we need to calculate the mass of Cl in the compound and divide it by the total mass of the compound, then multiply by 100.

The molar mass of manganese(IV) perchlorate (Mn(ClO₄)₄) is given as 452.74 g/mol.

First, let's calculate the molar mass of Cl in the compound:

Molar mass of Cl = 35.45 g/mol (molar mass of Cl)

Next, we can calculate the mass of Cl in the compound:

Mass of Cl = Molar mass of Cl × Number of Cl atoms in the compound

= 35.45 g/mol × 4

Now, let's calculate the percent by mass of Cl:

Percent by mass of Cl = (Mass of Cl ÷ Total mass of the compound) × 100

= (35.45 g/mol × 4 ÷ 452.74 g/mol) × 100

Calculating this expression:

Percent by mass of Cl = (141.8 g ÷ 452.74 g) × 100

= 31.33%

Therefore, the percent by mass of Cl in manganese(IV) perchlorate is approximately 31.33%.

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From what we know we can confirm that currently, the primary source of sulfur dioxide of emissions into the atmosphere is coal and other fossil fuel burning in industry.

From what we know, this compound has proved to be quite toxic for humans to breathe. Increased concentrations of this in the atmosphere lead to increased rates of lung disease among other health complications.

Therefore, we can confirm that the primary source of sulfur dioxide of emissions into the atmosphere is coal and other fossil fuel burning in industry.

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Answer:

the periodic table is the table of contents of the elements

Answer:

1) k2O = 2K(1+) + O(2-)This is, every molecule of K2O

Explanation:

hope this helps if not let me know have a blessed day

Answer:

At -20°C the mercury state will be liquid

Explanation:

The melting point of a substance is the temperature at which it changes from solid state to a liquid state, and the boiling point is the temperature at which it changes from liquid state to a gaseous state.

If mercury melts at -39°C and boils at 356.9°C, it means that if the temperature is lower than -39°C, mercury will remain al solid state. Between -39°C and 356.9°C, the state of mercury will be liquid and, above 356.9°C mercury will remain at gaseous state.

So, at -20°C the mercury state will be liquid, because that temperature it is between -39°C and 356.9°C.

Answer:

The tectonic style and viability of modern plate tectonics in the early Earth is still debated. Field observations and theoretical arguments both in favor and against the uniformitarian view of plate tectonics back until the Archean continue to accumulate. Here, we present the first numerical modeling results that address for a hotter Earth the viability of subduction, one of the main requirements for plate tectonics. A hotter mantle has mainly two effects: 1) viscosity is lower, and 2) more melt is produced, which in a plate tectonic setting will lead to a thicker oceanic crust and harzburgite layer. Although compositional buoyancy resulting from these thick crust and harzburgite might be a serious limitation for subduction initiation, our modeling results show that eclogitization significantly relaxes this limitation for a developed, ongoing subduction process. Furthermore, the lower viscosity leads to more frequent slab breakoff, and sometimes to crustal separation from the mantle lithosphere. Unlike earlier propositions, not compositional buoyancy considerations, but this lithospheric weakness could be the principle limitation to the viability of plate tectonics in a hotter Earth. These results suggest a new explanation for the absence of ultrahigh-pressure metamorphism (UHPM) and blueschists in most of the Precambrian: early slabs were not too buoyant, but too weak to provide a mechanism for UHPM and exhumation.

Explanation:

An Endothermic reaction releases energy/heat, whereas an Exothermic reaction requires energy/heat.

An endothermic reaction is a chemical reaction that requires the absorption of energy in the form of heat to proceed. In other words, this reaction absorbs heat energy from its surroundings during the reaction. This causes the temperature of the reaction to drop because heat energy is used to break the bonds of the reactants. The chemical reaction, on the other hand, is endothermic since it requires the absorption of heat energy.

An exothermic reaction is a chemical reaction that releases energy in the form of heat. In other words, this reaction releases heat energy to its surroundings during the reaction. This causes the temperature of the reaction to rise since the heat energy produced is used to form the bonds between the products. The chemical reaction, on the other hand, is exothermic since it releases heat energy.

Thus, an endothermic reaction requires energy/heat, whereas an exothermic reaction releases energy/heat.

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Given the activity series of elements, the reaction that will occur is: 2AgNO3 + Ni -----> Ni(NO3)2 + 2Ag

The activity series of elements can also be called the "reactivity series" of elements because it actually arrangement of elements in order of decreasing reactivity. The most reactive elements are higher up in the series while the less reactive elements are found at the bottom of the series.

Given the fact that nickel is far higher in the series than silver, nickel can displace silver from an aqueous solution of its salt. Hence the equation; 2AgNO3 + Ni -----> Ni(NO3)2 + 2Ag is possible.

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Answer:

Option (C) = 2AgNO3 + Ni Right arrow. Ni(NO3)2 + 2Ag

Explanation:

EDG22, pls tell me if im wrong!

Answer:

La velocidad inicial es 55 \(\frac{m}{s}\)y su aceleración es -10 \(\frac{m}{s^{2} }\)

Explanation:

Un movimiento es rectilíneo uniformemente variado, cuando la trayectoria del móvil es una línea recta y su velocidad  varia la misma cantidad en cada unidad de tiempo . Dicho de otra manera, este movimiento se caracteriza por una trayectoria que es una línea recta y la velocidad cambia su módulo de manera uniforme: aumenta o disminuye en la misma cantidad por cada unidad de tiempo. Y la aceleración es constante y no nula (diferente de cero).

En este caso la posición del objeto esta dada por la expresión:

\(x=x0+v0*t+\frac{1}{2} *a*t^{2}\)

donde x es la posición del cuerpo en un instante dado, x0 la posición en el instante inicial, v0 la velocidad inicial y a la aceleración.

En este caso, por un lado podes considerar:

Reemplazando obtenes:

\(90=v0*2+\frac{1}{2} *a*2^{2}\)

\(90=v0*2+\frac{1}{2} *a*4\)

\(90=v0*2+2*a\)

Y por otro lado tenes:

Reemplazando obtenes:

\(120=v0*3+\frac{1}{2} *a*3^{2}\)

\(120=v0*3+\frac{1}{2} *a*9\)

\(120=v0*3+\frac{9}{2} *a\)

Por lo que tenes el siguiente sistema de ecuaciones:

\(\left \{ {{2*v0+2*a=90} \atop {3*v0+\frac{9}{2} *a=120}} \right.\)

Resolviendo por el método de sustitución, que consiste en aislar en una ecuación una de las dos incógnitas para sustituirla en la otra ecuación, obtenes:

Despejando v0 de la primera ecuación:

\(v0= \frac{90-2*a}{2}\)

Reemplazando en la segunda ecuación:

\(120=\frac{90-2*a}{2} *3+\frac{9}{2} *a\)

Resolviendo:

\(120=(90-2*a)*\frac{3}{2} +\frac{9}{2} *a\)

\(120=135-3*a +\frac{9}{2} *a\)

\(120-135=-3*a +\frac{9}{2} *a\)

\(-15=\frac{3}{2} *a\)

\(\frac{-15}{\frac{3}{2} } =a\)

-10=a

Reemplazando el valor de a en la expresión despejada anteriormente obtenes:

\(v0= \frac{90-2*(-10)}{2}\)

Resolviendo:

\(v0= \frac{90+20}{2}\)

\(v0= \frac{110}{2}\)

v0=55

La velocidad inicial es 55 \(\frac{m}{s}\)y su aceleración es -10 \(\frac{m}{s^{2} }\)

The products for the balanced reaction of hydrochloric acid (HCL) and magnesium hydroxide (mg(oh)2) are salt (magnesium chloride ) and water.

The balanced equation is:

\(Mg(OH) _{2}+2HCl - MgCl_{2}+2H_{2} O\)

What happens when magnesium hydroxide reacts with HCl?

Does magnesium hydroxide dissolve in HCl?

Magnesium Hydroxide is soluble in dilute hydrochloric acid.

Thus, products obtained from the reaction are salt and water.

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The number of moles of sodium (Na) in 3.4 x 10^23 atoms is approximately 5.64 moles.

In the first paragraph, the main answer is that there are approximately 5.64 moles of sodium (Na) in 3.4 x 10^23 atoms.

Now, let's explain the calculation in the second paragraph. The mole is a unit of measurement used in chemistry to quantify the amount of a substance. One mole of any element contains Avogadro's number of atoms, which is approximately 6.022 x 10^23. In this case, we have 3.4 x 10^23 atoms of sodium (Na). To convert this into moles, we divide the number of atoms by Avogadro's number.

Mathematically, the calculation is as follows:

Moles of Na = (Number of atoms of Na) / (Avogadro's number)

Moles of Na = (3.4 x 10^23) / (6.022 x 10^23)

Moles of Na ≈ 5.64 moles

Therefore, there are approximately 5.64 moles of sodium (Na) in 3.4 x 10^23 atoms.

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To calculate the standard free energy change (ΔG°) for the reaction CH4(g) + H2O(g) → 3H2(g) + CO(g) at 298.15 K and a pressure of 16.00 mm Hg for each gas, we need to use the following equation:

ΔG° = ΣnΔGf°(products) - ΣnΔGf°(reactants)

where ΔGf° is the standard molar free energy of formation, n is the stoichiometric coefficient of the reactant or product in the balanced chemical equation.

Using the standard thermodynamic data from the tables linked above, we have:

ΔGf°(CH4,g) = -50.8 kJ/mol
ΔGf°(H2O,g) = -228.6 kJ/mol
ΔGf°(H2,g) = 0 kJ/mol
ΔGf°(CO,g) = -137.2 kJ/mol

Substituting these values into the equation above, we get:

ΔG° = (3 mol x 0 kJ/mol) + (-137.2 kJ/mol) - [(1 mol x (-50.8 kJ/mol)) + (1 mol x (-228.6 kJ/mol))]
ΔG° = -137.2 kJ/mol + 279.4 kJ/mol
ΔG° = 142.2 kJ/mol

To convert kJ/mol to J/molecule, we need to multiply by 1000 and divide by Avogadro's number:

ΔG° = (142.2 kJ/mol x 1000 J/kJ) / 6.022 x 10^23 molecules/mol
ΔG° = -2.36 x 10^-19 J/molecule

Therefore, the standard free energy change for the reaction at 298.15 K and a pressure of 16.00 mm Hg for each gas is -2.36 x 10^-19 J/molecule.

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The percent by mass of barium in the original unknown compound is 68.25%.

When barium ions in a solution are treated with an excess of sodium sulfate, a white precipitate of barium sulfate (BaSO₄) is formed. The balanced chemical equation for the reaction will be:

Ba₂⁺(aq) + SO₄²⁻(aq) → BaSO₄(s)

From the given information, we can calculate the amount of barium present in the unknown compound as follows:

Calculate the moles of BaSO₄ precipitated:

moles of BaSO₄ = mass of BaSO₄ / molar mass of BaSO₄

moles of BaSO₄ = 0.9712 g / 233.38 g/mol

moles of BaSO₄ = 0.004159 mol

Since barium sulfate is formed in a 1:1 stoichiometric ratio with barium ions, the number of moles of barium ions in the original sample is also 0.004159 mol.

Calculate the mass of barium in the sample:

mass of Ba = moles of Ba × molar mass of Ba

mass of Ba = 0.004159 mol × 137.33 g/mol

mass of Ba = 0.5708 g

Calculate the percent by mass of barium in the original unknown compound:

percent by mass of Ba = (mass of Ba / mass of unknown compound) × 100%

percent by mass of Ba = (0.5708 g / 0.8360 g) × 100%

percent by mass of Ba = 68.25%

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To generate a buffer solution with a pH above 7, the correct answer would be NH3 (ammonia) and its corresponding salt, NH4Cl. A buffer solution is a solution that can resist changes in pH when small amounts of an acid or a base are added to it.

Buffers are typically composed of a weak acid and its corresponding conjugate base, or a weak base and its corresponding conjugate acid.
In the case of NH3, it acts as a weak base and can be used to generate a buffer solution with a pH above 7. When NH3 is added to water, it reacts with water to form ammonium ions (NH4+) and hydroxide ions (OH-):
NH3 + H2O → NH4+ + OH-
The ammonium ion acts as a weak acid, while the hydroxide ion acts as a strong base. By adding NH4Cl to the solution, we can ensure that the concentration of ammonium ions remains high, and the pH of the solution remains above 7.
In contrast, HCN (hydrogen cyanide) and KOH (potassium hydroxide) would not be suitable for generating a buffer solution with a pH above 7. HCN is a weak acid, and its corresponding salt (such as NaCN) would generate a buffer solution with a pH below 7. KOH is a strong base, and its corresponding salt (such as KCl) would not be able to generate a buffer solution at all.

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(a) To get the pH of the media to 5.8, you would add NaOH solution. NaOH is used as a basic solution, and when it is added to a solution, it will increase the pH of the solution.

(b) The molecular weight of BA is 225.3. To prepare a 1M solution, you would have to weigh out 225.3 grams of BA.(c) To convert a 1M solution of BA to mg/mL, you can use the following equation: 1 mole = molecular weight in grams; 1000 millimoles = 1 mole. So, 1 M = 1000 mg/mL. Therefore, a 1M solution of BA is equivalent to 1000 mg/mL .(d) To convert a concentration of 1000 mg/mL .

Therefore, to calculate the weight required for a 5 mM solution, use the following formula :Mass of BA = molarity × volume × molecular weight= 5 × 0.001 × 225.3= 1.1265 grams(f) To convert a concentration of 5 mM to mg/mL, we use the following formula: Concentration (mg/mL) = (Concentration (mM) × Molecular weight) / 1000= (5 × 225.3) / 1000= 1.1265 mg/mL(g)

To convert a concentration of 1.1265 mg/mL to mg/L, we multiply by 1000, so 1.1265 mg/mL = 1126.5 mg/L.(h) Given that the stock solution of BA is 5 mM and the working solution is 0.2 mg/mL.

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Answer:d

Explanation:

The enthalpy of the reaction CO₂(g) + H₂(g) → CO(g) + H₂O(g) is c. 41 kJmol⁻¹  

Enthalpy is the heat of a chemical reaction.

Given

CO(g) + 1/2O₂(g) → CO₂(g)  ΔH = -283 kJmol⁻¹  (1)

H₂(g) + 1/2O₂(g) → H₂O(g)  ΔH = -286 kJmol⁻¹   (2)

H₂O(g) → H₂O(l)  ΔH = -44 kJmol⁻¹  (3)

What is the enthalpy change for the following reaction

CO₂(g) + H₂(g) →  CO(g) + H₂O(g)

We proceed as follows

Since we have the reaction

CO(g) + 1/2O₂(g) → CO₂(g)  ΔH = -283 kJmol⁻¹

Reversing it, we have that

CO₂(g) → CO(g) + 1/2O₂(g)  ΔH = +283 kJmol⁻¹  (4)

Now adding reactions (2) to (4), we have that

CO₂(g) → CO(g) + 1/2O₂(g)  ΔH = +283 kJmol⁻¹

+ H₂(g) + 1/2O₂(g) → H₂O(l)  ΔH = -286 kJmol⁻¹   (2)

CO₂(g) + H₂(g) + 1/2O₂(g)  → CO(g) + 1/2O₂(g) + H₂O(l) ΔH = 283 kJmol⁻¹ +  (-286 kJmol⁻¹)

CO₂(g) + H₂(g) + 1/2O₂(g)  → CO(g) + 1/2O₂(g) + H₂O(l) ΔH = 283 kJmol⁻¹ - 286 kJmol⁻¹

CO₂(g) + H₂(g) + 1/2O₂(g)  → CO(g) + 1/2O₂(g) + H₂O(l) ΔH = -3 kJmol⁻¹ (5)

Now, reversing the reaction (3), we have that

H₂O(l) → H₂O(g)  ΔH = +44 kJmol⁻¹  (6)

Now, adding reactions (5) and (6), we have that

CO₂(g) + H₂(g) + 1/2O₂(g)  → CO(g) + 1/2O₂(g) + H₂O(l) ΔH = -3 kJmol⁻¹ (5)

+

H₂O(l) → H₂O(g)  ΔH = +44 kJmol⁻¹  (6)

CO₂(g) + H₂(g) + 1/2O₂(g) + H₂O(l) → CO(g) + 1/2O₂(g) + H₂O(l) + H₂O(g) ΔH = -3 kJmol⁻¹ + 44 kJmol⁻¹  

CO₂(g) + H₂(g) → CO(g) + H₂O(g) ΔH = 41 kJmol⁻¹  

So, the enthalpy of the reaction is c. 41 kJmol⁻¹  

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Answer: A, Coniferous Forest.

Answer:

gravity that's what I rellat think it is