organic acids are weaker than inorganic once it is true or false​

Answer:

Answer 9 - 100 joules energy was at the producer level

Answer 10 - Remaining energy is used in metabolism

Explanation:

Answer 9

The energy at each trophic level is only 10% of the energy at its previous trophic level.

The energy at producer level is X

\(10\) % of \(X = 10\) Joules

\(\frac{10}{100} * X = 10\\X = 100\)Joules

Answer 10

Because the remaining 90% energy is utilized by the producer for its metabolism

Answer:

Im going to say sleep

Explanation:

Answer:

es él water she id cooled

The  answer is that the maximum number of electrons allowed in the fourth principal energy level (n = 4) is 32.

Each principal energy level has a specific maximum number of electrons it can hold, and this maximum number can be determined using the formula 2n², where n is the principal quantum number. For the fourth principal energy level, n = 4, so we can calculate the maximum number of electrons as 2 x 4²= 32.

The principal quantum number, denoted by n, is a positive integer that determines the energy and size of an electron's orbital.

The first principal energy level (n = 1) can hold a maximum of 2 electrons, the second (n = 2) can hold 8 electrons, the third (n = 3) can hold 18 electrons, and the fourth (n = 4) can hold 32 electrons. The maximum number of electrons in any energy level is limited by the number of orbitals it contains, and the number of orbitals in a principal energy level is equal to n^2. Each orbital can hold a maximum of 2 electrons with opposite spins. Therefore, the maximum number of electrons in the fourth principal energy level (n = 4) is 2 x 4² = 32.

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Therefore, the pH of a 7.00×10^-6 M solution of HCNHCN is approximately 7.73, ignoring the effects of the autoprotolysis of water.

To calculate the pH of a solution of HCNHCN, we need to consider the dissociation of the acid and its equilibrium constant (Ka).

The equation for the dissociation of HCNHCN can be written as:

HCNHCN ⇌ H+ + CN-

Given that HCNHCN is a monoprotic weak acid with a Ka value of 4.90×10^-10, we can set up an equilibrium expression:

Ka = [H+][CN-] / [HCNHCN]

Since we are given the concentration of the acid as 7.00×10^-6 M, we can assume that the initial concentration of [HCNHCN] is equal to the given concentration.

Let x be the concentration of [H+] and [CN-]. Since the acid is monoprotic, the concentrations of [H+] and [CN-] will be equal to each other.

Using the equilibrium expression, we have:

4.90×10^-10 = (x)(x) / (7.00×10^-6)

Solving for x, we find:

x = √(4.90×10^-10 * 7.00×10^-6) ≈ 1.86×10^-8

Now, we can calculate the pH using the formula:

pH = -log[H+]

pH = -log(1.86×10^-8) ≈ 7.73

Therefore, the pH of a 7.00×10^-6 M solution of HCNHCN is approximately 7.73, ignoring the effects of the autoprotolysis of water.

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Answer:

Explanation:

A

Answer:A

Explanation:

It takes approximately 100.704 years (since 1964) until only 9 percent of the original amount of radioactive strontium-90 absorbed remains.

The half-life of radioactive strontium-90 is given as 29 years, which means that every 29 years, the amount of radioactive strontium-90 is reduced by half.

To find the number of years it takes until only 9 percent of the original amount remains, we can set up the following equation:

(0.5)^(t/h) = 0.09

Where:

t represents the number of years since 1964 (the initial time),

h represents the half-life of 29 years, and

0.09 represents 9 percent.

Let's solve for t:

(0.5)^(t/29) = 0.09

Taking the natural logarithm (ln) of both sides:

ln[(0.5)^(t/29)] = ln(0.09)

Using the logarithmic property: ln(a^b) = b × ln(a):

(t/29) × ln(0.5) = ln(0.09)

Dividing both sides by ln(0.5):

t/29 = ln(0.09) / ln(0.5)

t = 29 × (ln(0.09) / ln(0.5))

Using a calculator, we can find the value of t:

t = 29 × (-2.40794561 / -0.69314718)

t = 100.704

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Answer:

0.004243 KW/K.

Explanation:

From the question given above, the following data were obtained:

Heat transfered (Q) = 2 KW

Temperature of hot reservoir (Tₕ) = 825 K

Temperature of cold reservoir (T꜀) = 300 K

Next, we shall determine the entropy of both reservoir. This can be obtained as follow:

For hot reservoir:

Heat transfered (Q) = 2 KW

Temperature of hot reservoir (Tₕ) = 825 K

Entropy of hot reservoir (Sₕ) =?

Sₕ = Q/Tₕ

Sₕ = 2/825

Sₕ = 0.002424 KW/K

For cold reservoir:

Heat transfered (Q) = 2 KW

Temperature of cold reservoir (T꜀) = 300 K

Entropy of cold reservoir (S꜀) =?

S꜀ = Q/T꜀

S꜀ = 2/300

S꜀ = 0.006667 KW/K

Finally, we shall determine the change in the entropy of the two reservoirs. This can be obtained as follow:

Entropy of hot reservoir (Sₕ) = 0.002424 KW/K

Entropy of cold reservoir (S꜀) = 0.006667 KW/K

Change in entropy (ΔS) =?

ΔS = S꜀ – Sₕ

ΔS = 0.006667 – 0.002424

ΔS = 0.004243 KW/K.

To calculate the value for the molecular weight of your unknown been affected if a small quantity of the unknown stuck to the metal stirring rod and failed to dissolve in the benzophenone following is the process:

Your mass of counted solute added to the detergent would be lower than the recorded value performing in a lower temperature change grounded on mass of solute. A lower temperature change will affect in a lower number of calculated intelligencers of solute present. This will give a advanced molar mass for your unknown compared to the real molar mass( lower number of intelligencers divided into the mass of solute gives a larger molar mass).

These two scenarios are predicated on a solute-solvent mixture's lower freezing-point (or melting-point) as compared to pure solvent. A nonelectrolyte solute's equation is:

ΔTf = Kfm

Kf is the solvent's specific molal freezing-point depression constant, and m is the molality of the solution mixture.

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Answer:

The correct answer is - 3.864 L of CO2.

Explanation:

Answer:

That would be the necleus! I hope this helps you! :)

A substance that ionizes nearly completely in aqueous solutions and produces OH⁻ ions is called a strong base.

In aqueous solutions, water molecules will act as both acids as well as bases. When a substance ionizes in water, it undergoes a chemical reaction where it dissociates into ions. In the case of a strong base, it dissociates almost completely, releasing a high concentration of OH⁻ ions into the solution.

The presence of OH⁻ ions in a solution increases the concentration of hydroxide ions, which in turn increases the pH of the solution, making it more basic. Strong bases are capable of neutralizing acids and are known for their ability to accept protons (H⁺ ions) from acids.

Examples of strong bases include sodium hydroxide (NaOH), potassium hydroxide (KOH), and calcium hydroxide (Ca(OH)₂). These substances readily dissociate in water, producing a large number of hydroxide ions and contributing to the alkalinity of the solution.

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--The given question is incomplete, the complete question is

"A substance that ionizes nearly completely in aqueous solutions and produces OH ions is a---------."--

Answer:

1.) Fluorine

2.) Francium

3.) Nonmetals

4.) Metals

5.) Aluminum

6.) Helium

Explanation:

Looking at how others are reacting when we are uncertain about how we should react is a process called social referencing.

Infants use an adult's affective displays to control how they behave around environmental objects, people, and circumstances. This process is known as social reference. One of the key mechanisms through which infants learn to comprehend their environment is social reference.

By the age of twelve months, newborns can use the faces of their caregivers as a source of visual information to assist them grasp unfamiliar or unclear situations. For instance, when given a new toy car, a baby may decide whether or not to play with it by observing his mother's facial expressions.

It appears that social referencing processes are active during a variety of intragroup and interpersonal interactions.

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Looking at how others are reacting when we are uncertain about how we should react is a process called a. social referencing.

In the field of sociology, social referencing can be described as a process by which people tend to look at each other when they do not know how to act in a particular social situation.

Social referencing refers to acting according to how others have behaved in a particular scenario as you do not know how to face a particular social situation.

Social referencing is the ability of a person to learn from others when he himself does not know how to act in a situation and is uncertain.

Although a part of your question is missing, you might be referring to this question:

Looking at how others are reacting when we are uncertain about how we should react is a process called

a. social referencing.

b. sympathy.

c. empathic feelings.

d. emotional intelligence.

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Answer:

Explanation:

Here, we want to calculate the percentage composition of the compound formed when oxygen reacts with iron

We have the equation of reaction as follows:

The compound formed is Fe2O3

Now, let us get its percentage composition

The molar mass of the compound is 160 g/mol

The atomic mass of iron is 56 amu

The atomic mass of oxygen is 16 amu

Now, let us get the percentage composition:

The closest here is thus the option C

Nitric oxide and 21.6 grams of \(C_3H_6\)may combine to make roughly 21.62 grams of \(C_3H_3N\).

To determine the approximate mass of acrylonitrile (\(C_3H_3N\)) that can be produced from the given reactants, we first need to write and balance the chemical equation for the reaction. The reaction between \(C_3H_6\)(propene) and nitric oxide (NO) to produce acrylonitrile is as follows:

2 \(C_3H_6\)+ 2 NO -> 2 \(C_3H_3N\)+ 2 \(H_2O\)

From the balanced equation, we can see that the molar ratio between \(C_3H_6\)and \(C_3H_3N\)is 2:2, which simplifies to 1:1. This means that the molar mass of \(C_3H_6\)is equal to the molar mass of \(C_3H_3N\).

To calculate the molar mass of \(C_3H_6\), we sum the atomic masses of carbon (C) and hydrogen (H):

Molar mass of \(C_3H_6\)= (3 × atomic mass of C) + (6 × atomic mass of H)

Using the atomic masses from the periodic table:

Molar mass of \(C_3H_6\)= (3 × 12.01 g/mol) + (6 × 1.01 g/mol) = 42.09 g/mol

Since the molar mass of \(C_3H_6\) is equal to the molar mass of \(C_3H_3N\), the molar mass of \(C_3H_3N\)is also 42.09 g/mol.

Now, let's calculate the number of moles of \(C_3H_6\) and \(C_3H_3N\)using their respective masses:

Number of moles of \(C_3H_6\)= Mass of \(C_3H_6\) / Molar mass of \(C_3H_6\)

= 21.6 g / 42.09 g/mol

≈ 0.514 mol

Number of moles of \(C_3H_3N\)= Number of moles of \(C_3H_6\)(due to 1:1 molar ratio)

≈ 0.514 mol

Finally, to find the mass of \(C_3H_3N\), we multiply the number of moles by its molar mass:

Mass of \(C_3H_3N\)= Number of moles of \(C_3H_3N\)× Molar mass of \(C_3H_3N\)

≈ 0.514 mol × 42.09 g/mol

≈ 21.62 g

Therefore, Nitric oxide and 21.6 grams of \(C_3H_6\)may combine to make roughly 21.62 grams of \(C_3H_3N\).

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Answer:

b) Exothermic

Explanation:

Exothermic reaction:

The type of reactions in which energy is released are called exothermic reactions.

In this type of reaction energy needed to break the bonds are less than the energy released during the bond formation.

For example:

Chemical equation:

C + O₂   →  CO₂

ΔH = -393 Kj/mol

it can be written as,

C + O₂   →  CO₂ + 393 Kj/mol

In the nuclear transmutation represented by 23994 pu(42 he, 10 n), the product is 24596 Cm.

In the nuclear transmutation represented by pu(he, n), the product can vary depending on the specific isotopes used. However, if we assume that the starting isotope is curium-242 (Cm-242) and it undergoes the transmutation process by absorbing a helium nucleus (He-4), the resulting product would be uranium-246 (U-246). However, if the starting isotope is uranium-242 (U-242) and it undergoes the transmutation process by absorbing a neutron (n), the resulting product would be uranium-243 (U-243).
In the nuclear transmutation represented by 23994Pu(42He, 10n), the product is curium-242.

To find the product, follow these steps:
1. Identify the reactants: plutonium-239 (23994Pu) and helium-4 (42He).
2. Identify the ejected particle: neutron (10n).
3. Calculate the sum of the reactants' mass numbers (A) and atomic numbers (Z): A(Pu) + A(He) - A(n) = 239 + 4 - 1 = 242; Z(Pu) + Z(He) - Z(n) = 94 + 2 - 0 = 96.
4. The product is an element with atomic number 96 and mass number 242, which is curium-242.

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In the context of a nation's economy, the terms "produce" and "source" can refer to two important aspects of economic activity: the goods and services that a country produces, and the resources that a country uses to produce those goods and services.

In the context of economics, "produce" refers to the goods and services that are created or manufactured within a country or region. These goods and services can include anything from food, clothing, and electronics to transportation services, health care, and education. The production of goods and services is an important part of economic activity, as it creates value and generates income and employment for individuals and businesses within a country. The level of production within a country can be measured using various economic indicators, such as gross domestic product (GDP), which is the total value of all goods and services produced within a country's borders in a given period of time.

Here,

Overall, the concepts of "produce" and "source" are closely related in the context of a nation's economy, as a country's ability to produce is often closely tied to its ability to source the resources it needs to sustain economic growth and development.

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Answer:

Hydrogen

Lithium ,Beryllium,Nitrogen

Sodium.Magnesium,Phosphorus

Potassium,Calcium,Arsenic

Rubidium,Strontium,Antimony

The element in period 6 that would have chemical properties similar to nitrogen is bismuth.

The chemical properties of an element like oxidation states, reactivities, among others, are mainly related to its electronic configuration.

Elements located in the same group on the periodic table will have similar chemical properties since the electron configuration in their outer shell is the same.            

The electronic configuration of nitrogen is the following:

1s² 2s² 2p³  

Of all the elements of period 6, bismuth is the one that is located in the same nitrogen group (group 15), whose electronic configuration is:

[Xe] 4f¹⁴ 5d¹⁰ 6s² 6p³  

The electron configuration of group 15 (ns² np³) is which gives them chemical properties like high reactivity at high temperatures, high reactivity with oxidant acids (except for nitrogen), low or almost no reactivity with water, etc.    

Therefore, bismuth is the element in period 6 that would have chemical properties similar to nitrogen.

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I hope it helps you!            

Answer:

A molecule is the smallest particle in a chemical element or compound that has the chemical properties of that element or compound. Molecules are made up of atoms that are held together by chemical bonds. These bonds form as a result of the sharing or exchange of electrons among atoms.

Answer:

C

Explanation:

Answer:

nitrogen

nitrogen oxide

zincflorite

?

potassium oxide

23.8 mL of NaOH is dispensed from the buret.

There are several types of titration. However, the most common titrations are as follows

The initial reading of buret, \(V_i\) = 0.00 ml

The final reading of buret, \(V_f\) = 23.8 ml

Change in volume, \(\Delta V = V_f - V_i\)

                                    = 23.8 - 0.00 = 23.8 ml

Hence, the volume of NaOH dispensed from the burette is 23.8 ml.

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Question: Suppose you titrated a sample of NaOH with 0.150 m of HCl. Your starting volume on the burette is 0.00 ml. This is your final reading. How much NaOH was dispensed from the buret?

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The answer to the question is D. Appearance was of primary importance because of which Mortise-and-tenon joints were used in most 18th century timber framing

Mortise-and-tenon joints were commonly used in 18th century timber framing because they provided a strong and durable joint, but they also allowed for a clean and aesthetically pleasing appearance. While metal fasteners were scarce at the time, it was not the only reason for the use of this joint. The use of mortise-and-tenon joints was also a reflection of the craftsmanship and skill of the builders who wanted to create a lasting and visually appealing structure. Additionally, the tools needed to make mortise-and-tenon joints were readily available and could easily be produced with the primitive tools of the time.

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Answer:

Pretty much, yes!

Explanation:

The cell starts like this: o

First, the DNA inside the cell replicates and condenses into chromosomes. The also gathers all the materials necessary to divide and duplicates some organelles. (represented by 0)

Then the chromosomes pair up and are pulled to opposite poles of the cell. Then, the membrane pinches (invaginates) in in preparation to make two cells (8).

Then, cytokinesis occurs, when the cytoplasm splits and two new cells are formed (oo)

2ⁿ is the time complexity of an algorithm that operates in exponential time. This means that the process times double with the addition of each data element.

In computational complexity theory, the time complexity of an algorithm describes the relationship between the input size and the amount of time it takes to run. An algorithm with exponential time complexity implies that the runtime grows exponentially as the input size increases.

In this case, if the process times double with the addition of each data element, it indicates an exponential growth pattern. This can be represented by the function 2ⁿ, where n denotes the number of data elements.

The time complexity of O(2ⁿ) is used to express exponential time complexity. It indicates that the algorithm's runtime increases exponentially with the input size.

As the number of data elements grows, the runtime of the algorithm becomes significantly larger, making it inefficient for larger inputs.

Therefore, the time complexity of an algorithm operating in exponential time is represented by 2ⁿ, where n is the number of data elements, and the process times double when adding each element.

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Answer:

Well unless you have your testicales removed but I don't really know

Answer:

In the periodic table element Y is known as Yttrium and the Atomic number is 39. And the group is Transition Metal