Original Price: $124; Markdown: 14% (what is the final/marked-down price?)

Answer:

B) x-6

Step-by-step explanation:

Dylan is 6 years younger so you take away (subtract) from Briana's age (x)

Answer:

x-6

Step-by-step explanation:

Briana =x

Dylan =x-6

Briana's age is considered more because accoding to the statement Dylan is 6yrs younger so choice a is incorrect because we should subtract 6 from x the explanation x-6 is correct

Answer:

Correct choices are a, b, e

Step-by-step explanation:

As per diagram, the circles are equal.

Since the distance AB is the radius of both circles:

So the answer choices:

a. AC = BC

b. AC = BD

C. CD = AB

d. ABCD is a square

e. ABD is an equilateral triangle

f. CD = AB + AB

The colour of your eyes and your shoe size.

Option B is the correct answer.

the correct choice is {0, 18}. These elements are unique to set C and do not appear in set A.

To find the set difference C - A, we need to remove all elements from A that are also present in C. Let's examine the sets:

C = {0, 6, 12, 18}

A = {2, 4, 6, 8, 10, 12}

We compare each element of A with the elements of C. If an element from A is found in C, we exclude it from the result. After the comparison, we find that the elements 2, 4, 8, 10 are not present in C.

Thus, the set difference C - A is {0, 18}, as these are the elements that remain in C after removing the common elements with A.

Therefore, the correct choice is {0, 18}. These elements are unique to set C and do not appear in set A.

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Answer:

B. 3x - 7

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Distributive Property

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

f(x) = 4x - 3

g(x) = x + 4

(f - g)(x) is f(x) - g(x)

Step 2: Find

Answer:

Step-by-step explanation:

The phase of the systems life cycle during which users are trained to use the new system is called the implementation phase. In this phase, the new system is installed and made operational, and users are trained on how to use it effectively. This phase typically follows the design and development phases and precedes the maintenance phase.

What is the main focus of the implementation phase in the systems life cycle?

The main focus of the implementation phase is training users to use the new system effectively. This includes installing the system and making it operational, as well as providing necessary support and training to ensure users are able to utilize the system efficiently.

The phase of the systems life cycle during which users are trained to use the new system is the implementation phase. This is the phase where the new system is actually implemented and made available for use by the users. It is important to provide training to users during this phase so that they are able to effectively use the new system and understand its functionality.

Therefore, users are trained to use the new system during the implementation phase.

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The implementation phase of the systems life cycle is the time when users are taught how to utilize the new system.

The new system is installed, made operational, and users are instructed on how to utilize it efficiently during the implementation phase. In most cases, this phase comes after the design and development phases and comes before the maintenance period.

Why is user training important during the implementation phase of the systems life cycle?

User training is important during the implementation phase of the systems life cycle because it ensures that users are able to effectively use the new system and understand how it works. This is essential for the successful adoption and utilization of the system by the organization. Without proper training, users may struggle to use the system effectively, leading to reduced productivity and potentially even causing issues with data accuracy and integrity. By providing thorough user training, organizations can ensure that their employees are able to use the new system efficiently and effectively, leading to a successful implementation.

The implementation phase of the systems life cycle is the time when users are taught how to utilise the new system. In this stage, the new system is really put into use and made accessible to users. During this stage, it's crucial to give users training so they can utilize the new system correctly and comprehend its functions.

Therefore, during the implementation phase, users are instructed on how to utilize the new system.

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The probability that 2 gardeners will order the same type of seeds is approximately 0.8103 or 81.03%

The probability that 2 gardeners will order the same type of seeds can be calculated using the formula below:

P (at least 2 gardeners order the same type of seeds) = 1 - P (no gardeners order the same type of seeds)

We can use the formula for calculating probability when there is no replacement,

which is:

P (no gardeners order the same type of seeds)

= n! / (n - r)! × n^r,

Where n is the total number of options and r is the number of choices or gardeners in this case.

Therefore, we have:

P (no gardeners order the same type of seeds)

= 11! / (11 - 6)! × 11^6

= 11 × 10 × 9 × 8 × 7 / 720 × 11^6

≈ 0.1897

Using the formula for the probability that at least 2 gardeners will order the same type of seeds,

we have:

P (at least 2 gardeners order the same type of seeds)

= 1 - P (no gardeners order the same type of seeds)

≈ 1 - 0.1897

≈ 0.8103

Therefore, the probability that 2 gardeners will order the same type of seeds is approximately 0.8103 or 81.03%.

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Answer:122/600= 0.20333333333

Step-by-step explanation:

Answer:

13,440 is the area of this irregular object....

Answer:

If you didn’t understand what the person previous of me said. You’re going to do what is in parenthesis first and then continue from the left. If you need to draw the expression out and after that add together the pieces that are the same. To me it looks like it’s already simplified since there isn’t any pieces that are the same that you can add together if I’m not mistaken. Hope this could help. Your are welcome in advance. Stay Safe ‼️ :)

Step-by-step explanation:

The finite population correction factor is used in computing the standard error of the sample mean when the sample size is smaller than 5% of the population size.

The finite population correction factor is a adjustment made to the standard error of the sample mean when the sample is taken from a finite population, rather than an infinite population.

It accounts for the fact that sampling without replacement affects the variability of the sample mean.

When the sample size is relatively large compared to the population size (more than half), the effect of sampling without replacement becomes negligible, and the finite population correction factor is not necessary.

In this case, the standard error of the sample mean can be estimated using the formula for sampling with replacement.

On the other hand, when the sample size is small relative to the population size (less than 5%), the effect of sampling without replacement becomes more pronounced, and the finite population correction factor should be applied.

This correction adjusts the standard error to account for the finite population size and provides a more accurate estimate of the variability of the sample mean.

Therefore, the correct answer is option 2: the finite population correction factor is used when the sample size is smaller than 5% of the population size.

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Answer: No

Step-by-step explanation:

The product of x and y is not constant. (note how the product is 45, then 320, then 500, then 2420)

The number of numbers in the intersection of sets D and E is E. 7

To determine the number of numbers in the intersection of sets D and E, we need to understand the composition of each set.

Set D contains all the integers between -7 and 6, excluding -7 and 6. This means it includes the numbers -6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, and 5. There are a total of 12 numbers in set D.

Set E contains the absolute values of all the numbers in set D. This means we take the absolute value of each number in set D. The absolute value of a number is its distance from zero on the number line, so it will always be positive or zero.

Considering the numbers in set D, the absolute values would be 6, 5, 4, 3, 2, 1, 0, 1, 2, 3, 4, and 5. Notice that for each positive number in set D, its absolute value will be the same. Therefore, the intersection of sets D and E will only include the positive numbers.

In this case, the numbers in the intersection are 1, 2, 3, 4, and 5. Hence, there are 5 numbers in the intersection of sets D and E. Therefore, Option E is correct.

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These are the solutions to the quadratic equation p^2 + 2p^2 - 5 * 2p + 5 = 0.

To solve the quadratic equation p^2 + 2p^2 - 5 * 2p + 5 = 0, we need to simplify and rearrange the equation to its standard form and then solve for p.

Combining like terms, the equation becomes:

3p^2 - 10p + 5 = 0

Now, we can use the quadratic formula to solve for p. The quadratic formula states:

p = (-b ± √(b^2 - 4ac)) / (2a)

For our equation, a = 3, b = -10, and c = 5. Substituting these values into the quadratic formula, we have:

p = (-(-10) ± √((-10)^2 - 4 * 3 * 5)) / (2 * 3)

Simplifying further:

p = (10 ± √(100 - 60)) / 6

p = (10 ± √40) / 6

p = (10 ± 2√10) / 6

Now, we can simplify and find the two possible values of p:

p₁ = (10 + 2√10) / 6

p₂ = (10 - 2√10) / 6

These are the solutions to the quadratic equation p^2 + 2p^2 - 5 * 2p + 5 = 0.

In simplified form, the solutions are:

p₁ = (5 + √10) / 3

p₂ = (5 - √10) / 3

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Answer:

2

Step-by-step explanation:

Okay...I might be misunderstanding

but since it's from 5 to 7 it should be 2 units long

Answer:

2

Step-by-step explanation:

Based on the given mean delivery time of 10:28am and the standard deviation of 0:55 mins, the estimated times within which 95% of the deliveries are made is (a) between 8:38 am and 12:18 pm.

To calculate this interval, we need to use the z-score formula, where we find the z-score corresponding to the 95th percentile, which is 1.96. Then, we multiply this z-score by the standard deviation and add/subtract it from the mean to get the upper and lower bounds of the interval.

The upper bound is calculated as 10:28 + (1.96 x 0:55) = 12:18 pm, and the lower bound is calculated as 10:28 - (1.96 x 0:55) = 8:38 am.

Therefore, we can conclude that the interval between 8:38 am and 12:18 pm represents the estimated times within which 95% of the deliveries are made based on the given mean delivery time and standard deviation.

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Answer:

its 0.59

Step-by-step explanation:

Because if you divide 7.08 and 12 then you get the answer.

Answer:

-2degrees

Step-by-step explanation:

(3 degrees Celsius - 5 degrees Celsius)= -2 degrees Celsius

At a price of $2, the quantity demanded is 20 units, while the quantity supplied is only 4 units. This indicates that the quantity demanded exceeds the quantity supplied, creating a situation of excess demand or a shortage of 16 units.

A surplus occurs when the quantity supplied exceeds the quantity demanded at a given price. In this case, the quantity supplied (4 units) is lower than the quantity demanded (20 units) at a price of $2, resulting in a surplus of 16 units.

To determine the occurrence of a surplus or shortage, we compare the quantity demanded and the quantity supplied at a given price. In this case, when the price is $2, the quantity demanded is 20 units, while the quantity supplied is 4 units.

Since the quantity demanded (20 units) exceeds the quantity supplied (4 units), there is a surplus of (20 - 4) 16 units. This means that at a price of $2, there will be an excess supply of 16 units in the market.

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Answer:

n\(\geq\)8

Step-by-step explanation:

You add 4 to both sides to make n the only thing on one side. Then to make the answer look better you move n to the left side and flip the symbol because n changed sides.

\(4\leq n-4\\ 4+4\leq n-4+4\\ 8\leq n\\ n\geq 8\)

Between clock skew and clock jitter, skew is preferred because it is more predictable and can sometimes increase max frequency. This makes it easier to manage in electronic systems and can provide benefits in certain scenarios.

Jitter is preferred because it is predictable. Clock jitter refers to the variability of the clock signal and can be predicted and compensated for. On the other hand, clock skew refers to the difference in arrival time of the clock signal at different points in the circuit and can sometimes increase maximum frequency. However, skew is preferred because it is more predictable and can be compensated for, while jitter is preferred because it is unpredictable and can't be compensated for. Therefore, in general, jitter is considered more preferable than skew.

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(b) (iii) Factory 0 is better than all other factories (i.e., it is less likely to produce defective fidget spinners).

(c) (iii)Factory 0 is better than all other factories (i.e., it is less likely to produce defective fidget spinners).


(b) Nat chose the value of a to be 0.3 because she knows that factory 0 produces fewer defective fidget spinners than factory 1. This means that factory 0 is better, or less likely to produce defective fidget spinners, which is why the value of a is closer to 0 than 1.

(c) Nat chose the values of a and B to be 1 and 5 for factory 0, and 5 and 1 for factory 1, because she knows that factory 0 is better, or less likely to produce defective fidget spinners, than factory 1.

The values of a and B are used to determine the probability of a fidget spinner being defective from each factory, with a lower value of a and a higher value of B indicating a lower probability of a defective fidget spinner.

Therefore, the values of a and B for factory 0 indicate a lower probability of a defective fidget spinner than the values of a and B for factory 1.

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Answer:

I think it is 4.48.

Explain:

6.16/22 is 0.28    Then 0.28 times 16 is 4.48.

Can I get a Brainliest?

Answer: \(-\frac{3}{10}\)

Step-by-step explanation:

Answer:

-3/10

Step-by-step explanation:

Step 1: Use this rule a/b x c/d = ac/bd

-3x2/4x5

Step 2: Simplify 3x2 to 6

-6/4x5

Step 3: Simplify 4x5 to 20

-6/20

Step 4: Simplify 6/20 to 3/10.

-3/10

Step-by-step explanation:

5 : 8 :: 125 : x

5x = 1000

X = 1000/5

X = 200

Answer:

If a:b :: c:d or in other words a:b = c: d, then the quantity 'd' is what we call the fourth proportional to a, b and c. For example, if we have 2, 3 and 4, 5 are in the proportion such that 2 and 5 are the extremes, then 5 is the fourth proportional to 2, 3, and 4.

The best measure of variability for the dot plot is the interquartile range (IQR).

The interquartile range (IQR) is a measure of variability that is resistant to outliers. It is used to calculate the difference between the 75th and 25th percentiles of a data set. The interquartile range (IQR) of a dot plot is calculated as follows:1. The data set is arranged in ascending order.2. The median of the data set is found.3. The data set is divided into two halves, with the median as the dividing line.4. The lower quartile (Q1) is the median of the lower half of the data set.5. The upper quartile (Q3) is the median of the upper half of the data set.6. The interquartile range (IQR) is the difference between the upper quartile (Q3) and the lower quartile (Q1).Thus, the interquartile range (IQR) is the best measure of variability for the dot plot with 2 extreme values because it is a resistant measure that is not influenced by outliers.

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The algebraic expression that is defined by the model is given as follows:

3x + 2y + 5.

The algebraic expression is defined as the sum of multiple terms as defined by the tiles.

We have 3 tiles with terms of x, hence:

3x.

We have 3 tiles with values of y, hence:

3x + 2y.

Finally, we also have five constant tiles, hence the complete algebraic expression is given as follows:

3x + 2y + 5.

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