out of 30 questions on the maths test tomi knew the answer to 27 of them what percentage of questions did tomi know the answer for ?

Answer:

The given image is a graph of an exponential function. The graph is in the form of y = ab^x, where a is the initial value (y-intercept), b is the base (growth or decay factor), and x is the exponent (input value).

In this particular graph, the function appears to be a decay function since the value of the function is decreasing as x increases. We can also see that the initial value of the function is 24, which means that when x = 0, y = 24. We can also see that the base of the function is less than 1 (approximately 0.8), which tells us that the function is decreasing at a constant rate.

To write the exponential function that represents this graph, we can use the general form of the function y = ab^x and substitute the known values:

y = 24(0.8)^x

Therefore, the exponential function that represents the given graph is y = 24(0.8)^x.

Image 2.

The given image is a graph of an exponential function. The graph is in the form of y = ab^x, where a is the initial value (y-intercept), b is the base (growth or decay factor), and x is the exponent (input value).

In this particular graph, the function appears to be a growth function since the value of the function is increasing as x increases. We can also see that the initial value of the function is 5, which means that when x = 0, y = 5. We can also see that the base of the function is greater than 1 (approximately 1.2), which tells us that the function is increasing at a constant rate.

To write the exponential function that represents this graph, we can use the general form of the function y = ab^x and substitute the known values:

y = 5(1.2)^x

Therefore, the exponential function that represents the given graph is y = 5(1.2)^x.

Answer:

Use the formula SA=2×length×width+2 length× height+2×height×width. With this I believe your answer should be 13.5. Sorry if it's wrong since the answer choices don't line up but thats the only way it makes sense for me.

Answer:

\(3x^{2}\)

Answer:

120km^2

Step-by-step explanation:

9x3=27

9X5=45

9x4=36

3x4/2=6

3x4/2=6

27+45+36+6+6=120

It will take approximately 3.96 years (or approximately 3 years and 11 months) for Vincent's savings to reach $9,000.

To solve this problem, we can use the formula for the future value of an ordinary annuity:

FV = P * [(1 + r)^n - 1] / r

Where:

FV = Future Value

P = Payment (deposit amount)

r = Interest rate per compounding period

n = Number of compounding periods

In this case, Vincent deposits $165 at the end of each quarter, so P = $165. The annual interest rate is 6%, compounded quarterly, so the interest rate per compounding period, r, would be 6% divided by 4 (since there are 4 quarters in a year), which is 0.06/4 = 0.015.

We want to find the number of years, n, it will take for Vincent's savings to reach $9,000. Let's substitute the given values into the formula and solve for n:

9,000 = 165 * [(1 + 0.015)^n - 1] / 0.015

To solve this equation, we can use algebraic techniques or a financial calculator. Solving the equation, we find that n is approximately 15.83.

Since n represents the number of quarters, we need to convert it to years by dividing it by 4 (since there are 4 quarters in a year):

n (in years) = 15.83 / 4 ≈ 3.96

Therefore, it will take approximately 3.96 years (or approximately 3 years and 11 months) for Vincent's savings to reach $9,000.

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The simplified form of the given expression is -18. The correct option is the third option-  -18

From the question, we are to simplify

|3-10| - (12 ÷ 4 + 2)²

Simplifying

|3-10| - (12 ÷ 4 + 2)²

|-7| - (3 + 2)²

7 - (5)²

7 - 25

= -18

Hence, the simplified form of the given expression is -18. The correct option is the third option-  -18

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a) The pressure at the exit of the turbine can be determined using the isentropic expansion process and the ideal gas model.

b) The work out of the turbine per kilogram of oxygen flowing can be calculated using the ideal gas equation and the temperature and pressure changes during the expansion process.

a) To determine the pressure at the exit, we can use the isentropic expansion process, which assumes no heat transfer and reversible adiabatic conditions. Using the ideal gas model, we can apply the relationship between temperature and pressure for an isentropic process:

P1 / \(T2^(γ)\) = P2 / \(T2^(γ)\)

where P1 and T1 are the initial pressure and temperature, P2 is the pressure at the exit, T2 is the temperature at the exit, and γ is the specific heat ratio of the gas.

b) The work out of the turbine per kilogram of oxygen flowing can be calculated using the ideal gas equation for a steady-state process:

Work = ∫(Cp × dT)

where Cp is the specific heat at constant pressure. By integrating the equation with respect to temperature from the initial to final states, and assuming constant Cp, we can calculate the work.

The specific values of γ and Cp will depend on the gas being used (oxygen in this case). Using the given initial and final conditions, the specific values of γ and Cp for oxygen, and the equations mentioned above, we can calculate the pressure at the exit and the work out of the turbine per kilogram of oxygen flowing.

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Answer:

The 2nd equation is false.

Step-by-step explanation:

You don't even have to solve. DE is not 58, it's 40.

The 2nd equation is false.

Answer:

x = 3/2

Step-by-step explanation:

9^x = 27 base equation

9^x = 3^3 convert 27 to exponential

3^(2x) = 3^3 convert 9^x to the same base number

2x = 3 drop the bases and compare exponents

x= 3/2 answer

Answer:

62.5% or 63%

5 ÷ 8 = 0.625

0.625 = 62.5% or 63%

Answer:

Same situation as before, thanks for points.

Step-by-step explanation:

The only value of p that satisfies both conditions and makes the interval of convergence [-11, 1) is p = 1.

To find the values of "p" that make the interval of convergence of the series \(∑ₙ₌₁^[∞] 5ⁿ/(6ⁿ(x - p)ⁿ) be [-11, 1),\) we can use the ratio test to determine the radius of convergence.

The ratio test states that for a power series \(∑ₙ₌₀^[∞] aₙ(x - c)ⁿ,\)the series converges if the limit of\(|aₙ₊₁(x - c)ⁿ⁺¹ / (aₙ(x - c)ⁿ)|\) as n approaches infinity is less than 1.

Let's apply the ratio test to the given series:

\(|aₙ₊₁(x - p)ⁿ⁺¹ / (aₙ(x - p)ⁿ)| = |(5ⁿ⁺¹ / 6ⁿ⁺¹)(x - p)ⁿ⁺¹ / (5ⁿ / 6ⁿ)(x - p)ⁿ| = |5(x - p)ⁿ⁺¹ / 6(x - p)ⁿ| = |5(x - p) / 6|\)

To ensure convergence, we want the absolute value of this ratio to be less than 1:

|5(x - p) / 6| < 1

Now, let's consider the given interval of convergence, [-11, 1).

When x = -11:
|5(-11 - p) / 6| < 1
|-55 - 5p| < 6
-55 - 5p < 6  (since the absolute value is always non-negative)
-5p < 6 + 55
-5p < 61
p > -61/5

When x = 1:
|5(1 - p) / 6| < 1
|5 - 5p| < 6
-5p < 6 - 5
-5p < 1
p > -1/5

Therefore, the values of p that make the interval of convergence of the series \(∑ₙ₌₁^[∞] 5ⁿ/(6ⁿ(x - p)ⁿ) be [-11, 1)\) are p > -61/5 and p > -1/5.

In the given options:
- P = -6: Does not satisfy p > -61/5 or p > -1/5.
- P = -5: Satisfies p > -61/5 but does not satisfy p > -1/5.
- P = 1: Satisfies p > -61/5 and p > -1/5.
- P = -211: Satisfies p > -61/5 but does not satisfy p > -1/5.
- P = -7: Does not satisfy p > -61/5 or p > -1/5.

Therefore, the only value of p that satisfies both conditions and makes the interval of convergence [-11, 1) is p = 1.

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Answer:

16) 142

17) 23

18) 134

19) 38

Please mark brainliest if this is correct.

Answer:

370 mm²

Step-by-step explanation:

The area of this figure can be calculated by taking the whole figure as a full rectangle, and consider the part that is cut out from the middle of the shape as another rectangle.

Find the area of the cut-out part and subtract from the area of the full rectangular shape to get the area of the composite figure.

=>Area of full rectangular shape:

Length = 30 mm

Width = 15 mm

Area = L * B = 30*15 = 450 mm²

=>Area of the cut-out Rectangle part:

Length = 10 mm

Width = 8 mm

Area = 10*8 = 80 mm²

=>Area of composite figure = 450 mm² - 80 mm² = 370 mm²

Answer:

1/64

Step-by-step explanation:

Answer:

=\(\frac{1}{64}\)

Step-by-step explanation:

Answer: The answer is 626

Step-by-step explanation:

Substitute 11 for x, you get 626.

Answer:

Step-by-step explanation:

The length of the arc on the unit circle is 3.67 units

The angle measure is given as:

x = 7π/6

The radius of a unit circle is:

r = 1

The length of the arc is calculated using:

L =rx

So, we have:

L = 1 * 7π/6

Evaluate

L = 3.67

Hence, the length of the arc on the unit circle is 3.67 units

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Answer: n = 1/2; m = 2/3

Step-by-step explanation:

A ⇒ 12 y = 6x + 24

\(y=\frac{n}{2}+2\)

\(n=\frac{1}{2}\)

B ⇒ 3y = 2x + 18

\(y=\frac{2}{3}n+6\)

\(m=\frac{2}{3}\)

∴ Lines are neither because slop diff.

Answer:

256

Step-by-step explanation:

The quotient of the given expression will be 256.

From the given data

\(=\dfrac{2^{4} }{2^{-4} }\)

Now it will become

\(2^{4} \times 2^{4} = 2^{8} =256\)

Thus the quotient of the given expression will be 256

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Answer:

3280

Step-by-step explanation:

50 m  ≅ 164 ft (3s.f.)

50 m/s  ≅ 164 ft/s

distance after  20 s:

d = 164 ft/s   ⋅ 20 s

= 3280 ft

The correct answer is: W is not a subspace of R³.

The subset W of R³ consists of all vectors [x₁ x₂ x₃] such that x₁ + x₂ + x₃ > 2. We need to determine whether W is a subspace of R³ or not.The subset W is not a subspace of R³. This is because if x = [1 1 1] and y = [2 2 2] are in W, then x + y = [3 3 3] is not in W. This contradicts the condition that any subspace must be closed under addition.Let's check whether W satisfies the conditions for a subspace or not:1.

The zero vector [0 0 0] is in W since 0 + 0 + 0 = 0 < 2.2. Closure under scalar multiplication: Let c be any scalar and let x = [x₁ x₂ x₃] be any vector in W. Then, we have c x = [cx₁ cx₂ cx₃]. Since x₁ + x₂ + x₃ > 2, we have cx₁ + cx₂ + cx₃ = c(x₁ + x₂ + x₃) > 2c > 2. Therefore, cx is also in W.3. Closure under addition: Let x = [x₁ x₂ x₃] and y = [y₁ y₂ y₃] be any two vectors in W. Then, we have x₁ + x₂ + x₃ > 2 and y₁ + y₂ + y₃ > 2. Adding these two inequalities, we get (x₁ + y₁) + (x₂ + y₂) + (x₃ + y₃) > 4. Therefore, x + y = [x₁ + y₁ x₂ + y₂ x₃ + y₃] is also in W.However, W fails the closure under addition axiom, which is necessary to be a subspace of R³. Therefore, the correct answer is: W is not a subspace of R³.

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Step-by-step explanation:

An expression is a number, a variable, or a combination of numbers and variables and operation symbols. An equation is made up of two expressions connected by an equal sign.

Answer:

An expression is written as a phrase and an equation is written as a statement. Equations are written as sentences with capitalization and punctuation. Expressions are written as phrases with no capitalization or punctuation. An equation has an equals sign and an expression does not.

Step-by-step explanation:

Hope this helps! Please mark me brainliest!

The correct graph to display this data is

The bar graph with the title favorite sport and the x-axis labeled sport and the y-axis labeled the number of students, with the first bar labeled basketball going to a value of 17, the second bar labeled baseball going to a value of 12, the third bar labeled soccer going to a value of 27, and the fourth bar labeled tennis going to a value of 44.

The bar graph is used to display categorical data and the number of observations in each category. In this case, the categories are the different sports and the number of observations is the number of students who selected each sport as their favorite.

Here we have

A random sample of 100 middle schoolers was asked about their favorite sport. The following data was collected from the students.

Sports              Basketball    Baseball    Soccer    Tennis

No of Students       17                  12             27            44

A histogram is used to display continuous data and is not appropriate for this categorical data.

Additionally, the order of the bars in the first histogram is incorrect, which can lead to confusion when interpreting the data.

The correct graph to display this data is

The bar graph with the title favorite sport and the x-axis labeled sport and the y-axis labeled the number of students, with the first bar labeled basketball going to a value of 17, the second bar labeled baseball going to a value of 12, the third bar labeled soccer going to a value of 27, and the fourth bar labeled tennis going to a value of 44.

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variability.

In statistics, variability refers to the spread or spread of a data set. It is a measure of how much the data points in the dataset differ from each other and from the mean (mean) of the data.

There are several ways to quantify dataset variability. A common measure of variability is range. This is the difference between the highest and lowest values ​​in the dataset. Another measure of variability is variance. This is a measure of how far the data points are from the mean. Standard deviation is another measure of variability calculated by taking the square root of the variance.

In addition to these measures of variability, there are other statistical techniques that can be used to summarize the spread of datasets, such as Box plot and histogram. These techniques help visualize data variability and identify outliers.

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Answer:

Hi there!

Your answers are:

a) x= 10

b) x= 4

c) x= 2

Step-by-step explanation:

a) 5+2x=25

-5

2x= 20

/2

x= 10

Plug back in!

5+2(10)= 25

5+20=25

25=25✓✓✓

b) 14= 5x-6

+6

5x= 20

/5

x= 4

14= 5(4)-6

14= 20-6

14=14✓✓✓

c) 15= 4x+7

-7

8= 4x

/4

2=x

15= 4(2)+7

15= 8+7

15= 15✓✓✓

Hope this helps!

Answer:

$1.08

Step-by-step explanation:

The probability density function (pdf) of the largest of the five waiting times is given by: f(x) = 4/10^5 * x^4, where x is a real number between 0 and 10. The expected value of the largest of the five waiting times is 8.33 minutes.

The pdf of the largest of the five waiting times can be found by considering the order statistics of the waiting times. The order statistics are the values of the waiting times sorted from smallest to largest.

In this case, the order statistics are X1, X2, X3, X4, and X5. The largest of the five waiting times is X5.

The pdf of X5 can be found by considering the cumulative distribution function (cdf) of X5. The cdf of X5 is given by: F(x) = (x/10)^5

where x is a real number between 0 and 10. The pdf of X5 can be found by differentiating the cdf of X5. This gives: f(x) = 4/10^5 * x^4

The expected value of X5 can be found by integrating the pdf of X5 from 0 to 10. This gives: E[X5] = ∫_0^10 4/10^5 * x^4 dx = 8.33

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