Oxygen + Hydrogen -> Water

Answer: atoms/molecules

Explanation:

Answer:

7 Images

Explanation:

n = 360 / a - 1 =  360 / 45 - 1 = 8-1= 7

(Based on multiple reflections)

I hope im right!!

Out of the given options, the compound that contains a sulfur atom that bears a +1 formal charge is H2SO4. The correct option is c. H2SO4. Please find a long answer below:Sulfur is a chemical element with the symbol S and atomic number 16. It is a nonmetallic element and is a member of the oxygen group.

In compounds, sulfur forms an oxidation state of +6 with oxygen and a +2 oxidation state with oxygen. Sulfur also exhibits a +4 oxidation state with oxygen. The electronegativity of sulfur is 2.5 and it has six valence electrons. Now, let's discuss the given options.a. MgSO4: Magnesium sulfate is a compound that is made up of magnesium, sulfur, and oxygen. In MgSO4, magnesium has a +2 charge, sulfur has a -2 charge, and oxygen has a -2 charge. Therefore, sulfur does not have a +1 formal charge. b. SO2: Sulfur dioxide is a compound that is made up of sulfur and oxygen. In SO2, sulfur has a +4 oxidation state and oxygen has a -2 charge.

Therefore, sulfur does not have a +1 formal charge.c. H2SO4: Sulfuric acid is a compound that is made up of sulfur, hydrogen, and oxygen. In H2SO4, sulfur has a +6 oxidation state and hydrogen has a +1 charge. Therefore, sulfur bears a +1 formal charge. d. SF6: Sulfur hexafluoride is a compound that is made up of sulfur and fluorine. In SF6, sulfur has a +6 oxidation state and fluorine has a -1 charge. Therefore, sulfur does not have a +1 formal charge. e. H2S: Hydrogen sulfide is a compound that is made up of sulfur and hydrogen. In H2S, sulfur has a -2 charge and hydrogen has a +1 charge. Therefore, sulfur does not have a +1 formal charge.Hence, H2SO4 is the compound that contains a sulfur atom that bears a +1 formal charge.

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So, Na (Z=11) has the largest atomic radius among the given elements in the third period.

The element with the largest atomic radius among the given compounds is Na (Z=11) which is a group 1 element and has only one valence electron, leading to a larger atomic radius compared to the other elements in the third period.

1. List the elements given: Al (Z=13), Na (Z=11), Si (Z=14), and Cl (Z=17).
2. Understand that atomic radius generally decreases across a period from left to right due to an increase in effective nuclear charge.
3. Since Na is the farthest left element among the options provided, it has the largest atomic radius.

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Land absorb more radiation from the solar energy than water and retains the absorbed heat.

As the earth surface is darker compared to the water surface, more radiations gets absorbed, so it heats up quickly. Water surface reflects most of the incoming radiations, so it takes longer for water to get heated. Also, it takes less energy to rise the temperature on land than water, because water has higher specific heat capacity. Also water cools downs slowly because of this.

Due to this difference in heating and cooling properties of land and water, the differences in temperature and air mass movement occurs across land and water. During day time, as it absorbs more radiations, the land gets heated up quickly and temperature of water changes only slightly. During night, the temperature of lands drops quickly, but water will retain the temperature for long period.

Thus land gains and lose heat quickly compared to water and this result in climatic changes across different areas.

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The rusting of a kitchen knife is a natural process that occurs when iron or steel reacts with oxygen and moisture in the air. Rusting is a form of corrosion that gradually damages the metal surface, causing it to become brittle and lose its sharpness.

The process of rusting involves an electrochemical reaction. When the metal is exposed to air and moisture, water molecules combine with carbon dioxide in the air to form a weak acid. This acid reacts with the iron or steel, breaking it down into iron ions and releasing electrons. The iron ions combine with oxygen from the air to form iron oxide, commonly known as rust. Rusting can be accelerated by factors such as high humidity, exposure to saltwater or chemicals, and scratches or damage to the knife's protective coating. To prevent rusting, it is important to keep the knife dry, clean, and properly stored, preferably in a dry environment and away from moisture.

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The volume of the gas at a pressure of 1.00 x 10^2 kPa is 1.8 x 10^3 L.

To calculate the volume of a gas at a different pressure, we can use Boyle's Law, which states that the product of pressure and volume is constant for a given amount of gas at a constant temperature. Mathematically, it is represented as P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.

Given:
Initial pressure (P1) = 1.2 x 10^2 kPa
Initial volume (V1) = 1.50 x 10^3 L
Final pressure (P2) = 1.00 x 10^2 kPa

We need to find the final volume (V2). Using Boyle's Law formula:

P1V1 = P2V2

(1.2 x 10^2 kPa)(1.50 x 10^3 L) = (1.00 x 10^2 kPa)(V2)

Solving for V2:

V2 = [(1.2 x 10^2 kPa)(1.50 x 10^3 L)] / (1.00 x 10^2 kPa)
V2 = (1.8 x 10^5) / (1.0 x 10^2)
V2 = 1.8 x 10^3 L

So, the volume of the gas at a pressure of 1.00 x 10^2 kPa is 1.8 x 10^3 L.

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There are three NMR signals present in the given isomer of dimethylcyclopropane.

The number of NMR signals is defined as the number of different types of protons in a molecule. NMR signal is the example we used in the introduction to NMR spectroscopy. The spectrum has five signals which basically indicates five types of different protons.

The given compound is shown in Fig(i).

The name of the compound is (1R, 2R)-1,2- dimethylcyclopropane.

The above molecule has plane of symmetry which is shown in Fig(ii).

So, the given molecule has three types of protons. The denotation of three types of protons are shown in Fig (iii).

Hence, the number signals is three.

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During electrolysis of an aqueous solution of potassium sulfate, hydrogen gas or hydroxide ions may be produced at the cathode. The actual product depends on the concentration of hydrogen ions in the solution.

During electrolysis of an aqueous solution of potassium sulfate (K2SO4), the products produced at the cathode could be hydrogen gas (H2) or hydroxide ions (OH-), depending on the conditions of the electrolysis. The following reactions may occur at the cathode:

1) Reduction of water:
2H2O + 2e- -> H2 + 2OH-

2) Reduction of hydrogen ions:
2H+ + 2e- -> H2

In both cases, hydrogen gas is produced. However, the second reaction is only possible if there are hydrogen ions (H+) available in the solution. If the concentration of hydrogen ions is low, as is the case in a solution of K2SO4, then the reduction of water is more likely to occur, producing hydroxide ions at the cathode instead of hydrogen gas. So, the correct answer would be either hydrogen gas or hydroxide ions (OH-).

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Cations are always smaller than the atoms from which they form. Anions are always larger than the atoms from which they form. Ions are usually bigger than the atoms from which they are formed.

When an atom receives or loses electrons, the atom's electron configuration changes, resulting in a net positive or negative charge.

This net charge expands the electron cloud surrounding the nucleus, making the ion bigger in size than the neutral atoms from which it arose. When a metal atom loses one or more electrons to create a cation, it shrinks in size because the positive charge of the nucleus pulls the remaining electrons more strongly.

When a nonmetal atom obtains one or more electrons to create an anion, it normally expands in size.Because of the increasing amount of electrons, the electron cloud surrounding the nucleus grows. It should be noted that this comparison is not absolute and is dependent on the individual factors involved. Some ions are smaller than their neutral atom counterparts, while others are similar in size.

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The complete question is:

Compare the size of ions to the size of atoms from which they form.

The equilibrium constant at 1000K for the reaction CaCO3(s) + C(s) --> CaO(s) + 2CO(g) is K = K1.K2 = 0,039 . 1,9 = 0,074.

The equilibrium constant at 1000 K for the given chemical reaction, CaCO3(s) + C(s) CaO(s) + 2 CO(g), can be determined as follows:

\(K1 = 0,039\\K2 = 1,9\)

We know that the equilibrium constant of a reaction is the product of the equilibrium constants of its individual steps (if the reaction is made up of more than one step) under the given conditions. Therefore, we can use the following equations to calculate the equilibrium constant of the given reaction: \(Kc = \frac{K1. K2}{Keq}\) (where Keq is the equilibrium constant of the desired reaction) \(Kc = [(P(CO))^2/(P(CaCO3).P(C))] . 0,039 . 1,9\).

Now, we have to express the pressure of all the species involved in terms of the equilibrium constant of the reaction we need to find. For this, we use the following relation:

Keq = \((P(CaO).P(CO)^2)/(P(CaCO3).P(C))\). On substituting the above expression for Keq in the expression for Kc, we get:

Kc = \([(P(CO))^2/(P(CaCO3).P(C))] . 0,039 . 1,9\)

Keq = \((P(CaO).P(CO)^2)/(P(CaCO3).P(C))\)

On comparing the expressions for Kc and Keq, we get:

\(Kc = K1 . K2/Keq\\Kc = [(P(CO))^2/(P(CaCO3).P(C))] . 0.039 . 1.9\\Kc = (P(CaO).P(CO)^2)/(P(CaCO3).P(C))\)

Therefore, we can write: \((P(CaO).P(CO)^2)/(P(CaCO3).P(C))\)

Kc =\([(P(CO))^2/(P(CaCO3).P(C))] . 0,039 . 1,9(P(CaO).P(CO)^2)/(P(CaCO3))^2\)

\(Kc = 0,039. 1,9P(CO)^2/P(CaCO3) \\Kc = 0,074251/P(CaO) \\Kc = (P(CaCO3).P(C) )/P(CO)^2.\)

Now, using the expression for Keq, we can write:

\(Keq = (P(CaO).P(CO)^2)/(P(CaCO3).P(C))\\Keq = (P(CaCO3).P(C).P(CO)^2)/(P(CaCO3).P(C))\\Keq = P(CO)^2/P(C)\\Keq = 0.07425\)

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At the end of mitosis, the cells are genetically identical to each other. Therefore, option B is correct.

Mitosis is the process by which a cell replicates and then segregates its chromosomes, producing two identical nuclei in preparation for cell division.

Meiosis produces four haploid (n) gametes that are genetically distinct from each other and the original parent (germ) cell, whereas mitosis produces two diploid (2n) somatic cells.

Mitosis results in the formation of two identical daughter cells, each with the same number of chromosomes as the parent cell.

Thus, option B is correct.

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Answer:

genetically identical to each other

Explanation:

Answer:

D.) K, Mn, As, Ar

Explanation:

The metalloids are located in the p-block on the periodic table and have a ladder-like arrangement.

The most commonly recognized metalloids are:

boron (B), silicon (Si), germanium (Ge), arsenic (As), antimony (Sb), tellurium (Te)

The main problem in synthesizing l-alanyl-l-valine directly from its two component amino acids is the formation of dipeptides and other peptide products.

Peptide bonds are formed between the carboxyl group of one amino acid and the amino group of another. The direct synthesis of L-alanyl-L-valine from its two component amino acids may result in the formation of dipeptides and other peptide products.

In addition, the process is also time-consuming, expensive, and results in low yields. The reaction rate and yield can be affected by various factors such as the pH of the medium, temperature, and reactant concentrations. The presence of other amino acids and impurities can also interfere with the synthesis process.

Moreover, the purity of the final product can be affected by the separation and purification techniques used. Therefore, the direct synthesis of L-alanyl-L-valine from its two component amino acids is not an ideal method for its production.

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Taking into account the Charles' law, the temperature of the gas if the volume drops to 75.0 L is 246 K or -27 C.

Charles' law establishes the relationship between the temperature and the volume of a gas when the pressure is constant. This law says that for a given sum of gas at constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases. That is, the volume is directly proportional to the temperature of the gas.

Mathematically, Charles' law is a law that says that when the amount of gas and pressure remain constant, the ratio between volume and temperature will always have the same value:

\(\frac{V}{T}=k\)

Considering an initial state 1 and a final state 2, it is fulfilled:

\(\frac{V1}{T1}=\frac{V2}{T2}\)

In this case, you know:

Replacing in Charles's law:

\(\frac{100 L}{328 K}=\frac{75 L}{T2}\)

Solving:

\(T2x\frac{100 L}{328 K}=75 L\)

\(T2=\frac{75 L}{\frac{100 L}{328 K}}\)

T2= 246 K= -27 C

Finally, the temperature of the gas if the volume drops to 75.0 L is 246 K or -27 C.

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The percent composition of copper in CuCl2 is approximately 47.29%.

The molar mass of CuCl2 is approximately 134.45 g/mol (63.55 g/mol for copper + 2 x 35.45 g/mol for chlorine).

To calculate the percent composition of copper (Cu) in CuCl2, we need to determine the mass of copper in 1 mole of CuCl2.

The mass of copper in 1 mole of CuCl2 is 63.55 g/mol (the molar mass of copper).

So, the percent composition of copper in CuCl2 is:

(63.55 g Cu / 134.45 g CuCl2) x 100% = 47.29%

Therefore, the percent composition of copper in CuCl2 is approximately 47.29%.

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Answer:

I say 20 is ur best option

Answer: To find the wavelength of the photons emitted by hydrogen atoms when they undergo n = 4 to n = 2 transitions, we can use the Rydberg formula:

1/λ = R_H * (1/n1² - 1/n2²)
Where λ is the wavelength, R_H is the Rydberg constant for hydrogen (approximately 1.097 x 10^7 m^-1), n1 and n2 are the initial and final energy levels, respectively.

Explanation:

The formula used to determine the wavelength of light is known as the Rydberg formula. The energy of an electron changes when it transitions from one atomic orbit to another. The photon of light is produced when the electron transitions from a high-energy orbit to a lower-energy state. Additionally, the photon of light is absorbed by the atom when the electron transitions from a low energy to a higher energy state.

In this case, n1 = 2 and n2 = 4. Plugging the values into the formula, we get:

1/λ = (1.097 x 10^7) * (1/2² - 1/4²)

1/λ = (1.097 x 10^7) * (1/4 - 1/16)

1/λ = (1.097 x 10^7) * (12/64)

λ = 1 / (1.097 x 10^7 * 12/64)

λ ≈ 4.86 x 10^-7 m

Converting meters to nanometers (1 m = 1 x 10^9 nm):

λ ≈ 486 nm

The wavelength of the photons emitted by hydrogen atoms when they undergo n = 4 to n = 2 transitions is approximately 486 nm. This radiation occurs in the visible region of the electromagnetic spectrum.

Answer: The wavelength of the photons emitted by hydrogen atoms when they undergo n = 4 to n = 2 transitions is approximately 486 nm, and this radiation occurs in the visible region of the electromagnetic spectrum (option d).

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The pressure of \(N_{2}\) will rise under the given conditions. And, Yes, it is possible to reverse this tendency by adding \(H_{2}\). The minimum pressure of H2 required to reverse the tendency is 0.01 atm.

The reaction involved is: \(N_{2}\)(g) + 3\(H_{2}\)(g) ⇌ 2\(NH_{3}\)(g)  Hence, when \(H_{2}\) is added to the above system, the \(N_{2}\) and  \(H_{2}\)  will react to produce \(NH_{3}\). This reaction will reduce the amount of \(N_{2}\) present in the system, causing the pressure of \(N_{2}\) to decrease. Therefore, by adding \(H_{2}\)  , we can change the tendency of \(N_{2}\) pressure from rise to fall.To calculate the minimum pressure of  \(H_{2}\)  required to reverse the tendency, we have to use the equilibrium constant, Kp. The expression for Kp for the above reaction is: Kp =( \(NH_{3}\)) / p(\(N_{2}\)) p3( \(H_{2}\) )

At equilibrium, Kp = 1.7 × 104 at 1126 °C.Now, we will solve for the minimum pressure of \(H_{2}\)   needed to reverse the tendency. Let's assume that the pressure of \(N_{2}\) has increased by x atm. Therefore, the new pressure of \(N_{2}\) will be (0.0406 + x) atm. At equilibrium, we have:

p2(\(NH_{3}\) ) / p(\(N_{2}\)) p3( \(H_{2}\) ) = 1.7 × 104

On substituting the given values and simplifying, we get:

p2(\(NH_{3}\)) / p(N2) = 6.39 × 10-5

Now, p2(\(NH_{3}\)) = 5.97 atm, and p(\(N_{2}\)) = (0.0406 + x) atm.

On substituting these values, we get:5.97 / (0.0406 + x) = 6.39 × 10-5

Solving for x, we get:x = 0.00579 atm ≈ 0.01 atm (rounded to 2 significant digits)Therefore, the minimum pressure of \(H_{2}\)   required to reverse the tendency is 0.01 atm.

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The specific heat capacity of the metal on temperature change of 45.2°C is 0.0675 cal g\(^-1\)°C\(^-1\).

Specific heat capacity is defined as the amount of energy required to raise the temperature of one gram of substance by one degree Celsius. It has units of calories or joules per gram per degree Celsius.

It varies with temperature and is different for each state of matter. Water in the liquid form has the highest specific heat capacity among all common substances .Specific heat capacity of a substance is infinite as it undergoes phase transition ,it is highest for gases and can rise if the gas is allowed to expand.

It is given by the formula ,

Q=mcΔT

In the given example, mass= 87.01 g  , Δt=45.2°C=318.2 K ,c=1870 J

Substituting the values in the formula,

c=Q/mΔt

c=1870/87.01×318.2

c=0.0675 cal g\(^-1\) °C\(^-1\)

Hence, the specific heat capacity of metal is 0.0675 cal g\(^-1\) °C\(^-1\).

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Answer:

All living things use cellular respiration to turn organic molecules into energy. ... This process makes energy from food molecules available for the organism to carry out life processes. Cellular respiration usually occurs in the presence of oxygen. This is called aerobic respiration.

The preparation of lead (ii) sulphate from lead (ii) carbonate occurs in two steps:

Lead (ii) carbonate and  lead (ii) sulphate are both insoluble salts of lead.

In order to prepare lead (ii) sulphate, a two step process is performed.

In the first step, Lead (ii) carbonate is reacted with dilute trioxonitrate (v) acid to produce lead (ii) nitrate.

In the second step, dilute sulfuric acid is reacted with the lead (ii) nitrate to produce insoluble lead (ii) sulphate which is filtered and dried.

In conclusion, lead (ii) sulphate is prepared in two steps.

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Answer:

1s2 2s2 2p6 3s2 3p6 4s2 3d2

Explanation:

1s2 2s2 2p6 3s2 3p6 4s2 3d2

Answer:

Y

ou have learnt in your previous classes that the sour and bitter

tastes of food are due to acids and bases, respectively, present in them.

If someone in the family is suffering from a problem of acidity after

overeating, which of the following would you suggest as a remedy– lemon

juice, vinegar or baking soda solution?

n Which property did you think of while choosing the remedy?

Surely you must have used your knowledge about the ability of

acids and bases to nullify each other’s effect.

n Recall how we tested sour and bitter substances without tasting

them.

You already know that acids are sour in taste and change the colour

of blue litmus to red, whereas, bases are bitter and change the colour of

the red litmus to blue. Litmus is a natural indicator, turmeric is another

such indicator. Have you noticed that a stain of curry on a white cloth

becomes reddish-brown when soap, which is basic in nature, is scrubbed

on it? It turns yellow again when the cloth is washed with plenty of

water. You can also use synthetic indicators such as methyl orange and

phenolphthalein to test for acids and bases.

In this Chapter, we will study the reactions of acids and bases, how

acids and bases cancel out each other’s effects and many more interesting

things that we use and see in our day-to-day life. Do You Know?

Litmus solution is a purple dye, which is extracted from lichen, a plant belonging to

the division Thallophyta, and is commonly used as an indicator. When the litmus

solution is neither acidic nor basic, its colour is purple. There are many other natural

materials like red cabbage leaves, turmeric, coloured petals of some flowers such as

Hydrangea, Petunia and Geranium, which indicate the presence of acid or base in a

solution. These are called acid-base indicators or sometimes simply indicators.

2021–22

18 Science

2.1 UNDERSTANDING THE CHEMICAL PROPERTIES OF

ACIDS AND BASES

2.1.1 Acids and Bases in the Laboratory

Activity 2.1

These indicators tell us whether a substance is acidic or basic by

change in colour. There are some substances whose odour changes in

acidic or basic media. These are called olfactory indicators. Let us try

out some of these indicators.

Explanation:

Answer:

electrons have a negative charge

Explanation:

Answer:

Electrons

Explanation:

Answer:

runoff is he draining away of water (or substances carried in it) from the surface of an area of land, a building or structure, etc.

Explanation:

Answer:

Sure because of the gravity of the earth

Answer:

please make me brainalist and keep smiling dude I hope helped you

please thank all of my answer

Explanation: