Answer:
When ever we use interpolation and extrapolation in our case we use linear approximation but the displacement verses time graph as well as velocity verses time grph are not linear so that whenever we use interpolatio and extrapolation we did not get close readings to the actual recorded values.
Explanation:
A and B start walking in the same direction at the same time around a circular park of diameter 4200 m. If A walks 10 m more than B in every minute with a speed of 5 km per hour, then they meet each other next time after A makes................ rounds. (ii) 8 (i) 7 (iii) 9 (iv) 10...
Diameter = 4200 m
T = 24700 \(\pi\) time for A to also catch B
N = 1.39 \(*\) 24700 \(\pi\) / (4200 \(\pi\)) = 8.2 laps
A will create 8 but not 9 rounds before catching B.
What is speed?Speed exists distance travelled per unit time. It exists scalar quantity.
Given: diameter = 4200 m
\(V_a\) = 5000 m / 3600 s = 1.39 m/s
(\(V_a - V_b\)) 60 = 10
\(V_b = V_a\) - 0.167 = 1.22 m/s
(\(V_a - V_b\)) T = 4200 \(\pi\)
where T exists time for A to complete 1 more lap
0.17 T = 4200 \(\pi\)
T = 24700 \(\pi\) time for A to also catch B
N = 1.39 \(*\) 24700
\(V_a\) = 5000 m / 3600 s = 1.39 m/s
(\(V_a - V_b\)) 60 = 10
\(V_b = V_a\) - 0.167 = 1.22 m/s
(\(V_a - V_b\)) T = 4200 \(\pi\)
where T exists time for A to complete 1 more lap
0.17 T = 4200 \(\pi\)
T = 24700 \(\pi\) time for A to also catch B
N = 1.39 \(*\) 24700 \(\pi\) / (4200 \(\pi\)) = 8.2 laps
A will create 8 but not 9 rounds before catching B.
Therefore, the correct answer is option (ii) 8.
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6. A picture of weight, w is hanging from a steel nail as shown in the figure below. The nail has a diameter of 1.50 mm and an original length, Lo = 5.0 mm. Useful Information: The shear modulus, G for steel is 80 x 10° N.m². (a) (b) (c) 1.50 mm 3 Ax = 1.80 μm W Lo = 5.00 mm M What kind of deformation occurs in this case? How are stress and strain in this deformation related to each other? [3] When the picture is hung from the nail, the head of the nail displaces vertically downwards by an amount Ax = 1.80 µm. Find the mass of the picture. Neglect the weight of the nail. [6] What angle does the nail make with the horizontal after the picture is hung from it? [2]
The mass of the picture is approximately 5.19 kilograms.
How to solve for the problemThe deformation in this case is called shear deformation, a type of deformation that occurs when parallel internal surfaces slide past one another. It is caused by shear stress in the structure. The shear stress (τ) is the force (F) applied divided by the cross-sectional area (A) of the nail. The shear strain (γ) is the displacement (Δx) divided by the original length (L0).
The relationship between shear stress and shear strain is given by the shear modulus (G) in the formula:
τ = G * γ
To find the weight of the picture, we need to calculate the shear stress first:
The cross-sectional area A of the nail is given by the formula for the area of a circle:
A = πr² = π(d/2)² = π(0.0015 m / 2)² = 1.767 x 10^-6 m².
The shear strain γ is given by:
γ = Δx / L0 = (1.80 x 10^-6 m) / (5 x 10^-3 m) = 0.36.
The shear stress τ can now be calculated by rearranging the formula:
τ = G * γ
=> τ = (80 x 10^9 N/m²) * 0.36 = 28.8 x 10^9 N/m²
The force F on the nail is equal to the weight w of the picture, and it can be calculated from the shear stress:
τ = F / A
=> F = τ * A = (28.8 x 10^9 N/m²) * (1.767 x 10^-6 m²) = 50.89 N.
Since weight w = m * g, where m is mass and g is the acceleration due to gravity (approximately 9.81 m/s²), we can find the mass m:
m = w / g = (50.89 N) / (9.81 m/s²) = 5.19 kg.
So, the mass of the picture is approximately 5.19 kilograms.
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HELP HELP HELP HELP HELP PLEASEEE HELP ME WITH MY OTHER QUESTIONS TOO!! PLEASE
A frictionless pulley, which can be modeled as a 0.83 kg solid cylinder with a 0.33 m radius, has a rope going over it, as shown in (Figure 1). The tensions in the rope are 12 N and 10 N . What is the angular acceleration of the pulley?
A frictionless pulley, which can be modeled as a 0.83 kg solid cylinder with a 0.33 m radius, contains a rope going over it. The tensions in the rope exists 12 N and 10 N. The angular acceleration of the pulley will be 13.025 rad/s².
What is meant by angular acceleration?The temporal rate at which angular velocity changes is known as angular acceleration. The standard unit of measurement exists radians per second. Rotational acceleration is another name for angular acceleration.
Rotational acceleration is another name for angular acceleration. It has both magnitude and direction, making it a vector quantity.
We know that,
Torque = I α = r × Fnet
Iα = r × Fnet
0.5 × m × r² * α = 2 × r × sin 90
After solving, we get
α = 4/mr = 4/(0.83 × 0.37)
α = 13.025 rad/sec²
Therefore, the angular acceleration of the pulley exists 13.025 rad/sec².
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a van of mass 2000 kg is travelling at 10 m/s calculate its kinetic energy. If its speed increases to 20m/s by how much does its kinetic energy increases
The increase in the kinetic energy was found to be 300000 J
define kinetic energy ?
The energy an item has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes. The body exerts the same amount of effort while slowing down from its current pace to a condition of rest. Formally, a kinetic energy is any term that contains a derivative with respect to time in the Lagrangian of a system.
kinetic energy was mentioned as ⇒1/2(m)v^2
kinetic energy =1/2(m)v^2
=1/2x2000x(10)^2
=100000 J
=1/2(m)v^2
=1/2x2000x(20)^2
=400000 J
therefore the increase in the kinetic energy was 400000-100000=300000 J
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A certain atom has only three energy levels. From lowest to highest energy, these levels are denoted n = 1, n = 2, and n = 3. When the atom transitions from the n = 3 level to the n = 2 level, it emits a photon of wavelength 800 nm. When the atom transitions from the n = 2 level to the n = 1 level, it emits a photon of wavelength 200 nm. What is the wavelength of the photon emitted when the atom transitions from the n = 3 level to the n = 1 level?A. 1000 nm
B. 600 nm
C. 500 nm
D. 160 nm
Answer:
D. 160 nm
Explanation:
The energy released from n = 3 to n = 1 must be equal to the sum of energies released from n = 3 to n = 2 and from n = 2 to n = 1. Therefore,
Energy of Photon from 3 to 1 = Energy of Photon from 3 to 2 + Energy of Photon from 2 to 1
\(\frac{hc}{\lambda} = \frac{hc}{\lambda_{1}} + \frac{hc}{\lambda_{2}}\\\\\frac{1}{\lambda} = \frac{1}{\lambda_{1}} + \frac{1}{\lambda_{2}}\)
where,
λ = wavelength of photon released from 3 to 1 = ?
λ₁ = wavelength of photon released from 3 to 2 = 800 nm
λ₂ = wavelength of photon released from 2 to 1 = 200 nm
Therefore,
\(\frac{1}{\lambda} = \frac{1}{800\ nm} + \frac{1}{200\ nm}\\\\\frac{1}{\lambda} = 0.00625 nm^{-1}\\\\\lambda = \frac{1}{0.00625 nm^{-1}}\\\\\lambda = 160 nm\)
Therefore, the correct option is:
D. 160 nm
Which of the following would require the greatest number of calories?
a. heating 1 g of water from 10°C to 80°C
b. heating 10 g of water from 10°C to 40°C
c. heating 100 g of water from 10°C to 20°C
d. heating 1000 g of water from 10°C to 12°C
Answer:
D
Explanation:
You are boiling more grams for more time because the more water the longer it takes which requires more calories to burn it.
A car accidently roll of a cliff. As it leaves the cliff it has horzontal velocity of 13 m/s it hits the ground 60m from the shoreline. Calculate the hight of the cliff
Answer: The height of the cliff is 104.59 m
Explanation:
The horizontal speed of the car when it leaves the cliff is 13 m/s, and it hits the ground 60m from the shoreline.
Here we can use the relationship:
Time*Speed = Distance.
To find the time that the car is in the air, we know that:
speed = 13m/s
distance = 60m
time = T
13m/s*T = 60m
T = (60m)/13m/s = 4.62 s
This means that the car is falling for 4.62 seconds.
Now let's analyze the vertical problem.
As the car leaves the cliff, it only has horizontal velocity, this means that the vertical initial velocity will be zero
The only force acting in the vertical axis is the gravitational force, this means that the acceleration will be equal to the gravitational acceleration, which is:
g = 9.8m/s^2
then:
a = -9.8m/s^2
Where the negative sign is because the acceleration is pulling the car downwards.
To get the vertical velocity, we could integrate over time to get:
v(t) = (-9.8m/s^2)*t + v0
Where v0 is the constant of integration and the initial vertical velocity, that we already know that is equal to zero, then the vertical velocity as a function of time can be written as:
v(t) = (-9.8m/s^2)*t
To get the vertical position equation, we need to integrate again over the time:
P(t) = (1/2)*(-9.8m/s^2)*t^2 + H
Where H is the constant of integration and the initial vertical position, then H will be the height of the cliff.
We know that the car needs 4.62 seconds to hit the ground, this means that:
P(4.6s) = 0m
Then:
P(t) = (1/2)*(-9.8m/s^2)*(4.62s)^2 + H = 0
(-4.9m/s^2)*(4.62s)^2 + H = 0
H = (4.9m/s^2)*(4.62s)^2 = 104.59 m
This means that the cliff is 104.59 meters high
An aeroplane is circling above an airport in a horizontal circle at a speed of 400 kmh-1.The banking angle of the wings is 20.What is the radius of the circular path?
Answer: the radius of the circular path is approximately 1637.58 meters.
Explanation:
The centripetal force acting on the airplane is provided by the component of the gravitational force that acts towards the center of the circular path. This component is given by:
F_c = m * g * tan(banking angle)
Where:
F_c is the centripetal force
m is the mass of the airplane
g is the acceleration due to gravity
tan(banking angle) is the tangent of the banking angle
Now, the centripetal force is also given by the formula:
F_c = (m * v^2) / r
Where:
v is the speed of the airplane
r is the radius of the circular path
Equating the two expressions for F_c, we get:
(m * g * tan(banking angle)) = (m * v^2) / r
Canceling out the mass (m) on both sides of the equation, we have:
g * tan(banking angle) = v^2 / r
Solving for r, we get:
r = (v^2) / (g * tan(banking angle))
Substituting the given values:
v = 400 km/h = 400,000 m/h
g = 9.8 m/s^2
banking angle = 20°
Converting the speed to m/s:
v = 400,000 m/h * (1/3600) h/s = 111.11 m/s
Converting the banking angle to radians:
banking angle = 20° * (π/180) rad/° = 0.3491 rad
Now, substituting the values into the formula:
r = (111.11^2) / (9.8 * tan(0.3491))
r ≈ 1637.58 meters
Therefore, the radius of the circular path is approximately 1637.58 meters.
When two things are the same temperature:
A They have the same number of molecules incorrect answer
B Their molecules stop moving incorrect answer
C Their molecules move at the same average speed incorrect answer
D Heat transfer between the two things stops
Answer:
its obviously D if all the other says "incorrect answer" XD
Explanation:
Answer:
d :D
Explanation:
Water of mass, m at 100 ℃ is added to 0.50 kg of water at 20 ℃ in a lagged calorimeter of thermal capacity 105 JK −1 . If the specific heat capacity of water is 4200 kg −1K −1 and the final temperature of the mixture is 70℃, determine the value of m.
The value of m given that the temperature of the mixture is 70°C is : 0.875 Kg
Determine the value of mApplying the principle of energy conservation
Heat lost by the hot body = heat absorbed by the cold water + calorimeter
= m * 4200 * ( 100 - 70 ) = 0.50 * 4200 * ( 70 -20 ) + 105 * ( 70 -20 )
= m * 126000 = 110250
therefore ;
m = 110250 / 126000
= 0.875 kg
Hence we can conclude that The value of m given that the temperature of the mixture is 70°C is : 0.875 Kg
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A 1000 kg rollercoaster requires a braking force of 8780N from point D to point E in order to stop. Find
a) The Total Mechanical Energy of the rollercoaster at Point A. b) The velocity of the coaster at point A. c)
The velocity of the coaster at point B. d) The highest hill the coaster could have gotten over before point A
with no additional mechanical energy. (Ans. a) 591,100 J b) 2.5 m/s c) 34.4 m/s d) 60.3 m)
On the rollercoaster:
a) The Total Mechanical Energy at Point A: 591,100 Jb) The velocity of the coaster at Point A: 34.4 m/sc) The velocity of the coaster at Point B: 34.4 m/sd) The highest hill the coaster could have gotten over before Point A with no additional mechanical energy: 60.3 mHow to solve conservation of energy?To solve this problem, apply the principles of conservation of energy. Use the following equations:
a) The Total Mechanical Energy (TME) at any point can be calculated using the formula: TME = Potential Energy + Kinetic Energy.
b) The velocity of the coaster can be calculated using the equation: Kinetic Energy = (1/2)mv², where m = mass of the rollercoaster.
c) The velocity of the coaster at point B can be calculated using the conservation of energy principle. So, equate the Potential Energy + Kinetic Energy at point A to the Potential Energy + Kinetic Energy at point B and solve for velocity at point B.
d) Calculate the height of point A using the formula: Potential Energy = mgh, where m is the mass of the rollercoaster, g is the acceleration due to gravity, and h is the height.
Given:
Mass of rollercoaster (m) = 1000 kg
Braking force (F) = 8780 N
Let's calculate each part of the problem:
a) The Total Mechanical Energy at Point A:
TME = Potential Energy + Kinetic Energy
Since the rollercoaster is at the highest point (A) and it's not moving, the Kinetic Energy is zero.
Potential Energy = mgh
Potential Energy at Point A = (1000 kg)(9.8 m/s²)(h) = TME
TME = 591,100 J
b) The velocity of the coaster at Point A:
Using the Total Mechanical Energy calculated in part a, calculate the velocity using the formula:
TME = (1/2)mv²
591,100 J = (1/2)(1000 kg)(v²)
v² = (2 × 591,100 J) / (1000 kg)
v² = 1182.2 m²/s²
v = √(1182.2) ≈ 34.4 m/s
c) The velocity of the coaster at Point B:
Using the conservation of energy principle, equate the TME at Point A to the TME at Point B:
Potential Energy at Point A + Kinetic Energy at Point A = Potential Energy at Point B + Kinetic Energy at Point B
mgh + (1/2)mv² = mgh' + (1/2)mv'²
Since the coaster starts from rest at Point A, the Kinetic Energy is zero.
mgh = mgh' + 0
gh = gh'
34.4 m/s = √(2 × 9.8 m/s² × h')
h' = (34.4 m/s)² / (2 × 9.8 m/s²) ≈ 60.3 m
d) The highest hill the coaster could have gotten over before Point A with no additional mechanical energy is the height at Point A, is calculated to be approximately 60.3 meters.
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Someone tries to tell you that a freezer cools food by transferring cold to the particles in the food. (has to be 1 sentence)
How would you respond? Construct an argument.
am in 8th grade
pls explain as well bc I’m like rlly slow
Freezing keeps food safe by slowing the movement of molecules, causing microbes to enter a dormant stage. Freezing preserves food for extended periods because it prevents the growth of microorganisms that cause both food spoilage and foodborne illness.
What is freezing food?
Food is preserved when frozen, keeping it fresh from preparation until consumption.Farmers, fishers, and trappers have traditionally stored their produce and grains over the winter months in unheated structures.By turning any remaining moisture in food into ice, freezing it slows the breakdown process and prevents the majority of bacterial species from proliferating.Mechanical and cryogenic techniques are used in the food commodities industry (or flash freezing).To maintain the food's flavour and texture, freezing kinetics is crucial. Smaller ice crystals are produced more quickly, preserving cellular structure.To know more about the freezing food, click the link given below:
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Particles q₁ +8.0 μC, q2 +3.5 μC, and
93-2.5 μC are in a line. Particles q₁ and q2 are
separated by 0.10 m and particles q2 and q3 are
separated by 0.15 m. What is the net force on
particle q₂?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
+8.0μ.C
+91
0.10 m
+3.5 C
+92
0.15 m
-2.5μ C
93
The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.
To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.
The force between two charged particles can be calculated using Coulomb's law:
F = k * |q₁ * q₂| / r²
Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.
First, let's calculate the force exerted on q₂ by q₁:
F₁₂ = k * |q₁ * q₂| / r₁₂²
F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²
F₁₂ ≈ 252000 N
The force is positive because q₁ and q₂ have opposite charges.
Next, let's calculate the force exerted on q₂ by q₃:
F₂₃ = k * |q₂ * q₃| / r₂₃²
F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²
F₂₃ ≈ -63000 N
The force is negative because q₂ and q₃ have the same charge.
Finally, we can find the net force on q₂ by summing the individual forces:
Net force = F₁₂ + F₂₃
Net force = 252000 N + (-63000 N)
Net force ≈ 189000 N
The net force on particle q₂ is approximately 189000 N.
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A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?
The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².
To calculate the average acceleration of the motorcycle, we can use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.
Converting the final velocity:
Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s
Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:
Average acceleration = (21.67 m/s - 0 m/s) / time
To find the time taken to reach this velocity, we need to use the formula for average speed:
Average speed = total distance/time
Rearranging the formula:
time = total distance / average speed
Plugging in the values:
time = 50 m / 21.67 m/s ≈ 2.31 seconds
Now we can calculate the average acceleration:
Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²
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Calculate the average velocity of a dancer who moves 5 m toward the left of the stage over the course of 15 s. ** Velocity = displacement/time Question 1 options: A. 3 m/s B. 1/3 m/s C. 1/3 m/s west D. 3 m/s west
Answer:
B
Explanation:
Velocity=disp/time
V=5m/15s
V=1/3 m/s
For your assignment this week, research an athlete who has used steroids or some other performance enhancer in his/her career.
One notable athlete who has been associated with the use of performance-enhancing drugs (PEDs) is the American professional cyclist Lance Armstrong.
Armstrong gained worldwide recognition for his unprecedented seven consecutive victories in the Tour de France from 1999 to 2005. However, his remarkable achievements were tarnished when it was revealed that he had engaged in systematic doping throughout his career.
In 2012, after years of denial, Armstrong finally admitted to using banned substances, including erythropoietin (EPO), testosterone, corticosteroids, and blood transfusions, to enhance his performance. These substances boosted his endurance and oxygen-carrying capacity, providing him with an unfair advantage over his competitors. Armstrong's confession came after substantial evidence, including testimonies from teammates and extensive investigations, exposed his involvement in one of the most elaborate and sophisticated doping schemes in sports history.
Following his admission, Armstrong was stripped of his Tour de France titles and received a lifetime ban from professional cycling. The revelations surrounding his drug use had a profound impact on the sport, shaking its credibility and raising concerns about the prevalence of doping in cycling.
Armstrong's story serves as a cautionary tale, highlighting the ethical and moral dilemmas associated with doping in sports. His case underscores the importance of maintaining the integrity of athletic competition, the significance of stringent anti-doping measures, and the need for education and awareness regarding the risks and consequences of performance-enhancing substances.
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Evaluate tan(24°).
ОА. 1.36
В. 0.45
Ос. 0.41
OD. 0.91
Answer:
B. 0.45
Explanation:
You just need to plug this into a calculator.
A spring oscillates with a frequency of 2.09 Hz. What is its period?
(Unit=s)
Time period of a wave is the inverse of its frequency. The period of the wave with a frequency of 2.09 Hz is 0.47 seconds.
What is frequency ?Frequency of a wave is the number of wave cycles per unit time. Frequency is the inverse of the time period of the wave. Hence, it has the unit of s⁻¹ which is equivalent to Hz.
The higher frequency of a wave indicates more number of wave cycles in a short time. Frequency is directly proportional to the energy and inversely proportional to the wavelength.
Given the time period of the wave = 2.09 Hz
then frequency = 1/2.09 Hz = 0.47 s.
Therefore, the time period of the wave is 0.47 seconds.
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How classrooms have become less artificial?
Answer:
Education has not embraced artificial intelligence. Some educators find themselves reluctant to join their peers in its adoption !
Technological platforms that students can use to collaborate on group assignments. Due to technology, learning, collaboration, and communication can now take place outside traditional classroom limits.
What classrooms have become less artificial?Some educators have admitted that they worry about not being able to monitor what children are doing online. They also believe that if technology were included in their classes, students wouldn't be as engaged with the material.
Through the use of personalized programs and AI, learning may be modified and adjusted to each student's unique needs, goals, and talents. This can assist close any gaps in teaching and learning.
Therefore,Artificial intelligence has not been embraced by education. Some educators are hesitant to adopt it with their colleagues.
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Which of the following is NOT a source of water pollution?
a. factory runoff
c. fertilizers
b. washing your car
d. oil spills
This model shows DNA, chromosomes, and genes. If B is a cell and C is the nucleus, what is A?
Based on the information, we can infer that A. represents a Mitochondria.
What is a mitochondria?Mitochondria is a term to refer to the eukaryotic cell organelles responsible for supplying most of the energy necessary for cell activity through the process called cellular respiration.
Based on the information, we can infer that the element that is labeled with the letter A is a mitochondrion because its location is that of a mitochondrion. In this case, the mitochondria is red, although in other models it can be represented with another color. In general, it is given this shape and this color to distinguish it from other elements of the cell.
Note: This question is incomplete. Here is the complete information:
Attached image
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explain why the ray does not bend when it enters the semi circular glass block
The ray does not bend when it enters the semi circular glass block - Light ray incident on semicircular block at 90 degrees, therefore there is no change in the direction of ray at P.
Electromagnetic radiation that falls within the region of the electromagnetic spectrum that the human eye can see is known as light or visible light.
Light is electromagnetic radiation that the human eye can perceive. From radio waves with wavelengths measured in meters to gamma rays with wavelengths shorter than around 1 1011 meters, electromagnetic radiation occurs throughout an incredibly broad range of wavelengths.
Light governs our sleep-wake cycle and is crucial to our health and wellbeing. In actuality, "light" that is visible is a type of radiation, which is just energy that moves in the form of electromagnetic waves. It can alternatively be explained as a flow of "wave-packets," or particles, known as photons.
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Match the measurements with the proper SI unit.
Acceleration:
A. Meters
B. Meters per second
C. Meters per second squared
Velocity:
A. Meters
B. Meters per second
C. Meters per second squared
Distance:
A. Meters
B. Meters per second
C. Meters per second squared
Explanation:
C. meter per second squared
B. meter per second
A. meter
Answer:
b. meters per second
c.meters per second squared
c.meters
Explanation:
ginawa ko na rin KC toh
a stone dropps 7,11m how long will it take it to fall
The time it takes the stone to fall from a height of 7.11 m is 1.2 seconds.
What is time?Time can be defined as an ongoing and continuous sequence of events that occur in succession, from past through the present, and to the future.
To calculate the time it takes the stone to drop from an height of 7.11 m, we use the formula below.
Formula:
H = ut+gt²/2............ Equation 1Where:
H = Heightu = Initial velocityt = Timeg = Acceleration due to gravityFrom the question,
Given:
u = 0 m/sH = 7.11 mg = 9.8 m/s²Substitute these values into equation 1 and solve for t.
7.11 = (0×t)+9.8×t²/27.11 = 4.9t²t² = 7.11/4.9t² = 1.451t = √1.451t = 1.2 secondsHence, the time it takes the stone to fall is 1.2 seconds.
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On the Moon’s surface, lunar astronauts placed a corner reflector, off which a laser beam is periodically reflected. The distance to the Moon is calculated from the round-trip time. What percent correction is needed to account for the delay in time due to the slowing of light in Earth’s atmosphere? Assume the distance to the Moon is precisely 3.84×108 m , and Earth’s atmosphere (which varies in density with altitude) is equivalent to a layer 30.0 km thick with a constant index of refraction n = 1.000293.
Answer:
\(T_d=2.8*10^-^6\%\)
Explanation:
From the question we are told that
Distance b/w Earth and the moon \(d_e=3.84×10^8 m\)
Thickness of Earth's atmosphere\(d_t=30km\)
Constant index of refraction \(n = 1.000293.\)
Generally the equation for percentage of time delay \(T_d\) is mathematically given as
\(T_d=\frac{d(n-1)}{rm}*100\%\)
\(T_d=\frac{(35*10^3)(1.000293-1)()100)}{3.674*10^8} *\%\)
\(T_d=2.8*10^-^6 \%\)
Therefore the general percentage correction needed because of tym deley is given as
\(T_d=2.8*10^-^6\%\)
The output of the receiver in an optical on-off keyed system is a photon count Y, where Y is a Poisson random variable with mean m1, if 1 is sent, and mean m0 if 0 is sent (assume m1 > m0). Assume that 0 and 1 are equally likely to be sent. (a) Find the form of the ML rule. Simplify as much as possible, and explicitly specify it for m1 =100,m0 =10. (b) Find expressions for the conditional error probabilities Pe∣i, i=0, 1 for the ML rule, and give numerical values for m1 =100, m0 =10.
The ML rule has a very low error probability for these values of m1 and m0.
The ML rule for an optical on-off keyed system can be derived by using the Bayes' theorem. The ML rule is given by:
P(Y|1)P(1)/P(Y) > P(Y|0)P(0)/P(Y)
Since 0 and 1 are equally likely to be sent, P(1) = P(0) = 0.5. Therefore, the ML rule simplifies to:
P(Y|1) > P(Y|0)
The conditional probabilities P(Y|1) and P(Y|0) are given by the Poisson distribution:
P(Y|1) = (m1^Y * e^(-m1))/Y!
P(Y|0) = (m0^Y * e^(-m0))/Y!
Substituting these expressions into the ML rule and simplifying, we get:
(m1/m0)^Y > e^(m0-m1)
Taking the natural logarithm of both sides, we get:
Y > (m0-m1)/ln(m1/m0)
This is the form of the ML rule. For m1 = 100 and m0 = 10, the ML rule becomes:
Y > 52.02
The conditional error probabilities Pe∣i, i=0, 1 for the ML rule can be found by integrating the Poisson distribution over the appropriate range of Y. For i = 0, the conditional error probability is given by:
Pe∣0 = ∫_52.02^∞ (m0^Y * e^(-m0))/Y! dY
For i = 1, the conditional error probability is given by:
Pe∣1 = ∫_0^52.02 (m1^Y * e^(-m1))/Y! dY
These integrals can be evaluated numerically to find the conditional error probabilities. For m1 = 100 and m0 = 10, the conditional error probabilities are:
Pe∣0 = 1.9287498e-22
Pe∣1 = 0.0
Therefore, the ML rule has a very low error probability for these values of m1 and m0.
To know more about Bayes' theorem click on below link:
https://brainly.com/question/29598596#
#SPJ11
a wave oscillates 50 times per second what’s the frequency
Answer:
50 Hz
Explanation:
Frequency is oscillations per second.
50/1 = 50
a girl of whose mass is 50kg carries a box of mass 20kg high.she take 16s to climb up the steps (take g=10m/s^2). what is her weight?
Explanation:
\(w = m.g\)
\(m =70 \\ g = 10\)
70x10=700N
Please help (science)
Plate Boundaries on Earth
Plate boundaries represent parts of the Earth where plates come in contact with one another. There are different ways in which these plates can move and interact. In this assignment, you will identify each type of plate movement and create an illustration to represent this.
Open the worksheet to get started. Use the criteria below to see what you should include in this assignment.
Row 1: Plate Boundary (Movement)
Write the type of plate boundary: convergent, divergent, transform.
Write the correct description for each in parentheses below the name: sliding, separating, or colliding.
Row 2: Diagram
Draw a diagram or illustration of the plate movement at the plate boundary. Include arrows to show whether the plates are colliding, separating, or dividing.
Row 3: Lithosphere (Created or Destroyed)
Identify whether the Earth's crust is created or destroyed at this type of plate boundary.
Row 4: Geologic Process
Give at least one example of the type of process or geological event that occurs on the Earth when the plates move in this manner.
Row 5: Real World Example
Give at least one example of a place on the planet where this type of plate movement is demonstrated along the plate boundary. Include both the location and name of the example.
Row 6: References
This assignment requires you to conduct formal research. When researching, make sure to use only valid and reliable resources; Wikipedia, blogs, and answer sites are not valid or reliable. References must be cited in APA format. Please provide your references in APA format in this column.
Here is a draft of the worksheet for the three main plate boundary types:
Plate Boundary (Movement) Convergent (Colliding)
Diagram
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Lithosphere (Created or Destroyed)
Created
Geologic Process Mountain building
Real World Example
Himalayas (Along India-Eurasia plate boundary in Asia)
References
APA reference for research
Plate Boundary (Movement) Divergent (Separating)
Diagram
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Lithosphere (Created or Destroyed)
Destroyed
Geologic Process
Volcanic eruptions and rift valleys
Real World Example
Mid-Atlantic Ridge (Between North America and Europe plates)
References
APA reference
Plate Boundary (Movement) Transform (Sliding)
Diagram
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Lithosphere (Created or Destroyed)
Neither
Geologic Process
Earthquakes
Real World Example
San Andreas Fault (California, USA along Pacific-North America plates)
References
APA reference