Part of the population of 5,000 elk at a wildlife preserve is infected with a parasite. A random sample of 50

elk shows that 11 of them are infected. How many elk are likely to be infected?

Based on the sample, there will likely be

infected elk in the wildlife preserve.

Answer:

SA = 10,800 ft²

Step-by-step explanation:

To find the surface area of a rectangular prism, you can use the equation:

SA = 2 ( wl + hl + hw )

SA = surface area of rectangular prism

l = length

w = width

h = height

In the image, we are given the following information:

l = 40

w = 60

h = 30

Now, let's plug in the information given to us to solve for surface area:

SA = 2 ( wl + hl + hw)

SA = 2 ( 60(40) + 30(40) + 30(60) )

SA = 2 ( 2400 + 1200 + 1800 )

SA = 2 ( 5400 )

SA = 10,800 ft²

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3.1, 3.6, 4.2, 4.5, 4.9, 5.0

First, order the numbers with the lowest one's value. Then, order numbers within the category from lowest to highest tenth place.

Answer:The sum of A and B is the result of adding A to B, as opposed to something like the product of A and B, which would be multiplying A and B

Step-by-step explanation:

Trapezoid is the quadrilateral with only one pair of opposite parallel sides.

A quadrilateral is a closed shape and a type of polygon that has four sides, four vertices and four angles.

Given that, each of the quadrilaterals noted below has two pairs of parallel sides as one of its properties.

Trapezoid is a quadrilateral having base angles equal and one pair of opposite sides are parallel.

Hence, the correct option is Trapezoid.

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Answer:

Its 8 and 2

Step-by-step explan

The area of a shape is the amount of space it occupies.

The values of H and the length of the missing shorter base are: \(\mathbf{H = 8\ and\ B =2}\)

The given parameters are:

\(\mathbf{Area = 40cm^2}\)

\(\mathbf{Base_1 = 8cm}\)

The area of a trapezoid is:

\(\mathbf{Area = \frac 12 \times (Base_1 + Base_2) \times Height}\)

Substitute known values

\(\mathbf{40= \frac 12 \times (8 + Base_2) \times Height}\)

Multiply through by 2

\(\mathbf{80= (8 + Base_2) \times Height}\)

Make Height the subject

\(\mathbf{Height = \frac{80}{(8 + Base_2) }}\)

Now, we make use of trial by error.

Let:  \(\mathbf{Base_2 =1}\)

So:

\(\mathbf{Height = \frac{80}{(8 + 1)} = \frac{80}{9} = 8.89}\)

The above result is not a whole number.

Let: \(\mathbf{Base_2 =2}\)

So:

\(\mathbf{Height = \frac{80}{(8 + 2)} = \frac{80}{10} = 8}\)

The above result is a whole number.

So, the values of H and the length of the missing shorter base are:

\(\mathbf{H = 8\ and\ B =2}\)

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The equation of the plane passing through point P and perpendicular to line g is:

r + 11 = 0, or equivalently,

x + y + z + 11 = 0

To find the equation of the plane passing through point P and perpendicular to line g, we need to first find the direction vector of line g.

From the equations of line g, we can see that it is the intersection of two planes:

-x + 2y + z - 9 = 0   ----- (1)

3x + y - 4z + 7 = 0   ----- (2)

To find the direction vector of line g, we can take the cross product of the normal vectors of the two planes. The normal vectors of the planes are given by the coefficients of x, y, and z in their equations. Thus, the normal vectors of the two planes are:

Plane (1): (-1, 2, 1)

Plane (2): (3, 1, -4)

Taking the cross product of these two vectors gives us the direction vector of line g:

(3, 13, 7)

Now, let's find the coordinates of point P. We know that point P lies on the plane 3x-2y+z+ 11 = 0, so we can substitute this equation into the general equation of a line:

x = t

y = 2t - 5

z = -3t - 2

Substituting these values into the equation of the plane gives:

3(t) - 2(2t-5) + (-3t-2) + 11 = 0

Simplifying this equation gives us:

-t + 1 = 0

So t = 1, which means that the coordinates of point P are:

P(1, -3, -5)

Now, we have the coordinates of point P and the direction vector of line g. To find the equation of the plane passing through point P and perpendicular to line g, we can use the point-normal form of the equation of a plane, which is:

n · (r - r0) = 0

where n is the normal vector of the plane, r is the position vector of any point on the plane, and r0 is the position vector of a known point on the plane (in this case, point P).

We know that the normal vector of the desired plane must be perpendicular to the direction vector of line g. Therefore, we can take the cross product of the direction vector of line g with any other vector to get a vector that is perpendicular to it. Let's use the vector (1, 0, 0):

(3, 13, 7) × (1, 0, 0) = (0, 7, -13)

So the normal vector of the plane passing through point P and perpendicular to line g is (0, 7, -13). Substituting this vector and the coordinates of point P into the point-normal form of the equation of a plane gives us:

(0, 7, -13) · (r - <1, -3, -5>) = 0

Expanding the dot product gives us:

0(r - 1) + 7(r + 3) - 13(r + 5) = 0

Simplifying this equation gives us:

-6r - 66 = 0

Dividing both sides by -6 gives us:

r + 11 = 0

So the equation of the plane passing through point P and perpendicular to line g is:

r + 11 = 0, or equivalently,

x + y + z + 11 = 0

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Answer:

Your answer (x + 4)2 =-11 x + 4)2 13 x + 4)221 Correct answer.

Answer:

The tatal budget of what, there's no budget the budget down so I can do the problem.

Answer:

A. r = -0.93

Step-by-step explanation:

First, if there is a negative correlation, the correlation coefficient will be negative.

This eliminates answer choices C and D, which are positive.

If there is a strong correlation, the correlation coefficient will be closer to 1, or -1 (since the correlation is negative).

Since -0.93 is closer than -0.23 to 1, it has a stronger correlation.

So, the correct answer is A. r = -0.93

With the $10 gift card, Jose can buy at most 8 songs

x(the number of songs) less than or equal to 8

Answer:

With the $10 gift card, Jose can buy at most 8 songs

Step-by-step explanation:

trust the process

The correlation coefficient of 0.49 indicates a moderate positive relationship between study times and test scores. This suggests that as study times increase, there is a tendency for test scores to also increase. However, the relationship is not extremely strong.

The correlation coefficient, denoted by 'r', ranges from -1 to 1. A positive value indicates a positive relationship, meaning that as one variable increases, the other tends to increase as well. In this case, the correlation coefficient of 0.49 indicates a moderate positive relationship between study times and test scores.

It's important to note that the correlation coefficient of 0.49 falls between 0 and 1, closer to 1. This suggests that there is a tendency for test scores to increase as study times increase, but the relationship is not extremely strong. Other factors may also influence test scores, and the correlation coefficient does not imply causation.

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The expected activity time for the given statement is = 5.33

The average amount of time required for an activity when it is repeatedly performed is known as the expected time. The weighted average of the three estimated times, i.e., the optimistic time, the most probable time, and the pessimistic time, is used in project management analysis to determine the expected time of activity.

A network model called the Program Evaluation and Review Technique (PERT) allows for randomness in the timing of activity completion. PERT was created in the late 1950s again for a massively labor-intensive Polaris project for the US Navy. It might shorten a lot of time and cost needed to finish a project.

optimistic = 2

most likely = 5

pessimistic = 10.

We will use the following formula to calculate the anticipated time for each activity in order to solve this problem:

Expected Time = (Optimistic Time + (4 x Most likely) + Pessimistic Time) / 6

Putting the values into formula:

= (2 + (4 x 5) + 10)/ 6

= (2 + 20 + 10) / 6

= 5.33

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Answer:

Year 3 and year 4 and the percentage is 8%

Step-by-step explanation:

Because it grown by 8

Answer:

It won't because the area is length times height. So 11 x 11. So some of the car will be hanging out of the garage.

Step-by-step explanation:

Answer:

what we have to do with this please ask complete question

Answer:

it is the abstract science of number, quantity and space, either as abstract concept

Answer:

Step-by-step explanation:

Given system:

Solve by elimination, multiply the first equation by 5 and add up equations:

Find y:

Answer:

x = 4

y = 2

Step-by-step explanation:

Rewrite  x + y = 6  to make y the subject:  

⇒ y = 6 - x

Substitute y = 6 - x   into  6x - 5y = 14  and solve for x:

⇒ 6x - 5(6 - x) = 14

⇒ 6x - 30 + 5x = 14

⇒ 11x - 30 = 14

⇒ 11x = 44

⇒ x = 4

Substitute  x = 4  into  x + y = 6  and solve for y:

⇒ 4 + y = 6

⇒ y = 2

Answer:

Step-by-step explanation:

To solve the given equation \(\sf x - y = 4 \\\), we can perform the following calculations:

a) To find the value of \(\sf 3(x - y) \\\):

\(\sf 3(x - y) = 3 \cdot 4 = 12 \\\)

b) To find the value of \(\sf 6x - 6y \\\):

\(\sf 6x - 6y = 6(x - y) = 6 \cdot 4 = 24 \\\)

c) To find the value of \(\sf y - x \\\):

\(\sf y - x = - (x - y) = -4 \\\)

Therefore:

a) The value of \(\sf 3(x - y) \\\) is 12.

b) The value of \(\sf 6x - 6y \\\) is 24.

c) The value of \(\sf y - x \\\) is -4.

\(\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}\)

♥️ \(\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)

Answer:

4 i hope that helps

After solving, the test statistic value of z is -2.65.

In the given question,

Sample Mean x=264.4

Population standard deviation σ=20

sample size (n) = 25

significance level α=0.05

To test  Jean's claim that Jack's driving distance is less than 275 yards

The null and alternative hypothesis are

H(0): μ=275

H(α): μ<275

Test Statistic Z is:

Z = (x-μ)/(σ/√n)

Z = (264.4-275)/(20/√25)

Z = -10.6/(20/5)

Z = -10.6/4

Z = -2.65

Hence, the test statistic value of z is -2.65.

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The right question is:

Jack tells Jean that his average drive of a golf ball is 275 yards. Jean is skeptical, she thinks he has overstated is driving distance and asks for substantiation. So Jack takes a random sample of 25 of his drives. The mean of this sample is 264.4 yards. His driving distance is known to be normally distributed with a population standard deviation of 20 yards. Test Jean's claim that Jack's driving distance is less than 275 yards at a 0.05 significance level. Calculate the test statistic to 2 decimal places.

Total price

\(\\ \rm\longmapsto 0.065(17)+17\)

\(\\ \rm\longmapsto 17+1.105\)

\(\\ \rm\longmapsto 18.11\)

Step-by-step explanation:

To calculate the minimum number of days required to finish this project, we need to use the critical path method (CPM), which involves identifying the longest sequence of dependent tasks and their durations.

First, we need to draw the network diagram for the project:

```

|---(T1-8)---(T3-10)---|

(T2-6) (T5-12)

| / |

|---(T4-7)---(T6-15)---|

```

Next, we need to calculate the earliest start time (EST), earliest finish time (EFT), latest start time (LST), and latest finish time (LFT) for each task. For the starting task, EST = 0 and EFT = 0.

```

EST EFT LST LFT

T1 (8 days) 0 8 22 30

T2 (6 days) 0 6 6 12

T3 (10 days) 8 18 22 32

T4 (7 days) 18 25 25 32

T5 (12 days) 18 30 32 44

T6 (15 days) 32 47 32 47

```

The critical path is the longest sequence of dependent tasks that have no slack (i.e., the difference between LST and EST, or LFT and EFT, is zero). In this case, the critical path is T1-T3-T5-T6.

Therefore, the minimum number of days to finish this project is the sum of the durations of tasks on the critical path:

8 + 10 + 12 + 15 = 45 days

Therefore, the minimum number of days required to finish this project is 45 days.

1. The parse tree for the statement D = 24 * 21 + T + Y is:

       D

      /|\

     / | \

    *  +  +

   / \    \

  24  21   +

          / \

         T   Y

2. The parse tree for the statement C = 10(T + 11) / 40 is:

       C

      /|\

     /= \

    /   \

   /     \

  /       \

 *        40

/ \

10  +

  / \

 T  11

3. The parse tree for the statement A = 10 % 2 is:

      A

     /|\

    /= \

   /   \

  /     \

 %       2

/ \

10  2

1. For the statement D = 24 * 21 + T + Y, the parse tree represents the order of operations. First, the multiplication of 24 and 21 is performed, and the result is added to T and Y. The parse tree shows that the multiplication operation (*) is at the top, followed by the addition operations (+) and the variables T and Y.

2. For the statement C = 10(T + 11) / 40, the parse tree represents the order of operations and the grouping of terms. Inside the parentheses, the addition of T and 11 is performed, and then the result is multiplied by 10. Finally, the division by 40 is performed. The parse tree shows the multiplication operation (*) at the top, followed by the division operation (/) and the variables T and 11.

3. For the statement A = 10 % 2, the parse tree represents the modulo operation (%) between 10 and 2. The parse tree shows the modulo operation at the top, with the operands 10 and 2 as its children.

Parse trees provide a graphical representation of the syntactic structure of a statement or expression, showing the relationships between the operators and operands. They are useful for understanding the order of operations and the grouping of terms in mathematical expressions.

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Answer:

There is no graph attached but it would look like this

Stratified random sampling was the technique employed by Homer to choose his sample.

Given case;

Homer Simpson is fascinated with the proportion of the different sprinkled colors on lard lad doughnuts. Homer buys three of each type of donut they produce and counts the sprinkles on them to perform his research.

The method did homer use to select his sample is stratified random sampling. Because each variety is a stratum.

From there 3 3 samples are collected.

Stratified random sampling:

A crucial aspect of the sampling strategy known as stratified random sampling is the stratification of a population into smaller subgroups known as strata. During stratified random sampling, the strata are created based on the shared traits or features of the participants, such as level of education or income. Numerous uses and advantages of stratified random sampling include examining life expectancy and population demography.

The terms proportionate random sampling and quota random sampling are also used to describe stratified random sampling.

The method did homer use to select his sample is stratified random sampling.

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Answer:

Solution,

\(f(x) = - 4 {x}^{2} + 5x \\ f(6) = - 4 \times {6}^{2} + 5 \times 6 \\ \: \: \: \: \: \: = - 4 \times 36 + 30 \\ \: \: \: = - 144 + 30 \\ \: \: \: - 114\)

hope this helps.

Good luck on your assignment..

Answer:

-114

Step-by-step explanation:

To find f(6), you need to plug in the value in parentheses wherever there is an x in the equation.

f(x) = -4x + 5x

f(6) = -4(6) + 5(6)

f(6) = -4(36) + 30

f(6) = -144 + 30

f(6) = -114

The answer is -114.