Perform the following
mathematical operation, and
report the answer to the correct number of significant figures.

7.68 x 4.564 = [?]

Answer:

b

Explanation:

.

Answer: performing experiments that use specific materials or processes with known characteristics.

Explanation:

Independent variable was temperature, dependent variable was was reaction rate and other factors was constant.

Changes in the dependent variable have no effect on an independent variable. When studying the effect of temperature on photosynthesis, for example, temperature is the independent variable because it is not reliant on photosynthetic rate.Because temperature changes the rate of reaction, the reaction rate is the dependent variable. When carrying out the experiment, make sure that other factors that affect the pace of reaction, such as reactant concentration, are kept constant.

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Answer:

During steps 2–5, the

✔ temperature

was the independent variable and the

✔ reaction rate

was the dependent variable. The other factors were

✔ constant

Explanation:

The Van't Hoff factor is the ratio of the concentration of particles in an ideal solution to the concentration of particles in a real solution. The ideal value of the Van't Hoff factor for aqueous solutions is as follows:
- C12H22O11: 2
- Na2SO4: 3
- CaCl2: 3
- NaCl: 2
- NH4Cl: 5

This is because the Van't Hoff factor is determined by the number of ions each solute releases when dissolved in water. C12H22O11 dissociates into two ions, Na2SO4 dissociates into three ions, CaCl2 dissociates into three ions, NaCl dissociates into two ions, and NH4Cl dissociates into five ions.The Van't Hoff factor can be defined as the ratio of the concentration of particles formed when a substance is dissolved to the concentration of the substance by mass. The extent to which a substance associates or dissociates in a solution is described by the Van't Hoff factor.

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Answer:

A.) Longer and Shorter

Explanation:

If the wavelength of a light wave is shorter that means the frequency will be higher.

That means that longer wavelengths have a lower frequency.

Answer:

C: Mg

Explanation:

Hybridization of atomic orbitals is a fundamental concept introduced by Pauling that describes the mixing of orbitals at an atom which adds a definite direction to the Lewis - shared electron pair or electron chemical - bond concept.

Carbon(C) can hybridized on sp, sp2 and sp3 simply because it's valence shell gives room for it.

For silicon(si), when forming covalent bonds with other atoms, it's 3s and 3p orbitals are mixed with each other to form new hybrid orbitals.

Magnesium in itself doesn't hybridized except in magnesium hydrides.

Boron orbitals(B): when boron forms bonds with three other atoms like borazine, they are hybridized to either the sp2 or hybridized to the sp3 which occurs when boron forms bonds with four atoms just as is in metal borohydrides.

Answer:   This is an acid-base reaction (neutralization): Ca(OH) 2 is a base, CO 2 is an acid. ; White, odorless powder. [Note: Readily absorbs CO2 from the air to form calcium carbonate.]

Explanation:

Answer:

-113.2 kJ/mol

Explanation:

(-1207-285.8)-(-981.1-393.5)= -133.2

(Products)-(Reactants)= Answer

Answer:

Heat transferred, Q = 1542.42 J

Explanation:

Given that,

Mass of water, m = 30 grams

Initial temperature, \(T_i=25^{\circ} C\)

Final temperature, \(T_f=12.7^{\circ} C\)

We need to find the energy transferred. The energy transferred is given by :

\(Q=mc\Delta T\)

c is specific heat of water, c = 4.18 J/g °C

So,

\(Q=30\ g\times 4.18\ J/g-^{\circ} C\times (12.7-25)\ ^{\circ} C\\\\Q=-1542.42\ J\)

So, 1542.42 J of energy is transferred.

The total mass of sodium chloride is 58.44 g/mol.

The mass of sodium is 22.99 g/mol.

To find the percent sodium in sodium chloride can be found by dividing the amounts.

Therefore, the percent sodium is 39%.

Explanation:

she could waited for the saturated vapour pressure to equal the prevailing atmospheric pressure

ergo boiling to take place seeing as she had gotten the first indication that boiling had started

Answer:

hey yk me from pad let

Explanation:

Answer:

i think the answer is D

Explanation:

Answer:

C: O2

Explanation:

Hope it helps

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The amount of air required to burn 1 gram of paper is 17.22 grams. This is because paper is made up of pure cellulose which is a compound of 6 carbon atoms, 10 hydrogen atoms, and 5 oxygen atoms (C6H10O5).

To burn this compound, the oxygen from the air must combine with the carbon and hydrogen atoms from the paper. For every 1 mole of C6H10O5, 12 moles of oxygen are required.

Since 1 mole of oxygen has a mass of 32 grams, 12 moles of oxygen would have a mass of 384 grams.

Since 1 gram of paper has 1 mole of C6H10O5, 384 grams of oxygen is required to burn 1 gram of paper.

Since air is composed of approximately 21% oxygen, the amount of air required to burn 1 gram of paper is 17.22 grams (384/21 = 17.22).

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Answer:it is a stable element

Explanation:because it has six stable isotopes

The maximum mass of lead that can be obtained by the reaction of 57.33 g PbO and 33.80 g of PbS is 58.4 g.

To answer this question, we need to use the balanced chemical equation for the reaction between lead (II) oxide (PbO) and lead (II) sulfide (PbS):

PbO + PbS → 2Pb + SO\(^{2}\)

According to the equation, one mole of PbO reacts with one mole of PbS to produce two moles of lead (Pb) and one mole of sulfur dioxide (SO\(^{2}\)). We can use this information to calculate the theoretical yield of lead from the given amounts of PbO and PbS.

First, we need to convert the masses of PbO and PbS to moles. The molar mass of PbO is 223.20 g/mol, so 57.33 g PbO is equal to 0.257 mol. The molar mass of PbS is 239.27 g/mol, so 33.80 g PbS is equal to 0.141 mol.

Next, we need to determine which reactant is limiting, i.e. which one will be completely consumed in the reaction. We can do this by calculating the number of moles of each reactant needed to produce the same amount of product. Since the ratio of PbO to PbS in the balanced equation is 1:1, we can compare the number of moles of each:

- PbO: 0.257 mol × (1 mol Pb / 1 mol PbO) = 0.257 mol Pb
- PbS: 0.141 mol × (1 mol Pb / 1 mol PbS) = 0.141 mol Pb

Since PbS is the limiting reactant (i.e. there is less of it than PbO), we will use its moles to calculate the theoretical yield of lead.

According to the equation, 1 mole of PbS produces 2 moles of Pb, so:

0.141 mol PbS × (2 mol Pb / 1 mol PbS) = 0.282 mol Pb

Finally, we can convert the moles of Pb to grams using the molar mass of Pb, which is 207.2 g/mol:

0.282 mol Pb × (207.2 g Pb / 1 mol Pb) = 58.4 g Pb

Therefore, 58.4 g is the maximum mass of lead that can be obtained by the reaction of 57.33 g PbO and 33.80 g PbS.

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Answer:

Climatology

Explanation:

Climatology is the study of climate and how it changes over time. This science helps people better understand the atmospheric conditions that cause weather patterns and temperature changes over time.

1. The approximate percent of water in the hydrate is 16%

2. The value of x in the hydrate is 2

Mass of hydrate, SnCl₂•xH₂O = 0.366 g

Mass of water, H₂O = 0.0586 g

Percentage of water =?

Percentage = (mass of water / mass of hydrate) ×100

Percentage of water = (0.0586 / 0.366) × 100

Percentage of water = 16%

To obtain the value of x, we shall determine the formula of the hydrate. This can be obtained as follow:

Divide by their molar mass

SnCl₂ = 0.3074 / 190 = 0.0016

H₂O = 0.0586 / 18 = 0.0032

Divide by the smallest

SnCl₂ = 0.0016 / 0.0016 = 1

H₂O = 0.0032 / 0.0016 = 2

Thus, the formula of the hydrate is SnCl₂•2H₂O

Comparing the formula of the hydrate (SnCl₂•2H₂O) with SnCl₂•xH₂O, we can see that the value of x is 2

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Among the given options, SO2, SO3, and SO32- can exhibit delocalized bonding.

Delocalized bonding is a type of bonding where the electrons are not localized between two atoms but rather are shared among multiple atoms in a molecule. This type of bonding is characterized by the presence of resonance structures and is commonly observed in molecules that contain pi bonds.

SO2 has a bent structure with a lone pair of electrons on the sulfur atom. The double bond between sulfur and oxygen involves the overlap of a p orbital on sulfur and a p orbital on one of the oxygen atoms. This results in a pi bond and a sigma bond. The pi electrons are delocalized between the sulfur and oxygen atoms, and resonance structures can be drawn to show the delocalization.

SO3 has a trigonal planar structure with all three sulfur-oxygen bonds being identical. The sulfur atom in SO3 uses its three 3p orbitals to form three sigma bonds with the three oxygen atoms. The remaining 3p orbital on sulfur overlaps with the p orbitals on the three oxygen atoms to form three pi bonds. The pi electrons are delocalized over all three sulfur-oxygen bonds.

SO32- has a resonance structure in which the negative charge is delocalized over the sulfur and two oxygen atoms. The two sulfur-oxygen double bonds can be described as a combination of one strong sigma bond and one weaker pi bond, resulting in the delocalization of electrons over the sulfur-oxygen bonds.

In summary, SO2, SO3, and SO32- can exhibit delocalized bonding due to the presence of pi bonds and the ability to form resonance structures.

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Magnetic property of iron will help in seperating iron from rest of the materials.

Iron is a metal and have magnetic property. Magnetic property is property of metal in which metal has the attraction power to attract other metal. Iron is ferromagnetic but it requires certain temperature and certain conditions. It occurs below 770°C, which is curie temperature.

There are 5 magnetic properties

 types of magnetic materials

Diamagnetic Material,Paramagnetic Materials,Ferromagnetic Materials,Antiferromagnetic Materials,Ferrimagnetic Materials.

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Answer:

Temperature has a significant effect on the reaction rate of enzymes. At low temperatures, the reaction rate is typically slower as the enzymes and substrate molecules move more slowly, reducing the likelihood of successful collisions between them. As the temperature increases, the reaction rate generally increases as well, due to increased enzyme activity and the higher likelihood of successful collisions.

However, at high temperatures, the reaction rate can decrease rapidly as the enzyme's structure becomes denatured or permanently altered, resulting in a loss of enzyme activity. Enzymes have an optimal temperature range, typically between 37°C to 40°C (or 98.6°F to 104°F) for human enzymes, beyond which they become less efficient or inactive.

Therefore, temperature must be carefully controlled when conducting experiments with enzymes. At temperatures close to the optimal range, enzyme activity is highest and the reaction rate is fastest. However, at temperatures outside this range, the reaction rate can slow down or the enzyme can become denatured, leading to a loss of activity.

Therefore, 0.00723 moles of Na3C6H5O7 can be produced if one tablet containing 0.0217 mol of NaHCO3 is dissolved.

The balanced chemical equation shows that 3 moles of NaHCO3 react with 1 mole of H2C6H6O7 to produce 1 mole of Na3C6H5O7. Therefore, the number of moles of Na3C6H5O7 produced is directly proportional to the number of moles of NaHCO3.

If one tablet containing 0.0217 mol of NaHCO3 is dissolved, then according to the balanced chemical equation, the number of moles of Na3C6H5O7 produced is:

(0.0217 mol NaHCO3) x (1 mol Na3C6H5O7 / 3 mol NaHCO3) = 0.00723 mol Na3C6H5O7

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Answer:

The different types of storms are hailstorms, ice storms, snowstorms, thunderstorms, wind storms, hurricanes, and tornadoes.

Explanation:

Answer:

b.plasma

Explanation:

they jump in a exited energy level and by doing that they give off light

Answer:

b

Explanation:

its plasma

Answer:

12.5655

Explanation:

divide by 100

Answer:

12.5655

Explanation:

To find the answer you need to move the decimal place left two times <3

Answer:

B) -1.00 M/min

Explanation:

Based on the reaction:

2 SO2(g) + O2(g) → 2SO3(g)

2 moles of SO2 are consumed per mole of O2 producing 2 moles SO3

In the problem, the sulfur dioxide has a rate of change of -2.00M/min. As the moles of oxygen that reacted are half the moles of SO2, its rate of change is halved, that is:

The rate of change for the concentration of \(O_2\), i.e. d[\(O_2\)]/dt is 0.1175 M/s.

The decomposition of dinitrogen monoxide (\(N_2O\)) into nitrogen and oxygen takes place as follows:

\(N_2O (g) \rightarrow N_2(g) +1/2 O_2 (g)\)

The given reaction is a first-order reaction, which implies that the rate of the reaction is directly proportional to the concentration of \(N_2O\).

Therefore, the rate law for this reaction can be given as:

Rate = k[\(N_2O\)]where k is the rate constant and [\(N_2O\)] is the concentration of \(N_2O\).

Since the given reaction decomposes into nitrogen and oxygen, we need to calculate the rate of change of the concentration of \(O_2\).

For this, we first need to determine the stoichiometry of the reaction:

1 mole of \(N_2O\) produces ½ mole of \(O_2\)

According to the problem, the initial rate of the reaction is 0.235 M/s, which is the rate of change of the concentration of \(N_2O\). Therefore, we can write:

0.235 = k[\(N_2O\)]......(1)

Since the initial concentration of \(N_2O\) is not given in the problem, we cannot solve for the value of k.

However, since we know the stoichiometry of the reaction, we can relate the rate of change of the concentration of \(N_2O\) to that of \(O_2\) as follows:

Rate of change of \(O_2\) = ½ (Rate of change of \(N_2O\))

Therefore,

Rate of change of \(O_2\) = ½ x 0.235 = 0.1175 M/s

Therefore, the initial rate of change for the concentration of \(O_2\), i.e. d[\(O_2\)]/dt is 0.1175 M/s.

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