Phosphorus pentachloride decomposes to phosphorus trichloride at high temperatures according to the equation: PCl5(g) ⇌ PCl3(g) + Cl2(g) At 250° 13.0 g of PCl5 is added to the flask with a final solution volume of 0.500 L. If the value of Kc at this temperature is 1.80, what are the equilibrium concentrations of each gas?

Answer:

gas giant

large red spot

and i think possibly icy/liquid surface

Answer:

0.36 g of N2.

Explanation:

The following data were obtained from the question:

Temperature (T) = 25 °C

Volume (V) = 340 mL

Measured pressure = 730 torr

Vapour pressure = 23.76 torr

Mass of N2 =..?

First, we shall determine the true pressure of N2. This can be obtained as follow:

Measured pressure = 730 torr

Vapor pressure = 23.76 torr

True pressure =..?

True pressure = measured pressure – vapor pressure

True pressure = 730 – 23.76

True pressure = 706.24 torr.

Converting 706.24 torr to atm, we have:

760 torr = 1 atm

Therefore,

706.24 torr = 706.24 / 760 = 0.929 atm

Next, we shall convert 340 mL to L. This is illustrated below:

1000 mL = 1 L

Therefore,

340 mL = 340/1000 = 0.34 L

Next, we shall convert 25 °C to Kelvin temperature. This is illustrated below:

Temperature (K) = Temperature (°C) + 273

T(K) = T (°C) + 273

T (°C) = 25 °C

T(K) = 25 °C + 273

T (K) = 298 K

Next, we shall determine the number of mole of N2. This can be obtained as follow:

Pressure (P) = 0.929 atm

Volume (V) = 0.34 L

Temperature (T) = 298 K

Gas constant (R) = 0.0821 atm.L/Kmol

Number of mole (n) =...?

PV = nRT

0.929 x 0.34 = n x 0.0821 x 298

Divide both side by 0.0821 x 298

n = (0.929 x 0.34 ) /(0.0821 x 298)

n = 0.0129 mole

Finally, we shall determine the mass of N2 as shown below:

Mole of N2 = 0.0129 mole

Molar mass of N2 = 2x14 = 28 g/mol

Mass of N2 =.?

Mole = mass /Molar mass

0.0129 = mass of N2/ 28

Cross multiply

Mass of N2 = 0.0129 x 28

Mass of N2 = 0.36 g

Therefore, 0.36 g of N2 was collected.

The ΔS° value for the reaction KCl(s) → K+(aq) + Cl−(aq) is ΔS° > 0, as the products have a higher degree of disorder than the reactant due to an increase in the number of particles in solution. Hence the correct option is (C) ΔS° > 0.

The ΔS° value for a reaction represents the change in the entropy of the system, which is a measure of the disorder or randomness of the system. The reaction KCl(s) → K+(aq) + Cl−(aq) involves a solid compound breaking down into two separate aqueous ions, which means that the products have a higher degree of disorder than the reactant. This increase in the number of particles in solution results in an increase in entropy, which means that ΔS° > 0. Option (A) is incorrect because the reaction involves a change in state, which results in an increase in entropy. Option (B) is incorrect because it represents the relationship between enthalpy and entropy, not the ΔS° value for this particular reaction. Option (D) is incorrect because the reaction results in an increase in entropy, not a decrease. Option (E) is incorrect because the given information is sufficient to predict the sign of ΔS°.

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To solve this problem using the gas laws, we need to use the Ideal Gas Law. This law states that the product of the pressure and the volume of a gas is proportional to the absolute temperature.

The equation of the Ideal Gas Law is the following:

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{\dfrac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2} } \end{gathered}$} }\)

Where:

We clear for V₂:

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{V_2=\frac{P_1V_1T_2}{P_2T_1 } } \end{gathered}$} }\)

Where:

Substituting the known values:

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{V_2=\frac{760\not{kPa}\times0.050 \ L\times20.0\not{k} }{ 380\not{kPa}\times10.0\not{k} } } \end{gathered}$} }\)

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{V_2=\frac{760 \ L}{3800 } } \end{gathered}$} }\)

\(\boxed{\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{V_2\approx0.2 \ Liters} \end{gathered}$} }}\)

Option C, The electron transition from n = 5 to n = 1 in hydrogen atom requires the largest amount of energy as it is moving from a higher energy state to a lower energy state, thus overcoming the highest amount of electrostatic force of attraction to the nucleus.

In the hydrogen atom, the energy of an electron is related to its distance from the nucleus, which is characterized by the principal quantum number (n). As the distance of an electron from the nucleus increases, its energy decreases. Therefore, the electron transition that requires the largest amount of energy is when an electron jumps from the state with the lowest principal quantum number to the state with the highest principal quantum number.

From the options given, the transition that requires the largest amount of energy is c. From n = 5 to n = 1 because, in this case, the electron is transitioning from the state with the highest principal quantum number (n = 5) to the state with the lowest principal quantum number (n = 1). This transition requires the largest amount of energy because the electron must overcome the highest amount of electrostatic force of attraction to the nucleus.

It's important to notice that all the other options (a. from n=1 to n=2, b. from n=2 to n=3, d. from n=3 to n=5) are transitions that go to a lower n, meaning that the electron is getting closer to the nucleus and therefore lower energy state.

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Answer:

I will go for a heterogeneous mixture

Explanation:

alloy is basically a mixture

The time taken for the water fountain to dispense 842.75 mL of water is 20.625 seconds

Time can be defined as the measure of past, present or future events.

To calculate the time taken to dispense 842.75 mL of water, we use the formula below.

Formula:

Where:

Make t the subject of the equation.

From the question,

Given:

Substitute these values into equation 2

Hence, The time taken for the water fountain to dispense 842.75 mL of water, is 20.625 seconds.

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Answer:

The waters' temp increased

Explanation:

The temperature of the water in the swimming pool has increased due to the heat from the Sun. As a result, the particles in the water are moving faster and have a higher kinetic energy than in the morning.

The question requires us to provide the correct charge for a variety of ions, being lone elements or a combination of atoms.

For ions where there are more than one element, we need to analyze the charges of all atoms to achieve the total charge.

For example, for the ion NH4:

H presents charge +1

N presents charge -3

If we calculate the total charge, considering the number of atoms of each element, we have: 1*(-3) + 4*(+1) = +1

Therefore, the charge is +1 and the ion is written as:

Next, for the ion NO3:

O usually presents charge -2

N might have a varying charge. In this case, it presents charge +5

The total charge is: 1*(+5) + 3*(-2) = -1

Therefore, the charge is -1 and the ion is written as:

Next, for CO3:

O usually presents charge -2.

C presents charge +4 (just remember it normally makes 4 bonds)

The total charge is: 1*(+4) + 3*(-2) = -2

Therefore, the charge is -2 and this anion is written as:

Next, for SO4:

O usually presents charge -2

S presents charge +6

The total charge is: 1*(+6) + 4*(-2) = -2

Therefore, the charge is -2 and this anion is written as:

At last, for PO4:

O usually presents charge -2 and

P presents charge +6

The total charge is: 1*(+6) + 4*(-2) = -2

Therefore, the charge is -2 and this anion is written as:

Now, for the ions made of just one element, we need to analyze the electron distribution.

For example, for Mg which has atomic number 12, the electrons are distributed as:

1s2 2s2 2p6 3s2

Thus, there are 2 valence electrons and it is easier to lose this electrons rather than gain 6 more (to achieve the octet). Since Mg can lose 2 electrons, it forms an anion with charge +2.

Next, let's write the electronic distribution for the elements Al, Na, K, Cl and O so we can make a similar analysis for them. (Note that, to make it easier, I'll be using the notation with noble gases)

Al: [Ne] 3s2 3p1

There are 3 valence electrons in Al - this atom loses 3 electrons and usually forms the ion Al3+

Na: [Ne] 3s1

There is 1 valence electron in Na - this atom loses this electron and forms the ion Na+

K: [Ar] 4s1

just like Na, there is 1 valence electron in K - this atom forms the ion K+

Cl: [Ne] 3s2 3p5

There are 7 valence electrons in Cl - in this case, it is easier to gain 1 electron to complete the octet - this atom forms the ion Cl-

O: 1s2 2s2 2p4

There are 6 valence electrons in O - in this case, it is easier to gain 2 more electrons to complete the octet - this atom usually forms the ion O2-

We can use a similar logic to find the charge for the ions formed by Cu and Fe. On the other side, these elements are transition metals and they can form ions with different charges.

Fe: 1s2 2s2 2p6 3s2 3p6 4s2 3d6

There are 2 valence electrons - this atom can lose 2 electrons and form the ion Fe2+, but it can also form the ion Fe3+

Cu: 1s2 2s2 2p6 3s2 3p6 4s1 3d10

Even though the electronic distribution shows us that the ion formed is Cu+, the most common ion for copper is Cu2+

Answer:

The correct answer to this is C. Trigonal Planner

Explanation:

I got it right..

The component which is least soluble in gasoline is 2.candle wax. So, correct option is 2.

The octane rating still up in the air by blending fills from just ordinary heptane and iso-octane (2,2,4-trimethylpentane, an exceptionally extended octane), and relegating hostile to thump evaluations of zero for typical heptane and 100 for unadulterated iso-octane. The counter thump rating of this combination would be equivalent to the level of iso-octane in the blend. Various isomers of octane can add to a lower or higher octane rating. For instance, n-octane (the straight chain of 8 carbon molecules with no stretching) has a - 20 (negative) Exploration Octane Rating, while unadulterated iso-octane has a RON rating of 100. A few energizes have an octane rating higher than 100, outstandingly those containing methanol or ethanol.

Candle wax exist in solid state.On dissolving candle wax in octane it will least dissolve becuase of inert reaction between octane and candle wax.

Hence,correct answer is 2.

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Answer: The situation was Alexander Fleming made an experiment showing that the fungus produced a chemical that could kill bacteria. The scientific knowledge was based off Fleming's work, scientists produced the first antibitoic drugs.

It should reanalyze the data to determine whether their results contradicted your hypothesis if the experiment's findings did not support it. So shouldn't change the experiments, observations, or both in order to get results that support the theory.

An assumption or concept is given as a hypothesis for the purpose of debating it and testing if it might be true.

If the facts continually contradict the hypothesis, it is obvious that the hypothesis is not a viable explanation for the phenomenon you are examining. The proposed explanation is disproved, and we now look for a fresh hypothesis to explain the experimental results.

If the results confirm the prediction, the hypothesis is supported. Results can be used to disprove the hypothesis if the prediction was not confirmed by the data. By monitoring data and creating a new hypothesis using the new facts, you might need to come up with new questions. Make a finding and a forecast.

Thus, It should reanalyze the data to determine whether their results contradicted your hypothesis if the experiment's findings did not support it.

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Answer:

uncomplete question

Explanation:

Answer:

THE HEAT CAPACITY OF THE CALORIMETER IS 3666.67 J/C

Explanation:

Mass = 2 g

Temperature difference = 32 C - 29 C = 3 C

Heat of combustion = 11 kJ/g

Heat capacity of the calorimeter = unknown

It is important to note that the heat of combustion of the reaction is the heat absorbed by the calorimeter in raising the mixture by 3 C

So therefore,

Heat = heat capacity * temperature difference

Heat capacity = Heat / temperature difference

Heat capacoty = 11 000 J / 3 C

Heat capacity = 3666.67 J/ C

Answer:

0.956 grams O₂        or
0.956 milliliters O₂   or
9.56 x 10⁻⁴ L O₂

Explanation:

If the reactant were to decompose completely, the entire balanced reaction would look like this:

2 KClO₃ --> 2 K(s) + Cl₂(g) + 3 O₂(g)

To find the answer, (1) convert the grams of KClO₃ to moles (via molar mass from periodic table), then (2) convert moles KClO₃ to moles O₂ (via mole-to-mole ratio from balanced equation), then (3) convert moles O₂ to grams (via molar mass from periodic table).

Molar Mass (KClO₃) = 39.098 g/mol + 35.453 g/mol + 3(15.999) g/mol

Molar Mass (KClO₃) = 122.548 g/mol

Molar Mass (O₂) = 2(15.999) g/mol

Molar Mass (O₂) = 31.998 g/mol

2.44 g KClO₃           1 mole KClO₃             3 moles O₂             31.998 g
--------------------  x  --------------------------  x  --------------------  x  ------------------------
                                   122.548 g             2 moles KClO₃        1 mole O₂

= 0.956 grams O₂
= 0.956 milliliters O₂
= 9.56 x 10⁻⁴ L O₂

**The prompt askes to determine the volume. As far as I know, there is no easy way to find liters/milliliters with the given information. As such, I found the mass of O₂ instead. Technically, grams is equal to milliliters, so this may be what you are looking for. Then, you can convert from milliliters to liters by dividing by 1,000 (if necessary). **

Moles of KBr = Mass/Molar mass = 10.5g/119g/mol = 0.088 mol. Now, Molarity=moles of KBrVolume of the solution in liter. M o l a r i t y = m o l e s o f K B r V o l u m e o f t h e s o l u t i o n i n l i t e r .

1200 mL will be the closing extent of the solution.

However, seeing that there may be already 500 mL of answer present, you only need to add 700 mL of water to get 1200 mL as your last volume. The answer: seven hundred mL.

QUESTION 13 What hundreds of KBr and water are wished to produce 300. g of a solution that is three p.c by using mass? 9.00 g of KBr and 300.

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1. The constituent gases of air are:

2. The surrounding air is not seen with the eyes because it is transparent. Air molecules are not visible to the na-ked eye, and they do not scatter or absorb visible light significantly. Therefore, air appears colorless and transparent.

3. To prove that air supports burning, you can perform an experiment with a burning candle. Place a glass jar or bell jar over a lit candle, ensuring that the jar is airtight. As the candle burns, it consumes oxygen from the air inside the jar. Eventually, the candle flame will go out due to the lack of oxygen, proving that air (specifically oxygen) is necessary for burning.

4. To show that air occupies space, you can perform a simple experiment using a plastic bottle or syringe. Fill the bottle or syringe with water, ensuring there are no air bubbles. Then, cover the opening tightly and try to compress the air inside. You will find that it is not possible to compress the air significantly, indicating that air occupies space.

5. To prove that air has weight, you can use a sensitive balance or scale. Weigh an airtight container or balloon, and then fill it with air. The weight of the container or balloon with the added air will be greater than its initial weight, demonstrating that air has weight.

6. Air is useful to us in various ways. Three points highlighting the importance of air are:

7. Three properties of air include:

Air exerts force in various ways. For example, air pressure allows objects like airplanes to fly by providing lift. Air resistance or drag opposes the motion of objects moving through the air, creating a force that can affect their speed and trajectory.

8. Four effects of air pollution include:

9. Causes of pollution:

10. Two control measures for air pollution include:

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Answer:

This question is incomplete, however, it is asking to calculate the empirical formula of the compound.

The empirical formula is N2O3

Explanation:

The following information about a compound was got from the question:

N = 36.8%

O = 63.2%

It can be said that the compound contains 36.8g of nitrogen (N) and 63.2g of oxygen (O).

Next, we convert each mass composition to moles by dividing by their respective molar masses.

N = 36.8g ÷ 14g/mol = 2.628mol

O = 63.2g ÷ 16g/mol = 3.95mol

Next, we divide each mole value by the smallest value (2.628mol).

N = 2.628mol ÷ 2.628 = 1

O = 3.95mol ÷ 2.628 = 1.5

We multiply each value by 2 to get a empirical ratio.

N = 2

O = 3

The ratio of N:O is 2:3, hence, the empirical formula is N2O3.

Answer:

What is the speed of an object traveling 50 m in five hours

Explanation:

Answer:

lol what? bruh you need to explain what your talking about im in an ap class i can help

Explanation:

Answer:

for me, it is hard to understand the topics in the module and it can affect your grades that's why I am angry like a volcano When the pressure is too much an explosive eruption can happen, which can be dangerous and destructive

Answer:

If you heat a gas you give the molecules more energy so they move faster.

Explanation:

With a 20 atomic number and 20 electrons, calcium is an atom. The atom of bromine has an atomic number of 35 and 35 electrons. 13 electrons make up the atom of aluminium, which has an atomic number of 13.

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Answer:

1.674 x 10^-23 grams

Explanation:

Hydrogen-1 is called Protium

wikipedia

atomic mass of Protium is 1.00794 amu

sciencedirectcom

atomic mass of 10 Protiums is 10.0794 amu

10.0794 amu in grams is

1.6737236x10^-23 grams

The pressure inside the tire is approximately 1.970796 newtons per square centimeter (N/cm²) when measured in those units.

To convert the pressure from pounds per square inch (psi) to newtons per square centimeter (N/cm²), we need to use the conversion factors between these units.

First, let's convert pounds to newtons:

1 pound = 0.45359237 kilograms

1 kilogram = 9.80665 newtons

Next, let's convert square inches to square centimeters:

1 square inch = 6.4516 square centimeters

Now, we can perform the conversion:

1 psi = (0.45359237 kg) × (9.80665 N/kg) / (6.4516 cm²)

≈ 0.070307 N/cm²

Therefore, the pressure inside the tire of 28.0 psi is approximately equal to 28.0 × 0.070307 N/cm², which is approximately 1.970796 N/cm².

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To find out if the diet lemonade contains any sugar, Liam should follow these steps (using Benedict's solution):

1. Take a sample of the diet lemonade and pour it into a test tube.

2. Add a few drops of Benedict's solution to the test tube with the diet lemonade sample.

3. Mix it to make it homogeneous.

4. Take the test tube to a water bath.

5. Heat the test tube in the water bath.

6. If the solution (sample of diet lemonade + drops of Benedict's solution) turns orange-red, the diet lemonade contains sugar.