physics






is my answer correct?

Answer:

What cell organelle makes turgor pressure in a plant cell

possible? Describe the role of this organelle in this process.

Explanation:

pls help dude

Answer:

it's D

Explanation:

its on edge

if Betelgeuse and Rigel have the same luminosity but Betelgeuse is cooler, then it means that Betelgeuse must be larger in radius and have a greater surface area than Rigel. This is because Betelgeuse emits more of its energy at longer wavelengths, which requires a larger surface area to maintain the same luminosity as Rigel.

The luminosity of a star refers to the amount of energy it emits per unit of time, while the surface area is the total area of the star's outer shell. If Betelgeuse and Rigel have the same luminosity but different temperatures, it means that they emit the same amount of energy, but at different wavelengths. Betelgeuse, being cooler, emits more of its energy at longer wavelengths, while Rigel emits more of its energy at shorter wavelengths.

The temperature of a star determines its color, with cooler stars appearing reddish and hotter stars appearing bluish. The surface area of a star is related to its radius, which in turn is related to its temperature and luminosity. Hotter stars are smaller in radius and have a greater surface area, while cooler stars are larger in radius and have a smaller surface area.

Luminosity is the amount of energy a star emits per unit of time. It depends on the star's surface area and its temperature. The relationship between luminosity (L), surface area (A), and temperature (T) can be described by the Stefan-Boltzmann Law:

L = A * σ * T⁴

where σ is the Stefan-Boltzmann constant.

Since Betelgeuse and Rigel have the same luminosity, we can set their luminosity equations equal to each other:

A1 * σ * T1⁴ = A2 * σ * T2⁴

Here, A1 and T1 refer to the surface area and temperature of Betelgeuse, while A2 and T2 refer to the surface area and temperature of Rigel. Since σ is a constant, we can simplify the equation to:

A1 * T1⁴ = A2 * T2⁴

Given that the temperature of Betelgeuse is cooler than Rigel, T1 < T2. To maintain the same luminosity, Betelgeuse must have a larger surface area (A1) to compensate for its lower temperature. Therefore, the surface area of Betelgeuse is greater than that of Rigel.

In summary, if Betelgeuse and Rigel have the same luminosity but different temperatures, then Betelgeuse would have the greater surface area due to its larger radius. If the stars Betelgeuse and Rigel were to have the same luminosity but the temperature of Betelgeuse is cooler than Rigel, then Betelgeuse would have the greater surface area.

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Answer:

A lightbulb has 25 W stamped on it. What does this mean?:

These labels mean that each lightbulb has Its respective power delivered to It when It Is connected to a constant

Explanation:

I guess a missile?

A bird is not a projectile, a ball isn't really, and an airplane isn't, so, yeah.

?:]

Answer: okay thx

Explanation:

It's all about Inertia! Inertia says an object, the egg in this case, will stay at rest, unless an outside force acts upon it, your hand in this case. When you move the pie pan with your hand, gravity pulls the egg straight into the glass of water.

Check Writing QualityThe Egg-Drop Device Process The process of dropping an egg is more complex than an average person would believe. The egg-dropping process requires knowledge of history, engineering, mathematics, and physics. To fully understand how an egg drops, the ability of the history of physics, the engineering behind a device, and the mathematics and physics of free-fall are needed.

Physics originates in its classical form in Ancient Greece. Thales was the first physicist. The theories Thales made gave the discipline of physics its name. Thales believes that the world, although made of many materials, was made of only one element: water. The interaction of water between the phases of solid, liquid, and gas gives materials different properties.

Copernicus discovers that the Sun was the center of the solar system, not the Earth. Kepler develops the three laws of planetary motion. Galileo discovers that the natural state of an object is either at rest or moving with a constant speed, for as long as no unbalanced forces are acting on the object. Galileo reasons that if friction and other forces were balanced, an object would continue along at constant speed.

The conceptual side of egg-dropping requires knowledge of free-fall physics. The most basic formula to know is v = d/t, or velocity is equal to the distance divided by the elapsed time. In the test simulation, the device is dropped at a distance of 75 feet or 22.86 meters, and the average elapsed time is 2.223 seconds. Using these two values, substituted into the formula, the velocity is determined to be 10.2834 meters per second. Velocity is a vector quantity with direction and magnitude. In the case of the device, the direction is directly down or 90 degrees below the horizontal and the magnitude is 10.2834. After solving for velocity, one can get the acceleration of the device as it drops from 75 feet. To calculate acceleration, the formula a = v / t, or in other words, acceleration is equal to velocity divided by the elapsed time.

The Egg Drop project is a highly-versatile activity that can be used to introduce students to physics, materials science, and fluid dynamics. For elementary and middle school classes, the students have a wide range of materials to 'buy' with their allotted budgets.

Answer: 1. Make a triangle out of a straw and tape it together.

2. Repeat this two more times.

3. Tape all 3 triangles together around the egg to make a pyramid shape.

4. Decide how else to cushion the egg - for example: using more straws.

5. Spread the painter's tarp on the floor.

Answer:

λ = 5.85 x 10⁻⁷ m = 585 nm

f = 5.13 x 10¹⁴ Hz

Explanation:

We will use Young's Double Slit Experiment's Formula here:

\(Y = \frac{\lambda L}{d}\\\\\lambda = \frac{Yd}{L}\)

where,

λ = wavelength = ?

Y = Fringe Spacing = 6.5 cm = 0.065 m

d = slit separation = 0.048 mm = 4.8 x 10⁻⁵ m

L = screen distance = 5 m

Therefore,

\(\lambda = \frac{(0.065\ m)(4.8\ x\ 10^{-5}\ m)}{5\ m}\)

λ = 5.85 x 10⁻⁷ m = 585 nm

Now, the frequency can be given as:

\(f = \frac{c}{\lambda}\)

where,

f = frequency = ?

c = speed of light = 3 x 10⁸ m/s

Therefore,

\(f = \frac{3\ x\ 10^8\ m/s}{5.85\ x\ 10^{-7}\ m}\\\\\)

f = 5.13 x 10¹⁴ Hz

Answer:

d. changing the direction if force

kindly follow.tnx

Answer: Your answer for this question would be letter D if this is wrong let me know ok have a great day and keep the good work up.

Explanation:

Answer:

1 A No, snacks are not healthy.

2 D Keep his commitment to exercise but just walk if it is a low energy day.

3 C She should not take a class unless she thinks that she will genuinely enjoy it

4 B No, push-ups are a better indicator of cardio fitness than strength.

Answer:

4.D  yes, this is an effective way to monitor strength

Explanation:

Based on the principle of conservation of momentum;

The principle of conservation of momentum states that in an isolated system of colliding bodies, momentum is conserved.

This principle can be stated mathematically as:

The average speed of each trolley is calculated using the formula:

For Trolley A:

average speed = 100 mm/0.5 = 200 mm/s

average speed of A = 0.2 m/s

For Trolley B:

distance = 200 mm = 0.2 m

average speed = 0.2 m/0.5 s

average speed of B = 0.4 m/s

Momentum = mass × velocity

Assuming direction of motion of B is positive, direction of A is negative

Momentum of A = - m × 0.2 = -0.2m

Momentum of B = m/2 × 0.4 = 0.2 m

Total momentum = 0.2 m - 0.2 = 0

Therefore, the total momentum before and after the release of the spring is zero.

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The scientist would look out for patterns and connections. Option D

We define data as a set of facts that we can obtain from a study. We know that scientists are always engages in some kind of study and the reason for the study is that they want to obtain the reasons for certain occurrence.

It is common that when we present a professional scientist with a data set, what first comes to mind is that we need to find the patterns that are in the data set as well as the connections.

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Answer:

Approximately \(1.5\; {\rm s}\).

(Assumptions: \(g = 9.81\; {\rm m\cdot s^{-2}}\); air resistance on the volleyball is negligible.)

Explanation:

Under the assumptions, acceleration of the volleyball would be \(a = (-g) = (-9.81)\; {\rm m\cdot s^{-2}}\) during the entire flight. (This value is negative since the ball is accelerating downwards- toward the ground.)

By the time the volleyball hits the ground, the volleyball would be at a position \(2.0\; {\rm m}\) below where it was launched. In other words, the (vertical) displacement of the volleyball during the entire flight would be \(x = (-2.0)\; {\rm m}\). (Negative since the ball is below where it was launched.)

Apply the SUVAT equation \((v^{2} - u^{2}) = 2\, a\, x\) to find the velocity of the volleyball right before hitting the ground. In this equation:

Rearrange this equation and solve for the velocity right before landing, \(v\). Note that because \(v\!\) is raised to the power of \(2\) in \((v^{2} - u^{2}) = 2\, a\, x\), both \(v = \sqrt{u^{2} + 2\, a\, x}\) and \(v = -\sqrt{u^{2} + 2\, a\, x}\) could satisfy this equation. However, \(v\!\!\) needs to be negative since the volleyball would be travelling downwards before reaching the ground.

Therefore, right before reaching the ground, velocity of the volleyball would be:

\(\begin{aligned} v &= -\sqrt{u^{2} + 2\, a\, x \\ &= -\sqrt{(6.0)^{2} + 2\, (-9.81)\, (-2.0)} \; {\rm m\cdot s^{-1}} \\ &\approx (-8.67)\; {\rm m\cdot s^{-1}}\end{aligned}\).

In other words, velocity of this volleyball has changed from \(u = 6.0\; {\rm m\cdot s^{-1}}\) (upwards) to \(v \approx (-8.67)\; {\rm m\cdot s^{-1}}\) (downwards) during this flight. Divide the change in the velocity \((v - u)\) by the rate of change in velocity \(a = (-9.81)\; {\rm m \cdot s^{-2}}\) to find the duration of this flight:

\(\begin{aligned}t &= \frac{v - u}{a} \\ &\approx \frac{(-8.67) - 6.0}{(-9.81)}\; {\rm s} \\ &\approx 1.5\; {\rm s}\end{aligned}\).

The force necessary to gain the velocity is 40 N.

The velocity gained by the object at the end of the second minute is 30 m/s.

F = mv/t

where;

F = (200 x 60)/(300)

F = 40 N

F = mv/t

Ft = mv

v = Ft/m

where;

v = (150 x 120)/(600)

v = 30 m/s

Thus, the force necessary to gain the velocity is 40 N.

The velocity gained by the object at the end of the second minute is 30 m/s.

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Answer:

0.19m/s²

Explanation:

Initial velocity(u) = 50×1000/60×60

=13.88 m/s

Final velocity(v) = 36.5×1000/60×60

=10.13 m/s

Acceleration(a) = v-u/t

=10.13-13.88/19.5

a= -0.19m/s²

-a = 0.19m/s²

The magnitude of retar dation is 0.19m/s²

Answer:

\(\sf 0.192\:ms^{-2}\:\:(3\:s.f.)\)

Explanation:

Given:

First, convert the velocities into meters per second by dividing by 3.6:

\(\implies \sf 50.0\: km h^{-1}=\dfrac{50.0}{3.6}\:ms^{-1}= \dfrac{125}{9}\:ms^{-1}\)

\(\implies \sf 36.5\: km h^{-1}=\dfrac{36.5}{3.6}\:ms^{-1}= \dfrac{365}{36}\:ms^{-1}\)

To find the vehicle's acceleration, use one of the constant acceleration equations with the given values:

\(\implies \sf v=u+at\)

\(\implies \sf \dfrac{365}{36}=\dfrac{125}{9}+19.5a\)

\(\implies \sf \dfrac{365}{36}-\dfrac{125}{9}=19.5a\)

\(\implies \sf 19.5a=-3.75\)

\(\implies \sf a=-\dfrac{3.75}{19.5}\)

\(\implies \sf a=-0.1923076923...\:ms^{-2}\)

Therefore, the magnitude of acceleration is:

\(\implies \sf |a|=|-0.19230...|=0.192\:ms^{-2}\:\:(3\:s.f.)\)

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Answer:

P = 40.7kPa

Explanation:

To find the pressure on a surface 6 meter below you use the following formula, which takes into account the heights in which pressures are measured and also the density of the fluid and the gravitational acceleration:

\(P_2-P_1=-\rho g(y_2-y_1)\)             (1)

P2: pressure for a height of -6 m = ?

P1: pressure for a height of -2 m = 1.5kPa = 1500 Pa

ρ: density of water = 1000kg/m^3

g: gravitational acceleration = 9.8 ms^2

y2: -6m

y1: -2m

(the height is measure from the water level, because of that, the heights are negative)

You solve the equation (1) for P1:

\(P_1=P_2-\rho g(y_2-y_1)\)         (2)

Next, you replace the values of all variables in equation (2):

\(P_2=1500Pa-(1000kg/m^3)(9.8m/s^2)(-6-(-2))m=40700Pa\\\\P_2=40.7kPa\)

hence, the pressure on a surface 6 m below the water level is 40.7kPa

The acceleration of the box is 0.025 m/s²

We'll begin by calculating the the frictional force

Coefficient of kinetic friction (μ) = 0.21

Mass (m) = 8 Kg

Acceleration due to gravity (g) = 10 m/s²

Normal reaction (N) = mg = 8 × 10 = 80 N

Fբ = μN

Fբ = 0.21 × 80

Frictional force (Fբ) = 16.8 N

Force (F) = 17 N

Fₙ = F – Fբ

Fₙ = 17 – 16.8

Mass (m) = 8 Kg

Net force (Fₙ) = 0.2 N

a = Fₙ / m

a = 0.2 / 8

Therefore, the acceleration of the box is 0.025 m/s²

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Answer:

I think the answer is B

Explanation:

If the Voltage is halved, then the current goes down as well so the voltage drop across the lamps will decrease as well.

Answer:

No

Explanation:

No because like my other answer if we put to many diesels on it it will crack and little by little it will break eventually everyone will come tumbling into the water making them drown because they can't get the buckles loose or they wanted to save their families lives

The critical speed below which the rope would become slack when the bucket reaches the highest point in the circle is determined by the length of the rope and the radius of the circle.

When the bucket is at the highest point in the circle, it is momentarily at rest and the tension in the rope must be zero.

The formula for calculating the critical speed at which the rope becomes slack is:

v = √(gr)

where v is the critical speed, g is the acceleration due to gravity, and r is the radius of the circle.

For example, if the radius of the circle is 2 meters and the acceleration due to gravity is 9.8 m/s², the critical speed would be:

v = √(9.8 × 2) = 4.4 m/s

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A person at the station would hear a frequency of 428.37 Hz.

To determine the frequency heard by a person at the station, use the formula for the Doppler effect:

f' = f × (v + v₀) / (v + vₛ)

Where:

f' is the frequency heard by the observer at the station

f is the frequency of the whistle (4.0 × 10² Hz)

v is the speed of sound in air (approximately 343 m/s)

v₀ is the speed of the train (25 m/s)

vₛ is the speed of the observer at the station (0 m/s, since they are stationary)

Substitute the values in the above equation:

f' = (4.0 × 10² Hz) × (343 m/s + 25 m/s) / (343 m/s + 0 m/s)

Simplifying the equation:

f' = (4.0 × 10² Hz) × (368 m/s) / (343 m/s)

f' = 428.37 Hz

Therefore, 428.37 Hz will be heard by a person at the station.

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A hydrogen atom is in its ground state (nᵢ = 1) when a photon impinges upon it. The atom absorbs the photon, which has precisely the energy required to raise the atom to the nf = 3 state. (a) The photon's energy that was absorbed is approximately 1.51 eV (negative sign indicates absorption).(b)option B and C are correct.

To determine the photon's energy and the energies of photons that might be emitted when the hydrogen atom returns to the ground state, we can use the energy level formula for hydrogen atoms:

E = -13.6 eV / n^2

where E is the energy of the electron in the atom, and n is the principal quantum number.

(a) To find the energy of the photon that was absorbed by the hydrogen atom to raise it from the ground state (nᵢ = 1) to the nf = 3 state, we need to calculate the energy difference between the two states:

ΔE = Ef - Ei = (-13.6 eV / 3^2) - (-13.6 eV / 1^2)

Calculating the value of ΔE:

ΔE = -13.6 eV / 9 + 13.6 eV

= -1.51 eV

Therefore, the photon's energy that was absorbed is approximately 1.51 eV (negative sign indicates absorption).

(b) When the hydrogen atom returns to the ground state, it can emit photons with energies corresponding to the energy differences between the excited states and the ground state. We need to calculate these energy differences and check which values are present among the given options.

ΔE1 = (-13.6 eV / 1^2) - (-13.6 eV / 3^2) = 10.20 eV

ΔE2 = (-13.6 eV / 1^2) - (-13.6 eV / 4^2) = 10.20 eV

ΔE3 = (-13.6 eV / 1^2) - (-13.6 eV / 5^2) = 12.10 eV

ΔE4 = (-13.6 eV / 1^2) - (-13.6 eV / 6^2) = 12.10 eV

ΔE5 = (-13.6 eV / 1^2) - (-13.6 eV / 7^2) = 13.55 eV

ΔE6 = (-13.6 eV / 1^2) - (-13.6 eV / 8^2) = 13.55 eV

ΔE7 = (-13.6 eV / 1^2) - (-13.6 eV / 9^2) = 13.55 eV

Comparing the calculated energy differences with the given options:

(A) 1.89 eV: This energy difference does not match any of the calculated values.

(B) 12.1 eV: This energy difference matches ΔE3 and ΔE4.

(C) 10.2 eV: This energy difference matches ΔE1 and ΔE2.

(D) 13.6 eV: This energy difference does not match any of the calculated values.

Therefore option B and C are correct.

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Kinetic energy of Corvette with a mass of 1,054 kg and a velocity of 48m/s is 12,14,208 J

Kinetic energy is a type of power that an item or particle possesses as a result of motion. An object accelerates and acquires kinetic energy when it undertakes work—the transfer of energy—by being subjected to a net force. Kinetic energy is one of the properties of a moving object or particle, which depends on both mass and speed. The type of motion can be any combination of vibration, rotation on an axis, and translation (or transit along a path from one spot to another).

A body's translational kinetic energy is equal to 1/2mv2, or one-half of the product of its mass, m, and square of its velocity, v.

Here,

m = 1,054 kg

v = 48 m/s

KE = ?

KE = 1/2 mv²

KE = \(\frac{1}{2}\) × 1054 × 48²

KE = 0.5 × 1054 × 2304

KE = 12,14,208 J

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By using vector

a. the distance traveled is 12 kilometres

b. the resultant displacement is (7 i + 5 j) kilometres

We need to know about vectors to solve this problem. Vector has magnitude and also direction. Displacement is included in vector. It can be written as

s = sx i + sy j + sz k

where s is displacement, sx is displacement on x-axis, sy is displacement on y-axis and sz us displacement on z-axis.

From the question above, we know that

east = positive x

south = negative y

west = negative x

north = positive y

s1 = 7 j

s2 = 5 j

The distance traveled is

s = s1 + s2

s = 7 + 5

s = 12 kilometres

The resultant displacement is

s = s1 + s2

s = 7 i + 5 j

s = (7 i + 5 j) kilometres

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(a) The gravitational force received by each 1 kg mass is 8.66 N.

(b) The magnitude of gravitational acceleration is 8.66 m/s².

(c) The orbital speed of the ISS is  7,663.6 m/s.

(d) The time take  for the ISS to orbit round the Earth is 5,558.75 seconds which is equal to 1.54 hours.

The gravitational force received by each 1 kg mass is calculated as follows;

F = Gm₁m₂/r²

where;

F = (6.67 x 10⁻¹¹ x 5.97 x 10²⁴ x 1) / (6780,000)²

F = 8.66 N

mg = GMm/r²

g = GM/r²

where;

g = (6.67 x 10⁻¹¹ x 5.97 x 10²⁴ ) / (6780,000)²

g = 8.66 m/s²

v = √GM/r

v = √(6.67 x 10⁻¹¹ x 5.97 x 10²⁴  / 6780,000)

v = 7,663.6 m/s

T = 2πr/v

T = (2π x 6780,000) / (7663.6)

T = 5,558.75 seconds

1 hour = 3600 seconds

=  5,558.75/3600

= 1.54 hours

Thus, the gravitational force received by each 1 kg mass is 8.66 N.

The magnitude of gravitational acceleration is 8.66 m/s².

The orbital speed of the ISS is  7,663.6 m/s.

The time take  for the ISS to orbit round the Earth is 5,558.75 s = 1.54 hours.

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Answer: A shunt is a low-ohm resistor that can be used to measure current. ... The entire current flows through the shunt and generates a voltage drop, which is then is measured. Using Ohm's law and the known resistance, this measurement can then be used to calculate the current (I = V/R).

Answer:

\(\text{Weight} = \text{Mass} \times \text{Gravitational acceleration}\)

Explanation:

An electric field is defined along the x-axis by the function then if g=1.5m and h=6m, then v(g)-v(h) = 7768.40V.

When charge is present in any form, a point in space has an electric field that is connected to it.

The value of E, often known as the electric field strength, electric field intensity, or just the electric field, expresses the strength and direction of the electric field.

Each location in space where a charge exists in any form can be considered to have an electric field attached to it. The electric force per unit charge is another name for an electric field. The electric field’s equation is given as E = F / Q.

E = + 5 x^4 x^n

Also, E = -x^n r/rx (v)

⇒ 5 x^4 x^n = -x^n r/rx (v)

⇒ v = - ∫ 5 x^4 dx

⇒ v = -5 x^5/5

⇒ v = - x^5 v

So, v(g) - v(h) = - (1.5)^5 + (6)^5

= -7.59375 + 7776

=7768.40 V

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