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Jenny loves to chew gum, but hates losing
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She buys 4 different packs of gum, one of
them being her normal Juicy Fruit. Every
day after lunch she picks one piece of gum
and chews it until it loses flavor. She
times how long it takes for the gum to lose
flavor, and records the time. She chews the
same type of gum every day until she has
used up the pack, and finds an average time
for how long the flavor lasted. Then she
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The pulley system to the right will be in static equilibrium at an unknown angle of 90 degrees.

An object must satisfy two requirements of equilibrium in order to maintain static equilibrium. First, there must be no net force acting on the item. Second, there must be no net torque pulling on the object.

The 80 N weight is fastened to a freely rotating pulley in this setup.

As a result, the cable's tension is also 80 N.

The tensions' x components must be balanced against one another:

T1x = T2x

Since T1x = T1 cos(θ) and T2x = 0 (because the cable attached to the wall is vertical), we have:

T1 cos(θ) = 0

Therefore, cos(θ) = 0, which means that θ = 90 degrees.

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The force with which the second astronaut is pushing is 11.25 N in the problem given.

We have to note that force is a vector and because that force is a vector, we know that the direction of the force that has been applied is also very important.

As we know, it is clear that;

Force of an astronaut Fₓ = 42 N

Angle θ = 15º

Then we can write that;

F = 42 tan 15

= 11.25 N

Thus, the force that acts as the second astronaut is pushing is about 11.25 N.

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The phenomenon of wind blowing across suspended power lines causing them to vibrate at their natural frequency and producing audible sound waves is commonly referred to as an aeolian harp.

When wind flows across a power line, it sets up alternating areas of high and low pressure on either side of the line. These pressure differences can cause the line to vibrate back and forth, much like a guitar string being plucked. If the frequency of the wind-induced vibration matches the natural frequency of the power line, resonance can occur, resulting in a sustained and amplified sound wave.

The sound produced by an aeolian harp can vary in pitch and volume depending on the wind speed and direction, the size and shape of the power line, and other environmental factors. In some cases, the sound can be loud enough to be heard from a significant distance away, leading to complaints from nearby residents.

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Answer:

the answer would be c sry if it is wrong

Answer: the kinetic energy is equal to 125 Joules, or (1/2 * 10 kg) * 5 m/s2.

Explanation:

if a an object with a mass of 10 kg (m = 10 kg) is moving at a velocity of 5 meters per second (v = 5 m/s), the kinetic energy is equal to 125 Joules, or (1/2 * 10 kg) * 5 m/s2.

Answer:

The Kinetic energy of a 10Kg object moving with a speed of 5m/s is 125 Joules

Explanation:

Kinetic energy refers to the energy of a moving object. The formula for kinetic energy is given by

KE=(1/2)\(mv^{2}\).......(i)

, where, m⇒mass of object

             v⇒velocity

and the unit is given by Joules.

Now, as we are given in the question,

mass, m=10kg

velocity, v= 5m/s

Substituting these values in the equation (i), we get,

KE=(1/2)x(10Kg)x(5m/s)^2,

we have,

KE=125 J

Therefore, the kinetic energy of a 10 kg object moving with a speed of 5m/s is 125 Joules.

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The beam can be lifted at a distance of approximately 770.27 meters.

The quantity of energy transmitted when a force is applied across a distance is measured by the physical concept of work. A force must be applied to an object in order for it to move in the direction of the force and perform work. The unit of measurement for work is the joule (J), which has a magnitude but no direction.

To find the distance of the beam can be lifted, use the formula:

Work = force × distance × cos(θ)

Distance = 57000 J ÷ (74 N × cos(θ))

= 770.27 meters

Thus, the capacity of beam 770.27 meter.

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Answer:

meters, yards or feet

Explanation:

When a 30 micro of capacitor is attached to the a 9 v battery at its intermediate level, the equation states that 2.7μC is the charges on the capacitor.

A capacitor operates on the basis that capacitance of the a conductor exhibits rise when a grounding conductor is introduced near it. As a result, the capacitance has parallel plates that are spaced apart from one another and facing in opposing directions.

Two conductors that are separated from one another and positioned close to one another make up a capacitor, a electrical energy storage device. A parallel-plate capacitor is a simple example with one such storage device.

If we rearrange the previous formula to account for C=30F and V=9v in our issue, we can calculate the charge held in the capacitor:

             Q=CV

                =(30μF) (9v)

                =2.7μC

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Scrum teams take an incremental, iterative approach to their work in order to create usable prototypes of their products or other desired results as soon as possible.

The scrum team should use the following strategy to create worthwhile improvements: Since the scrum team employs an iterative and gradual method of operation, they must swiftly find solutions to issues and deliver effective product iterations or other desired outcomes. Every Sprint, the entire Scrum Team is in charge of creating a valuable, useful increment. The developers, the product owner, and the scrum master are the three distinct accountabilities set forth by Scrum for the Scrum Team. Whether or whether an increment is shipped to consumers, it must be released at the end of each Sprint. Each increment has to be complete, useable, and adhere to the scrum team's quality criteria.

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Answer:

5.5 m/s

Explanation:

Right on Edge

The statement explains the importance of enzymes that check for and repair mistakes during DNA replication is the enzymes prevent many genetic mutations from being expressed. Thus, the option C is correct.

RNA polymerase is an enzyme that aids in the transcription of DNA into RNA during transcript in the nucleus. The enzymes prevent many genetic mutations from being expressed.

Primase is an enzyme that synthesizes short RNA sequences called primers. These primers serve as a starting point for DNA synthesis during replication as the DNA polymerases cannot begin the synthesis of the new strand, they only extend it after primase begins it and primase produces RNA molecules, the enzyme can be said to be a type of RNA polymerase.

Therefore, The statement explains the importance of enzymes that check for and repair mistakes during DNA replication is the enzymes prevent many genetic mutations from being expressed. Thus, the option C is correct.

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The gravitational force of a star on planet 2 orbiting it is half that of planet 1.

Newton's gravitational law formula for gravitational force between two objects

\(F = G \frac{M \: m}{r^2}\)

Given

Compare the gravitational force on two condition.

\(\frac{f1}{f2} = \frac{G \frac{M \: m_1}{r_1^2}}{G \frac{M \: m_2}{r_2^2}}\)

\(\frac{f1}{f2} = \frac{\frac{m_1}{r_1^2}}{\frac{m_2}{r_2^2}}\)

\(\frac{f1}{f2} = \frac{m_1 \: r_2^2}{m_2 \: r_1^2}\)

\(\frac{f1}{f2} = \frac{m_1 \: (2r_1)^2}{2m_1 \: r_1^2}\)

\(\frac{f1}{f2} = \frac{4r_1^2}{2r_1^2}\)

\(\frac{f1}{f2} = \frac{2}{1}\)

The ratio of gravitational force f1 : f2 = 2 : 1

2f2 = f1

\(f2 = \frac{f1}{2}\)

\(f2 = \frac{1}{2} f1\)

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It is gravity that causes planets to orbit around each othe—for example, Earth orbits around the Sun. During the daytime of its orbit, the Sun provides sunlight that produces vegetation for creatures to eat and light for us to see. However, it can cause a thunderstorm and when it comes, it can set trees on fire releasing carbon dioxide into the atmosphere and producing global warming, melting glaciers.

Answer:

Explanation:

electron attraction between electron and nucleus = centripetal force of the orbiting electron

In fact, Bohr model depicts the atom as a nucleus surrounded by electrons in circular orbit around it, similar to the planets around the Sun. The centripetal force that keeps the electrons in circular motion around the nucles is provided by the electrostatic force between the electrons and the nucleus.

Answer:

Fg = G M m / R^2    the gravitational force (M  proton, m electron)

Fe = K e^2 / R^2   the electrical force where K = 9 *10E9 and e = charge

Fe / Fg = K e^2 / (G M m)

Fe / Fg = 9 * 10E9 * (1.6 * 10E-19)^2 / (6.67 * 10E-11 * 1.67 * 10E-27 * 9.11 * 10E-31

9 * 1.6^2 / (6.67 * 1.67 * 9.11) * 10^-29 / 10^-69

= 2.27 * 10E39  for the ratio of the two forces

One of the fundamental general safety guidelines is to keep the work area clear of combustibles for at least 35 feet from the hot work area.

Hot works or combustible works such as welding, heating or cutting should be done at a location which is far away form any combustible material.

Prior to start working in such a location make sure there are no hazardous or combustible material around such as fire, ignition source or electric spark.

All precautionary measures must be taken to confine heat, fire or spark so that they don not come into contact with nay combustible object.

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Answer:  Initial Velocity = 2.8 km/h

Final Velocity = 32 km/h

Explanation:

Answer:

C. Overcome Friction

Explanation:

When using any machine usually those with moving parts, you may notice heat forming near the areas where most movement occurs. As friction continues, more energy is used up and released as heat. For that reason, the efficiency of a machine will forever be less than 100%

Answer:

x is approximately 95.495

Explanation:

The given information are;

One lunar month = 30 days

The measured time between the first and third quarters = 14.9 days

Therefore, the angle of rotation for 30 days = 360°

The angle of rotation for 14.9 days = 14.9×360/30 = 178.8°

Therefore, whereby 2·θ = 178.8°

θ = 178.8°/2 = 89.4°

Therefore, given that the angle at the tangent from Sun to the Moon = 90°, we have;

The angle between the line from the Sun to the Moon = 90° - 89.4° = 0.6°

From sine rule, we have;

1/(sin 0.6) = x/(sin 90°)

x = (sin 90°)/(sin 0.6°) ≈ 95.495

x = 95.495.

To raise the automobile with a hydraulic lift, a force of approximately 19,000 N must be applied to the piston.

In a hydraulic lift, the principle of Pascal's law is applied, which states that pressure applied to an enclosed fluid is transmitted undiminished to all portions of the fluid and the walls of its container. By utilizing this principle, a smaller force applied to a smaller piston can generate a larger force on a larger piston.

In this scenario, the force needed to lift the automobile can be calculated using the formula:

\(\frac{F_{1}}{A_{1}} =\frac{F_{2}}{A_{2}}\)

where \(F_{1}\) is the force applied to the piston, \(A_{1}\) is the area of the piston, \(F_{2}\) is the force generated on the larger piston (required to lift the automobile), and \(A_{2}\) is the area of the larger piston.

Given the radius of the shaft (small piston) as 0.08 m and the radius of the piston as 0.01 m, we can calculate the forces applied and generated as follows:

\(A_{1} = \pi (0.08)^2\\A_{2}= \pi (0.01)^2\)

\(\frac{F_{1}}{A_{1}} =\frac{F_{2}}{A_{2}}\)

Simplifying the equation and substituting the values, we can solve for \(F_{2}\):

\(F_{2}=\frac{F_{1}A_{2}}{A_{1}}\)

Plugging in the values, we find:

\(F_{2}=\frac{F_{1} \pi (0.01)^2 }{ \pi (0.08)^2} \\F_{2}= \frac{F_{1}\times 0.0001}{0.0064} \\F_{2}= 0.015625 \times F_{1}\)

Given that the mass of the automobile is 1520 kg and the acceleration due to gravity is \(9.8 \hspace m/s^{2}\), we can equate \(F_{2}\) to the weight of the automobile:

\(F_{2}= mg\\0.015625\times F_{1}= 1520\times 9.8\)

Solving for \(F_{1}\), we find:

\(F_{1}\approx \frac{1520\times 9.8}{0.015624} \\F_{1} \approx 19072 \hspace N\)

Therefore, a force of approximately 19,000 N must be applied to the piston in order to raise the automobile using the hydraulic lift.

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Light-colored igneous rocks and dark-colored igneous rocks differ in their chemical composition and mineral content. Light-colored igneous rocks are composed of minerals that are rich in silica, such as quartz and feldspar. Dark-colored igneous rocks are composed of minerals that are rich in iron and magnesium, such as olivine and pyroxene.

The chemical composition of an igneous rock determines its color. Light-colored igneous rocks are typically light gray, pink, or white. Dark-colored igneous rocks are typically black, brown, or green.

The mineral content of an igneous rock also affects its properties. Light-colored igneous rocks are typically less dense and have a lower melting point than dark-colored igneous rocks.

Light-colored igneous rocks are typically found in areas where the crust is thin, such as continental rifts and the edges of continents. Dark-colored igneous rocks are typically found in areas where the crust is thick, such as oceanic ridges and the interiors of continents.

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Answer:

satellite B

Explanation:

A .F= G (mM)/r²

B .F= G (2mM)/r² = 2G (Mm)r²

C .F= G (3mM)/(2r)² = ¾G (mM)/r²

D .F= G (4mM)/(2r)² = G (mM)/r²

Answer:

like 23 or something

Explanation:

Answer:C

Explanation: I studied, and C is correct

Answer:

D

Explanation:

To accommodate both telecommunications and power cables in a cable tray or cable runway, they must be separated, as mandated by the National Electrical Code (NEC).

The National Electrical Code (NEC) sets standards for electrical installations to ensure safety and proper functioning. According to NEC guidelines, telecommunications and power cables should be physically separated when placed in a cable tray or cable runway. This separation is necessary to prevent interference and potential hazards. Telecommunications cables carry data signals, while power cables carry electrical currents. When these cables are in close proximity, there is a risk of electromagnetic interference (EMI) from the power cables affecting the data signals in the telecommunications cables. This interference can lead to signal degradation and communication errors. Additionally, power cables carry high voltage, which poses a safety hazard if there is a fault or short circuit. Therefore, by keeping telecommunications and power cables separated in cable trays or runways, the risk of interference and safety concerns is minimized, ensuring proper functionality and compliance with the NEC.

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